The nth term of an arithmetic sequence is :
[tex]a_n=a_1+d(n-1)[/tex]From the problem, we have :
[tex]\begin{gathered} a_5=4x-3 \\ a_9=12x+9 \end{gathered}[/tex]Substitute a5 and n = 5 :
[tex]\begin{gathered} a_n=a_1+d(n-1) \\ a_5=a_1+d(5-1) \\ 4x-3=a_1+4d \end{gathered}[/tex]Rewrite the equation as d in terms of x and a1 :
[tex]\begin{gathered} 4x-3=a_1+4d \\ 4x-3-a_1=4d \\ d=\frac{4x-3-a_1}{4} \end{gathered}[/tex]Subsitute a9 and n = 9
[tex]\begin{gathered} a_n=a_1+d(n-1) \\ a_9=a_1+d(9-1) \\ 12x+9=a_1+8d \end{gathered}[/tex]Rewrite the equation as d in terms of x and a1 :
[tex]\begin{gathered} 12x+9=a_1+8d \\ 12x+9-a_1=8d \\ d=\frac{12x+9-a_1}{8} \end{gathered}[/tex]Now, equate two equations of d :
[tex]\begin{gathered} \frac{4x-3-a_1}{4}=\frac{12x+9-a_1}{8} \\ 8(4x-3-a_1)=4(12x+9-a_1) \\ 32x-24-8a_1=48x+36-4a_1 \\ 4a_1-8a_1=48x+36-32x+24 \\ -4a_1=16x+60 \\ a_1=-4x-15 \end{gathered}[/tex]The answer is a1 = -4x-15
If the 5th term of an arithmetic sequence is a5=4x−3. The 9th term of the sequence is a9=12x+9. The first term of the sequence is -4x-15
What is Sequence?a sequence is an enumerated collection of objects in which repetitions are allowed and order matters.
The nth term of AP
aₙ=a+(n-1)d..(1)
From give we have,
a₅=4x−3
a₉=12x+9.
Substitute n=5 in (1)
a₅=a+4d
4x-3=a+4d
4d=4x-3-a
d=4x-3-a/4...(2)
Substitute n=9 in (1)
a₉=a+8d
12x+9=a+8d
12x+9-a/8=d..(3)
Equate 2 and 3
4x-3-a/4=12x+9-a/8
8(4x-3-a)=4(12x+9-a)
32x-24-8a=48x+36-4a
32x-24-8a-48x-36+4a=0
-16x-4a-60
-16x-60=4a
a=-4x-15
Hence the first term of the AP sequence is -4x-15
To learn more on Sequence click:
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The hallway of an apartment building is 44 feet long
and 6 feet wide. A landlord has 300 square feet of carpet. Does she have
enough carpet to cover the hallway? Explain.
Answer:
Yes, there is enough carpet to cover the hallway. We know this because the area of the floor is shown as 44 times 6, which equals 264 feet. With 300>264, there is enough feet of carpet to cover
Step-by-step explanation:
44 times 6 = 264
Part A: Show all work to solve the quadratic equation x2 − 12x + 35 = 0 by factoring.Part B: Using complete sentences, explain what the solutions from Part A represent on the graph.
Answer:
A) Notice that:
[tex]\begin{gathered} x^2-12x+35=x^2+(-5-7)x+(-5)(-7) \\ =x^2-5x-7x+(-5)(-7)=x(x-5)-7(x-5) \\ =(x-7)(x-5)\text{.} \end{gathered}[/tex]Therefore:
[tex]x^2-12x+35=0\text{ if and only if x=7 or x=5.}[/tex]B) The solutions from part A represent the x-coordinates of the x-intercepts of the graph of the function
[tex]f(x)=x^2-12x+35.[/tex]What is the volume of this rectangular prism? 5/3 cm 1/4 cm 3/2 cm
The volume of the prism can be determined as,
[tex]\begin{gathered} V=\frac{5}{3}cm\times\frac{1}{4}cm\times\frac{3}{2}cm \\ V=\frac{5}{8}cm^3 \end{gathered}[/tex]Thus, the required volume is 5/8 cubic centimeters.
a/5 + 8<13 please help
We have the inequality
[tex]\frac{a}{5}+8<13[/tex]solving for a, we have
[tex]\begin{gathered} \frac{a}{5}+8<13 \\ \frac{a}{5}<13-8 \\ \frac{a}{5}<5 \\ a<5\cdot5 \\ a<25 \end{gathered}[/tex]Then a has to be less than 25. Written the solution in interval form we have:
[tex](-\infty,25)[/tex]PLESSS HELP I NEED HELP PLESS HELP I NEEED HELP
For this exercise you need to remember that the area of a triangle can be calculated with the following formula:
[tex]A=\frac{bh}{2}[/tex]Where "b" is the base of the triangle and "h" is the height of the triangle.
Analyzing the information given in the exercise, you can identify that, in this case:
[tex]\begin{gathered} b=x=11units \\ h=7units \end{gathered}[/tex]Then, knowing these values, you can substitute them into the formula and then evaluate, in order to find the area of the triangle. This is:
[tex]\begin{gathered} A=\frac{(11units)(7units)}{2} \\ \\ A=\frac{77units^2}{2} \\ \\ A=38.5units^2 \end{gathered}[/tex]The answer is: Option B.
the sum of 2 numbers is 30. the sum of the squares of the two numbers is 468 what is the product of the two numbers
Take x and y as the 2 numbers
Define the equation that represents each situation
The sum of 2 numbers is 30
[tex]x+y=30[/tex]The sum of the squares of the numbers is 468
[tex]x^2+y^2=468[/tex]Complete the square in the second equation (don't forget to write
HEL LE Maria has 36 episodes of Grey's Anatomy to watch with her friends. They watch 3 episodes each day. Which of the following equations represents the number days, d, it took for them to have 21 episodes left? 0210 - 3 = 36 O 21 - 3d = 36 36 - 3d = 21 36 + 3d = 21 LE
Total episodes: 36
Episodes watched per day: 3
Number of days: d
To represents the number of days, d, it will take for them to have 21 episodes left:
Subtract the episodes watched per day (3d) to the total episodes (36), and that expression must be equal to 21:
36-3d=21
Evaluate each expression using the graphs of y=f(x) and y = g(x) shown below.(a) (gof)(-1) (b) (gof)(0) (c) (fog) - 1) (d) (fog)(4)
Answer:
a) 5
b) 6
c) -2
d) -3
Explanation:
Given:
a) From the graph, we can see that f(-1) = 1 and g(1) = 5, so we'll have that;
[tex](g\circ f)(-1)=g(f(-1))=g(1)=5[/tex]b) From the graph, we can notice that f(0) = 0, g(0) = 6, so we'll have that;
[tex](g\circ f)(0)=g(f(0))=g(0)=6[/tex]c) From the graph, we can notice that g(-1) = 4 and f(4) = -2, so we'll have that;
[tex](f\circ g)(-1)=f(g(-1))=f(4)=-2[/tex]d) From the graph, we can see that g(4) = 3 and f(3) = -3, so we'll have that;
[tex](f\circ g)(4)=f(g(4))=f(4)=-3[/tex]I am in alternative school I am a 12th grader I dropped out Beginning 10th grade then came back to school 12th grade I have applied math I have no clue what I'm doing I'm scared for my finals in May I need help
we have the expression
4÷5×6+7×55
Remember that
Applying PEMDAS
P ----> Parentheses first
E -----> Exponents (Powers and Square Roots, etc.)
MD ----> Multiplication and Division (left-to-right)
AS ----> Addition and Subtraction (left-to-right)
so
step 1
Multiplication and Division (left-to-right)
5x6=30
7x55=385
substitute in the given expression
4÷30+385
step 2
Multiplication and Division (left-to-right)
4÷30=0.13
substitute
0.13+385
step 3
Addition and Subtraction (left-to-right)
0.13+385=385.13
therefore
the answer is 385.13Which of the following statements about the Real Number System is always true?A Rational numbers include irrational numbers.B A number that is an integer is also a whole number and a natural number.C A number that is a whole number is also an integer and a rational Fimber.Tmber.D A number that is a whole numbers is also a natural number.
C
1) Let's draw a sketch to better understand this:
2) So, based on that we can say that
A number that is a Whole number is also an integer and a Rational Number.
Whole numbers are counting number with the 0 included
Integers numbers are whole numbers and the negative numbers
Rational numbers are any number that can be written as a ratio like 2, (2/1), 3/2, 5, 6/7, etc.
So whole numbers are integer numbers and rational ones simultaneously.
For example 2, 3, etc.
NO -6 -10 Use the graph to complete the function table. Input Output -7 1 5 Submit
In order to complete the function table, we just need to locate the input values in the x-axis and then find the corresponding values of y in the line.
For x = -7, we have y = 9
For x = 1, we have y = -3
For x = 5, we have y = -9
So the output values for the table are
Third-degree, with zeros of -3,-1, and 2 and passes through the point (3,6)
Since the polynomial must have zeroes at x=-3, x=-1, x=2, then, we can write it as a combination of the factors (x+3), (x+1), (x-2):
[tex]p(x)=k(x+3)(x+1)(x-2)[/tex]The constant k will help us to adjust the value of the polynomial when x=3:
[tex]\begin{gathered} p(3)=k(3+3)(3+1)(3-2) \\ =k(6)(4)(1) \\ =24k \end{gathered}[/tex]Since p(3) must be equal to 6, then:
[tex]\begin{gathered} 24k=6 \\ \Rightarrow k=\frac{6}{24} \\ \Rightarrow k=\frac{1}{4} \end{gathered}[/tex]Therefore, the following polynomial function has zeroes at -3, -1 and 2, and passes through the point (3,6):
[tex]p(x)=\frac{1}{4}(x+3)(x+1)(x-2)[/tex]A 20% tip on a $26.00 dinner bill ishow much money?
Mela, this is the solution:
Dinner bill = $ 26
Tip = 20% or 0.2
Tip = 26 * 0.2
Tip = $ 5.20
An experiment was conducted to determine whether a deficiency of carbon dioxide in the soil affects the phenotype of peas. Lisphenotype codes where 1 = smooth-yellow, 2 = smooth-green, 3 = wrinkled-yellow, and 4 = wrinkled-green. Do the results make1 1 3 2 1 2. 4 2 3 1 3 3 3 3A. The mode phenotype code is(Use a comma to separate answers as needed.)Help me solve thisView an exampleGet more help210SongOLD
Step 1
The mode is the value that occurs most often. The mode is the only average that can have no value, one value or more than one value. When finding the mode, it helps to order the numbers first.
For this qustion , the number code that occurs most are/is;
[tex]3[/tex]The mode phenotype code = 3 and this represents wrinkled yellow
Write an equation for the line that contains (-32, -12) and is perpendicularto the graph -8x + 10y = 40Can anyone that KNOWS the answer help?
The first step is finding the slope of the equation -8x + 10y = 40.
To do so, let's put this equation in the slope-intercept form: y = mx + b, where m is the slope.
So we have:
[tex]\begin{gathered} -8x+10y=40 \\ -4x+5y=20 \\ 5y=4x+20 \\ y=\frac{4}{5}x+4 \end{gathered}[/tex]Then, since the line we want is perpendicular to this given line, their slopes have the following relation:
[tex]m_2=-\frac{1}{m_1}[/tex]So, calculating the slope of the line, we have:
[tex]m_2=-\frac{1}{\frac{4}{5}}=-\frac{5}{4}[/tex]Finally, our equation has the point (-32, -12) as a solution, so we have:
[tex]\begin{gathered} y=mx+b \\ y=-\frac{5}{4}x+b \\ -12=-\frac{5}{4}\cdot(-32)+b \\ -12=-5\cdot(-8)+b \\ -12=40+b \\ b=-12-40 \\ b=-52 \end{gathered}[/tex]So our equation is y = (-5/4)x - 52
Use the Law of Sines to find the indicated side x. (Assume a = 400. Round your answer to two decimal places.)
The law of sines is given by:
a/sinA = b/sinB = c/sinC
Take into account that in the given problem you need to know what is the measure of angle C, to be able to use the law of sines.
Consider that the sum of the interioiro angles of a triangle is 180°. Then, you have:
m∠C + 98.4° + 24.6° = 180°
m∠C + 123° = 180°
m∠C = 180° - 123°
m∠C = 57°
Next, use the law of sines with sides a and x, angle A and C:
a/sinA = x/sinC solve for x
(a/sinA)(sinC) = x
x = (a/sinA)(sinC) replace the values of known parameters (a = 400)
x = (400/sin98.4°)(sin57°)
x = 339.106
Hence, the length of side x is x = 339.106
Determine if each of the following relationships form a function.(1,1), (3,2), (5,4), (-9,6)
Determine if each of the following relationships form a function.
(1,1), (3,2), (5,4), (-9,6)
we know that
A relationship between x and y form a function, if for one value of x there is only one value of y
In this problem we have that
for one value of x there is only one value of y
therefore
Yes, form a function
Consider the sequence below:-2,1,6,13,22, ....What explicit expression can be used to find the nth term of this sequence?
Answer:
f(n)=n²-3
Explanation:
In the sequence:
[tex]-2,1,6,13,22,...[/tex]First, we find the difference between the terms.
[tex]\begin{gathered} 1-(-2)=3 \\ 6-1=5 \\ 13-6=7 \\ 22-13=9 \end{gathered}[/tex]It is observed that the difference between successive terms is the addition of consecutive odd numbers.
This is an example of a quadratic sequence.
The general form of a quadratic sequence is:
[tex]\begin{gathered} f(n)=an^2+bn+c \\ f(1)=-2 \\ \implies a+b+c=-2 \\ f(2)=1 \\ \implies4a+2b+c=1 \\ f(3)=6 \\ \implies9a+3b+c=6 \end{gathered}[/tex]If we solve the system of equations:
[tex]\begin{gathered} a+b+c=-2 \\ 4a+2b+c=1 \\ 9a+3b+c=6 \\ a=1,b=0,c=-3 \end{gathered}[/tex]The explicit expression for this sequence is:
[tex]f(n)=n^2-3[/tex]Sec 0=9/4, 0 in quadrant 4. Find tan 0. Show your work
Determine the value of angle theta.
[tex]\begin{gathered} \sec \theta=\frac{9}{4} \\ \theta=\sec ^{-1}(\frac{9}{4}) \\ =296.3878\text{ (As }\theta\text{ lie in fourth quadrant)} \end{gathered}[/tex]Determine the value of tan theta.
[tex]undefined[/tex]A) Find the points of intersection between the curve y = x(x - 1) (x - 2) and x-axis.
To find the intersection of the curve
[tex]y=x(x-1)(x-2)[/tex]And the x-axis, we first have to notice that the x-axis is the same as the line:
[tex]y=0[/tex]Now, we have a system of two equations.
If we substitute y = 0 into the first, we have:
[tex]x(x-1)(x-2)=0[/tex]Now, for this equation to be true, one of the factors, "x", "(x-1)" or "(x-2)" has to be zero.
So, we will have three solutions:
[tex]\begin{gathered} x=0 \\ x-1=0\leftrightarrow x=1 \\ x-2=0\leftrightarrow x=2 \end{gathered}[/tex]And since these are on the x-axis, we already know that the y values for them are all y = 0.
Thus, the points of intersections are:
[tex]\begin{gathered} (0,0) \\ (0,1) \\ (0,2) \end{gathered}[/tex]10c - 6(2c - 1) = -2( c- 3) Your answer
10c - 6(2c - 1) = -2( c- 3)
[tex]10c-6\left(2c-1\right)=-2\left(c-3\right)[/tex]in this case, we have a equation with an unknown value (c9
Step 1
operate to eliminate ()
[tex]\begin{gathered} 10c-(6\cdot2c)-(6)(-1)=-2c+6 \\ 10c-12c+6=-2c+6 \\ 10c-12c+2c=6-6 \\ 12c-12c=0 \\ 0=0 \end{gathered}[/tex]it means, that for any value of x, it will work
this equation has infinite solutions
What are all of the answers for these questions? Use 3 for pi. Please do not use a file to answer, I cannot read it.Question 8.
To calculate the area of the doughnut, we need to calculate the area of the larger circle and substract the area of the smaller circle.
The area of a circle can be calculated using its radius:
[tex]A=\pi r^2[/tex]The diameter of the larger circle is 6cm which meand that its radius is half as large, so the radius is 3 cm and the area of the larger circle is:
[tex]A_L=\pi3^2=9\pi[/tex]Area of 9π cm².
The smaller one have a diameter of 2 cm, so its radius is half as large, radius of 1 cm.
So, the area of the smaller circle is:
[tex]A_S=\pi1^2=\pi[/tex]Area of π cm².
The total shaded area is, then, the area of the larger minus the area of the smaller.
So, the shaded area is:
[tex]\begin{gathered} A=A_L-A_S \\ A=(9\pi-\pi)cm^2 \\ A=8\pi cm^2 \\ A\approx(9\cdot3)cm^2 \\ A\approx27cm^2 \end{gathered}[/tex]If ST = x + 4, TU = 10, and SU = 9x + 6, what is ST?
Given:
[tex]\begin{gathered} ST=x+4 \\ \\ TU=10 \\ \\ SU=9x+6 \end{gathered}[/tex]Find-:
The value of "x."
Explanation-:
The line of property
[tex]SU=ST+TU[/tex]Put the value is:
[tex]9x+6=x+4+10[/tex][tex]\begin{gathered} 9x+6=x+14 \\ \\ 9x-x=14-6 \\ \\ 8x=8 \\ \\ x=\frac{8}{8} \\ \\ x=1 \end{gathered}[/tex]So, the value of "x" is 1.
1 5/6 - (-2 4/5)[tex]1 \frac{5}{6} - ( - 2 \frac{4}{5} )[/tex]
We have the following:
[tex]1\frac{5}{6}-(-2\frac{4}{5})[/tex]solving:
[tex]\begin{gathered} 1\frac{5}{6}=\frac{11}{6} \\ 2\frac{4}{5}=\frac{14}{5} \\ \frac{11}{6}+\frac{14}{5}=\frac{11\cdot5+14\cdot6}{30}=\frac{55+84}{30}=\frac{139}{30} \\ \frac{139}{30}=4\frac{19}{30} \end{gathered}[/tex]The answer is 4 19/30
two segments are interesting outside the circle, choose the correct equation to set up before having to solve for y
Option (C)
Given:
Two segments are interesting outside the circle.
The objective is to find the correct equation.
Since the two lines drawn from a point outside the circle passes through two points in a circle, the line is call secant line.
Consider the given figure as,
If two secant line is drawn from a point outside the circle, the equation wil be,
[tex]a(a+b)=c(c+d)[/tex]Now, substitute the given values in the above formula,
[tex]\begin{gathered} 4(4+6)=2(2+y) \\ 4(10)=2(2+y) \end{gathered}[/tex]Hence, option (C) is the correct answer.
The principal is trying to come up with a playground policy to protect students from the risk of getting heatstroke on especially hot and humid days. If that's her goal, at which temperature should students stop being allowed outside for recess?A 80 degrees B 90 degrees C 105 degreesD 130 degrees
The temperature should be the following:
*Temperatures greater than 80° on hot or humid days should be the temperature limit.
Convert Following expression in radical form into an exponential expression in rational form, multiply and simplify then divide you do not need to evaluate just put in simplest form
9.
[tex]\frac{\sqrt[]{5^7}\cdot\sqrt[]{5^6}}{\sqrt[5]{5^3}}[/tex]Using the following properties:
[tex]\begin{gathered} x^a\cdot x^b=x^{a+b} \\ a^{-x}=\frac{1}{a^x} \\ \sqrt[z]{x^y}=x^{\frac{y}{z}} \end{gathered}[/tex][tex]\frac{\sqrt[]{5^7}\cdot\sqrt[]{5^6}}{\sqrt[5]{5^3}}=5^{\frac{7}{2}}\cdot5^{\frac{6}{2}}\cdot5^{-\frac{3}{5}}=5^{\frac{7}{2}+\frac{6}{2}-\frac{3}{5}}=5^{\frac{59}{10}}[/tex]Answer:
5 7/5
Step-by-step explanation:
As you can see there is a divisions sign so you will start there.
The square root of 5^6 will turn into 5 6/2 divided by 5 3/5.
You want to find the LCD for the denominator. That will be 10, 6 divided by 3 equals 2 so you will have 5 7/2 times 5 2/10. You then change the two to a 10 and multiply the 7 and 2 which will become 5 14/10.
Once simplified the answer is 5 7/5.
Hope this helps :)
Hi I need help with this question please thank you!
To answer this question we will factorize each term.
Notice that:
[tex]20x^4y=5xy(4x^3),[/tex][tex]10x^3y^3=5xy(2x^2y^2),[/tex][tex]5xy^2=5xy(y).[/tex]Therefore, the greatest common factor of the terms is:
[tex]5xy\text{.}[/tex]Answer:
[tex]5xy\text{.}[/tex]
Which of the following functions best describes this graph?O A. y=x2- 8x+15O B. y=x+8x+15O c. y = x + x - 12O D. y=x2-5x+6
We will investigate how to best represent a parabolic graph using a function description.
All parabolas are denoted as either a " U " or inverted " U ". There are two principal parameters of a parabola. The vertex i.e the maximum or minimum point attained by the parabola. The line of symmetry or focus point: The line of symmetry can either be vertical or horizontal but it always passes through the focus point.
We are given a graph of a parabola that has two zeros which can be read off from the plot.
We will locate these zeros and write them down:
[tex]\begin{gathered} x\text{ = 3} \\ x\text{ = 5} \end{gathered}[/tex]All parabolas are expressed by a quadratic polynomial function. The quadratic polynomial can be expressed in factorized form as follows:
[tex](\text{ x - }\alpha\text{ )}\cdot(x\text{ - }\beta\text{ )}[/tex]Where,
[tex]\begin{gathered} \alpha\text{ = 3 ( First Zero )} \\ \beta\text{ = 5 , ( Second Zero )} \end{gathered}[/tex]We will express our located zeros in the factorized quadratic expressed above:
[tex](\text{ x - 3 )}\cdot(x\text{ - 5 )}[/tex]Then we will try to solve the parenthesis and expand the factorized form as follows:
[tex]\begin{gathered} -5\cdot(x\text{ - 3 ) + x}\cdot(x\text{ - 3 )} \\ -5x+15+x^2\text{ - 3x} \end{gathered}[/tex]Group the similar terms and simplify:
[tex]x^2\text{ - 8x + 15 }[/tex]Therefore the function that best describes the given plot is:
[tex]y=x^2\text{ -8x + 15 }\ldots\text{ Option A}[/tex]I can’t figure this out. Getting different answer than listed. Please help with attached pic.
Solution
We are required to use synthetic division to rewrite the expression
[tex](x^3+6x^2-5)\div(x+2)[/tex]The synthetic division is shown below
Re-write the result in polynomial form
[tex]=x^2+4x-8+\frac{11}{x+2}[/tex]The answer is
[tex]=x^2+4x-8+\frac{11}{x+2}[/tex]