State if the triangles in each pair are similar. If so, state how you know they are similar andcomplete the similarity statement.1) 2)

State If The Triangles In Each Pair Are Similar. If So, State How You Know They Are Similar Andcomplete

Answers

Answer 1

Triangles Similarity

For two shapes to be similar, two conditions must be satisfied:

* They must have the same angles.

* The side lengths must be in proportion

Let's focus on the image provided in problem 1.

We must try to find if the length sides of ABU and VWU are in proportion.

To do it, we find the ratio of the sides. If we find the same ratio of two pairs of sides, then the second condition is met.


Related Questions

Select the following that are true.Select one or more:a.If a quadrilateral is a square, then it is a rectangle.b.If a quadrilateral is a square, then it is a parallelogram.c.If a quadrilateral is a rhombus, then it is a parallelogram.d.If a quadrilateral is a rectangle, then it is a rhombus.e.If a quadrilateral is a square, then it is a rhombus.f.If a quadrilateral is a parallelogram, then it is a rectangle.

Answers

a. One of the properties of squares is all sides are congruent (they have the same length) and this is not a property of rectangles. But the square is a special rectangle since it fits in the properties of rectangles, but rectangles are not squares. In this case, this is TRUE.

b. A parallelogram is a quadrilateral with two pairs of opposite parallel sides and the opposite sides are congruent. The square fits into this description, so this is TRUE.

c. A rhombus has four equal opposite parallel sides, so we can say it fits into the parallelogram definition. This is TRUE.

d. As we said in part a, a rectangle doesn't have all of its sides congruent, but the rhombus does. Then, this is FALSE.

e. Squares have four equal opposite parallel sides, and rhombus too. Then, a square is a rhombus. This is TRUE.

f. Not all parallelograms have the properties of rectangles, then this is FALSE.

Jackson types 120 words in 2 minutes. Enter the number of words Jackson types in 4 minutes at this ratewords

Answers

if in 2 minutes Jackson Typed 120 words, in 4 minutes will type twice the amount. SO

[tex]w=120\cdot2=240[/tex]

he will type 240 words in 4 minutes

Calculate the volume of the rectangular prism.A. 179 cm³B. 187 cm³C. 189 cm³D. 198 cm³

Answers

ANSWER

[tex]C.\text{ }189\text{ }cm^3[/tex]

EXPLANATION

We want to calculate the volume of the rectangular prism.

The volume of a rectangular prism is given by:

[tex]V=L*W*H[/tex]

where L = length

W = width

H = height

Therefore, the volume of the rectangular prism is:

[tex]\begin{gathered} V=9*7*3 \\ \\ V=189\text{ }cm^3 \end{gathered}[/tex]

The answer is option C.

The Hudson family is saving for a
family vacation to Disney World.
They determine that the trip will
cost $3,200. Mr. and Mrs.
Hudson have already set aside
$1,500 for the trip. If they leave
in 16 weeks, then how much
will they need to save
each week?

Answers

The amount of money that Hudson will need to save each week is $106.25.

How to calculate the value?

From the information, they determine that the trip will cost $3,200. Mr. and Mrs. Hudson have already set aside $1,500 for the trip.

Let the amount saved each week be represented as w.

Based on the information given, this will be illustrated as:

1500 + 16w = 3200

Collect like terms

16w = 3200 - 1500

16w = 1700

Divide

w = 1700 / 16

w = 106.25

The amount is $106.25.

Learn more about money on:

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I need help with math please

Answers

1. 92 .

2. 7

3. >=<

4. -

5. 8x3=24

Step-by-step explanation:

how many kiloliters are in 32,500 centiliters325 kl3,250,000,000 kl32.5 kl0.325 kl

Answers

0.325 kl

Explanation:

We need to convert from centiliters to Kiloliters:

[tex]\begin{gathered} 1liter=100^{}\text{centiliter} \\ 1\text{ kilo = 1000} \\ 1\text{ kiloliter = 1000liter} \\ 1\text{ kiloliter = 100000 centiliter} \end{gathered}[/tex][tex]\begin{gathered} 100000\text{ centiliter = }1\text{ kiloliter} \\ 32500\text{ centiliter = }\frac{\text{32500(1)}}{100000} \\ \text{= }\frac{32500}{100000} \\ 32500\text{ centiliter }=\text{ 0.325 kl} \end{gathered}[/tex]

For almost all mortgage lenders, a home buyer must put down a certain percentage ofthe selling price towards the sale and financing of a home. Different banks and differentkinds of loans have set standards. Based on the given information, solve the problems.A buyer decides to put a contract on a house he/she would like to purchase. For eachscenario given, find the amount of down payment, the loan amount, the realestate commission, and tax assessment.#1 Selling price is $250,000.00 10% down payment would be $______ the real estate commissionthe seller would pay (at 6% commission) would be $______ and the amount for the mortgage(selling price - down payment) would be $______ House assesses for $245,000.00 and the taxrate is $1.15 per $100.00 of assessed value so taxes on the house would be $_____ for theyear#2 Selling price is $195,000.00 10% down payment would be $______ the real estate commissionwould be (at 6%) $______ and the mortgage amount would be for $_______ House assesses for$189,000.00 and the tax rate is $1.09 per $100.00 so the real estate taxes for the yearwould be $______

Answers

Answer:

(1)

• 10% down payment would be $25,000.

• The real estate commission would be $15,000.

• The amount for the mortgage would be $225,000.

• Taxes on the house would be $2817.50 for the year.

(2)

• 10% down payment would be $19,500.

• The real estate commission would be $11,700

• The amount for the mortgage would be $175,000.

• Taxes on the house would be $2060.10 for the year.

Explanation:

Part 1

The selling price is $250,000.00.

[tex]\begin{gathered} \text{ Down Payment}=10\%\text{ of }250,000 \\ =0.1\times250,000 \\ =25,000 \end{gathered}[/tex]

• 10% down payment would be $25,000.

[tex]\begin{gathered} \text{ Real Estates Commission}=6\%\text{ of }250,000 \\ =0.06\times250,000 \\ =15,000 \end{gathered}[/tex]

• The real estate commission the seller would pay (at 6% commission) would be $15,000.

[tex]\begin{gathered} \text{ Mortgage Amount}=\text{ Selling Price}-\text{ Down Payment} \\ =250,000-25,000 \\ =225,000 \end{gathered}[/tex]

• The amount for the mortgage would be $225,000.

[tex]Tax=\frac{1.15}{100}\times245,000=2817.50[/tex]

• Taxes on the house would be $2817.50 for the year.

Part 2

The selling price is $195,000.00.

[tex]\begin{gathered} \text{ Down Payment}=10\%\text{ of }195,000 \\ =0.1\times195,000 \\ =19,500 \end{gathered}[/tex]

• 10% down payment would be $19,500.

[tex]\begin{gathered} \text{ Real Estates Commission}=6\%\text{ of }195,000 \\ =0.06\times195,000 \\ =11,700 \end{gathered}[/tex]

• The real estate commission the seller would pay (at 6% commission) would be $11,700.

[tex]\begin{gathered} \text{ Mortgage Amount}=\text{ Selling Price}-\text{ Down Payment} \\ =195,000-19,500 \\ =175,500 \end{gathered}[/tex]

• The amount for the mortgage would be $175,000.

[tex]Tax=\frac{1.09}{100}\times189,000=2060.10[/tex]

• Taxes on the house would be $2060.10 for the year.

hey ms or mr can you please help me out?

Answers

Answer:

B'C' = 3BC

Explanations:

Note:

When a figure is dilated by a scale factor, a similar figure of the same shape but of different size is formed.

When a triangle ABC is dilated by a scale factor of 3, the vertices of the image of ΔA'B'C' formed will have a distance from the center of dilation that is three times that of the vertices of ΔABC

Therfore:

A'B' = 3AB

B'C' = 3BC

A'C' = 3AC

The correct choice is option B

That is, B'C' = 3BC

Solve M=2rt^3-3rx for x

Answers

You have the following equation:

M = 2rt³ - 3rx

In order to solve the previous equation for x, proceed as follow:

M = 2rt³ - 3rx subtract 2rt³ both sides

M - 2rt³ = -3rx divide by -3r both sides

(M - 2rt³)/(-3r) = x simplify left side

-M/3r + 2/3 t³ = x

Please help me with this quickly, I need to go to sleep, thank you

Answers

Answer:

x = -43/4

Explanation:

Given:

[tex]\frac{17-4x}{12}=5[/tex]

To find:

the value of x

[tex]\begin{gathered} \frac{17-4x}{12}=5 \\ multiply\text{ both sides by 12:} \\ 17\text{ - 4x = 5\lparen12\rparen} \\ 17\text{ - 4x = 60} \end{gathered}[/tex][tex]\begin{gathered} add\text{ 4x to both sides:} \\ 17\text{ -4x + 14x = 60 + 4x} \\ 17\text{ = 60 + 4x} \\ \\ subtract\text{ 60 from both sides:} \\ 17\text{ - 60 = 4x} \\ -43\text{ = 4x} \\ \\ divide\text{ boh sides by 4:} \\ x\text{ = -43/4} \end{gathered}[/tex]

Solve |x| < 12 a{ x| x < -12 or x > 12}b { x|-12 < x < 12} c{-12, 12}Pllzzzzz alot of points

Answers

We need to solve the inequality:

[tex]|x|<12[/tex]

What be it’s value, to the nearest thousand dollars, in 13 years?

Answers

The Solution:

The value of the house in 13 years time can be calculated using the formula below:

[tex]F\mathrm{}V=P\mathrm{}V(1+\frac{r}{100})^n[/tex]

In this case,

[tex]\begin{gathered} FV=\text{future value (value after 13 years)=?} \\ PV=\text{present value= \$249000} \\ r=\text{ rate \%=10.5\%} \\ n=\text{ number of years=13 years} \end{gathered}[/tex]

Substituting these values in the formula above, we get

[tex]FV=249000(1+\frac{10.5}{100})^{13}=249000(1+0.105)^{13}[/tex][tex]FV=249000(1.105)^{13}=911819.68\approx\text{ \$911820}[/tex]

Thus, the value of the house in 13 years is $911820 (to the nearest dollars)

See question below as I tried to ask another tutor

Answers

Given the word problem, we can deduce the following information:

1. The formula V=2.5r can be used to estimate the maximum safe velocity,v, in miles per hour, at which a car can travel if it is driven along a curved radius of curvature r in feet.

2. The radius of curvature is 280 feet.

To determine the maximum safe speed, we use the given formula as shown below:

[tex]V=2.5r[/tex]

where:

V= Maximum safe velocity in miles per hour

r=radius of curvature = 280 feet

We plug in what we know:

[tex]\begin{gathered} V=2.5r \\ =2.5(280) \\ Calculate \\ V=700\text{ }\frac{miles}{hour} \end{gathered}[/tex]

Therefore, the maximum safe speed is 700 miles per hour.

Question 7 using radians, find the amplitudeand period of each function and graph it

Answers

Given:

y = 4 sin 4θ

The amplitude is 4.

Period:

[tex]\begin{gathered} P=\frac{2π}{B};\text{ }hence: \\ \\ P=\frac{2π}{4}=\frac{π}{2} \end{gathered}[/tex]

The period is π/2.

Graph:

6/2(1+2)help me with math problem

Answers

[tex]\frac{6}{2}(1+2)=3(1+2)=3(3)=9[/tex]

Which kind of symmetry does the letter D have?A. point symmetry, onlyB. line symmetry, onlyC. neither point nor line symmetryD. both point and line symmetry

Answers

Analysing the letter D, we can find the following symmetry (in red):

There is no point of symmetry. Therefore, the correct option is B.

one-half of a number y is more than 22

Answers

1) Writing that statement as an inequality we have:

[tex]\begin{gathered} \frac{y}{2}>22\text{ } \\ Multiplied\text{ by 2 on both sides} \\ y>44 \end{gathered}[/tex]

2) Hence, we can say that if one-half of a number y is more than 22​

then y > 44

i need help with this

Answers

graphing the points

answer: (- 8, 6)

A sales person is given a choice of two salary plans. Plan 1 is a weekly salary of 700 plus 4% commission of sales. Plan 2 is a straight commission of 12%Of sales. How much in sales must he make in a week for both plans to result in the same salary?

Answers

Let 's' represent the amount of sales.

Plan 1:

[tex]\text{ \$700 + (4\% of s)}[/tex][tex]\begin{gathered} \text{ \$700+(}\frac{\text{4}}{100}\times s) \\ \text{ \$700+(0.04}\times s)=\text{ \$700}+0.04s \end{gathered}[/tex]

Plan 2:

[tex]12\text{ \% of s}[/tex][tex]\begin{gathered} \frac{12}{100}\times s \\ 0.12\times s=0.12s \end{gathered}[/tex]

Equating the two plans together and solving for the amount of sales,

[tex]\begin{gathered} \text{Plan 2=Plan 1} \\ 0.12s=\text{ \$700+0.04s} \\ \end{gathered}[/tex]

Collecting like terms,

[tex]\begin{gathered} 0.12s-0.04s=\text{ \$700} \\ 0.08s=\text{\$700} \end{gathered}[/tex]

Divide both sides by 0.08,

[tex]\begin{gathered} \frac{0.08s}{0.08}=\frac{\text{ \$700}}{0.08} \\ s=\text{ \$8750} \end{gathered}[/tex]

Hence, the amount of sales is $8,750.

QuestionWrite the following function in terms of its cofunction.csc (pi/4)

Answers

Two functions are called cofunctions if they are equal on complementary angles

[tex]\csc \theta=\sec (\frac{\pi}{2}-\theta)[/tex]

Since

[tex]\theta=\frac{\pi}{4}[/tex]

Substitute it in the rule above

[tex]\csc (\frac{\pi}{4})=sec(\frac{\pi}{2}-\frac{\pi}{4})[/tex][tex]\csc (\frac{\pi}{4})=\sec (\frac{\pi}{4})[/tex]

The cofunction is sec(pi/4)

Solve for 2. Enter the solutions from least to greatest.(x + 6)2 – 16 = 0lesser 1 =greater I =

Answers

The given expression is

[tex](x+6)^2-16=0[/tex]

First, we add 16 on each side

[tex]\begin{gathered} (x+6)^2-16+16=16 \\ (x+6)^2=16 \end{gathered}[/tex]

Then, we apply a square root on each side

[tex]\begin{gathered} \sqrt[]{(x+6)^2}=\sqrt[]{16} \\ x+6=\pm4 \end{gathered}[/tex]

Now, we subtract 6 from each side

[tex]\begin{gathered} x+6-6=\pm4-6 \\ x_1=4-6=-2 \\ x_2=-4-6=-10 \end{gathered}[/tex]Therefore, the lesser solution is -10 and the greater solution is -2.

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Answers

Given,

g(x) = - x^2

now, in part (b), we have to find g(-2)

It can be done by replacing the value of x with -2, so

g(x) = - x^2

g(-2) = - (-2)^2

g(-2) = - 4

Part d:

g(m) = ?

So, here we will put the 'm' value in place of x.

g(x) = - x^2

g(m) = - (m)^2

g(m) = -m^2

how do I solve for x intercepts of this equation. I'm having trouble solving it.[tex]y = 2x ^{2} + 12x + 13[/tex]

Answers

[tex]y=2x^2+12x+13[/tex]

To find the x-intercepts of this equation, substitute y by 0 at first

[tex]0=2x^2+12x+13[/tex]

Now we need to factor this equation into 2 factors

We need 2 numbers their sum = 12 (the middle term)

But we can not find them mentally, then we will use the formula

[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]

a is the coefficient of x^2

b is the coefficient of x

c is the numerical term

a = 2, b = 12, c = 13

Let us substitute them in the rule to find x

[tex]\begin{gathered} x=\frac{-12+\sqrt[]{(12)^2-4(2)(13)}}{2(2)} \\ x=\frac{-12+\sqrt[]{144-104}}{4} \\ x=\frac{-12+\sqrt[]{40}}{4} \end{gathered}[/tex]

We will simplify the root

[tex]x=\frac{-12+2\sqrt[]{10}}{4}[/tex]

Divide up and down by 2 to simplify the fraction

[tex]x=\frac{-6+\sqrt[]{10}}{2}[/tex]

The 2nd root will be the same number but a different middle sign

[tex]x=\frac{-6-\sqrt[]{10}}{2}[/tex]

The x-intercepts are

[tex](\frac{-6+\sqrt[]{10}}{2},0)\text{and(}\frac{-6-\sqrt[]{10}}{2},0)[/tex]

Multiply the following [tex] \sqrt{ - 15} \times \sqrt{ - 15} [/tex]

Answers

Answer: -15

Given:

[tex]\sqrt[]{-15}\times\sqrt[]{-15}[/tex]

Since the radical rule states that:

[tex]\begin{gathered} \sqrt[]{a}\sqrt[]{a}=a \\ \Rightarrow\sqrt[]{-15}\times\sqrt[]{-15}=-15 \end{gathered}[/tex]

Therefore, the answer is -15.

2. Find each of the following products of monomials. (a) (3x?) (10x) (b) (-2x)(-9x) (c) (4x+y)(8x*y) (d) (5x) (e) (-41)(-151") 2 (f) (7x)(5xy^) ** | (12x) (h) (2xP)(5x)(-6x4)

Answers

In order to solve the products between the followings monomials you take into account that the multiplication is in between coefficients, and also you take into account that it is necessary to multiply the involved signs.

a)

[tex](3x^3)(10x^4)=(3)(10)x^{^{3+4}}=30x^7[/tex]

when the product is between the same variable but different exponents, you sum the exponents

b)

[tex](-2x^5)(-9x)=(-2)(-9)x^{5+1}=18x^6[/tex]

where you have used that minus multiplied by minus is equal to positive

c)

[tex](4x^2y)(8x^5y^3)=(4)(8)x^{2+5}y^{1+3}=32x^7y^4[/tex]

where you sum the exponents of x and y

d)

[tex](5x^4)^2=(5)^2(x^4)^2=25x^{4\cdot2}=25x^8[/tex]

In the case in which you have a variable with an exponent, power to another exponent, these exponents must be multiplied. The coeeficient also has to be exponentiated

e)

[tex](-4t^2)(-15t^5)=(-4)(-15)t^{2+5}=60t^7[/tex]

f)

[tex](7x)(5xy^4)=35x^2y^4[/tex]

g)

[tex](\frac{2}{3}x^4)(12x)=\frac{2\cdot12}{3}x^5=8x^5[/tex]

f)

[tex](2x^2)(5x)(-6x^4)=(2)(5)(-6)x^{2+1+4}=-60x^7[/tex]

where you multiply all coefficientes and signs, and sum the exponents of x

Look again at the table of refrigerator sizes and prices. Is the relation a function?A. The relation is not a function. All input values are paired with only oneoutput value.B. The relation is not a function. Some of the input values are paired withmore than one output value.C. The relation is a function. The input values are paired with more than oneoutput value.D. The relation is a function. All input values are paired with only one outputvalue.HINTSUBMIT

Answers

B. The relation is not a function. Some of the input values are paired with

more than one output value.

Explanation

A function is a relation from a set of inputs to a set of possible outputs where each input is related to exactly one output.

Step 1

Identify the input values and compare with the outputs

as we can see one input is related to TWO outputs, for example

[tex]\begin{gathered} 1.7\rightarrow80 \\ 1.7\rightarrow79 \end{gathered}[/tex]

hence, the relation is not a function

B. The relation is not a function. Some of the input values are paired with

more than one output value.

I hope this helps you

12 posters for 36 students 21 poses for 36 students

Answers

In order to find Lorenzo's speed in miles per hour, we need to convert from yard to mile and from second to hour. The rates are:

1 yard = 1/1760 miles

1 second = 1/3600 hours

So we have that:

[tex]\text{speed}=5\frac{yards}{\sec ond}=5\frac{\frac{1}{1760}miles}{\frac{1}{3600}hour}=5\frac{3600}{1760}\frac{miles}{hour}=10.227\text{ miles/hr}[/tex]

Lorenzo can ride 10.227 miler per hour.

i have an answer in mind i just need to make sure its correct

Answers

The names of the angles are ; ∠XYZ , ∠ ZYX or ∠1

Here, we want to give three different ways in which we can name the angle

To name the angle, we can use the two end points and the location of the angle itself as angle

This can be ∠ZYX or ∠XYZ

Lastly, we can make use of the labeling on the angle itself

The name can be ∠1

For f(x) = 2x and g(x) = x,find f (g(2))

Answers

Answer: f(g(2)) = 4Explanation:f(x) = 2xg(x) = xSince g(x) = x, at x = 2;g(2) = 2Since g(2) = 2, and f(x) = 2x; f(g(2) = f(2) = 2(2)f(g(2) = 4

write a recursive rule for the sequence -10,-3,4,11

Answers

Let the given sequence is -10,-3,4,11

The objective is to write recursive rule for the sequence.

In the given sequence each number has an equal difference between them

[tex]\begin{gathered} -3-(-10)=7 \\ 4-(-3)=7 \\ 11-4=7 \end{gathered}[/tex]

So, consider the terms as,

[tex]\begin{gathered} a_1=-10 \\ a_2=-3 \\ a_2=a_1+7 \\ a_3=a_2+7 \\ a_4=a_3+7 \end{gathered}[/tex]

Hence the recursive series is

[tex]a_n=a_{n-1}+d[/tex]

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