After 3 hours, Selma is approximately 130 miles from home and Didi is approximately 52 miles from home
please help this math seem hard 50 points anyone
An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.
The equivalent expression is
[tex]x^{3/2}y^{19/2}[/tex]
Option C is the correct answer.
What is an expression?An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.
Example: 2 + 3x + 4y = 7 is an expression.
We have,
√(xy³) x ([tex]x^{1/2} y^4[/tex])²
This can be written as,
[ √ means 1/2, √a = [tex]a^{1/2}[/tex]]
√(xy³) = [tex]x^{1/2}y^{3/2}[/tex]
([tex]x^{1/2} y^4[/tex])² = x[tex]y^8[/tex]
Now,
√(xy³) x ([tex]x^{1/2} y^4[/tex])²
= [tex]x^{(1/2 + 1)}y^{(3/2 + 8)}[/tex]
= [tex]x^{3/2}y^{19/2}[/tex]
Thus,
The equivalent expression is
[tex]x^{3/2}y^{19/2}[/tex]
Option C is the correct answer.
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1. An input-output table has constant differences. When the input is 3, the output is 10. When the input is 7, the output is 24. a. Find the constant difference. b. Find the output when the input is 0. C. Find the linear function that fits the table.
a)7,17
b)-25
c)
[tex]y=3.5x-25[/tex]Explanation
table
a) differences
10-3=7
24-7=17
Step 1
find the slope
[tex]\begin{gathered} \text{slope}=\frac{\Delta y}{\Delta x}=\frac{y_2-y_1}{x_2-x_1} \\ \text{where} \\ P1(x_1,y_1) \\ P2(x_2,y_2) \end{gathered}[/tex]Let
P1(3,10)
p2(7,24)
replace,
[tex]\begin{gathered} \text{slope}=\frac{\Delta y}{\Delta x}=\frac{y_2-y_1}{x_2-x_1} \\ \text{slope}=\frac{24-10}{7-3}=\frac{14}{4}=\frac{7}{2} \\ \text{slope}=\frac{7}{2} \end{gathered}[/tex]Step 2
find the equation
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-10=\frac{7}{2}(x-10) \\ y-10=\frac{7}{2}x-\frac{70}{2} \\ y=\frac{7}{2}x-\frac{70}{2}+10 \\ y=3.5x-25 \end{gathered}[/tex]Step 3
when x=0
[tex]\begin{gathered} y=3.5x-25 \\ y=3.5\cdot0-25 \\ y=-25 \end{gathered}[/tex]I hope this helps you
If.A = (e, x, a, m) and U = {a, b, c, d, e, f, g, h, I, J. K, 1. m. n. o. p. q. r, S, t. u, v. w.x.y.z} find A.
Given that the set A contains the letters e, x, a and m, the complement A' will be the set that does not include these letters, thus, A' can be written as:
[tex]A^{\prime}=\mleft\lbrace b,c,d,f,g,h,i,j,k,l,n,o,p,q,r,s,t,u,v,w,y,z\mright\rbrace[/tex]The fish population of a receding pond is 8,000. The population is expected to decrease at a rate of 8% each year.Which function represents the population of the fish in the pond after x years?
Answer: f(x) = 8000(0.92)^x
Explanation:
The formula for calculating exponential decay is expressed as
f(x) = P(1 - r)^x
where
f(x) is the population after a period of x
P is the initial population
r is the decay rate
x is the time
From the information given,
P = 8000
r = 8% = 8/100 = 0.08
By substituting r = 0.08 into the equation. We have
f(x) = 8000(1 - 0.08)^x
f(x) = 8000(0.92)^x
Convert 7π/6 radians to degrees
ANSWER:
210°
STEP-BY-STEP EXPLANATION:
In order to convert from radians to degrees, we must take into account that π is equal to 180°, knowing this, let's do the conversion:
[tex]\begin{gathered} \pi=180\degree \\ \\ \text{ We replacing} \\ \\ 7\cdot\frac{180\degree}{6}=210\degree \end{gathered}[/tex]Therefore, 7π/6 radians is equal to 210°
In the circle below, if arc AB = 48 °, and arc CD = 122 °, find the measure of < CPD.
SOLUTIONS
In the circle below, if arc AB = 48°, and arc CD = 122°, find the measure of < CPD.
[tex]\begin{gathered}Therefore the measure of angle CPD = 85 degree
Hence the correct answer = Option C
Rational Expression and EquationsClassify each equation as direct inverse or joint variation then state the constant of variation
2. Given:
[tex]y=7z[/tex]To classify the equation as direct, inverse or joint variation then state the constant of variation:
It is of the form,
[tex]y=kz,\text{ whe}re\text{ }k\text{ is the constant}[/tex]If y increases then z increases and if y decreases then z decreases.
Therefore, it is direct variation.
We know that the ratio between two variables in a direct variation is a constant of variation.
Thus, the constant of variation is k = 7.
I’m not quite sure on why I’m not getting the correct solution. Please help!The questions are A) what is the initial value of Q, when t = 0? What is the continuous decay rate? B) Use the graph to estimate the value of t when Q = 2 C) Use logs to find the exact value of t when Q = 2
The given exponential function is
[tex]Q=11e^{-0.13t}[/tex]The form of the exponential continuous function is
[tex]y=ae^{rt}[/tex]a is the initial amount (value y at t = 0)
r is the rate of growth/decay in decimal
Compare the given function by the form
[tex]a=11[/tex][tex]\begin{gathered} r=0.13\rightarrow decay \\ r=0.13\times100\text{ \%} \\ r=13\text{ \%} \end{gathered}[/tex]a)
The value of Q at t = 0 is 11 and the decay rate is 13%
The initial value of Q is 11
The continuous decay rate is 13%
From the graph
To find the value of t when Q = 2
Look at the vertical axis Q and go to the scale of 2
Move horizontally from 2 until you cut the graph
Go down to read the value of t
The value of t is about 13
b)
At
Q = 2
t = 13
c)
Now, we will substitute Q in the function by 2
[tex]2=11e^{-0.13t}[/tex]Divide both sides by 11
[tex]\frac{2}{11}=e^{-0.13t}[/tex]Insert ln on both sides
[tex]ln(\frac{2}{11})=lne^{-0.13t}[/tex]Use the rule
[tex]lne^n=n[/tex][tex]lne^{-0.13t}=-0.13t[/tex]Substitute it in the equation
[tex]ln(\frac{2}{11})=-0.13t[/tex]Divide both sides by -0.13
[tex]\begin{gathered} \frac{ln(\frac{2}{11})}{-0.13}=t \\ \\ 13.11344686=t \end{gathered}[/tex]At
Q = 2
t = 13.11344686
A parabola has a vertex at (2, -1) and a y- intercept at (0,3). Is this enough information to sketch a graph? Explain your answer. Henny Yoffe . 11:20 AM
It is given that the parabola has the vertex at (2,-1)and y intercept of 3,
Consider the general equation of the parabola with vertex (p,q),
[tex]y=a(x-p)^2+q[/tex]Sbstitute 2 for 'p' and -1 for 'q',
[tex]y=a(x-2)^2-1[/tex]Given that the y-intercept is 3, it means that the curve passess through (0,3),
So it must satisfy the equation,
[tex]3=a(0-2)^2-1\Rightarrow4a=4\Rightarrow a=1[/tex]Substitute the value of 'a', 'p', and 'q' in the standard equation,
[tex]y=1(x-2)^2-1\Rightarrow y=(x-2)^2-1[/tex]Thus, the equation of the parabola can be obtained using the given conditions.
A catapult is malfunctioning and not throwing objects in the intended manner. The builders have modeled the path of the objects thrown by using thefollowing parametric equations. Rewrite the parametric equations by eliminating the parameter.
Solution
Given
[tex]\begin{gathered} x(t)=2t-1 \\ \\ y(t)=\sqrt{t}\Rightarrow y^2=t \\ \\ \Rightarrow x=2y^2-1 \end{gathered}[/tex]Hence, the correct option is D
determine the degree of the polynomial -56a^2y^3+23a^2y-29a+17
The degree a polynomial is determine by the highest highest power of variable in the equation.
However, for a multivariable polynomial, the degree is the highest sum of powers of different variables in any of the terms in the expression.
For this polynomial,
[tex]-56a^2y^3+23a^2y\text{ - 29a + 17}[/tex]The degree of polynomial is 5 at the term -56^2y^3 which has 2 and 3 exponent at variable a and y respectively.
I’m just starting writing these and I don’t understand it much
In geometry, formal definitions are formed using other defined words or terms. There are, however, three words in geometry that are not formally defined. These words are point, line, and plane, and are referred to as the "three undefined terms of geometry".
a. Defined terms can be combined with each other and with undefined terms to define still more terms. An angle, for example, is a combination of two different rays or line segments that share a single endpoint. Similarly, a triangle is composed of three noncollinear points and the line segments that lie between them.
b. Undefined terms can be combined to define other terms. Noncollinear points, for example, are points that do not lie on the same line. A line segment is the portion of a line that includes two particular points and all points that lie between them, while a ray is the portion of a line that includes a particular point, called the endpoint, and all points extending infinitely to one side of the endpoint.
Enter your searchrmFind the compound interest and future value. Do not round intermediate steps. Round your answers to the nearest cent.Principal Rate Compounded Time$895Annually11 years2%The future value is $, and the compound interest is $ХS
Given:
Principal, P = $895
Time, t = 11 years
Rate, r = 2% compounded annually.
Let's find the compound interest and the future value.
To find the future value apply the formula:
[tex]A=P(1+r)^t[/tex]Where:
A is the future amount.
P is the principal = 895
r is the rate = 2% = 0.02
t is the time in years = 11
Hence, we have:
[tex]\begin{gathered} A=895(1+0.02)^{11} \\ \\ A=895(1.02)^{11} \\ \\ A=895(1.2433743) \\ \\ A=1112.82 \end{gathered}[/tex]Therefore, the future value is $1112.82
To find the compound interest, substitute the principlal (P) from the future value (A).
Compound interest = $1112.82 - $895
= $217.82
The compound interest is $217.82
A
slope = 2/5; y-intercept = -7
We want to find the equation of the line with given slope and y-intercept.
The slope-intercept form of a line is:
[tex]y=mx+b[/tex]Where
m is the slope
b is the y-intercept (y-axis cutting point)
We are given the slope and y-intercept, so we simply substitute it. Steps are shown below:
[tex]\begin{gathered} y=mx+b \\ y=\frac{2}{5}x+(-7) \\ y=\frac{2}{5}x-7 \end{gathered}[/tex]The equation of the line is:
[tex]y=\frac{2}{5}x-7[/tex]The graph of a function g is shown below.Find g (0) and find one value of x for which g(x) = 4,
From the graph provided,
a) For g(0), on the graph,
[tex]g(0)=-2[/tex]b) One value of x for which g(x) = 4 is given below as,
[tex]\begin{gathered} g(x)=4 \\ x=3\text{ where g(x) = 4} \end{gathered}[/tex]Hence, g(0) = -2 and one of the value of x for which g(x) = 4 is 3
An empty shipping box weighs 250 grams. The box is then filled with t-shirts. Each tshirts weighs 132.5 grams. The equation W = 250 + 132.5T represents the relationship between the quantities in this solution where W is the weight in grams of the filled box and T the number of shirts in the box. Consider this equation 2900 = 250 + 132.5T. What does the solution to this equation tell us?
Given the next equation
2900 = 250 + 132.5T
its solution is:
2900 - 250 = 132.5T
2650 = 132.5T
2650/132.5 = T
T = 20
Given that W is weigth and T is t-shirts, the solution tell us that a box with 20 t-shirts weights 2900 grams
You would like to make Chili, Tacos and Grilled Cheese this week. The grocery store prices and ingredients for the meals are listed above. One of each item will be enough to cover all recipes, except you will need two packages of cheese to make all three recipes. How much will you spend on groceries?
Answer:
i dont get it
Step-by-step explanation:
If ABCD is dilated by a factor of 3, thecoordinate of D' would be:4C3B21-5 -4 -3-2 -1 012345DA-1-2D-3D' = ([?],[ ]
Answer:
(6, -6)
Explanation:
The coordinate of D is the figure = (2, -2)
If ABCD is dilated by a factor of 3, then:
[tex]\begin{gathered} D(2,-2)\to D^{\prime}(2\times3,-2\times3) \\ =(6,-6) \end{gathered}[/tex]The coordinate of D' would be (6, -6).
Write an equation in general form of the circle with the given properties. Ends of diameter at (5,7) and (-5,-7) ?
Write an equation in general form of the circle with the given properties.
Ends of diameter at (5,7) and (-5,-7)
we have that
the equation of the circle is
(x-h)^2+(y-k)^2=r^2
where (h,k) is the center and r is the radius
step 1
Find the center
Remember that
The center of the circle is the midpoint of diameter
so
[tex]\begin{gathered} (h,k)=(\frac{5-5}{2},\frac{7-7}{2}) \\ (h,k)=(0,0) \end{gathered}[/tex]the center is the origin
step 2
Find the radius
Find the diameter
calculate the distance between two points
[tex]\begin{gathered} d=\sqrt[\square]{(-7-7)^2+(-5-5)^2} \\ d=\sqrt[\square]{(-14)^2+(-10)^2} \\ d=\sqrt[\square]{296} \end{gathered}[/tex]simplify
[tex]D=\sqrt[\square]{296}=2\sqrt[\square]{74}[/tex]the radius is half the diameter
so
r=2√74/2=√74
step 3
the equation iof the circle is
x^2+y^2=(√74)^2
x^2+y^2=74Help Please, I don’t understand and it’s really confusing me
We have this expression:
[tex]\frac{15}{y}[/tex]Let's substitute y = 1/4 into this expression.
[tex]\frac{15}{\frac{1}{4}}[/tex]Multiply the top and bottom by 4/1 in order to get rid of the double fractions.
[tex]15(\frac{4}{1})=60[/tex]The answer to this problem is C) 60.
John wishes to build a square fence with an area of 121 square yards. What is the perimeter of the fence in yards.
Solution:
Given that John wishes to build a square fence with an area of 121 square yards, as shown below:
The area of a square is expressed as
[tex]\begin{gathered} Area\text{ of square = L}^2 \\ where \\ L\Rightarrow length\text{ of a side of the square} \end{gathered}[/tex]Given that the area of the square fence is 121 square yards, this implies that
[tex]\begin{gathered} 121=L^2 \\ take\text{ the square root of both sides,} \\ \sqrt{121\text{ }}\text{ =}\sqrt{L^2} \\ \sqrt{11\times11}\text{ =}\sqrt{L\times L} \\ \Rightarrow L=11\text{ yards} \end{gathered}[/tex]The perimeter of a square is expressed as
[tex]\begin{gathered} Perimeter\text{ of square = 4}\times L \\ where \\ L\Rightarrow length\text{ of a side of the square} \end{gathered}[/tex]Thus, the perimeter of the fence is evaluated by substituting the value of 11 for L into the perimeter formula.
[tex]\begin{gathered} Perimeter\text{ of fence = 4}\times11 \\ \Rightarrow Perimeter\text{ of fence = 44 yards} \end{gathered}[/tex]Hence, the perimeter of the fence is 44 yards.
Functions > 1.02 Function families and transformations How do we shift the graph of y = f(x) to get the graph of y = f(x) + 2?
y = f(x)
to
y = f(x) + 2
Move up the graph by 2 units along the y- axis. (vertical translation)
Assume that (a,b) is a point on the graph of f. What is the corresponding point on the graph of the following function?f(x-25)What is the point on the graph of f(x-25) that corresponds to the point (a,b) on the graph of f?
Given
There exist a point (a, b) on the original function f(x).
Two points are corresponding if they appear in the same place in two similar situations.
The new function f(x-25) is a function shifted right by 25 units.
Hence, the point on the graph of f(x-25) that corresponds to the point (a, b) on the graph of f is:
[tex](a+25,\text{ b)}[/tex]
Directions: Drag each tile to the correct box.Put the recursive formulas below in order from least to greatest according to the value of their 10th terms.For all of the formulas, let n be equal to the whole numbers greater than or equal to one.
Solving for the 10th term for each of the recursive sequence
First sequence
[tex]\begin{gathered} a_1=32 \\ a_{n+1}=-5+a_n \\ \\ \text{This can be converted to} \\ a_n=a_1+(n-1)(-5) \\ \\ \text{Substitute }n=10 \\ a_{10}=32+(10-1)(-5) \\ a_{10}=32+(9)(-5) \\ a_{10}=32-45 \\ a_{10}=-13 \end{gathered}[/tex]Second sequence
[tex]\begin{gathered} a_1=2048 \\ a_{n+1}=-\frac{1}{2}a_n \\ \\ \text{This can be converted to} \\ a_n=a_1\cdot\Big(-\frac{1}{2}\Big)^{n-1} \\ \\ \text{Substitute }n=10 \\ a_{10}=2048\cdot\Big(-\frac{1}{2}\Big)^{10-1} \\ a_{10}=2048\cdot\Big(-\frac{1}{2}\Big)^9 \\ a_{10}=-4 \end{gathered}[/tex]Third sequence
[tex]\begin{gathered} a_1=0.125 \\ a_{n+1}=2a_n \\ \\ \text{This can be converted to} \\ a_n=a_1\cdot2^{n-1} \\ \\ \text{Substitute }n=10 \\ a_{10}=0.125\cdot2^{10-1} \\ a_{10}=0.125\cdot2^9 \\ a_{10}=64 \end{gathered}[/tex]Fourth sequence
[tex]\begin{gathered} a_1=-7\frac{2}{3} \\ a_{n+1}=a_n+1\frac{2}{3} \\ \\ \text{This can be converted to} \\ a_n=a_1+(n-1)\Big(1\frac{2}{3}\Big) \\ \\ \text{Substitute }n=10 \\ a_{10}=-7\frac{2}{3}+(10-1)\Big(1\frac{2}{3}\Big) \\ a_{10}=\frac{-23}{3}+(9)\Big(\frac{5}{3}\Big) \\ a_{10}=-\frac{23}{3}+\frac{45}{3} \\ a_{10}=\frac{22}{3} \\ a_{10}=7\frac{1}{3} \end{gathered}[/tex]Arranging the formulas from least to greatest according to their 10th terms, we have the following:
First Sequence → Second Sequence → Fourth Sequence → Third Sequence
Please see attached photo for question
For the function g(x), the graph is shown and the domain of that function is set of all integer numbers.
Domain of a function is all possible input values for that function.
Here, the domain of g(x) is set of all integers numbers
The x intercept of g(x)
The x intercept is when the value of y is zero, analysing the graph the x intercept can be interpreted as -5 and 1
The y intercept is when the value of x is zero, analysing the graph the y intercept can be interpreted as 1
From the graph,
g(4) is 1
Therefore, For the function g(x), the graph is shown and the domain of that function is set of all integer numbers.
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How can I get the volume in cubic centimetres of one large cereal box? How do I calculate the total surface of a cereal box? How do I calculate the volume of the cereal box? If the height of a small box is 20cm, list two different Pairs of values which the company can use for the length and width of a small box?
The volume of the cereal box is 7200 cm³ and the surface area of the cereal box is 2776 cm².
The dimensions of the cereal box are given as:
Length = 25 cm
Width = 8 cm
Height = 36 cm
The volume of the cereal box is:
Volume = l × b × h
V = 25 cm × 8 cm × 36 cm
V = 7200 cm³
The surface area of the cereal box is:
Surface area = 2 l b + 2 b h + 2 h l
S = 2 (25) (8) + 2 (8) (36) + 2 (36) (25)
S = 400 + 576 + 1800
S = 2776 cm²
Therefore, we get that, the volume of the cereal box is 7200 cm³ and the surface area of the cereal box is 2776 cm².
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Lin family has completed 70% of a trip. They have traveled 35 miles. How far is the trip?A. 24.5 milesB. 50 milesC. 59.5 milesD. 200 miles
The given information is:
The family have traveled 35 miles and it represents the 70% of the trip.
To find how far is the trip we need to divide the 35 miles by the percentage that it represents:
[tex]35\text{miles}\cdot\frac{100\%}{75\%}=50miles[/tex]Thus, the trip is 50 miles.
Answer: B.
Lisa is saving $50 that she received from her grandmother. She earns $6 each time she walks her neighbor's dog, which she also saves. Which function can be used to find f, the amount of money Lisa will have saved after walking the neighbor's dog d times?
Let
f ------> the amount of money Lisa will have saved
d -----> number of times that she walking the neighbor's dog
so
Remember that
The linear equation in slope intercet form is equal to
f=md+b
where
m is the unit rate or slope
b is the y-intercept or initial value
in this problem we have
m=6
b=50
therefore
substitute
f=6d+50
answer is last one option
Solve the right triangle ABC for all missing parts. Express all angles in decimal degrees. a= 306.5 km, c=591.3 km(Round to the nearest hundredth as needed)
Explanation
Step 1
we have a rigth triangle, then
let
[tex]\begin{gathered} side_1=306.5 \\ side_2=b \\ \text{hypotenuse}=591.3 \end{gathered}[/tex]to find the missing side we an use the Pythagorean theorem. it states that the sum of the squares on the legs of a right triangle is equal to the square on the hypotenuse (the side opposite the right angle)
so
[tex]\begin{gathered} side^2+side^2=hypotenuse^2 \\ \text{replace} \\ 306.5^2+b^2=591.3^2 \\ \text{subtract }306.5^2i\text{n both sides} \\ 306.5^2+b^2-306.5^2=591.3^2-306.5^2 \\ b^2=591.3^2-306.5^2 \\ b=\sqrt[]{591.3^2-306.5^2} \\ b=\sqrt[]{255693.44} \\ b=505.66\text{ km} \end{gathered}[/tex]hence
b=505.66 km
Step 2
angles
a)A
[tex]\begin{gathered} \sin \text{ }\alpha=\frac{opposi\text{te side}}{\text{hypotenuse}} \\ \text{replace} \\ \sin \text{ A=}\frac{a}{c}=\frac{360.5\text{ }}{591.3} \\ A=\sin ^{-1}(\frac{360.5\text{ }}{591.3}) \\ A=37.56\~ \end{gathered}[/tex]and B
[tex]\begin{gathered} \sin \text{ B=}\frac{b}{c} \\ B=\sin ^{-1}(\frac{505.66}{591.3}) \\ B=58.77\text{ \degree} \end{gathered}[/tex]I hope this helps you
Um Im in fith grade and i need help with some of my math questions if your able to help me with five or 10 questions that will be great
Solution
For this case we can do the following:
Then the solution would be:
21 6/24 = 21 1/4
For this case we can do the following for 21 1/4
[tex]21\cdot\frac{1}{4}=\frac{21\cdot4+1}{4}=\frac{85}{4}[/tex]For the second part we can do this:
[tex]\frac{1}{3}\cdot5=\frac{5}{3}[/tex]Then the answer is 5/3