ReTest_Linear Functions Unit Topic 35 of 75 of 7 Items25:50 / 01:30:00 Is the relation a function? If so, is it one-to-one or not one-to-one?
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Function
one- to -one
Explanation:For a relation to be a function, each of the input of the function must have only one output.
The input are the x values while the output are the y values.
Input -2 has one output of -1
input -1 has output of -2
input 0 has output 0
input 1 has output 2
input 2 has output 4
Each of the input have only one output.
Hence, it is a function
A function is one-to-one when the elements in the domain has one value in the range.
Hence, it is one-to-one
Related Questions
Please help me find the inverse of f(x) = 2^x. I think that will help me label these?
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Given function:
[tex]f(x)=2^x[/tex]To obtain the inverse of the function f(x), we follow the steps outlined below:
Step 1: Replace f(x) with y:
[tex]y=2^x[/tex]Step 2: Interchange x and y
[tex]x=2^y[/tex]Step 3: Solve for y:
[tex]\begin{gathered} \text{Take logarithm of both sides} \\ \log x=log2^y \\ y\log 2\text{ = log x} \\ \text{Divide both sides by log2} \\ y\text{ = }\frac{\log x}{\log \text{ 2}} \\ y\text{ = }\log _2x \end{gathered}[/tex]Step 4: Replace y with f-1(x):
[tex]f^{-1}(x)\text{ = }\log _2x[/tex]Answer:
[tex]f^{-1}(x)\text{ = }\log _2x[/tex]Express the fraction as a percentage use the bar notation if necessary
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We have to express the fraction as a percentage.
We can think of the percentage as a fraction with denominator 100.
This means that 25% is equivalent to 25/100.
This is because 100% is the unit, then 100/100 = 1.
We can use this to convert a fraction to a percentage by transforming the denominator into 100.
In this case, the fraction is 2/5.
The denominator is 5, so to convert it to 100 we have to multiply it by 100/5 = 20.
Then, we apply this both to the numerator and denominator:
[tex]\frac{2}{5}*\frac{20}{20}=\frac{2*20}{5*20}=\frac{40}{100}=40\%[/tex]Answer: 2/5 = 40%
Which of the following lines is parallel to the line y= -3/2x-4?
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ANSWER:
1st option: y = -3/2x + 5
STEP-BY-STEP EXPLANATION:
We have that the equation in its slope-intercept form is the following:
[tex]\begin{gathered} y=mx+b \\ \\ \text{ where m is the slope and y-intercept is b} \end{gathered}[/tex]Two lines are parallel when the slope is the same, therefore, the line parallel to this line must have a slope equal to -3/2.
We can see that option 2 is the same line, therefore, they cannot be parallel, so the correct answer is 1st option: y = -3/2x + 5
1. According to a recent poll, 4,060 out of 14,500 people in the United States were clas-sified as obese based on their body mass index. What’s the relative frequency of obe-sity according to this poll?
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The relative frequency of obesity is the ratio between obese people in the sample and total people in the sample:
[tex]\frac{4060}{14500}=0.28[/tex]The relative frequency is 0.28
Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.At a candy store, Carla bought 6 pounds of jelly beans and 6 pounds of gummy worms for $108. Meanwhile, Rachel bought 6 pounds of jelly beans and 1 pound of gummy worms for $63. How much does the candy cost?
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Given:
Let x and y be the cost of 1 pound of Jelly beans and 1 pound of gummy worms.
[tex]\begin{gathered} 6x+6y=108 \\ x+y=18\ldots\text{ (1)} \end{gathered}[/tex][tex]6x+y=63\ldots\text{ (2)}[/tex]Subtract equation (1) from equation(2)
[tex]\begin{gathered} 6x+y-x-y=63-18 \\ 5x=45 \\ x=9 \end{gathered}[/tex]Substitute x=9 in equation(1)
[tex]\begin{gathered} 9+y=18 \\ y=18-9 \\ y=9 \end{gathered}[/tex]Cost of 1 pound of Jelly beans is $9
Cost of 1 pound of gummy worms is $9
The ordered pairs are graphed from the table in question 27 which of the following lines show the correct relationship
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To find the price per pound of oranges, we need to divide the cost by the number of pounds:
[tex]\text{ Price / pound=}\frac{12}{3}=4\text{ \$/pound}[/tex]Thus, each pound costs $4.
The cost of 5 pounds is:
[tex]5*4=20[/tex]The answer is C. $20
Writing Equations Is As Easy As 1, 2, 3 Digital Write the equation of the line that has the indicated slope and y-intercept. Slope = 2; y-intercept is (0,5)
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The general structure of a linear function is "slope-intercept" form is
y=mx+b
Where
m is the slope
b is the y-intercept
To write the equation for a slope 2 and y-intercept (0,5) you have to replace said values in the formula:
m=2
b=5
y=2x+5
Find the missing side length and angles of ABC given that m B = 137º, a = 15, and c = 17. Round to the nearest tenth.(Find angles A and C and side b)
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Given the triangle ABC and knowing that:
[tex]\begin{gathered} a=BC=15 \\ c=AB=17 \\ m\angle B=137º \end{gathered}[/tex]You need to apply:
• The Law of Sines in order to solve the exercise:
[tex]\frac{a}{sinA}=\frac{b}{sinB}=\frac{c}{sinC}[/tex]That can also be written as:
[tex]\frac{sinA}{a}=\frac{sinB}{b}=\frac{sinC}{c}[/tex]Where A, B, and C are angles and "a", "b" and "c" are sides of the triangle.
• The Law of Cosines:
[tex]b=\sqrt[]{a^2+c^2-2ac\cdot cos(B)}[/tex]Where "a", "b", and "c" are the sides of the triangle and "B" is the angle opposite side B.
Therefore, to find the length "b" you only need to substitute values into the formula of Law of Cosines and evaluate:
[tex]b=\sqrt[]{(15)^2+(17)^2-2(15)(17)\cdot cos(137\degree)}[/tex][tex]b\approx29.8[/tex]• To find the measure of angle A, you need to set up the following equation:
[tex]\begin{gathered} \frac{a}{sinA}=\frac{b}{sinB} \\ \\ \frac{15}{sinA}=\frac{29.8}{sin(137\degree)} \end{gathered}[/tex]Now you can solve for angle A. Remember to use the Inverse Trigonometric Function "Arcsine". Then:
[tex]\frac{15}{sinA}\cdot sin(137\degree)=29.8[/tex][tex]\begin{gathered} 15\cdot sin(137\degree)=29.8\cdot sinA \\ \\ \frac{15\cdot sin(137\degree)}{29.8}=sinA \end{gathered}[/tex][tex]A=\sin ^{-1}(\frac{15\cdot sin(137\degree)}{29.8})[/tex][tex]m\angle A=20.1\degree[/tex]• In order to find the measure of Angle C, you need to remember that the sum of the interior angles of a triangle is 180 degrees. Therefore:
[tex]m\angle C=180º-137º-20.1\degree[/tex]Solving the Addition, you get:
[tex]\begin{gathered} m\angle C=180º-137º-20.1\degree \\ m\angle C=22.9\degree \end{gathered}[/tex]Therefore, the answer is:
[tex]undefined[/tex]From a point on the North Rim of the Grand Canyon, the angle of depression to a pointon the South Rim is 2. From an aerial photo, it can be determined that the horizontaldistance between the two points is 10 miles. How many vertical feet is the South Rimbelow the North Rim (nearest whole foot).
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Question:
Solution:
The situation of the given problem can be drawn in the following right triangle:
This problem can be solved by applying the trigonometric identities as this:
[tex]\tan(2^{\circ})=\frac{y}{10}[/tex]solving for y, this is equivalent to:
[tex]y\text{ = 10 tan\lparen2}^{\circ}\text{\rparen=0.349 miles}[/tex]now, 0.349 miles is equivalent to 1842.72 feet. Now, this number rounded to the nearest whole foot is equivalent to 1843.
Then, the correct answer is:
1843 feet.
Set B and Set C are grouped according to the Venn Diagram below. Set B is (9, 12, 14, 17, 18) and Set C is (6,9,11, 12, 18, 19). The sample space is (1, 6, 9, 11, 12, 14, 17, 18, 19, 20).
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To get the probability of an event to occur, we have the following formula:
[tex]P=\frac{no.\text{ of favorable outcomes}}{\text{total no. of possible outcomes}}[/tex]According to the problem, the sample space is (1, 6, 9, 11, 12, 14, 17, 18, 19, 20) therefore, the total no. of possible outcomes is 10.
For Set B, the sample is (9, 12, 14, 17, 18), therefore, there are 5 possible outcomes that belong to set B.
Starting with the first question, what is the probability of Set B to occur?
[tex]P=\frac{no.\text{ of outcomes from B}}{\text{total no. of possible outcomes}}=\frac{5}{10}=\frac{1}{2}=0.50=50\text{ percent}[/tex]For Set C, the sample is (6,9,11, 12, 18, 19) therefore, there are 5 possible outcomes that belong to set C as well.
On the next question, what is the probability of Set C to occur?
[tex]P=\frac{no.\text{ of outcomes from C}}{\text{total no. of possible outcomes}}=\frac{5}{10}=\frac{1}{2}=0.50=50\text{ percent}[/tex]For the third question, what is the probability of Set B or C to occur?
Since the outcomes under B or C are (6, 9, 11, 12, 14, 17, 18, 19), the probability of the union of B and C is:
[tex]P=\frac{no.\text{ of outcomes from B or C}}{\text{total no. of possible outcomes}}=\frac{8}{10}=\frac{4}{5}=0.80=80\text{ percent}[/tex]On to the last question, what is the probability of the intersection of B and C to occur?
Since the outcomes that are found on both B and C are (9,12,18), the probability of the intersection of B and C is:
[tex]P=\frac{no.\text{ of outcomes found on both B and C}}{\text{total no. of possible outcomes}}=\frac{3}{10}=0.30=30\text{ percent}[/tex]Estimate the fraction 3/8 by rounding to the nearest whole or one-half
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SOLUTION
The fraction given is
[tex]\frac{3}{8}[/tex]To round-off the fraction, we need to convert it to decimal number
[tex]\frac{3}{8}\text{ to decimal is }[/tex]Hence
The estimated fraction in decimal will be
[tex]0.375=0.4=\frac{4}{10}=\frac{2}{5}[/tex]Answer: 1/2 is the answer
hope this helped :)
Step-by-step explanation:
I need help with this practice from my ACT prep guide onlineI’m having trouble solving it It asks to graph, if you can, use Desmos
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Given:
[tex]f(x)=-4\cos (\frac{2}{3}x+\frac{\pi}{3})-3[/tex]Graph of function is cos from.
Period of the function is:
Check for period inter.
[tex]=3\pi[/tex]What is the inmage of A(2, 1) after reflecting it across x =4 and then across the x-axis? a.16. 1)b. (6,-1) c(-6,-1) d. -6, 1)
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If we reflect the point A (2, 1) across x=4, the point will be at (6, 1). Then if we reflect it again across the x axis, the point will be at (6, -1)
Answer: (6, -1)
o from Mobile. How Tar IS Il IIUMI U 3117 12. Cincinnati is 488 miles from New York City and along the way to Brownsville, Texas which is 2007 miles from New York. How far, then, is it from Cincinnati to Brownsville?
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ANSWER:
2495 miles.
STEP-BY-STEP EXPLANATION:
To answer the question we make the following scheme:
Therefore the distance between Cincinnati and Brownsville is the sum of the distance between Cincinnati to New York and New York to Brownsville, like this
[tex]\begin{gathered} d=488+2007 \\ d=2495 \end{gathered}[/tex]Therefore the distance between Cincinnati and Brownsville is 2495 miles.
on which of the following lines does the point (1,6) lie
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It is required to determine which line the point (1,6) lies on.
To do this, substitute the point into each equation and check which of the equations it satisfies.
Check the first equation:
[tex]\begin{gathered} y=x+5 \\ \text{ Substitute }(x,y)=(1,6): \\ \Rightarrow6=1+5 \\ \Rightarrow6=6 \end{gathered}[/tex]Since the equation is true, it follows that the point lies on the line.
Check the second equation:
[tex]\begin{gathered} y=-x+7 \\ \text{ Substitute }(x,y)=(1,6): \\ \Rightarrow6=-1+7 \\ \Rightarrow6=6 \end{gathered}[/tex]Since the equation is true, it follows that the point also lies on the line.
Check the third equation:
[tex]\begin{gathered} y=2x-1 \\ \text{ Substitute }(x,y)=(1,6): \\ \Rightarrow6=2(1)-1 \\ \Rightarrow6=1 \end{gathered}[/tex]Notice that the equation is not true. Hence, the point does not lie on the line.
So the given point only lies on lines a and b.
The answer is option D.
20. Monroe's teacher wants each student to draw a sketch of the longest specimen. Which specimen is the longest? 21. Seen through the microscope, a specimen is 0.75 cm long. What is its actual length?
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20)
The sketch of the given data is
By observing the sketch, the longest line is A.
Hence the specimen A is the longest.
21)
In the microscope, the size of the specimen is 0.75cm long.
It is given that the microscope enlarges the actual length 100 times.
[tex]\text{Size =100}\times Actual\text{ length}[/tex][tex]\frac{\text{Size }}{100}\text{=}Actual\text{ length}[/tex]Substitute Size=0.75, we get
[tex]\frac{0.75}{100}=\text{Actual length}[/tex][tex]\text{Actual length=0.0075 cm}[/tex]Hence the actual length of the specimen is 0.0075cm.
Find the area of the triangle below.Be sure to include the correct unit in your answer.025 ft24 ft7 ft
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To calculate the area of the triangle you have to multiply its base by its height and divide the result by 2, following the formula
[tex]A=\frac{bh}{2}[/tex]Considering the given right triangle, the base and the height of the triangle are its legs:
The area can be calculated as:
[tex]\begin{gathered} A=\frac{bh}{2} \\ A=\frac{7\cdot24}{2} \\ A=\frac{168}{2} \\ A=84ft^2 \end{gathered}[/tex]The area of the triangle is 84ft²
(G.12, 1 point) Which point lies on the circle represented by the equation (x-4)2 + (y - 2)2 = 72? O A. (-1,4) B. (8,3) O C. (9,0) O D. (-2, 2)
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To know if a point lies on a circle you use the (x,y) of each point in the equation and prove it that correspond to a mathematical congruence.
A. (- 1 , 4)
[tex]\begin{gathered} (-1-4)^2+(4-2)^2=7^2 \\ -5^2+2^2=49 \\ 25+4=49 \\ 29=49 \end{gathered}[/tex]As 29 is not equal to 49, this point doesn't lie in the circle
B. ( 8 , 3)
[tex]\begin{gathered} (8-4)^2+(3-2)^2=7^2 \\ 4^2+1^2=49 \\ 16+1=49 \\ 17=49 \end{gathered}[/tex]As 17 is not equal to 49, this point doesn't lie in the circle
C. (9 , 0)
[tex]\begin{gathered} (9-4)^2+(0-2)^2=7^2 \\ 5^2+(-2)^2=49 \\ 25+4=49 \\ 29=49 \end{gathered}[/tex]As 29 is not equal to 49, this point doesn't lie in the circle
D. (-2 , 2)
[tex]\begin{gathered} (-2-4)^2+(2-2)^2=7^2 \\ -6^2+0^2=49 \\ 36=49 \end{gathered}[/tex]As 36 is not equal to 49, this point doesn't lie in the circle
None of the points lies on the circle.The next graph represents the circle and the 4 given points:
I tried but immediately got confused on what to start with
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Radius of the inscribed circle.
Given:
Side length of square = 8cm
From the diagram, the circumference of the inscribed circle touches the sides of the square. Hence, we can say that the diameter of the inscribed circle is equal to the side length of the square.
The diagram below shows this relationship
We know that the radius (r) is related to the diameter (d) as
use the first derivative test to classify the relative extrema. Write all relative extrema as ordered pairs
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The given function is
[tex]f(x)=-10x^2-120x-5[/tex]First, find the first derivative of the function f(x). Use the power rule.
[tex]\begin{gathered} f^{\prime}(x)=-10\cdot2x^{2-1}-120x^{1-1}+0 \\ f^{\prime}(x)=-20x-120 \end{gathered}[/tex]Then, make it equal to zero.
[tex]-20x-120=0[/tex]Solve for x.
[tex]\begin{gathered} -20x=120 \\ x=\frac{120}{-20} \\ x=-6 \end{gathered}[/tex]This means the function has one critical value that creates two intervals.
We have to evaluate the function using two values for each interval.
Let's evaluate first for x = -7, which is inside the first interval.
[tex]f^{\prime}(-7)=-20(-7)-120=140-120=20\to+[/tex]Now evaluate for x = -5, which is inside the second interval.
[tex]f^{\prime}(7)=-20(-5)-120=100-120=-20\to-[/tex]As you can observe, the function is increasing in the first interval but decreases in the second interval. This means when x = -6, there's a maximum point.
At last, evaluate the function when x = -6 to find the y-coordinate and form the point.
[tex]\begin{gathered} f(-6)=-10(-6)^2-120(-6)-5=-10(36)+720-6 \\ f(-6)=-360+720-5=355 \end{gathered}[/tex]Therefore, we have a relative maximum point at (-6, 355).Carolyn has a circular swimming pool with a diameter of 20 feet. She needs to know the area of the bottom of the pool so that she can find out how much paint to buy for it. What is the approximate area?
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To find the area of the bottom we have to use the formula to find the area of a circle:
[tex]A=\pi r^2[/tex]Where A is the area and r is the radius.
The first step is to find the radius of the circle, which is half the diameter:
[tex]\begin{gathered} r=\frac{D}{2} \\ r=\frac{20ft}{2} \\ r=10ft \end{gathered}[/tex]Replace r in the given formula and use 3.14 as pi:
[tex]\begin{gathered} A=3.14\cdot(10ft)^2 \\ A=314ft^2 \end{gathered}[/tex]The answer is 314ft^2.
Are the ratios 1:6 and 14:18 equivalent
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I don't know I need points you are loved tho I don't know I need points you are loved tho
In a right triangle, cos (2x) = sin (8x + 5)'. Find the smaller of the triangle's two
acute angles.
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According to the given problem,
[tex]\cos (2x)^{\circ}=\sin (8x+5)^{\circ}[/tex]Consider the formula,
[tex]\sin (90-\theta)=\cos \theta[/tex]Apply the formula,
[tex]\sin (90-2x)=\sin (8x+5)[/tex]Comparing both sides,
[tex]\begin{gathered} 90-2x=8x+5 \\ 8x+2x=90-5 \\ 10x=85 \\ x=\frac{85}{10} \\ x=8.5 \end{gathered}[/tex]Obtain the value of the two angles,
[tex]\begin{gathered} 2x=2(8.5)=17 \\ 8x+5=8(8.5)+5=73 \end{gathered}[/tex]It is evident that the smaller angle is 17 degrees, and the larger angle is 73 degrees.
Thus, the required value of the smaller acute angle of the triangle is 17 degrees.
Convert the following Quadratic Equations from Vertex Form to Standard Form.
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4)
Given:
The vertex form is given as,
[tex]y=-\frac{1}{3}(x+6)^2-1[/tex]The objective is to convert the vertex form to standard form.
The standard form can be obtained as,
[tex]\begin{gathered} y=-\frac{1}{3}(x+6)^2-1 \\ =-\frac{1}{3}(x^2+6^2+2(x)(6))-1 \\ =-\frac{1}{3}(x^2+36+12x)-1 \\ =-\frac{x^2}{3}-\frac{36}{3}+\frac{12x}{3}-1 \\ =-\frac{x^2}{3}-12+4x-1 \\ =-\frac{x^2}{3}+4x-13 \end{gathered}[/tex]Here,
[tex]\begin{gathered} a=-\frac{1}{3} \\ b=4 \\ c=-13 \end{gathered}[/tex]Hence, the required standard form of the equation is obtained.
You are hiking and are trying to determine how far away the nearest cabin is, which happens to be due north from your current position. Your friendr walks 220 yards due west from your position and takes a bearing on the cabin of N 21.2°E. How far are you from the cabin?A. 638 yardsB. 608 yardsC. 567 yardsD. 589 yards
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In the given right triangle
we have that
[tex]\begin{gathered} tan(21.2^o)=\frac{220}{x}\text{ -----> by TOA} \\ \\ solve\text{ for x} \\ \\ x=\frac{220}{tan(21.2^o)} \\ \\ x=567\text{ yrads} \end{gathered}[/tex]The answer is option Cwhat is the slope of y=x-7
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The given equation is in slope-intercept form, which means the coefficient of x is the slope.
Therefore, the slope is 1.How to know if you have the slope-intercept form?
The slope intercept-form is y = mx + b, as you can observe, the variable y is completely isolated, and the other side of the equation has two terms. Whenever you have a linearGrea equation like this, it means you have a slope-intercept form where the slope is m, and the y-intercept is b.
Evaluate x^1 - x^-1 + x^0 for x = 2.
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The value of x^1 - x^-1 + x^0 for x = 2 is 5
we need to evaluate x¹ - x⁻¹ + x⁰
A positive exponent tells us how many times to multiply a base number, while a negative exponent tells us how many times to divide a certain base number. Negative exponents can be re written. x⁻ⁿ as 1 / x
x¹ - 1/x + x⁰
(any number or variable which is raised to the power zero is considered as 1)
x¹ - 1/x + 1
x² - 1 + x
x² + x - 1
The value of this expression for x = 2
2² + 2 - 1
4 + 2 - 1
5
Therefore,the value of x^1 - x^-1 + x^0 for x = 2 is 5
To learn more about indices refer here
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I need help with statistical problem I have got the answer of 0.3354 because I subtracted 0.9991 - 0.146 I wanted to know if that was correct I kept getting the answer wron
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From the quetion
We are given a normal distribution with mean = 0 and standard deviation = 1
The sketch of the distribution is as shown below
Therefore option C is the correct answer
We are to find the probability that a given score is between -2.18 and 3.74
The probability is
[tex]P\mleft(-2.18Therefore,The probability is 0.9853
Evaluate the expression. 2 13 21 The value of the expression is
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To solve the exercise you can use the following property of powers
[tex](\frac{a}{b})^n=\frac{a^n}{b^n}[/tex]Then, you have
[tex]\begin{gathered} |(\frac{-1}{2})^3\div(\frac{1}{4})^2|=|\frac{(-1)^3}{(2)^3}^{}\div\frac{(1)^2}{(4)^2}^{}| \\ |(\frac{-1}{2})^3\div(\frac{1}{4})^2|=|\frac{-1^{}}{8}^{}\div\frac{1}{16}^{}| \end{gathered}[/tex]Now, apply the definition of fractional division, that is
[tex]\frac{a}{b}\div\frac{c}{d}=\frac{a\cdot d}{b\cdot c}[/tex][tex]\begin{gathered} |(\frac{-1}{2})^3\div(\frac{1}{4})^2|=|\frac{-1^{}\cdot16}{8\cdot1}^{}| \\ |(\frac{-1}{2})^3\div(\frac{1}{4})^2|=|\frac{-1^{}6}{8}^{}| \\ |(\frac{-1}{2})^3\div(\frac{1}{4})^2|=|-2| \end{gathered}[/tex]Finally, apply the definition of absolute value, that is, it is the distance between a number and zero. The distance between -2 and 0 is 2.
Therefore, the value of the expression is 2.
[tex]\begin{gathered} |(\frac{-1}{2})^3\div(\frac{1}{4})^2|=|-2| \\ |(\frac{-1}{2})^3\div(\frac{1}{4})^2|=2 \end{gathered}[/tex]Make a estimate then divide using partial-quotients division write your remainder as a fraction
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We can make an estimate for the given division by rounding the dividend to the nearest hundred and the divisor to the nearest ten.
We obtain:
[tex]812\div17\cong800\div20=40[/tex]Now, using partial-quotients division, we obtain:
17 ) 812
-170 +10 because 10*17=170
642
-170 +10
472
-170 +10
302
-170 +10
132