The interquartile range is a measure of where the “middle fifty” is in a data set, where the bulk of the values lies.
The interquartile range formula is the first quartile subtracted from the third quartile:
[tex]IQR=Q_3-Q_1[/tex]IQR of the Mid-Term
Step 1: Arrange the numbers in order
[tex]73,78,80,81,82,86,87,90,92,95,96[/tex]Step 2: Find the median
[tex]Median\Rightarrow86[/tex]Step 3: Find Q1 and Q3
Q1 and Q3 are the median of the numbers before and after the median of the data set. Therefore, Q1 is the median of the first 5 numbers:
[tex]Q_1=80[/tex]Q3 is the median of the last 5 numbers:
[tex]Q_3=92[/tex]Step 4: Calculate the IQR
[tex]IQR=92-80=12[/tex]IQR of the Final
Step 1: Arrange the numbers in order
[tex]75,78,78,78,81,82,83,83,85,85,100[/tex]Step 2: Find the median
[tex]Median\Rightarrow82[/tex]Step 3: Find Q1 and Q3
Q1 and Q3 are the median of the numbers before and after the median of the data set. Therefore, Q1 is the median of the first 5 numbers:
[tex]Q_1=78[/tex]Q3 is the median of the last 5 numbers:
[tex]Q_3=85[/tex]Step 4: Calculate the IQR
[tex]IQR=85-78=7[/tex]ANSWER
The data with the smallest IQR is the FINAL.
I will make seafood salad using strawberries and blueberries he uses 5 cups of strawberries for every 3 cups of blueberries which measure represents the amount of strawberries Alan uses for every bowl of fruit salad
His salad calls for 8 cups of salad to maintain the given ratio. (5 cups of strawberries for every 3 cups of blueberries) So the ratio is 5/8 for the strawberries.
Let x be what he needs for 1 cup of fruit
5/8 = x
That's because there are 5 cups of strawberries for every 8 ( 5 strawberries + 3 blueberries ) items he needs.
I need your help know
Answer : 87.9 square inches
Given the following data
Radius of the cylindrical cup = 2 inches
Height of the cylindrical cup = 5 inches
Surface area is given as
[tex]\begin{gathered} A\text{ = 2}\pi rh\text{ + 2 }\cdot\pi\cdot r^2 \\ \text{Where }\pi\text{ = 3.14} \\ A\text{ = 2}\pi r(h\text{ + r)} \\ A\text{ = 2 x 3.14 x 2(5 + 2)} \\ A\text{ = 12.56(7)} \\ A\text{ = 12.56 x 7} \\ A=87.9inches^2 \end{gathered}[/tex]Quadrilateral GHJK is a rectangle. Find each measure if m<1=37
Answer:
[tex]\begin{gathered} m\angle2\text{ = 53} \\ m\angle3\text{ = 37} \\ m\angle4\text{ = 37} \\ m\angle5\text{ =53} \\ m\angle6\text{ =106} \\ m\angle7\text{ = 74} \end{gathered}[/tex]Explanation:
Here, we want to find the measure of the given angles
From what we have, the angle marked 1 is of a value 37 degrees
For a rectangle, each angle at the edges equal 90 degrees
That makes a total of 360 degrees
Also, we have four isosceles triangle. These are triangles with equal base angle in each
With these in mind, we can proceed to get the value of the missing indicated angles
a)
[tex]\begin{gathered} m\angle1\text{ + m}\angle2\text{ = 90} \\ m\angle2\text{ = 90-37} \\ m\angle2\text{ = 53} \end{gathered}[/tex]b)
[tex]\begin{gathered} m\angle5\text{ + m}\angle1\text{ = 90} \\ By\text{ transition:} \\ m\angle5\text{ = m}\angle2\text{ = 53} \end{gathered}[/tex]c)
[tex]\begin{gathered} m\angle4\text{ + m}\angle5\text{ = 90} \\ m\angle1\text{ = m}\angle4\text{ = 37} \end{gathered}[/tex][tex]\begin{gathered} d)\text{ m}\angle3\text{ = m}\angle4\text{ = 37} \\ \text{Base angles of isosceles triangle are equal} \end{gathered}[/tex]d)
[tex]\begin{gathered} m\angle6\text{ + m}\angle3\text{ + m}\angle4\text{ = 180} \\ \text{sum of interior angles of a triangle} \\ m\angle6\text{ = 180-37-37} \\ m\angle6\text{ = 106} \end{gathered}[/tex]e)
[tex]\begin{gathered} m\angle6\text{ + m}\angle7\text{ = 180} \\ \text{Sum of angles on a straight line} \\ m\angle7\text{ = 180-106} \\ m\angle7\text{ = 74} \end{gathered}[/tex]f)
what is the area of the triangle formed from (0,-1) (0,4) and (4,-1)
The area of the triangle is 10 square units formed from (0,-1), (0,4), and (4,-1).
What is the Area of a Triangle?A triangle is a closed shape composed of three angles, three sides, and three vertices.
The triangle is formed from (0,-1), (0,4), and (4,-1) which are given in the question.
As per the attached graph,
The length of the base of the triangle = 4 units
The length of the height of the triangle = 5 units
The area of the triangle = 1/2 × 4 × 5
The area of the triangle = 10 square units
Therefore, the area of the triangle is 10 square units formed from (0,-1), (0,4), and (4,-1).
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--212x21 4 Kuta Software - Infinite Algebra 2 Graphing Absolute Value Equations Graph each equation. 1) y=x-11 De 36 2) -\ x41
The expression below is an absolute expression
y = | x + 4|
An absolute value can be expressed as either plus or minus
Therefore, the equation can be written as
y = ( x + 4) or -(x + 4)
y = (x + 4)
y = -( x + 4)
We will need to graph this equation one after the other
y = x + 4
To find x, let y = 0
0 = x + 4
x = 0 - 4
x = -4
(-4, 0)
To find y, let x = 0
y = 0 + 4
y = 4
(0, 4)
The second equation is given as
y = -x - 4
To find x, let y = 0
0 = -x - 4
-x = 0 + 4
-x = 4
x = -4
(-4, 0)
To find y, let x = 0
y = -0 - 4
y = -4
(0, -4)
We will be graphing the above points
(-4, 0), (0, 4) and (-4, 0) (0, -4)
you start on the unit circle at 0 negative one and move 300 degrees counterclockwise which angle in degrees will you end up on the unit circle Answer Choices:30330210120
By definition, it is important to remember that a circle has 360 degrees.
According to the information given in the exercise, you start at this point on the unit circle:
[tex](0,-1)[/tex]Observe the following picture:
By definition, from the point (0,-1) to the point (1,0) there are 90 degrees.
Therefore, if you move 300 degrees counterclockwise from the point (0,-1), you can subtract 90 degrees from the 300 degrees in order to calculate which angle in degrees will you end up on the unit circle:
[tex]300\degree-90\degree=210\degree[/tex]Therefore, you will end up with 210 degrees.
The answer is: Third option.
Plot three points for the line and graph the line. X-3y=6
x-3y = 6
Pick 3 points
Let x = 0
0 -3y = 6
Divide by -3
-3y/-3 = 6/-3
y = -2
(0,-2)
Let y =0
x - 3(0)=6
x = 6
(6,0)
Let x=3
3 - 3y = 6
Subtract 3 from each side
3-3y-3 = 6-3
-3y = 3
Divide by -3
-3y/-3 = 3/-3
y = -1
(3,-1)
The scale factor of a model of a warehouse to the actual warehouse is 1 to 2. The volume of theactual warehouse is 8,455 ft^3. Find the volume of the model. Round to a whole number.
Question
The scale factor of a model of a warehouse to the actual warehouse is 1 to 2. The volume of the actual warehouse is 8,455 ft^3. Find the volume of the model. Round to a whole number.
Solution
The scale factor (or ratio) of the model to the actual is
[tex]1\colon2[/tex]The scalar factor (or ratio) for the volume will be
[tex]\begin{gathered} 1^3\colon2^3 \\ 1\colon8 \end{gathered}[/tex]To find the volume of the model
Let the volume of the model by denoted with x
We use the ratio
[tex]\begin{gathered} \frac{1}{8}=\frac{x}{8455} \\ \text{cross multiply} \\ 8\times x=1\times8455 \\ 8x=8455 \\ x=\frac{8455}{8} \\ x=1056.875 \\ x=1057ft^3\text{ (to the nearest whole number)} \end{gathered}[/tex]Thus, the volume of the model is 1057ft^3
One side of a triangles two centimeters shorter than the base. The other side is four centimeters longer than the base. What lengths of the base will allow the perimeter to be greater than 29 cm?
Answer:
x > 9 cm
Explanation:
Let the length of the base = x cm
One side of a triangle is 2 cm shorter than the base.
Length = (x-2)cm
The other side is 4 cm than the base, therefore:
Length of the other side = (x+4)cm
Perimeter = x+(x-2)+(x+4)
If the perimeter is greater than 29, then:
x+(x-2)+(x+4)>29
3x-2+4>29
3x+2>29
3x>29-2
3x>27
x>27/3
x>9
The length of the base greater than 9cm will allow the perimeter to be more than 29 cm.
A surveying crew has two points A and B marked along a roadside at a distance of 400 yd. A third point C ismarked at the back corner of a property along a perpendicular to the road at B. A straight path joining C to A forms a 28° angle with the road. Find the distance from the road to point C at the back of the property andthe distance from A to C using sine, cosine, and/or tangent. Round your answer to three decimal places.
In order to calculate the distance from B to C, we can use the tangent relation of the angle 28°.
The tangent is equal to the length of the opposite leg to the angle over the length of the adjacent leg to the angle.
So we have:
[tex]\begin{gathered} \tan(28°)=\frac{BC}{AB}\\ \\ 0.5317094=\frac{BC}{400}\\ \\ BC=0.5317094\cdot400\\ \\ BC=212.684 \end{gathered}[/tex]Now, to calculate the distance from A to C, we can use the cosine relation.
The cosine is equal to the length of the adjacent leg to the angle over the length of the hypotenuse.
So we have:
[tex]\begin{gathered} \cos(28°)=\frac{AB}{AC}\\ \\ 0.8829476=\frac{400}{AC}\\ \\ AC=\frac{400}{0.8829476}\\ \\ AC=453.028 \end{gathered}[/tex]Evaluate (10²-8²)÷(5+7)-6
BODMAS RULE is used in simplification problems. The opertation are done in the following order in simplification.
B-->Bracket
D-->Division
M-->Multiplication
A-->Addition
S-->Subtraction
[tex]\begin{gathered} (10^2-8^2)\div(5+7)-6 \\ =(100-64)\div(12)-6\text{ (Did operations inside brackets)} \\ =36\div12-6\text{ } \\ =3-6\text{ (Did division 36 }\div\text{ 12)} \\ =-3 \end{gathered}[/tex]Therefore, the answer is -3.
Arectangular field has an area of 646 square feet. The width of the field is 19 feetWite a number in the box to show the missing measurement What is the length of the field?
The area of a rectangle is
[tex]A=19\cdot x=76[/tex]x is the number missing in the box
[tex]x=\frac{76}{19}=4[/tex]the length of the field is 30+4 =34 feet
PLEASEEEE HELPPP!!!!!PLEASEEEEEEEEEEEEE!!!!!!!!Assessment practice!!!!it's URGENT HELP is much appreciated find the vertex of each equation. Then use a table to graph each quadratic equation
Remember that the x-coordinate of the vertex of a quadratic function is -b/2a. In this case is:
[tex]x=-\frac{4}{2\cdot1}=-2[/tex]the y coordinate is
[tex]y=4+4\cdot-2-6=4-8-6=-10[/tex]Ryhanna has a container with a volume of 1.5 liters. She estimates the volume to be 2.1 liters. What is the percent error?
We know that Ryhanna has a container with a volume of 1.5 liters and that she estimates the value to be 2.1 liters. We want to find the percent error.
For doing so, we remember that the percent error is given by the expression:
[tex]=\frac{\mleft|v_{true}-v_{estimated}\mright|}{v_{true}}\cdot100[/tex]In this exercise, we have that:
[tex]\begin{gathered} v_{\text{true}}=1.5 \\ v_{\text{estimated}}=2.1 \end{gathered}[/tex]So, replacing we obtain:
[tex]\text{error}=\frac{\mleft|1.5-2.1\mright|}{1.5}\cdot100=\frac{0.6}{1.5}\cdot100=0.4\cdot100=40[/tex]This means that Ryhanna estimated the value of the volume with an error of 40%.
Simplify the following expression by multiplying by theconjugate:6+3/5√5-2
Answer:
Simplifying the given expression gives;
[tex]27+12\sqrt[]{5}[/tex]Explanation:
Given the expression;
[tex]\frac{6+3\sqrt[]{5}}{\sqrt[]{5}-2}[/tex]Multiplying both the denominator and numerator by the conjugate of the denominator;
[tex]\begin{gathered} \frac{6+3\sqrt[]{5}}{\sqrt[]{5}-2}\times\frac{\sqrt[]{5}+2}{\sqrt[]{5}+2}=\frac{(6+3\sqrt[]{5})(\sqrt[]{5}+2)}{(\sqrt[]{5}-2)(\sqrt[]{5}+2)} \\ =\frac{6\sqrt[]{5}+6\sqrt[]{5}+12+3(5)}{5-4} \\ =\frac{12\sqrt[]{5}+12+15}{1} \\ =27+12\sqrt[]{5} \end{gathered}[/tex]Therefore, simplifying the given expression gives;
[tex]27+12\sqrt[]{5}[/tex]How would you classify 8/2?
8/ 2 is a whole number, this is because 8 divided by 2 is 4. and 4 is a whole number.
4 is an integer. An integer is a whole number that can be positive, negative or zero. A rational numbe is a number that can be mode
A pianist plans to play 6 pieces at a recital from her repertoire of 26 pieces.
Answer:
[tex]230230\text{ Recital programs are possible}[/tex]Explanation:
Here, we want to get the number of possible recital programs
We are not concerned about arrangements here
Thus, we have to use combination
We have this as:
[tex]^nC_r\text{ = }\frac{n!}{(n-r)!r!}[/tex]where in this case, n is 26 and r is 6
Substituting the values in the combination formula, we have it that:
[tex]^{26}C_6=\text{ }\frac{26!}{(26-6)!6!}\text{ = 230230}[/tex]
5 1 point A high rise apartment is on fire. 1 There are two people in a window that is 14.5 feet above the What angie must the ladder make with the ground in order to 2 Type your answer... 3 4
Detrmine the angle of ladder by uisng the trigonometric ratio.
[tex]\begin{gathered} \sin \alpha=\frac{14.5}{22} \\ \alpha=\sin ^{-1}(0.66) \\ =41.29 \\ \approx41^{\circ} \end{gathered}[/tex]So answer is 41 degree.
find the x-intercept and the y-intercept of the graph of the equation 6X + 4y equals 72
the given equation is
6x + 4y = 72
divide the equation by 2
3x + 2y = 36
3x + 2y - 36 = 0
compare with ax+by +c = 0
a = 3
b = 2
c = -36
x-intercept will be, -c/a = -(-36)/3 = 12
y intercept will be c/b = -36/2 = -18
Which equation represents a circle? (x – 2)222+(y – 3)232=1 (x – 4)232+(y + k)212=1 x222+y222=1 x212+y232=1
Given:
Four different equations are given
Required:
To tell Which equation represents a circle?
Explanation:
The formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle. If a circle is tangent to the x-axis this means it touches the x-axis at that point
[tex]\begin{gathered} \frac{x^2}{2^2}+\frac{y^2}{2^2}=1 \\ \\ x^2+y^2=2^2 \\ \\ so\text{ r =2} \end{gathered}[/tex]That is others are in the form of ellipse equation.
How do you find the general form of an ellipse?
The equation of an ellipse written in the form (x−h)2a2+(y−k)2b2=1. The center is (h,k) and the larger of a and b is the major radius and the smaller is the minor radius.
[tex]\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1[/tex]else three options resemble with ellipse equation
Required answer:
[tex]\frac{x^{2}}{2^{2}}+\frac{y^{2}}{2^{2}}=1[/tex]1. Determine the difference inclock 12 arithmetic bystarting at the first numberand countingcounterclockwise on theclock the number. Of unitsgiven by the second number 1-11=?
Given:
The identity element is P.
Required:
Determine the inverse if exist of
(a) P (b) Q (c) R
Explanation:
We know that the inverse is the element when combined on the right or the left through the operation, always gives the identity element as the result.
We can see in the first row the identity element P is getting by the operation of P and P. Thus the Inverse of P is itself.
In the second and third rows, the identity element is P is getting by the operation of Q and R.
Thus the inverse of Q is R and the inverse of R is Q.
Both are inverse of each other.
Final Answer:
The Inverse of the following are as:
(a) P = P
(b) Q = R
(c) R =Q
Which equation best represents the volume,V, of this cylinder in terms of π
Answer:
[tex]V=18.75\pi[/tex]Step-by-step explanation:
The volume of a cylinder is represented by the following expression:
[tex]V=h\cdot\pi\cdot r^2[/tex]Then, in this case for a radius of 2.5 and height of 3:
[tex]\begin{gathered} V=3\cdot\pi\cdot2.5^2 \\ V=6.25\cdot3\cdot\pi \\ V=18.75\pi \end{gathered}[/tex]Cuál es el MCD de 42 y 30 ?. Opción única. (3 puntos) 5 6 7 15
Greatest Common Factor:
The greatest common factor, or GCF, is the greatest factor that divides two numbers.
Given Numbers : 42 & 30
Factors of 42 : 7x3x2x1, 7x6x1,
Factors of 30=5x3x2x1, 5x6,1
Here the common factors of 42 & 30 are : 6,3, 2, 1
The greatest number in 6, 3, 2, 1 is 6
So, the greatest common factor is 6
The greatest common factor of 42 & 30 is 6
Answer: B) 6
solve the equation 3b-13+4b=7b+1
Answer:
The given equation has no solution.
Explanation:
Given the equation:
[tex]3b-13+4b=7b+1[/tex]To solve, Firstly let's collect the like terms;
[tex]\begin{gathered} 3b-13+4b=7b+1 \\ 3b+4b-13=7b+1 \\ 7b-13=7b+1 \end{gathered}[/tex]From the resulting equation, we can see that the left side of the equation is not equal to the right side.
Adding 13 to both sides;
[tex]\begin{gathered} 7b-13+13=7b+1+13 \\ 7b=7b+14 \end{gathered}[/tex]Therefore, the given equation has no solution.
Find the midpoint of AC.B (0, a)C (a, a)D (a,0)a(4)2A (0,0)Enter the value thatbelongs in the green box.Midpoint Formula: M = (*¹*²₁¹²)RE
The formula to calculate the midpoint between two points is given by
[tex]M=(\frac{x1+x2}{2},\frac{y1+y2}{2})[/tex]we have the coordinates
A(0,0) and C(a,a)
substitute the given coordinates
[tex]\begin{gathered} M=(\frac{0+a}{2},\frac{0+a}{2}) \\ \\ M=(\frac{a}{2},\frac{a}{2}) \end{gathered}[/tex]I will be attaching a picture of the question as you can see the question has already been answered my teacher wants me to type out how she got the answer I need it fast bc this is due in an hour.
we calculate the radius, i.e. the distance between two points
[tex]\begin{gathered} r=\sqrt[]{(x2-x1)^2+(y2-y1)^2} \\ r=\sqrt[]{(-1-2)^2+(-8-(-3))^2} \\ r=\sqrt[]{(-3)^2+(-8+3)^2} \\ r=\sqrt[]{(-3)^2+(-5)^2} \\ r=\sqrt[]{9+25} \\ r=\sqrt[]{34} \end{gathered}[/tex]then, we have that the equation of the circle is
[tex]\begin{gathered} (x-h)^2+(y-k)^2=r^2 \\ \text{where} \\ h=2 \\ k=-3 \\ r^2=(\sqrt[]{34})^2=34 \end{gathered}[/tex]therefore the equation is
[tex]\begin{gathered} (x-2)^2+(y-(-3))^2=34 \\ (x-2)^2+(y+3)^2=34 \end{gathered}[/tex]Kinetic energy varies jointly as the mass and the square of the velocity. A mass of 8 grams and velocity of 3 centimeters per second has a kinetic energy of 36 ergs. Find the kinetic energy for a mass of 4 grams and a velocity of 6 centimeters per second.
72 ergs
Explanation
Step 1
Kinetic energy varies jointly as the mass and the square of the velocity,then
[tex]E_k=\lambda\cdot m\cdot v^2[/tex]where
m is the mass, v is the velocity and
[tex]\lambda\text{ is a constant}[/tex]A mass of 8 grams and velocity of 3 centimeters per second has a kinetic energy of 36 ergs
[tex]\begin{gathered} E_k=\lambda m\cdot v^2 \\ 36\text{ erg=}\lambda\cdot8\cdot3^2 \\ 36=\lambda\cdot8\cdot9 \\ 36=\lambda\cdot72 \\ \text{divide both sides by 72} \\ \frac{36}{72}=\lambda \\ \lambda=\frac{1}{2} \end{gathered}[/tex]so, the equation is
[tex]\begin{gathered} E_k=\lambda\cdot m\cdot v^2 \\ E_k=\frac{1}{2}\cdot m\cdot v^2 \end{gathered}[/tex]Step 2
now , we know the equation to find the kinetic energy of a object if we know its mass and its velocity
Let
mass= 4 grams
velocity = 6 cms per sec
then
[tex]\begin{gathered} E_k=\frac{1}{2}\cdot m\cdot v^2 \\ E_k=\frac{1}{2}\cdot4gr\cdot(6\frac{\operatorname{cm}}{\sec})^2 \\ E_k=\frac{1}{2}\cdot4gr\cdot36\frac{\operatorname{cm}}{\sec ^2} \\ E_k=72\text{ erg} \end{gathered}[/tex]I hope this helps you
a shipping tube is shaped like a triangular prism the bases are equilateral triangles with edges of 5 in and a height of 4.3 in the tube is 14in long find the total surface area of the shipping tube
The figure is a triangular prism and the formular for total surface area of a triangular prism is represented below
[tex]\begin{gathered} \text{surface area = }bh+2ls+lb \\ \text{surface area=}(5\times4.3)+2(14\times5)+(14\times5) \\ \text{surface area=}21.5+140+70 \\ \text{surface area=}231.5in^2 \end{gathered}[/tex]You are comparing two savings accounts based on the interest you would earn and the fees they charge. Assuming you have a savings account with an average balance of $500, which combination of interest rates and fees are a better deal? (Hint: Using a one year period, determine the balance that you would have at Bank A and Bank B). O Bank A offers you a savings account with a 10% annual interest rate and $5/month in fees O Bank B offers you a savings account with 2% annual interest rate and no fees O The two banks deals are equivalent O Trick question -- it's a bad idea to open a savings account with just $500
Bank B gives the better deal to open the savings account rather than Bank A.
Given that:-
Average balance of savings account = $ 500
Annual interest rate of Bank A = 10 %
Fees of Bank A = $ 5/month
Annual interest rate of Bank = 2 %
We have to find which bank gives the better deal.
In Bank A, after one year the amount of money in my bank account will be:-
500 + 10 % of 500 - 5*12 = 500 + 50 - 60 = 500 - 10 = $ 490.
In Bank B, after one year the amount of money in my bank account will be:-
500 + 2 % of 500 = 500 + 10 = $ 510.
Hence,
Bank B gives the better deal to open the savings account rather than Bank A.
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Bentley and Arianys are reading the same book. At the beginning of the month, Bentley was on page 39 and Arianys was on page 19. Bentley will read 16 pages per day and Arianys will read 18 pages per day. Let BB represent the page of the book that Bentley is on at the end of tt days into the month, and let AA represent the page of the book that Arianys is on at the end of tt days into the month. Write an equation for each situation, in terms of t,t, and determine whether Bentley or Arianys is farther along in the book after 15 days.
a) An equation representing the number of pages of the book that Bentley is on at the end of t days is A = 39 + 16t.
b) An equation representing the number of pages of the book that Arianys is on at the end of t days is B = 19 + 18t.
c) Arianys is farther along in the book after 15 days than Bentley because Arianys is on page 289 of the book while Bentley lags on page 279.
What is an equation?An equation is a statement showing the equality of two or more mathematical expressions.
Equations are depicted using the equation symbol (=).
The pages of the book already covered by Bentley at the beginning of the month = 39
The pages of the book already covered by Arianys at the beginning of the month = 19
Bentley's reading speed per day = 16 pages
Arianys' reading speed per day = 18 pages
The page already read by Bentley = A
The page already read by Arianys = B
Equations:For the pages already read by Bentley, A = 39 + 16t
For the pages already read by Arinys, B = 19 + 18t
After 15 days, who has read more?
Bentley, A = 39 + 16t = 39 + 16(15) = 279 pages
Arianys, B = 19 + 18t = 19 + 18(15) = 289 pages
Thus, using equations, we can conclude that Arianys can conclude the book faster than Bentley if it takes up to 15 days in the month to complete the book.
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