Someone please help me with this problem in the most simple easy way possible no long explanation needed.

Someone Please Help Me With This Problem In The Most Simple Easy Way Possible No Long Explanation Needed.

Answers

Answer 1

ANSWER:

2797.74 cubic inches

EXPLANATION:

Given:

Height of the cylinder(h) = 11 inches

Radius of the cylinder(r) = 9 inches

Pi = 3.14

To find:

The volume(V) of the cylinder

We'll go ahead and determine the volume(V) of the cylinder using the below formula;

[tex]\begin{gathered} V=\pi r^2h \\ =3.14*9^2*11 \\ =31.4*81*11 \\ =2797.74\text{ cubic inches} \end{gathered}[/tex]

So the volume of the cylinder is 2797.74 cubic inches


Related Questions

Jeff has 45 pounds of organic apples. He earns $4.50 for every 3/4of a pound of organicapples he sells. How much money will Jeff receive if he sells all his organic apples?

Answers

Given data:

The total weight of the apples Jeff have W=45 pounds.

The amount Jeff earned for every 3/4 pound of apple is A=$4.50.

The expression for the given statement is,

[tex]\begin{gathered} \frac{3}{4}\text{ pound =\$4.50} \\ 1\text{ pound =\$6} \end{gathered}[/tex]

Multiple the above expression by 45 on both sides.

[tex]\begin{gathered} 45(\text{ 1 pound)=45(\$6)} \\ 45\text{ pounds =\$270} \end{gathered}[/tex]

Thus, the amount Jeff earned is $270.

how do I do plus 4 with 928 times 90 equal to what plus 57 divided by 134

Answers

[tex]4\text{ + 928 }\times\text{ 90 = x +}\frac{57}{134}[/tex][tex]\begin{gathered} 4\text{ + 83520 =}\frac{134x\text{ + 57}}{134} \\ 83524\text{ }\times134\text{=134x + 57} \\ 11192216\text{ - 57 = 134x} \\ 11192159\text{ =134x} \\ x\text{ =}\frac{11192159}{134}\text{ = 83523.57} \end{gathered}[/tex]

What to plus 57 divided by 134 is 83523.57

add 3 feet 6 in add 3 feet 6 in + 8 ft 2 in + 4in + 2ft 5in what does that add up to

Answers

We want to find the sum of;

3 feet 6 in + 3 feet 6 in + 8 ft 2 in + 4in + 2ft 5in.

Recall that;

[tex]1\text{ feet = 12 inches}[/tex]

Adding we have;

[tex]undefined[/tex]

301123233What Happened When the Crossword Puzzle Champion Died?Find the graph of the solution set of each inequality below in the corresponding column of graphs. Notice the letter next to it.Write this letter in each box containing the number of that exercise. Keep working and you will find out about this grave event.x<2(10 x<1 0 4x is less than 2-3 -2 -1 0 1 2 3-3 -2 -1 0 1 2X<2D++++-3 -2 -123-3 -2 -1 0 1 2 33 x>2+ 12 -3 2 A +++ +13 x>-3-3 -2 -1 0 1 2-3 -2 -1 0 1 2 3(5) x 114 #-1 ++++-3 -2 -10 1 2 3x < -1 A+++ 6 0 >-3 -2 -12-3 -2 -1 0 1 2 3x>-1 E+6 0 6 +++-3 -2 -1 0 1 2-3 -2 -1 0 1 2 318 0

Answers

I'm doing it on my notebook, hold on, it's easy

Select the correct answer from each drop-down menu. The general form of the equation of a circle is 7x2 + 7y2 − 28x + 42y − 35 = 0. The equation of this circle in standard form is . The center of the circle is at the point , and its radius is units.

Answers

1.) At a conference, there are 176 math teachers and 16 science teachers.

In the last three years, Franks basketball team won 20 more games than they lost. if they won 130 games, what was the ratio of wins to looses? Write in fraction form.

Red
2.) Green Beans are canned by 2 companies. The Del Monte Company sells
14.5 oz for $1.75 and the Green Giant company sells 15.5 oz for $1.95.
Who has the best deal?



3.)In the last three years, Frank's basket ball team won 20 more games than
they lost. If they won 130 games, what was the ratio of wins to losses?
Write in fraction form.
((. 3 questions into one pls answer !))

Write two numbers that multiply to the value on top and add to the value on bottom.-14Х5

Answers

Let the first number be m while the second num

Erica's marks in eight consecutive mathematics examinations were:94,83,75,52,71,68,75,49

Answers

(a) The total marks Erica scored is the sum of the given marks:

total = 94 + 83 + 75 + 52 + 71 + 68 +75 + 49 = 567

(b) The mean is given by the quotient between the total and the number of marks, as follow:

mean = 567/8 = 70.875

Consider the relation y = −3|x + 5| − 6. What are the coordinates of the vertex?

Answers

Solution:

Given the relation below

[tex]y=-3|x+5|-6[/tex]

The general form, an absolute value function is

[tex]y=a|x-h|+k[/tex]

The vertex coordinates are (h, k)

Solving to find the vertex below

[tex]\begin{gathered} x+5=x-h \\ 5=-h \\ h=-5 \\ k=-6 \\ (h,k)\Rightarrow(-5,-6) \end{gathered}[/tex]

Hence, the coordinates of the vertex is

[tex](-5,-6)[/tex]

Use this graph of y = 2x2 - 12x + 19 to find the vertex. Decide whether thevertex is a maximum or a minimum point.TV-5O A. Vertex is a minimum point at (1,3)B. Vertex is a minimum point at (3,1)C. Vertex is a maximum point at (1,7)D. Vertex is a maximum point at (3,1)

Answers

For a parabola, the vertex is the critical point, in other words, it is the maximum or the minimum of the function.

From the graph, we can see that the minimum (the minimum value of y) of the graph is 1. The vertex is the point (3,1).

Moreover, as we mentioned the vertex is always the minimum or the maximum, in this case, it is the minimum since the rest of the graph is 'above' that point.

The answer is option B. Vertex is a minimum point at (3,1)

2.Flight of a Model Rocket A model rocket is launched from the ground with veloc-ity 48 ft per sec at an angle of 60° with respect to the ground.(a) Determine the parametric equations that model the path of the projectile.(b) Determine the rectangular equation that models the path of the projectile.(c) Determine approximately how long the projectile is in flight and the horizontaldistance covered.

Answers

The parametric equation for the rocket is given by

x = 24 t and y = 24√3 t

Given velocity = 48 ft per sec

∅ = 60°

Distance = speed × time

d = 48t

Displacement along the x-axis

= v cos ∅

= 48× t ×cos60°

=24 t

displacement along the y axis

= v sin ∅

=48 t sin 60°

=24√3 t

In mathematics, a parametric equation represents a set of numbers as functions between one or maybe more independent variables, often known as parameters.

When equations are used to indicate the dimensions of the constituent parts of a geometric object, such as a curve or surface, they are collectively referred to as the parametric representation (alternatively written as parametrization) of the object.

b) now we will use the parametric equation to calculate the rectangular equation.

we know that x = 24t and y = 24√3 t

again, x/24 = y/24√3

or, √3x = y

c) Hence we can see that the parametric equation for the projectile is given by x = 24 t and y = 24√3 t and the rectangular equation is given by

√3x = y .

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Convert the measurement. 12 in/sec = ft/min

Answers

kmartinez2849, this is the solution:

Let's recall that:

1 inch/second = 5 feet/minute

Thus:

12 inch/second = 5 * 12 feet/minute

12 inch/second = 60 feet/minute

Let's recall that:

1 feet = 12 inches

1 minute = 60 seconds

Therefore:

1 inch/second * 60 = 60 inches/minute

Converting inches to feet

60 inches = 5 feet

In conclusion, 5 feet/minute

Kyle throws a baseball straight up from a height of 5 feet with an initial speed of 41feet per second.What is the maximum height of the baseball?

Answers

We will determine the maximum height of the baseball as follows:

We will need the following formulas:

[tex]v=u+at[/tex][tex]s=ut+\frac{1}{2}at^2[/tex]

Here "u" represents the original speed, "t" represents the time, "a" the acceleration of the body and "s" is the total discance moved. [We will find s to solve the problem].

So:

First we have that the acceleation that the body will experience is -9.8m/s^2 [Since the object is going upwards and gravity is pulling on it towards the ground]. [acceleration of gravity using feet over second squared is 32.17 ft/s^2].

[tex]v=(12.4968)+(-9.8)t[/tex]

But the maximum height will be reached when the velocity after certain time has passed is 0 ft/s, so:

[tex]0=(12.4968)+(-9.8)t\Rightarrow9.8t=12.4968[/tex][tex]\Rightarrow t=1.275183673\ldots\Rightarrow t\approx1.3[/tex]

So, at approximately 1.3 seconds the maximum heigth willl be reached.

Now, we solve for s:

[tex]s=(12.4968)(1.275183673)+\frac{1}{2}(-9.8)(1.275183673)^2\Rightarrow s=7.967857665[/tex][tex]\Rightarrow s\approx8[/tex]

So, the maxumum altitude for the baseball will be 8 meters, but we have to add the initial 5 feet at which it was launched:

[tex]h\approx8+1.524\Rightarrow h\approx9.491857665[/tex]

And taking that to feet we will have:

[tex]h\approx31.141265305118\ldots[/tex]

So, the solution must be the last option. [The discrepanc

n - 3 over 10 = 3 over 5

Answers

The given expression is

[tex]\frac{n-3}{10}=\frac{3}{5}[/tex]

First, we multiply by 10 on each side.

[tex]\begin{gathered} 10\cdot\frac{n-3}{10}=\frac{3}{5}\cdot10 \\ n-3=6 \end{gathered}[/tex]

Then, we sum 3 on each side.

[tex]\begin{gathered} n-3+3=6+3 \\ n=9 \end{gathered}[/tex]Therefore, the solution is 9.

Evaluate the expression and leaving your answer in polar form.

Answers

Complex numbers z₁ = 6 · [tex]e^{i\,\frac{17\pi}{20} }[/tex] and z₂ = 6 · [tex]e^{i\,\frac{27\pi}{20} }[/tex] are the square roots of the complex number in polar form.

How to find the square root of a complex number in polar form

In this problem we find a complex number in polar form, that is, a complex number of the form:

z = r · [tex]e^{i\,\theta}[/tex]

Where:

r - Norm of the complex number.θ - Direction of the complex number, in radians.

The square root of this number can be found by means of the De Moivre's theorem:

[tex]\sqrt{z} = \sqrt{z} \cdot e^{i\,\left(\frac{\theta + 2\pi\cdot k}{n} \right)}[/tex], for k = {0, 1}

If we know that z = 36 and θ = 17π / 10, then the roots of the complex number are:

z₁ = 6 · [tex]e^{i\,\frac{\frac{17\pi}{10}}{2} }[/tex]

z₁ = 6 · [tex]e^{i\,\frac{17\pi}{20} }[/tex]

z₂ = 6 · [tex]e^{\frac{\frac{17\pi}{10} + 2\pi }{2} }[/tex]

z₂ = 6 · [tex]e^{i\,\frac{27\pi}{20} }[/tex]

The solutions are z₁ = 6 · [tex]e^{i\,\frac{17\pi}{20} }[/tex] and z₂ = 6 · [tex]e^{i\,\frac{27\pi}{20} }[/tex].

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How much should be invested now at an interest rate of 6.5% per year, compounded continuously l, to have $3500 in four years.Round your answer to the nearest cent.

Answers

Okay, here we have this:

Considering the provided information we are going to replace in the formula of continuous compound interest:

[tex]\begin{gathered} A=Pe^{rt} \\ 3500=Pe^{(0.065\cdot4)} \end{gathered}[/tex]

Now, let's solve for P:

[tex]\begin{gathered} P=\frac{3500}{e^{0.26}} \\ P=$2,698.68$ \end{gathered}[/tex]

Finally we obtain that should be invested $2,698.68.

what is the value of B ( area of the base) for the following triangular prism?40 ft^248 ft^260 ft^224ft^2

Answers

SOLUTION:

The base of the prism is a triangle and the formula for finding the area of a triangle is "half base multiplied by height".

From the figure of the prism given the base and height of the triangle is 6 ft and 8 ft.

[tex]\begin{gathered} \frac{1}{2\text{ }}\text{ x 6 x 8} \\ \\ \frac{48}{2} \\ \\ 24ft^2 \end{gathered}[/tex]

CONCLUSION:

The area of the base of the given triangular prism is 24 squared feet ( the fourth option).

Find the tangent of the larger acute angle in a right triangle with side lengths 3, 4, and 5.

Write your answer as a fraction.

The tangent of the larger acute angle is ______?______

Answers

The tangent should be in fraction is 4/3

Calculation of the tangent:

Since in a right triangle with side lengths 3, 4, and 5

Here there is the larger acute angle in the 3, 4 and 5 so it should be lies between 3 and 5

So, it should be like

= opposite side ÷ adjacent side

= 4/3

Hence, The tangent should be in fraction is 4/3

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Use the given conditions to find the exact values of sin(2u), cos(2u), and tan(2u) using the double-angle formulas.tan(u) = 13/5, 0 < u < /2

Answers

The first step to answer this question is to find tan(2u) by using the double angle formula:

[tex]\begin{gathered} tan(2u)=\frac{2tan(u)}{1-tan^2(u)} \\ tan(2u)=\frac{2(\frac{13}{5})}{1-(\frac{13}{5})^2} \\ tan(2u)=\frac{\frac{26}{5}}{1-\frac{169}{25}} \\ tan(2u)=\frac{\frac{26}{5}}{-\frac{144}{25}} \\ tan(2u)=-\frac{65}{72} \end{gathered}[/tex]

It means that tan(2u) is -65/72.

The next step is to rewrite the equations for sin(2u) and cos(2u) to have them in terms of the least number of variables possible, this way:

[tex]\begin{gathered} sin(2u)=2sin(u)cos(u) \\ sin(2u)=2sin(u)\frac{sin(u)}{tan(u)} \\ sin(2u)=\frac{2sin^2(u)}{tan(u)} \end{gathered}[/tex][tex]\begin{gathered} cos(2u)=cos{}^2(u)-sin^2(u) \\ cos(2u)=1-sin^2(u)-s\imaginaryI n^2(u) \\ cos(2u)=1-2sin^2(u) \end{gathered}[/tex]

If we rewrite tan(2u) in terms of sin(2u) and cos(2u) we will have:

[tex]\begin{gathered} tan(2u)=\frac{sin(2u)}{cos(2u)} \\ tan(2u)=\frac{\frac{2s\imaginaryI n^{2}(u)}{tan(u)}}{1-2sin^2(u)} \end{gathered}[/tex]

We know the values of tan(2u) and tan(u), so we can solve the equation for sin^2(u).

[tex]\begin{gathered} tan(2u)=\frac{2sin^2(u)}{tan(u)(1-2sin^2(u))} \\ -\frac{65}{72}=\frac{2s\imaginaryI n^2(u)}{\frac{13}{5}(1-2s\imaginaryI n^2(u))} \\ -\frac{65}{72}\cdot\frac{13}{5}\cdot(1-2sin^2(u))=2sin^2(u) \\ -\frac{169}{72}(1-2sin^2(u))=2sin^2(u) \\ -1+2sin^2(u)=\frac{72}{169}\cdot2sin^2(u) \\ -1+2sin^2(u)=\frac{144}{169}sin^2(u) \\ 2sin^2(u)-\frac{144}{169}sin^2(u)=1 \\ \frac{194}{169}sin^2(u)=1 \\ sin^2(u)=\frac{169}{194} \end{gathered}[/tex]

Using this value we can find the values of sin(2u) and cos(2u):

[tex]\begin{gathered} sin(2u)=\frac{2sin^2(u)}{tan(u)} \\ sin(2u)=\frac{2\cdot\frac{169}{194}}{\frac{13}{5}} \\ sin(2u)=\frac{65}{97} \end{gathered}[/tex][tex]\begin{gathered} cos(2u)=1-2sin^2(u) \\ cos(2u)=1-2\cdot\frac{169}{194} \\ cos(2u)=1-\frac{169}{97} \\ cos(2u)=-\frac{72}{97} \end{gathered}[/tex]

It means that sin(2u)=65/97, cos(2u)=-72/97 and tan(2u)=-65/72.

Use long division to find the quotient. If there is a remainder do not include it in your answer. Recall:dividend\div divisor=quotient (4x^2-10x+6) \div(4x+2) Answer:

Answers

Let's do the division:

Answer: x-3

If f(x) is a third degree polynomia function, how many distinct complex roots are possible?

Answers

Complex roots always appear in pairs, actually if a+ib is a root then a-ib is also a root. Then, at most there are 2 complex roots in a third degree polynomial.

Simplify:6.2n - 8.3 + -9.1 + 1.4n

Answers

ANSWER

7.6n - 17.4

EXPLANATION

We have the expression that we want to simplify.

We have:

6.2n - 8.3 + (-9.1) + 1.4n

The first step is to collect like terms:

=> 6.2n + 1.4n - 8.3 - 9.1

Now, simplify:

7.6n - 17.4

That is the answer.

Both circles have the same center. What is the area of the shaded region?10.7 md=26.2 mUse 3.14 for a. Write your answer as a whole number or a decimal rounded to the nearesbundredth

Answers

To determine the area of the shaded region, we would subtract the area of the smaller or inner circle from the area of the bigger or outer circle.

From the information given,

diameter of inner circle = 26.2m

radius of inner circle = diameter/2 = 26.2/2 = 13.1m

B applying the formula for determining the area of a circle which is expressed as

Area = pie * r^2,

pie = 3.14

Area of inner circle = 3.14 * 13.1^2 = 538.86 m^2

Radius of outer circle = 10.7 + 13.1 = 23.8m

Area of outer circle = 3.14 * 23.8^2 = 1778.62m^2

Therefore,

Area of shaded region = 1778.62 - 538.86 = 1239.76m^2

5.True or False: The ordered pair (0, 3) is a solution to the equationy = -5x + 3.

Answers

You have the following equation:

y = -5x + 3

in order to determine if the point (0,3) is solution of the previous equation, replace the values of x = 0 and y = 3, and verify if the equation is consistent, as follow:

3 = -5(0) + 3

3 = 3

the equation is consistent for the given point, then, the point (0,3) is a olution of the given equation

A professor had students keep track of the social relations for a week and a number of social directions over the weekend and following the distribution how many students had at least 75 social interactions in the week?

Answers

Answer: 12 students

Since we need to find how many students had at least 75 social interactions in the week, we will add up all the frequencies from at least 75 interactions. Looking at the given table, that would be 3, 6, 1, and 2.

Adding them up together and we will get:

[tex]3+6+1+2=12[/tex]

Therefore, 12 students had at least 75 social interactions in the week.

The figure below shows an upside-down pyramid with a square base.inverted pyramid with a square baseNote: figure not to scale.Which shape does the intersection of the horizontal plane with the pyramid look like?

Answers

ANSWER:

EXPLANATION:

Given:

Since the pyramid has a square base, therefore intersection of the horizontal plane will produce a shape that looks like a square.

Find the range of the function for the given domain: {-4, 0, 4}
f(x)=x²-2
O {-14, 2)
O {-14, 2, 18)
O {-2, 14)
O (-18, -2, 14)

Answers

Answer:

{-2,14}

Step-by-step explanation:

f(-4) = f(4) = 14

f(0) = -2

Paul has $50,000 to invest. His intent is to earn 13% interest on his investment. He can invest part of his money at 8% interest and part at 16% interest. How much does Paul need to invest in each option to make a total 13% return on his $50,000?8% interest $ 16% interest $

Answers

Let x be the amount invest at 8%

Let y be the amount invest at 16%

Paul has $50,000 to invest:

[tex]x+y=50,000[/tex]

His intent is to earn 13% interest on his investment. He can invest part of his money at 8% interest and part at 16% interest.

[tex]\begin{gathered} 50,000(0.13)=x(0.08)+y(0.16) \\ \\ 6,500=0.08x+0.16y \end{gathered}[/tex]

Use the next system of equations to find x and y:

[tex]\begin{gathered} x+y=50,000 \\ 6,500=0.08x+0.16y \end{gathered}[/tex]

1. Solve x in the first equation:

[tex]x=50,000-y[/tex]

2. Substitute the x in the second equation by the value you get in the previous step:

[tex]6,500=0.08(50,000-y)+0.16y[/tex]

3. Solve y:

[tex]\begin{gathered} 6,500=4,000-0.08y+0.16y \\ 6,500=4,000+0.08y \\ 6,500-4,000=0.08y \\ 2,500=0.08y \\ \frac{2,500}{0.08}=y \\ \\ y=31,250 \end{gathered}[/tex]

4. Use the value of y to solve x:

[tex]\begin{gathered} x=50,000-y \\ x=50,000-31,250 \\ x=18,750 \end{gathered}[/tex]

Solution for the system:

x=18,750

y=31,250

Answer: Paul needs to invers8% interest $18,75016% interest $31,250

A group of workers can plant  334  acres in  118  days. What is the unit rate in acres per day? Write your answer as a fraction or a mixed number in simplest form.

Answers

[tex]\text{Unit rate in acres per day is }2\frac{53}{57}[/tex]

Explanation:

Number of acres = 334

Number of days = 118 days

unit rate = Number of acres/Number of days

Unit rate = 334 acres/114 days

2 is common to both numerator and denominator

Divide both by 2:

Unit rate = 167/57

No other number asides 1 is common to both the numerator and denominator

Hence, the unit rate in acres per day is 167/57

In mixed fraction = 2 53/57

The organizer of a conference is selecting workshops to include. She will select from 6 workshops about chemistry and 7 workshops about biology. In how many ways can she select 4 workshops if 2 or fewer must be about chemistry?

Answers

Given that there are 6 workshops about chemistry and 7 workshops about biology.

So the total number of workshops available are,

[tex]\begin{gathered} =6+7 \\ =13 \end{gathered}[/tex]

The number of ways of selecting 'r' objects from 'n' distinct objects is given by,

[tex]^nC_r=\frac{n!}{r!\cdot(n-r)!}[/tex]

The total number of ways of selecting 4 workshops having no workshop about chemistry is calculated as,

[tex]\begin{gathered} n(\text{ 0 chemistry)}=^7C_4 \\ n(\text{ 0 chemistry)}=\frac{7!}{4!\cdot(7-4)!} \\ n(\text{ 0 chemistry)}=\frac{7\cdot6\cdot5\cdot4!}{4!\cdot3!} \\ n(\text{ 0 chemistry)}=\frac{7\cdot6\cdot5}{3\cdot2\cdot1} \\ n(\text{ 0 chemistry)}=35 \end{gathered}[/tex]

The total number of ways of selecting 4 workshops having exactly 1 workshop about chemistry is calculated as,

[tex]\begin{gathered} n(\text{ 1 chemistry)}=^7C_3\cdot^6C_1 \\ n(\text{ 1 chemistry)}=\frac{7!}{3!\cdot(7-3)!}\cdot\frac{6!}{1!\cdot(6-1)!} \\ n(\text{ 1 chemistry)}=\frac{7\cdot6\cdot5\cdot4\cdot3!}{3!\cdot4!}\cdot\frac{6\cdot5!}{1!\cdot5!} \\ n(\text{ 1 chemistry)}=\frac{7\cdot6\cdot5\cdot4}{4\cdot3\cdot2\cdot1}\cdot6 \\ n(\text{ 1 chemistry)}=210 \end{gathered}[/tex]

The total number of ways of selecting 4 workshops having exactly 2 workshops about chemistry is calculated as,

[tex]\begin{gathered} n(\text{ 2 chemistry)}=^7C_2\cdot^6C_2 \\ n(\text{ 2 chemistry)}=\frac{7!}{2!\cdot(7-2)!}\cdot\frac{6!}{2!\cdot(6-2)!} \\ n(\text{ 2 chemistry)}=\frac{7\cdot6\cdot5!}{2!\cdot5!}\cdot\frac{6\cdot5\cdot4!}{2!\cdot4!} \\ n(\text{ 2 chemistry)}=\frac{7\cdot6}{2\cdot1}\cdot\frac{6\cdot5}{2\cdot1} \\ n(\text{ 2 chemistry)}=315 \end{gathered}[/tex]

Consider that the number of ways to select 4 workshops if 2 or fewer must be about chemistry, will be equal to the sum of the individual cases when the number of chemistry workshops in the selection are either 0 or 1 or 2.

This can be calculated as follows,

[tex]\begin{gathered} \text{ Total}=n(\text{ 0 chemistry)}+n(\text{ 1 chemistry)}+n(\text{ 2 chemistry)} \\ \text{Total}=35+210+315 \\ \text{Total}=560 \end{gathered}[/tex]

Thus, the total number of ways is 560.

There are 25
students in an
Algebra class. 9 of
them got an A on
the test. What
percent of them
scored an A?

Answers

Answer:

36%

Step-by-step explanation:

First, you would write that as a fraction, which would be 9/25. Then, you'd convert the fraction to a percentage by getting the denominator to 100. Multiply the numerator and denominator by 4 to achieve this. The answer would be 36/100, which translates to 36%.

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