The inequality 0.2 (30 + x) - 0.3 (30 - x) >2 is solved to get x > 10
How to solve the inequalityThe given inequality is 0.2 (30 + x) - 0.3 (30 - x) >2
0.2 (30 + x) - 0.3 (30 - x) >2
expanding the parenthesis
6 + 0.2x - 9 + 0.3x > 2
collecting like terms
6 - 9 + 0.2x + 0.3x > 2
-3 + 0.5x > 2
0.5x > 2 + 3
0.5x > 5
dividing by the coefficient of x which is 0.5
x > 10
Learn more about inequality here:
https://brainly.com/question/24372553
#SPJ1
The length of a rectangle is four times the width. If the area of the rectangle is 196square inches, then find the length and width
Let the length of the rectangle be "l" and width be "w".
The length is 4 times the width, we can write:
[tex]l=4w[/tex]The area is given as 196. We know area of a rectangle is A = lw, where l is length and w is width. Thus, we can write:
[tex]196=lw[/tex]Substituting the first equation into the second, we can solve for w. The process is shown below:
[tex]\begin{gathered} 196=lw \\ 196=(4w)w \\ 196=4w^2 \\ w^2=\frac{196}{4} \\ w^2=49 \\ w=\sqrt[]{49} \\ w=7 \end{gathered}[/tex]Now, using the 1st equation, we can solve for the length, "l". Shown below:
[tex]\begin{gathered} l=4w \\ l=4\times7 \\ l=28 \end{gathered}[/tex]Answer:
Length = 28 inches
Width = 7 inches
A farm let's you pick 3 pints of raspberries for $12.00.What is the cost per pint?How many pints do you get per dollar?
Step 1
Given;
[tex]3\text{ pints of raspberries = \$12}[/tex]Required; To find the cost per pint and how many pints you get per dollar.
Step 2
Find the cost per pint using the ratio below
[tex]\begin{gathered} \frac{3\text{ pints of raspberries}}{1\text{ pint of raspberries}}=\frac{\text{\$}12}{\text{\$}x} \\ \end{gathered}[/tex]where;
[tex]\text{\$x=cost per pint}[/tex][tex]\begin{gathered} 3x=12 \\ \frac{3x}{3}=\frac{12}{3} \\ x=\text{\$}4 \end{gathered}[/tex]Step 2
Find how many pints you get per dollar.
[tex]\begin{gathered} \frac{1\text{ pint of raspberries}}{x\text{ pints of raspberries}}=\frac{\text{\$}4}{\text{\$}1} \\ 1=4x \\ \frac{4x}{4}=\frac{1}{4} \\ x=0.25\text{ pints of raspberries } \end{gathered}[/tex]Hence, you will get 0.25 pints of raspberries per dollar
A motorboat travels 200 miles in 5 hours going upstream. It travels 260 miles going downstream in the same amount of time. What is the rate of the boat in still water and what is the rate of the current?
B= Speed of the boat in the water =46 miles per hour
A= Speed of the Current =6 miles per hour
Speed upstream: B-A
Speed Downstream: B+A
Distance= Speed x time
Upstream :
(B-A) 5 = 200
Downstream:
(B+a) 5 = 260
Simplify both equations:
5B-5A =200
5B+5A =260
Add both equations:
10B = 460
Solve for B
B= 460/10
B= 46 miles/hour
Replace B on any distance equation:
5B-5A =200
5(46)-5A=200
Solve for A
230-5A=200
230-200=5A
30=5A
30/5 =A
A= 6 miles/hour
Peter works at a sports store. On a particular day, he surveyed a random sample of 50 customers and observed that 30 customers liked to play tennis and 15 customers liked to play basketball.Which of the statements are likely true? Select all that are true.A. 30% of the equipment in the store should be related to basketball.B. 60% of the equipment in the store should be related to tennis.C. 30% of the sales at the sports store that day were related to basketball.D. 70% of the sales at the sports store that day were related to basketball.E. 40% of the sales at the sports store that day were related to tennis equipment. F. 60% of the sales at the sports store that day were related to tennis equipment.
Given data:
Total sample = 50
customers that liked tennis = 30
customers that liked basketball = 15
To select the answers that are true, we can check all the options
Step 1: Find the percentage of those who like tennis and basketball
[tex]\begin{gathered} \text{ The percentage of customers that like tennis is given by} \\ \frac{30}{50}\text{ x 100\% = 60\%} \end{gathered}[/tex][tex]\begin{gathered} \text{The percentage of customers that like basketball is given by} \\ \frac{15}{50}\text{ x 100\% = 30\%} \end{gathered}[/tex]Option A
Since 30% like basketball, then it will be reasonable to have 30% of the equipment related to basketball.
OptionB
Since 60% like tennis, then it will be reasonable to have 60% of the equipment related to tennis
Option C
Since 30% like basketball, then 30% of the sales is likely to be related to basketball
Option D
Since 30% like basketball, then IT IS NOT LIKELY to have 70% of the sales related to basketball.
Option E
Since 60% like tennis, then IT IS NOT LIKELY to have 40% of the sales related to tennis
Option F
Since 60% like tennis, then IT IS LIKELY to have 60% of the sales related to tennis
Hence, we select options
A, B, C, and F as True
choose the fraction pair that is equivalent. 3/4 and 4/3, 4/5 and 8/20, 8/24 and 1/3, or 3/12 and 1/3
To find out if two fractions are equivalent or not, we multiply by a cross. That is, multiply the numerator of the first fraction with the denominator of the second fraction and multiply the denominator of the first fraction with the numerator of the second fraction and check that it gives us the same result. For example:
[tex]\begin{gathered} \frac{1}{3}\text{ and }\frac{2}{6} \\ 1\cdot6=3\cdot2 \\ 6=6 \end{gathered}[/tex]So, in this case, you have
[tex]\begin{gathered} \frac{3}{4}\text{ and }\frac{4}{3} \\ 3\cdot3\ne4\cdot4 \\ 9\ne16 \\ \text{ They are not equivalent fractions} \end{gathered}[/tex][tex]\begin{gathered} \frac{4}{5}\text{ and }\frac{8}{20} \\ 4\cdot20\ne5\cdot8 \\ 80\ne40 \\ \text{ They are not equivalent fractions} \end{gathered}[/tex][tex]\begin{gathered} \frac{8}{24}\text{ and }\frac{1}{3} \\ 8\cdot3=24\cdot1 \\ 24=24 \\ \text{They are equivalent fractions} \end{gathered}[/tex][tex]\begin{gathered} \frac{3}{12}\text{ and }\frac{1}{3} \\ 3\cdot3\ne12\cdot1 \\ 9\ne12 \\ \text{ They are not equivalent fractions} \end{gathered}[/tex]Therefore, the fraction pair that is equivalent is
[tex]\frac{8}{24}\text{ and }\frac{1}{3}[/tex]You flip a coin 100 times and record each outcome.You find that you land on heads 47 times and land ontails 53 times. What is the theoretical probability oflanding on heads?
If we were asked the "experimental probability", the answer would have been
[tex]\frac{47}{100}\text{ that is number of outcomes/total outcomes. }[/tex]But we were asked the "theoretical probability". And in theory, we can get either a head or a tail if a coin is flipped. So that makes it
[tex]\frac{1\text{ outcome }}{total\text{ outcomes of 2 }}\text{ = }\frac{1}{2}[/tex]Therefore, the answer is
[tex]\frac{1}{2}[/tex]Point M is the midpoint of AB. The coordinates of point A are (-7,2) and the coordinates of M are (-3, 1).What are the coordinates of point B?The coordinates of point B are
We have three points that lie on a line namely, A M B, in a cartesian coordinate system.
The coordinates of each point are as such:
[tex]A\text{ ( -7 , 2 )}[/tex]The mid-point of a line segment ( AB ) is given by coordinate ( M ) as follows:
[tex]M\text{ ( -3 , 1 )}[/tex]We will define the coordinates of point ( B ) in terms of cartesian coordinates as follows:
[tex]B\text{ ( x , y ) }[/tex]Here the line ( A B ) with points [ A, M , B ] are colinear. This means they all lie on the same line passing through all three points.
A straight line always have a constant slope/gradient ( m ) . This slope is determined between two points that lie on the line.
The formulation of calculating the slope ( m ) of the line in a cartesian coordinate system is as follows:
[tex]m\text{ = }\frac{y_2-y_1}{x_2-x_1}[/tex]The respective cartesian coordinates of each of the two points are represented by sub-scripts of ( x and y ).
Here we will take two points ( A and M ) to determine the slope ( m ) of the line passing throgh all three points as follows:
[tex]\begin{gathered} m\text{ = }\frac{1\text{ - 2}}{-3\text{ -(-7)}}\text{ = }\frac{1-2}{-3+7} \\ m\text{ = }\frac{-1}{4} \end{gathered}[/tex]This slope ( m ) holds true for the entire line and must satisfy all consecutive points that lie on the line.
We will now consider points ( A and B ) and determine the slope ( m ):
[tex]\begin{gathered} m\text{ = }\frac{y\text{ - 2}}{x\text{ - (-7)}} \\ \\ -\frac{1}{4}\text{ = }\frac{y\text{ - 2}}{x+7} \\ \\ -\text{ ( x + 7 ) = 4}\cdot(y-2) \\ -x\text{ - 7 = 4y - 8} \\ \textcolor{#FF7968}{x}\text{\textcolor{#FF7968}{ = 1 - 4y }}\textcolor{#FF7968}{\ldots}\text{\textcolor{#FF7968}{ Eq 1}} \end{gathered}[/tex]What we did above was calculated the slope ( m ) between two points ( A and B ) which resulted in an expression in terms of coordinates of point B ( x and y ). We equated that expression with the value of slope ( m ) that holds true for all points that lie on the line.
Then we used the slope equation and expressed the x-coordinate of point B in terms of y-coordinate of point B. This relaitonship is termed as Equation 1 ( Eq 1 ).
Next, we were also given that point M is the midpoint of line segment ( AB ). Using the definition of a mid-point ( M ) i.e the magnitude of line segments are:
[tex]|AM|\text{ = |MB|}[/tex]The magnitudes of line segment AM and MB must be equal for point ( M ) to be a mid-point of line segment ( AB ).
We will express the formulation of determining a magnitude of line segment using two points:
[tex]\text{length of line segment = }\sqrt{(\times_2-x_1)^2+(y_2-y_1)2}[/tex]So for equating the lengths (magnitudes) of line segments ( AM ) and ( MB ) we have:
[tex]\begin{gathered} A\text{ ( -7 , 2 ) , M ( -3 , 1 ) , B ( x , y )} \\ \sqrt{(-3-(-7))^2+(1-2)^2}\text{ = }\sqrt{(-3-x)^2+(1-y)^2} \end{gathered}[/tex]Square both sides of the equation:
[tex](4)^2+(-1)^2=(-1)^2\cdot(x+3)^2+(1-y)^2[/tex]Evaluate left hand side of equation and apply PEMDAS at right hnd side of the equation:
[tex]\begin{gathered} 16+1=(x^2+6x+9)+(y^2\text{ - 2y + 1 )} \\ 17\text{ = }x^2+y^2\text{ + 6x - 2y + 10} \\ \textcolor{#FF7968}{7}\text{\textcolor{#FF7968}{ = }}\textcolor{#FF7968}{x^2+y^2}\text{\textcolor{#FF7968}{ + 6x - 2y }}\textcolor{#FF7968}{\ldots Eq2} \end{gathered}[/tex]We have two equations with two unknows ( x and y ) as follows:
[tex]\begin{gathered} x\text{ = 1 - 4y }\ldots Eq1 \\ 7=x^2+y^2\text{ + 6x - 2y }\ldots Eq2 \end{gathered}[/tex]We will solve the two equation by simultaneous substitution method. Substitute Eq1 into Eq2 as follows:
[tex]\begin{gathered} 7=(1-4y)^2+y^2\text{ + 6}\cdot(1\text{ - 4y ) - 2y} \\ 7=(1-8y+16y^2)+y^2\text{ + ( 6 - 24y ) - 2y} \\ 7=17y^2\text{ -34y + 7 } \\ 0=17y^2\text{ -34y} \\ 0\text{ = y}\cdot(17y\text{ - 34 )} \\ \textcolor{#FF7968}{y}\text{\textcolor{#FF7968}{ = 0 OR y = }}\textcolor{#FF7968}{\frac{34}{17}}\text{\textcolor{#FF7968}{ = 2}} \end{gathered}[/tex]We will now plug the two values of coordinate ( y ) into ( Eq 1 ) and solve for ( x ):
[tex]\begin{gathered} y\text{ = 0, x = 1 - 4}\cdot(0)\text{ = 1} \\ y\text{ = 2, x = 1 -4}\cdot(2)=-7\text{ } \end{gathered}[/tex]We have two solutions for the coordinates of point ( B ) as follows:
[tex]B\text{ : ( 1 , 0 ) OR ( -7 , 2 )}[/tex]However, point B must have only one pair of coordinate. So we have to investigate both solutions given above and reject a redundant solution.
We see that solution B: ( -7 , 2 ) is redundant solution, hence, rejected. This is because it represents the coordinates of point A: ( -7 , 2 ) - given in question. So two different points can not attain the same set of coordinates! Hence,
The solution to the set of coordinates of point B is:
[tex]\textcolor{#FF7968}{B\colon}\text{\textcolor{#FF7968}{ ( 1 , 0 ) }}[/tex]
f(1) = 4
f(2)= 25
f(n) = f(n − 2). f(n − 1)
f(3)=
The value of f(3) is 100 when f(1)=4 and f(2)=25 for function f(n) = f(n − 2). f(n − 1)
What is a function?A relation is a function if it has only One y-value for each x-value.
Given,
f(1) = 4
f(2)= 25
f(n) = f(n − 2). f(n − 1)
We need to find the value of f(3)
plug in 3 as n
f(3)=f(3-2).f(3-1)
f(3)=f(1)f(2)
Now put values of f(1) and f(2)
f(3)=4.25
f(3)=100
Hence the value of f(3) is 100 when f(1)=4 and f(2)=25 for function f(n) = f(n − 2). f(n − 1)
To learn more on Functions click:
https://brainly.com/question/21145944
#SPJ1
Solving systems by substituting Y= -3x+52x+y=6
Answer:
x=-1, y=9.
Explanation:
Given the system of equations
[tex]\begin{gathered} y=-3x+5 \\ 2x+y=6 \end{gathered}[/tex]Substitute y=-3x+5 into 2x+y=6.
[tex]\begin{gathered} 2x+y=6 \\ 2x+(-3x+5)=6 \\ 2x-3x+5=6 \\ -x=6-5 \\ -x=1 \\ x=-1 \end{gathered}[/tex]Next, we solve for y.
[tex]\begin{gathered} y=-3x+5 \\ =-3(-1)+5 \\ =4+5 \\ y=9 \end{gathered}[/tex]The solution to the system of equations are:
x=-1 and y=9.
I need help with math I have dyscalculia and I don’t understand
The summation symbol means that we need to add the terms (n-1) for n = 1, 2, 3, and 4.
In other words, we have the following terms:
[tex]\begin{gathered} 1-1=0 \\ \\ 2-1=1 \\ \\ 3-1=2 \\ \\ 4-1=3 \end{gathered}[/tex]And we need to add them:
[tex]0+1+2+3=6[/tex]Therefore, the result is 6.
Evaluate the expression y = -4y^2 + 6y + 9
The given expression is
[tex]\begin{gathered} y^2\text{ + 6y + 9} \\ We\text{ would substitute y = - 4 into the given expression. It becomes} \\ (-4)^2+6(-4)+9 \\ 16-24+9 \\ =\text{ 1} \end{gathered}[/tex]The answer is 1
Use arguments based on the Pythagorean theorem, its converse, and similar triangles to show that a triangle with sides 5n, 12n, and 13n is a right triangle. HINT: Start with n= 1, which results in side lengths of 5, 12, and 13. Answer in complete sentences and include all relevant calculations and algebraic manipulations
Sides:
5n
12n
13n
If n is 1 the triangle have sides: 5, 12, 13
The converse of the pythagorean theorem is: If the square of the length of the longest side of a triangle is equal to the sum of the squares of the other two sides, then the triangle is a right triangle:
[tex]\begin{gathered} 13^2=12^2+5^2 \\ 169=144+25 \\ 169=169 \end{gathered}[/tex]Then, a triangle with sides 5, 12, 13 is a right triangle.
If n is 2 the triangle have sides: 10,24, 26
converse of the pythagorean theorem:
[tex]\begin{gathered} 26^2=24^2+10^2 \\ 676=576+100 \\ 676=676 \end{gathered}[/tex]Triangle with n=1 and n=2 are similars as the ratio between corresponding side is equal:
[tex]\begin{gathered} \frac{5}{10}=\frac{1}{2} \\ \\ \frac{12}{24}=\frac{1}{2} \\ \\ \frac{13}{26}=\frac{1}{2} \end{gathered}[/tex]Then, with any value of n the triangles are similar triangles.
Similar triangles have different sizes but the correpondign angles are the same (are congruent).
As triangles with sides 5n, 12n, 13n are similar triangles (All of then have the same measure on his correspondig angles) and makes true the Pythagorean theorem, they are right triangles.
Find the midpoint of the segment with the given endpoints. (-9,7) and (-4,2)
We have the following:
The midpoint is:
[tex]m=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex]replacing:
[tex]m=(\frac{-9-4}{2},\frac{7+2}{2})=(\frac{-13}{2},\frac{9}{2})[/tex]The midpoint of the segment is:
[tex](-6.5,4.5)[/tex]Find the difference: 75.12 - 2.1 O A. 7.302O B. 73.02O C. 75.11 O D. 54.12
Then, the answer is number B.
Consider the quadrilateral FACT below.FTAсСDetermine which of the following pairs is an opposite angle.
For any shaè, two angles are opposite if they are across each other, these angles share no sides. To determine which angles are opposite to each other you have to draw the diagonals of the quadrilateral since they go from one opposite angle to the other:
The opposite angles are:
F and C
A and T
The first option is the correct one.
Theirs 165 freshman145 Sophomores 114 Juniors102 SeniorsIf a studemt is chosen at random from this group whats the probability a senior will be chosen
To find the probability of choosing a senior student, we have to divide the total number of seniors by the total number of students.
According to the problem, there are 102 seniors. Let's sum to find the total number of students.
[tex]165+145+114+102=526[/tex]Then, we divide these numbers.
[tex]P_{\text{senior}}=\frac{102}{526}=\frac{51}{263}\approx0.19[/tex]The probability of choosing a senior is 51/263 or 19%, approximately.find the supplement of the angle 19 degrees
Supplementary angles are the ones that when you add them, the result is 180°.
Let's call the angle we are looking for "x", since it is supplementary to the angle of 19°, they add up to 180°:
[tex]x+19=180[/tex]From this equation, we can solve to find the supplementary angle x.
We solve for x by subtracting 19 to both sides of the equation:
[tex]\begin{gathered} x+19-19=180-19 \\ x=161 \end{gathered}[/tex]Answer: 161°
Can you please help me out with a question
Consider the following mapping:(a)948546Part A:Write a set of ordered pairs to represent the mapping.
For order pair
In the first block the value 9 maps to 4 So, (9,4)
The value 8 maps to 4 & 6 so, the pair is (8,4) & (8,6)
The value 4 maps to 5So, (4,6)
The order pairs are (9,4), (8,4) (8,6) & (4,5)
b) Domain are the set of input values
In this mapping the first block map to the second thus, the value at the first block is the initial valua and act as domain of the mapping
So, the Domain = {9,8,4}
c) Range is the set of all the possible outputs
In this mapping, the second block show the final values of the function, thus the second block act as a range of the mapping
So, the Range= {4,5,6}
d) The mapping doesnot represent the function as the mapping is not one-one
A function must staisfy one-one rulei.r for every value of domain thier exists only one value of range
Where in this mapping we have, the range 4 whose domain are 9 & 8 does they donot satisfy the one-one creteria hence they are not one-one and niether they are function
A rectangular room is 5 meters longer than it is wide, and its perimeter is 30 meters. Find the dimension of the room
The dimensions of the rectangular room is 10 meters and 5 meters respectively.
What is the dimensions of the room?The perimeter of a rectangle = 2(length + width)
Let
Width of the room = w metersLength of the room = (w + 5) metersPerimeter of the room = 30 metersThe perimeter of the rectangular room = 2(length + width)
30 = 2{(w + 5) + w}
30 = 2(w + 5 + w)
open parenthesis
30 = 2w + 10 + 2w
collect like terms
30 - 10 = 4w
20 = 4w
divide both sides by w
w = 20/4
w = 5
Hence,
Width of the room = w meters
= 5 meters
Length of the room = (w + 5) meters
= (5 + 5)
= 10 meters
Therefore, the length and width of the room are 10 meters and 5 meters respectively.
Read more on perimeter of rectangle:
https://brainly.com/question/24571594
#SPJ1
Find the volume of the cylinder. Round your answer to the nearest tenth. Use 3.14 for a.4 ft17 ftThe volume of the cylinder is about|ft3
we know that
The volume of the cylinder is equal to
[tex]V=B\cdot h[/tex]where
B is the area of the base and h is the height of cylinder
we have that
[tex]B=\pi\cdot r^2[/tex]we have
pi=3.14
r=4 ft
substitute
[tex]\begin{gathered} B=3.14\cdot4^2 \\ B=50.24\text{ ft\textasciicircum{}2} \end{gathered}[/tex]Find the volume
[tex]V=B\cdot h[/tex]we have
B=50.24 ft^2
h=17 ft
substitute
[tex]\begin{gathered} V=50.24\cdot17 \\ V=854.1\text{ ft\textasciicircum{}3} \end{gathered}[/tex]the volume is about 854.1 cubic feetcan Someone help me i still cant understand ,number 3
3)yes, the lines are parallel
Explanation
[tex]\begin{gathered} y=2x+5 \\ y=2x \end{gathered}[/tex]To see whether or not two lines are parallel, we must compare their slopes. Two lines are parallel if and only if their slopes are equal
Step 1
check the slopes
when you have a equation of a line in the form
[tex]\begin{gathered} y=mx+b \\ it\text{ is called, slope intercetp form} \\ \text{where} \\ m\text{ is the slope} \\ \text{and b is the y intercept} \end{gathered}[/tex]hence, for line 1
[tex]\begin{gathered} y=2x+5\rightarrow y=mx+b \\ so \\ m_1=2 \\ b=5 \end{gathered}[/tex]now, for line 2
[tex]\begin{gathered} y=2x\rightarrow y=mx+b \\ so \\ m_2=2 \\ b_2=0 \end{gathered}[/tex]Finally, compare the slopes
[tex]\begin{gathered} m_1=2 \\ m_2=2 \end{gathered}[/tex]the slopes are equal so the lines are parallel
I hope this helps you
4) The capacity of a bathtub is 297 liters. The capacity of a sink is 9 liters, How many sinks of water will fill the bathtub? A 2,673 B 30 33 5) There are 354 milliliters of soda in each can. How much soda is there in cans? A 59 L B 2 L 124 mL © 360 L Short Answer Write the answer in the space given.
We are told that one can of soda has a capacity of 354 milliliters, then in order to calculate how much soda is there in 6 cans, we just have to multiply 354 mlliliters by 6, then we get:
Soda in 6 cans = 354 × 6 = 2124
We can split these 2124 milliliters as 2000 milliliters+ 124 milliliters.
1 liter is equivalent to 1000 milliliters, then we can convert the first 2000 milliliters to liters by dividing by 1000, then we get:
soda in 6 cans = 2000 ÷ 1000 liters + 124 milliliters
soda in 6 cans = 2 liters + 124 milliliters
Then, the amount of soda in 6 cans is 2liters 124milliliters, the correct answer is option B
What can you tell about the means for these two months? (1 point)The mean for April is higher than October's mean.There is no way of telling what the means are.The low median for October pulls its mean below April's mean.O The high range for October pulls its mean above April's mean.
The box plot shows the distribution of the data classified in quartiles.
If we want to know about the mean of the data set, we can only that it will be located within the range of the data set.
It will be closer to the median as the distribution gets less skewed.
By looking at the box plot, we can not confirm that April's mean is higher than October's mean, as the plots are overlapped.
We can not also concluded about the relation between the spread of the data and the relation with the mean.
Then, the most appropiate conclusion from the options is "There is no way of telling what the means are".
A recent study of 28 city residents showed that the mean of the time they had lived at their present address was 9.3 years. The standard deviation of the population was 2 years. Find the 90% confidence interval of the true mean? Assume that the variable is approximately normally distributed. Show all your stepsVery confused in this exercise I’m self teaching myself
Given that:
- The sample size is 28 city residents:
[tex]n=28[/tex]- The mean of the time (in years) they had lived at their present address was:
[tex]\mu=9.3[/tex]- The standard deviation (in years) of the population was:
[tex]\sigma=2[/tex]Then, you need to use the following formula for calculating the Confidence Interval given the Mean:
[tex]C.I.=\mu\pm z\frac{\sigma}{\sqrt{n}}[/tex]Where μ is the sample mean, σ is the standard deviation, "z" is the z-score, and "n" is the sample size.
By definition, the z-score for a 90% confidence interval is:
[tex]z=1.645[/tex]Therefore, you can substitute values into the formula and evaluate:
[tex]C.I.=9.3\pm(1.645)(\frac{2}{\sqrt{28}})[/tex]You get that the lowest value is:
[tex]9.3-(1.645)(\frac{2}{\sqrt{28}})\approx8.678[/tex]And the highest value is:
[tex]9.3+(1.645)(\frac{2}{\sqrt{28}})\approx9.922[/tex]Hence, the answer is:
[tex]From\text{ }8.678\text{ }to\text{ }9.922[/tex]f(x)=(0.13x⁴+0.22x³)-0.88x²-0.25x-0.09for this polynomial use a graph to state the number of turning points
The graph of the function is:
From this, we can conclude that the polynomial has three turning points
Carol Wynne bought a silver tray that originally cost $135 and was advertised at 35% off. What was the sale price of the tray?The sale price was $(Type an integer or a decimal.)
Let:
Op = Original price
r = Percentage discount = 35% = 0.35
Sp = Sale price
We can find the sale price as follows:
[tex]\begin{gathered} Sp=Op-r\cdot Op \\ so: \\ Sp=135-0.35\cdot135 \\ Sp=135-47.25 \\ Sp=87.75 \end{gathered}[/tex]Answer:
$87.75
Linear functions f(x) = x and g(x) = 8/9x are graphed on the same coordinate plane. Which statement about therelationship between these two graphs is true?
Firstly, let us proceed to plot the graph of f(x) and g(x).
From the graph;
f(x)=x (green line)
g(x)=8/9 x (Blue)
The relationship they have is that they both starts from the origin (0,0).
Also, They both have a positive but not the same slope.
f(x) slope = 1
g(x) slope = 8/9
In the regular octagon below, if AP = 10 cm. and BC = 15 cm, find it's area.
Given:
There is a regular octagon given as below
Required:
We want to find the area of given regular octagon if AP = 10 cm. and BC = 15 cm
Explanation:
As we can see in the figure that there 8 triangles which are exactly same
so if we find area of 1 triangle and multiply with 8 we get the area of whole regular octagon
The area of 1 triangle is
[tex]a=\frac{1}{2}*10*15=75\text{ cm}^2[/tex]now to find area of regular octagon
[tex]A=8a=75*8=600\text{ cm}^2[/tex]
Final answer:
600 sq cm
I want to know the volume of the largest cube she could build with them.
All of the sides of a cube are equal, then, the volume is given by the cube of the length of any side.
We need to find the biggest cubic value smaller than 80.
[tex]\begin{gathered} 3\times3\times3=27 \\ 4\times4\times4=64 \\ 5\times5\times5=125 \end{gathered}[/tex]The largest cube has volume 64 cubic units, and the sides are 4 units long.