the radius of a circle is 1 what is the length of an arc that subtends an angle of 10pi/9 radians

The Radius Of A Circle Is 1 What Is The Length Of An Arc That Subtends An Angle Of 10pi/9 Radians

Answers

Answer 1

To convert from radians to degrees, you have to know that 180 degrees is equal to one pi

[tex]\frac{10\text{ pi}}{9}\text{ = }\frac{10X180^{\circ}}{9}=200^{\circ}[/tex]

Angle 360 -200 = 160

[tex]\begin{gathered} lengthofarc=\frac{\emptyset}{360}X\frac{2\pi\text{ r}}{1} \\ =\text{ }\frac{160}{360}X\frac{2\pi\text{ X 1 }}{1} \end{gathered}[/tex]

length of arc =2.7925

The length of the arc is approximately 2.8


Related Questions

Find the value of b please I’m having some trouble

Answers

Given:

The expression given is,

[tex]3-\frac{2}{9}b=\frac{1}{3}b-7[/tex]

Required:

To find the value of b.

Explanation:

We have the given expression as:

[tex]3-\frac{2}{9}b=\frac{1}{3}b-7[/tex]

Let us find the value of b.

[tex]\begin{gathered} 3-\frac{2}{9}b=\frac{1}{3}b-7 \\ \Rightarrow\frac{b}{3}+\frac{2b}{9}=3+7 \\ \Rightarrow\frac{3b+2b}{9}=10 \\ \Rightarrow\frac{5b}{9}=10 \\ \Rightarrow5b=9\times10 \\ \Rightarrow5b=90 \\ \Rightarrow b=\frac{90}{5} \\ \Rightarrow b=18 \end{gathered}[/tex]

Final Answer:

The value of b is,

[tex]b=18[/tex]

The value if b is b=18

find the measure of the angles in the following triangles.x=______missing angle measures:_______ ______

Answers

First, we have to use the interior angles theorem

[tex]x-2+72+x=180[/tex]

Then, we solve for x

[tex]\begin{gathered} 2x+70=180 \\ 2x=180-70 \\ 2x=110 \\ x=\frac{110}{2} \\ x=55 \end{gathered}[/tex]

Then, we use this value to find each angle

[tex]\begin{gathered} (x-2)=55-2=53 \\ x=53 \end{gathered}[/tex]Hence, the interior angles are 72°, 55°, and 53°

I need help with this question please1) Picture2) In(2x) + ln(7) = 4

Answers

1) We must solve for x the following equation:

[tex]e^{5x}=25.[/tex]

To solve this equation, we take the natural logarithm to both sides of the equation:

[tex]\begin{gathered} \ln (e^{5x})=\ln (25), \\ 5x\cdot\ln e=\ln 25. \end{gathered}[/tex]

Now, we use the following results:

[tex]\begin{gathered} \ln e=1, \\ \ln (25)=\ln (5^2)=2\cdot\ln 5. \end{gathered}[/tex]

Replacing these results in the equation above, we have:

[tex]5x=2\cdot\ln 5.[/tex]

Solving for x, we get:

[tex]x=\frac{2}{5}\cdot\ln 5\cong0.64.[/tex]

2) We must solve for x the following equation:

[tex]\ln (2x)+\ln (7)=4.[/tex]

To solve this problem, we isolate the part that involves the x:

[tex]\ln (2x)=4-\ln (7)\text{.}[/tex]

Now, using the following property:

[tex]\ln y=z\rightarrow y=e^z\text{.}[/tex]

with:

[tex]\begin{gathered} y=2x, \\ z=4-\ln 7. \end{gathered}[/tex]

we have:

[tex]\ln (2x)=4-\ln 7\rightarrow2x=e^{4-\ln 7}.[/tex]

Solving the last equation for x, we get:

[tex]x=\frac{1}{2}\cdot e^{4-\ln 7}\cong3.90.[/tex]

Answers

1) The value of x that solves the first equation is 0.64 to two decimal places.

2) The value of x that solves the second equation is 3.90 to two decimal places.

Review of the base of a logarithm

We can define the logarithm in base a through the following equations:

[tex]\begin{gathered} \log _aa=1, \\ \log _aa^x=x\cdot\log _aa=x\cdot1=x\text{.} \end{gathered}[/tex]

When we use as a base the Euler number e ≅ 2.718, the logarithm is called "natural" and we use the following notation for it:

[tex]_{}\log _e=\ln .[/tex]

With this notation, we have the following properties:

[tex]\begin{gathered} \ln e=1, \\ \ln e^x=x\cdot\ln e=x\cdot1=x\text{.} \end{gathered}[/tex]

solve2cos²x+3sin x=0

Answers

One of the most important trigonometric identities is the one below

[tex]\cos ^2x+\sin ^2x=1[/tex]

Then,

[tex]\Rightarrow\cos ^2x=1-\sin ^2x[/tex]

Use this result in the equation given by the problem

[tex]\begin{gathered} 2\cos ^2x+3\sin x=0 \\ \Rightarrow2(1-\sin ^2x)+3\sin x=0 \\ \Rightarrow2-2\sin ^2x+3\sin x=0 \end{gathered}[/tex]

Furthermore,

[tex]\begin{gathered} \Rightarrow2\sin ^2x-3\sin x-2=0 \\ \Rightarrow2\sin ^2x-3\sin x=2 \\ \Rightarrow\sin x(2\sin x-3)=2 \end{gathered}[/tex]

Set y=sinx

[tex]\begin{gathered} \Rightarrow y(2y-3)=2 \\ \Rightarrow y=-\frac{1}{2},y=2 \end{gathered}[/tex]

Thus,

[tex]\begin{gathered} \sin x=-\frac{1}{2},\sin x=2 \\ \Rightarrow\sin x=-\frac{1}{2} \\ \text{if sinx=2, then x is not a real number} \end{gathered}[/tex]

Finally,

[tex]\begin{gathered} \sin x=-\frac{1}{2} \\ \Rightarrow x=\sin ^{-1}(-\frac{1}{2})=-\frac{\pi}{6} \end{gathered}[/tex]

Then, the answer is

[tex]x=-\frac{\pi}{6}+2n\pi,\text{ n is an integer}[/tex]

The answer is x=-pi/6+2n*pi

pls today I have it for tomorrow​

Answers

Answer:

6/5 x 5/3 is 2

if that's what you need help with

step-by-step explanation

A sample has a mean of M = 90 and a standard devia-tion of s 20.=a. Find the z-score for each of the following X values.X = 95X = 80X = 98X = 88X = 105X = 76

Answers

Answer:

[tex]\begin{gathered} X=95,z=0.25 \\ X=80,z=-0.5 \\ X=98,z=0.4 \\ X=88,z=-0.1 \\ X=105,z=0.75 \\ X=76,z=-0.7 \end{gathered}[/tex]

Explanation:

Given a sample with the following:

• Mean,M = 90

,

• Standard deviation, s = 20

To find the z-score for each of the given X values, we use the formula below:

[tex]\begin{equation*} z-score=\frac{X-\mu}{\sigma}\text{ where }\begin{cases}{X=Raw\;Score} \\ {\mu=mean} \\ {\sigma=Standard\;Deviation}\end{cases} \end{equation*}[/tex]

The z-scores are calculated below:

[tex]\begin{gathered} \text{When X=95, }z=\frac{95-90}{20}=\frac{5}{20}=0.25 \\ \text{When X=80, }z=\frac{80-90}{20}=\frac{-10}{20}=-0.5 \\ \text{When X=98, }z=\frac{98-90}{20}=\frac{8}{20}=0.4 \end{gathered}[/tex][tex]\begin{gathered} \text{When X=88,}z=\frac{88-90}{20}=\frac{-2}{20}=-0.1 \\ \text{When X=105, }z=\frac{105-90}{20}=\frac{15}{20}=0.75 \\ \text{When X=76, }z=\frac{76-90}{20}=\frac{-14}{20}=-0.7 \end{gathered}[/tex]

factorize 5m^3-10m^2+8m+2

Answers

The expression 5m³ - 10m² + 8m + 2 cannot be factorized

How to factorize the polynomial?

From the question, the polynomial is given as

5m^3-10m^2+8m+2

Rewrite the polynomial properly

So, we have

5m³ - 10m² + 8m + 2

Next, we represent the above expression on a graph

From the attached graph, we can see that the polynomial expression only cross the x-axis at x = -0.197

This implies that the expression cannot be factored

So, we cannot further rewrite the given expression

Read more about factorized expressions at

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Solve for w.182- w = 252

Answers

Given the equation :

[tex]182-w=252[/tex]

solve for w, so:

subtract 182 from both sides:

[tex]\begin{gathered} 182-w-182=252-182 \\ \\ -w=70 \\ \end{gathered}[/tex]

multiply both sides by -1

[tex]w=-70[/tex]

So, the value of w = -70

55°Angle FGH is a right angle.The measure of angle FGJ is 559.The measure of angle JGH is xº.What is the value of x?toХS

Answers

Given angle FGH is a right angle. This means angle FGH is 90 degrees

But

The lowest airport in the world is Atyrau Airport in Kazakhstan at 72 feet below sea level. How would we represent this elevation using negative numbers? 6.NS.5

Answers

ANSWER

-72 ft

EXPLANATION

We can draw a number line:

If the 0 of the number line is sea level, we would normally say that all positive numbers are those that are above sea level and negative numbers those that are below sea level.

Therefore, to represent an elevation that is below sea level, we'd write it as a negative number: -72 ft

Complete the general solution to [tex]y = arcsin - \frac{ \sqrt{3} }{2} [/tex]y=___+-2πkSelect all that apply.π/3(2π)/3(4π)/3(5π)/3

Answers

To find the general solution to y we need take the sine function in both sides of the equation given:

[tex]\begin{gathered} \sin y=\sin (\sin ^{-1}-\frac{\sqrt[]{3}}{2}) \\ \sin y=-\frac{\sqrt[]{3}}{2} \end{gathered}[/tex]

Now, we have to find the value of y for which the sine function is equal to the right side. From the properties of the sine function and its definition we conclude that y has to be:

[tex]y=\frac{5\pi}{3}[/tex]

Therefore the general solution is:

[tex]y=\frac{5\pi}{3}\pm2\pi k[/tex]

What are the coordinates of vertex C'after rotating the figure 180° about theorigin?у6BID42A АEXo024 6A. (-6,4)B. (4.-6)C. (4,6)D. (-4,-6)

Answers

Vertex C (4, 6 ) Rotation 180º about the origin CCW c' (-4, -6)

C (x, y ) C ' (-x, -y )

________________

Answer

Option D

The textbook isn't helping with the screenshot problem below.

Answers

From the frequency distribution, the measures are given as follows:

a) Total number of observations: 27.

b) The width of each class is of 5.

c) The midpoint of the second class if of 20.5.

d) The modal class is Class 12 - 17.

e) If another class was added, the limits would be 48 - 53.

What is represented by the frequency distribution?

The frequency distribution gives the number of observations that is located in each class.

Hence the total number of observations is given by the sum of the frequencies, as follows:

Total = 9 + 1 + 3 + 8 + 6 = 27.

The modal class is class with the highest number of observations, hence it is of:

Class 12-17.

The width of a class is given by the subtraction of the limits, hence:

Width = 47 - 42 = ... = 23 - 18 = 17 - 12 = 5.

For an added class, the lower bound would be one more than the last class, while the upper bound would be five added to the lower bound, hence the limits are:

48 - 53.

The midpoint of each class is given by the mean of the coordinates, hence, for the second class, it is of:

Midpoint = (18 + 23)/2 = 41/2 = 20.5.

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Hi how are you today can you please help me with this question

Answers

$ 119.607

Explanation

we can easily solve this by using a rule of three

Step 1

Let

actual price(2020)=price of 2019 + 2%

so

actual price(2020)= 102 % and

price ( 2019)=100 %

let x represents the cost for 2019, so

[tex]\begin{gathered} \text{if} \\ 122\Rightarrow\text{ 102\%} \\ x\text{ }\Rightarrow\text{ 100 \%} \end{gathered}[/tex]

the proportion would be

[tex]\begin{gathered} \frac{122}{102\text{ \%}}=\frac{x}{100\text{ \% }} \\ \text{ Multiply both sides by 100 \%} \\ \frac{122}{102\text{ \%}}\cdot100=\frac{x}{100\text{ \% }}\cdot100 \\ 119.607=x \end{gathered}[/tex]

therefore, the cost in January of 2019 is

$ 119.607

I hope this helps you

What is the surface area of the following solid? *13 ft 12ft 5ft 5ft

Answers

In order to calculate the total surface area we just need to sum the area of the different faces.

From the picture we see that we have the following faces.

- 2 x A (two triangles)

- S (a rectangle)

- T (a rectangle)

- B (the base rectangle)

Now me calculate the area of each one:

[tex]A\text{ = }\frac{1}{2}\cdot12\cdot5\text{ = }30[/tex]

[tex]S\text{ = 5}\cdot5=\text{ 25}[/tex][tex]B=12\cdot5=60[/tex][tex]T=13\cdot5=65[/tex]

Now that we have the area of each face, we sum all the areas, taking in account the ones that appears twice:

[tex]\text{Total area = 2}\cdot A+S+T+B=2\cdot30+25+60+65=210[/tex]

And, because the lenghts are measured in ft, the final answer is:

[tex]\text{Total area = 210 ft}^2[/tex]

Note:

[tex]\text{Area of a triangle = }\frac{1}{2}\cdot\text{base}\cdot\text{height}[/tex][tex]\text{Area of a rectangle = base }\cdot\text{ height}[/tex]

Is 128 degrees plus 62 degrees supplementary or complimentary?

Answers

Let's begin by identifying key information given to us:

One angle = 128 degrees, Second angle = 62 degrees

Complementary angle are angles that sum up to 90 degrees

Supplementary angles are angles that sum up to 180 degrees

We will proceed to sum these two angles together. We have:

[tex]\begin{gathered} 128^{\circ}+62^{\circ}=180^{\circ} \\ \therefore These\text{ angles are supplementary angles since they sum up to 180 degr}ees \end{gathered}[/tex]

Therefore, these angles are supplementary angles since they sum up to 180 degrees

What should be true about the line of best fit? Check all that apply.


A. The line of best fit must have an equal number of points above and below the line.

B. The line must show the relationship between the two variables.

C. The line of best fit should minimize the distance between itself and the data points.

D. The line of best fit has to cross through at least 2 points in the scatter plot.

E. The line of best fit could be used as a prediction tool showing a trend in the data.

F. The line of best fit should be an exact representation of the data points.

Answers

The line of best fit could be used as a prediction tool showing a trend in the data and the line of best fit should minimize the distance between itself and the data points thus options (C) and (E) will be correct.

What is a graph?

The graph is a geometrical representation of a function and can be plotted by taking x's and y's corresponding values within the interval.

For example plot of y = x³ ,y = sinx.

A scatter point represents the relation or function.

If a line is used to predict the function then the distance between the points to the line must be minimized.

The line is useful for the representation of the data point.

Hence "The line of best fit could be used as a prediction tool showing a trend in the data and the line of best fit should minimize the distance between itself and the data points".

To learn more about graphs,

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how many hours, x, do they run?

Answers

We know that

• Sean runs 6 miles per hour (rate).

,

• Sean's initial condition is 0.25 miles.

,

• Darryl runs 0.7 miles per hour faster than Sean (we have to sum).

Sean's expression would be 6x + 0.25.

Darryl's expression would be 6x + 0.7x = 6.7x.

Now, we make them equal

[tex]6x+0.25=6.7x[/tex]Hence, the right answer is C.

Assume the random variable X has a binomial distribution with the given probability of obtaining a success. Find the following probability, given the number of trials andthe probability of obtaining a success. Round your answer to four decimal places.P(X ≤ 4), n = 8, p = 0.4

Answers

Answer: [tex]\text{P\lparen X \le4\rparen is 0.8263}[/tex]Explanation:

Given:

n = 8, p = 0.4

To find:

P(X ≤ 4)

To determine the given probability, we will apply the binomial probability formula:

[tex]\begin{gathered} $$P(x=X)=^nC_x\times p^x\times q^{n-x}$$ \\ n\text{ = number of trials} \\ p\text{ = number of success} \\ q\text{ = number of failure} \end{gathered}[/tex][tex]P\left(X≤4\right)\text{ = P\lparen x = 0\rparen + P\lparen x = 1\rparen + P\lparen x =2 \rparen + P\lparen x = 3\rparen + P\lparen x = 4\rparen}[/tex][tex]\begin{gathered} p\text{ + q = 1} \\ q\text{ = 1- p} \\ q\text{ = 1 - 0.4} \\ q\text{ = 0.6} \\ \\ P(x=0)=\text{ }^8C_0\times(0.4)^0\times(0.6)^{8-0} \\ P(x\text{ = 0\rparen = 0.01679616} \\ \\ P(x=1)=\text{ }^8C_1\times(0.4)^1\times(0.6)^{8-1} \\ P(x\text{ = 1\rparen = 0.08957952} \end{gathered}[/tex][tex]\begin{gathered} P(x=2)=\text{ }^8C_2\times(0.4)^2\times(0.6)^{8-2} \\ P(x\text{ = 2\rparen = 0.20901888} \\ \\ P(x=3)=\text{ }^8C_3\times(0.4)^3\times(0.6)^{8-3} \\ P(x\text{ = 3\rparen = 0.27869184} \\ \\ P(x=4)=\text{ }^8C_4\times(0.4)^4\times(0.6)^{8-4} \\ P(x\text{ = 4\rparen = 0.2322432} \end{gathered}[/tex][tex]\begin{gathered} P(X≤4)\text{ = 0.01679616 + 0.08957952 + 0.20901888 + 0.27869184 + 0.2322432} \\ \\ P\left(X≤4\right)\text{ = 0.8263296} \\ \\ To\text{ 4 decimal place, P\lparen X \le4\rparen is 0.8263} \end{gathered}[/tex]

Select the Coordinate point that is not a solution to the given system of linear inequalities. 3x + 5y 2-15 3x + y > 3

Answers

3x + 5y ≥ -15 (1)

3x - y > 3 (2)

From (1) let's solve for x:

3x + 5y ≥ -15

Subtract 5y from both sides:

3x ≥ -15 - 5y

Divide both sides by 3:

x ≥ -5 - 5y/3 (3)

Replace (3) into (2)

3(-5 - 5y/3) - y > 3

Using distributive property:

-15 - 5y - y > 3

-15 - 6y > 3

Solving for x:

Add 15 to both sides:

-6y > 18

Divide both sides by -6:

y < -3

Replacing y into (3)

x ≥ 0

3x - y > 3

if x = 4 and y =9

3*4 - 9 >3

12 - 9 > 3

3 > 3

this is false because 3 = 3

Suppose a city's population grows by 5% each year. How long will it take for the population of the city to triple? Answer to the nearest hundredth of a year.

Answers

Since it is given that the population grows by 5% each year, it follows that the Exponential Growth Function is the appropriate function that can be used to model the problem.

The Exponential Growth Function is given by:

[tex]y=a(1+r)^t[/tex]

Where

• a is the initial amount.

,

• r is the percent of increase in decimal.

,

• t is the time.

,

• y is the amount after time t.

Since we want when the initial population will triple, substitute y=3a into the equation:

[tex]3a=a(1+r)^t[/tex]

Substitute r=5%=0.05 into the equation:

[tex]3a=a(1+0.05)^t[/tex]

Solve the resulting equation for t:

[tex]\begin{gathered} 3a=a(1+0.05)^t \\ \Rightarrow a(1+0.05)^t=3a \\ \Rightarrow a(1.05)^t=3a \\ Divide\text{ both sides by a:} \\ \Rightarrow(1.05)^t=3 \\ \text{Take logarithm of both sides:} \\ \Rightarrow\ln (1.05)^t=\ln 3 \\ \Rightarrow t\ln (1.05)=\ln 3 \\ \Rightarrow t=\frac{\ln 3}{\ln (1.05)}\approx22.52\text{ years} \end{gathered}[/tex]

The population will triple after about 22.52 years.

14. Which points are on the graph by = 3x - 12? Select all that apply. (A) (B) (C) (D) (-2,0) (0,-2) (6,-3) (8,2) M 23 hp

Answers

6y=3x-127

Replace the values of x , y in the equation by the coordinates values given on each option, and check if the equality remains.

A. (x,y) = (-2,0)

6y=3x-127

6(0) =3(-2)-127

0 = -6-127

0= -133

zero is not equal to -133.

A. is not

B. (0,-2)

6(-2) = 3(0)-127

-12 = -127

B is not

C, (6,-3)

6(-3) = 3(6)-127

-18 = 18-127

-18 = -109

C is not

D (8,2)

6(2) = 3(8)-127

12 = 24-127

12=-103

D is not

None of the points are in the graph

Hi thank you so for all your time and help in advance

Answers

Question:

Solution:

Remember the following definition :

[tex]\cos (x)=\frac{adjacent\text{ side to the angle x }}{hypotenuse}[/tex]

thus, if:

[tex]\cos (x)=\frac{adjacent\text{ side to the angle x }}{hypotenuse}=\frac{\sqrt[]{3}}{2}[/tex]

then, according to the given triangles in the problem, the only angle that fulfills this, is:

[tex]x=30[/tex]

so that, the correct answer is:

[tex]x=30[/tex]

you're planning to supply cookies for a staff party. You're thinking of purchasing platters and cookies containing 80 sugar cookies and 15 chocolate chip cookies. what is the ratio of sugar cookies to chocolate chip cookies?

Answers

We have the following:

To calculate the proportion, we must calculate the quotient between sugar cookies and chocolate chip cookies, as follows

[tex]\frac{80}{15}=\frac{16\cdot5}{3\cdot5}=\frac{16}{3}[/tex]

Which means that for every 3 chocolate chip cookies there are 16 sugar cookies.

units givenQuestion 2 (3 points)toUsing the Rectangular Prism in the picture, find the Lateral Area, the Area of a Single Base,and the TOTAL Surface Area:.12 cm825 cm10 cmUse the face with dimensions 10cm x 5cm as the base.Lateral Area =cm²Single Base Area =64188 in48cm²

Answers

Solution:

Given the rectangular prism;

Where;

[tex]\begin{gathered} length,l=10cm \\ \\ width,w=5cm \\ \\ height,h=2cm \end{gathered}[/tex]

Thus, the lateral area, L is;

[tex]\begin{gathered} L=2(l+w)h \\ \\ L=2(10+5)2 \\ \\ L=4(15) \\ \\ L=60cm^2 \end{gathered}[/tex]

ANSWER:

[tex]Lateral\text{ }Area=60cm^2[/tex]

Also, the single base area, B, is;

[tex]\begin{gathered} B=l\times w \\ \\ B=10\times5 \\ \\ B=50cm^2 \end{gathered}[/tex]

ANSWER:

[tex]Single\text{ }Base\text{ }Area=50cm^2[/tex]

Then, the surface area, S, is;

[tex]\begin{gathered} S=L+2B \\ \\ S=60+2(50) \\ \\ S=60+100 \\ \\ S=160cm^2 \\ \\ \end{gathered}[/tex]

ANSWER:

[tex]Surface\text{ }Area=160cm^2[/tex]

You roll two 4-sided number cubes. Let X be the sum of the numbers on the two cubes P(X=3)

Answers

Notice that, since we are rolling two dices, we are dealing with 2 independent events

Let's suppose that the numbers on each dice are 1,2,3,4.

Then, if we roll two dices, there are 16 possible pairs (in principle)

(1,1)

(1,2)

...

(1,4)

(2,1)

...

(4,4)

Each of those pairs is equally probably than the others

Know, we need to identify the pairs that add up 3:

(1,2) and (2,1) are the only possibilities

Finally, we obtain the probability:

[tex]P(x=3)=\frac{2}{16}=\frac{1}{8}=0.125[/tex]

Which is none of the options.

Another possibility is that the dices are cubes:

So, the possible combinations that can be obtained by throwing 2 cubes are:

(1,1)...(1,6),(2,1),...(6,6) Which are 36 possible combinations

And there are only 2 combinations that add up to 3: (2,1),(1,2)

So, the probability of adding up 3 is:

[tex]P(x=3)=\frac{2}{36}=\frac{1}{16}=0.0625[/tex]

The number of fish in a fish tank doubles each week. The function y=equals 3 (2)^x represents the population, where X is the number of one week periodsa. Describe the domains and range of the function. Then graph the functionb. Find and interpret the y intercept c. How many fish are in the tank at the end of first week?d. How many fish are in the tank after 4 weeks?

Answers

a. The domain of the function is the set of values of the independent variable (x) on which the function acts, in this case, the independent variable is time, since the time can only take positive values, the domain would be [0,∞) or x≥0.

The range is all the possible values that the dependent variable can take, in this case, the dependent variable is the population of fish, then it can't be a negative number, since you can't have for example -1 fish, then, again, the interval would be [0,∞) or y≥0

A graph of the function looks like this:

b. We can find the y-intercept by making x equals 0 in the formula of the function, like this:

y= 3*(2)^x

y= 3*(2)^0

y= 3*1, since any number raised to zero equals 1

y=3

Since x equals zero represents the initial time, the y-intercept represents the initial population of fish, then at the beginning, there were 3 fish.

c. We just have to replace 1 for x, and then calculate y, like this:

y= 3*(2)^x

y= 3*(2)^1

y= 3*(2)

y=6

At the end of the first week, there will be 6 fish.

d. Now, we just have to replace 4 for x, like this:

y= 3*(2)^4

y= 3*16

y=48

Then, after 4 weeks, there will be 48 fish

Help me with math and explain it with a Quick solution By explaining the you answer

Answers

EXPLANATION

Given the points (x_1,y_1) = (-9,2) and (x_2,y_2) = (-4,2)

We can apply the distance formula in order to get the distance between them as shown as follows:

[tex]\text{distance}=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Replacing terms:

[tex]\text{distance}=\sqrt[]{(-4-(-9))^2+(2-2)^2}[/tex]

Adding numbers:

[tex]\text{distance}=\sqrt[]{(5)^2+(0)^2}[/tex]

Computing the powers:

[tex]\text{distance}=\sqrt[]{25}=5[/tex]

Hence, the distance is equal to 5 units.

write the ratio of the first measurement. make sure to simply if possible

Answers

1. Ratio of 10 feet to 5 yards

A yard is equvalent to 3 feet

So we can say that ratio of 10 feet to 5 yards is the same as ratio of 10 feet to 5x3 feet, which is:

ratio of 10 feet to 15 feet = 10/15

10/15 simplified by dividing both numerator and denominator by 5:

2/3

Answer:

2/3

[tex]\frac{2}{3}[/tex]

Which of the following is equivalent to a rhombus? *O A rectangle with congruent diagonalsA parallelogram where opposite angles are congruentA parallelogram with two consecutive congruent sidesA quadrilateral where consecutive angles are supplementary

Answers

A parallelogram with two consecutive congruent sides.

1) Since a rhombus is a quadrilateral with 4 congruent sides. Then we can examine the options and state that

2) Given that a rhombus has congruent opposite angles, with four congruent sides.

3) The answer is

A parallelogram with two consecutive congruent sides.

With two consecutive sides, the whole polygon will have congruent sides.

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