Answers
Step 1:
Write the function
[tex]g(x)=x^5-16x^3[/tex]Step 2:
Write an inequality equation where g(x) > 0
[tex]\begin{gathered} x^5-16x^3\text{ > 0} \\ \text{Factorize the left hand side of the equation} \\ x^3(x^2\text{ - 16) > 0} \\ x^3(x\text{ - 4)(x + 4) > 0} \end{gathered}[/tex]Step 3:
Identify the intervals
- 4 < x < 0 or x > 4
[tex]\text{Answer in interval notation: }(\text{ - 4 , 0 ) }\cup\text{ ( 4 , }\infty\text{ )}[/tex]Related Questions
nQuestion 6Mutiple Choice Worth 1 points)(06.04 MC)The length of a rectangle is represented by the function L(x)= 2x. The width of that same rectangle is represented by the function W(x)=8x²-4x+1. Which of the following shows the area of the rectangle interms of x?(L+ W)(x)=8x²-2x+1(L + W)(x)=8x² - 6x +1(L• W)(x)=16x-4x+1(L • W)(x)=16x³-8x²+2x
Answers
Answer:
[tex]D\text{ :}(L\text{ }\circ\text{ W\rparen\lparen x\rparen= 16x}^3-8x^2+2x[/tex]Explanation:
Here, we want to select the option that best represents the area of the rectangle in terms of x
Mathematically, the area can be calculated by:
[tex]A(x)\text{ = L\lparen x\rparen }\times\text{ W\lparen x\rparen}[/tex]We have that as:
[tex]\begin{gathered} 2x\text{ }\times\text{ 8x}^2-4x+1 \\ =\text{ 2x\lparen8x}^2-4x+1) \\ =\text{ 16x}^3-8x^2+2x \end{gathered}[/tex]Is a tutor availible?
Answers
this is a conversion problem
First you must understand that 1 foot = 12inches
Given a ribbon that is 5 1/2 feet long
To convert to inches, you will simply multiply 5 1/2 by 12 as shown;
= 5 1/2 * 12
convert the mixed fraction to improper fraction
= 11/2 * 12
= 11 * 12/2
= 11 * 6
= 66 inches
Hence the ribbon is 66 inches long
The product of a number and 5 is always greater than 15.Which of the following shows this inequality?
Answers
Let x be the unkown number.
The product of a number and 5: multiplication of x and 5 (5x)
Is always greater than 15: >15
Inequality:
[tex]5x>15[/tex]Another form of write the inequality is soving x:
[tex]\begin{gathered} \frac{5}{5}x>\frac{15}{5} \\ \\ x>3 \end{gathered}[/tex]Posible Inequalities: 5x>15x>3n a 45 minute basketball game, 30 girls want to play. Only 10 can play at once. If each player is to play the same length of time, how many minutes should each play?
Answers
A 45 minute basketball game, 30 girls want to play. Only 10 can play at once. If each player is to play the same length of time. 15 minutes should each play
10/30=1/3
[tex]\frac{1}{3} \times 45$$[/tex]
Convert element to fraction: [tex]$\quad 45=\frac{45}{1}$[/tex]
[tex]=\frac{1}{3} \times \frac{45}{1}$$[/tex]
Apply the fraction rule:[tex]$\frac{a}{b} \times \frac{c}{d}=\frac{a \times c}{b \times d}$[/tex]
[tex]=\frac{1 \times 45}{3 \times 1}$$[/tex]
[tex]$\frac{1 \times 45}{3 \times 1}=\frac{45}{3}$[/tex]
[tex]=\frac{45}{3}[/tex]
Divide the numbers: [tex]$\frac{45}{3}=15$[/tex]
=15
15 minutes for 3 groups of 10 each to play basketball.
To add or subtract fractions, the denominator must be the same (the bottom value). Subtraction and addition with the same denominators If the denominators are already the same, all that remains is to add or subtract the numerators (the top value).
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11. The volume of a pyramid is equal to1the product of the altitude and the area of the base. If the area of the base3remains the same and the altitude is doubled, the volume Please help
Answers
Answer:
Double
Explanation:
[tex]\text{Volume of a Pyramid=}\frac{1}{3}\times Base\text{ Area}\times Altitude[/tex]If the area of the base remains the same and the altitude is doubled, we have:
[tex]\begin{gathered} New\; Volume=\frac{1}{3}\times\text{Base Area}\times(2\times Altitude) \\ =2\times(\frac{1}{3}\times\text{Base Area}\times Altitude) \\ =2\times\text{Old Volume} \end{gathered}[/tex]Thus, if the area of the base remains the same and the altitude is doubled, the volume will double,
Solve the following system of linear equations.x + 3y + z = - 42x – 4y – 3z = 73x – 3y + 4z = 13AnswerBH」KeyboardX =y =z =
Answers
Given
Solve the following system of linear equations.
x + 3y + z = - 4
2x – 4y – 3z = 7
3x – 3y + 4z = 13
Solution
[tex]\begin{bmatrix}x+3y+z=-4 \\ 2x-4y-3z=7 \\ 3x-3y+4z=13\end{bmatrix}[/tex]Substitute x= -4-3y-z
[tex]\begin{bmatrix}2\mleft(-4-3y-z\mright)-4y-3z=7 \\ 3\mleft(-4-3y-z\mright)-3y+4z=13\end{bmatrix}[/tex]Simplify
[tex]\begin{bmatrix}-10y-5z-8=7 \\ -12y+z-12=13\end{bmatrix}[/tex]Make y the subject
[tex]\begin{gathered} -10y-5z-8=7 \\ -10y\text{ -5z=7+8} \\ -10y-5z=15 \\ \text{divide all through by 5} \\ -2y-z=3 \\ y=-\frac{z+3}{2} \end{gathered}[/tex]Now substitute
[tex]\begin{bmatrix}-12\mleft(-\frac{z+3}{2}\mright)+z-12=13\end{bmatrix}[/tex]Simplify
[tex]\begin{gathered} \\ \begin{bmatrix}7z+6=13\end{bmatrix} \\ \text{Make z the subject} \\ 7z=13-6 \\ 7z=7 \\ \text{divide both sides by 7} \\ \frac{7z}{7}=\frac{7}{7} \\ z=1 \end{gathered}[/tex]Now substitute z=1
[tex]\begin{gathered} y=-\frac{z+3}{2} \\ y=-\frac{1+3}{2}=-\frac{4}{2}=-2 \end{gathered}[/tex]Finally, to find x
when z =1 and y =-2
[tex]\begin{gathered} x+3y+z=-4 \\ x+3(-2)+1=-4 \\ x-6+1=-4 \\ \text{collect the like terms} \\ x-5=-4 \\ x=-4+5 \\ x=1 \end{gathered}[/tex]The final answer
[tex]\begin{gathered} x=1 \\ y=-2 \\ z=1 \end{gathered}[/tex]Use the quadratic formula to solve for X. 3x^2 = -3x +7
Answers
The solutions are:
x = -2.11 or 1.11
Explanation:Given the equation:
[tex]3x^2=-3x+7[/tex]This can be written as:
[tex]3x^2+3x-7=0[/tex]Comparing this with the general equation;
[tex]ax^2+bx+c=0[/tex]We see that;
[tex]\begin{gathered} a=3 \\ b=3 \\ c=-7 \end{gathered}[/tex]The quadratic formula is:
[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]Substitute the values of a, b, and c
[tex]\begin{gathered} x=\frac{-3\pm\sqrt[]{3^2-4\times3\times(-7)}_{}}{2\times3} \\ \\ =\frac{-3\pm\sqrt[]{9+84}}{6} \\ \\ =\frac{-3\pm\sqrt[]{93}}{6} \\ \\ =\frac{-3\pm9.64}{6} \\ \\ x=\frac{-3+9.64}{6}=1.11 \\ \\ OR \\ x=\frac{-3-9.64}{6}=-2.11 \end{gathered}[/tex]A resident is to receive 2 ounces of liquid . You know 30 ccs equals one ounce . How many ccs of the liquid will you give to ensure the resident receives 2 ounces
Answers
From the statement of the question, we know that 1 ounce and 30ccs are equivalent, we represent that with the following equation:
[tex]1\text{ounce}=30\text{ccs.}[/tex]Now, 2 ounces is double of 1 ounce, because 1 ounce is 30 ccs, 2 ounces must be 60ccs, the double of 30ccs.
[tex]2\text{ounces}=2\cdot1\text{ounce}=2\cdot30\text{ccs}=60\text{ccs.}[/tex]So if we want to ensure that the resident will receive 2 ounces of liquid, we must give him 60ccs.
Answer: we must give him 60ccs of liquid.
Which of the following equations is equivalent to the given equation?
Answers
Answer:
[tex]\begin{equation*} 5(7a+5)-80=4(3a+15) \end{equation*}[/tex]Explanation:
Given the equation:
[tex]\frac{7a+5}{8}-2=\frac{3a+15}{10}[/tex]First, find the lowest common multiple of the denominators 8 and 10.
• The LCM of 8 and 10 = 40
Then, multiply all through by 40:
[tex]\begin{gathered} \frac{40(7a+5)}{8}-2(40)=\frac{40(3a+15)}{10} \\ \implies5(7a+5)-80=4(3a+15) \end{gathered}[/tex]The third option is equivalent.
Answer:
5(7a + 5) - 80 = 4(3a + 15)
Step-by-step explanation:
Find the inverse of 1/4x^3+2x-1=y
Answers
210000The first five multiples for the numbers 4 and 6 are shown below.Multiples of 4: 4, 8, 12, 16, 20, ...Multiples of 6: 6, 12, 18, 24, 30,...What is the least common multiple of 4 and 6?222122423 24 25Mark this and returnSave and ExitNext
Answers
Answer: 12
Explanation
The least common multiple can be calculated by getting the factor of each number. As we are told, the multiples of 4 are 4, 8, 12, 16, 20, ..., and the multiples of 6 are 6, 12, 18, 24, 30, ....
Thus, the lowest factor that they share is 12.
a store advertises a 20% markdown on a dishwasher that normally sells for $952. what is the price on sale
Answers
The price on sale of the dishwasher is $201.6
How to determine the price on sale?From the question, we have the following parameters that can be used in our computation:
Mardown = 20%
Selling price = $252
The price on sale of the dishwasher is calculated using the following equation
Price on sale = Selling price * (1 - Mardown)
Substitute the known values in the above equation, so, we have the following representation
Price on sale = 252 * (1 - 20%)
Evaluate
Price on sale = 201.6
Hence, the price is $201.6
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if I need 1/2 cup of oil but I only have 1/3 cup of oil how much oil do I need
Answers
We need 1/2 cup of oil and we are told that we already have 1/3 cup of oil, to find out how much we need we subtract this and the result will be the amount of oil we need.
[tex]\frac{1}{2}-\frac{1}{3}=\frac{3-2}{6}=\frac{1}{6}[/tex]In conclusion, the answer is 1/3 cup of oil
a parking lot is distracted in the shape of a parallelogram if the base is 200 feet the height is 120 ft and the Dialganal with is 140 feet what is the area of the parking lot?
Answers
a parking lot is distracted in the shape of a parallelogram if the base is 200 feet the height is 120 ft and the Dialganal with is 140 feet what is the area of the parking lot?
we know that
the area of parallelogram is equal to
A=b*h
where
b is the base
h is the height
substitute the given values
A=200*(120)
A=24,000 ft^2
the area is 24,000 square feetThe length of a side of a square is (2x + 1) km. Find the area of thesquare in terms of the variable x
Answers
The area of the square is given by:
[tex]A=s^2[/tex]Where s is the length of the side. Then s=(2x+1) km.
By replacing this into the formula we have:
[tex]A=(2x+1)^2[/tex]Also, the square of a sum is given by:
[tex](a+b)^2=a^2+2ab+b^2[/tex]If a=2x and b=1, then:
[tex]\begin{gathered} (2x+1)^2=(2x)^2+2(2x)(1)+(1)^2 \\ (2x+1)^2=4x^2+4x+1 \end{gathered}[/tex]Thus, the area of the square in terms of the variable x is:
[tex]A=4x^2+4x+1[/tex]If you receive 360 promotional emails per month and only 2.5% percent of those emails are of interest to you, what is the expected number of promotional emails that will be of interest to you each month?
Answers
Total email 360
percentage email of interest 2.5%
Solution[tex]\begin{gathered} \frac{2.5}{100}\times360=9 \\ \end{gathered}[/tex]The final answer9 promotional emails that will be of interest to you each monthneed help with example #4 Find all missing angles and sides.
Answers
We will use the law of sines and law of cosines shown below
[tex]\begin{gathered} c=\sqrt{a^2+b^2-2ab\cos C}\rightarrow\text{ law of cosines} \\ and \\ \frac{sinA}{a}=\frac{sinB}{b}=\frac{sinC}{c}\rightarrow\text{ law of sines} \end{gathered}[/tex]Therefore, in our case, finding side c.,
[tex]\begin{gathered} a=28,b=13,C=49\degree \\ \Rightarrow c=\sqrt{784+169-2*28*13cos(49\degree)} \\ \Rightarrow c\approx21.8 \end{gathered}[/tex]Thus, side c is approximately 21.8km.
Finding the missing angles using the law of sines,
[tex]\begin{gathered} A=\cos^{-1}(\frac{c^2+b^2-a^2}{2bc}) \\ \Rightarrow A=\cos^{-1}(\frac{21.8^2+13^2-28^2}{2*13*21.8}) \\ \Rightarrow A\approx104.3 \\ \end{gathered}[/tex]Similarly, in the case of angle B,
[tex]sinB=\frac{13}{21.8}sin(49\degree)\approx26.7\degree[/tex]Therefore, the answers are
c=21.8km,
Team A, B, and C are competing in a basketball tournament. The probability of team A winning is 0.2, the probability of team B winning is 0.45, and the probability of team C winning is 0.35. Anna can join either team A or team B. Elina can join either team B or team C. Nancy can join either team A or team C. Who is most likely to win?AnnaNancyElenaAll have an equal probability to win.
Answers
Solution
We are given that
[tex]\begin{gathered} p(A)=0.2 \\ p(B)=0.45 \\ p(C)=0.35 \end{gathered}[/tex]Note 1: Probability Formula To use
[tex]p(A\cup B)=p(A)+p(B)-p(A\cap B)[/tex]Note 2: Team A, B and C are Mutually Exclusive
[tex]\begin{gathered} p(A)+p(B)+p(C)=0.2+0.45+0.35=1 \\ Th\text{ey are mutually exclusive} \\ A\cap B=B\cap C=A\cap C=\varnothing \\ p(A\cap B)=p(B\cap C)=p(A\cap C)=0 \end{gathered}[/tex]Therefore, the formula to use now is
[tex]p(A\cup B)=p(A)+p(B)[/tex]For Anna
Anna can join either team A or team B.
We calculate the probability
[tex]\begin{gathered} p(A\cup B)=p(A)+p(B) \\ p(A\cup B)=0.2+0.45 \\ p(A\cup B)=0.65 \end{gathered}[/tex]For Elina
Elina can join either team B or team C.
We calculate the probability
[tex]\begin{gathered} p(B\cup C)=p(B)+p(C) \\ p(B\cup C)=0.45+0.35 \\ p(B\cup C)=0.8 \end{gathered}[/tex]For Nancy
Nancy can join either team A or team C.
We calculate the probability
[tex]\begin{gathered} p(A\cup C)=p(A)+p(C) \\ p(A\cup C)=0.2+0.35 \\ p(A\cup C)=0.55 \end{gathered}[/tex]The one with the highest probability is most likely to win and that is
ELINA
Correct answer is Elina
Solve: Tom is building a barn 36 feet wide and 60 feet long. How many feet long will the diagonal be across the footer if the footer is square?
Answers
Solution
For this case we can do the following:
Then we can use the Pythagoras theorem and we can solve for d and we got:
[tex]d=\sqrt[]{60^2+36^2}=\sqrt[]{4896}=69.97[/tex]Then the answer would be:
69.97 ft
If pp is inversely proportional to the square of qq, and pp is 22 when qq is 8, determine pp when qq is equal to 4.
Answers
Given that p is inversely proportional to the square of q that implies:
[tex]p\propto\frac{1}{q^2}[/tex]Remove the sign of proportionality and put a proportionality constant k such that:
[tex]p=\frac{k}{q^2}[/tex]Given that when q is 8 then p is 22. So,
[tex]22=\frac{k}{8^2}\Rightarrow k=22\times64=1408[/tex]Put k = 1408 and q = 4 in the equation to find the value of p:
[tex]p=\frac{1408}{4^2}=\frac{1408}{16}=88[/tex]Thus, the answer is 88.
Use the sum and difference identities to rewrite the following expression as a trigonometric function of asingle number.sin(15°)cos(135) + cos(159) sin(135)
Answers
The value of the given trigonometric function is [tex]\sqrt{3} +1[/tex]
The given trigonometric function is sin(15°)cos(135) + cos(15) sin(135).
Evaluating the expression with the sum and difference identities.
We know, SinACosB + CosASinB = Sin(A +B)
Now, We have :
sin(15°)cos(135) + cos(15) sin(135) = Sin ( 15 +135 ) = Sin150
Now, Sin 150 = Sin(120 +30) = Sin120Cos30 + Cos120Sin30
Sin 150 =
[tex]=\frac{\sqrt{3} }{2} * \frac{\sqrt{3} }{2} + \frac{1}{2}*\frac{1}{2} = \frac{2\sqrt{3} }{2} +\frac{2}{2} \\\\= \sqrt{3} +1[/tex]
Hence, the value of the given trigonometric function is [tex]\sqrt{3} +1[/tex]
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Triangle ACD is dilated about the origin.10D'984DC'с-7-8-5-4-3-234-1-2Which is most likely the scale factor?O3O223
Answers
ACD has a base (AC) with a length of 3 units.
A'C'D' has a base (A'C') with a length of 9 units.
Therefore, the scale factor is 9/3 = 3.
-ExerciseActivity 1Please see the image above & use table NOTE: HELP ME ASAP
Answers
Given:
Required:
To complete the table.
Explanation:
[tex]\begin{gathered} 1\text{ pinch = }\frac{1}{16}\text{ teaspoon} \\ 2pinch\text{ = }\frac{2}{16\text{ }}tps \\ 2p\imaginaryI nch=\frac{1}{8}\text{ tps} \end{gathered}[/tex][tex]\begin{gathered} 1\text{ teaspoon = 76.0012} \\ 3\text{ teaspoons = 1 tablespoon} \end{gathered}[/tex]Since
[tex]\begin{gathered} 16\text{ tablespoon = 1 cup} \\ \end{gathered}[/tex]Divide by 8 into both sides.
[tex]\begin{gathered} 2\text{ tablespoon = }\frac{1}{8}\text{ cup} \\ 4\text{ tablespoon=}\frac{\text{1}}{4}\text{{\text{cup}}} \end{gathered}[/tex][tex]\begin{gathered} 16\text{ tablespoon = 1 cup} \\ 8\text{ tablespoon=}\frac{1}{2}\text{cup} \end{gathered}[/tex][tex]\begin{gathered} 2\text{ cups = 1 pint} \\ 4\text{ cups = 2 pint} \end{gathered}[/tex][tex]4\text{ quarts = 1 gallon}[/tex]Final Answer:
Explain in explanation parts.
5. List all of the factors of 24.O1, 2, 4, 6, 8, 121,2,3,4,61, 2, 3, 4, 6, 8, 12, 2424, 48, 72, 96, 192I need to learn this.
Answers
To find the factors of a number we must find all the numbers that divide 24, two numbers are always easy, 1 and the number itself! But how do we find the others? We start at 1 and divide the number (here it's 24) by all the possible numbers until we reach the number we are finding the factor, it the division is an integer number, then it's a factor!
Another thing may help us! if we divide a number, for example, 24 by 2, the result is 12. Then 2 is a factor of 24 but 12 is also a factor of 24! Then when we find one factor, in fact, we have 2 factors. Now let's apply it to our problem:
As we can see, just by 3 divisors we found all the factors of 24! They are 1, 2, 3, 4, 6, 8, 12, 24
Final answers: 1, 2, 3, 4, 6, 8, 12, 24
graph the quadrilateral with the given vertices in a coordinate plane. then show the quadrilateral in a a parallelogram
Answers
First, let's graph the polygon:
Now, let's prove it's a parallelogram by showing that the segments NP and RQ are parallel, and NR and PQ are parallel as well.
Let's prove that the angular coefficient is the same for NR and PQ
[tex]\begin{gathered} m_{NR}=\frac{0-(-4)}{-5-(-3)}=-\frac{4}{3} \\ \\ m_{PQ}=\frac{5-0}{0-3}=-\frac{4}{3} \end{gathered}[/tex]Then they're parallel, just to confirm, let's do the same for NP and RQ
[tex]\begin{gathered} m_{NP}=\frac{4-0}{0-(-5)}=\frac{4}{5} \\ \\ m_{RQ}=\frac{-4-0}{-2-(3)}=\frac{4}{5} \end{gathered}[/tex]Then it's parallel as well.
lebron walked 4 1/2 miles to library in 2 1/4 hours. he walked the return trip at the same average rate , but a different route, taking my 2 1/2 hours. How many miles did lebron walk on the return trip?
Answers
Answer:
5 miles
Explanation:
First, we need to transform the mixed number into decimal numbers using as follows:
[tex]\begin{gathered} 4\frac{1}{2}=4+\frac{1}{2}=4+0.5=4.5\text{ miles} \\ 2\frac{1}{4}=2+\frac{1}{4}=2+0.25=2.25\text{ hours} \\ 2\frac{1}{2}=2+\frac{1}{2}=2+0.5=2.5\text{ hours} \end{gathered}[/tex]Now, the average rate was the same, so the ratio of the miles to the hours is always the same. Therefore, we can write the following equation:
[tex]\frac{\text{Miles}}{\text{Hours}}=\frac{4.5\text{ Miles}}{2.25\text{ Hours}}=\frac{x}{2.5\text{ Hours}}[/tex]Where x is the number of miles that Lebron walked on the return trip. So, solving for x, we get:
[tex]\begin{gathered} \frac{4.5}{2.25}=\frac{x}{2.5} \\ \frac{4.5}{2.25}\times2.5=\frac{x}{2.5}\times2.5 \\ 5=x \end{gathered}[/tex]Therefore, Lebron walked 5 miles on the return trip.
Don’t know how to solve with the -1 before the x
Answers
ANSWER and EXPLANATION
We are given a function and its inverse function:
[tex]\begin{gathered} f(x)=\frac{1}{2}x \\ f^{-1}(x)=2x \end{gathered}[/tex]To solve the problems, we have to substitute the values of x in the brackets into the appropriate function (or inverse function).
Therefore, we have that the value of the function for x = 2:
[tex]\begin{gathered} f(2)=\frac{1}{2}\cdot2 \\ f(2)=1 \end{gathered}[/tex]For x = 1, we have that the value of the inverse function is:
[tex]\begin{gathered} f^{-1}(1)=2(1) \\ f^{-1}(1)=2 \end{gathered}[/tex]For x = -2, we have that the value of the inverse function is:
[tex]\begin{gathered} f^{-1}(-2)=2\cdot-2 \\ f^{-1}(-2)=-4 \end{gathered}[/tex]For x = -4, we have that the value of the function is:
[tex]\begin{gathered} f(-4)=\frac{1}{2}\cdot-4 \\ f(-4)=-2 \end{gathered}[/tex]For the fifth option, substitute the value of the function at x = 2 into the inverse function.
That is:
[tex]\begin{gathered} f^{-1}(f(2))=f^{-1}(1)=2\cdot1 \\ f^{-1}(f(2))=2 \end{gathered}[/tex]For the sixth option, substitute the value of the inverse function at x = -2 into the function.
That is:
[tex]\begin{gathered} f(f^{-1}(-2))=f(-4)=\frac{1}{2}\cdot-4 \\ f(f^{-1}(-2))=-2 \end{gathered}[/tex]To find the general form of the function:
[tex]f^{-1}(f(x))=f(f^{-1}(x))[/tex]either substitute the function for x in the inverse function or substitute the inverse function for x in the function.
Therefore:
[tex]\begin{gathered} f^{-1}(f(x))=2(\frac{1}{2}x)) \\ f^{-1}(f(x))=x \end{gathered}[/tex]That is the answer.
The sum of three numbers is 154. The first number is 10 more than the second. The third number is 4 times the second. What are the numbers?First number:х5?Second number:000Third number
Answers
Let's call those numbers a, b and c.
Since their sum is 154, we have:
a + b + c = 154
Also, since the first number is 10 more than the second, we have:
a = b + 10
And, since the third number is 4 times the second number, we have:
c = 4b
Now, we can use the expressions of a and c in terms of b in the first equation:
a + b + c = 154
b + 10 + b + 4b = 154
6b + 10 = 154
6b = 154 - 10
6b = 144
b = 144/6
b = 24
Then, we can use the value of b to find a and c:
a = b + 10
a = 24 + 10
a = 34
c = 4b
c = 4 * 24
c = 96
Therefore,
• First number: ,34
,• Second number: ,24
,• Third number: ,96
need help asappppppp
Answers
Here, we want to get the length of the ladder
The kind of triangle we have is a right triangle for which obeys the Pythagoras' theorem
According to the theorem, the square of the hypotenuse equals the sum of the squares of the two other sides
The length of the ladder marked as h is the hypotenuse
Thus, we have it that;
[tex]\begin{gathered} h^2=9^2+7^2 \\ h^2\text{ = 81 + 49} \\ h^2\text{ = 130} \\ h\text{ = }\sqrt[]{130} \\ h\text{ = 11.40 meters} \end{gathered}[/tex]Which relation represents a function sample A or sample B
Answers
Sample A is a function because we don't have 2 values of x that are the same
Sample B is not a function, because it fails the vertical line test (x = 4 and y =1 also x=4 and y = 10) (4, 1) and (4, 10)
Hence the correct option is ; sample A