Answer: 0.276g of H2 could be obtained from the reaction, considering the mass of reactants given
Explanation:
The question requires us to determine the amount of hydrogen gas (H2) that would be obtained when 10.0g of metallic magnesium (Mg) and 10.0g of chloridric acid (HCl) are reacted.
The following unbalanced chemical equation was provided:
[tex]Mg+HCl\rightarrow MgCl_2+H_2[/tex]To solve this problem, we'll need:
1) obtain the balanced chemical equation;
2) determine the limiting reactant considering the amount of reactants used and the stoichiometry of the reaction;
3) calculate the mass of hydrogen gas produced, considering the limiting reactant
1) Balancing the chemical equation
From the unbalaced chemical equation, we can see that there is the same amount of Mg on both sides of the equation, but we need to adjust the amount of H and Cl atoms.
There are 2 Cl atoms and 2 H atoms on the right side, and 1 Cl and 1 H atom on the left side, thus we can adjust the coefficient of HCl from 1 to 2 to adjust these elements. The balanced chemical equation can be written as:
[tex]Mg+2HCl\rightarrow MgCl_2+H_2[/tex]2) Determining the limiting reactant
Now that we know the balanced chemical equation, we can say that 2 moles of HCl are necessary to react with 1 mol of Mg. Thus, we can write:
1 mol Mg ----------------------- 2 mol HCl
From this stoichiometric relation, we can calculate the amount of HCl that would be necessary to react with 10.0 g of Mg.
First, let's determine the amount of moles of Mg contained in 10.0g of this metal and the number of moles of HCl in 10.0g of this acid:
[tex]\begin{gathered} number\text{ of moles = }\frac{mass\text{ of sample \lparen g\rparen}}{molar\text{ mass \lparen g/mol\rparen}} \\ \\ number\text{ of moles of Mg = }\frac{10.0g}{24.31g/mol}=0.411mol\text{ of Mg} \\ \\ number\text{ of moles of HCl = }\frac{10.0g}{36.46g/mol}=0.274mol\text{ of HCl} \end{gathered}[/tex](the atomic mass of Mg is 24.31 amu, which is numerically identical to its molar mass, 24.31 g/mol, and the molar mass of HCl is 36.4g g/mol)
Therefore, 0.411 moles of Mg and 0.274 moles of HCl were used in the reaction.
Next, we can determine how many moles of HCl would be necessary to react with 0.411 moles of Mg:
1 mol Mg ----------------------- 2 mol HCl
0.411 mol Mg ----------------- x
Solving for x, we have that 0.822 moles of HCl would be necessary to react with the given amount of Mg. Since the amount actually used of HCl (0.274 mol) is smaller than the necessary amount, we can say that HCl is the limiting reactant.
3) Calculating the mass of H2 obtained
Using the limiting reactant and the stoichiometry of the reaction, we can determine the amount of H2 that could be produced.
From the balanced chemical equation, we know that 2 moles of HCl are necessary to produce 1 mol of H2. Thus, we can write:
2 mol HCl ------------------- 1 mol H2
0.274 mol HCl ------------ y
Solving for y, we have that 0.137 moles of H2 would be obtained.
We can convert the number of moles of H2 to its correspondent mass as it follows (the molar mass of H2 is 2.016 g/mol):
[tex]\begin{gathered} number\text{ of moles = }\frac{mass\text{ of sample \lparen g\rparen}}{molar\text{ mass \lparen g/mol\rparen}}\rightarrow mass\text{ of sample = number of moles}\times molar\text{ mass} \\ \\ mass\text{ of H}_2=0.137mol\times2.016g/mol=0.276g \end{gathered}[/tex]Therefore, 0.276g of H2 could be obtained from the reaction, considering the mass of reactants given.
The reaction of 192g of Fe2O3 with 82.5g of CO produces 72.9 of Fe Fe2O3 + 3CO => 2Fe + 3CO2 Calculate the theoretical yield of iron in grams.
ANSWER
The theoretical yield of Fe is 109.64 grams
EXPLANATION
Given that;
The mass of Fe2O3 is 192 grams
The mass of CO is 82.5 grams
Follow the steps below to find the theoretical yield of Iron
Steps 1; Find the number of moles of Fe2O3 and CO using the below formula
[tex]\text{ mole = }\frac{\text{ mass}}{\text{ molar mass}}[/tex]Recall, that the molar mass of Fe2O3 and CO are 159.69 g/mol and 28.01 g/mol
[tex]\begin{gathered} \text{ For Fe}_2O_3 \\ \text{ mole = }\frac{\text{ 192}}{\text{ 159.69}} \\ \text{ mole = 1.202 moles} \\ \\ \text{ For CO} \\ \text{ mole = }\frac{\text{ 82.5}}{\text{ 28.01}} \\ \text{ mole = 2.945 moles} \end{gathered}[/tex]Step 2; Determine the limiting raectant of the reaction
To determine the limiting reactant, divide the number of moles by the co-efficient of each reactant
[tex]\begin{gathered} \text{ For Fe}_2O_3 \\ \text{ mol/wt of Fe}_2O_3\text{ = }\frac{\text{ 1.201 }}{\text{ 1}} \\ \text{ mol/wt of Fe}_2O_3\text{ = 1.202 mol} \\ \\ \text{ for CO} \\ \text{ mol/wt of CO = }\frac{\text{ 2.945}}{\text{ 3}} \\ \text{ mol/wt of CO = 0.982 mol} \end{gathered}[/tex]From the calculations, the limiting reactant of the reaction is CO
Step 3; Find the number of moles of Fe using a stoichiometry ratio
Let x represents the number of moles of Fe
[tex]\begin{gathered} \text{ 3 moles CO }\rightarrow\text{ 2 moles Fe} \\ \text{ 2.945 moles CO }\rightarrow\text{ x moles Fe} \\ \text{ cross multiply} \\ \text{ 3 moles CO}\times\text{ x moles Fe = 2 moles Fe }\times\text{ 2.945 moles CO} \\ \text{ x moles Fe = }\frac{\text{ 2 moles Fe}\times2.945mole\cancel{CO}}{3moles\cancel{CO}} \\ \\ \text{ x mole Fe = }\frac{\text{ 2 }\times\text{ 2.945}}{\text{ 3}} \\ \\ \text{ x mole Fe = }\frac{\text{ 5.89}}{\text{ 3}} \\ \text{ x mole Fe = 1.963} \end{gathered}[/tex]The number of moles of Fe is 1.963 moles
Step 4; Find the theoretical yield of Fe
[tex]\begin{gathered} \text{ mole = }\frac{\text{ mass}}{\text{ molar mass}} \\ \text{ cross multiply} \\ \text{ mass = mole }\times\text{ molar mass} \end{gathered}[/tex]Recall, molar mass of Fe is 55.845 g/mol
[tex]\begin{gathered} \text{ mass = 1.963 }\times\text{ 55.845} \\ \text{ mass = 109.64 grams} \end{gathered}[/tex]Therefore, the theoretical yield of Fe is 109.64 grams
\Which of the following should be broken into ions when writing a complete ionic equation? Select all that apply.
Step 1 - How to tell whether a given substance is ionic or covalent
To decide whether a substance is ionic or covalent, we must look for metals in its formula. If the substance is composed of both metals and non metals, it is an ionic susbtance.
If it's, on the other hand, composed solely by non-metals, it is a covalent substance.
Covalent substances do not produce ions in aqueous solution. Therefore, they can't be "broken into ions".
Step 2 - Analysing the given substances
H2O --> composed of H and O; both non-metals, so covalent
LiF --> composed of a metal (Li) and a non-metal (F), so ionic
K3PO4 --> composed of a metal (K) and non-metals (P, O), so ionic
AgCl --> composed of a metal (Ag) and non-metal (Cl), so ionic
Step 3 - Answering the exercise
All substances except H2O should be broken into ions when writing a complete ionic equation.
Answer: all except H2O
24.How is a supersaturated solution prepared?Select one:a. Heat a solution to the boiling point and continue to boil for 15 minutes.b. Add solute to a saturated solution and heat until all of the solute dissolves. Then, slowly cool to the original temperature.c. Add solute to cold solvent and then heat the solution to room temperature.d. Stir the solution until all of the solid dissolves and then heat the solution.
Answer
b. Add solute to a saturated solution and heat until all of the solute dissolves. Then, slowly cool to the original temperature.
Explanation
A supersaturated solution contains more dissolved solute than required for preparing a saturated solution and can be prepared by heating a saturated solution, adding more solute, and then cooling it gently. Excess dissolved solute crystallizes by seeding supersaturated solution with a few crystals of the solute.
Therefore, a supersaturated solution is prepared by:
b. Add solute to a saturated solution and heat until all of the solute dissolves. Then, slowly cool to the original temperature.
A 13.5- L scuba diving tank contains a helium-oxygen (heliox) mixture made up of 24.0 g of He and 5.00 g of O2 at 298 K . Calculate the mole fraction of each component in the mixture.
13.5- L scuba diving tank contains a helium-oxygen (heliox) mixture made up of 24.0 g of He and 5.00 g of O2 at 298 K then mole fraction of each component in the mixture is ˣHe = 1.15 and ˣO₂ = 7
Mole fraction is the ratio of number of moles one component of a solution or other mixture to the total number of moles representing all of the components
Here given data is
Helium = 24.0 g
Oxygen = 5.00 g
Temprature = 298 K
Here we know the mass of both helium and oxygen, in order to obtain the mole fractions we first need the compute the moles by using their atomic masses 4.00 g/mol and 32.00 g/mol respectively as shown below then
ⁿHe = 24.0 g×1 mol He/4.00g He = 6 mol He
ⁿO₂ = 5.00 g×1 mol of O₂/ 32.00 g = 0.15 mol O₂
Then the mole fraction are
ˣHe = ⁿHe/ⁿHe + ⁿO₂ = 6/6 + 0.15
ˣHe = 1.15
ˣO₂ = ⁿO₂/ⁿO₂ + ⁿHe = 0.15/0.15 + 6
ˣO₂ = 7
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Determine if this is a property of acids, bases, or neutral solutions: Feels slippery to the touch.
Although there are neutral solutions that feel slipery, this is not a characteristic of all neutral solutions.
Acid solutions normally feels similar to neutral solutions, just wet.
However, base solutions has the characteristics of feeling slippery.
So, the most correct answer would be base
Answer: Bases
Explanation:
Bases have a slippery feel. Many soaps and detergents contain bases. Strong bases are able to react with the fatty acids and oils that naturally occur on the surface of your skin. The product of the reaction (which is known as saponification) is effectively a soap, which is why it feels slippery.
A 16%(m/m) solution contains 10 grams of NaOH. It also contains ___ grams of water.
1) List the known and unknown quantities.
Concentration: 16%(m/m).
Mass of solute: 10 g NaOH.
Mass of solvent: unknown.
2) Set the equation.
Mass percent.
[tex]Mass\text{ }\%=\frac{grams\text{ }of\text{ }solute}{grams\text{ }of\text{ }solvent}*100[/tex]3) Plug in the known values and solve for grams of solvent (water).
[tex]16\%=\frac{10\text{ }g\text{ }NaOH}{grams\text{ }of\text{ }solvent}*100[/tex].
[tex]grams\text{ }of\text{ }solvent=\frac{10\text{ }g\text{ }NaOH}{16}\times100[/tex][tex]grams\text{ }of\text{ }solvent=62.5\text{ }g\text{ }H_2O[/tex]The 16%(m/m) solution contains 62.5 g H2O.
.
Lidocaine, a widely used local anesthetic, it’s available as a 2.0% (w/v) solution for injection. Calculate the volume of the solution that contains 60 mg of lidocaine. Be sure your answer has a unit symbol and is rounded to the correct number of significant digits.
Givens.
• Lidocaine is available as a 2.0% (w/v) solution.
,• The mass of solute is 60. mg of lidocaine.
To find the volume of this solution, we use the following equation.
[tex](\frac{w}{v})=\frac{Mass\text{ of solute}}{Volume\text{ of solution}}[/tex]Use the given magnitudes and solve for volume.
[tex]\begin{gathered} 0.02=\frac{60mg}{V} \\ V=\frac{60mg}{0.02} \end{gathered}[/tex]But, we need to use grams.
[tex]V=\frac{0.060g}{0.02}=3[/tex]Therefore, the volume of this solution is 3.0 mL.
Local winds are produced by geographic freatures true or false
Explanation:
Hey! The answer is True!
write a flow diagram or dimensional analysis scheme from % Mass to Molarity
To convert %Mass to Molarity, we have to know two things: the molecular mass of the solute and the density of the solution.
The first step is to convert the mass of the solute to moles using the molecular mass.
The second step is to conver the mass of the solution to liters of solution using the density.
Finally, the last step is to simplify the obtained result.
Hi I need help with this question please and thank you
Let's see an illustration of a water molecule:
You can see that the oxygen has two pairs of electrons free representing a partial negative charge. These partial negative charges don't allow the molecule has a linear structure. All of the electron pairs—shared and unshared—repel each other and that's why the water molecule has a bent shape, because of these unshared electrons of oxygen.
Answer the question with the choices Which is not a biotic factor that influences the relationships of organisms in ecosystem?A-Competition among predatorsB- A disease caused by bacteriaC-Invasive speciesD-Weather
Step 1 - Understanding what is a biotic factor
Biotic, as well as other words with "bio" in them, is related to living organisms. A biotic factot is, therefore, a factor which depends on living organisms. When living organisms shape their environment, as well as other living beings environments, we call it a "biotic factor".
Step 2 - Using the definition to solve the exercise
a) Competition among predators: since this is a consequence of the struggling between two or more living beings, the outcome of it is surely a biotic factor. Individuals can die because they could not find enough food due to competition. A population could thus be modified by this biotic factor, for example.
b) A disease caused by bacteria: a bacteria is a living being and a disease can disastrously kill an entire population, radically changing the ecological relations and the environment. This is another biotic factor.
c) Invasive species: this is also caused by living beings. When a specie invades another species territory, there may be fight among them or just resources sharing. Either way, the ecological relations will be drastically modified. This accounts for a biotic effect as well.
d) weather: this is not solely caused by living beings. In fact, it depends rather poorly on living beings, and much more on Earth's temperature, geographical location an so on. Since the changes caused by weather are not from a living source, this is not a biotic factor.
The answer is thus item d.
Can I find a tutor to help me with question?
Answer:
Hafnium is more likely to be the identity of the substance.
Explanation:
The given information about the substance is:
- Mass: 46.9g
- Volume: 3.5cm^3
- Solid at room temperature (23°C)
We can calculate the density of the substance by replacing the values of mass and volume in the density formula:
[tex]\begin{gathered} Density=\frac{mass}{volume} \\ . \\ Density=\frac{46.9g}{3.5cm^3} \\ . \\ Density=13.4\frac{g}{cm^3} \end{gathered}[/tex]Now we know that the density of the substance is 13.4g/cm^3.
At this point, the substance could be mercury or hafnium, because they have a similar density, but we also know that the substance is solid at 23°C, so since hafnium has a melting point of 2,233°C, it is more likely to be the identity of the substance.,
Which molecules separate during the light reaction of photosynthesis?Carbon dioxide and oxygeno Hydrogen and OxygenООHydrogen and Carbon Dioxide
Answer
Hydrogen and Oxygen
Explanation
During Light reactions of Photosynthesis, the chlorophyll will be activated by light. This light-activated chlorophyll will split the water molecule to release H+ ions and also oxygen. This process is called Photolysis.
Therefore, the correct option to your question is: Hydrogen and Oxygen
2 H₂O + electricity → 2 H₂ + O₂15. In which type of cell would this reaction most likely occur?(1) a chemical cell, because it is exothermic(2) an electrolytic cell, because it is exothermic(3) a chemical cell, because it is endothermic(4) an electrolytic cell, because it is endothermic
Answer:
(4) an electrolytic cell, because it is endothermic.
Explanation:
You can see that we're using electricity to carry out the reaction, so this reaction is occuring in an electrolytic cell.
Remember that electricity is a form of energy. In an exothermic process, the energy is released but in an endothermic process, the energy is being absorb, and the process would required energy.
As you can note, this reaction requires electricity, it required energy, so this would be an endothermic process.
The answer would be (4) an electrolytic cell, because it is endothermic.
Find the total molarity of the acid? MaVa = MbVb Ma= what you are looking forVa= 100mLMb = 1MVb = 25 mL
In this question, we have to find the molar concentration of the acid, and the question already provides us with the formula and each required data:
MaVa = MbVb
We have:
Ma = ?
Va = 100 mL
Mb = 1.0 M
Vb = 25 mL
Now we add these values into the formula:
Ma * 100 = 1 * 25
100Ma = 25
Ma = 25/100
Ma = 0.25 M
What is the percent by mass of bromine in the compound MgBr₂?A) 13.2%B) 43.4%C) 56.6%D) 86.8%
Answer:
D) 86.8%
Explanation:
It necessary to use the molar mass of Br (80g/mol) and MgBr2 (184g/mol). The MgBr2 is the 100%, so with a mathematical rule of three we can calculate the percent by mass of bromine.
In the molecule of MgBr2 there are 2 bromine, so the total mass of bromine it is 160g (80gx2):
[tex]\begin{gathered} 184g-100\% \\ 160g-x=\frac{160g*100\%}{184g} \\ x=86.9\% \end{gathered}[/tex]Finally, the percent by mass of bromine is 86.9% (86.8%).
Ksp= 2×10−19 for LaF3 Calculate the solubility of LaF3 in grams per liter in a solution that is 0.011 M in KF
Solubility of LaF3: "S"
First, we need to write the reaction of solubility:
LaF3 (s) <=> La+3 + 3 F-
Initial - 0 +0.011 (F-, from KF)
Change +S +3.S
Equilibrium S 0.011 + 3.S
Now, we know:
Ksp = [La³⁺]x[F⁻]³ = 2×10^−19 = S x (0.011+3.S)³
We work with: 2×10^−19 = S x (0.011+3.S)³, and we clear the "S"
=> S = 1.5x10^-13 mol/L x (195.9 g/mol) = 2.93x10^-11 g/L
The molar mass of LaF3 = 195.9 g/mol
Answer: S = 2.93x10^-11 g/L
What are the coefficients when the chemical equation below is balanced?___ Fe + ___ H2SO4 -> ___ Fe2(SO4)3 + ___ H21,1,1,12,3,3,32,3,1,33,2,3,1
Answer:
2, 3, 1, 3.
Explanation:
Remember that a balanced chemical equation is when we have the same number of elements for reactant and product side.
Let's see the unbalanced equation:
[tex]Fe+H_2SO_4\rightarrow Fe_2(SO_4)_3+H_2.[/tex]You can note that we have:
You can realize that we have Fe, S, and O unbalanced, but if we put '2' moles beside Fe, we will balance Fe, like this:
[tex]2Fe+H_2SO_4\operatorname{\rightarrow}Fe_2(SO_4)_3+H_2[/tex]Now, if we put '3' moles beside H2SO4 we will balance S and O, obtaining 3 moles of S, and 12 moles of O for both sides:
[tex]2Fe+3H_2SO_4\operatorname{\rightarrow}Fe_2(SO_4)_3+H_2[/tex]But H is unbalanced because on the left side we have 6 hydrogens but on the right side we have 2 hydrogens, so if we put '3' moles beside H2, we obtain the balanced chemical equation:
[tex]2Fe+3H_2SO_4\operatorname{\rightarrow}Fe_2(SO_4)_3+3H_2.[/tex]The order of the coefficients is 2, 3, 1, 3.
Answer:
2,3,1,3
Explanation:
I took the test
Calculate the percent yield if 1.95 g of Ca(OH)2 reacts with excess HCl to produce 2.50 g of CaCl2. Ca(OH)2 + 2HCl → CaCl2 + 2H2OTheoretical yield?Percent yield?
The first step is to write a balanced chemical equation.
[tex]Ca(OH)_2+\text{ 2HCl}\rightarrow CaCl_2+2H_2O[/tex]The above equation is already balanced.
Now lets write what we have.
Ca(OH)2 = 1.95g
CaCl2 = 2.50g
We already know that HCl is in excess, meaning Ca(OH)2 is the limiting reagent.
%Yield = (actual yield/theoretical yield) x 100
Lets first calculate the theoretcal yield. To find this we need to first calculate the number of moles of CaCl2.
n = m/M where m is the mass and M is the molar mass of CaCl2
n = 2.50g/110,98 g/mol
n = 0.0225 mol
Theoretical Yield is the amount of product that would have been produced if all of the limiting reagent reacted and it was 100% pure. The limiting reagent is used up first in a reaction and controls the amount of product that can be produced.
The actual yield of CaCl2 we were given, which is 2.50g of CaCl2.
For every 1 mole of Ca(OH)2, 1 mole of CaCl2 is produced
n = 1.95g/74.09 g/mol
n = 0.0263 mol
Therefore the number of moles of CaCl2 = 0.0263 mol
mass of CaCl2 = nM
m = 0.0263 mol x 110,98 g/mol
m = 2.92 g
So the theoretical yield of CaCl2 = 2.92g
percentage yield = (2.50g/2.92)*100
percentage yield = 85.62%
Calculate the number of molecules in 3.00 L of CO gas at STP.
One carbon atom and one oxygen atom bound together by three bonds make up carbon monoxide. The number of molecules in 3.00 L of CO gas at STP is 67.2 liters.
What is carbon monoxide gas ?Colorless, lethal, odorless, tasteless, and combustible, carbon monoxide is a gas that is somewhat less thick than air. One carbon atom and one oxygen atom bound together by three bonds make up carbon monoxide. The oxocarbon family's simplest molecule is this one.
Headache, dizziness, weakness, nausea, upset stomach, vomiting, chest discomfort, and confusion are the most typical signs of CO poisoning. The symptoms of CO are frequently compared to the flu. CO can cause you to lose consciousness or kill you if you breathe it in heavily.
If the gas is at STP,
Then 1 mole = 22.4 liters.
3 moles x 22.4 L/mol
= 67.2 liters.
Thus, The number of molecules in 3.00 L of CO gas at STP is 67.2 liters.
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Boron has a greater atomic radius than fluorine true or false?
Answer:
false trust me gang^^^
Explanation:
A balloon is floating around outside your window. The temperature outside is 37 ∘C , and the air pressure is 0.800 atm . Your neighbor, who released the balloon, tells you that he filled it with 3.60 moles of gas. What is the volume of gas inside this balloon?
Answer:
[tex]114.53\text{ L}[/tex]Explanation:
Here, we want to get the volume of the gas inside the balloon
Mathematically, from the ideal gas equation:
[tex]\begin{gathered} PV\text{ = nRT} \\ V\text{ = }\frac{nRT}{P} \end{gathered}[/tex]where:
P is the pressure which is given as 0.8 atm
V is the volume which we want to calculate
R is the molar gas constant which is 0.0821 L.atm/mol.K
T is the temperature in Celsius which we can convert to K by adding 273 (273 + 37 = 310 K)
n is the number of moles which is 3.6
Substituting the values, we have it that:
[tex]\begin{gathered} \text{ V = }\frac{3.6\text{ }\times0.0821\times310}{0.8} \\ \\ V\text{ = 114.53 L} \end{gathered}[/tex]10. Which of the following would speed up the rate of a the reaction A(s) + B(aq) → AB(aq) +heata.Add more of reactant Ab. Add more of product ABC. Crush reactant A into a powderd.Cool the reaction vessel
In this question, we need to determine which option can speed up the rate of a chemical reaction, and there are a few ways possible in order to speed up a reaction, usually we have: Increasing temperature, increasing surface area, increasing the concentration of reactants
In this case, increasing temperature would not make the reaction occur faster, since the reaction is exothermic, therefore there is no need to input energy for the reaction to occur
Increasing the concentration of reactants, is the option A, but there is a small problem, A is a solid compound and B is an aqueous compound, if we add more A, we can speed up the reaction but we can also turn the extra amount of A insoluble, which would not make the reaction to occur faster
The best way, in this case, is to crush reactant A into powder, because this would make the surface area of A to increase, making A and B interact more and then the reaction would occur faster
The best option will be letter C
6.The ability to do which of the following is a chemical property of a substance?Select one:a. React with oxygen.b. Conduct electricity.c. Be drawn into a wire.d. Be worked into different shapes.
Answer:
[tex]A\text{ : React with oxygen}[/tex]Explanation:
Here, we want to select the option that represents a chemical property
A chemical property is one in which there is a chemical change
Asides from the first option, the other are physical
By reacting with oxygen, entirely new substances are formed
For each of the given elements, list two other elements with similar chemical properties.
a. iodine (1)
b. barium (Ba)
c. iron (Fe)
Answer:
Iodine - > Fluorine, Bromine
Barium - > Beryllium, Magnesium
Iron - > Hassium, Osmium
Explanation:
How many grams of hydrogen are in 25 g of (NH4)2SO4?
ANSWER
The mass of hydrogen in 25g of (NH4)2S04 is 1.5152 grams
EXPLANATION
Given information
[tex]\text{ The mass of \lparen NH}_4)_2SO_4\text{ is 25g}[/tex]To find the grams of hydrogen, please follow the steps below
Step 1: Find the molar mass of (NH4)2SO4
Recall, that
The unit mass of nitrogen is 14u
The unit mass of hydrogen is 1u
The unit mass of sulfur is 32u
The unit mass of oxygen is 16u
[tex]\begin{gathered} \text{ \lparen NH}_4)_2SO_4\text{ = \lbrack\lparen14 + \lparen1}\times4)]\times2\text{ + \lparen32\rparen + \lparen4 }\times16) \\ \text{ \lparen NH}_4)_2SO_4\text{ = \lparen14 + 4\rparen}\times2\text{ + 32 + 64} \\ \text{ \lparen NH}_4)_2SO_4\text{ = 18}\times2\text{ + 32 +64} \\ (NH_4)_2SO_4\text{ = 36 +32 +64} \\ \text{ \lparen NH}_4)_2SO_4\text{ = 132 g/mol} \end{gathered}[/tex]From the calculations, the molar mass of (NH4)2SO4 is 132 g/mol
Step 2: Find the number of moles of the compound
[tex]\begin{gathered} \text{ Mole = }\frac{\text{ mass}}{\text{ molar mass}} \\ \end{gathered}[/tex]Mass = 25g
Molar mass = 132 g/mol
Substitute the given data into the formula above
[tex]\begin{gathered} \text{ Mole = }\frac{25}{132} \\ \text{ Mole = 0.1894 mol} \end{gathered}[/tex]The number of moles of (NH4)2SO4 is 0.1894 mol
Step 3: Find the moles of hydrogen in the compound
There are 8 hydrogen atoms in (NH4)2SO4
Hence, we can find the number of moles of hydrogen below
[tex]\begin{gathered} \text{ Mole of hydrogen = 8 }\times\text{ 0.1894} \\ \text{ Mole of hydrogen = 1.5152 moles} \end{gathered}[/tex]Step 4: Find the mass of hydrogen using the below formula
[tex]\text{ Mole = }\frac{mass}{\text{ molar mass}}[/tex]Recall, that the molar mass of hydrogen is 1.000 g/mol
[tex]\begin{gathered} \text{ 1.5152 = }\frac{\text{ mass}}{\text{ 1}} \\ \text{ cross multiply} \\ \text{ mass = 1.5152}\times\text{ 1} \\ \text{ Mass = 1.5152 grams} \end{gathered}[/tex]Hence, the mass of hydrogen in 25g of (NH4)2S04 is 1.5152 grams
number of moles in 16.23 liters of hydrogen sulfide h2s gas at stp?
The number of moles in 16.23 liters of hydrogen sulfide h2s gas at STP is 0.7245 moles.
Standard temperature and pressure (STP) refer back to the nominal situations within the surroundings at sea stage. these conditions are zero degrees Celsius and 1 ecosystem (atm) of pressure.
A mole is a completely important unit of size that chemists use. A mole of something manner you have got of that aspect, like how having a dozen eggs approach you to have twelve eggs. Chemists should degree the use of moles for very small such things as atoms, molecules, or different debris.
The mole, symbol mol, is the unit of quantity of substance inside the worldwide machine of gadgets. the amount quantity of the substance is a degree of what number of elementary entities of a given substance is in an item or pattern. The mole is defined as containing exactly 6.02214076×10²³ simple entities
calculation:-
mole at STP = volume in liters/22.4
= 16.23 liters /22.4
= 0.7245 moles.
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When the reactants have less enthalpy than the products, then __________.A. the reaction will be completeB. heat energy is absorbedC. heat energy is given outD. None of these
Chemistry => Thermochemistry => Exothermic and Endothermic Processes
The type of chemical reaction will depend on whether the reaction absorbs or releases energy.
When the reaction releases energy, it is because there is an excess of it and it is called exothermic. This excess occurs because the energy of the products is lower than that of the reactants.
Now, when the products have more energy than the reactants, it means that the reaction needs energy since there is a lack of energy. We call these types of reactions endothermic.
Now, according to the establishment, if the reactants have less energy (or enthalpy), it means that heat must be adsorbed in order to obtain the products that have higher energy (or enthalpy).
Therefore, the answer will be:
B. heat energy is absorbed
Using the equation below, what mass of iron canbe produced from 10.5 grams of aluminum?Al + FeO → Al2O3 + Fe
32.6 grams
Explanations:Given the reaction between aluminium and ferric oxide as shown;
[tex]2Al+3FeO\rightarrow Al_2O_3+3Fe[/tex]Determine the moles of Aluminium
Mole = Mass/Molar mass
Mole = 10.5/26.98
Mole of Al = 0.3892moles
According to stoichiometry, 2moles of aluminium produced 3 moles of Iron, the moles of Iron needed is given as:
moles of Fe = 3/2 * 0.3892
moles of Fe = 0.5838moles
Determine the mass of iron
Mass of Fe = moles * molar mass
Mass of Fe = 0.5838 * 55.845
Mass of Fe = 32.6grams
Hence mass of iron that can be produced from 10.5 grams of aluminium is 32.6 grams
One measure of solubility is concentration in grams per liter. What is the concentration of copper(II) ions, in grams per liter, measured in a 0.200 L sample of water in which 0.00026 g of copper(II) ions are present?
One measure of solubility is concentration in grams per liter concentration of copper(II) ions, in grams per liter, measured in a 0.200 L sample of water in which 0.00026 g of copper(II) ions are present is 0.0013 g/L means 1.3×10⁻³g/L
Concentration is defined as mass per unit volume
Here given data is
Volume = 0.200 L
Mass = 0.00026 g
We have to calculate concentration = ?
Concentration = mass/volume
Concentration = 0.00026 g/0.200 L
Concentration = 0.0013g/L = 1.3×10⁻³g/L
1.3×10⁻³g/L concentration of copper(II) ions, in grams per liter, measured in a 0.200 L sample of water in which 0.00026 g of copper(II) ions are present
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