Given:
The two sides and angle of triangle are
[tex]\begin{gathered} a=19m \\ b=25m \\ \angle C=65\degree \end{gathered}[/tex]Required:
To find the value of X.
Explanation:
By cosine rule
[tex]\begin{gathered} X=\sqrt{a^2+b^2-2ab\cos C} \\ \\ =\sqrt{19^2+25^2-2\times19\times25\cos65} \\ \\ =24.17m \end{gathered}[/tex]Final Answer:
The value of X is
[tex]X=24.17m[/tex]Claire took part in a cross country race
and completed the course in 1 hour and 12
minutes. Her average speed for the race
was a sound 17.5 km per hour. What was
the distance that she ran
Claire who took part in a cross-country race ran 21 km in 1 hour and 12 minutes.
What is a unitary method?A unitary method is a mathematical way of obtaining the value of a single unit and then deriving any no. of given units by multiplying it with the single unit.
Given, Claire took part in a cross-country race and completed the course in 1 hour and 12 minutes which is (1 + 12/60) = (1 + 1/5) = 6/5 = 1.2 hours.
Her average speed for the race was 17.5 km per hour.
∴ The total distance she ran is,
= (17.5×1.2) km.
= 21 km.
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8. Select the equation that has no real solution.12x + 15 = 12x - 157x +21= 21-5x-25 = 5x + 2512x+ 15 = 3(4x+5)
We will have that the equation with no real solution is:
[tex]12x+15=12x-15[/tex]Because:
[tex]12x-12x=-15-15\Rightarrow0\ne-30[/tex]How would you do this type of problem and what would the increasing and decreasing interval be
y-intercept is the point in the y-axis that the graph intersects.
From the figure, the graph intersects at point (0, 3)
The y- intercept is (0, 3)
x-intercept is the point in the x-axis that the graph intersects.
Since the graph does not intersects the x-axis, the x-intercept does not exist
Vertex is a point on the graph that is a maximum or a minimum.
The vertex of the graph which is the lowest point as shown in the figure is at point (1, 2)
And this is a minima, since it is the lowest point.
Domain is the set of x-values that exist in the graph, the graph is going infinitely to the left and to the right, therefore the domain is (-∞, ∞)
Range is the set of y-values that exist in the graph, the y values starts from the vertex which is the lowest point at (1, 2) going upward.
So the range is all real numbers greater than or equal to 2. [2, ∞)
End behavior is the behavior of the function at large positive and negative values of x.
when x goes positive infinity, f(x) goes to positive infinity
As x ⇒ ∞, f(x) ⇒ ∞
when x goes negative infinity, f(x) goes to negative infinity
As x ⇒ -∞, f(x) ⇒ -∞
Decreasing interval occurs when the graph is going down, and increasing interval occurs when the graph is going up.
Decreasing interval will be (-∞, 1]
Increasing interval will be [1, ∞)
The expression to represent the decrease in temperature then the explanation and it’s meaning
The expression would be:
[tex]\frac{10}{1000}\cdot x[/tex]Where x are the meters climbed.
For 2,000 m we'll have:
[tex]\frac{10}{1000}\cdot2000\rightarrow20[/tex]A 20°C decrease in temperature.
Greetings, i need help with this math problem. Thank you
The numerator of the left hand side can be rewritten as:
[tex]x^2+6x+9=(x+3)^2[/tex]Then, the given equation can be written as:
[tex]\frac{(x+3)^2}{x+3}=0[/tex]Since
[tex](x+3)^2=(x+3)(x+3)[/tex]we have
[tex]\frac{(x+3)(x+3)}{x+3}=0[/tex]We can to can cancel out one term x+3 and get
[tex]x+3=0[/tex]which gives
[tex]x=-3[/tex]Finally, in order to check that this value corresponds to a real answer, we need to subsitute this value into the equation and compute the limit when x approaches to -3, that is,
[tex]lim_{x\rightarrow-3}\frac{x^2+6x+9}{x+3}[/tex]which gives
[tex]l\imaginaryI m_{x\operatorname{\rightarrow}-3}\frac{x^{2}+6x+9}{x+3}=\frac{0}{0}[/tex]Since the limit has the form 0/0 we can to apply L'Hopital rule, that is,
[tex]l\imaginaryI m_{x\operatorname{\rightarrow}-3}\frac{\frac{d}{dx}(x^2+6x+9)}{\frac{d}{dx}(x+3)}[/tex]which gives
[tex]l\imaginaryI m_{x\operatorname{\rightarrow}-3}\frac{\frac{d}{dx}(x^{2}+6x+9)}{\frac{d}{dx}(x+3)}=l\imaginaryI m_{x\operatorname{\rightarrow}-3}\frac{2x+6}{1}=\frac{0}{1}=0[/tex]Since the limit exists and is equal to zero then the solution of the equation is: x= -3
The population of one country changed from 23 million to 54 million. Use the information to find the unknown values in the bar diagrams a = L.347 b
The population of one country changed from 23 million to 54 million. Use the information to find the unknown values in the bar diagrams a = L.347 b
y
taxes :2.69 * 10 ^ 5 square miles Rhode Island:1.21 * 10 ^ 3 square miles Determine the differences in square miles between the area Texas and the area Rhode Island. write your answer in scientific notation
Explanation:
The difference is:
[tex]2.69\cdot10^5-1.21\cdot10^3[/tex]To solve this we need the exponent of 10 be the same for both terms of the substraction. It is better is we change the exponent of the area of Texas, by moving the decimal point two places to the right:
[tex]2.69\cdot10^5-1.21\cdot10^3=269\cdot10^3-1.21\cdot10^3[/tex]Now we can substract the numbers and leave the 10³ out:
[tex]269\cdot10^3-1.21\cdot10^3=(269-1.21)\cdot10^3=267.79\cdot10^3[/tex]Scientific notation has always only one place with a number before the decimal point. Therefore 267.79x10³ is not in scientific notation, we have to move the decimal point two places to the left and add 2 to the exponent of 10:
Answer:
The difference is 2.6779 x 10⁵ square miles
Find X and RDB:
X =
RDB =
[tex]\frac{13x+7-60}{2}=5x-10 \\ \\ 13x-53=10x-20 \\ \\ 3x-53=-20 \\ \\ 3x=33 \\ \\ \boxed{x=11} \\ \\ m\angle RDB=5(11)-10=\boxed{45^{\circ}}[/tex]
Use the GCF and the Distributive property to find the sum.
Notice that both numbers 26 and 29 are divisible by 13:
[tex]\begin{gathered} \frac{26}{13}=2 \\ \frac{39}{13}=3 \end{gathered}[/tex]thus, we can write the sum 26 + 39 like this:
[tex]26+39=13(2+3)[/tex]What is the surface area of a right square pyramid with height of 3 centimeters and a base that measures 8 centimeters by 8 centimeters?
Okay, here we have this:
Considering the provided measures, we are going to calculate the requested surface area, so we obtain the following:
So to calculate the surface area we will use the following formula:
A = a(a + √(a^2 + 4h^2))
A = 8 cm(8cm + √((8 cm)^2 + 4(3 cm)^2))
A = 8 cm(8cm + √(64 cm^2 + 4*9 cm^2))
A = 8 cm(8cm + √(64 cm^2 + 36 cm^2))
A = 8 cm(8cm + √(100 cm^2))
A = 8 cm(8cm + 10 cm)
A = 8 cm(18 cm)
total surface areaA = 144 m^2
Finally we obtain that the total surface area is equal to 144 m^2
which one is X value the proceeds from a carwash are directly proportional to the number of cars washed. The total after 9 cars with $180. How much can be raised if 60 cars were washed
Answer:
$1200 would be raised if 60 cars were washed.
Step-by-step explanation:
This question can be solved using a rule of three.
The total after 9 cars was of $180. How much would be raised with 60 cars washed?
9 cars - $180
60 cars - $x
Applying cross multiplication
9x = 180*60
9x = 10800
x = 10800/9
x = 1200
$1200 would be raised if 60 cars were washed.
Ivanna is on her way home in her car. Her drive is 12 miles long. She has finished one-fourth of the drive so far. How far has she driven?miles
Fractions
Ivanna has to drive 12 miles. She has already driven 1/4 so far.
The distance she has driven is:
[tex]\frac{1}{4}\cdot12=\frac{12}{4}=3[/tex]Ivanna has driven 3 miles so far
Question 4 of 10Select the correct product of the exponential expression.35A. 5.5.5B. 3.5C. 15D. 3.3.3.3.3SUBMIT
You have the following expression:
[tex]3^5[/tex]it means that the number 3 is multipled by itself five times (because of the exponent), then, the previous expression can be written as follow:
[tex]3^5=3\cdot3\cdot3\cdot3\cdot3[/tex]witch is an equation in point slope form the given point and slope point (1, 9) point 5
The formula for equation of line pasing through point (x_1,y_1) with slope m is,
[tex]y-y_1=m(x-x_1)[/tex]Substitute point and slope in the equation to obtain the equation of line.
[tex]\begin{gathered} y-9=5(x-1) \\ y-9=5x-5 \\ y=5x+4 \end{gathered}[/tex]So equation of line is y=5x+4.
2705 is compound annually at a rate of 8% for 1 year
The formula of compound interest is,
[tex]\begin{gathered} A=P(1+i)^n \\ \text{Here, A=2075, i=8\%, n=1 year} \\ 2075=P(1+\frac{8}{100})^1 \\ P=1921.3 \end{gathered}[/tex]Can you pls help me with this question thank you
I) We have to convert the temperature from Celsius to Farenheit, using the formula:
[tex]F=\frac{9}{5}\cdot C+32[/tex]The temperature in the Poconos is 15 °C, so we have C = 15. We can then calculate the temperature as:
[tex]\begin{gathered} F=\frac{9}{5}\cdot15+32 \\ F=27+32 \\ F=59 \end{gathered}[/tex]The temperature in Canada is 5 °C, so we can calculate the temperature in Farenheit as:
[tex]\begin{gathered} F=\frac{9}{5}\cdot5+32 \\ F=9+32 \\ F=41 \end{gathered}[/tex]II) We have to find the expression for the cost for each hotel in function of "n", the number of nights.
Holiday inn costs $80 per night plus $10 for parking.
We can express the total cost in function of n as:
[tex]undefined[/tex]richard can break up a fight in 12 minutes, harold can break up a fight in 5 minutes how long will it take them to solve it together pls help
SOLUTION
Write out the given information
[tex]\begin{gathered} \text{Time for Richard to break up a fight =12 minutes } \\ \text{Time for harold to break up a fight =5 minutes } \end{gathered}[/tex]Let the time at which both of them work be
[tex]R[/tex]Then
The individual rate will be
[tex]\begin{gathered} \text{Richard}=\frac{1}{12} \\ \text{And } \\ \text{Harold}=\frac{1}{5} \end{gathered}[/tex]Then
[tex]\frac{1}{12}+\frac{1}{5}=\frac{1}{R}[/tex]Simplifying fraction, we have
[tex]\begin{gathered} \frac{5+12}{60}=\frac{1}{R} \\ \text{Then} \\ \frac{17}{60}=\frac{1}{R} \end{gathered}[/tex]Hence
[tex]\begin{gathered} R=\frac{60}{17} \\ R=3.53 \end{gathered}[/tex]Therefore
It will take both of them 3.53 minutes to solve it together
Determine the slope of the line between (-6,13) and (1,11)
We can find the slope using the following formula:
[tex]m=\frac{y2-y1}{x2-x1}[/tex]Let:
[tex]\begin{gathered} (x1,y1)=(-6,13) \\ (x2,y2)=(1,11) \\ \end{gathered}[/tex]Therefore:
[tex]m=\frac{11-13}{1-(-6)}=\frac{-2}{7}=-\frac{2}{7}[/tex]Answer:
[tex]-\frac{2}{7}[/tex]Find the exact value of s in the given interval that has the given circular function value.
Recall that:
[tex]\tan x=\frac{\sin x}{\cos x}\text{.}[/tex]Therefore:
[tex]\tan s=1\Leftrightarrow\frac{\sin s}{\cos s}=1.[/tex]Then:
[tex]\sin s=\cos s\text{.}[/tex]Now, notice that:
[tex]\sin s-\cos s=-\sqrt{2}\cos (s+\frac{\pi}{4}).[/tex]Then:
[tex]-\sqrt[]{2}\cos (s+\frac{\pi}{4})=0.[/tex]Therefore:
[tex]\cos (s+\frac{\pi}{4})=0.[/tex]Then:
[tex]\begin{gathered} s+\frac{\pi}{4}=\frac{\pi}{2}+n\pi, \\ s+\frac{\pi}{4}=\frac{3\pi}{2}+n\pi\text{.} \end{gathered}[/tex]Therefore:
[tex]\begin{gathered} s=\frac{\pi}{4}+n\pi, \\ s=\frac{5\pi}{4}+n\pi\text{.} \end{gathered}[/tex]Since:
[tex]s\in\lbrack\pi,\frac{3\pi}{2}\rbrack^{},[/tex]we get that:
[tex]s=\frac{5\pi}{4}\text{.}[/tex]Answer:
[tex]s=\frac{5\pi}{4}\text{.}[/tex]The back of Toms property is a creek. Tom would like to enclose a rectangular area, using the creek as one side and fencing for the other three sides, to create a pasture. If there is 120 feet of fencing available, what is the maximum possible area of the pasture?
Suppose that the sides of the rectangle have lengths x and y, and that the measure of the side parallel to the creek is y, as shown in the drawing below
The total length of the fence, according to the drawing, is:
[tex]2x+y[/tex]Since there is 120 feet of fencing available, then:
[tex]\begin{gathered} 2x+y=120 \\ \Rightarrow y=120-2x \end{gathered}[/tex]On the other hand, the area A of the pasture, is equal to the base 120-2x times the height x:
[tex]\begin{gathered} A=x(120-2x) \\ =2x(60-x) \end{gathered}[/tex]Find the maximum value of the 2nd degree polynomial for A. Since A has roots at x=0 and x=60, the maximum value is found at x=(60+0)/2=30.
Then, the maximum possible area of the pasture can be found by plugging in x
Convert the following units as indicated.2,250 watts to horsepower (Round answer to the nearest thousandth.)
The question given is to convert
[tex]2250\text{ watts to horse power}[/tex]From a conversion calculator,
[tex]1\text{ horse power = }745.699872\text{Watt}[/tex]Therefore,
[tex]1\text{ watts = }\frac{1}{745.699872}\text{horse power}[/tex]Therefore,
2250 watts will be
[tex]\begin{gathered} =2250\times\frac{1}{745.699872} \\ =\frac{2250}{745.699872}\text{horse power} \\ =3.0172997\text{ horse power} \\ \approx to\text{ the nearest thousandth} \\ =3.017\text{ horsepower} \end{gathered}[/tex]Hence,
The final answer = 3.017 horse power
I need help converting to logarithmic equation e^-t = 125
Apply ln to both sides:
Ln e^-t = ln 125
Ln e (125) = -t
find the area of the white region ...blue region has a 150 degree triangle with 7cm side and the circle has a radius of 7
First, let's find the area circular sector:
[tex]A=\frac{r^2\theta}{2}[/tex]Where:
r = radius = 7cm
θ = angle (in radians) = 5/6 π
so:
[tex]\begin{gathered} A=\frac{7^2(\frac{5}{6}\pi)}{2} \\ A=\frac{245}{12}\pi \end{gathered}[/tex]Now, let's find the area of the triangle, that triangle is an isosceles triangle, so, we can use the following formula in order to find its area:
[tex]\begin{gathered} At=\frac{1}{2}s^2\cdot\sin (\theta) \\ \end{gathered}[/tex]where:
s = one of the equal sides = 7
θ = angle = 150
so:
[tex]\begin{gathered} At=\frac{1}{2}(7^2)\sin (150) \\ At=\frac{49}{4} \end{gathered}[/tex]Therefore, the area of the white region will be, the area of the circular sector minus the area of the isosceles triangle, so:
[tex]Area_{\text{ }}of_{\text{ }}the_{\text{ }}white_{\text{ }}region=\frac{245}{12}\pi-\frac{49}{4}=51.9cm^2[/tex]please help me Solve for a6=a/4+2-6+x/4=-59x-7=-70=4+n/5-4=r/20-52(n+5)=-2-9x+1=-80144=-12(x+5)10-6v=-104
6=a/4+2
Subtract 2 from both sides of the equation:
6-2 = a/4+2-2
4 = a/4
Multiply both sides by 4
4 (4) = a/4 (4)
16 = a
a= 16
At an important meet, Hassan won the men's 400 meters in 47.36 seconds. Hassan ran an average rate of__ meters per minnearest hundredth
506.78 meters per min
Explanation:distance = 400 m
time = 47.36 seconds
The result is meant to be in meters/min
We need to convert the seconds to minute:
60 seconds = 1 min
47.36 seconds = 47.36/60 = 0.7893
The average rate will be distance divided by time
[tex]\begin{gathered} \text{Average rate =}\frac{400}{0.7893} \\ \text{Average rate =}\frac{400}{0.7893}\text{ = }506.7782 \\ \\ \text{Average rate = }506.78\text{ meters per min (nearest hundredth)} \end{gathered}[/tex]We use absolute value to find distances in the real world. Suppose you travel 10 miles north to the grocerystore, then 6 miles south to the post office. From there, you travel 8 miles north to the nearest bank. What isthe total distance you have traveled?A. 4 milesB. 8 milesC.12 milesD. 24 milesPlease select the best answer from the choices providedOAOBOCOD
Given:
Thesis about question is given
Required:
To select which option is correct
Explanation:
assumption S1 is the distance to the grocery store
assumption S2 is the distance to the south post office
assumption S3 is the distance to the north bank
assumption S is the total distance
according to the question
S1= 10 miles S2=6 miles S3=8 miles
S=S1+S2+S3=10+6+8=24 miles
Required answer:
option D
a rectangle with a base of 6 and height of 4 has been scaled with a scale factor of 3. what is the area of the scaled copy?
We have a rectangle of base 6 and height 4. We have a rectangle like this:
Now, we have a scale factor of 3. We need to multiply each side by 3:
Now the rectangle has a height of 12 and a base of 18.
The area of a rectangle is h*b. Then, the area of the scaled copy is:
[tex]A=12\cdot18\Rightarrow A=216[/tex]Therefore, the scaled copy has an area of 216 square units.
when Thanos snapped his fingers in Avengers endgame he put a circular hole in this Square what is the area of the Shaded region last left?
Calculate the area of the square (A1), and then subtract the area of the circle (A2).
Square area = side length ^2
A1 = 12^2 = 144 ft2
Area of a circle = π r^2
where:
r= radius = diameter /2 = 12/2 = 6
Replacing:
A2 = π 6^2 = 113.09 ft^2
Area of the shaded region = A1- A2 = 144-113.09 = 30.92 ft2
How is the series 7 + 13 + 19+...+ 139 represented in summation notation?
Each term is 6 greater than the previous term.
First term is "7".
So,
a = 7
d = 6
Let's find the formula for the series,
[tex]\begin{gathered} a+(n-1)d \\ 7+(n-1)(6) \\ 7+6n-6 \\ 6n+1 \end{gathered}[/tex]We can immediately eliminate the firsst and third choice.
The variable is "t", so the general formula will be:
[tex]6t+1[/tex]How many terms are there?
The series starts from t = 1,
since 6(1) + 1 = 6 + 1 = 7
and 6(2) + 1 = 12 + 1 = 13
The terms match!
So, 2nd answer choice is correct!!
Answer[tex]\sum ^{23}_{t\mathop=1}(6t+1)[/tex]A farmer has 36 ft of fencing and wants to enclose the maximum rectangular area for his llamas. Find the dimensions of three possible areas he could enclose. What do you think the maximum area is? Why?
The farmer would like to eclose a rectangle
First we know that the perimeter of the rectangle is
[tex]P=2x+2y[/tex]We also know that we have 36 ft of fence, that is we only can enclose a rectangle of 36 ft of perimeter. Then
[tex]36=2x+2y[/tex]From this we can find y
[tex]\begin{gathered} 36=2x+2y \\ 36-2x=2y \\ y=\frac{36-2x}{2} \\ y=18-x \end{gathered}[/tex]The area of the rectangle is
[tex]A=xy[/tex]But we know the value of y, plugging this value into the last equation we have that
[tex]A=x(18-x)[/tex]To find three possible values for the area we only have to give values to x. This values have to be positive (since we can't have a negative lenght). We also notice that the value can't exceed 18 since that would mean a zero area. With those point in consideration we choose three values between zero and 18.
If x=3, then the area is
[tex]\begin{gathered} A=3(18-3) \\ =3(15) \\ =45 \end{gathered}[/tex]If x=9, then the area is
[tex]\begin{gathered} A=9(18-9) \\ =9(9) \\ =81 \end{gathered}[/tex]if x=15, then the area is
[tex]\begin{gathered} A=15(18-15) \\ =15(3) \\ =45 \end{gathered}[/tex]Then we have three possible areas for the rectangle.
The maximum value for the area is 81, and we see that because the equation for the area is a parabola that opens down with vertex in the point (9,81)