The Haber Process is performed: __N₂ + __H₂__NH,If I start with 35.0 grams of N₂ and 45.0 grams of H₂, how many grams of NH, are produced? HowMuch excess is left over?

Answers

Answer 1

We must first balance the equation, we have two atoms of nitrogen and hydrogen in the reactants, so we must put the coefficient 2 on the side of the products to balance the equation. The balanced equation of the reaction will be:

[tex]N_2+H_2\rightarrow2NH[/tex]

Now, to find the grams of NH that will be produced, we will follow these steps:

1. We find the moles of N2 and H2 by dividing the grams by the molar mass of each element.

Molar Mass N2=28.0g/mol

Molar Mass H2=2.0g/mol

2. By stoichiometry we find out which is the limiting reactant, we see that for each mole of H2 one mole of N2 reacts, therefore, the limiting reactant will be the one with the least number of moles. The other reactant will be the excess reactant

3. We find the moles of NH using the limiting reactant.

4. We find the grams of NH by multiplying the moles by the molar mass of NH.

5. We find how much of the excess reactant is left by subtracting the initial moles minus the reacting moles.

Let's proceed with the calculations

1. Moles of N2 and H2

[tex]\begin{gathered} molH_2=givengH_2\times\frac{1molH_2}{MolarMassgH_2} \\ molH_2=45.0gH_2\times\frac{1molH_2}{2.0gH_2}=22.5molH_2 \end{gathered}[/tex][tex]\begin{gathered} molN_2=givengN_2\times\frac{1molN_2}{MolarMassgN_2} \\ molN_2=35.0gN_2\times\frac{1molN_2}{28.0gN_2}=1.25molN_2 \end{gathered}[/tex]

2. Limiting reactant

We see that there are 22.5 moles of H2 and 1.25 moles of N2. The ratio N2 to H2 is 1/1, therefore, the limiting reactant will be the one with fewer moles, since it will be consumed faster. Therefore, the limiting reactant is nitrogen.

3. Moles of NH

The ratio NH to N2(Limiting reactant) is 2/1, therefore the moles of NH produced will be:

[tex]\begin{gathered} molNH=givenmolN_2\times\frac{2molNH}{1molN_2} \\ molNH=1.25molN_2\times\frac{2molNH}{1molN_{2}}=2.5molNH \end{gathered}[/tex]

4. Mass of NH

[tex]\begin{gathered} MassNH=givenmolNH\times\frac{MolarMass,gNH}{1molNH} \\ MassNH=2.5molNH\times\frac{286gNH}{1molNH}=15.0gNH \end{gathered}[/tex]

5. Excess of H2

[tex]\begin{gathered} molH_2(LeftOver)=molH_2initial-molH_2react \\ molH_2(LeftOver)=22.5H_2-1.25molhH_2=21.25molH_2 \end{gathered}[/tex]

The mass of H2 left over will be:

[tex]\begin{gathered} MassH_2=21.25molH_2\times\frac{MolarMass,gH_2}{1mol} \\ MassH_2=21.25molH_2\times\frac{2.0gH_2}{1molH_2}=42.5gH_2 \end{gathered}[/tex]

Answer: 15.0 grams of NH will be produced and the excess will be 42.5g of H2


Related Questions

I would like some help to solve this problem number 1

Answers

Answer:[tex]\text{NaCl}+\text{KNO}_3\rightarrow KCl+NaNO_3[/tex]

Explanations:What is a balanced equation?

A chemical equation is known to be balanced if the total number of moles of elements at the reactant is equal to that of the product.

For the reaction between sodium chloride (NaCl) and potassium nitrate (KNO₃), the balanced reaction is given as;

[tex]\text{NaCl}+\text{KNO}_3\rightarrow KCl+NaNO_3[/tex]

You can see that the reactant ions exchange places to form new products (potassium chloride and sodium nitrate). This shows that the equation is a double displacement reaction

An unknown gas is found to consist of 10.48 g of nitrogen and 11.96 g if oxygen. What is the percentage composition of this gas? * A. 53.3% N, 46.7% O B. 74.5% N, 25.5% O C. 28.6% N, 71.4 % O D. 46.7%N, 53.3%O

Answers

Answer:

A. 53.3% N, 46.7% O

Explanation:

1st) It is necessary to add both quantities (10.48g of nitrogen and 11.96g of oxygen) to obtain the total mass of the sample, which represents 100%:

10.48g + 11.96g = 22.44g

22.44g represents the 100% of the sample.

2nd) Now we can calculate the percentage composition of the gas, using a mathematical rule of three and the amount of nitrogen and oxygen:

• Nitrogen:

[tex]\begin{gathered} 22.44g-100\% \\ 10.48g-x=\frac{10.48g*100\%}{22.44g} \\ x=46.7\% \end{gathered}[/tex]

• Oxygen:

[tex]\begin{gathered} 22.44g-100\% \\ 11.96g-x=\frac{11.96g*100\%}{22.44g} \\ x=53.3\% \end{gathered}[/tex]

We can also calculate the oxygen percentage by subtracting 100% minus the nitrogen percentage (46.7%):

100% - 4607% = 53.3%

So, the percentage composition is 53.3% N and 46.7% O.

Which compound BH3 or BO3 would have polar covalent bonds? How do you know?These are the options in photo

Answers

To solve this problem, let's find the electronegativity difference that we have between each pair of elements. If we look for the electronegativity of B, H and O we might find these values:

B: 1.5 O: 3.4 H: 2.1

So the two bonds that are present in our molecules have a difference of:

O ---- B = 3.4 - 1.5 = 1.9

H ----- B = 2.1 - 1.5 = 0.6

We have two types of covalent bonds, polar and non-polar. When the electronegativity difference is between 1.5 and 0.4 the bond is covalent polar, when it is less that 0.4 is non-polar and when it is higher than 1.5 it is ionic.

In our case, the electronegativity difference between O and B is 1.9, it seems that it would be an ionic bond. But that's not an option. The difference between H and B is 0.6, the polarity of that bond is weak compared to the polarity of the bond between O and B (if we consider that it is covalent).

So the answer to our problem is the first one:

BO₃ would have polar covalent bonds because

How many L of solution do you have if you dissolve 5 moles of salt in enough water to make a 0.5 M solution?

Answers

Answer:

10L

Explanations:

The formula for calculating the molarity of a solution is expressed as:

[tex]molarity=\frac{moles}{volume}[/tex]

Given the following parameters

• Moles of salt = 5 moles

,

• Molarity of solution = 0.5M

Substitute the given parameters into the formula

[tex]\begin{gathered} volume=\frac{moles}{molarity} \\ volume=\frac{5moles}{0.5M} \\ volume=10L \end{gathered}[/tex]

Hence the required volume of the solution is 10L

A compound of molecular mass 28 has a molecular formula CxHy. What is the value of x and y if its empirical formula is CH?

Answers

Answer

x = 2, y = 2

Explanation

The empirical formula is the simplest whole number ration that defines constituent atoms in a species.

The molecular formula is always a multiple of the empirical formula.

Since the empirical formula of the compound i given to be CH, ithen its molecula formula is:

[tex]Molecular\text{ }formula=n\times(empirical\text{ }formula)[/tex]

From the periodic table, the molar masses of (H = 1.00784, C = 12.011)

Thus, the molecular formula is

[tex]\begin{gathered} Molecular\text{ }formula=28\text{ }g\text{/}mol=n(12.011+1.00784)\text{ }g\text{/}mol \\ \\ n=\frac{28}{12.011+1.00784}=\frac{28}{13.01884}=2.150729251\approx2 \end{gathered}[/tex]

(CH)n = (CH)₂ = C₂H₂

Therefore, CxHy = C₂H₂. The value of x and y is 2 and 2 respectively.

The value of x and y if its empirical formula is CH is x = 2, y = 2

when 14.12 moles of mercury (ll) oxide decomposes, how many moles of oxygen gas will form ?

Answers

ANSWER

The number of moles of oxygen formed is 7.06 moles

EXPLANATION

Given that

The number of moles of mercury (II) oxide is 14.12 moles

Follow the steps below to find the number of moles of oxygen

Step 1; Write the balanced equation for the decomposition of the reaction

[tex]\text{ 2HgO }\rightarrow\text{ 2Hg}_{(s)}\text{ + O}_{2(g)}[/tex]

In the reaction above, 2 moles HgO decompose to produce 2 moles Hg and 1 mole O2

Step 2; Find the number of moles of oxygen using a stoichiometry ratio

Let x represents the number of moles of oxygen

[tex]\begin{gathered} \text{ 2 moles HgO }\rightarrow\text{ 1 mole O}_2 \\ \text{ 14.12 moles HgO}\rightarrow\text{ x mole O}_2 \\ \text{ cross multiply} \\ \text{ 2 moles HgO }\times\text{ x mole O}_2\text{ }=\text{ 1 mole O}_2\times\text{ 14.12 moles HgO} \\ \text{ Isolate x} \\ \text{ x = }\frac{1\text{ mole O}_2\times14.12moles\cancel{HgO}}{2moles\cancel{HgO}} \\ \text{ x = }\frac{14.12}{2} \\ \text{ x = 7.06 moles} \end{gathered}[/tex]

Therefore, the number of moles of oxygen formed is 7.06 moles

For the following reaction, 0.156 moles of sulfuric acid are mixed with 0.567 moles of calcium hydroxide.

Answers

The first step is to write the reaction using the molecular formulas of the substances:

[tex]H_2SO_4+Ca(OH)_2\rightarrow CaSO_4+2H_2O[/tex]

Now that the equation is balanced, we have to divide the amount of each reactant by its stoichiometric coefficient, that in this case is 1 for both of them:

[tex]\begin{gathered} \frac{0.156mol}{1}=0.156mol \\ \frac{0.567mol}{1}=0.567mol \end{gathered}[/tex]

The least result will indicate the limiting reagent, which in this case is sulfuric acid. It means that its formula is H2SO4.

Basing our calculations in this reagent, we can find the maximum amount of calcium sulfate that is produced:

[tex]0.156molH_2SO_4\cdot\frac{1molCaSO_4}{1molH_2SO_4}=0.156molCaSO_4[/tex]

It means that the maximum amount of calcium sulfate that can be produced is 0.156 moles.

Select the statements that are true about electronegativity between elements, and their type of bond.A.If the difference is over 1.0, an ionic bond will form.B.If the difference in electronegativity is 0 to 0.5, the bond will be polar covalent.C.If the difference in electronegativity is from 0.6 to 1.7, the bond will be polar and covalent.

Answers

Answer:

C. If the difference in electronegativity is from 0.6 to 1.7, the bond will be polar and covalent.

Explanation:

Let's see the type of bondings based on the electronegativity differences between atoms:

[tex]\begin{gathered} less\text{ than 0.4 : Nonpolar covalent.} \\ 0.4\text{ - 1.7 :}Pola\text{r covalent.} \\ Greater\text{ than 1.7: Ionic.} \end{gathered}[/tex]

So based on this, the answer would be C. If the difference in electronegativity is from 0.6 to 1.7, the bond will be polar and covalent.

Which of the following is not an empirical formula?H2O2HOH2OH3O

Answers

An empirical formula is the simplest form of a formula, that is, the subscripts are simplified.

Therefore, the answer is H2O2 because it's not the simplest form.

3.21 X 10^54 atoms of nitrogen=___ moles of nitrogen.

Answers

Answer:

[tex]5.33\text{ }\times\text{ 10}^{30\text{ }}\text{ moles}[/tex]

Explanation:

Here, we want to get the number of moles of nitrogen

Mathematically:

[tex]1\text{ mole of nitrogen = 6.02 }\times\text{ 10}^{23}\text{ atoms}[/tex]

3.21 * 10^54 atoms of nitrogen will contain:

[tex]\frac{3.21\times10^{54}}{6.02\text{ }\times\text{ 10}^{23}}\text{ = 5.33 }\times\text{ 10}^{30\text{ }}\text{ moles}[/tex]

Which of the following methods would be most useful for describing atoms

Answers

Answer: Option B

Explanations: Atoms are very small to be observed vissually, as a reslt we need the construction of a model to be able to successfully describe an atom.

Turn the following word equation into a symbolic equation: potassium hydroxide and hydrobromic acid react to form potassium bromide and water.

Answers

The chemical formula of potassium hydroxide is KOH.

The chemical formula of hydrobromic acid is HBr.

The chemical formula of potassium bromide is KBr.

The chemical formula of water is H2O.

The symbolic equation for this reaction is:

[tex]KOH+HBr\rightarrow KBr+H_2O[/tex]

It means that the correct answer is the first choice.

Which models of the atom include a structure that is mostly made of empty space?RutherfordThomsonBohrQuantum mechanical

Answers

Answer:

Rutherford's models

Explanations:What is the electron cloud model?

There are known as the region where electrons are found especially in the nucleus.

According to the five basic atomic models which have contributed to the structure of the atom itself, the Rutherford's models of the atom include a structure that is mostly made of empty space compared to thomson that proposed the plum pudding model of the atom

I need to know the answer to this science problem . Please and thank you

Answers

Step 1 - Understanding the types of heat transfer

There are three types of heat transfer: conduction, convection and irradiation. Let's see how each one works:

a) Conduction: is when a very hot substance enters in contact with a cooler substance. The atoms in the hotter substance are moving with a greater velocity and will therefore collide with the atoms of the cooler substance.

b) Convection: it happens especially in liquids and air (fluids). The liquid is warmed up at the bottom first, via conduction. The heated bottom thus changes its density: it becomes less dense, and go up. This process repeats itself several times, warming the whole liquid.

c) Irradiation: when something is put near a heat source, but do not touch it directly. In this case, there's no direct atom collision, but indirect: the rapid atoms of the heat source collide with atoms in the air which then collide with the atoms in the object that is being heated.

Step 2 - Discovering the type of heat transfer in each scenario

In the first scenario, the water at the bottom is in direct contact with the pan. Therefore, water molecules will directly collide with "pan" molecules (probably aluminum atoms or other materials). But there's also convection. The water is not heated only by conduction.

In the second scenario, the hands are near the Bunsen burner, but not directly touching it. What is happening here is then heat irradiation, not conduction.

In the third scenario, the hand is touching the object (the handle of the pan). Even though handles are made of material that poorly conduct heat, it will increase its temperature, at least a little bit. When we touch it, we can feel it is hotter than before. In this case, only conduction is involved (from the handle to our hand). In this case atoms are directly colliding and this is the only source of heat.

Finally, in the last scenario, we also have a case of irradiation: the pan with water is near the heat source, but not directly touching it.

Step 3 - How to set an experiment

In science in general, anytime we want to investigate some effect it is good manners to investigate a system controling all other effects. We want to investigate a variable at a time.

Therefore, while both scenario 1 and 3 involve conduction, scenario 1 also involves convection, which could be a problem to a experiment intending to study conduction only.

The best experiment would be then scenario 3, hands touchind the handle of pan siting in a Bunsen burner.

Given the following reaction:2 Li (s) + 2 H2O (I) = 2 LiOH (aq) + 1 H2 (g)How many grams of solid lithium must be used in this reaction in order to obtain 6.00 L of hydrogen gas at 1.10 atm and 25.0 C ?

Answers

Answer:

3.73 g of Li.

Explanation:

What is given?

Volume of hydrogen gas, H2 (V) = 6.00 L.

Pressure (P) = 1.10 atm.

Temperature (T) = 25.0°C + 273 = 298 K.

R = 0.082 L*atm/mol*K.

Step-by-step solution:

First, we have to find the number of moles of hydrogen gas (H2) using the ideal gas formula:

[tex]PV=nRT,[/tex]

where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant and T is the temperature on Kelvin scale. So let's solve for 'n' and replace the given values:

[tex]n=\frac{PV}{RT}=\frac{1.10\text{ atm}\cdot6.00\text{ L}}{0.082\text{ }\frac{L\cdot atm}{mol\cdot K}\cdot298K}=0.270\text{ moles.}[/tex]

Based on this, we have 0.270 moles of H2.

You can see in the chemical equation that 2 moles of Li reacted produce 1 mol of H2, so we have to state a rule of three:

[tex]\begin{gathered} 2\text{ moles Li}\rightarrow1\text{ mol H}_2 \\ ?\text{ moles Li}\rightarrow0.270\text{ moles H}_2 \end{gathered}[/tex]

The calculation will look like this:

[tex]0.270\text{ moles H}_2\cdot\frac{2\text{ moles Li}}{1\text{ mol H}_2}=0.540\text{ moles Li.}[/tex]

The final step is to convert 0.540 moles of Li to grams using its molar mass that can be found in the periodic table, which is 6.9 g/mol:

[tex]0.540\text{ moles Li}\cdot\frac{6.9\text{ g Li}}{1\text{ mol Li}}=3.73\text{ g Li.}[/tex]

The answer is that we must use 3.73 g of Li to produce 6.00 L of H2 at 1.10 atm and 25.0 °C.

which best corresponds to a strong base?I need to know

Answers

Assuming that the question is considering quantity of OH- ions as strength of base, the most basic compound will be the last one, as it has more OH- being released into the reaction, but the definition of strong base is a base that totally dissociates, but for the purpose of the question, letter D corresponds to a strong base.

Which of the following combinations will form a solution?Group of answer choicesOil and waterSand and waterSugar and waterSand and sugar

Answers

Answer: the combination "sugar and water" will form a solution.

Explanation:

The question requires us to determine which of the combinations given will form a solution.

To solve this question, let's consider this definition of solution: a homogenous mixture of two or more substances in relative amounts. This means that, to be considered a solution, two mixed substances must form a homogeneous mixture, i.e., without separation of phases.

Considering the options given by the question, we can say:

- oil and water do not mix (because they have different polarities), and separate in different phases when are put together;

- sand and water do not form a homogeneous mixture: sand is deposited at the bottom of the vessel and forms a separated phase of solid;

- sugar and water can form a homogeneous mixture, therefore they form a solution;

- sand and sugar form visible separated phases when mixed together (we can see the particles of sugar and sand separated).

Therefore, considering the points above, we can say that only sugar and water form a solution.

Determine the molarity of a solution with a volume of 707. mL and 0.610 mol of solute dissolved.Answer: ____ M

Answers

Molarity or molar concentration is a measure of the concentration of a chemical species, of a solute in a solution, using as units, number of moles, and volume in liters. The formula for Molarity is:

M = n/V

Where:

n = number of moles, 0.610 moles

V = volume in Liters, 0.707

Now we add these values into the formula:

M = 0.610/0.707

M = 0.863 M is the molarity

Select the correct structure thatcorresponds to the name.2-hexyneA.CH3CH₂CH₂C=CCH3B. CH3C CCH₂CH₂CH3C. both

Answers

Answer

c. both

explanation

both structures have a triple bond on the second carbon and the have 6 carbons in the carbon chain

Calcium reacts with Aluminum chloride to form Calcium chloride and Aluminum. If you react 100 grams of Aluminum chloride with Calcium, how many grams of Aluminum are produced?

Answers

38.95 g of Al is produced on reacting 100 g of Aluminium chloride with Calcium.

We need to write a balanced equation for the reaction. This is illustrated below:

2AlCl₃ + 3Ca —> 3CaCl₂ + 2Al

Molar Mass of AlCl₃

= 27 + (3x35.5)

= 27 + 106.5 = 133.5g/ mol

Mass of AlCl₃ from the balanced equation

= 2 x 133.5g

= 267g

Molar mass of Al= 26  

Mass of Al from balanced equation= 2×26

= 52

Molar Mass of CaCl₂ = 40 + (2 x 35.5)

= 40 + 71 = 111g/mol

Mass of CaCl₂ from the balanced equation

= 3 x 111 = 333g

From the equation,

133.5g of AlCl₃ produced 52g of Al

Therefore, 100g of AlCl₃ will produce

= (100 x 52)/133.5

= 38.95g of Al

So, 38.95 g of Al is produced on reacting 100 g of Aluminium chloride with calcium.

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what is the percent composition of h and o in H2O2

Answers

[tex]Molecular\text{ }weight\text{ }of\text{ }H_2O_2=34.0gmol^{-1}[/tex]

Percent compositions:

[tex]\begin{gathered} Hydrogen:\frac{2}{34}\times100=5.9\% \\ \\ Oxygen:\frac{32}{34}\times100=94.1\% \end{gathered}[/tex]

Howmany molecules of iron (iii) oxide canbe produced from 13.5 molesFe

Answers

Answer: 8.1297x10^24 molecules

Calculations:

Balanced Reaction :

[tex]2Fe+3O_2\Rightarrow2Fe_2O_3[/tex]1. by stoichiometry,

• 2 moles of Fe : 2 moles of iron (iii) oxide

• then 13.5 moles Fe : x

X = 13.5 *2 /2 = 13.5 moles of Fe

• This means that 13.5 mole of Fe2O3 will be produce.

2. Calculate number of molecules by Avogardo principles.

No. of molecules = Moles * Avogardo Number

[tex]\begin{gathered} Fe_2O_{3\text{ }}Molecules\text{ = 13.5 moles }\cdot6.022\cdot10^{23} \\ \text{=8.1297}\cdot10^{24} \end{gathered}[/tex]

• This means that there are 8.1297 x10^24molecules of Fe2O3 from 13.5 moles Fe.

10.Which of the following elements is correctly matched with the number of electrons it needs to become stable?Select one:a. Sulfur (S) .. 6b. Hydrogen (H) .. 2c. Chlorine (Cl) .. 1d. Aluminum (Al) .. 3

Answers

Answer:

Chlorine (Cl). Option C is correct

Explanations:

For an elements to be stable, it must attain its octet configuration that is the total number of electron in its outermost shell is must be 8 electrons.

For sulphur (atomic number of 16) with an electronic configuration 1s^2 2s^2 2p^6 3s^2 3p^4. This shows that sulphur needs 2 electrons to complete its shell making the first option incorrect.

For hydrogen (atomic number of 1) will need one electron to attain duplet rule making the option B is incorrect.

For chlorine element (atomic number of 17), with electronic configuration 1s^2 2s^2 2p^6 3s^2 3p^5. This shows that chlorine will need 1 more electron to make it stable

If there are 1.1 moles of SeCl6 how many moles of Cl2 will be produced? Use up to one decimal point

Answers

ANSWER

There are 3.3 moles of Cl2 in 1.1 moles of SeCl6

EXPLANATION

Given that

The number of moles of SeCl6 is 1.1 moles

Firstly, write a balanced equation of the reaction

[tex]\text{ SeCl}_6\text{ }\rightarrow\text{ Se + 3Cl}_2[/tex]

In the reaction above, 1 mole SeCl6 gives 3 moles Cl2

Let x be the number of moles of Cl2

[tex]\begin{gathered} \text{ 1 mole SeCl}_6\text{ }\rightarrow\text{ 3 moles Cl}_2 \\ \text{ 1.1 mole SeCl}_6\text{ }\rightarrow\text{ x moles Cl}_2 \\ \text{ cross multiply} \\ \text{ 1 mole SeCl}_6\times\text{ x moles Cl}_2\text{ = 1.1 mole SeCl}_6\text{ }\times\text{ 3 moles Cl}_2 \\ \text{ Isolate x } \\ \text{ x = }\frac{1.1moles\cancel{SeCl_6}\times\text{ 3 moles Cl}_2}{1mole\cancel{SeCl_6}} \\ \\ \text{ x = 1.1 }\times\text{ 3} \\ \text{ x = 3.3 moles} \end{gathered}[/tex]

Therefore, there are 3.3 moles of Cl2 in 1.1 moles of SeCl6

Is there any difference(s) in observation and molarity of the strong base when phenolphthalein or methyl orange is used? If Yes / No account for this reason.​

Answers

Yes, the molarity in both the cases will be different if the indicator is changed from methyl orange to phenolphthalein or from phenolphthalein to methyl orange.

Since molarity is defined as the Molar concentration, also known as molarity, amount concentration, or substance concentration, is a unit used to describe the amount of a substance in a solution expressed as a percentage of the volume of the solution or it is the number of moles of solute divided by volume of solution in liters.

So on changing indicator, the number of moles changes as the molar mass is changing, so the molarity and other observations will get changed too and may increase or decrease.

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The Croatian seismologist, Andrija Mohorovicic, discovered a boundary change in the Earth's layers. Please explain how he discovered this using two to three sentences using your best grammar.

Answers

The Croatian seismologist, Andrija Mohorovicic, discovered a boundary change in the Earth's layers  because he noticed that P-waves were refracted at the boundary.

Who is a seismologist?

Seismologists are described as Earth scientists, specialized in geophysics, who study the genesis and the propagation of seismic waves in geological materials.

Andrija Mohorovicic realized that as one crosses the boundary the predominant mineral composition of the rock changes, and the minerals on the mantle side enable seismic waves to travel faster.

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6. A sample of nitrogen gas weighs 130 g. Write the chemical formula for nitrogen gas. Howmany molecules of elemental nitrogen is this? How many atoms of nitrogen are in this sample?

Answers

Chemical formula for nitrogen gas is N₂.

To find the number of molecules in the given sample, we have to convert the mass of the sample to moles by using the molecular mass of elemental nitrogen (N₂).

[tex]130gN_2\cdot\frac{1molN_2}{28gN_2}=4.64molN_2[/tex]

Now, we have to use Avogadro's number (6.022x10^23) that indicates the number of molecules in one mole of substance:

[tex]4.64molN_2\cdot\frac{6.022\times10^{23}molecules}{1molN_2}=2.79\times10^{24}molecules[/tex]

It means that there are 2.79x10^24 molecules of elemental nitrogen.

To find the number of atoms we just have to multiply the number of molecules by 2, which is the number of atoms of nitrogen per molecule of elemental nitrogen:

[tex]2.79\times10^{24}molecules\cdot\frac{2atoms}{1molecule}=5.59\times10^{24}atoms[/tex]

There are 5.59x10^24 atoms of nitrogen in the sample.

PLEASE HELP
Balance the chemical reaction
using an atom inventory.
What is the coefficient for
oxygen?
4NH3 + ? O2 ---> ?NO + ? H2O

Answers

The balance chemical equation will be 4NH3 + 5 O2 → 4NO + 6H2O and the coefficient for water will be 5.

The given unbalanced chemical equation is :

4NH3 +  O2 → NO + H2O

It can be seen that number of nitrogen atom in reactant side is 4. By multiplying by 4 as the coefficient of NO , multiplying by 5 as the coefficient of oxygen and multiplying by 6 as the coefficient of H2O. The equation will be balanced.

The balanced chemical equation will be :

4NH3 +  5O2 →4 NO + 6H2O

Therefore, the the coefficient for water will be 5.

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I really need help on this problem for chemistry, please help!

Answers

answer and explanation

we are given the balanced reaction and so we begin by calculating the number of mols of each reactant

for Al

mols = mass/Molar mass

= 22.0g / 26.98g/mol

= 0.82 mols

for oxygen

mols = mass / Molar mass

= 26.0g / 16.00g/mol

= 1.6 mols

theerefore

a. the limiting reagent is Al

b. theoretical yield will be determine using the limiting reagent.

from the balanced reaction we see that the mol ratio between aluminum and aluminum oxide is 4:2

therefore

2/4 x0.82 = 0.41 mols of aluminum oxide will form

the mass will be

mass = n x M

= 0.41 mols x 101.96g/mol

= 41.8 grams

c. percentage yield is:

actual yield/ theorectical yield x 100

= 40.0/41.8 x 100%

= 95.7 %

What coefficients would correctly balance this equation?_Ag2S → _Ag +_ S₂

Answers

In order to properly balance an equation, we need to make sure that the same amount of elements on the reactants side matches the number of elements on the products side, we can do that by increasing the number in front of each molecule, the so called stoichiometric coefficient. In the reaction from the question we can properly balance by adding the following stoichiometric coefficients

For our question, we have:

2 Ag2S -> 4 Ag + S2

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