The hypotenuse of a right triangle is 1 centimeter longer than the longer leg. The shorter leg is 7 centimeters shorter than the longer leg. Find the length of the shorter leg of the triangle.

Answers

Answer 1

Answer:

[tex]\text{Shorter leg= 5cm}[/tex]

Step-by-step explanation:

As a first step to go into this problem, we need to make a diagram:

Let x be the measure of the longer leg.

Now, understanding this we can apply the Pythagorean theorem to find x, it is represented by the following equation:

[tex]\begin{gathered} a^2+b^2=c^2 \\ \text{where,} \\ a=\text{longer leg} \\ b=\text{shorter leg} \\ c=\text{hypotenuse } \end{gathered}[/tex]

Substituting a,b, and c by the expressions corresponding to its sides:

[tex]\begin{gathered} x^2+(x-7)^2=(x-1)^2 \\ \end{gathered}[/tex]

apply square binomials to expand and gather like terms, we get:

[tex]\begin{gathered} x^2+x^2-14x+49=x^2-2x+1 \\ 2x^2-x^2-14x+2x+49-1=0 \\ x^2-12x+48=0 \end{gathered}[/tex]

Now, factor the quadratic equation into the form (x+?)(x+?):

[tex]\begin{gathered} (x-4)(x-12)=0 \\ x_1=4 \\ x_2=12 \end{gathered}[/tex]

This means, the longer leg could be 4 or 12, but if we subtract 7 to 4, we get a negative measure for the shorter leg, that makes no sense.

Therefore, the long leg is 12 cm.

Hence, if the shorter leg is 7 centimeters shorter than the longer leg:

[tex]\begin{gathered} \text{Shorter leg=12-7} \\ \text{Shorter leg=}5\text{ cm} \end{gathered}[/tex]

The Hypotenuse Of A Right Triangle Is 1 Centimeter Longer Than The Longer Leg. The Shorter Leg Is 7 Centimeters

Related Questions

GEOMETRY: Express the volume of each cube below as a monomialNeeded fast!

Answers

Remember that

The volume of a cube is equal to

[tex]V=b^3[/tex]

where b is the long side of the cube

so

Part 19

we have that

[tex]b=7c^6d^2[/tex]

substitute in the formula

[tex]V=(7c^6d^2)^3[/tex]

Applying property of exponents

[tex]\begin{gathered} V=(7^3)(c^{(6\cdot3)})(d^{(2\cdot3)}) \\ V=342c^{(18)}d^6 \end{gathered}[/tex]

Part 20

we have

[tex]b=6r^7s^8[/tex]

substitute in the formula

[tex]\begin{gathered} V=(6r^7s^8)^3 \\ V=216r^{(21)}s^{(24)} \end{gathered}[/tex]

5 times 5 I need help solving that one

Answers

5 times 5 = 5 x 5

= 25

Answer : 25

Flying against the wind, an airplane travels 2010 kilometers in 3 hours. Flying with the wind, the same plane travels 10,530 kilometers in 9 hours. What is the rate of the plane in still air and what is the rate of the wind?

Answers

it is given that,

the distance travel against wind = 2010

time = 3 hrs

so, the relative speed is = distance/ time = 2010/3 = 670 km/hr

the distance travel with wind is 10,530

time 9 hrs

so,the relative speed is,= 10 530/9 = 1170 km/hr

let a = speed of plane ,

b = speed of wind

so, when plane travel with wind the the relative speed is ,

a + b = 1170

when travel against wind then the relative speed,

a - b = 670

sum the equation

a + b + a - b = 1170 + 670

2a = 1840

a = 920

put a = 920 in equation a + b = 1170

920 + b = 1170

b = 1170 - 920

b = 250

thus, the rate of plane is 920

rate of wind is 250

How do I know if 6.209 is greater or lesser than 6.29

Answers

Since,

[tex]6.29-6.209=0.081[/tex]

The difference gives us a positive value.

So, 6.29 is grater than 6.209

Answer: Add a 0 to 6.29 and compare the numbers to see which one is greater

6.29  (or 6.290) is greater than 6.209 since the hundrenth in 6.29 is 9 and the other hundrenth for 6.209 is 0.

-2/5 divide (-3) multiply and reduce to lowest terms.

Answers

Answer:

2/15

Explanation:

Given the expression:

[tex]-\frac{2}{5}\div(-3)[/tex]

First, change the division sign to times by taking the reciprocal of the number after the sign:

[tex]=-\frac{2}{5}\times-\frac{1}{3}[/tex]

Next, multiply the numerators and denominators:

[tex]\begin{gathered} =\frac{(-2)\times(-1)}{5\times3} \\ =\frac{2}{15} \end{gathered}[/tex]

The fraction is already in its lowest form as required.

Which relation is a function?

Answers

Answer:

The left upper one is a function

Step-by-step explanation:

If you draw a straight vertically and the line goes through two point then its not a function. Just look what makes a function or answer again if you are confused.

The relation which is a function is f ( x ) = x³

What is a function rule?

The function rule is the relationship between the input or domain and the output or range. A relation is a function if and only if there exists one value in the range for every domain value.

A function is a relation from a set of inputs to a set of possible outputs where each input is related to exactly one output.

Given data ,

Let the function be represented as f ( x )

Now , the value of f ( x ) is

y = x³   be equation (1)

Now , relation is a function if and only if there exists one value in the range for every domain value.

So , when x = { 1 , 2 , 3 , 4 }

The values of y are = { 1 , 8 , 27 , 64 }

Hence , the function is y = x³ and the graph is plotted

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help my brother the other one I tried was a scam

Answers

1. Given the integers a and b, a common multiple is a positive integer that is divisible by both a and b.

2. The Least Common Multiple (LCM ) is the smallest positive integer that is divisible by both a and b.

3. Multiples of 6: 6 (= 6x1), 12 (= 6x2), 18 (= 6x3), 24 (= 6x4), ...

Multiples of 4: 4 (= 4x1), 8 (= 4x2), 12 (= 4x3), 16 (= 4x4), ...

The smallest number of these two lists is 12, then the LCM between 6 and 4 is 12.

The sum of two numbers is30. The sum of4 times the larger and6 times the smaller is128. Find the numbers.

Answers

let

the smaller number = x

the larger number = y

x + y = 30

4y + 6x = 128

[tex]\begin{gathered} x+y=30 \\ 4y+6x=128 \\ x=30-y \\ 4y+6(30-y)=128 \\ 4y+180-6y=128 \\ -2y=128-180 \\ -2y=-52 \\ y=\frac{52}{2} \\ y=26 \\ x+y=30 \\ x+26=30 \\ x=30-26 \\ x=4 \end{gathered}[/tex]

The numbers are 4 and 26.

Three cards are drawn from an ordinary deck and not replaced find the probability of the following P(getting 3 queens)P(getting an ace and king and queen)P(getting club and spade and heart)P(getting 3 diamonds)Answer the following problems using multiplication rule make sure to reduce your fraction

Answers

a) P(3 queens) ) = 4/52*3/51*2/50 = 1/5525

b) P(ace,king, queen) = 4/52*4/51*4/50 = 8/16575

c) P( ) = 10/52 * 10/51*10/50 = 5/663

d) P(3 diamonds) = 10/52 * 9/51* 8/50 = 6/1105

what is five plus two

Answers

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data:

five plus two

Step 02:

addition:

5 + 2 = 7

The answer is:

7

What type of number is 3 - 77iChoose all answers that apply:A. RealB. ImaginaryC. Complex

Answers

[tex]\begin{gathered} \Rightarrow3-77i \\ When\text{ the number is having i, then it is treated as the imaginary number.} \end{gathered}[/tex]

The solutions to a quadratic equation are -2 and 6. What is the equation of its axisof symmetry?

Answers

General form of a quadratic equation is

[tex]ax^2+bx+c=0[/tex]

another form is

[tex](x+h)(x+k_{})=0[/tex]

where h and k are the number opposite by the sign of the solutions, then on this case the values of h and k are 2 and -6

[tex](x+2)(x-6)=0[/tex]

Our equatio is a parabola then if we find the vertex we are finding the axis of simmetry

to find the vertex we trasnforme ou equation to the general form of a quadratic equation multipliying parenthesis

[tex]\begin{gathered} (x\times x)+(x\times-6)+(2\times x)+(2\times-6)=0 \\ x^2-6x+2x-12=0 \\ x^2-4x-12=0 \end{gathered}[/tex]

now take the equation and derivate

[tex]\begin{gathered} 2x-4-0=0 \\ 2x-4=0 \end{gathered}[/tex]

if we solve x we find the coordinate x of the vertex and the axis of simmetry

then

[tex]\begin{gathered} 2x-4=0 \\ 2x=4 \\ x=\frac{4}{2} \\ \\ x=2 \end{gathered}[/tex]

axis of Symmetry is x=2

find the slope of the line

Answers

Solution

We can use the following points from the graph:

(0,-2) and (2,1)

And we can find the slope on this way:

[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{1+2}{2-0}=\frac{3}{2}[/tex]

Then we can find the intercept on this way:

1= 3/2 (2)+b

b= 1-3= -2

Then the equation would be:

y= 3/2 x -2

use the equation and type the ordered-pairs.y=3^x[(-1,_),(0,_),(1,_),(2,_),(3,_),(4,_)]

Answers

Given the equation :

[tex]y=3^x[/tex]

we need to complete the order pairs :

[(-1,_),(0,_),(1,_),(2,_),(3,_),(4,_)]​

So, for each value of x, we will find the corresponding value of y

[tex]\begin{gathered} x=-1\rightarrow y=3^{-1}=\frac{1}{3} \\ \\ x=0\rightarrow y=3^0=1 \\ \\ x=1\rightarrow y=3^1=3 \\ \\ x=2\rightarrow y=3^2=9 \\ \\ x=3\rightarrow y=3^3=27 \\ \\ x=4\rightarrow y=3^4=81 \end{gathered}[/tex]

So, the answer is : the order pairs will be :

[tex](-1,\frac{1}{3}),(0,1),(1,3),(2,9),(3,27),(4,81)[/tex]

Which of the following is a solution to the quadratic equation below?x²-3x-54-0A. 9B. -57C. 2D. 27

Answers

A. 9

Explanation

to solve for x we can use the quadratic formula

it says

[tex]\begin{gathered} for \\ ax^2+bc+c=0 \\ the\text{ solution for x is} \\ x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \end{gathered}[/tex]

hence

Step 1

a) let

[tex]\begin{gathered} x^2-3x-54=0\Rightarrow ax^2+bx+c=0 \\ so \\ a=1 \\ b=-3 \\ c=-54 \end{gathered}[/tex]

b) now, replace in the formula and evaluate

[tex]\begin{gathered} x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \\ x=\frac{-(-3)\pm\sqrt{(-3)^2-4(1)(-54)}}{2(1)} \\ x=\frac{-(-3)\pm\sqrt{9+216}}{2}=\frac{3\pm\sqrt{225}}{2} \\ x=\frac{3\pm15}{2} \end{gathered}[/tex]

so

[tex]\begin{gathered} x_1=\frac{3+15}{2}=9 \\ x_2=\frac{3-15}{2}=-6 \end{gathered}[/tex]

therefore, the answer is

A. 9

I hope this helps you

A regular hexagon has perimeter 72m. Find the area

Answers

A regular hexagon has six equal sides:

If you notice, a regular hexagon has exactly six equilateral triangles inside of it.

So, to find the area we could find the area of a triangle and then multiply this result by 6. This seems to be a little bit complicated to do, so, there's a formula to find the area of a regular hexagon, which is:

[tex]\begin{gathered} A=\frac{3\sqrt{3}s^2}{2} \\ Where: \\ s:Measure\text{ of a side of the regular hexagon} \end{gathered}[/tex]

We know that the measure of any side of our regular hexagon equals 12m, so, we could just replace in the equation:

[tex]A=\frac{3\sqrt{3}(12m)^2}{2}\rightarrow A=\frac{3\sqrt{3}(144m^2)}{2}\rightarrow A=216\sqrt{3}m^2[/tex]

Simplified, that's about 374.1 m2.

I have been stuck on this for a while, your help would be most appreciated!

Answers

Answer:I Don't Know What She Said

Step-by-step explanation:

Question: What is the solution to this system of linear equations? 8x + 2y = 2 and x + 3y 2 = 14 I NEED The claim, evidence and reasoning. Please I need help

Answers

[tex]\begin{gathered} 8x+2y=2\ldots\ldots.(1) \\ x+3y=14 \\ x=14-3y\ldots\text{.}(2) \\ \text{Substitute the value of x in equation (1).} \\ 8(14-3y)+2y=2 \\ 112-24y+2y=2 \\ 112-2=22y \\ y=5 \\ Now,\text{ from equation (2)} \\ x=14-3y \\ x=14-3\times5 \\ x=14-15 \\ x=-1 \\ \text{So, the solution is(-1,5).} \end{gathered}[/tex]

what is four fiths minus 6 fiftheens

Answers

what is four fiths minus 6 fiftheens ​

we have

4/5-6/15

Multiply by 3/3 fraction 4/5

4/5(3/3)=12/15

substi

What is the value of y in the equation 2(2y − 16) = 0? (5 points)4689

Answers

Given the following equation,

[tex]\text{ 2\lparen2y - 16\rparen = 0}[/tex]

Let's determine the value of y.

[tex]\text{ 2\lparen2y - 16\rparen = 0}[/tex][tex]\text{ }\frac{2(2y\text{ - 16\rparen}}{2}\text{ = 2}[/tex][tex]\text{ 2y - 16 = 0}[/tex][tex]\text{ 2y = 16}[/tex][tex]\text{ }\frac{2y}{2}\text{ = }\frac{16}{2}[/tex][tex]\text{ y = 8}[/tex]

Therefore, y = 8

The answer is 8.

PLEASE HELP 15 POINTS I'M GIVING BRAINLIEST

Answers

Answer:

below

Step-by-step explanation:

In a RIGHT triangle such as this, cos = adjacent leg / hypotenuse

cos (beta)   = 22/24 =  11/12

What is the value of X?

Answers

Check the picture below.

Make sure your calculator is in Degree mode.

two numbers have a sum of -10 and a difference of -2 what is the product of numbers

Answers

let 'x' and 'y' be two numbers that have a sum of -10 and a difference of -2, then, we have the following system of equations:

[tex]\begin{gathered} x+y=-10 \\ x-y=-2 \end{gathered}[/tex]

notice that if we add both equations at the same time, we get:

[tex]\begin{gathered} x+y=-10 \\ x-y=-2 \\ --------- \\ 2x=-12 \\ \Rightarrow x=\frac{-12}{2}=-6 \\ x=-6 \end{gathered}[/tex]

now that we have that x = -6, we can find the value of y substituting x = -6 on any equation:

[tex]\begin{gathered} -6+y=-10 \\ \Rightarrow y=-10+6=-4 \\ y=-4 \end{gathered}[/tex]

therefore, x = -6 and y = -4. Next, we have that the product is (-6)(-4) = 24

In a painting of the Mona Lisa, the length of the painting is 4 - inches, Milo scales the drawing up by 2 What is the length of the scaled copy?

Answers

Wee, it he is scalaing the painting by two the new length must be twice the original length.

length = 2 x 4 = 8 in

New length = 8 in

Blair purchases the T-shirts from Company B. She needs to add a 75markup to her total cost to make a profit when she sells the shirts at thcarnival. How should Blair determine the selling price of each T-shirt athe carnival?Drag a number into each box to make the statements true.She canThe total cost Blair paid for one T-shirt is $calculate the markup by multiplying her total cost byBlair will sell each T-shirt at the carnival for $

Answers

[tex]\text{ markup \% = }\frac{\text{ selling price - cost}}{\text{ cost}}\cdot100[/tex]

Isolating selling price,

[tex]\begin{gathered} \frac{\text{ markup \% }}{100}\text{= }\frac{\text{ selling price - cost}}{\text{ cost}} \\ \frac{\text{ markup \% }}{100}\cdot\cos t=\text{selling price - cost} \\ \frac{\text{ markup \% }}{100}\cdot\cos t+cost=\text{selling price} \\ \cos t(\frac{\text{ markup \% }}{100}+1)=\text{ selling price} \end{gathered}[/tex]

The markup is 75 %. Supposing that the cost of a T-shirt is $6.00, then the selling price will be:

[tex]\begin{gathered} \text{selling price = 6.00}\cdot(\frac{75}{100}+1) \\ \text{selling price = 6.00}\cdot(0.75+1) \\ \text{selling price = 6.00}\cdot1.75 \\ \text{selling price = \$}10.5 \end{gathered}[/tex]

Is (2,7) a solution to the system of equations: y= x + 5 y= 4x + 1 Part 1 (circle 1) Yes No Part 2 Shows a proof of your answer

Answers

Answer

(2, 7) is not a solution to this system of equations.

The ordered pair doesn't fit into the second equation

Explanation

To check if the given ordered pair is a solution to this, we will insert the values into the two equations and if they fit into rach equation, then, the ordered pair is a solution for this.

y = x + 5

y = 4x + 1

(2, 7) means x = 2, y = 7

y = x + 5

7 = 2 + 5

7 = 7

y = 4x + 1

7 = 4(2) + 1

7 = 8 + 1

7 ≠ 9

The ordered pair doesn't fit into the second equation, hence, (2, 7) is not a solution to this system of equations.

Hope this Helps!!!

I got the first one right but I can’t figure out the rest. College Calculus 1. Please help :)

Answers

SOLUTION

Consider the image given

In other to evaluate the value of

[tex]g(f(0))[/tex]

We first evaluate

[tex]f(0)[/tex]

From the graph,

[tex]f(0)=0[/tex]

Then, we obtain the value of g(0) by tracing the value of zero on the blue curve, we have

[tex]g(0)=3[/tex]

Therefore

g(f(0) = 3

f(2)=1/xsolve both go 2)=3x

Answers

The functions are:

[tex]\begin{gathered} f(x)=\frac{1}{x} \\ g(x)=3x \end{gathered}[/tex]

We need to evaluate f(x) in x=-2 and g(x) in x=2, so:

[tex]\begin{gathered} f(-2)=\frac{1}{(-2)}=-\frac{1}{2}=-0.5 \\ g(2)=3\cdot2=6 \end{gathered}[/tex]

P(A)=0.35P(B)=0.40P(A and B)=0.13Find P(A or B).Round your answer to two decimal places.

Answers

Given:

[tex]\begin{gathered} P\left(A\right)=0.35 \\ P\left(B\right)=0.40 \\ P\left(A\text{ }and\text{ }B\right)=0.13 \end{gathered}[/tex]

To find:

[tex]P(A\text{ or }B)[/tex]

Explanation:

Using the formula,

[tex]\begin{gathered} P(A\text{ or}B)=P(A)+P(B)-P(A\text{ and }B) \\ =0.35+0.40-0.13 \\ =0.62 \end{gathered}[/tex]

Therefore, the value is,

[tex]P(A\text{ or }B)=0.62[/tex]

Final answer:

The value is,

[tex]P(A\text{ or }B)=0.62[/tex]

If f(x)=x²-20 and g(x) = 4+3x, then f(g(-3)) =

Answers

The value of function f(g(-3)= 5.

What is composite function?

A composite function is generally a function that is written inside another function. Composition of a function is done by substituting one function into another function. For example, f [g (x)] is the composite function of f (x) and g (x).

Given, f(x)=x²-20 and g(x) = 4+3x

first we will find

f(g(x)) = f(4+3x)^2-20

=9x^2+16+24x-20

=9x^2+24x-4

Now to find, f(g(-3)), substitute x=-3,

= 9(9)+24(-3)-4

=81-72-4

=5

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