The stem-and-leaf plot shows the weights (in pounds) of yellowfin tuna caught during a fishing contest.

Answer:

the data of the cubic

as it the distance between the two integers closed under addition

Answer:

39

Step-by-step explanation:

0.59 h + 0.98 b = 1041.37 - 79.37

h + b = 1300

Answer:

I would say it's d (sorry if im wrong)

Answer:

x = 0.6

Step-by-step explanation:

We use tangent because the given numbers are opposite and adjacent from x

So, tangent (x) = opposite/adjacent

tan(x) = 8.78/12

[tex]tan^{-1}(\frac{8.78}{12}) = x[/tex]

x = 0.631664

Round to nearest tenth:

x ~ 0.6

Answer:

37.69911184

Step-by-step explanation:

because circumference is equal to pi multiplied by diameter, you will not get the circumference with the radius times pi. in order to get the diameter, you multiply the radius by 2, because the diameter is the length across the circle. So the diameter of this circle is equal to 12. so simply multiply that number by pi (3.14) and there is your answer. Hope i helped.

Answer:

5M

Step-by-step explanation:

Answer:

BOGO ko sa math

Step-by-step explanation:

hahaha sorryyyyy

Answer:

See the attached

Step-by-step explanation:

I left last bits to you as it is about checking your understanding

Answer:

x-intercept

Step-by-step explanation:

Answer:

- 10 degrees Fahrenheit at 9:00 PM

Step-by-step explanation:

35 - 45 = -10

Answer:

hope this will help you more

good luck...

Answer:

[tex] \frac{ {x}^{ \frac{2}{3} } {y}^{ \frac{1}{3} } }{2} [/tex]

Answer C is correct

Step-by-step explanation:

[tex] \sqrt[3]{ \frac{ {x}^{2} }{8 {y}^{ - 1} } } \\ \frac{ {x}^{2 \times \frac{1}{3} } \times {y}^{1 \times \frac{1}{3} } }{ \sqrt[3]{8} } \\ = \frac{ {x}^{ \frac{2}{3} } {y}^{ \frac{1}{3} } }{2} [/tex]

Answer: 95%

Step-by-step explanation:

Answer:

I belive the answer for the first box is 9.67

I belive the answer for the second box is 71.

I hope I helped

Answer:

120 and 144

120÷24=5

144÷24=6

Answer:

y=−25x+300

Step-by-step explanation:

have a good day/night

may i please have a branlliest

Step-by-step explanation:

question 1

[tex]6 {x}^{4} - 36 {x}^{3} \\ 6 {x}^{3} (x - 6)[/tex]

question 2

[tex]64 {x}^{2} + 48x + 9 \\ {(8x + 3)}^{2} [/tex]

Answer:

[tex]x = \frac{50 + 92}{2} = 71[/tex]

Answer:

A{-4,-2,1,4} is the domain of function.

Answer:

946589196.155

Step-by-step explanation:

Hope that helps

Answer:

Solution given:

cotangent x=cot x=-1

now

x=cot -¹(-1)

x=180-45°

x=135°

So

ans is d. 135 degrees.

as cot is negative in 2nd quadrant.

Answer:log a - log b = log (a/b) than use this formula will get

log x^2 -log x = log (x^2 /x) = log x

so answer is log x

Step-by-step explanation:

Answer:

106°

Step-by-step explanation:

An isosceles triangle has 2 sides of the same length. All triangles add up to 180°

37 + 37 + x = 180

74 + x = 180

x = 106

Answer:

Its an Obtuse angles

Step-by-step explanation:

x+79=2x-37

(x+79)+(-79)=(2x-37)+(-79)

x+79-79=(2x-37)-79

x=2x-37-79

x=116

An obtuse angle has a measurement greater than 90 degrees but less than 180 degrees.

Answer:

Vector (ordered pair - rectangular form)

[tex]\vec F = (27.189,12.679)\,[lbf][/tex]

Vector (ordered pair - polar form)

[tex]\vec F = (30\,lbf, 25^{\circ})[/tex]

Sum of vectorial components (linear combination)

[tex]\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N][/tex]

Step-by-step explanation:

From statement we know that force exerted on the wagon has a magnitude of 30 pounds-force and an angle of 25° above the horizontal, which corresponds to the +x semiaxis, whereas the vertical is represented by the +y semiaxis.

The force ([tex]\vec F[/tex]), in pounds-force, can be modelled in two forms:

Vector (ordered pair - rectangular form)

[tex]\vec F = \left(\|\vec F\|\cdot \cos \theta, \|\vec F\|\cdot \sin \theta\right)[/tex] (1)

Vector (ordered pair - polar form)

[tex]\vec F = \left(\|\vec F\|, \theta\right)[/tex]

Sum of vectorial components (linear combination)

[tex]\vec {F} = \left(\|\vec F\|\cdot \cos \theta\right)\cdot \hat{i} + \left(\|\vec F\|\cdot \sin \theta \right)\cdot \hat{j}[/tex] (2)

Where:

[tex]\|\vec F\|[/tex] - Norm of the vector force, in newtons.

[tex]\theta[/tex] - Direction of the vector force with regard to the horizontal, in sexagesimal degrees.

[tex]\hat{i}[/tex], [tex]\hat{j}[/tex] - Orthogonal axes, no unit.

If we know that [tex]\|\vec F\| = 30\,lbf[/tex] and [tex]\theta = 25^{\circ}[/tex], then the force exerted on the wagon is:

Vector (ordered pair - rectangular form)

[tex]\vec F= \left(30\cdot \cos 25^{\circ}, 30\cdot \sin 25^{\circ}\right)\,[lbf][/tex]

[tex]\vec F = (27.189,12.679)\,[lbf][/tex]

Vector (ordered pair - polar form)

[tex]\vec F = (30\,lbf, 25^{\circ})[/tex]

Sum of vectorial components (linear combination)

[tex]\vec F = (30\cdot \cos 25^{\circ})\cdot \hat{i} + (30\cdot \sin 25^{\circ})\cdot \hat{j}\,[N][/tex]

[tex]\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N][/tex]

Answer:

A) 28 7/12, or 343/12, or 28.583

B) 57.75

C) 86.3 or 86 1/3

Step-by-step explanation:

Answer:

x=-6, y=1

Step-by-step explanation:

Let's solve your system by substitution.

y=x+7;−2x−11=y

Step: Solve y=x+7 for y:

y=x+7

Step: Substitute x+7 for y in −2x−11=y:

−2x−11=y

−2x−11=x+7

−2x−11+−x=x+7+−x(Add -x to both sides)

−3x−11=7

−3x−11+11=7+11(Add 11 to both sides)

−3x=18

−3x/ −3 = 18/ −3  (Divide both sides by -3)

x=−6

Step: Substitute−6 for x in y=x+7:

y=x+7

y=−6+7

y=1  (Simplify both sides of the equation)

Answer:

x=−6 and y=1