solve the system of equations by graphing. y = -5x + 4 andy = 3x + 4

Answers

Answer 1

1) To solve this System of Solutions graphically, we'll need to plot those lines described by those respective equations.

2) Let's set two tables

y=-5x +4

x | y

1 -1 ( 1,-1)

2 -6 ( 2,-6)

3 -11

y=3x + 4​

x | y

1 | 7 ( 1,7)

2 |10 ( 2,10)

3 | 13

2.2 Let's plot those equations and interpret the results:

3) As these lines have point (0,4) as their common point. Therefore we can state that the solution for this consistent system is S=(0,4)

Solve The System Of Equations By Graphing. Y = -5x + 4 Andy = 3x + 4
Solve The System Of Equations By Graphing. Y = -5x + 4 Andy = 3x + 4

Related Questions

Hello! Would you please explain if Questions 7 and 8 are the same? I'm confused if I need to sub x for 23 for number 8

Answers

In question 7, the exercise only wants an explanation, in text form, of the meaning of the substitutions. That is, that the value of x=5 indicates the time that has passed, 5 hours, and that f(5)=32 indicates the number of riders.

In question 8, you need to pick some values for x, make a table with those values and the respective values of the function when you substitute those values of x, and put the points on the graph.

PLEASE HELPPP ASAP For the trapezoid below, what is he correct term for RL

Answers

GIVEN:

We are given the diagram showing a trapezoid REWT, with the vertical line RL.

Required;

Identify the correct term for the line RL.

Solution;

The trapezoid has;

RE = Shorter base

TW = Longer base

RL = Altitude (or vertical height).

ANSWER:

The correct answer is option B

[tex]Altitude[/tex]

can u tell me what the answer are ????

Answers

Answer:

Step-by-step explanation:

x = 10

y = -1


See pics for explanation:-

Hope it helps :)

Can you please help me with this questions Find the critical value t(alpha/2) corresponding to the 95% confidence interval

Answers

Answer:

df = 49

t = 2.01

Explanation:

The degrees of freedom for the t-distribution is always equal to the size of the sample n minus 1, so the degrees of freedom are:

df = n - 1

df = 50 - 1

df = 49

Then, the critical value is t(alpha/2) can be calculated using a t table with 49 degrees of freedom, where

alpha = 100% - 95% = 5%

So, alpha/2 = 5%/2 = 2.5%

Therefore, using a table, we get:

[tex]t_{\frac{\alpha}{2}}=2.01[/tex]

So, the answers are:

df = 49

t = 2.01

need help find the crimcumference of each circles round your answer to the nearest tenth.

Answers

The formula in getting the circumference of a circle is:

[tex]C=2\pi r[/tex]

where r = length of the radius and π = 3.14159.

Since the radius is already given in the circle which is 9.9 km, let's use this value to replace "r" in the formula. Use 3.14159 to replace π as well.

[tex]C=2\times3.14159\times9.9km[/tex]

Then, multiply.

[tex]C=62.203482km\approx62.2km[/tex]

Hence, the circumference of the given circle is approximately 62.2 km.

Please break down how to do these pls

Answers

The value of given expressions is -4[tex]x^{-2}[/tex] + 3[tex]y^{0}[/tex] = 19 and 2[tex]x^{0}[/tex][tex]y^{-2}[/tex] = 0.08

Simplifying an equation is simply another way of saying solving a math problem. When you simplify a phrase, you are attempting to write it in the simplest way feasible. In conclusion, there should be no more adding, subtracting, multiplying, or dividing to do.

Given expression 1. -4[tex]x^{-2}[/tex] + 3[tex]y^{0}[/tex]  2. 2[tex]x^{0}[/tex][tex]y^{-2}[/tex]

Expression for x =2 and y=5

-4x-2 + 3y0

= -4(2)-2 + 3(5)0

= 16+3

=19

Now

2x0y-2

= 2(2)0x(5)-2

= 2 x (1/25)

= 2 x 0.04

= 0.08

Therefore the value of given expressions is -4[tex]x^{-2}[/tex] + 3[tex]y^{0}[/tex] = 19 and 2[tex]x^{0}[/tex][tex]y^{-2}[/tex] = 0.08

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suppose we want to choose 6 colors without replacement from 9 distinct colors if the order of choices is not taken into consideration how many ways can this be done and b if the order of the choices is taken into consideration how many ways can this be done

Answers

The first case is when the order of choices is not taken into consideration. If the order of choices is not taken into considerations then it is a case of permutations. So, the number of ways in which 6 colors can be chosen from 9 distinct colors are

The second case is when the order of choices is taken into consideration. If the order of choices is taken into considerations then it is a case of combinations. So, the number of ways in which 6 colors can be chosen from 9 distinct colors are

If Mike buys 2 pounds of basmati rice and 3.9 pounds of brown rice, how much will he spend? brown rice $3 per lb basmati rice $4 per lb white rice $4 per lb Bhutanese red rice $3 per lb sticky rice $3 per lb

Answers

Mike wants to buy 2 lb of basmati rice and 3.9 lb of brown rice.

The prices are given as

Basmati rice = $4 per lb

Brown rice = $3 per lb

How much will he spend?

Simply multiply the quantity of rice by its price

[tex]\begin{gathered} Basmati\: rice=2\times\$4=\$8 \\ Brown\: rice=3.9\times\$3=\$11.7 \end{gathered}[/tex]

So the total amount is

[tex]Total\: amount=\$8+\$11.7=\$19.7[/tex]

Therefore, Mike will spend $19.7

What percent of the runs are intermediate

Answers

Solution

For this case we have the following

[tex]\frac{56}{144}\cdot100=38.89[/tex]

If we round to the nearest whole number we got:

39%

In the figure below, ∠ABC ≅ ∠DEC and ∠GFE ≅ ∠DCE. Point C is the point of intersection between segment AG and segment BD , while point E is the point of intersection between segment AG and segment DF.

Prove ΔABC ∼ ΔGEF.

Answers

A figure is given with :-

∠ABC ≅ ∠DEC

∠GFE ≅ ∠DCE

Point C is the point of intersection between segment AG and segment BD.

Point E is the point of intersection between segment AG and segment DF.

We have to prove that ΔABC ∼ ΔGEF.

As ∠ABC ≅ ∠DEC

We can write,

∠DEC =  ∠FEG  (Vertically opposite angles)

Similarly,

As ∠GFE ≅ ∠DCE

We can write,

∠DCE = ∠ ACB (Vertically opposite angles)

Hence,

∠ ACB = ∠DCE = ∠GFE

∠ ACB = ∠GFE

Also,

∠FEG = ∠DEC = ∠ ABC

∠FEG = ∠ ABC

Hence, by using AA corollary, we can write,

ΔABC ∼ ΔGEF

Hence, proved.

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How much does a customer pay for three memory cards if the store increases the percent of discount in part (b) by 2%.Part (b) was 5%

Answers

discount was 2%

Cost of 3 mem cards

A + B + C = X

2% of X = X+ (2/100)X

Then

Cost of 2 mem cards= $47.50

5% of $47.50 = $2.375

Cost of 3 mem cards = 47.50 + 47.50/2= 47.50 + 23.75= $71.25

Now find 2% 0f 71.25

= (2/100)x71.25= $1.425

Then

customer pays

$71.25 - $1.425= 69.83

Answer is

customer pays $69.83 for three memory cards

there are 4 girls and 16 boys on the dodgeball team. What is the ratio of girls to the total number of kids on the team?

Answers

Given:

The number of girsl is, 4

The number of boys is, 16

Therefore the total number of kids is,

[tex]16+4=20[/tex]

Taking the ratio of number of girsl to the tital number of kids, we have,

[tex]\frac{4}{20}=\frac{1}{5}[/tex]

The required ratio is 1 : 5.

Pls help some one and can you explain how you do it

Answers

Answer:

about 37

Step-by-step explanation:

(8x-23) ----> divide

----  ----

8.     8. ------> 8x cancels out and is just x

x- 2.875+34 =.  37

The graph of Ax), shown below, resembles the graph of G(X) = x2, but it hasbeen changed somewhat. Which of the following could be the equation ofFx)?600 = x2-5OTFC) = ?AO A. F(X) = 3(x - 2)2 - 2B. F(x) = -3(x - 2)2 - 2C. F(x) = -3(x+ 2)2 - 2D. F(x) = 3(x + 2)2 - 2

Answers

The correct answer is option C

Explanation

First observation; the graph f(x) is n- shaped, so the coefficient of x^2 must be negative. This means option A and option D cannot be the answer

We have to channel our focus to option B or C

From the graph f(x), when x = -1, f(-1) = -5

Test option B and option C by substituting x= -1 into f(x) and check which options gives -5 as the answer

Testing option c

f(-1) = -3(-1 + 2)^2 -2

=-3(1) -2

= -3 - 2

=-5

f(-1) = -5

Since f(-1) = -5, which gives a correct value as we have on the graph,

Then the answer is option C

There are 5 blue marbles, 2 red marbles, and 3 green marbles in a bag. What is theprobability of selecting a red marble? Your answer can be a fraction, decimal orpercent.

Answers

Given

There are 5 blue marbles, 2 red marbles, and 3 green marbles in a bag

[tex]\begin{gathered} \text{Total Marbles =5+2+3} \\ \text{Total Marbles =10} \end{gathered}[/tex]

Probability of selecting a red marble

[tex]\text{Probability of selecting a red marble =}\frac{2}{10}=\frac{1}{5}[/tex]

The final answer

The probability of selecting a red marble

[tex]\frac{1}{5}[/tex]

Evaluating a Function In Exercises 5-12, evaluate the function at the given value(s) of the independent variable. Simplify the results. 5. f(x) = 3x - 2 (a) f(0) (b) f(5) (c) f(b) (d) f(x - 1)

Answers

Since the given function is

[tex]f(x)=3x-2[/tex]

We want to evaluate it at some values of x

a) To find f(0), substitute x by 0

[tex]\begin{gathered} x=0 \\ f(0)=3(0)-2 \\ f(0)=0-2 \\ f(0)=-2 \end{gathered}[/tex]

b) To find f(5), substitute x by 5

[tex]\begin{gathered} x=5 \\ f(5)=3(5)-2 \\ f(5)=15-2 \\ f(5)=13 \end{gathered}[/tex]

c) To find f(b), substitute x by b

[tex]\begin{gathered} x=b \\ f(b)=3(b)-2 \\ f(b)=3b-2 \end{gathered}[/tex]

d) To find f(x-1), substitute x by (x - 1)

[tex]\begin{gathered} x=(x-1) \\ f(x-1)=3(x-1)-2 \end{gathered}[/tex]

Simplify it by multiply 3 by the bracket

[tex]\begin{gathered} f(x-1)=3(x)-3(1)-2 \\ f(x-1)=3x-3-2 \end{gathered}[/tex]

Add the like term

[tex]\begin{gathered} f(x-1)=3x+(-3-2) \\ f(x-1)=3x+(-5) \\ f(x-1)=3x-5 \end{gathered}[/tex]

In the following diagram, AB bisects CD at E. Which of the following must be true?(1) CE is twice the length of CD(2) BE is half the length of AB(3) AE and BE are the same length (4) E is the midpoint of CD

Answers

EXPLANATION:

In the graph we can see that by bisecting point E in line C and D it does not remain in equal parts as if it can be seen in A and B, then the most accurate answer according to the graph would be the following:

(1) CE is twice the length of CD.

8 Kiara has a bag with 9 oranges. She shares the oranges between 3 friends and herself. Write an equation to model the situation. How many oranges does each person receive?

Answers

9 oranges shared between 4 persons

x = 9/4

Oranges for each person = 9/(number of persons)

In this case, number of persons = 4

Oranges for each person = 9/4

Oranges for each person = 2.25 oranges (also we can write 2 1/4)

This graph shows the distance that a robot walks. What is the rate of change of the robot's location?

Answers

Solution:

The rate of change, m, is;

[tex]\begin{gathered} m=\frac{d_2-d_1}{t_2-t_1} \\ \\ \text{ Where }d=distance,t=time \end{gathered}[/tex]

Thus;

[tex]\begin{gathered} (1,10),(3,30) \\ \\ m=\frac{30-10}{3-1} \\ \\ m=\frac{20}{2} \\ \\ m=10 \end{gathered}[/tex]

ANSWER: (D) 10 feet per minute

The perimeter of a square is 56 cm. What is the approximate length of its diagonal ? 10.6 cm 14.0 cm15.0 cm18.8 cm

Answers

We are given the perimeter of a square. Since a square has all of the sides of the same length the perimeter is, therefore:

[tex]P=4l[/tex]

Where "l" is the length of the side. Solving for "l" by dividing both sides by 4:

[tex]\frac{P}{4}=l[/tex]

Replacing the value of "P":

[tex]\frac{56}{4}=l[/tex]

Solving the operations:

[tex]l=14[/tex]

The length of the diagonal of a square is given by:

[tex]d=l\sqrt[]{2}[/tex]

Replacing the value of the length we get:

[tex]d=14\sqrt[]{2}[/tex]

Solving the operation:

[tex]d=19.8[/tex]

Therefore, the length of the diagonal is 19.8 cm.

use the figure at the right . if JK =3x+18 and NO=18, what is the value of x?

Answers

You have the following information:

JK = 3x + 18

NO = 18

You can notice that segment JM and MK are equal, furthermore, JK = JM + MK.

Then, JK = 2JM. From this expression you obtain:

JM = JK/2

By replacing the given expression for JK you have:

JM = (3x + 18)/2 = 3/2 x + 9

Moreover, you can notice that segments JM and NO are qual. Then, you have:

JM = NO you replace the expressions for JUM and NO

3/2 x + 9 = 18 subtract 9 both sides

3/2 x = 18 - 9

3/2 x = 9 multiply both sides by 2/3

x = 9(2/3)

x = 18/3

x = 6

Hence, the value of x is x = 6

Find the midpoint of the segment with the given endpoints.(-10,9) and (-3,4)

Answers

Let's apply the midpoint formula

((x1+x2)/2, (y1+y2)/2)

[tex](\frac{-3-10}{2},\frac{4+9}{2})[/tex][tex](\frac{-13}{2},\frac{13}{2})[/tex]

Find the y-intercept and x-intercept of the line 6x-2y=12

Answers

The expression we have is:

[tex]6x-2y=12[/tex]

This is the equation of the line.

To find the y-intercept, we need to find the value for y, when x is equal to 0. So we plug x=0 into our equation:

[tex]6(0)-2y=12[/tex]

And we solve for y:

[tex]-2y=12[/tex]

Divide both sides by -2:

[tex]\begin{gathered} \frac{-2y}{-2}=\frac{12}{-2} \\ y=-6 \end{gathered}[/tex]

The y-intercept is at y=-6

In the coordinate form, the y-intercept is (0,-6)

Now, to find the x-intercept, we need to find the value of x, when y=0.

So we plug y=0 into the equation:

[tex]6x-2(0)=12[/tex]

And we solve for x:

[tex]6x=12[/tex]

Divide both sides by 6:

[tex]\begin{gathered} \frac{6x}{6}=\frac{12}{6} \\ x=2 \end{gathered}[/tex]

The x-intercept is at x=2

In coordinate form, the x-intercept is: (2,0)

Answer:

2,-6

Step-by-step explanation:

the app is desmos btw- very helpful

oq voce precisa esta na foto se for possivel explique em portugues faça passo a passo

Answers

This is a riddle where the left-hand side represents the amount spent and the right-hand side represents the balance.

We have that:

[tex]\text{Total Spent+Current Balance=50}[/tex]

Adding the values in the balance column is not really necessary; in fact, it is coincidental in this case that the balances add up to 51.

How can you compare two or more fractions so as to arrange them in ascending or descending order?

Answers

There are two ways to arrange them in ascending or descending order.

The first way is to convert them into similar fractions (if they are not similar fractions yet), and arrange them in the order that you like.

[tex]\begin{gathered} \text{Example} \\ \frac{2}{3},\frac{1}{2},\frac{3}{4} \end{gathered}[/tex]

Convert them to similar fractions, by getting their LCD and we have

[tex]\begin{gathered} \text{LCD}(2,3,4)=12 \\ \frac{2}{3}=\frac{8}{12} \\ \frac{1}{2}=\frac{6}{12} \\ \frac{3}{4}=\frac{9}{12} \end{gathered}[/tex]

We can now arrange them based on their numerators

[tex]\begin{gathered} \text{Ascending} \\ \frac{6}{12},\frac{8}{12},\frac{9}{12}\Longrightarrow\frac{1}{2},\frac{2}{3},\frac{3}{4} \\ \\ \text{Descending} \\ \frac{9}{12},\frac{8}{12},\frac{6}{12}\Longrightarrow\frac{3}{4},\frac{2}{3},\frac{1}{2} \end{gathered}[/tex]

Another way to arrange them is to get their decimal equivalent, and arrange them accordingly

[tex]\begin{gathered} \text{Example} \\ \frac{2}{3}=0.67 \\ \frac{1}{2}=0.5 \\ \frac{3}{4}=0.75 \\ \\ \text{Ascending} \\ 0.5,0.67,0.75\Longrightarrow\frac{1}{2},\frac{2}{3},\frac{3}{4} \\ \\ \text{Descending} \\ 0.75,0.67,0.5\rightarrow\frac{3}{4},\frac{2}{3},\frac{1}{2} \end{gathered}[/tex]

What is the radius for a circle whose equation is x2 + y2 = 36?A. 18B. 36C. 1296D. 6

Answers

Answer:

D. 6

Explanation:

The general equation for a circle centered at the origin (0,0) is:

[tex]x^2+y^2=r^2[/tex]

Given the equation of the circle:

[tex]\begin{gathered} x^2+y^2=36 \\ \implies r^2=36 \\ r^2=6^2 \\ r=6 \end{gathered}[/tex]

Thus, the radius of the given circle is 6.

The perimeter of ΔPQR below is 55 units. What is the length of side QR?P to Q 2x+4 P to R x+3 Q to R has an x there.

Answers

Given:

In ΔPQR, Perimeter is 55 units.

The length of PQ = 2x+4

The length of PR = x+3

The length of Q+R = x

To find the length of QR, that is x:

Perimeter of the triangle formula is,

[tex]P=\text{ Sum of the length of thre}e\text{ sides}[/tex]

So, we have

[tex]\begin{gathered} 2x+4+x+3+x=55 \\ 4x+7=55_{} \\ 4x=48 \\ x=12 \end{gathered}[/tex]

Then, the length of QR is, 12 units.

Convert the expression from radical form to exponential expression in rational form, multiply and simplify then divide no need to evaluate just simplify

Answers

Solution

Given:

[tex]\sqrt[]{5^7}\text{ }\cdot\sqrt[]{5^6}\div\sqrt[5]{5^3}[/tex]

Recall from the law of indices that;

[tex]\begin{gathered} a^{\frac{b}{c}}=\sqrt[c]{a^b}=(\sqrt[c]{a})^b \\ a^{\frac{b}{2}}=\sqrt[]{a^b}^{} \end{gathered}[/tex][tex]undefined[/tex]

Identify the slope and y-intercept of the line y = -3(x - 1) + 5. Also, graph this line.

Answers

Answer:

The slope is -3, and y-intercept is 8

The graph is shown below:

Explanation:

Given the line:

y= -3(x - 1) + 5

Let us write this in the form:

y = mx + b

Where m is the slope and b is the y-intercept

Removing the parentheses, we have:

y = -3x + 3 + 5

= -3x + 8

Therefore,

The slope is -3, and y-intercept is 8

compute the monthly cost of the cellular phone for use of the following anytime minutes.

Answers

ANSWER:

(a) $29.99

(b) $37.49

(c) $30.24

STEP-BY-STEP EXPLANATION:

We have a function by part to calculate the monthly cost of a cell phone plan.

If the consumption is between 0 and 300 minutes, the value will always be $29.99. While if the consumption is greater than 300 minutes, the value is given by the following equation:

[tex]C\mleft(x\mright)=0.25x-45.01[/tex]

Knowing the above, we calculate in each case:

(a) 190 minutes.

It is in the interval between 0 and 300 minutes, therefore, the cost is $29.99.

C (190) = $29.99

(b)

[tex]\begin{gathered} C(330)=0.25\cdot330-45.01 \\ C(330)=82.5-45.01 \\ C(330)=37.49 \end{gathered}[/tex]

(c)

[tex]\begin{gathered} C(301)=0.25\cdot301-45.01 \\ C(301)=75.25-45.01 \\ C(301)=30.24 \end{gathered}[/tex]
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