Answers
ANSWER
a) The current at P is 1.0A and it is moving towards the node.
b) A total of 1C charges flow through P in 1.0 seconds
EXPLANATION
a) To find this, we have to apply Kirchoff's node law which states that:
Therefore, we have that:
[tex]4.0+3.0-8.0+P=0[/tex]Solve for P:
[tex]\begin{gathered} 4.0+3.0-8.0+P=0 \\ -1.0+P=0 \\ \Rightarrow P=1.0A \end{gathered}[/tex]This implies that the current at point P is 1A and it is moving towards the node (in the left direction).
b) To find the electric charge that flows through P in 1.0s, we have to use the formula for current:
[tex]I=\frac{q}{t}[/tex]where I = current, q = electric charge and t = time
Therefore, we have to find q:
[tex]\begin{gathered} q=I\cdot t \\ \Rightarrow q=1.0\cdot1.0 \\ q=1.0C \end{gathered}[/tex]Therefore, a total of 1C charges flow through P in 1.0 seconds.
Related Questions
physics need help picture below. Consider the position vs time graph for objects A and B below.
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The motion of the object B is uniform and having constant velocity and, the motion of the object A is non-uniform throughout. Object A doesn't having constant velocity.
The siren of a burglar alarm system has a frequency of 960Hz . During a patrol a security officer, traveling in his car , hears the siren of the alarm of a house and approaches the house at a constant velocity. A detector in his car registers the frequency of the sound as 1000 Hz . Calculate the speed at which the patrol car approaches the house . Use the speed of sound in air as 340m.s
Answers
Answer:
14.2 m/s
Explanation:
When the source and receiver are getting closer, we can use the following equation:
[tex]f_o=(\frac{v+v_o}{v-v_s})f_s[/tex]Where fo is the observed frequency, fs is the emitted frequency, vo is the speed of the observed, vs is the speed of the source, and v is the speed of the sound. Solving for vo, we get:
[tex]\begin{gathered} \frac{f_o}{f_s}=\frac{v+v_o}{v-v_s} \\ \\ \frac{f_o}{f_s}(v-v_s)=v+v_o \\ \\ \frac{f_o}{f_s}(v-v_s)-v=v_o \\ \\ v_o=\frac{f_o}{f_s}(v-v_s)-v \end{gathered}[/tex]Then, replacing v = 340 m/s, vs = 0 m/s, fs = 960 Hz, and fo = 1000 Hz, we get:
[tex]\begin{gathered} v_r=\frac{1000}{960}(340-0)-340 \\ \\ v_r=14.2\text{ m/s} \end{gathered}[/tex]Therefore, the speed of the patrol car is 14.2 m/s
After traveling for 6.0 seconds, a runner reaches a speed of 12 m/s after starting from rest. What is the runner’s acceleration?A. .5 m/s2B. 6 m/s2C. 72 m/s2D. 2 m/s2
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We can find the acceleration as follows:
[tex]\begin{gathered} a=\frac{\Delta v}{\Delta t} \\ so: \\ a=\frac{12-0}{6-0} \\ a=\frac{12}{6} \\ a=2m/s^2 \end{gathered}[/tex]Answer:
D. 2 m/s^2
help please asap !looking for the answer to number 1 Its assigned homework for online that I don’t understand
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Let's explain what a simple machine is.
Definition:
A simple machine can be defined as a mechanical device used for applying force and doing work.
It changes the direction and magnitude of force.
In a simple machine there is no combination of parts and they have very few movable parts.
Types of Simple machines:
• Screw
,• Pulley
,• Wedge
,• Wheel and axel
,• Lever
,• Inclined plane
Example of Screw is a screw.
Example of a pulley is an elevator
Example of a wedge is
If the voltage between 2 plates is 10 V and they are separated by 2 m, what is the electric field? A. 10 V/m B. 5 V/m C. 2 V/m D. 20 V/mWhat does it mean when there is a straight line on a current vs voltage graph?A. Current is proportional to the Voltage squared.B. Current and Voltage are not proportional.C. Current and Voltage are directly proportional.D. Current and Voltage are inversely proportional.
Answers
1) We will have that:
[tex]E=\frac{kQ}{r^2}[/tex]So:
[tex]E=5V/m[/tex]2) We will have the following:
It would mean that:
Current and voltage are directly proportional.
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Answer:
u nor get work at all just dey post..
Find the angular velocity (in rad/s) of a motor that is developing 37.0 W of power with a torque of 5.5 Nm.
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ANSWER
[tex]6.72\text{ rad/s}[/tex]EXPLANATION
Parameters given:
Power, P = 37.0 W
Torque, T = 5.5 Nm
To find the angular velocity, we apply the relationship between torque and power:
[tex]P=\tau\cdot\omega[/tex]where ω = angular velocity
Therefore, the angular velocity of the motor is:
[tex]\begin{gathered} \omega=\frac{P}{\tau} \\ \omega=\frac{37}{5.5} \\ \omega=6.72\text{ rad/s} \end{gathered}[/tex]That is the answer.
Keplers third law of planetary motion describes the relationship between the semi-major axis of a planet’s orbit and its (Fill in the blank)
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Kepler's third law states that:
The squares of the orbital periods of the planets are directly proportional to the cubes of the semi-major axes of their orbits.
Therefore, it states the relationship between the semi major axis of the planet's orbit and its period. And the correct choice is C
When will the force be balance and when will the force won’t be balance [unbalance]
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A force is a pull or push of an object that causes it to accelerate. When there are more than one force acting on a body then we call this a system of forces.
Suppose that we have the following system of two forces:
Forces "a" and "b" are acting in opposite directions. If the forces have the same magnitude then the total acceleration in the object will be zero. When a system of forces produces no acceleration on an object we call this balanced force.
If the magnitude of the forces is different then by Newton's second law we have;
[tex]F_a-F_b=ma[/tex]Where "m" is mass and "a" is acceleration. A system where the sum of forces is the product of mass by acceleration is called an unbalanced force.
How much potential energy does a person of mass 50 kg have if they are standing at the top of a building that is 54.8 m high? Submit your answer in exponential form.
Answers
ANSWER:
2.69 x 10^4 J
STEP-BY-STEP EXPLANATION:
Given:
Mass (m) = 50 kg
Height (h) = 54.8 m
The potential energy is calculated by the following formula:
[tex]E=m\cdot g\cdot h[/tex]We replace and determine the value of the energy:
[tex]\begin{gathered} E=50\cdot9.8\cdot54.8 \\ \\ E=26852=2.69\cdot10^4\text{ J} \end{gathered}[/tex]The potential energy is equal to 2.69 x 10^4 joules.
A person travels by car from one city to another with different constant speeds between pairs of cities. She drives for 15.0 min at 90.0 km/h, 7.0 min at 65.0 km/h, and 40.0 min at 40.0 km/h and spends 40.0 min eating lunch and buying gas.(a) Determine the average speed for the trip. km/h(b) Determine the distance between the initial and final cities along the route. km
Answers
a)
To determine the average speed we need to determine the time the person travels and the distance. Since we need the average speed in km/h we need to convert all the times given into hours, let's do this:
[tex]\begin{gathered} 15\text{ min}\cdot\frac{1\text{ h}}{60\text{ min}}=0.25\text{ h} \\ 7\text{ min}\cdot\frac{1\text{ h}}{60\text{ min}}=\frac{7}{60}\text{ h} \\ 40\text{ min}\cdot\frac{1\text{ h}}{60\text{ min}}=\frac{2}{3}\text{ h} \end{gathered}[/tex]Now, that we have the time in each interval of the motion we can determine the distance is travel in each of them:
[tex]\begin{gathered} d_1=90(0.25)=22.5 \\ d_2=65(\frac{7}{60})=7.583 \\ d_3=40(\frac{2}{3})=26.667 \end{gathered}[/tex]This means that the total distance the person traveled is 56.8 km (we use three significant figures as shown in the problem).
Once we know this we need to find the time it takes to make this, from our previos discussion and adding the 40 minutes the person took to eat we have that the total time was 1.7 h, then the average speed is:
[tex]v=\frac{56.8}{1.7}=33.4[/tex]Therefore, the average speed on the trip was 33.4 km/h
b)
From point a we know that the distance was 56.8 km
Two 4-1 resistors are connected in parallel to a 12-V bat-tery. Use the fact that the voltage across each of the resis-tors is 12 V to find the total current through the battery.What single resistor, if connected to the battery alone(called the equivalent resistance), would draw this samecurrent?
Answers
Given data
*The given resistors are
[tex]R_1=R_{2_{}}_{}_{}=4\text{ ohm}[/tex]*The given battery voltage is V = 12 V
The equivalent resistance in parallel combination is calculated as
[tex]\begin{gathered} R_{eq}=\frac{R_1\times R_2}{R_1+R_2} \\ =\frac{4\times4}{4+4} \\ =\frac{16}{8} \\ =2\text{ ohm} \end{gathered}[/tex]The total current flows through the battery is calculated as
[tex]\begin{gathered} I=\frac{V}{R_{eq}} \\ =\frac{12}{2} \\ =6\text{ A} \end{gathered}[/tex]How much heat is necessary to change 480 g of ice at -19°C to water at 20°C? answer in:____kcal
Answers
ANSWER
[tex]18.05\text{ }kcal[/tex]EXPLANATION
The amount of heat necessary to change the ice to water is given by:
[tex]Q=m(c_{ice}\Delta T_{ice}+L+c_{water}\Delta T_{water})[/tex]where m = mass of ice = 480 g = 0.48 kg
c(ice) = specific heat capacity of ice = 2108 J/kg/K
ΔTice = change in temperature of ice = 0 - (-19) = 19 K or 19 °C
L = latent heat of fusion of ice = 33600 J/k
c(water) = specific heat capacity of water = 4186 J/kg/K
ΔTwater = change in temperature of water = 20 - 0 = 20 K or 20 °C
Therefore, the heat necessary is:
[tex]\begin{gathered} Q=0.48([2108*19]+33600+[4186*20]) \\ \\ Q=0.48(40052+33600+83720)=0.48*157372 \\ \\ Q=75538.56\text{ }J \end{gathered}[/tex]Convert this to kcal:
[tex]\begin{gathered} 1\text{ }J=\frac{1}{4184}\text{ }kcal \\ \\ 75538.56\text{ }J=\frac{75538.56}{4184}\text{ }kCal=18.05\text{ }kcal \end{gathered}[/tex]That is the answer.
Harmonics are multiples of the fundamental. If the fundamental frequency is 53 Hz, with what frequency will the 8th harmonic resonate?
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Take into account that the relation in betwee the fundamental and the harmonics is given by:
f = fo·n
where f is the frecuency of the nth harmonic and fo is the fundamental.
Then, for the 8th harmonic (n = 8) and a fundamental of 53 Hz, you obtain for f:
f = (53 Hz)(8)
f = 424 Hz
Hence, the frequency of the 8th harmonic is 424 Hz
1. An object 2.25 mm high is 8.5 cm to the left of a convex lens of 5.5-cm focal length.
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According to problem ( considering sign convention for convex lens)
height of object = 2.25 mm;
object distance(u)= - 8.5 cm
focal length (f)= 5.5 cm
image distance(v)= ?
Using lens formula
[tex]\begin{gathered} \frac{1}{f}=\text{ }\frac{1}{v}-\frac{1}{u}; \\ \therefore\frac{1}{5.5}=\text{ }\frac{1}{v}\text{ -}\frac{1}{-8.5} \\ \frac{1}{5.5}=\frac{1}{v}\text{ +}\frac{1}{8.5}; \\ \frac{1}{v}=\frac{1}{5.5}-\frac{1}{8.5}=\frac{3}{5.5\times8.5}=\frac{3}{46.75} \\ v=\frac{46.75}{3}=15.58\text{ cm} \end{gathered}[/tex]a) Answer is :- Location of image = 15.58cm
Using magnification formula
[tex]\begin{gathered} Magnification\text{ =}\frac{height\text{ }of\text{ }image}{height\text{ of object}}=\frac{v}{u} \\ \therefore Magnification=\text{ }\frac{15.58}{8.5}\text{ =1.83} \\ \therefore\frac{height\text{ }ofimage}{2.25}\text{ =1.83;} \\ \therefore height\text{ of image = 1.83}\times2.25=4.12\text{ mm} \end{gathered}[/tex]b) Height of image = 4.12 mm
C) Magnification= 1.83
A boat travels 60 miles downstream in the same time as it takes it to travel 40 miles upstream. The boat's speed in still water is 20 miles per hour. Find the stream of the current.
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The equation of the boat upstream is 20-s.
The equation downstream is 20+s.
Where s is the speed of the current.
Then, we know that the time spent is equal in both cases, and we also know that time equals distance divided by the speed. So, we express the following.
[tex]\frac{40}{20-s}=\frac{60}{20+s}[/tex]Solve for s.
[tex]\begin{gathered} 40(20+s)=60(20-s) \\ 800+40s=1200-60s \\ 60s+40s=1200-800 \\ 100s=400 \\ s=4 \end{gathered}[/tex]Therefore, the speed of the current is 4 miles per hour.
How do I solve number 5? Answer hing in radians
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Angular velocity is the speed at which an object travels in terms of radians or degrees, not any unit of length.
One full revolution around the sun: 2*pi radians, 365 days
2*pi/365 = 0.0172 rad/day
1 day = 86400 seconds, so to convert from rad/day to rad/s, simply divide by 86400.
0.0172 rad/day = 1.99238 * 10^-7 rad/s
An object is placed 10.0 cm in front of a thin concave lens with a focal length of 18 cm. Calculate the imageposition
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The focal length of a concave lens is expressed as,
[tex]\frac{1}{f}=\frac{1}{u}+\frac{1}{v}[/tex]Here, f is the focal length, u is the distance of object and v is the distance of image.
Plug in the known values,
[tex]\begin{gathered} \frac{1}{18\text{ cm}}=\frac{1}{10.0\text{ cm}}+\frac{1}{v} \\ \frac{1}{v}=\frac{1}{18\text{ cm}}-\frac{1}{10.0\text{ cm}} \\ v=\frac{(18\text{ cm)(10.0 cm)}}{10.0\text{ cm-18 cm}} \\ =-22.5\text{ cm} \end{gathered}[/tex]Thus, the distance of image is -22.5 cm where negative sign indicates that the image will be at the same side of object.
Bella is approaching some congested traffic and wisely slows her Audi from 19.6 m/s to 3.7 m/s at a constant rate of -3.33 m/s/s. How much time elapses before the car is traveling at 3.7 m/s?
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The Time that elapses before the car is traveling at 3.7 m/s is 4.8 s.
What is time?Time is a measure of non-stop, consistent change in our surroundings, usually from a specific viewpoint.
To calculate the time require for the to be traveling at 3.7 m/s, we use the formula below.
Formula:
t = (v-u)/a........... Equation 1Where:
t = Timev = Final velocityu = Initial velocitya = AccelerationFrom the question,
Given:
v = 3.7 m/su = 19.6 m/sa = - 3.33 m/s²Substitute these values into equation 1
t = (19.6-3.7)/-3.33t = -15.9/-3.33t = 4.8 sHence, the time need for the car to start traveling at 3.7 m/s is 4.8 s.
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What is one way that the gravitational force between the moon and the earth would increase?a. If the size of the moon decreased while the distance remained constant.b. If the size of the moon increased while the distance remained constantc. If the size of the earth increased while the distance remained constant.d. both b and c
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Answer:
d. both b and c
Explanation:
If the mass of either object increases, the gravitational attraction between them increases.
F = G m1*m2 / r^2
Where:
F: Force
G = constant
m = masses
r = distance between objects
Mass is directly proportional to the gravitational force.
A car accelerates from from 20m/s to 30m/s in 10s (a) calculate the cars acceleration using v = u+at (b) Draw a velocity-time graph to show the cars motion find the distance it travels by calculating the area under the graph (c) check your answer by using the equation s = ut+1/2seqore
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a.
The cars acceleration is given as
V = u +at
30 = 20 + a * 10
30- 20 = 10*a
acceleration = 1 m/s²
b. The velocity time graph is shown below:
Distance covered (s)= Area under the curve=
20 x 10 + [ (1/2) x 10 x 10 ]
distance = 250 m
C. checking answer
s = ut + (1/2) x at²
s = 20 x 10 + [ (1/2) x 10 x 10 ]
s = 250 meters.
What is acceleration?
Acceleration is described as the rate of change of the velocity of an object with respect to time.
The Velocity-time graph is a plot between Velocity and Time that shows the Motion of the object that moves in a Straight Line. It is given that the magnitude of Velocity at a given instant is equal to its Instantaneous Speed.
On a velocity-time graph a horizontal (flat) line indicates the object is travelling at a constant speed while a straight diagonal line indicates that the object's velocity is varying.
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The small piston of a hydraulic press has an area of 3.2 in2. If the applied force is 2.0 lb, what must the area of the large piston be to exert a pressing force of 795 lb?
Answers
Given data:
The area of the hydraulic press is,
[tex]A_1=3.2in^2[/tex]The applied force is,
[tex]F_1=2\text{ lb}[/tex]The pressing force on the large piston is
[tex]F_2=795\text{ lb}[/tex]Given hydraulic press works on Pascal's law principle.
From the Pascal's law, the equation can be given as,
[tex]\frac{F_1}{A_1}=\frac{F_2}{A_2}[/tex]Here,
[tex]A_2[/tex]is the area of the larger piston.
Substituting the values in the above equation, we get:
[tex]\begin{gathered} \frac{2\text{ lb}}{3.2in^2}=\frac{795\text{ lb}}{A_2} \\ A_2=1272in^2 \end{gathered}[/tex]Thus, the area of the large piston is
[tex]1272in^2[/tex]You want to know the intensity of electric current whose total charge is 35 Coulombs, calculate the intensity if this charge is passed through copper for 7 seconds
Answers
ANSWER
[tex]5A[/tex]EXPLANATION
To find the current intensity, we have to apply the formula for current intensity:
[tex]I=\frac{q}{t}[/tex]where q = charge
t = time
Hence, the current intensity is:
[tex]\begin{gathered} I=\frac{35}{7} \\ I=5A \end{gathered}[/tex]That is the answer.
A 25 kg mass is thrown from the ground to a height of 50 m. (a) find the kineticenergy of the mass at this height.; (b) find the potential energy of the mass at thisheight. ; (C) find the velocity of the mass when it reach the ground.
Answers
Given
m: mass
m = 25 kg
h: height
h = 50 m
Procedure
(a) Kinetic energy is directly proportional to the mass of the object and to the square of its velocity. At this height initial velocity is equal to zero
K = 0 J
(b) The potential energy of any given object is a measurement of its potential to do work, create heat and generate power.
[tex]\begin{gathered} U=mgh \\ U=25\operatorname{kg}\cdot9.8m/s^2\cdot50m \\ U=12250\text{ J} \end{gathered}[/tex](c) When the mass reaches the ground all the potential energy is transformed into kinetic energy.
[tex]\begin{gathered} \frac{1}{2}mv^2=U \\ \frac{1}{2}mv^2=12250J \\ v=\sqrt[]{\frac{2\cdot12250}{25\operatorname{kg}}} \\ v=31.30\text{ m/s} \end{gathered}[/tex]A 0.7kg ball Is thrown and accelerated by 62 m/s. How much force is applied to it? Round your answer to the nearest whole number
Answers
Given:
the mass of the ball is m=0.7 kg.
The acceleration in the ball is
[tex]a=62\text{ m/s}^2[/tex]Required: the force applied on the ball
Explanation:
The force is given by
[tex]F=ma[/tex]here, F is force, m is the mass, and a is the acceleration.
Plugging all the values in the above relation, we get:
[tex]\begin{gathered} F=0.7\text{ kg}\times62\text{ m/s}^2 \\ F=43.4\text{ N} \\ F\approx43\text{ N} \end{gathered}[/tex]Thus, the force on the ball is 43 N.
Win Blonehare and Kent Swimtashore are sail boating in Lake Gustastorm. Starting from rest near the shore, they accelerate with a uniform acceleration of 0.136 m/s/s. How far are they from the shore after 13.6 seconds?
Answers
The distance they from the shore after 13.6 seconds is 12.58 m.
What is distance?Distance is the total movement of an object without any regard to direction
To calculate the distance traveled from the shore, we use the formula below.
Formula:
s = ut+at²/2......... Equation 1Where:
s = Distancet = timeu = Initial velocitya = AccelerationFrom the question,
Given:
u = 0 m/s (from rest)a = 0.136 m/s²t = 13.6 sSubstitute these values into equation 1
s = (0×13.6)+(0.136×13.6²/2)s = 12.58 mHence, the distance traveled from the shore is 12.58 m.
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Ball A of mass mA = 3 kg moves to the right (positive direction) with a velocity 4 m/s, while ball B moves to the left (negative direction) with a velocity -4 m/s. After the collision, A's velocity is -21 m/s and B's velocity is 1 m/s. What is the mass of B?
Answers
Given:
The mass of A is,
[tex]m_A=3\text{ kg}[/tex]The initial velocity of A is,
[tex]u_A=4\text{ m/s}[/tex]The initial velocity of B is,
[tex]u_B=-4\text{ m/s}[/tex]The final velocity of A is,
[tex]v_A=-21\text{ m/s}[/tex]The final velocity of B is,
[tex]v_B=-1\text{ m/s}[/tex]Applying the momentum conservation principle we can write,
[tex]\begin{gathered} m_Au_A+m_Bu_B=m_Av_A+m_Bv_B \\ 3\times4+m_B(-4)=3\times(-21)+m_B\times1 \\ 12-4m_B=-63+m_B \\ 5m_B=75 \\ m_B=15\text{ kg} \end{gathered}[/tex]Hence, the mass of B is 15 kg.
How does the velocity of a falling object change with time? How would you describe the mathematical relationship between velocity and time of a falling object? Explain the answer using your data, graphs, and the kinematic equations.The image below shows the ball stopping at 2 4 6 8 and 10 and how long it took it too stop there
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We will have the following:
First, we can see that the data presented is the following:
Now, from this information we can construct the following graphical relationship between time and distance drawn by the object:
From this we can infer that the relationship between time and distance is linear in nature, and the path of best descripton by linear regression is given by:
Where the approximation is:
[tex]f(x)=2.47204029x-0.4796893103[/tex]We can see the linear relationship that fits the model, from this and the fact that in kinematics the following is true:
[tex]d=v\ast t[/tex]Where "d" is the distace, "v" is the velocity and "t" the time.
From the data, the values of "x" represent the time and thus, the ratio of the function found is the velocity of the object.
In summary, the relationship is linear as per in kinematics, time and distace change proportionally in the data provided; and the approximated velocity of the object was 2.47m/s.
You read about the Air Canada flight, where the grounds crew used the wrong units
and conversion factors to fill the plane's fuel tank leading to it running out of fuel
and having to make a crash landing.
There are many other scenarios besides filling up a gas tank that require accuracy to
prevent serious injury. Several of these were discussed in the lessons. Even you may
have to make critical measurements that could result in a big problem if not done
accurately.
Think of a different scenario (NOT FUEL TANK RELATED) where it would be
important to measure or calculate something correctly.
Describe what would be measured and why it would be important to measure with
accuracy.
Answers
Answer:
no I don't understand it oo
On what behavior of matter does mercury in a glass thermometer depend?Select one:a. Change of color when heated.b. Change of state when heated.c. Change of size when heated. d. Change of mass when heated.
Answers
Since mercury expands with temperature a glass thermometer depends on the change of size when heated, therefore, the answer is c.