The vertices of a figure are A(1, -1), B(5.-6), and C(1, - 6). Rotate the figure 90 counterclockwise about the origin. Find the coordinates of the image. Polygon Undo Redo x Reset 7A 6. 5 4 3 2. 1 --7-6-5--4 -3 -2 -1 1 1 2 a 4 - 2 -3 -5 -6 -7 The coordinates of the image are:
Answers
The vertices of the given figure are
A(1, -1), B(5.-6), and C(1, - 6).
For a 90 counterclockwise about the origin, a coordinate, (x, y) would be (- y, x)
This means that after the 90 degrees rotation,
coordinate A would be (- - 1, 1) = (1, 1)
Coordinate B would be (- - 6, 5) = (6, 5)
Coordinate C would be (- - 6, 1) = (6, 1)
Related Questions
Find the distance between the points (0, 4) and (-7, -5).Round to the nearest tenthThe distance between them isunits.alm3
Answers
the distance between the points is
[tex]d=\sqrt[]{(-5-4)^2+(-7-0)^2}[/tex][tex]\begin{gathered} d=\sqrt[]{(-9)^2+(-7)^2} \\ d=\sqrt[]{81+49} \\ d=\sqrt[]{130} \end{gathered}[/tex][tex]d=11.401[/tex]rounding off to nearest tenth
d = 11.4
You have a set of cards labeled one through ten. Event A is drawing an even card. Event B is drawing a seven or higher. What is the P(A∩B) ?
Answers
Hello!
First, let's write the information that we know and then each event:
[tex]Set=\mleft\{1,2,3,4,5,6,7,8,9,10\mright\}[/tex]Event A is drawing an even card:[tex]A=\mleft\lbrace2,4,6,8,10\mright\rbrace[/tex]Event B is drawing a seven or higher:[tex]B=\mleft\lbrace7,8,9,10\mright\rbrace[/tex]When we use the interception symbol (∩), it means that we want to know which numbers are part of both sets simultaneously.
Let's calculate it:
[tex]A\cap B=\mleft\lbrace8,10\mright\rbrace[/tex]Bradley rolls two fair 6-sided dice with faces numbered 1 through 6. What is the probability that the sum of her two rolls has an odd number of factors?
Answers
Answer:
The probability that the sum of her two rolls has an odd number of factors will be;
[tex]P=\frac{7}{36}[/tex]Explanation:
We want to find the probability that the sum of her two rolls has an odd number of factors.
For the two rolls the total number of possible outcomes is;
[tex]6\times6=36[/tex]Let us list out the possible outcomes of the two rolls;
[tex]\begin{gathered} (\text{outcome)= sum= number of factors of the sum} \\ \mleft(1,1\mright)=2=2\text{ factors} \\ (1,2)=3=2\text{ factors} \\ (1,3)=4=3\text{ factors} \\ (1,4)=5=2\text{ factors} \\ (1,5)=6=4\text{ factors} \\ (1,6)=7=2\text{ factors} \\ \end{gathered}[/tex][tex]\begin{gathered} (2,1)=3=2\text{ factors} \\ (2,2)=4=3\text{ factors} \\ (2,3)=5=2\text{ factors} \\ (2,4)=6=4\text{ factors} \\ (2,5)=7=2\text{ factors} \\ (2,6)=8=4\text{ factors} \end{gathered}[/tex][tex]\begin{gathered} (3,1)=4=3\text{ factors} \\ (3,2)=5=2\text{ factors} \\ (3,3)=6=4\text{ factors} \\ (3,4)=7=2\text{ factors} \\ (3,5)=8=4\text{ factors} \\ (3,6)=9=3\text{ factors} \end{gathered}[/tex][tex]\begin{gathered} (4,1)=5=2\text{ factors} \\ (4,2)=6=4\text{ factors} \\ (4,3)=7=2\text{ factors} \\ (4,4)=8=4\text{ factors} \\ (4,5)=9=3\text{ factors} \\ (4,6)=10=4\text{ factors} \\ \end{gathered}[/tex][tex]\begin{gathered} (5,1)=6=4\text{ factors} \\ (5,2)=7=2\text{ factors} \\ (5,3)=8=4\text{ factors} \\ (5,4)=9=3\text{ factors} \\ (5,5)=10=4\text{ factors} \\ (5,6)=11=2\text{ factors} \end{gathered}[/tex][tex]\begin{gathered} (6,1)=7=2\text{ factors} \\ (6,2)=8=4\text{ factors} \\ (6,3)=9=3\text{ factors} \\ (6,4)=10=4\text{ factors} \\ (6,5)=11=2\text{ factors} \\ (6,6)=12=6\text{ factors} \end{gathered}[/tex]From the listed possible outcomes, the number of oucomes with odd number of factors of the sum is;
[tex]n_A=7[/tex]Total number of possibles outcomes is;
[tex]n_T=36[/tex]The probability that the sum of her two rolls has an odd number of factors will be;
[tex]\begin{gathered} P=\frac{n_A}{n_T}=\frac{7}{36} \\ P=\frac{7}{36} \end{gathered}[/tex]Would lines 4x+3y=52 and 3x-4y=44 be perpendicular parallel or neither? I just need a brief explanation with the answer
Answers
Would lines 4x+3y=52 and 3x-4y=44 be perpendicular parallel or neither?
step 1
Find out the slopes of the given lines
4x+3y=52
isolate the variable y
3y=-4x+52
y=-(4/3)x+52/3 ------> m=-4/3
3x-4y=44
4y=3x-44
y=(3/4)x-44/4 ------> m=3/4
step 2
Compare their slopes
m=-4/3 and m=3/4
the slopes are opposite reciprocal
that means
the lines are perpendicularat work one day, erica recieved 18 packages. speed delivery delivered three times as many as ralphs express, while ralphs express delivered two more than send quick service. how many packages did each service deliver to erica
Answers
Answer:
Let the number of packages delivered by Ralph's Express be x.
The number of packages delivered by Speedee Delivery would then be 4x.
The number of packages delivered by Send Quick Package Service would be x-5.
Adding all of these together,
x + 4x + (x - 5) = 6x -5
6x - 5 = 55
6x = 60
x = 10
Hence,
Ralph's Express delivered 10 packages.
Speedee Delivery delivered 40 packages.
Send Quick Package Service delivered 5 packages. Hope this help's you
Step-by-step explanation:
there are 750 seats.the number of seats in a row is 5 less than the number of rows.how many seats are there in a row?
Answers
Given:
The total number of seats, T=750.
Let x be the number of seats in a row and y be the number of rows.
It is given that the number of seats in a row is 5 less than the number of rows.
Hence, the number of seats in a row can be expressed as,
[tex]x=y-5\text{ ---(a)}[/tex]Now, expression for the total number of seats can be given by,
[tex]T=xy[/tex]Plug in x=y-5 and T=750 in the above equation and simplify.
[tex]\begin{gathered} 750=(y-5)y \\ 750=y^2-5y \\ y^2-5y-750=0\text{ ---(1)} \end{gathered}[/tex]The equation (1) is in the form of a quadratic equation of the form,
[tex]ay^2+by+c=0\text{ ---(2)}[/tex]Comparing equations (1) and (2), a=1, b=-5 and c=-750.
Now, using discriminant method, the solution of y can be expressed as,
[tex]\begin{gathered} y=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ y=\frac{-(-5)\pm\sqrt[]{(-5)^2-4\times1\times(-750)}}{2\times1} \\ y=\frac{5\pm\sqrt[]{25+3000}}{2\times1}\text{ } \\ y=\frac{5\pm\sqrt[]{3025}}{2} \\ y=\frac{5\pm55}{2}\text{ } \\ y=\frac{5+55}{2}\text{ or y=}\frac{5-55}{2} \\ y=\frac{60}{2}\text{ or y=}-\frac{50}{2} \\ y=30\text{ or y=-25} \end{gathered}[/tex]Since the number of rows cannot be negative, y=30.
Put y=30 in equation (a) to find x.
[tex]\begin{gathered} x=30-5 \\ x=25 \end{gathered}[/tex]Therefore, the number of seats in a row is 25.
The ratio of boys to girls in our class is 1210
Answers
The ratio of boys to girls in our class is 12:10
that means
12 divided by 10
so
12/10
simplify
6/5 or 6:5
In Exercises ***, find the value of x so that the function has the given value.4. f(x) = 6x; f(x) = -245. g(x) = -10x; g(x) = 15
Answers
We have to find the value of x, such that the function:
[tex]f(x)=6x[/tex]takes the value -24. This means that such x has to satisfy:
[tex]\begin{gathered} f(x)=-24 \\ 6x=-24 \end{gathered}[/tex]Now, we just clear out the variable x. We obtain:
[tex]\begin{gathered} x=-\frac{24}{6} \\ x=-4 \end{gathered}[/tex]This means that the value x=-4 makes the function f to be -24.
More people are purchasing food from farmers' markets around the country. As a consequence, a market researcher predicts that the number of farmers' markets will increase by 1.71.7% every six months. If there were 74997499 farmers' markets in 2019, how many will there be in 99 years?Given the exponential growth scenario above, answer the following questions:What is the initial value, P0P0 in this problem? What is the growth factor or growth rate (as a decimal value)? What is the nn value, or number of time periods? Question Help Question 1: Read 1
Answers
Step 1
Given;
[tex]\begin{gathered} Initial\text{ farmer market=P}_0=7499 \\ b=0.017 \\ n=number\text{ of time periods} \end{gathered}[/tex]Step 2
The exponential function for the question is
[tex]\begin{gathered} P=P_0(1+b)^n \\ P=P_0(1+0.034)^n \\ P=P_0(1.017)^n \end{gathered}[/tex]Step 3
The initial value in this problem is;
[tex]P_0=7499[/tex]Step 4
The growth rate factor as a decimal will be;
[tex]1.017[/tex]Step 5
What is the n value or a number of time periods?
[tex]n=18[/tex]Step 6
How many will there be in 9 years
[tex]\begin{gathered} P=7499(1.017)^{18} \\ P=10157.35207 \\ P\approx10157\text{ farmers' markets} \end{gathered}[/tex]On New Year's Eve, the probability of a person having a car accident is 0.08. The probability of a person driving while intoxicated is 0.28, and the probability of a person having a car accident while intoxicated is 0.04. What is the probability of a person driving while intoxicated or having a car accident ? A.0.15 B.0.16 C.0.18 D.0.32
Answers
Answer:
D. 0.32
Explanation:
The probability of a person driving while intoxicated or having a car accident can be calculated as:
[tex]P=P(\text{Intoxicated)}+P(\text{ Accident) - P(Intoxicated and Accident)}[/tex]So, replacing P(Intoxicated) = 0.28, P(Accident) = 0.08 and P(Intoxicated and Accident) = 0.04, we get
[tex]\begin{gathered} P=0.28+0.08-0.04 \\ P=0.32 \end{gathered}[/tex]Therefore, the answer is
D. 0.32
solve by factoring, by square roots, by completing the square, or using the quadratic formulaSolve for x in the equation belowX^2 −15x+54=0
Answers
STEP 1: Identify and Set up.
We have a quadratic equation and are asked to solve, i.e, solve for x. We approach this problem via the factoring method.
We look for two factors of the third term, c that add up to the coefficient of x, favtorise and solve.
STEP 2: Execute
[tex]\begin{gathered} x^2-15x+54=0 \\ \text{the factors are -6 and -9} \\ x^2-9x-6x+54=0 \\ Factorizing\text{ gives us:} \\ x(x-9)-6(x-9)=0 \\ (x-9)(x-6)=0 \\ x\text{ is either 9 or 6} \end{gathered}[/tex]x = 9 and x = 6
True or False Then need explanation in one paragraph or word
Answers
1) True
2) False
3) True
4) False
5) False
Explanations:Domains are indepedent variables for which a function exists while the range are dependent variables for which a function exist.
Foa a given coordinates (x, y), all the sets of first coordinates are the domain while all the sets of second coordinates are the range;
All functions are also known as relations but not all given relations are function.
Based on the explanations above, then;
1) A relation is a set of ordered pairs is TRUE
2) The set of all the first coordinates is called is range is FALSE
3) All functions are relations is TRUE
4) The set of all the second coordinates is called is domain is FALSE
5) All relations are function is FALSE
upper menu options: 1 3 7 8left menu options: 10 11 12 15
Answers
In order to find the amount of blue paint needed, we can write the following rule of three:
[tex]\begin{gathered} \text{green}\to\text{blue} \\ 1\text{ batch}\to2\frac{3}{8}\text{ oz} \\ 5\text{ batches}\to x\text{ oz} \end{gathered}[/tex]First, let's convert the mixed number into an improper fraction:
[tex]2\frac{3}{8}=2+\frac{3}{8}=\frac{16}{8}+\frac{3}{8}=\frac{19}{8}[/tex]From this rule of three, we can write the following equation and solve it for x:
[tex]\begin{gathered} \frac{1}{5}=\frac{\frac{19}{8}}{x} \\ x\cdot1=5\cdot\frac{19}{8} \\ x=\frac{95}{8} \\ x=\frac{88}{8}+\frac{7}{8} \\ x=11+\frac{7}{8} \\ x=11\frac{7}{8} \end{gathered}[/tex]Therefore the upper menu is 7 and the left menu is 11.
Solve the system: y = 12 + 4x y = -33 - 5x
Answers
The equation system is:
[tex]\begin{gathered} y=12+4x \\ y=-33-5x \end{gathered}[/tex]So we can made the equation equal so:
[tex]\begin{gathered} 12+4x=-33-5x \\ 4x+5x=-33-12 \\ 9x=-45 \\ x=-\frac{45}{9} \\ x=-5 \end{gathered}[/tex]Now we can replace the value of x to find y in the first equation so:
[tex]\begin{gathered} y=12+4(-5) \\ y=12-20 \\ y=-8 \end{gathered}[/tex]so the solution is:
[tex](-5,-8)[/tex]Which fractions are equivalent to ?Select all that apply. 64 64 yi 764 8 1 4
Answers
We are given the following radical expression
[tex]\sqrt[3]{\frac{1}{64}}[/tex]Let us simplify it using the properties of radicals.
The quotient property of radicals is given by
[tex]\sqrt[n]{\frac{x}{y}}=\frac{\sqrt[n]{x}}{\sqrt[n]{y}}[/tex]Let us apply the above property
[tex]\sqrt[3]{\frac{1}{64}}=\frac{\sqrt[3]{1}}{\sqrt[3]{64}}[/tex]Further simplifying the radical
[tex]\frac{\sqrt[3]{1}}{\sqrt[3]{64}}=\frac{1^{\frac{1}{3}}}{64^{\frac{1}{3}}}=\frac{1}{4}[/tex]The cube root of 1 is 1 and the cube root of 64 is 4
Therefore, the correct options are
[tex]\begin{gathered} \frac{\sqrt[3]{1}}{\sqrt[3]{64}} \\ \frac{1}{4} \end{gathered}[/tex]Can you please help me out
Answers
The bag contains,
Red (R) marbles is 9, Green (G) marbles is 7 and Blue (B) marbles is 4,
Total marbles (possible outcome) is,
[tex]\text{Total marbles = (R) + (G) +(B) = 9 + 7 + 4 = 20 marbles}[/tex]Let P(R) represent the probablity of picking a red marble,
P(G) represent the probability of picking a green marble and,
P(B) represent the probability of picking a blue marble.
Probability , P, is,
[tex]\text{Prob, P =}\frac{required\text{ outcome}}{possible\text{ outcome}}[/tex][tex]\begin{gathered} P(R)=\frac{9}{20} \\ P(G)=\frac{7}{20} \\ P(B)=\frac{4}{20} \end{gathered}[/tex]Probablity of drawing a Red marble (R) and then a blue marble (B) without being replaced,
That means once a marble is drawn, the total marbles (possible outcome) reduces as well,
[tex]\begin{gathered} \text{Prob of a red marble P(R) =}\frac{9}{20} \\ \text{Prob of }a\text{ blue marble =}\frac{4}{19} \\ \text{After a marble is selected without replacement, marbles left is 19} \\ \text{Prob of red marble + prob of blue marble = P(R) + P(B) = }\frac{9}{20}+\frac{4}{19}=\frac{251}{380} \\ \text{Hence, the probability is }\frac{251}{380} \end{gathered}[/tex]Hence, the best option is G.
need HELPPPPPPP with
Answers
let x be the number that we pick. So the final answer and the pattern is:
[tex]\frac{2(x+4)-6}{2}=(x+4)-3=x+1[/tex]so the pattern is that we get the x+1 if we choose x. so the pattern is to add 1 to the initial number
identify the special product by writing the letter of the answer provided. ( number 7 question in photo. )
Answers
(7)
Given the equation;
[tex](y+9)(y-9)=y^2-81[/tex]A binommial is a polynomial that is the sum of two terms, that is;
[tex]y^2-81\ldots.\ldots\ldots\ldots.\text{ is a binommial}[/tex]Thus;
[tex](y+9)(y-9)=y^2-81[/tex]is a binommial that is a product of sum and difference of two terms.
CORRECT OPTION: D
convert to degrees minutes and seconds54.158°
Answers
Convert 54.158 degrees
Firstly, Use the whole number as degree
54 degree
to convert to minutes
(54.548 - 54) x 60
= 0.158 x 60
= 9 minutes
To convert to seconds
(54.158 - 54 - 9/60) x 3600
= (0.158 - 0.15) x 3600
= 0.008 x 3600
= 28.8 seconds
This can be written as
[tex]54^o\text{ 9' 28.8''}[/tex]Flora has an annual income of $18,500. She has $6,500 withheld asdeductions. What is the amount of each paycheck if she gets paidsemimonthly?a. $500b. $461.54c. $711.54d. $1,000
Answers
To calculate the amount of each semimonthly paycheck, we need to find the actual amount of money Flora actually receives annually.
Her income is $18500, but $6500 are deducted. Then:
[tex]18500-6500=12000[/tex]The actual money she receives in one year, after deductions, is $12000.
If she receives semimonthly paychecks, we need to bear in mind that in total she receives 24 paychecks in one year. This considering that semimonthly means that she receives two paychecks in a month.
Then, we just need to divide $12000 by 24 to obtain the amount of each paycheck:
[tex]\frac{12000}{24}=500[/tex]The amount of each paycheck is $500.
The correct answer is option a.
A line has an x-intercept of 12 and a y-intercept of -4. What is the equation of theline?
Answers
A line has an x-intercept of 12 and a y-intercept of -4. What is the equation of the
line?
that means
we have the points
(12,0) and (0,-4)
Find the slope
m=(-4-0)/(0-12)
m=-4/-12
m=1/3
Find teh equation in slope intercept form
y=mx+b
we have
m=1/3
b=-4
therefore
y=(1/3)x-4QuestionLet x be a constant. The 5th term of an arithmetic sequence is a5=4x−3. The 9th term of the sequence is a9=12x+9. Find the first term of the sequence. Write your answer in simplest form.
Answers
The nth term of an arithmetic sequence is :
[tex]a_n=a_1+d(n-1)[/tex]From the problem, we have :
[tex]\begin{gathered} a_5=4x-3 \\ a_9=12x+9 \end{gathered}[/tex]Substitute a5 and n = 5 :
[tex]\begin{gathered} a_n=a_1+d(n-1) \\ a_5=a_1+d(5-1) \\ 4x-3=a_1+4d \end{gathered}[/tex]Rewrite the equation as d in terms of x and a1 :
[tex]\begin{gathered} 4x-3=a_1+4d \\ 4x-3-a_1=4d \\ d=\frac{4x-3-a_1}{4} \end{gathered}[/tex]Subsitute a9 and n = 9
[tex]\begin{gathered} a_n=a_1+d(n-1) \\ a_9=a_1+d(9-1) \\ 12x+9=a_1+8d \end{gathered}[/tex]Rewrite the equation as d in terms of x and a1 :
[tex]\begin{gathered} 12x+9=a_1+8d \\ 12x+9-a_1=8d \\ d=\frac{12x+9-a_1}{8} \end{gathered}[/tex]Now, equate two equations of d :
[tex]\begin{gathered} \frac{4x-3-a_1}{4}=\frac{12x+9-a_1}{8} \\ 8(4x-3-a_1)=4(12x+9-a_1) \\ 32x-24-8a_1=48x+36-4a_1 \\ 4a_1-8a_1=48x+36-32x+24 \\ -4a_1=16x+60 \\ a_1=-4x-15 \end{gathered}[/tex]The answer is a1 = -4x-15
If the 5th term of an arithmetic sequence is a5=4x−3. The 9th term of the sequence is a9=12x+9. The first term of the sequence is -4x-15
What is Sequence?a sequence is an enumerated collection of objects in which repetitions are allowed and order matters.
The nth term of AP
aₙ=a+(n-1)d..(1)
From give we have,
a₅=4x−3
a₉=12x+9.
Substitute n=5 in (1)
a₅=a+4d
4x-3=a+4d
4d=4x-3-a
d=4x-3-a/4...(2)
Substitute n=9 in (1)
a₉=a+8d
12x+9=a+8d
12x+9-a/8=d..(3)
Equate 2 and 3
4x-3-a/4=12x+9-a/8
8(4x-3-a)=4(12x+9-a)
32x-24-8a=48x+36-4a
32x-24-8a-48x-36+4a=0
-16x-4a-60
-16x-60=4a
a=-4x-15
Hence the first term of the AP sequence is -4x-15
To learn more on Sequence click:
https://brainly.com/question/21961097
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Using the cosine law to determine the measure of we could use _______:
Answers
Solution
- The Cosine law is given below as:
[tex]\begin{gathered} Given\text{ }\triangle ABC,\text{ with sides }a,b,c\text{ and angles }\angle A,\angle B,\angle C\text{ such that} \\ a\text{ is opposite }\angle A \\ b\text{ is opposite }\angle B \\ c\text{ is opposite }\angle C \\ \\ \text{ We have:} \\ a^2=b^2+c^2-2(bc)\cos\angle A \end{gathered}[/tex]- We can make [tex]\begin{gathered} a^2=b^2+c^2-2bc\cos\angle A \\ \text{ Subtract }b^2\text{ and }c^2\text{ from both sides} \\ \\ a^2-b^2-c^2=-2bc\cos\angle A \\ \\ \text{ Divide both sides by }-2bc \\ \cos\angle A=\frac{a^2-b^2-c^2}{-2bc} \\ \text{ } \\ \text{ Take the cos inverse of both sides} \\ \\ \therefore\angle A=\cos^{-1}(\frac{a^2-b^2-c^2}{-2bc}) \end{gathered}[/tex]
Final Answer
The answer is
[tex]\operatorname{\angle}A=\cos^{-1}(\frac{a^{2}-b^{2}-c^{2}}{-2bc})\text{ \lparen OPTION C\rparen}[/tex]find two expressions that are equivalent by the distributive property 42g+2142g+3. 7(6g+3) 7g+7select all that apply42g+217(6g+3)7g+742g+3
Answers
the expressions are
42g+21 and 7(6g+3)
because
[tex]\begin{gathered} 7(6g+3) \\ 7\times6g+7\times3 \\ 42g+21 \end{gathered}[/tex]the expressions are equivalents
what fraction is equivalent to 2/2
Answers
Answer:
4/4,6/6 etc
Step-by-step explanation:
multiply both numerator and denominator with the same number
(3x-3)
[6(x - 10)] What is the value of x?
Answers
3(x - 1)
[6(x - 10)]
6x + 6 times -10
simplify 6 times -10 to -60
6x - 60
11. Mr. Garcia uses a cylindrical container to protect his diploma. The dimensions of the cylinder are shown in the diagram. IS cm ------ 10 cm Which measurement is closest to the total surface area of the container in square centimeters?
Answers
Given data:
The given figure of cylinder.
The total surface area of the cylinder is,
[tex]\begin{gathered} SA=2\pi r(r+h) \\ =2\pi\frac{d}{2}(\frac{d}{2}+h) \end{gathered}[/tex]Substitute the given values in the above expression.
[tex]undefined[/tex]Express (5/6x + 4) 2 as trinomial in simplest form (2 is an exponent)
Answers
We are given the expression (5/6x + 4)^2 and we are asked to express it as a trinomial in the simplest form.
To do this, we will be using the FOIL method. FOIL stands for First-Outer-Inner-Last.
The product will then be:
[tex]\begin{gathered} (\frac{5}{6}x+4)^2=(\frac{5}{6}x+4)(\frac{5}{6}x+4) \\ \\ (\frac{5}{6}x+4)^2=(\frac{5}{6}x)^2+(\frac{5}{6}x)(4)+(4)(\frac{5}{6}x)+4(4) \\ \\ (\frac{5}{6}x+4)^2=\frac{25}{36}x^2+\frac{10}{3}x+\frac{10}{3}x+16 \\ \\ (\frac{5}{6}x+4)^2=\frac{25}{36}x^2+\frac{20}{3}x+16 \end{gathered}[/tex]So, the final answer is 25/36 x^2 + 20/3 x + 16.
find f such that the given conditions are satisfiedf’(x)=x-4, f(2)=-1
Answers
Given:
[tex]f^{\prime}\left(x\right)=x-4,\text{ and}f\left(2\right)=-1[/tex]To find:
The correct function.
Explanation:
Let us consider the function given in option D.
[tex]f(x)=\frac{x^2}{2}-4x+5[/tex]Differentiating with respect to x we get,
[tex]\begin{gathered} f^{\prime}(x)=\frac{2x}{2}-4 \\ f^{\prime}(x)=x-4 \end{gathered}[/tex]Substituting x = 2 in the function f(x), we get
[tex]\begin{gathered} f(2)=\frac{2^2}{2}-4(2)+5 \\ =2-8+5 \\ =-6+5 \\ f(2)=-1 \end{gathered}[/tex]Therefore, the given conditions are satisfied.
So, the function is,
[tex]f(x)=\frac{x^{2}}{2}-4x+5[/tex]Final answer: Option D
Spongebob was trying to fill up Gary's bath with water. He noticed the tub filled up 1 gallon per minute.AContinuousBDiscrete
Answers
given data:
Spongebob was trying to fill up Gary's bath with water. He noticed the tub filled up 1 gallon per minute.
to find what kind of data this is.
it is discrete because it is measurable. that is countiuse while countable.
Thus the answer is discrete.