Solve for the values of x and y for the regular hexagon.a. x = 120, y = 60b. x = 110, y = 70c. x = 105, y = 75d. x = 60, y = 120e. X = 115, y = 65

Solve For The Values Of X And Y For The Regular Hexagon.a. X = 120, Y = 60b. X = 110, Y = 70c. X = 105,

Answers

Answer 1

Remember that the sum of the interior angles of an hexagon is equal to 720°

Because this is a regular hexagon,

[tex]\begin{gathered} 6x=720\rightarrow x=\frac{720}{6} \\ \rightarrow x=120 \end{gathered}[/tex]

Notice angles x and y lay in the same straight line.

Thereby,

[tex]\begin{gathered} x+y=180 \\ \rightarrow120+y=180 \\ \rightarrow y=180-120 \\ y=60 \end{gathered}[/tex]

Therefore,

[tex]\begin{gathered} x=120 \\ y=60 \end{gathered}[/tex]

(The correct answer is option A)


Related Questions

The values of events A, B, and C are provided. Compare the probabilityof event A occurring, given that event C occurred to the probability ofEvent B happening, given that event C occurred (Compare P(A/C) toP(BIC)] Which event is more likely?P(A) = 0.45P(B) = 0.30P(C) = 0.25

Answers

The conditional probability P(A/C) is given by

[tex]P(A|C)=\frac{P(A\cap C)}{P(C)}[/tex]

If event A is independent to event C, we can write

[tex]P(A|C)=\frac{P(A)\cdot P(C)}{P(C)}=P(A)[/tex]

Similary, if event B is independent to event C, we get

[tex]P(B|C)=\frac{P(B)\cdot P(C)}{P(C)}=P(B)[/tex]

Then, by comparing both results we can see that event A is more likey than event B.

CheckWhich applies the power of a power rule properly to simplify this expression?(7-8)O (78)4 = 7-8) +(-4) = 7-12 =17121O (7-8)4 = 7(+8)+(-4) = 74 =741O (7-3) = 71-8)(-4) = 7-32 =732O 7-8,4 = 7(-8)(-4) = 72IntroDone

Answers

We are given the expression below

[tex](7^{-8})^{-4}[/tex]

This expression can be solved by using one of the laws of indices which is denoted below:

[tex](a^m)^n=a^{m\times n}[/tex]

Using the above the given expression beocmes

[tex]undefined[/tex]

help!!! i’ll mark brainliest!!!

Answers

For the given diagram, both the triangles are congruent that is  ΔLKM ≅ ΔJKM by using theorem of ASA ( Angle side Angle).

As given in the question,

In the given diagram of the triangles,

Given : ∠LKM ≅ ∠JKM

∠LMK ≅ ∠JMK

To prove : ΔLKM ≅ ΔJKM

∠LKM ≅ ∠JKM  ( given )

∠LMK ≅ ∠JMK ( given )

KM ≅ KM ( using reflexive property of congruence )

By applying ASA theorem ( Angle Side Angle )

ΔLKM ≅ ΔJKM

Therefore, for the given diagram, both the triangles are congruent that is  ΔLKM ≅ ΔJKM by using theorem of ASA ( Angle side Angle).

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1.) A.) Name the 'item' on which point L exists.B.) If ML= 6x - 4, LH = 10x+1 and MH = 29, find the length of ML.

Answers

Now for the point A), L is in the middle of M and H, and the interval will be:

[tex](M,H)[/tex]

For the second point, We need to put the value of the segments in the draw...

From the draw, we can deduce that:

[tex]ML+LH=MH[/tex]

We replace with values:

[tex]\begin{gathered} ML+LH=MH \\ 6x-4+(10x+1)=29 \end{gathered}[/tex]

We solve to x:

[tex]\begin{gathered} 6x-4+(10x+1)=29 \\ 6x\text{ -4 +10x +1=29 ; we agroup the values with x} \\ (6x+10x)-4+1=29 \\ 16x-3=29 \\ 16x=29+3 \\ 16x=32 \\ x=\frac{32}{16}=2 \\ x=2 \end{gathered}[/tex]

Finally, if the value of x = 2, then whi can replace in:

[tex]\begin{gathered} ML=6x-4 \\ ML=6(2)-4 \\ ML=12-4 \\ ML=8 \end{gathered}[/tex]

Your answer of point B) is ML=8.

Write an equivalent expression of 4(6x+12), and state the property you used to write it.

Answers

Solution

Using the distributive property

4(6x + 12)

[tex]4(6x+12)=4\times6x+4\times12=24x+48[/tex]

A toddler is jumping on another pogo stick whose length of their spring can be represented by the function g of theta equals 1 minus sine squared theta plus radical 3 period At what times are the springs from the original pogo stick and the toddler's pogo stick lengths equal?

Answers

Answer:

The springs from the original pogo stick and the toddler's pogo stick length are equal after 1 second and 0.9994 second.

Explanation:

The given functions are:

[tex]\begin{gathered} f(\theta)=2\cos \theta+\sqrt[]{3} \\ g(\theta)=1-\sin ^2\theta+\sqrt[]{3} \end{gathered}[/tex]

The springs from the original pogo stick and the toddler's pogo stick length are equal when both functions coincide

That is;

[tex]\begin{gathered} f(\theta)=g(\theta) \\ \Rightarrow2\cos \theta+\sqrt[]{3}=1-\sin ^2\theta+\sqrt[]{3} \end{gathered}[/tex]

Solving the equation, we have:

[tex]\begin{gathered} 2\cos \theta+\sqrt[]{3}=1-\sin ^2\theta+\sqrt[]{3} \\ Subtract\sqrt[]{3}\text{ from both sides} \\ 2\cos \theta=1-\sin ^2\theta \end{gathered}[/tex]

Note the identity below:

[tex]\begin{gathered} \cos ^2\theta+\sin ^2\theta=1 \\ \cos ^2\theta=1-\sin ^2\theta \end{gathered}[/tex]

This means

[tex]\begin{gathered} 2\cos \theta=\cos ^2\theta \\ \cos ^2\theta-2\cos \theta=0 \\ \cos \theta(\cos \theta-2)=0 \\ \cos \theta=0 \\ \Rightarrow\theta=\cos ^{-1}(0)=1 \\ \\ OR \\ \cos \theta-2=0 \\ \cos \theta=2 \\ \theta=\cos ^{-1}(2)=0.9994 \end{gathered}[/tex]

The springs from the original pogo stick and the toddler's pogo stick length are equal after 1 second and 0.9994 second.

From a point x = 80 feet in front of a public library, the angles of elevation to the base of the flagpole and the top of the flagpole are = 29.5° and 39° 45', respectively. The flagpole is mounted on the front of the library's roof. Find the height of the flagpole.

Answers

Let's draw the scenario to better understand the details.

To be able to determine the height of the flagpole, let's create two different triangles with 29.5° and 39° 45' angle. The two triangles have one common base at 80 Feet, yet have different heights at H+h and H respectively.

Where,

H = Height of the library

h = Height of the flag

The two triangles are proportional at a common base, thus, let's generate this expression using the Law of Sines:

[tex]\frac{H+h}{\sin(39\degree45^{\prime})}\text{ = }\frac{H}{\sin(29.5^{\circ})}[/tex]

Let's simplify,

[tex]\frac{H+h}{\sin(39\degree45^{\prime})}\text{ = }\frac{H}{\sin(29.5^{\circ})}\text{ }\rightarrow\text{ (}H+h)(\sin (29.5^{\circ}))\text{ = (H)(}\sin (39\degree45^{\prime}))[/tex][tex]H\sin (29.5^{\circ})\text{ + h}\sin (29.5^{\circ})\text{ = H}\sin (39\degree45^{\prime})\text{ ; but }29.5^{\circ}=29^{\circ}30^{\prime}[/tex][tex]H\sin (29^{\circ}30^{\prime})\text{ + h}\sin (29^{\circ}30^{\prime})\text{ = H}\sin (39\degree45^{\prime})[/tex][tex]\text{h}\sin (29^{\circ}30^{\prime})\text{ = H}\sin (39\degree45^{\prime})\text{ - }H\sin (29^{\circ}30^{\prime})[/tex][tex]\text{ h(}0.4924235601)\text{ = H(0.63943900198) -H}(0.4924235601)[/tex][tex]\text{ h(}0.4924235601)\text{ = H(0.14701544188)}[/tex][tex]undefined[/tex]

Find the slope of the line shown on the graph to the right.What is the slope of the line? The slop of the line is ___

Answers

The formula for determining slope is expressed as

slope = (y2 - y1)/(x2 - x1)

where

y1 and y2 are the y coordinates of initial and final points on the line

x1 and x2 are the x coordinates of initial and final points on the line

From the graph,

when x1 = - 4, y1 = 0

when x2 = 2, y2 = 4

slope = (4 - 0)/(2 - - 4) = 4/(2 + 4) = 4/6

Simplifying 4/6 to its lowest term

slope = 2/3

y=-2xy=x-8how do you do this

Answers

Separate

y =- 2xy

-2xy = x - 8

Now solve first equation

and then second equation

PART2

y = -2x

y= -4x + 10

Is solved by , substracting both equations

Then

(y - y) = -2x - ( -4x + 10)

0 = -2x + 4x - 10

10 = 2x

10/2= xx

The age of the Earth is inferred from the-A. age of the uranium -235B. age of the Grand CanyonC. age of the Canyon Diablo meteoriteD. age of dinosaurs

Answers

The age of the Earth is inferred from the - age of the Canyon Diablo meteorite .

To find : The age of the Earth

Age - Age is defined as the length of time during which a thing or being existed .

a ) the half life of age of uranium-238 , uranium's most abundant and longest-lived isotope is approximately 4.47 billion years ago .

b ) the age of Grand Canyon is 1.8 billion years ago .

c ) The fragment of the Canyon Diablo meteorite determined the elements that formed as radioactive uranium decayed over billions of years.

d ) age of dinosaurs was about 252 million to about 66 million years ago .

Hence , c ) age of the Canyon Diablo meteorite .

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determine the degree of the polynomial[tex] - 65b + {53x}^{3}y[/tex]

Answers

Determine the degree of the polynomial



656+ 3x^3 y

Degree of the polynomial = 4 = (3 + 1)

3x^3 grade (3)

y grade (1)

________________

The degree of the polynomial is 4

Solve the following system of equation using substitution4x + 2y = 10?/1x - y = 13What is the solution for x?

Answers

ANSWER

x = 6

EXPLANATION

The substitution method consists on taking one equation to solve for one variable as a function of the other. Then substitute that variable with the expression we find in the other equation and then solve for that other variable.

In this case, we want to solve for x, so we'll take one of the equations and find y as a function of x. For the second equation:

[tex]\begin{gathered} x-y=13 \\ y=x-13 \end{gathered}[/tex]

Now we replace y by x - 13 in the first equation:

[tex]4x+2(x-13)=10[/tex]

And solve for x:

[tex]\begin{gathered} 4x+2x-2\cdot13=10 \\ 6x-26=10 \\ 6x=10+26 \\ 6x=36 \\ x=\frac{36}{6} \\ x=6 \end{gathered}[/tex]

Miss Johnson has a tree in her garden that grows apples in the spring and summer the tree has a diameter of 32 ft from its base what is the circumference of that tree in Miss John's Garden

Answers

We know that the circunference of a circle is:

[tex]C=2D[/tex]

where D is the diameter so the circunference will be:

[tex]\begin{gathered} C=2\cdot32 \\ C=64 \end{gathered}[/tex]

-3x + 5y = -155x - 2y = -101. Find the solution2. Write an equation to replace the second equation so that the system will have infinitely many solutions.

Answers

Problem

-3x + 5y = -15

5x - 2y = -10

Solution

For this case we can solve x from the first equation and we got:

3x = 5y +15

x= (5y+15)/3

Now we can replace this value into the second equation and we got:

5((5y+15)/3) -2y = -10

25/3y +25 -2y= -10

And solving for y we got:

(25/3 -2)y =-10-25

19/3 y = -35

y= -105/19

And then we can solve for x and we got:

x= (5*(-105/19) +15)/3 = -80/19

What function best represents the perimeter of the orange boxes? *

Answers

The formula used to calculate the perimeter of a rectangle is given to be:

[tex]P=2l+2h[/tex]

FIRST BOX

For the first orange box, we have that:

[tex]\begin{gathered} l=x+x=2x \\ h=2 \end{gathered}[/tex]

Note that the box is divided into 2 parts.

Therefore, this perimeter is:

[tex]P_1=2(2x)+2(2)=2(2x)+4[/tex]

SECOND BOX

For the second orange box, we have that:

[tex]\begin{gathered} l=x+x+x=3x \\ h=2 \end{gathered}[/tex]

Note that the box is divided into 3 parts.

Therefore, the perimeter is:

[tex]P_2=2(3x)+2(2)=2(3x)+4[/tex]

Using the associative property of multiplication, we have that:

[tex]P_2=3(2x)+4[/tex]

Since x = 5, we have:

[tex]\begin{gathered} P_1=2(10)+4 \\ P_2=3(10)+4 \end{gathered}[/tex]

where 2 and 3 are the number of divisions of the boxes.

If we represent the number of divisions with x, we have the perimeter's function to be:

[tex]P=10x+4[/tex]

ANSWER

The correct option is the THIRD OPTION.

9 divided by 2765 that’s what I’m am asking for

Answers

Answer: 307.22222222222 ......

Step-by-step explanation: use the bus stop method to help you

A given circle has an approximate area of 78.5 square units. How long is the circles diameter?

Answers

Remember that

The area of a circle is equal to

[tex]A=\pi\cdot r^2[/tex]

we have

A=78.5 unit2

I will assume pi=3.14

substitute in the formula

[tex]\begin{gathered} 78.5=3.14\cdot r^2 \\ r^2=\frac{78.5}{3.14} \\ r=5\text{ units} \end{gathered}[/tex]

the diameter is two times the radius

so

D=2(5)=10 units

therefore

The diameter is 10 units

Find the radius of the circle with a circumference of 39 yards. Round your answer to the nearest hundredth of a yard.the radius of the circle is blank yards

Answers

Answer:

6.207

Explanation:

The circumference C of the circle is given by

[tex]C=2\pi r[/tex]

where r is the radius.

Now we are given that C = 39 yd; therefore,

[tex]39=2\pi r[/tex]

dividing both sides by 2pi gives

[tex]\frac{39}{2\pi}=\frac{2\pi r}{2\pi}[/tex][tex]r=\frac{39}{2\pi}[/tex][tex]r=6.207yd[/tex]

Hence, the radius of the circle is 6.207 yards.

On (07.03) Choose the correct simplification of the expression b5.54. (1 point)

Answers

[tex]\text{The answer is c}^{11}[/tex]

explanation/ Working:

[tex]c^2.c^9=c^2\times c^9=c^{2+9}=c^{11}[/tex]

Rule on iindex says when the base is same, you should add the powers

[tex]c^2.c^9=\text{ (c}\times c)\times(c\times c\times c\times c\times c\times c\times c\times c\times c)=c^{11}[/tex]

the ordered pair (2,16) is a solution for which equation(s) check all that apply

Answers

We have the following:

We must evaluate each equation (x = 2), if the result is 16 it will be a solution

A.

[tex]y=(2\cdot2)^2=4^2=16[/tex]

B.

[tex]y=(2+2)^2=(4)^2=16[/tex]

C.

[tex]y=2\cdot2^2=2\cdot4=8[/tex]

D.

[tex]y=2\cdot2+2=4+2=6[/tex]

Therefore, the correct answer is A and B

(5n+6)(5n-5) distribute property

Answers

We have the following:

[tex](5n+6)\cdot(5n-5)[/tex]

we apply distribute property:

[tex]25n^2-25n+30n-30=25n^2+5n-30[/tex]

Resultant of the distributive property is 25n² + 5n - 30 .

Given,

(5n+6)(5n-5)

Now,

Distributive property in multiplication  : a x (b x c) = (axb) x c

Thus apply the property in the given expression,

(5n+6)(5n-5)

= 25n² - 25n + 30n - 30

Solve the terms with variable n,

= 25n² + 5n - 30

Final expression : 25n² + 5n - 30

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What is the system of inequalities associated with the following graph?A) {y<−1x {+y>1 B) {y>−1 {x+y≥1 C) {y<−1 {x+y≥1 D) {y < -1 {x + y <1

Answers

SOLUTION:

Step 1:

In this question, we are given the following:

What is the system of inequalities associated with the following graph?

Step 2:

The details of the solution are as follows:

CONCLUSION:

The final answer is:

C) {y<−1

{x+y≥1

Find the lengths of the missing sides in the triangle. Write your answers as integers or as decimals rounded to the nearest tenth. Not drawn to scale x= 6.9, y = 5.7 x=8, y = 11.3 x 11.3, y = 8 x = 5.7, y = 6.9

Answers

x=11.3 y=8

Explanation

here we have a right triangle, so we can use a trigonometric function to find the missing sides

so

Step 1

a)let

[tex]\begin{gathered} angle=45\text{ \degree} \\ opposite\text{ side=8} \\ adjacent\text{ side=y} \\ hypotenuse=x \end{gathered}[/tex]

Step 2

now, fin the missing length

a) y

to find the adjacent side we can use the stan function

[tex]tan\theta=\frac{opposite\text{ side}}{adjacent\text{ side}}[/tex]

replace and solve for y( adjacent side)

[tex]\begin{gathered} tan45=\frac{8}{y} \\ y=\frac{8}{tan\text{ 45}}=\frac{8}{1} \\ y=8 \end{gathered}[/tex]

b)x (hypotenuse)

to find the hyoptenuse we can use the sin function ,

[tex]\sin\theta=\frac{opposite\text{ side}}{hypotenuse}[/tex]

replace and solve for x

[tex]\begin{gathered} sin\text{ 45=}\frac{8}{x} \\ x=\frac{8}{sin\text{ 45}}=11.3 \\ x=11.3 \end{gathered}[/tex]

therefore, the answer is

x=11.3 y=8

I hope this helps you

how do i do this i need answers help please

Answers

SOLUTION:

Step 1:

In Question 8, we have that:

The three vertices of Triangle ABC are located in Quadrant III.

The image of Triangle ABC after a reflection in the x-axis in the x-axis is

[tex]\text{Triangle A}^IB^IC^I[/tex]

Then, the triangle

[tex]A^IB^IC^I[/tex]

is located in II -- OPTION B

What is the component form of resultant of 4b⃗ −2aa = (7 , -5)b = ( -4 , 4)

Answers

[tex]\langle-30,26\rangle[/tex]

1) Since we have this expression, let's do it in parts.

[tex]\begin{gathered} 4\langle-4,4\rangle-2\langle7,-5\rangle \\ x-component=4(-4)-2(7)=-16-14=-30 \\ y-component=4(4)-2(-5)=16+10=26 \\ \end{gathered}[/tex]

Note that since each vector has two components x, and y. The resultant will be the vector:

[tex]\langle-30,26\rangle[/tex]

a smmall rectangular tray measures 16 cm by 18 cm determine the length of the diagonal . round you're answer to the nearest tenth.m

Answers

Given the dimension of the rectangle:

16 cm by 18 cm

We have the image of the rectangle below:

To find the length of the diagonal AC, use pythagorean theorem since ACD form a right triangle.

Thus, we have:

[tex]\begin{gathered} AC^2=AD^2+DC^2 \\ \\ AC=\sqrt[]{AD^2+DC^2} \end{gathered}[/tex]

Input values into the formula:

[tex]\begin{gathered} AC=\sqrt[]{18^2+16^2} \\ \\ AC=\sqrt[]{324+256} \\ \\ AC=\sqrt[]{580} \\ \\ AC=24.08\approx24.1\text{ cm} \end{gathered}[/tex]

Therefore, the length of the diagonal is 24.1 cm

ANSWER:

24.1 cm

the graph represent 1, and the equation represents function 2: function 2: y=8x + 12how much more is the rate of function 2 then the rate of change of function 1?answer choices:a.3b.4c.5d.8

Answers

as the graph represent a constant function, we have that the rate for function 1 is 0. The rate for the second function is 8. So we get that the the answer is D

collin noticed that various combinations of the nickels and dimes could add uo to $0.75 let x equal the numver of nickles let y equal the number of dimes what is the domain where y is a function of x and the total value is $0.75

Answers

Input data

nickles = 5 cents

dimes = 10 cents

x = number of nickles

y = number of dimes

Please please please help me

Answers

The lines l, m, and n are parallel to each other and the value of x is 8.34.

What are parallel lines?

Parallel lines are lines that are equidistant from each other and do not meet no matter how far they extend in either direction. Parallel lines form angles when crossed by a transversal and show some significant properties.

Angles that correspond are equal.Angles that are vertically opposite or vertically angled are equal.Interior angles that are opposite each other are equal.On the same side of the transversal, a pair of interior angles are supplementary.

For the given question, we can see that lines l ║m ║n.

Therefore, (6x - 2)° = 52° [Vertically opposite angles are equal]

6x = 52 - 2

6x = 50

x = 50/6

x = 8.34

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I require assistance on a troubling problem

Answers

Given data:

The given table.

The standard expression for the exponential function is,

[tex]y=a(b)^x[/tex]

Substitute o for x and 5 for y in the above expression.

[tex]\begin{gathered} 5=a(b)^0 \\ 5=a \end{gathered}[/tex]

Substitute 1 for x, 15 for y, and 5 for a in the standard exponential expression.

[tex]\begin{gathered} 15=5(b)^1 \\ b=3 \end{gathered}[/tex]

The exponential expression can be written as,

[tex]y=5(3)^x[/tex]

Thus, the expression for the exponential function is y=5(3)^x.

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