Really need help solving this practice from my ACT prep guide It’s a trig practice

Really Need Help Solving This Practice From My ACT Prep Guide Its A Trig Practice

Answers

Answer 1

Given:

- The amplitude of the Sine Function:

[tex]A=10[/tex]

- The midline:

[tex]y=4[/tex]

- And the period:

[tex]Period=2[/tex]

- You know that the function does not have a Phase shift.

• You need to remember that, by definition, the General Equation for a Sine Function has this form:

[tex]y=Asin\mleft(B\mleft(x+C\mright)\mright)+D[/tex]

Where "A" is the amplitude, "C" is the phase shift, "D" is the vertical shift and this is the period:

[tex]Period=\frac{2\pi}{B}[/tex]

Since the midline is given by the vertical shift, you can identify that, in this case:

[tex]D=4[/tex]

And, knowing the period, you can set up that:

[tex]2=\frac{2\pi}{B}[/tex]

Solving for "B", you get:

[tex]\begin{gathered} 2B=2\pi \\ \\ B=\frac{2\pi}{2} \\ \\ B=\pi \end{gathered}[/tex]

• It is important to remember the following Transformation Rule for Functions:

When:

[tex]-f(x)[/tex]

The function is reflected over the x-axis.

Therefore, knowing all the data, you can set up this equation:

[tex]f(x)=-10\sin (\pi x)+4[/tex]

Hence, the answer is: First option.


Related Questions

find all real solutions[tex](2x + 17) \div (x + 1) = x + 5[/tex]

Answers

We have the next equation

[tex]\frac{2x+17}{x+1}=x+5[/tex][tex]2x+17=(x+5)(x+1)[/tex][tex]\begin{gathered} 2x+17=x^2+x+5x+5 \\ 2x+17=x^2+6x+5 \end{gathered}[/tex]

Then we sum similar terms

[tex]\begin{gathered} x^2+(6x-2x)+(5-17)=0 \\ x^2+4x-12=0 \end{gathered}[/tex]

then we solve the quadratic equation

We can factorize the equation

[tex](x+6)(x-2)=0[/tex]

so the solutions are

x=-6

x=2

A rectangular play area has an area of 7,497 square meters. If the width of the rectangle is 49 meters, find the length.

Answers

If a rectangular play area has an area of 7,497 square meters. and the width of the rectangle is 49 meters, then the length is 153 meters

A rectangular play area has an area of 7,497 square meters

If the width of the rectangle is 49 meters

Let the length of the rectangular play be l

Area of a rectangle can be given by

area = length x width

7497 = l x 49

l = 7497 / 49

l = 153

Therefore, if a rectangular play area has an area of 7,497 square meters. and the width of the rectangle is 49 meters, then the length is 153 meters

To learn more about rectangle refer here

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1 block: 11 houses = 2 blocks : ??? houses

Answers

[tex]\begin{gathered} 1\text{ block =11 houses } \\ 2\text{ block = ? houses} \\ \text{cross multiply} \\ 2\text{ block=11}\times2=22\text{ houses} \end{gathered}[/tex]

Write the expression that can be used tofind the height of the Eiffel Tower.

Answers

First, let's picture the problem:

I have represented the height of the Effiel tower as H

Using the trigonometric ratios:

[tex]\begin{gathered} \tan 53^0\text{ = }\frac{H}{225} \\ H=225\times\tan 53^0^{} \end{gathered}[/tex]

Hence the required expression is :

[tex]\begin{gathered} \text{Height of tower = d }\times\text{ tan}\phi \\ \text{if d is the distance of the base} \end{gathered}[/tex]

The coordinates of the vertices of triangle RST are R(-2, -3), S(4,5), and T (8,2). List the angles of triangle RST in order from smallest to largest.

Answers

The first step is to plot the triangle RST with the given coordinates. The diagram of the triangle RST is shown below. We can see that the smallest angle is angle R, The larger angle is angle T while the largest angle is angle S

Listing the angles in order from smallest to largest.​, it becomes

angle R, angle T and angle S

Write the expression and simplifyThe difference of -10 and the product of p and q

Answers

We start with a subtraction, where we want to subtract the second term from - 10. The second term consists in a multiplication between p and q. Writing this as a mathematical expression we have

[tex]-10-pq[/tex]

This expression is already on simplest form.

How to do 2 step equations Can you solve 2x + 5=21?

Answers

Given

The equation,

[tex]2x+5=21[/tex]

To find the value of x or to solve for x.

Explanation:

It is given that,

The equation is,

[tex]2x+5=21[/tex]

That implies,

[tex]\begin{gathered} 2x+5=21 \\ 2x=21-5 \\ 2x=16 \\ x=\frac{16}{2} \\ x=8 \end{gathered}[/tex]

Hence, the value of x is 8.

The line M is parallel to the line y=-2x+2 and goes through the origin. Which of these points is on the line M? (-2,-4)(1,1)(2,-2)(-2,4)

Answers

Answer:

(-2,4)

Explanation:

Two lines are said to be parallel if their slopes are the same.

Comparing the line y =-2x+2 to the slope-intercept form y=mx+b, the slope of the line is -2.

Therefore, the slope of line M that is parallel to it is also - 2.

Since the line M goes through the origin, the y-intercept of line M is 0.

Therefore, the equation of line M is:

[tex]y=-2x[/tex]

Therefore, the point which is on line M is the point that satisfies the equation above.

This point is (-2,4).

Check

[tex]\begin{gathered} \text{When }x=-2,y=4 \\ y=-2x \\ 4=-2(-2) \\ 4=4 \end{gathered}[/tex]

find the value of the term in the arithmetic sequence 1,6,11,16...(8th term)

Answers

We need to find the 8th term of the following arithmetic sequence:

[tex]1,6,11,16,...[/tex]

The formula to find the n-th term an of aₙ arithmetic sequence is:

[tex]a_n=a_1+(n-1)d[/tex]

where a₁ is the first term and d is the difference between two consecutive terms.

The first term of this sequence is a₁ = 1, and d is given by:

[tex]\begin{gathered} d=a_2-a_1 \\ \\ d=6-1 \\ \\ d=5 \end{gathered}[/tex]

Then, for n = 8, we obtain:

[tex]\begin{gathered} a_8=1+(8-1)5 \\ \\ a_8=1+7(5) \\ \\ a_8=1+35 \\ \\ a_8=36 \end{gathered}[/tex]

Answer:

The 8th term is 36.

Determine the probability of being dealt 4 Aecs of cards, from a deck of 52 playing cards, with a replacement.

Answers

Given:

4 Aces of cards from a deck of 5 playing cards.

[tex]\begin{gathered} \text{Probability of drawing 4 Aces }=\frac{4}{52}\times\frac{4}{52}\times\frac{4}{52}\times\frac{4}{52}\times4! \\ \text{Probability of drawing 4 Aces }=\frac{1}{13}\times\frac{1}{13}\times\frac{1}{13}\times\frac{1}{13}\times24 \\ \text{Probability of drawing 4 Aces }=\frac{24}{28561} \end{gathered}[/tex]

A circle has area 36 cm². What is the diameter?

Answers

Answer:

6.77 cm

Explanation:

Given that the area of a circle = 36 cm²

We want to find the diameter of the circle.

The area of a circle of radius r is calculated using the formula:

[tex]A=\pi r^2[/tex]

Substitute A=36 and π=3.14:

[tex]\begin{gathered} 36=3.14r^2 \\ \text{ Divide both sides by 3.14} \\ \frac{36}{3.14}=\frac{3.14r^2}{3.14} \\ r^2=\frac{36}{3.14} \\ \text{ Take the square root of both sides} \\ r=\sqrt{\frac{36}{3.14}} \\ r=3.3845 \end{gathered}[/tex]

Finally, to get the diameter, multiply the radius by 2.

[tex]\begin{gathered} Diameter=Radius\times2 \\ =3.3845\times2 \\ =6.769 \\ Diameter\approx6.77\;cm \end{gathered}[/tex]

The diameter of the circle is approximately 6.77 cm.

1. Sue uses 2.59 pounds ofstrawberries and 0.65 poundof blueberries to make fruitsalad. She serves the sameamount of salad in each of 9bowls. What is the weight,in pounds, of each serving tothe nearest tenth?

Answers

Problem:

Sue uses 2.59 pounds of strawberries and 0.65 pounds of blueberries to make a fruit salad. She serves the same amount of salad in each of 9

bowls. What is the weight, in pounds, of each serving to

the nearest tenth?

Solution:

The total weight of the fruit salad is:

2.59 pounds + 0.65 pounds = 3.24 pounds.

Now, if she serves the same amount of salad in each of 9 bowls, we have that the weight in each serving is:

[tex]\frac{3.24}{9}=\text{ 0.36 pounds}[/tex]

Then, we can conclude that the correct answer is:

0.36 pounds.

Solve the system of equations.y = x2 - 2y = -2x + 1A. (-3,7) and (-1,3)B. (-3,7) and (1, -1)C. (1.-1) and (3,-5)D. (-1,3) and (3, -5)

Answers

Answer

Option B is correct.

the solutions to the system of equations include

(-3, 7) and (1, -1)

Step-by-step Explanation

The question is to solve the system of equations

y = x² - 2 ..... equation 1

y = -2x + 1 ..... equation 2

To solve this, we can just equate the expression given for y in equation 1 to the expression given for y in equation 2.

y = x² - 2

y = -2x + 1

Since

y = y

x² - 2 = -2x + 1

x² + 2x - 2 - 1 = 0

x² + 2x - 3 = 0

This gives a quadratic equation which we will now solve

x² + 2x - 3 = 0

x² + 3x - x - 3 = 0

x (x + 3) - 1 (x + 3) = 0

(x - 1) (x + 3) = 0

So,

x - 1 = 0 or x + 3 = 0

x = 1 or x = -3

If x = 1,

y = x² - 2

= 1² - 2

= 1 - 2

= -1

x = 1, y = -1

If x = -3

y = x² - 2

= (-3)² - 2

= 9 - 2

= 7

x = -3, y = 7

So, the solutions to the system of equations include

x = -3, y = 7, that is, (-3, 7)

And

x = 1, y = -1, that is, (1, -1)

Hope this Helps!!!

write a polynomial function in standard form with the given zeros x= -1,-2,-3,-4

Answers

Explanation: For this question we have 4 zeros so x can be as follows

x = -1 or x = -2 or x = -3 or x = -4

We can turn the equalities above into factors as follows

[tex]\begin{gathered} x=-1\rightarrow x+1=0 \\ x=-2\rightarrow x+2=0 \\ x=-3\rightarrow x+3=0 \\ x=-4\rightarrow x+4=0 \end{gathered}[/tex]

Step 1: Now that we have the factors we can build a function and simplify it as follows

[tex]\begin{gathered} y=(x+1)(x+2)(x+3)(x+4) \\ y=(x^2+2x+x+2)(x^2+4x+3x+12) \\ y=(x^2+3x+2)(x^2+7x+12) \\ y=x^4+7x^3+12x^2+3x^3+21x^2+36x+2x^2+14x+24 \\ y=x^4+7x^3+3x^3+12x^2+21x^2+2x^2+36x+14x+24 \\ y=x^4+10x^3+35x^2+50x+24 \end{gathered}[/tex]

Final answer: So the final answer is

[tex]y=x^4+10x^3+35x^2+50x+24[/tex]

.

Dante is saving money to buy a game. So far he has saved $20, which is four-fiths of the total cost of the game. How much does the game cosх$?

Answers

Money saved = $20

According to the statement we can establish the following equation

[tex]20=\frac{4}{5}X[/tex]

where X is the total cost of the game

now let's find X

[tex]\begin{gathered} \frac{4}{5}X=20 \\ 5\cdot\frac{4}{5}X=20\cdot\: 5 \\ 4X=100 \\ \frac{4X}{4}=\frac{100}{4} \\ X=25 \end{gathered}[/tex]

Therefore the total cost of the videogame is $25

Solve for v. v + 4/5 = 1/3. Simplify your answer as much as possible.

Answers

Answer:

v = -7/15.

Explanation:

Given the equation:

[tex]v+\frac{4}{5}=\frac{1}{3}[/tex]

To solve for v, first, subtract 4/5 from both sides of the equation:

[tex]\begin{gathered} v+\frac{4}{5}-\frac{4}{5}=\frac{1}{3}-\frac{4}{5} \\ \implies v=\frac{1}{3}-\frac{4}{5} \end{gathered}[/tex]

Next, simplify the right-hand side by taking the lowest common multiple of the denominators:

[tex]\begin{gathered} v=\frac{5-3(4)}{15}=\frac{5-12}{15} \\ \implies v=-\frac{7}{15} \end{gathered}[/tex]

The value of v is -7/15.

how do you write out this number in word 506,341,209.54

Answers

You write this number in word this way:

Five hundred six million three hundred fourty one thousand two hundred nine point fifty four.

Determine the independent and dependent quantities in each scenario include when possible Part A: A lamp manufacturing company produces 750 lamps per shift Part B:a grocery store sells pears by the pound. A customer purchases 3 pounds by $5.07

Answers

Here, we want to establish the independent and independent quantities in each of the parts

The independent quantities are simply the quantities that do not depend on the dependent quantity. The dependent quantity are the quantities that depend on the independent quantity

a) Here, we have 750 lamps produced per shift

This is obtained by dividing the number of lamps produced by the number of shifts it took to produce them

In this case, the number of lamps produced is dependent on the number of shifts'

Number of shifts is the independent variable while the number of lamps is the dependent variable

b) Here, the cost per pair is 5.07/3 = 1.69

So here, the cost is dependent on the number of pears

The number of pears is the independent variable while the cost of the pears is the dependent variable

In the diagram of \bigtriangleup△GKJ below, LH KJ, GL=6, LK=30, and GH=3. What is the length of GJ?

Answers

From the given figures

Since LH // KJ, then

[tex]\frac{GL}{LK}=\frac{GH}{HJ}[/tex]

GL = 6, LK = 30

GH = 3, HJ = y

Substitute them in the ratio above

[tex]\frac{6}{30}=\frac{3}{y}[/tex]

By using cross multiplication

[tex]\begin{gathered} 6\times y=30\times3 \\ 6y=90 \end{gathered}[/tex]

Divide both sides by 6

[tex]\begin{gathered} \frac{6y}{6}=\frac{90}{6} \\ y=15 \end{gathered}[/tex]

Since GJ = GH + HJ

[tex]\begin{gathered} GJ=3+15 \\ GJ=18 \end{gathered}[/tex]

The answer is 36

Determine the equation of the line that passes through the point (1/8,2) and is perpendicular to the line 5y+2x=2.

Answers

Step 1

Given;

Determine the equation of the line that passes through the point (1/8,2) and is perpendicular to the line 5y+2x=2.

Step 2

Find the slope of the new line based on a perpendicular relationship

[tex]\begin{gathered} m_1=-\frac{1}{m_2} \\ \end{gathered}[/tex][tex]\begin{gathered} 5y=2-2x \\ y=\frac{2-2x}{5} \\ y=\frac{2}{5}-\frac{2}{5}x \\ -\frac{2}{5}=-\frac{1}{m_2} \\ 2m_2=5 \\ m_2=\frac{5}{2} \end{gathered}[/tex]

Thus the equation will be;

[tex]\begin{gathered} (\frac{1}{8},2) \\ y=\frac{5}{2}x+b \\ b=y-intercept \\ 2=\frac{5}{2}(\frac{1}{8})+b \\ 2=\frac{5}{16}+b \\ b=2-\frac{5}{16} \\ b=\frac{27}{16} \end{gathered}[/tex][tex]y=\frac{5}{2}x+\frac{27}{16}[/tex]

Answer;

[tex]y=\frac{5}{2}x+\frac{27}{16}[/tex]

l A golf ball is hit in the air. The table shown describes y, the height of the ball, in feet, given the time elapsed, x, in seconds, since the time the ball was hit.Based on the information in the table, which statements are true? Select each correct statement.

Answers

Given:

y is the height of the ball in feet

x is the time in seconds

In the given table you can identify the next maximum:

x=3

y=30

The ball has height 0 when it is in the earth so it is hit at second 0 and will be back in the earth at second 6

Then, from the given statements the next are true:

The maximum height of the ball was 30 feetThe ball was in the air for only 6 seconds

Find each unit price and decide which is the better buy. Assume that we are comparing sizes of the same breadFrozen orange juice $1.51 for 14 ounces $0.51 for 4 ounces Find the unit price if a frozen orange juice which cost $1.51 for 14 ounces

Answers

Answer:

Unit price of a frozen orange juice which costs $1.51 for 14 ounces = $0.108 per ounce

Unit price of a frozen orange juice which costs $0.51 for 4 ounces = $0.128

The better buy is the frozen orange juice which costs $1.51 for 14 ounces

Option B

Explanations:

Cost of 14 ounces of orange juice = $1.51

Cost od 4 ounces of orange juice = $0.51

Unit price of a frozen orange juice which costs $1.51 for 14 ounces

Unit price = $1.51 / 14

Unit price of a frozen orange juice which costs $1.51 for 14 ounces = $0.108 per ounce

Unit price of a frozen orange juice which costs $0.51 for 4 ounces

Unit price = $0.51 / 4

Unit price of a frozen orange juice which costs $0.51 for 4 ounces = $0.128

The better buy is the one with the lower unit price

Since the frozen orange juice which costs $1.51 for 14 ounces has the lower unit price, it is the better buy

What is the y-intercept of the graph of y = 2.5x?a. 2.5b. 0c. 1d. -1

Answers

Solution

- We are asked to find the y-intercept of the graph of:

[tex]y=2.5x[/tex]

- In order to find the y-intercept, we need to know the definition of the y-intercept.

- The y-intercept is the y-value where the graph crosses the y-axis.

- An implication of this definition is that whenever the graph crosses the y-axis, the x-value at that point is zero. This means that we simply need to substitute x = 0 into the equation given to us to find the y-intercept of the graph.

- The y-intercept can thus is gotten as follows:

[tex]\begin{gathered} y=2.5x \\ \text{put }x=0 \\ y=2.5(0) \\ \\ \therefore y=0 \end{gathered}[/tex]

Final Answer

The y-intercept of the graph is y = 0 (OPTION B)

A. Step 1B. Step 2C. Priya did not make a mistake

Answers

We will have the following:

[tex]\frac{f}{0.25}=16\Rightarrow f=16\cdot0.25[/tex][tex]\Rightarrow f=4[/tex]

From this we can see that there was no mistaky on Priya's side. [Option 3]

suppose we spin the following spinner with the first spin giving us the numerator and the second spin giving the denominator of a fraction. What is the probability that the fraction will be less than or equal to 5/6?

Answers

numerator = top number

denominator = bottom number

numerator less than or equal to 5

total numbers = 4

numbers less than or equal to 5 = 2 ( 5 and 4)

Denominator

5, 6 or 7 = 3

Possible fractions = 4/5, 4/6, 4/7, 5/6 and 5/7

5 out of 16 possible fractions

probability = 5/16

You are going to paint your door on the outside. Your door is 7 feet 2 inches tall and 32inches wide. You need to know the surface area of the front of your door to determine howmuch paint to buy. The hardware store sells paint by how much covers a square foot. What isthe surface area you should report to the hardware store?

Answers

Data

height = 7 ft 2 in

width = 32 in

1.- Convert height into inches

1 ft ------------ 12 in

7 ft ------------ x

x = 84 in

total height = 84 + 2

= 86 in

2.- Calculate the area

Area = height x width

Area = 84 x 32

Area = 2688 in 2

Find the general solution to dy/dx = 2y passing through the point (5, 1)

Answers

We will have the following:

[tex]\frac{\partial y}{\partial x}=2y\Rightarrow\frac{1}{2y}\partial y=\partial x[/tex][tex]\Rightarrow\int (\frac{1}{2y})\partial y=\int \partial x\Rightarrow\frac{\log (y)}{2}=x+c[/tex]

Then we find "c":

[tex]\frac{\log(1)}{2}=5+c\Rightarrow c=-5[/tex]

Thus, the general solution passing through (5, 1) is:

[tex]\frac{\log(y)}{2}=x-5[/tex]

True or false the function f(x) = -3(x+10)^2 has a minimum

Answers

Notice that:

[tex]\begin{gathered} f^{\prime}(x)=-6(x+10), \\ f^{\prime\prime}(x)=-6. \end{gathered}[/tex]

Since for all x, f''(x)<0, by the second derivative criteria we get that f(x) reaches a maximum.

Answer: False.

The product of two whole numbers is 592 and their sum is 53. What are the two numbers?

Answers

To solve this problem, we have to build two equations with the given information. Using x and y to represent the two numbers:

• Equation 1

[tex]x\times y=592[/tex]

• Equation 2

[tex]x+y=53[/tex]

Now that we have to equations, we have to isolate one variable from one equation and replace it in the other.

[tex]x=53-y[/tex]

Then, we will replace this value of x in Equation 1:

[tex](53-y)\cdot y=592[/tex]

Solving for y we get:

[tex]53y-y^2=592[/tex][tex]-y^2+53y-592=0[/tex]

As we got this expression, we will have to use the General Quadratic Formula. With the help of a calculator, we get both values:

[tex]y_1=16[/tex][tex]y_2=37[/tex]

Finally, we have to replace these values in Equation 1 to evaluate which meets the condition:

[tex]x_1=\frac{592}{y_1}[/tex][tex]x_1=\frac{592}{16}=37[/tex][tex]x_2=\frac{592}{y_2}[/tex][tex]x_2=\frac{592}{37_{}}=16[/tex]

We have to evaluate the values in each equation:

[tex]\begin{gathered} 37+16=53 \\ 53=53 \end{gathered}[/tex][tex]37\cdot16=592[/tex]

The first numbers meet the condition.

Answer: 37 and 16

The minimum diameter for a hyperbolic cooling tower is 76 feet, which occurs at a height of 173 feet. The top of the cooling tower has a diameter of 93 feet, and the total height of the tower is 250 feet. Write the equation for the hyperbola that models the sides of the cooling tower assuming that the center of the hyperbola occurs at the height for which the diameter is least.Round your a and b values to the nearest hundredth if necessary.

Answers

STEP - BY - STEP EXPLANATION

What to find?

The equation for the hyperbola that models the sides of the cooling tower assuming that the center of the hyperbola occurs at the height for which the diameter is least.

Given:

Minimum diameter = 76 feet

Height = 173 feet

Diameter of the top of cooling tower = 93 feet

Total height of tower = 250 feet

Consider the general hyperbolic formula below:

[tex]\frac{x^2}{a^2}-\frac{y^2}{b^2}=1[/tex]

But;

2a = 76

⇒ a = 38

x=93/2 =46.5

y=250 - 173 =77

Substitute the values into the formula above and determine the value of b.

[tex]\frac{(46.5)^2}{38^2}-\frac{77^2}{b^2}=1[/tex][tex]b=109.18[/tex]

Now substitute the values a= 38 and b=109.18 into the general formula

[tex]\frac{x^2}{38^2}-\frac{y^2}{109.18^2}=1[/tex]

ANSWER

[tex]\frac{x^2}{38^2}-\frac{y^2}{109.18^2}=1[/tex]

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