Answer:
Below
Explanation:
Measure distance to pistol .....
speed of light is nearly instantaneous in this situation (short distance)
measure time from flash to hearing the sound
speed of sound = distance to pistol / time to hear
Both ?? PLEASE PLEASE THANK YOU SO MUCH
Answer:
18 kg·m/s
26 kg·m/s
Explanation:
5) J = Ft = (6N)(3s) = 18 kg·m/s
6) J = Ft = (6N)(3s) = 18 kg·m/s
J = Δp = p2 - p1
p1 = mv = (4kg)(2m/s) = 8 kg·m/s
p2 = J + p1 = 18 kg·m/s + 8 kg·m/s = 26 kg·m/s
An electric dipole with its center located at the origin of a Cartesian coordinate system oscillates along the x axis, creating an electromagnetic wave.a. At a position on the z axis far from the origin, what is the polarization of the wave?b. At a position on the axis far from the origin, what is the polarization of the wave?
Along the z-axis, the wave moves, Along the x-axis, the polarization is linear. When a dipole oscillates, it indicates that the two charges that make up the dipole oscillate all along line connecting them,
What exactly is oscillation?A Simple pendulum's oscillatory oscillation is described as its periodic back and forth motion. One oscillation of the a pendulum occurs when the bob moves back and forth starting from one end and ending in the same place.
What is motion-induced oscillation?The body moving back and forth about its fixed location is referred to as oscillatory motion. A form of periodic motion is oscillatory motion. Vibrating strings and swinging are examples of oscillatory motion.
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which electromagnetic radiation wavelength is efficiently observed using ground based telescopes?
Radio is the electromagnetic radiation wavelength that is efficiently observed using ground-based telescopes.
Most telescopes under $150 have poor optical quality and aren't worth much. Instead, I recommend getting good binoculars. Stay away from telescopes advertised as having high magnification. The most important feature of a telescope is its size and the diameter of the primary mirror or lens. With a diameter of 4 or 5 inches.
The telescope is ideal for viewing solar system objects such as planets, moons, and moons of Jupiter. There are three main types of astronomical telescopes. Refractor telescope, Newton telescope, and Schmidt-Cassegrain telescope. It can damage not only your eyes but also your telescope lens.
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Avanti works in a bookstore. She has four books and is going to place them in two stacks. The diagram above shows the books before they touch. Use the information in the diagram to answer the question.
How did the temperatures of the four books compare before they touched? How will the temperatures of the two top books compare after the books have been touching for a while, and why?
Answer:
Below
Explanation:
Black books were cooler in temp than yellow books to start
after a while they will all be the same temp
Stack 1 will be cooler(around 4) than stack 2 (around 5)
"A sound of frequency 15Hz and an amplitude of 70dB is inaudible." Explain with reasons if this statement is true or false.
A sound of frequency 15Hz and an amplitude of 70dB is inaudible. This is true statement.
What is audible sound?The human ear can easily hear frequencies between 20 Hz and 20 kHz. Therefore, sound waves with a frequency between 20 Hz and 20 kHz are regarded as audible sound. The human ear may be able to pick up on even the smallest changes in air pressure if they are in the audible frequency range. The difference in air pressure is less than one billionth of a percent.
As we age and are exposed to sound for extended periods of time, the upper limit of our hearing frequencies decreases. A typical middle-aged adult can hear well up to 12 to 14 kilohertz, which is the highest frequency.
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How does sleep heal the body?
Sleep is very crucial in healing our body. Proper sleep helps person in proper healing from any type of injuries.
The foundational resistant capability is harmed by sleep limitation. A clinical report by Smith et. al showed that sleep limitation deferred skin obstruction recuperation, and sustenance supplementation constricted decrements in nearby safe reactions delivered by rest limitation.
Proper sleep helps in proper flow of blood in all over of our body, due to which any type of injuries which is present in our body gets eliminated in few days.
As Dr. Walker examines in "Why We Rest"; in spite of the fact that competitors know the significance of pre-game rest, they are regularly amazed by the equivalent or expanded significance for rest in the days post-game. He distinguished that post-execution rest speeds up actual recuperation from aggravation, invigorates muscle fix, and restocks cell energy. This shows the really beneficial impacts of sufficient rest on insusceptible capability, actual recuperation, and mending.
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When the spring is stretched and the distanced from point A to point B is 5.2 feet, what is the valuue of 0 to the nearest tenth of a degree?
(A) The distance from point A to point B to the nearest tenth of a foot will be 3.4 ft.
(B) The value of 0 to the nearest tenth of a degree will be 54.8°
SOH, CAH, and TOA are the trigonometry ratios that need to be solved in order to find necessary measures or angles in a right triangle.
A) Reference angle = 28 degrees
Distance A-B = ?
Adjacent = 3 ft
We will calculate the distance between A-B by using the trigonometry function, CAH, that is:
Cos ∅ = adj ÷ hyp
Cos 28° = 3 ÷ A-B
A-B = 3 ÷ Cos 28°
A-B = 3.4 ft
B) Reference angle = ?
Distance A-B = 5.2 ft
Adjacent = 3 ft
We will calculate the distance between A-B by using the trigonometry function, CAH, that is:
Cos ∅ = adj ÷ hyp
Put the values
Cos ∅ = 3 ÷ 5.2
∅ = Cos⁻¹ (3 ÷ 5.2)
∅ = 54.8°
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an object is released from a stationary hot balloon at height h above the ground. an identical object is released at height h above the ground from another balloon that us rising at constant speed. air resistance is negligible. what does not increase for the object released from the rising balloon?
Whether the object is released from the stationary hot balloon or moving hot balloon, its acceleration is neither increased nor decreased because acceleration due to gravity "g" is constant or has a constant value.
When an object is released from the stationary hot balloon at a height h above the ground and an identical object is released at heigh h above the ground from another balloon that is rising at a constant speed, there is no difference in its acceleration compared to the previous one. This is because the acceleration due to gravity, denoted as 'g' is constant at the value of 9.8 m/s.
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since the observer does not interact with the subject in observation studies, observation is an error-free method of data collection question 2 options:
Ans is false. There are several errors associated with observation: subjectivity, observer bias, accuracy, and interpretation.
How to find error free method of data collection?Observational error (or measurement error) is the difference between a measured value of and its true value.
The errors associated with data collection, mentioned above can be defined as follows:
1. Subjectivity bias : the tendency of participant in a study to react, either consciously or unconsciously. Here they act experimentally and not naturally.
2. Observation bias : the tendency of observers to not see what is there, but instead to see what they expect or want to see.
3) Accuracy : the condition or quality of being true, correct, or exact; freedom from error or defect; precision or exactness; correctness.
4) interpretation: can be defined as understanding of something. One can avoid it by using multiple sources of information, such as references and personal interviews,
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Need help! Thanks lots!
The air bag reduces the force by increasing the time it takes the passenger to stop moving.
How does airbag make people safer ?Despite the fact that airbags are a widespread and necessary safety feature, few of us understand how they function in our cars. A processing unit chooses which airbags in the automobile to deploy in a crash based on data from any of a myriad of sensors.Depending on the severity of the crash, the frontal airbags can deploy with varied degrees of force. When the threshold is exceeded, an electrical pulse ignites a gas, triggering the airbags. This generates enough nitrogen gas in less than 30 milliseconds to fully inflate the airbag. Some airbags only deploy if the weight of a passenger in the relevant seat is detected, which means an airbag will not deploy if there is no passenger to protect.When you are involved in an automobile accident, airbags inflate when a sensor connected to your vehicle's airbag senses a collision. They are filled with nitrogen gas and deflate when the driver or passengers come into touch with the airbag.What is airbag system ?They're air cushions inflated in fractions of a second by a fast-acting inflator to protect you from your car's interior hardpoints, such as the dashboard, steering wheel, windscreen, and roof pillars, which are triggered during an accident. It inflates so quickly that it's already fully inflated when your body moves. If you're wondering where your airbags are, don't look in the steering wheel. They are embedded throughout the interior padding of the car, with perforated seams that allow them to deploy.Can learn more about airbags and safety from https://brainly.com/question/12842741
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What is potential energy of a spring if the spring is constant?
It is the potential energy stored in spring when it is stretched or deformed. It is equal to force multiplied by displacement. This energy is stored in the spring by virtue of its position. It is the work done to stretch the spring.
When spring is stretched, it undergoes displacement. It comes to its equilibrium position when force is removed. So, it exerts an equal and opposite force When it is stretched. Work is done by this force that is stored in the form of potential energy.
Since potential energy = force × displacement
and, force = spring constant × displacement
So, potential energy = spring constant × [tex](displacement)^{2}[/tex]
P.E. = k ×[tex]x^{2}[/tex]
Where,
k = spring constant
x = displacement caused due to stretching
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communications satellites would fly off in a straight line never to be see again if it were not for a force from the earth compelling them to constantly change their direction. this tendency to fly off in a straight line is a statement of the
Communications satellites would fly off in a straight line never to be see again if it were not for a force from the earth, The moon "falls" from a straight line because there IS some attraction toward the Earth.
What would happen if forces were suddenly removed from the satellite?The satellite will tend to move tangential to the initial orbit without the assistance of centripetal force at the same speed as it did just before the gravitational field vanishes. As a result, the spacecraft will veer off course and leave its orbit.
Do people gravitate toward one another?The combined gravitational force of acts on the mass in your body. What gives you weight is that. Additionally, you would weigh less than you do now if you were on a planet with a lower mass than Earth. You make the same gravitational force on Earth that it does on you.
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a container in the form of a right circular cone (vertex down) has radius 4 m and height 16 m. see the figure. if water is poured into the container at the constant rate of 16 m3/min, how fast is the water level rising when the water is 8 m deep?
A container in the form of a right circular cone when the water is 8 m deep, the water level is rising at approximately 1.273 m/min.
The volume of a cone is:
V(h) = (1/3) × π × r² × h
V(h) = (1/3) × (4²) × h
V(h) = (16/3) × π × h
The rate at which the volume is changing with respect to time is:
dV/dt = 16 m³/min
dV/dt = (d/dt) [(16/3) × π × h]
dV/dt = (16/3 × π × (dh/dt)
(16/3 × π × (dh/dt) = 16
dh/dt = (16/3π)
dh/dt = 1.273 m/min
Therefore, when the water is 8 m deep, the water level is rising at approximately 1.273 m/min.
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The complete question is:
A container in the form of a right circular cone (vertex down) has a radius of 4m and a height of 16 m. If water is poured into the container at the constant rate of 16 m³/min, how fast is the water level rising when the water is 8 m deep? (Hint: the volume V of a cone or radius r and height h is V = 1/3πr²h.)
a star has a distance of 30 parsecs and a apparent magnitude of 3 --what would its absolute magnitude be?
The absolute magnitude of the star would be +5.
The absolute magnitude of the star is dependent on the apparent magnitude and distance which is measured in parsecs.
A measurement of distance in astronomy that is approximately 3.26 light years (3.086 x 10^13 km) long. The distance at which the mean radius of the earth's orbit subtends an angle of one second of arc is equal to one parsec.
A measure of a celestial object's luminance on an inverse logarithmic astronomical magnitude scale is called absolute magnitude (M). The absolute magnitude of an object is the apparent magnitude that the object would have if it were seen from a distance of exactly 10 parsecs (32.6 light-years), without the light of the object being extinguished (or dimmed) owing to absorption by interstellar materials and cosmic dust. The luminosities of the various objects can be directly compared to one another on a magnitude scale by putting them all hypothetically at a fixed reference distance from the observer.
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an object is located midway between the focal point and the center of a concave spherical mirror. draw a ray diagram to locate its image. is the image real or virtual, erect or inverted, magnified or reduced in size?
At the concave mirror's center of curvature, something is situated. The picture is accurate and reversed.
For a concave mirror, the object-image connection is given by,
1 ÷ s + 1 ÷ s' = 2 ÷ R
the object distance, where s
The picture distance is s'.
The radius of curvature is R.
Now, the distance between an item and the point of curvature equals the radius of curvature.
s = R
Using s = R as a substitute and solving for s'
s' = [tex]((\frac{2}{R} ) - (\frac{1}{s} ))^{-1}[/tex]
s' = [tex]((\frac{2}{R} ) - (\frac{1}{R}))^{-1}[/tex]
s' = [tex]{(\frac{1}{R})}^{-1}[/tex]
s' = R
As a result, the photograph is real and can be found at R.
We discovered that the picture is genuine and is not at infinity.
Sideways magnification is
m = y' ÷ y = -s' ÷ s
where y is the height of the item.
The picture height is y'.
calculating the magnification
m = -s' ÷ s
= -R ÷ R
m = -1
As a result, the image size doesn't change.
We discover that neither the image's size nor its size has been changed.
calculating the picture height now
y' = my
y' = -y
Consequently, the picture is reversed.
The picture is not upright, as we discover.
The only accurate response to the query utilizing the outcomes is that the image is Real.
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an intergalactic spaceship arrives at a distant planet that rotates on its axis with a period of t. the spaceship enters a geosynchronous orbit at a distance of r.
The spaceship enters a geosynchronous orbit is M = 4π 2 R 3 /GT 2 M = 1.35 × 10²⁸ kg.
A geostationary orbit is a low-inclination prograde orbit around the Earth lasting 23 hours 56 minutes and 4 seconds. A spacecraft in a geostationary orbit appears to move north and south but appears to stay at a fixed longitude on Earth. A geostationary orbit is a geostationary orbit.
A geostationary satellite orbit is an orbit around the Earth that intentionally has an orbital period of one sidereal day equal to the Earth's sidereal rotation period, with the satellite returning to the same position in the sky after each sidereal day. Geostationary means that the satellite orbits with the same angular velocity as the earth.
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a galaxy with thin spiral arms and a small spherical central bulge would be a type
A type bulge would be a galaxy with small, spherical central bulge and thin spiral arms.
What is bulge?
The majority of spiral galaxies are made up of a bulge, or core collection of stars, and a flat, revolving disk filled with stars, gas, and dust. The spiral features that radiate from the galactic disc's core and give spiral galaxies their name. A spiral galaxy's nucleus is a sharply peaking, smooth-textured region that can be fairly small or even make up the majority of the galaxy in some circumstances. a relates to a large central bulge and wide central arms, whereas corresponds to a small central bulge with sharp spiral arms. Large spiral galaxies like the Andromeda galaxy and our own galaxy are common.
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When an object's momentum changes, usually that means its velocity has charged. What must happer fo
an object's velocity to change?
a. Its mass increases
b. An outside force acts upon it
c. Its mass decreases
d. Its momentum must stay the same
Answer:
b. An outside force acts upon it
Explanation:
a block with a mass of 200 g is connected to a light horizontal spring of force constant 5.00 n/m and is free to oscillate on a horizontal, frictionless surface. find the period of its motion.
A 200-gram block may freely oscillate on a longitudinal, stationary object for 1.26 seconds while being attached to a light longitudinal spring with a force constant of 5.00 n/m.
m = 200g = 0.2 kg
A = 5cm = 0.05 m
A = 5cm = 0.05 m
k = 5 (N ÷ m)
T = 2π √m ÷ k, We may calculate the period and, thus, the frequency by measuring the length of one full oscillation. Be aware that the period in the case of a block is separate from the mass, but the period in the case of a mass on a spring is irrespective of the spring's length.
T = 2π √m ÷ k
T = 2π √0.2 ÷ 5
T = 1.26 s
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if the magnitude of the magnetic field is now decreased at a rate of -0.16 t/s , what force (magnitude and direction) will act on q ?
The magnitude of the force acting on q will be 0.16 t/s times the magnitude of the charge q, and it will be in the opposite direction of the magnetic field.
The force on a charged particle in a magnetic field is given by the equation:
F = qv × B
where q is the charge of the particle, v is the velocity of the particle and B is the magnitude of the magnetic field.
When the magnitude of the magnetic field is decreased at a rate of -0.16 t/s, the force on the particle will be in the opposite direction of the decreasing magnetic field. This is because the magnitude of the magnetic field will be decreasing over time, so the force on the particle will be in the opposite direction of the decreasing magnetic field.
The magnitude of the force acting on the particle will be equal to the product of the charge of the particle and the velocity of the particle multiplied by the rate of change of the magnetic field. That is, the magnitude of the force will be:
F = qv × (-0.16 t/s)
The direction of the force will be in the opposite direction of the decreasing magnetic field.
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A 6. 0-m wire with a mass of 50 g, is under tension. A transverse wave, for which the frequency is 810 hz, the wavelength is 0. 40 m, and the amplitude is 4. 0 mm, is propagating on the wire. The time for a crest of this wave to travel the length of the wire is closest to.
The time for the crest of a wave having a frequency of 810 hz, a wavelength of 0.40 m, and an amplitude of 4.0 mm to travel to the closest length of wire is 19 ms.
WavelengthWavelength is the distance between one wave frequency peak and another peak. Therefore, the wavelength of frequency is the distance that a wave must travel in one period. This wavelength is denoted by the symbol λ (lambda) with units of m (meters).
the equation between wavelength, speed and frequency is:
λ = v/f
We have,
Wavelength = 0.4 m ⇒ λ
Frequency = 810 hz ⇒ f
Distance = 6.0 m
And, the velocity:
v = λ x f
= (0.4) (810)
= 324 m/s
So, the time for a crest of this wave to travel the length of the wire is closest to:
time = distance/velocity
= 6/324
= 0.0185 s = 19 ms.
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A 0.65 kg ball is attached to the end of a string. It is swung in a vertical circle of radius 0.50 m. At the top of the circle its velocity is 2.8 m/s.
In a vertical circular motion If the distance is measure from a fixed point is, it will be same at each point. The minimum velocity that the ball must have to make it around the circle is 8.57 m/s.
What is vertical circular motion?In a vertical circular motion If the distance is measure from a fixed point is, it will be same at each point.
According to the Given information:
The radius of the vertical circle is 1.5 m.
As the ball rotates in the vertical circular motion with constant velocity. Thus the speed of the ball will be same for each point.
Therefore the centripetal force should be same for each point which is,
Here, m is the mass v is the velocity and R is the radius. This centripetal force is balanced by the tension action on the ball (towards the center) and the gravitational force acting on it.
Therefore, For the minimum velocity, the value of tension should be zero.
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Question seems to be incomplete. The complete question be like this
Draw a free body diagram for the ball when it is at the top of the circle. Next to that diagram indicate the direction of its acceleration b. Use that free body diagram to set up the equations needed to determine the Tension in the string. c. Solve those equations for the Tension in the string.
an electron and a 0.0320-kg bullet each have a velocity of magnitude 510 m/s, accurate to within 0.0100%. within what lower limit could we determine the position of each object along the direction of the velocity?electron mmbullet m
for this we apply, Heisenberg's uncertainty principle.
it states that physical variables like position and momentum, can never simultaneously know both variables at the same moment.
the formula is,
Δp * Δx = h/4π
m(e).Δv * Δx = h/4π
by rearranging,
Δx = h / 4π * m(e).Δv
Δx = (6.63*10^-34) / 4 * 3.142 * 9.11*10^-31 * 5.10*10^-2
Δx = 6.63*10^-34 / 583.9 X 10 ⁻³¹
Δx = 0.011 X 10⁻³
for the bullet
Δx = (6.63*10^-34) / 4 * 3.142 * 0.032*10^-31 * 5.10*10^-2
Δx = 6.63*10^-34 /2.05
Δx =3.23 X 10⁻³² m
therefore, we can say that the lower limits are 0.011 X 10⁻³ m for the electron and 3.23 X 10⁻³² m for the bullet
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Which of the following is(are) true of globular clusters?
A. They are smaller groups of stars orbiting larger galaxies.
B. The stars in them are all of roughly the same age.
C. Both a and b are correct.
Answer:
B
Explanation:
the others don’t seem right
An intergalactic spaceship arrives at a distant planet that rotates on its axis with a period of T. The spaceship enters a geosynchronous orbit at a distance of R.
(a) Radius's general expression is R = ∛T²GM/4π²
(b)The planet's mass during its geosynchronous orbit is 4.9 × 10²⁵ kg.
We are given that,
T = period of the orbit = 26hours
r = radius of the orbit = = 2.1 × 10⁸ m.
G = gravitational constant = 6.674×10⁻¹¹ m³⋅kg⁻¹⋅s⁻²
M = mass of the planet
Putting the value in radius equation we get,
R = ∛T²GM/4π²
8.98 ×10⁷ m = ∛ (26 × 60 × 60)² ×( 6.67 ×10⁻¹¹) M/ 4×(3.142)²
M = (8.98 ×10⁷ m ×39.49 )/ (∛2.86 × 10¹⁸)
M = 4.9 ×10²⁵
As a result, the planet has a mass of 4.9 ×10²⁵kg throughout its geosynchronous orbital period.
The complete question is given below,
An intergalactic spaceship arrives at a distant planet that rotates on its axis with a period of T. The spaceship enters a geosynchronous orbit at a distance of R. a) From the given information, write a general expression for the mass of the planet in terms of G and the variables from the problem statement. b) Calculate the mass of the planet in kilograms if T = 26 hours and R = 2.1 × 108 m.
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There is strong evidence that Europa, a satellite of Jupiter, has a liquid ocean beneath its icy surface. Many scientists think we should land a vehicle there to search for life. Before launching it, we would want to test such a lander under the gravity conditions at the surface of Europa. One way to do this is to put the lander at the end of a rotating arm in an orbiting earth satellite. If the arm is 4.25 m long and pivots about one end, at what angular speed (in rpm) should it spin so that the acceleration of the lander is the same as the acceleration due to gravity at the surface of Europa? The mass of Europa is 4.80 x 10^{22} kg and its diameter is 3120 km.
The angular speed of the lander at the end of the rotating arm is 4.98 rpm.
It is given to us that -
The radius of the rotating arm = 4.25 m
Mass of the Europa = [tex]4.80 * 10^{22}[/tex] kg
Diameter of the Europa = 3120 km
=> Radius of the Europa = 3120/2 = 1560 km = 1,560,000 m
We have to find out the angular speed (in rpm) at which the rotating arm should spin so that the acceleration of the lander is the same as the acceleration due to gravity at the surface of Europa.
Firstly, we have to find out the acceleration due to gravity of the Europa. We know that the force on the Europa can be given as -
[tex]F = Mg\\= > Mg = \frac{G*m*M}{R^{2} } \\= > g = \frac{G*m}{R^{2}}\\= > g = \frac{(6.67 * 10^{-11} )*(4.80*10^{22} )}{1560000^{2} } \\= > g = 1.19 m/s^{2}[/tex] ----- (1)
It is given to us that -
Acceleration of the lander = Acceleration due to gravity at the Europa
[tex]= > a_{l} = g\\= > a_{l} = 1.19 m/s^{2}[/tex] ----- (2) [From equation (1)]
Now, to calculate the angular speed of the lander, we can use the formula as -
[tex]= > a_{l} = w^{2} r\\= > w^{2} = \frac{a_{l} }{r} \\[/tex] ----- (3)
where,
[tex]a_{l}[/tex] = Acceleration of the lander
[tex]w[/tex] = angular speed of the lander
r = radius of the rotating arm
Substituting the values of [tex]a_{l}[/tex] from equation (2) and r in equation (3), we have -
[tex]w^{2} = \frac{a_{l} }{r}\\= > w^{2} = \frac{1.19 }{4.25}\\= > w^{2} = 0.28\\= > w = 0.529 rad/s[/tex]
In order to convert the angular speed in rpm, we have to use -
[tex]w = 0.529 rad/s\\= > w = 0.529 * \frac{1 rev * 60 s}{2\pi rad*1 min}\\ = > w = 4.98 rpm[/tex]
Therefore, the angular speed of the lander at the end of the rotating arm is 4.98 rpm.
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Alfredo deDarke often leaves household appliances on for no good reason (at least according to his parents). The deDarke family pays 15¢/kilowatt-hour (i.e., $.15/kW•hr) for their electrical energy. Express your understanding of dollar power by filling in the following table.
Answer: $15 /KW.hr
What is Watt hour?
--A Watt Hour is a unit of measurement for power over a period of time (an hour), a way of measuring capacity.
-- One Watt hour is equal to one Watt of average power flow over an hour.
What is power?
--Power as the rate of doing work, it is the work done in unit time.
-- The SI unit of power is Watt (W) which is joules per second (J/s).
In above questions deDaeke family pay $15/Kilowatt .hour which means it pay $15 when used 1kilowatt power in 1hour i.e. 3.6 ×10^6 joule.
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Which theory states that the universe originated as a single mass?
Answer:
The Big Bang Theory
Explanation:
Today, the consensus among scientists, astronomers and cosmologists is that the Universe as we know it was created in a massive explosion that not only created the majority of matter, but the physical laws that govern our ever-expanding cosmos. This is known as The Big Bang Theory.
unlike signal transduction in many other sensory receptors, signal transduction in rods
Photoreceptors, in contrast to most sensory receptor cells, have a hyperpolarization response to stimulation and a depolarization response to inhibition. This indicates that when the cell is not activated, glutamate is constantly released; but, when the cell is triggered, release ceases.
What occurs when light impinges on a rod?As I previously stated, if a light ray strikes rhodopsin as it enters the eye and strikes a rod, it will really start a phototransduction cascade that causes the rod to fire an action potential. In a cone, the identical procedure takes place.
Cones and rods provide visual signals to bipolar cells, which send them on to ganglion cells. The retina itself is where a significant portion of visual information processing takes place.
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primary producers are present in every biome, including the deep sea. how can primary producers exist in the deep sea when sunlight does not penetrate to these depths?
Primary producers can exist in the deep sea when sunlight does not penetrate to these depths because primary producers in the deep sea use energy from chemical reactions to drive the reduction of carbon dioxide to organic compounds.
In the field of biology, primary producers can be described as organisms that can make their own food by reducing carbon dioxide in the presence of sunlight.
However, there are primary producers present in the deep sea that do not require sunlight for the production of food or organic compounds. This is because the primary producers that are present in the deep sea have the ability to derive energy from chemical reactions that will reduce carbon dioxide to produce organic compounds from it. These organic compounds can be used as a source of energy.
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