Sailor SheftalSimilar Figures / Proportion (Level 1)Aug 02, 10:17:02 AM?Triangle EFG is similar to triangle HIJ. Find the measure of side HI. Round youranswer to the nearest tenth if necessary.G94425Submit AnswerAnswer:attempt 1 out of 2
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If we have two similar triangles, that ratio of the corresponding sides are all the same. This means that:
[tex]\frac{GF}{JI}=\frac{EF}{HI}[/tex]Substituting the lengths, we get:
[tex]\begin{gathered} \frac{44}{9}=\frac{25}{HI} \\ HI=25\cdot\frac{9}{44}=5.1136\ldots\approx5.1 \end{gathered}[/tex]Related Questions
The 19% APR is the annual interest rate, but it is compounded monthly. What is the monthly interest rate ?
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Answer:
1.583%
Step-by-step explanation:
19% divided by 12% (how many months there are) = 1.583%
What is the inverse of the statement "If it is winter, then I am cold"?If it is not winter, then I am not coldIf it is winter, then I am coldIf I am cold, then it is winterIf I am not cold, then it is not winter
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ANSWER
If it is not winter, then I am not cold.
EXPLANATION
We want to find the inverse of the statement given:
If it is winter, then I am cold
To do this, we have to negate the if statement and the conclusion of the if statement there.
That is we find the negative of the if part and the then part of the statement.
The if part is:
If it is winter
The negative of this is:
If it is not winter
The then part is:
then I am cold
The negative of this is:
then I am not cold
Therefore, the inverse of the statement is If it is not winter, then I am not cold.
if (x=5)and y=10 which expression has the greatest value
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Let's assume the question was as stated below;
"If x=5 and y=10, which expression has the greatest value?"
a. xy
b. x + y
c. x-y
d. x/y
Answer:
Option A. Expression xy has the greatest value.
Explanation:
To determine which of the given options has the greatest value, let's go ahead and evaluate each of them;
Option A;
[tex]xy=x\ast y=5\ast10=50[/tex]Option B;
[tex]x+y=5+10=15[/tex]Option C;
[tex]x-y=5-10=-5[/tex]Option D;
[tex]\frac{x}{y}=\frac{5}{10}=\frac{1}{2}[/tex]We can see that the expression (xy) gives the greatest value.
Therefore, option A would be our correct answer.
33 over r =11 over 2
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Answer:
r=6
Step-by-step explanation:
33/r = 11/2
r/33 = 2/11 multiply both sides of the equation by 33
r = 33 * 2/11 = 6
Solve for V5/6= v-5 /4
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Okay, here we have this:
Considering the provided equation, we are going to solve it to find the value of y, so we obtain the following:
5/6= v-5 /4
v-5 /4+ 5 /4=5/6 + 5/4
v= 5/6 + 5/4
v=(20+30)/24
v=50/24
v=25/12
Finally we obtain that v is equal to 25/12.
On the plans for a treehouse, a beam represented by QR has endpoints Q(-6,2) and R (-1,8). A connecting beam represented by ST has endpoints S(-3,6) and T(-8,5). Are the beams perpendicular? Explain. (Hint:Graph the points if needed).
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We have the next graph
QR is the beam in red
ST is the beam in blue
As we can see the beams are not perpendicular because they do not intercept each other and they don't form a 90° angle between each other
use trigaonamets functions as nessary to find the missing parts the triangle
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Given a right angle triangle:
As shown on the acute angles is 21
So,
[tex]\begin{gathered} \cos \text{ 21=}\frac{adjacent}{\text{hypotenuse}}=\frac{6.4}{H} \\ \\ H=\frac{6.4}{\cos 21}=6.855 \end{gathered}[/tex]And:
[tex]\begin{gathered} \tan 21=\frac{opposite}{\text{adjacent}}=\frac{y}{6.4} \\ \\ y=6.4\cdot\tan 21=2.457 \end{gathered}[/tex]the third angle of the triangle =
[tex]90-21=69[/tex]NO LINKS!! Use the method of substitution to solve the system. (If there's no solution, enter no solution). Part 8z
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Answer:
(0, 0)(0.1, 0.005)=====================
Given system2y = x² y = 5x³Substitute the value of y into first equation2*5x³ = x²10x³ - x² = 0x²(10x - 1) = 0x = 0 and 10x - 1 = 0x = 0 and x = 0.1Find the value of yx = 0 ⇒ y = 5*0³ = 0x = 0.1 ⇒ y = 5*(0.1)³ = 0.005Answer:
[tex](x,y)=\left(\; \boxed{0,0} \; \right)\quad \textsf{(smaller $x$-value)}[/tex]
[tex](x,y)=\left(\; \boxed{\dfrac{1}{10},\dfrac{1}{200}} \; \right)\quad \textsf{(larger $x$-value)}[/tex]
Step-by-step explanation:
Given system of equations:
[tex]\begin{cases}2y=x^2\\ \;\;y=5x^3\end{cases}[/tex]
To solve by the method of substitution, substitute the second equation into the first equation and rearrange so that the equation equals zero:
[tex]\begin{aligned}y=5x^3 \implies 2(5x^3)&=x^2\\10x^3&=x^2\\10x^3-x^2&=0\\\end{aligned}[/tex]
Factor the equation:
[tex]\begin{aligned}10x^3-x^2&=0\\x^2(10x-1)&=0\end{aligned}[/tex]
Apply the zero-product property and solve for x:
[tex]x^2=0 \implies x=0[/tex]
[tex]10x-1=0 \implies x=\dfrac{1}{10}[/tex]
Substitute the found values of x into the second equation and solve for y:
[tex]\begin{aligned}x=0 \implies y&=5(0)^3\\y&=0\end{aligned}[/tex]
[tex]\begin{aligned}x=0 \implies y&=5\left(\dfrac{1}{10}\right)^3\\y&=5 \cdot \dfrac{1}{1000}\\y&=\dfrac{1}{200}\end{aligned}[/tex]
Therefore, the solutions are:
[tex](x,y)=\left(\; \boxed{0,0} \; \right)\quad \textsf{(smaller $x$-value)}[/tex]
[tex](x,y)=\left(\; \boxed{\dfrac{1}{10},\dfrac{1}{200}} \; \right)\quad \textsf{(larger $x$-value)}[/tex]
find (x) 76° 6x-9 47°
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There are two degrees, one variable and one number.
This probability distribution shows thetypical grade distribution for a Geometrycourse with 35 students.GradeAB.CDF3 2Frequency 51015Find the probability that a student earns agrade of A, B, or C.p = [?]Enter a decimal rounded to the nearest hundredth.
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The probability of an event is obtained as follows:
[tex]Pr(\text{Event)}=\frac{number\text{ of favourable outcomes}}{number\text{ of sample space}}[/tex][tex]\begin{gathered} Pr(a\text{ student earns a grade of A) = }\frac{number\text{ of students that earn grade A}}{Total\text{ number of students}} \\ Pr(a\text{ student earns a grade of A)=}\frac{5}{35} \\ \\ Pr(a\text{ student earns a grade of B)=}\frac{number\text{ of students that earn grade B}}{Total\text{ number of students}} \\ Pr(a\text{ student earns a grade of B)=}\frac{10}{35} \\ \\ Pr(a\text{ student earns a grade of C)=}\frac{\text{number of students that earn grade C}}{Total\text{ number of students}} \\ Pr(a\text{ student earns a grade of C)=}\frac{15}{35} \end{gathered}[/tex]Therefore, the probability that a student earns a grade of A, B or C=
Pr(a student earns a grade of A) + Pr(a student earns a grade of B) + Pr(a student earns a grade of C).
This becomes;
[tex]\frac{5}{35}+\frac{10}{35}+\frac{15}{35}=\text{ }\frac{30}{35}=\frac{6}{7}[/tex]Hence, the probability that a student earns a grade of A, B or C is
[tex]\frac{6}{7}=0.86\text{ (to the nearest hundredth)}[/tex]Question 9 of 10Which of these is an example of numerical data?A. Type of petB. Favorite carC. Average speedD. Home state
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Given:
Numerical data.
Find-: Numerical data.
Sol:
Average speed: Average speed define in numerical form and other options do not give any types of numerical data.
So answer is Average speed.
On March 8, 2017, one U.S. dollar was worth 19.61 Mexican pesos.(a) On that date, how many dollars was 149.23 pesos worth?Round your answer to the nearest hundredth of a dollar.dollars(b) On that date, how many pesos was 63.64 dollars worth?Round your answer to the nearest hundredth of a peso.OPpesosI need help with these two math problems.
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ANSWERS
(a) 7.61 USD
(b) 1247.98 MXN
EXPLANATION
We know that on March 8, 2017, 1 USD was worth 19.61 MXN.
(a) To find how many dollars was 149.23 MXN worth on that date, we have to divide this amount by 19.61,
[tex]149.23\text{ }MXN\cdot\frac{1\text{ }USD}{19.61\text{ }MXN}\approx7.61[/tex]Hence, 149.23 Mexican pesos were worth 7.61 US dollars.
(b) Now, to find how many Mexican pesos were 63.64 USD worth on that date, we have to multiply it by 19.61 instead,
[tex]63.64\text{ }USD\cdot\frac{19.61\text{ }MXN}{1\text{ }USD}\approx1247.98\text{ }MXN[/tex]Hence, 63.64 US dollars were worth 1247.98 Mexican pesos.
the factor of 26 are
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EXPLANATION
Factors are numbers we can multiply together to get another number.
The factor of 26:
26 divides by 2: 26/2=13
13 divides by 13: 13/13 = 1
2,13 are all prime numbers, therefore no further factorization is possible.
Add the primer factors:
2,13
Add 1 and the number 26 itself:
1,26
The factors of 26 are 1,2,13,26.
Find the equation of the line thatis parallel to y = 2x – 7 andcontains the point (-3,6).y = [ ? ]x + []Enter
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Answer:
y = 2x +12
Step-by-step explanation:
You want the line through point (-3, 6) that is parallel to y = 2x -7.
Parallel lineThe given line equation is in slope-intercept form ...
y = mx + b . . . . . line with slope m and y-intercept b
This allows us to see that its slope is 2.
The parallel line will have the same slope. All we need to do is find its y-intercept.
InterceptSolving the above equation for 'b', we get ...
b = y - mx
Using (x, y) = (-3, 6) and m = 2, we find 'b' to be ...
b = 6 -(2)(-3) = 12
EquationUsing the values for m and b that we now know, the desired equation is ...
y = 2x +12
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4. Solve for y 2x - y = -8
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The correct option is y = 2x + 8
Which pipe lengths could be joined to form a right triangle? 13 ft, 12 ft, 5 ft 19 ft, 16 ft, 2 ft 15 ft, 6 ft, 5 ft 40 ft, 20 ft, 10 ft
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Answer:
13ft, 12ft, 5ft
Explanation:
Looking at the given options, the correct option is the one with 13ft, 12ft, and 5ft because if the longest side of the right triangle(the hypotenuse) is 13ft then the summation of the other two sides must be equal or greater than 13ft (Pythagorean Theorem);
[tex]12ft+5ft\ge13ft[/tex]what kind of triangle is a triangle with the sides 8, 15, and 16? A. obtuseB. acuteC. right
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Lets draw the following picture:
which corresponds to an acute triangle. In acute triangles, all the angles are less than 90°.
This data set has two modes. Find the second mode of the data. 18, 12, 19, 15, 19, 18, 6 Mode: 18, [?]
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The mode of a dataset is the data that happens most frequently. A dataset has more then one mode when the most frenquet data values happens the same number of times.
Let's put the dataset in ascending order:
[tex]18,12,19,15,19,18,6\to6,12,15,18,18,19,19[/tex]As we can see, most data happens once and 18 and 19 happens twice each. So, both are the modes.
Since the given one is 18, the second mode is 19.
The school budget allows no more than $360 to be spent on balls and bats.The cost of a ball is $6 and the cost of a bat is $24write the inequality to represent this information
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Since the school budget allows no more than $360 to be spent on balls and bats, we have:
[tex]\text{total cost of balls and bats, in dollars }\le360[/tex]Now, let's call x the number of balls and y the number of bats that can be bought.
• The cost to buy x balls, in dollars, is 6x.
• The cost to buy y bats, in dollars, is 24y.
So, the total cost of balls and bats, in dollars, is 6x + 24y.
Now, we can use this expression in the above inequality to obtain the inequality:
[tex]\mathbf{6x+24y\le360}[/tex](F.LE.5) The function f(x) = 7.75x models the amount of money that Jimearns for each hour of work. What does the lack of a constant tell us?A. There is no initial amount of money he gets paid prior to startingB. His hourly wageC. His total amount he gets paid for the dayD. The number of hours Jim has worked
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In a linear model:
[tex]f(x)=mx+b[/tex]The coefficient of x, which is m, is the rate of change of the function f with respect to changes in the value of x. In the context of the problem, the coefficient of x tells us the amount of money that Jim earns per hour.
The constant term b is the initial value of the function f when x=0.
Since the given linear model has no constant term, it means that the initial value is 0. In other words, Jim will earn $0 if he works 0 hours.
Therefore, the correct choice is Option A) There is no initial amount of money he gets paid prior to starting.
ASSUME THAT THE WAITING TIMES FOR CUSTOMERS AT A POPULAR RESTAURANT BEFORE BEING SEATED ARE NORMALLY DISTRIBUTED WITH A MEAN OF 16 MINUTES AND STANDARD DEVIAITON OF 4 MINUTES.1. IN A RANDOM SAMPLE OF 1000 CUSTOMERS, HOW MANY WAIT 18 MINUTES OR MORE BEFORE BEING SEATED.2. IN A RANDOM SAMPLE OF 500 CUSTOMERS, HOW MANY WAIT LESS THAN 9 MINUTES BEFORE BEING SEATED
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Solution.
Calculate the z-score
The formula is shown below
[tex]\begin{gathered} \sigma=4 \\ \mu=16 \\ \end{gathered}[/tex][tex]\begin{gathered} Z_{18}=\frac{18-16}{4}=0.5 \\ P\left(x>0.5\right)=0.30854 \\ n=0.30854\text{ x 1000} \\ n=308.54 \\ n=309(nearest\text{ whole number\rparen} \end{gathered}[/tex]Thus, 309 customers (to nearest whole number) wait 18 minutes or more before being seated
(ii)
[tex]\begin{gathered} Z_9=\frac{9-16}{4} \\ Z_9=-1.75 \\ P\left(x<-1.75\right)=0.040059 \\ n=0.040059\text{ x 500} \\ n=20.03 \\ n=20(nearest\text{ whole number\rparen} \end{gathered}[/tex]Thus, 20 customers (to nearest whole number) wait less than 9 minutes before being seated
How many different 7-digit telephone numbers can be made if the first digit cannot be7,8, 9 or 0?
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The total amount of numbers that can be made is equal to the product of the amount of options for each digit.
The first digit has only 6 options: 1, 2, 3, 4, 5, or 6.
The other six digits have 10 options: 0,1,2,...,9.
Then, the total amount of different telephone numbers is six million:
[tex]6\times10\times10\times10\times10\times10\times10=6,000,000[/tex]Acorn is tossed three times. An outcome is represented by a string of the sort HTT (meaning ahead on the first tos, followed by two tails). The outcomes areIsted in the table below. Note that each outcome has the same probability,Por each of the three events in the table, check the outcomes) that are contained in the event. Then, in the last column, enter the probability of the event.OutcomesmiተብህቡብProbability음THTTTHTTHTHTHITHTEvent At A tail on both the first andthe last tosses$?0Event : Two or more tails0Event Ci Alternating tail and head(with either coming frst)0ContinueSubmit Assignment2022 MID CARDSign out00
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The outcome of tossing a coin is either a head or a tail.
Looking at the given table,
Event A = A tail in both the first and last tosses = THT, TTT
Event B = Two or more tails = TTH, TTT, HTT, THT
Event C = Alternating tail and head with either coming first = TTH, THH, HTT, HTH, THT. HHT
Recall,
probability = number of favorable outcome/number of total outcomes
Total number of outcomes = 8
Probability of event A = 2/8 = 1/4
Probability of event B = 4/8 = 1/2
Probability of event C = 6/8 = 3/4
can you explain step by step how to solve this?
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Remember that
the area of a parallelogram is equal to
A=b*h
in this problem
b=35 cm
h=44 cm
substitute
A=35*44
A=1,540 cm2Find out the perimeter
P=2*(35)+2*(47)
P=164 cmProblem N 2
we know that
the length of the wall is 170 inches
step 1
Find out the dimensions of the diagonal of the square
Applying the Pythagorean Theorem
d^2=12^2+12^2
d^2=2*12^2
[tex]d=12\sqrt[\square]{2}\text{ in}[/tex]Divide the length of the wall by the length of the diagonal
[tex]\frac{170}{12\sqrt[\square]{2}}=10.02[/tex]therefore
I need 11 (1/2 tiles)Note I rounded up because with 10 (1/2 tiles) the length is less than 170 incheshentIf TR = 11 ft, find the length of PS.IfР P.TentR16d ArcsSnd ArcsRound to 2 decimal places.and Arcs
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SOLUTION
This is a length of arc problem.
The formula for finding the length of an arc is:
[tex]\frac{\theta}{360}\times2\pi r[/tex]r=TR=PT=11ft
[tex]\begin{gathered} \frac{\theta}{360}\times2\pi r \\ r=11ft \\ \theta=164^o \end{gathered}[/tex][tex]\begin{gathered} \frac{164}{360}\times2\pi(11) \\ =\frac{164}{360}\times2\times3.14\times11 \\ =31.4698ft \\ =31.47ft(to\text{ 2 decimal places)} \end{gathered}[/tex]The final answer is 31.47ft.
100 in it takes 10 pounds of potatoes to make 15 pounds of mashed potatoes at this rate how many pounds of mashed potatoes can they make with 15 pounds of potatoes
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The box of cereals will weigh
[tex]undefined[/tex]Find the Midpoint of AB*round to the nearest tenth if necessaryA6,-3), B(2,9)
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19. The Millers open a savings account for their newborn son with $430. Find the total amount in the account after 3 years if the simple interest rate is 2.5%.
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we get that
[tex]C=430+3\cdot0.025\cdot430=462.25[/tex]How much do you owe at the end of five weeks ?
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First, find the interest percentage. Divide the amount borrowed by the interest amount.
[tex]\frac{100}{10}=10[/tex]Then, divide the result by 100% to express it as a percentage.
[tex]\frac{10}{100}=0.10[/tex]Once we have the interest percentage as a decimal number, multiply it by the new borrowed amount.
[tex]0.10\times1100=110[/tex]Therefore, you owe $110 at the end of the five weeks.if f(x) = 1/x and g(x) = x+1/x find(fog)(x).a) x +1/ x squared b) x / x + 1 c) x squared (x + 1)d) x + 1 / x cubed
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We have the following:
[tex]\begin{gathered} f(x)=\frac{1}{x} \\ g(x)=\frac{x+1}{x} \end{gathered}[/tex]now, (f(x) o g(x))
[tex]\mleft(f\: (x)\circ\: g(x)\mright)=\frac{1}{\frac{x+1}{x}}=\frac{x}{x+1}[/tex]The answer is the second option
[tex]\frac{x}{x+1}[/tex]