Solve the quadratic equation by completing the square.x^2+6x-1=0First choose the appropriate form and fill in the blank with the correct numbets. Then, solve the equation. Round your answer to the nerest hundredth. If there is more than one solutions, separate them with commas.

Solve The Quadratic Equation By Completing The Square.x^2+6x-1=0First Choose The Appropriate Form And

Answers

Answer 1

Answer:

Explanation:

Given the quadratic equation

x^2+6x-1=0

Step 1: Add 1 to both sides of the equation

x^2+6x-1 + 1 = 0 + 1

x^2 + 6x = 1

Step 2: Complete the square by adding the square of the half of coeficient of x to both sides

Coefficient of x = 6

Half of 6 = 6/2 = 3

Square of 3 = 3^2 = 9

Add 9 to both sides

x^2 + 6x + 3^2 = 1


Related Questions

2. Identify the vertex from the quadratic function y=-5(x-6)^2+8 *2 points(-5, 6)(-6,8)(6,8)(8,6

Answers

Answer

2) Option C is correct.

The vertex of the quadratic function is at

x = 6, y = 8.

In coordinate form, the vertex = (6, 8)

4) Option A is correct.

-3 stretches the graph and reflects it about the x-axis.

Explanation

2) We are told to find the vertex of the quadratic function. The vertex of a quadratic function is the point at the base of the curve/graph of the function. It is the point where the value of the quadratic function changes sign.

The x-coordinate of this vertex is given as

x = (-b/2a)

The y-coordinate is then obtained from the value of the x-coordinate.

The quadratic function for the question is

y = -5 (x - 6)² + 8

We first need to put the quadratic function in the general form of

y = ax² + bx + c

So, we first simplify the expression

y = -5 (x - 6)² + 8

= -5 (x² - 12x + 36) + 8

= -5x² + 60x - 180 + 8

y = -5x² + 60x - 172

So,

a = -5

b = 60

c = -172

For the vertex

x = (-b/2a)

= [-60/(2×-5)]

= [-60/-10]

= 6

So, if x = 6.

y = -5x² + 60x - 172

y = -5(6²) + 60(6) - 172

y = -5(36) + 360 - 172

y = -180 + 360 - 172

y = 8

So, the vertex of the quadratic function is at

x = 6, y = 8.

In coordinate form, the vertex = (6, 8)

Option C is correct.

4) y = -3(x²)

The graph of is a parabola, but multiplying the function by -3 transforms the graph.

The 3, because it is greater than 1, stretches or enlarges the graph.

And the minus sign in front of the 3, ,that is, -3 reflects the graph about the x-axis.

So, altogether, -3 stretches the graph and reflects it about the x-axis.

Option A is correct.

Hope this Helps!!!

1/ (gg^2 e^5)^2 Write your answer with only positive exponents

Answers

ANSWER

[tex]\frac{1}{g^6e^{10}}[/tex]

EXPLANATION

In the denominator, we have the product of g and g². The product of two powers with the same base is the base raised to the sum of the exponents,

[tex]\frac{1}{(gg^2e^5)^2}=\frac{1}{(g^{2+1}e^5)^2}=\frac{1}{(g^3e^5)^2}[/tex]

Now, we also have the power of a product. The exponents can be distributed into the multiplication,

[tex]\frac{1}{(g^3e^5)^2}=\frac{1}{(g^3)^2(e^5)^2}[/tex]

And finally, for both g and e, we have the power of a power. The result is the base raised to the product of the exponents,

[tex]\frac{1}{(g^3)^2(e^5)^2}=\frac{1}{g^{3\cdot2}e^{5\cdot2}^{}}=\frac{1}{g^6e^{10}}[/tex]

Hence, the simplified expression is,

[tex]\frac{1}{g^6e^{10}}[/tex]

Hello, I need help writing a recursive formula for these I’m struggling bad

Answers

1) Notice that:

[tex]\begin{gathered} 3=\frac{30}{10}, \\ \frac{3}{10}=\frac{3}{10}, \\ \frac{3}{100}=\frac{\frac{3}{10}}{10}. \end{gathered}[/tex]

Therefore the recursive formula for the first sequence is:

[tex]\begin{gathered} a_1=30, \\ a_n=\frac{a_{n-1}}{10}\text{ for }n\geq2. \end{gathered}[/tex]

2) Notice that:

[tex]\begin{gathered} 11=14-3, \\ 8=11-3, \\ 5=11-3. \end{gathered}[/tex]

Therefore the recursive formula for the second sequence is:

[tex]\begin{gathered} a_1=14, \\ a_n=a_{n-1}-3\text{ for }n\geq2. \end{gathered}[/tex]

Answer:

Left sequence:

[tex]\begin{gathered} a_1=30, \\ a_n=\frac{a_{n-1}}{10}\text{ for }n\geq2. \end{gathered}[/tex]

Right sequence:

[tex]\begin{gathered} a_1=14, \\ a_n=a_{n-1}-3\text{ for }n\geq2. \end{gathered}[/tex]

according to a census, there were 66 people per square mile (population density) in a certain country in 1980. By 2000, the # of people per square mile had grown to 76. This information was used to develop a linear equation in slope intercept form, given below, where x is the time in years and y is the population density. Think of 1980 as year zero. what is the population density expected to be in 2018? y = 1/2x + 66

Answers

Determine the value of x for taking 1980 as 0.

[tex]\begin{gathered} x=2018-1980 \\ =38 \end{gathered}[/tex]

The equation is y = 1/2x + 66.

Substitute the value of x in the equation to determine the population density in 2018.

[tex]\begin{gathered} y=\frac{1}{2}\cdot38+66 \\ =19+66 \\ =85 \end{gathered}[/tex]

So population density in year 2018 is 85.

Answer: 85

evaluate the expression 0.03^3

Answers

The given expression is,

[tex]0.03^3[/tex]

So, expanding we have,

[tex]0.03^3=0.03\times0.03\times0.03=\text{0}.000027[/tex]

write an equation of the line that satisfies the given conditions. give the equation (a) in slope intercept form and (b) in standard form. m=-7/12 ,(-6,12)

Answers

Given the slope of the line:

[tex]m=-\frac{7}{12}[/tex]

And this point on the line:

[tex](-6,12)[/tex]

(a) By definition, the Slope-Intercept Form of the equation of a line is:

[tex]y=mx+b[/tex]

Where "m" is the slope and "b" is the y-intercept.

In this case, you can substitute the slope and the coordinates of the known point into that equation, and then solve for "b", in order to find the y-intercept:

[tex]12=(-\frac{7}{12})(-6)+b[/tex][tex]12=\frac{42}{12}+b[/tex][tex]\begin{gathered} 12=\frac{42}{12}+b \\ \\ 12=\frac{7}{2}+b \end{gathered}[/tex][tex]\begin{gathered} 12-\frac{7}{2}=b \\ \\ b=\frac{17}{2} \end{gathered}[/tex]

Therefore, the equation of this line in Slope-Intercept Form is:

[tex]y=-\frac{7}{12}x+\frac{17}{2}[/tex]

(b) The Standard Form of the equation of a line is:

[tex]Ax+By=C[/tex]

Where A, B, and C are integers, and A is positive.

In this case, you need to add this term to both sides of the equation found in Part (a), in order to rewrite it in Standard Form:

[tex]\frac{7}{12}x[/tex]

Then, you get:

[tex]\frac{7}{12}x+y=\frac{17}{2}[/tex]

Hence, the answers are:

(a) Slope-Intercept Form:

[tex]y=-\frac{7}{12}x+\frac{17}{2}[/tex]

(b) Standard Form:

[tex]\frac{7}{12}x+y=\frac{17}{2}[/tex]

3.What are the coordinates of the center and the length of the radius of the circle whose equation is(x + 1)^2 + (-5)^2 = 16?

Answers

The general equation of circle with centre (h.k) and radius r is,

[tex](x-h)^2+(y-k)^2=r^2[/tex]

Simplify the equation to obtain the centre and radius of circle.

[tex]\begin{gathered} (x+1)^2+(y-5)^2=16 \\ (x-(-1))^2+(y-5)^2=(4)^2 \end{gathered}[/tex]

So center of circle is (-1,5) and radius 4.

A freight train is carrying goods across the country. The distance it has traveled directly with the number of gallons of fuel it has used. See the graph below

Answers

[tex][/tex]

1) To find how many miles per gallon that freight train makes is to find a rate. We can find it in two ways, either by setting a proportion or by finding the slope.

2) Note that this direct variation depicted by the graph is proportional. Therefore, let's find the slope by picking two points:

[tex]\begin{gathered} (200,50),(400,100) \\ \\ m=\frac{y_2-y_1}{x_2-x_1}=\frac{100-50}{400-200}=\frac{50}{200}=\frac{1}{4} \end{gathered}[/tex]

3) Thus, the answers are:

Sketch vector v. Be sure to number your axes. Then find the magnitude of vector v. Show all work.

Answers

Step 1

Sketch the vector V.

[tex]v=-2i\text{ +5j}[/tex]

Step 2

Find the magnitude of the vector. The magnitude of a vector is given as;

[tex]\begin{gathered} |v|=\sqrt{(i)^2+(j)^2} \\ i=-2 \\ j=5 \\ \left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2} \end{gathered}[/tex][tex]\begin{gathered} |v|=\sqrt{(-2)^2+(5)^2} \\ |v|=\sqrt{4+25} \\ |v|=\sqrt{29} \end{gathered}[/tex]

Therefore, the magnitude is given as;

[tex]|v|=\sqrt{29}[/tex]

the first drop down answers are 18,10,7,14the second drop down box options are 16.5,30.5,44.5the third options are 2.5, 1.5, 1,3 the fourth options are 14n, 18n, 7n, 10nthe fifth options are each movie tickets cost the same amount, there is a service fee for buying tickets online, the cost increase as tge number of tickets increase, the leaste amount of tickets you cab buy is 1

Answers

Answer:

Recursive formula:

a_n = a_n-1 + 14,

a_1 = 16.5

Explicit formula: a_n = 14(n - 1) + 16.5

Each movie costs the same amount.

Explanation:

Looking at the numbers we see that each next term a_n is 14 added to the previous term, a_n-1 and the first term a_1 is 16.5; therefore, we can say

[tex]\begin{gathered} a_n=a_{n-1}+14, \\ a_1=16.5 \end{gathered}[/tex]

Patricia keeps apples in 3 bins and 2 crates in her store. Each bin can hold no more than 200 pounds. Each crate can hold no more than 50 pounds. Which number line represents all of the possible weights, in pounds, of apples Patricia can keep in her store?

Answers

Given:

The bins can hold no more than w(b) < 200 pounds.

The crate can hold no more than w(c) < 50 pounds.

The number of bins is n(b) = 3.

The number of crates is n(c) = 2.

The objective is to find the correct number line for the graph.

Explanation:

The maximum quantity of bins can be calculated as,

[tex]\begin{gathered} Q(b)The maximum quantity of crate can be calculated as,[tex]\begin{gathered} Q(c)To find the maximum store capacity:

The maximum store capacity can be calculated as,

[tex]undefined[/tex]

differentiatey = 3x√x⁴-5

Answers

Given:

[tex]y=3x\sqrt{x^4-5}[/tex]

Required:

We need to differentiate the given expression.

Explanation:

Consider the given expression.

[tex]y=3x\sqrt{x^4-5}[/tex][tex]y=3x(x^4-5)^{\frac{1}{2}}[/tex]

Differentiate the given expression with respect to x.

[tex]Use\text{ }(uv)^{\prime}=uv^{\prime}+vu^{\prime}.\text{ Here u=3x and v=}(x^4-5)^{\frac{1}{2}}.[/tex][tex]y^{\prime}=3x(\frac{1}{2})(x^4-5)^{\frac{1}{2}-1}(4x^3)+(x^4-5)^{\frac{1}{2}}(3)[/tex][tex]y^{\prime}=\frac{3x(4x^3)}{2\left(x^4-5\right)^{\frac{1}{2}}}+3(x^4-5)^{\frac{1}{2}}[/tex][tex]y^{\prime}=\frac{6x^4}{\left(x^4-5\right)^{\frac{1}{2}}}+3(x^4-5)^{\frac{1}{2}}[/tex][tex]y^{\prime}=\frac{6x^4}{\left(x^4-5\right)^{\frac{1}{2}}}+\frac{3(x^4-5)^{\frac{1}{2}}(x^4-5)^{\frac{1}{2}}}{(x^4-5)^{\frac{1}{2}}}[/tex][tex]y^{\prime}=\frac{6x^4}{\left(x^4-5\right)^{\frac{1}{2}}}+\frac{3(x^4-5)}{(x^4-5)^{\frac{1}{2}}}[/tex][tex]y^{\prime}=\frac{6x^4}{\left(x^4-5\right)^{\frac{1}{2}}}+\frac{3x^4-15}{(x^4-5)^{\frac{1}{2}}}[/tex][tex]y^{\prime}=\frac{6x^4+3x^4-15}{\left(x^4-5\right)^{\frac{1}{2}}}[/tex][tex]y^{\prime}=\frac{9x^4-15}{\left(x^4-5\right)^{\frac{1}{2}}}[/tex][tex]y^{\prime}=\frac{3(3x^4-5)}{\left(x^4-5\right)^{\frac{1}{2}}}[/tex][tex]y^{\prime}=\frac{3(3x^4-5)}{\sqrt{x^4-5}}[/tex][tex]y^{\prime}=\frac{3(3x^4-5)}{\sqrt{x^4-5}}\times\frac{\sqrt{x^4-5}}{\sqrt{x^4-5}}[/tex][tex]y^{\prime}=\frac{3(3x^4-5)\sqrt{x^4-5}}{x^4-5}[/tex]

Final answer:

[tex]y^{\prime}=\frac{3(3x^4-5)\sqrt{x^4-5}}{x^4-5}[/tex]

3. If the mZLKI - 174º and KR bisects LLKI, then find the mLLKR.
R
E
K
87°
1740
0740
90°

Answers

SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1:

[tex]undefined[/tex]

Answer:

87°

Step-by-step explanation:

Angle bisector:

      Angle bisector is a ray that divides an  angle into two congruent angles.

 

∠LKR = ∠LKJ ÷ 2

        = 174° ÷ 2

        = 87°

What is the missing reason for The third step in the proof below

Answers

Solution

The image below contain the solution

find the shaded area to the nearest tenth, use 3.14 for pi. help pls due tmrw

Answers

The area of the shaded region inside the circle is 49.04cm².

What is a circle?

All points in a plane that are at a specific distance from a specific point, the center, form a circle.

In other words, it is the curve that a moving point in a plane draws to keep its distance from a specific point constant.

So, the shaded area is:

We can easily tell that the diameter of the circle here is 12cm.

So, the radius will be 6cm.

Now, calculate the area of a circle as follows:

A = πr²

A = 3.14(6)²

A = 3.14(36)

A = 113.04cm²

Now, the area of the smaller square:

A = s²

A = 2²

A = 64²

Area of the shaded region:

113.04 - 64

49.04 cm²

Therefore, the area of the shaded region inside the circle is 49.04cm².

Know more about circle here:

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As we learn more about lines, we will occasionally have to consider perfectly vertical lines as a special case and treat them differently. Think about applying what you have learned in the last couple of activities to the case of vertical lines. What is the same? What is different?

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If the line of the graph is vertical then the slope of the graph is zero. The coordinate of the y-value will never change on vertical lines.

What are vertical lines?

The vertical line is a line that is parallel to the y-axis. A vertical line can be defined as a line on the coordinate plane where all the points on the line have the same x-coordinate. A form of test employed in relation is the vertical line test. Any kind of vertical line equation lacks a y-intercept. The vertical line test is used to determine whether or not the given relation is a function. The vertical line is another name for the vertical bar. A mathematical sign is an upright slash. Depending on the context, it may be used to represent a certain kind of logic or an operation. The vertical line is the line that runs along the y-axis.

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Some roads in the Rocky Mountains have a rise of 7 feet for every 100 horizontal feet.What is the slope of such roads?

Answers

Let's begin by listing out the information given to us:

The road rises by 7 feet every 100 horizontal feet

The equation becomes:

Slope (m) = Δy/Δx = 7/100 = 0.07

Slope (m) = 0.07

Use the value of x to find the measure of Angle 1.x=25 5x-5 2x+10

Answers

Given:

• x = 25

,

• ∠1 = 5x - 5

,

• ∠2 = 2x + 10

Let's find the measure of angle 1.

To find the measure of angle 1, substitute 25 for x in (5x - 5) and evaluate.

We have:

m∠1 = 5x - 5

m∠1 = 5(25) - 5

m∠1 = 125 - 5

m∠1 = 120

Therefore, the measure of angle 1 is 120 degrees.

ANSWER:

∠1 = 120°

5. Determine the value of each variable for parallelogram INDY that has diagonals that intersect at P.IP = 3x, DP = 6x-2, NP = 3y, and YP = 7x - 2.

Answers

Given the INDY

The diagonals has intersected at the point P

IP = 3x, DP = 6x - 2

NP = 3y , YP = 7x - 2

So, IP = DP

[tex]6x-2=3x[/tex]

Solve for x :

[tex]\begin{gathered} 6x-2=3x \\ 6x-3x=2 \\ 3x=2 \\ \\ x=\frac{2}{3} \end{gathered}[/tex]

And : NP = YP

[tex]3y=7x-2[/tex]

substitute with the value of x :

[tex]\begin{gathered} 3y=7\cdot\frac{2}{3}-2=\frac{23}{3}-2=\frac{17}{3} \\ \\ y=\frac{17}{9} \end{gathered}[/tex]

So, the answer is :

[tex]\begin{gathered} x=\frac{2}{3} \\ \\ y=\frac{17}{9} \end{gathered}[/tex]

Suppose the booster club is raising money to help offset the cost of a trip.You make $10 per door wreath sold and $2 per candy bar sold. The clubwants to raise at least $400.00. Write an inequality to represent thissituation.

Answers

Let the number of door wreath sold is x.

Let the number of candy bar sold is y.

The inequality can be represented as,

[tex]10x+2y\ge400[/tex]

Thus, the above inequation gives the required inequality.

what is 8q= 96 what is it?

Answers

To find the value of q, divide both sides of the equation by 8:

[tex]\begin{gathered} 8q=96 \\ \Rightarrow\frac{8q}{8}=\frac{96}{8} \end{gathered}[/tex]

Simplify both members of the equation:

[tex]\begin{gathered} \Rightarrow q=\frac{96}{8} \\ \Rightarrow q=12 \end{gathered}[/tex]

Therefore:

[tex]q=12[/tex]

which portion must be true?

Answers

The two figures are similar

Using the similarity theorem

The only true proportion is

[tex]\frac{8}{2}\text{ = }\frac{x}{y}[/tex]

A committee must be made up of two students from grades 9, 10, or 11, and another two students from grade 12. How many different committees can be made? Explain and show all of your work.

Answers

to make the committee

. Compare: what is greater 5/3 or 9/16

Answers

hello

between 5/3 and 9/16, 5/3 is greater than 9/16

[tex]\frac{5}{3}>\frac{9}{16}[/tex]

Translate this sentence into an equation.The product of 5 and Julie's height is 80.Use the variablej to represent Julie's height.

Answers

ANSWER:

5 x j = 80

STEP-BY-STEP EXPLANATION:

The sentence as an equation would be the multiplication of j and 5 equal to 80, just like this:

[tex]5\times j=80[/tex]

Caleb is renting a kayak for 14.50 per half hour. how much would it cost Caleb to rent the kayak for 5 minutes

Answers

Answer:

It would cost Caleb approximately $2.4 to rent kayak for 5 minutes

Explanation:

Given that Caleb is renting a kayak for $14.40 per half hour.

This means he rents it for 30 minutes, as 30 minutes is half an hour.

In an equation form, we can write as:

$14.40 = 30 minutes

So that:

1 minute = $(14.50/30)

= $0.48

This mean he rents at $0.48 per minute

For 5 minutes, it would cost him:

$0.48 * 5 = $2.4 approximately.

Find the X-Intercept and the y-intercept of 4x- 5y = 15X-Intercept:???Y-intercept: ???help

Answers

The y-intercept is (0,-3) while the x-intercept is (18.75,0)

Here, we want to find the x and y-intercepts of the given line

Firstly, we have to rewrite the equation of the line in the standard form

We have this as;

[tex]\text{y = mx + b}[/tex]

m is the slope and b is the y-intercept

Rewriting the given equation, we have this as;

[tex]\begin{gathered} 5y\text{ = 4x-15} \\ y\text{ =}\frac{4}{5}x-\frac{15}{5} \\ \\ y\text{ = }\frac{4}{5}x\text{ - 3} \end{gathered}[/tex]

We have the y-intercept as -3

In the coordinate form, this is (0,-3)

To get the x-intercept, we set the y value to zero

We have this as;

[tex]\begin{gathered} 0\text{ = }\frac{4}{5}x-15 \\ 15\text{ = }\frac{4x}{5} \\ \\ 4x\text{ = (15}\times5) \\ 4x\text{ = 75} \\ x\text{ = }\frac{75}{4} \\ x\text{ = 18.75} \end{gathered}[/tex]

The x-intercept is 18.75 which in the coordinate form is (18.75,0)

solve equation 10 - 25x = 5 what is the value of x

Answers

ANSWER

x = 1/5

EXPLANATION

We are given the equation:

10 - 25x = 5

To find the value of x, first we subtract 10 from both sides of the equation:

10 - 25x - 10 = 5 - 10

10 - 10 - 25x = 5 - 10

-25x = -5

Now, divide both sides by 5:

=> x = -5 / -25

x = 1/5

That is the value of x.

If Rosa is at most 27 years old. What symbol does at most refer to less than greater than less than or equal to greater than or equal to

Answers

The correct answer is less than or equal to because at most 27 years means that Rosa's highest age is 27.

How to solve this problem step by step in depth. I have no idea how to solve this

Answers

Answer

[tex]f^{-1}(x)=\frac{-1}{5}x-\frac{4}{5}[/tex]

Explanation

The given function is

[tex]f(x)=-5x-4[/tex]

Let y = f(x), this implies

[tex]y=-5x-4[/tex]

Now, make x the subject of the formula

[tex]\begin{gathered} y=-5x-4 \\ 5x=-y-4 \\ \text{To get x, we divide both sides by 5} \\ \frac{5x}{5}=\frac{-y-4}{5} \\ \\ x=\frac{-y-4}{5} \end{gathered}[/tex]

Since f(x) = y, then x = f⁻¹(y)

[tex]\begin{gathered} f^{-}^{1}\mleft(y\mright)=\frac{-y-4}{5} \\ \therefore f^{-1}(x)=\frac{-x-4}{5} \end{gathered}[/tex]

The above inverse function can be rewritten as follows

[tex]\begin{gathered} f^{-1}(x)=\frac{-x}{5}-\frac{4}{5} \\ f^{-1}(x)=\frac{-1}{5}x-\frac{4}{5} \end{gathered}[/tex]

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