Answers
The classifications of the substances are;
Compound
1,2,3
Mixture
4,5,6
Pure substances
1,7,8
Elements and compounds
1
What is a mixture?The term mixture has to do with a substances that is obtained by a combination of two or more substances that are not chemically combined together. We know that on the other hand a compound is formed when there is a combination of elements that are chemically combined together.
When we talk of a pure substances, we are talking of the substances that are composed of only one kind of material. There are also some compounds that we may call compound elements. These are the compounds that are composed of only one kind of element.
The elements and the compounds are pure substances in the sense that they are composed of only one type of material.
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Related Questions
I need help with one of my physics question
Answers
Assume the motion of Oscillator is defined
As y = 2 cos6πt - Sin5πt. If the mass of
Oscillator is 10 gram,
What are the Mascimum and
minimum kinectic energy.
Answers
Explanation:
B. Choose will (‘ll) or (be) going to, whichever is correct or more likely, and one of these verbs (7 marks- half each).
Get out of the building! It sounds like the generator isgoing toexplode.
Roman _____________ early before she reaches 65. She mentioned it at the meeting recently.
A: I think _____________ home across the park.
B: That’s a good idea.
Next year, no doubt, more people _____________ the competition as the prize money increases.
A: Can we meet at 10.00 outside the ILS building?
B: Okay. I_____________ you there.
Don’t sit on that bench, I_____________.
I’m not feeling well. In fact, I think I_____________.
‘Closed over the new year period. This office _____________ on 2nd January’ (a sign on an office window).
I’m sure you _____________ a good time staying with Merga.
We _____________ with Kedija tonight. She’s asked us to be there at 7:00.
‘The 2.35 to Arba Minch_____________ from gate 5’ (announcement at the airport).
I wouldn’t walk across the old bridge if I were you. It looks like it ____________.
I read in the paper that they _____________the price of the gas again.
Do you like my new solar watch? Here, I_____________you how it works.
A: AtoMessay isn’t in his office at the moment.
B: In that case, I_____________him at home.
An elevator uses 100 000J of electrical energy to raise a load of 800 N through a height of 40m in a time of 20s. What fraction of the energy input was NOT transferred to the load? A) 32% B) 68% C) 80%D) 97%
Answers
W: work
F: force required to lift load; F = 800 N
d: distance lifted: d = 40 m
W = Fd = 800*40
W = 32000 J
If 100000J were exerted on a load for which only 32000J was necessary, the other 100000-32000 = 68000J was not transferred to the load.
68000/100000 = 0.68 = 68%
A 50 kW pump is used to pump up water from a mine that is 50 m deep. Find the mass of water that can be lifted by the pump in 1.4 min.
Answers
Given data
*The given power of the pump is P = 50 kW = 50 × 10^3 W
*The given depth is h = 50 m
*The given time is t = 1.4 min = (1.4 × 60) = 84 s
The mass is calculated by the power formula as
[tex]\begin{gathered} P=\frac{W}{t} \\ P=\frac{mgh}{t} \end{gathered}[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} 50\times10^3=\frac{m\times9.8\times50}{84} \\ m=8571.42\text{ kg} \end{gathered}[/tex]Hence, the mass of the water is m = 8571.42 kg
A long, thin wire offers more resistance to an electrical current than a thick, short wire would.TrueFalse
Answers
Resistance is directly proportional to the length of the conductor and inversely proportional to area of cross section.
Thus, the given statement is true.
A racing car of mass 1500 kg, is accelerating at 5.0 m/s2, is experiencing a lift force of 600 N [up}, due to its streamlined shape, and grounding effects of 1000 N [down], due to air dams and spoilers. Find the driving force needed to keep the car going given that μk = 1.0.
Answers
Given data:
* The acceleration of the car is,
[tex]a=5ms^{-2}[/tex]* The mass of the car is,
[tex]m=1500\text{ kg}[/tex]* The force acting on the car in the upward direction is,
[tex]F_1=600\text{ N}[/tex]* The force acting on the car in the downward direction is,
[tex]F_2=1000\text{ N}[/tex]* The coefficient of kinetic friction is,
[tex]\mu_k=1[/tex]Solution:
The weight of the car is,
[tex]\begin{gathered} w=mg \\ w=1500\times9.8 \\ w=14700\text{ N} \end{gathered}[/tex]The normal force acting on the car is,
[tex]\begin{gathered} F_N=w+F_2-F_1 \\ F_N=14700+1000-600 \\ F_N=15100\text{ N} \end{gathered}[/tex]The frictional force acting on the car is,
[tex]\begin{gathered} F_k=\mu_kF_N \\ F_k=1\times15100 \\ F_k=15100\text{ N} \end{gathered}[/tex]According to newton's second law, the force acting on the car is,
[tex]\begin{gathered} F=ma \\ F=1500\times5.0 \\ F=7500\text{ N} \end{gathered}[/tex]The net force acting on the car in terms of the applied force and frictional force is,
[tex]\begin{gathered} F=F_a-F_k \\ F_a=F+F_k \end{gathered}[/tex]Substituting the known values,
[tex]\begin{gathered} F_a=7500+15100 \\ F_a=22600\text{ N} \end{gathered}[/tex]Thus, the driving force required to maintain the motion of the car is 22600 N.
An oxygen atom has the mass of 2.66×10 to the -20/3 G and a glass of water has a mass of 0.050 kg. equation is in the picture
Answers
The number of moles of oxygen atoms that have a mass equal to the mass of a glass of water = 3.1 moles
Explanations:The mass of oxygen atom = The mass of glass water = 0.050kg
[tex]\begin{gathered} \text{Mass of oxygen atom = 0.050 }\times\text{ 1000g} \\ \text{Mass of oxygen atom = }50\text{ g} \end{gathered}[/tex]Use the formula below to calculate the number of moles of oxygen atoms
[tex]\text{Number of moles = }\frac{Mass\text{ in gram}}{\text{Molar mass}}[/tex]Molar mass of oxygen = 16 g/mol
Mass of oxygen atom = 50g
Substitute these values into the formula above
[tex]\begin{gathered} \text{Number of moles = }\frac{50}{16} \\ \text{Number of moles = }3.1\text{ moles} \end{gathered}[/tex]The number of moles of oxygen atoms that have a mass equal to the mass of a glass of water = 3.1 moles
A5 kg box is at the top of a 2.7 m tall frictionless incline as shown in the diagram. It slides to the bottom of the incline, reaching a speed of 7.3m / s . What is the box's kinetic energy at the bottom of the incline? Whats the boxs ptential energy at the top of the incline?
Answers
ANSWER:
Kinetic energy: 133.2 J
Potential energy: 132.3 J
STEP-BY-STEP EXPLANATION:
Gven:
Mass (m) = 5 kg
Height (h) = 2.7 m
Speed (v) = 7.3 m/s
We calculate the kinetic energy and the potential energy using the respective formula in each case, as follows:
[tex]\begin{gathered} E_k=\frac{1}{2}\cdot m\cdot v^2=\frac{1}{2}(5)(7.3)^2=133.2\text{ J} \\ \\ E_p=m\cdot g\cdot h=(5)(9.8)(2.7)=132.3\text{ J} \end{gathered}[/tex]Therefore, the kinetic energy is equal to 133.2 joules and the potential energy is equal to 132.3 joules.
Block 1 (2 kg) is sliding to the right on a level surface at aspeed of 3 m/s. Block 2 (5 kg) is initially at rest, and block 1collides with it. After the collision, block 2 is moving to theright with a speed of 1.5 m/s. Calculate the magnitude anddirection of the velocity of block 1 after the collision.
Answers
Given:
The mass of block 1, m₁=2 kg
The mass of the block 2, m₂=5 kg
The initial velocity of the block 1, u₁=3 m/s
The initial velocity of the block 2, u₂=0 m/s
The velocity of the block 2 after the collision, v₂=1.5 m/s
To find:
The magnitude and direction of the velocity of block 2 after the collision.
Explanation:
From the law of conservation of momentum, the total momentum of blocks before the collision must be equal to the total momentum of the blocks after the collision.
Thus,
[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2[/tex]Where v₁ is the velocity of block 1 after the collision.
On rearranging the above equation,
[tex]\begin{gathered} m_1v_1=m_1u_1+m_2u_2-m_2v_2 \\ \implies v_1=\frac{m_1u_1+m_2u_2-m_2v_2}{m_1} \end{gathered}[/tex]On substituting the known values,
[tex]\begin{gathered} v_1=\frac{2\times3+5\times0-5\times1.5}{2} \\ =-0.75\text{ m/s} \end{gathered}[/tex]The negative sign indicates that block 1 will be sliding to the left after the collision.
Final answer:
Thus the magnitude of the velocity of block 1 after the collision is 0.75 m/s.
And the direction of block 1 after the collision is to the left.
How much lift force will it take to accelerate a 10,000 Kg helicopter upward at a rate of 3 m/s2?
Answers
The amount of force required to lift the helicopter of mass 10000 kg moving with an acceleration of 3 m/s² is 30000 N.
What is force?Force is the product of mass and acceleration.
To calculate the amount of force it will take to lift the helicopter, we use the formula below.
Formula:
F = ma............. EquationWhere:
F = Force required to lift the helicopterm = Mass of the helicoptera = Acceleration of the helicopterFrom the question,
Given:
m = 10000 kga = 3 m/s²Substitute these values into equation 1
F = 10000×3F = 30000 NHence, the amount of force required to lift the helicopter is 30000 N.
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I’m working on this study guide but I’m stock on the first equation
Answers
To find the energy needed to jump from one state to another we just need to subtract the initial state energy to the final state. In this case the final state will have -13.6 eV of energy and the initial state has -122.4 eV of eneregy, then we have:
[tex]-13.6-(-122.4)=108.8[/tex]Therefore, the energy needed is 108.8 eV
Determine whether the statement is true or false.2 ∈ {x | x ∈ N and x is even}Is the statement true or false?❑ True❑ False
Answers
ANSWER
True
EXPLANATION
The set is the set of all the natural even numbers. The natural numbers are {1, 2, 3, 4, ...} and the natural even numbers are {2, 4, 6, 8, ...}. Therefore, it is true that 2 belongs to this set.
4kg of steam is at 100°C and he is removed until there is water at 39°C how much heat is removed
Answers
1024.8 KJ Heat is removed when 4kg of steam is at 100°C and he is removed until there is water at 39°C
Mass =4 kg
ΔT=100−39=61 ∘C
Q=m×C×ΔT
C= specific heat capacity of water =4200J/(kgK)
Q=4×4200×61
=1024800 Joule.
=1024.8KJ
Heat is the amount of energy that flows from one body to another on its own as a result of their different temperatures, as opposed to internal energy, which is the sum of all the molecules' energies within an item. Although it is an energy form, heat is energy in motion. Heat is not a system's property. However, a temperature difference causes the transfer of energy as heat to take place at the molecular level.
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A diver shines a flashlight upward from beneath the water (n=1.33) at an angle of 40.0° to the vertical. At what angle does the light refract through the air above the surface of the water?
Answers
Given:
The refractive index of water, n₁=1.33
The angle of incidence, θ₂=40.0°
To find:
The angle of refraction.
Explanation:
The refractive index of the air is n₂=1
From the snell's law,
[tex]n_1\sin\theta_1=n_2\sin\theta_2[/tex]Where θ₂ is the angle of refraction.
On substituting the known values,
[tex]\begin{gathered} 1.33\sin40.0\degree=1\sin\theta_2 \\ \implies\theta_2=sin^{-1}(\frac{1.33\sin40.0\degree}{1}) \\ =58.75\degree \end{gathered}[/tex]Final answer:
The angle of refraction is 58.75°
At the top of a raised platform, a ball is thrown vertically upward with a speed of 60 m/s. The ball rises up, then falls to the ground below the platform with a downward speed of 90 m/s.(a) For how much time was the ball in free-fall?(b) How far is the platform from the ground?
Answers
Before we begin to answer the question we need to notice that since the gravitaional acceleration will act on the motion this is a uniform accelerated motion. This means that we can use the following equations:
[tex]g=\frac{v_f-v_0}{t}[/tex][tex]y=y_0+v_0t+\frac{1}{2}gt^2[/tex][tex]v^2_f-v^2_0=2g(y-y_0)[/tex]Before we begin we establish that upward is the positve direction, this means that g=-10 m/s^2 and that the velocity of the ball when it reaches the ground below the platform is -90 m/s. We also establis that the origin of motion is at the platform
a)
To determine the time the ball is free-falling we need to know the maximum height the ball reaches before it begins falling.
-Motion from the platform to the maximum height.
In this case the initial velocity is 60 m/s while the final velocity is 0 m/s; furthermore the initial height is zero since our origin is on the platform.
The height it reaches the ball before it starts to fall can be obtained by the third equation:
[tex]\begin{gathered} 0^2-60^2=2(-10)(y-0) \\ -3600=-20y \\ y=-\frac{3600}{20} \\ y=180 \end{gathered}[/tex]Therefore the maximum height is 180 meters.
Now the time it takes the ball to reaches this height is given by the first formula:
[tex]\begin{gathered} -10=\frac{0-60}{t} \\ t=\frac{-60}{-10} \\ t=6 \end{gathered}[/tex]Hence it takes the ball six seconds to reach its maximum height.
Now, we know that in an accelerated uniform motion the time it takes to reach the maximum height is the same as the tame it takes to reach the initial height, therefore it takes 6 seconds for the ball to travel from the maximum height to the platform again.
Now we need to determine the time it takes the ball to fall from the height of the platform to the bottom; in this case the initial velocity is -60 m/s; this comes from the fact that the final velocity is the same at same heights in this kind of motion. Then, using the first formula we know that the time it takes is:
[tex]\begin{gathered} -10=\frac{-90-(-60)}{t} \\ t=\frac{-30}{-10} \\ t=3 \end{gathered}[/tex]Hence, it takes 3 seconds for the ball to travel from the platform to the ground.
Finally we add the three times to determine the total time of the free fall; therefore the time the ball is free falling is 15 seconds.
b)
To determine the height of the platform we can use the fact that the time it takes the ball to fall from this height to the ground is six seconds, then using the second equation we have that:
[tex]\begin{gathered} y=0-60(3)+\frac{1}{2}(-10)(3)^2 \\ y=-225 \end{gathered}[/tex]This means that the ball travels 225 meters downward from the height of the platform to the ground, therefore the platform is 225 meters above the ground.
The specific heat capacity of steel is 450 J/kg°C. If heat is added to 2 kg of steel for 30seconds, raising its temperature from 10°C to 32°C, what is the heat flow rate? Express your answer in W.
Answers
Given:
The specific heat capacity of steel is
[tex]c=\text{ 450 J/kg }^{\circ}C[/tex]The mass of the steel is m = 2 kg
The initial temperature of steel is
[tex]T_i=\text{ 10}^{\circ}\text{ C}[/tex]The final temperature of steel is
[tex]T_f\text{ = 32}^{\circ}C[/tex]
The time is t = 30 s
To find the heat flow rate.
Explanation:
The heat flow rate can be calculated by the formula
[tex]\frac{Q}{t}=\frac{mc(T_f-T_i)}{t}[/tex]On substituting the value, the heat flow rate will be
[tex]\begin{gathered} \frac{Q}{t}=\text{ }\frac{2\times450\times(32-10)}{30} \\ =\text{ 660 W} \end{gathered}[/tex]Thus, the heat flow rate is 660 W.
If a 150 pound weight is on a frictionless surface, raised at an angle of 35 degrees, what is the tension in the rope that keeps it from sliding down? What is the force perpendicular to the surface?
Answers
This is the given situation.
Where m is the mass of the block and g is the acceleration due to gravity. It is given in the question, mg=150 pound=68.04 kg.
There are two components of weight. One along with x-direction and the other with negative y-direction.
x-component is
[tex]mg\sin \theta[/tex]y-component is
[tex]mg\cos \theta[/tex]Tension on the string is equal to the x-component of the weight. and the normal force,i.e. perpendicular force is equal and opposite to the y component of the weight. But tension is in opposite direction to the x-component of weight and perpendicular force is opposite to the y-component.
Therefore the tension is,
[tex]T=-mg\sin \theta=-68.04\times\sin 35^o=-39.03\text{ N}[/tex]And the normal force is,
[tex]N=mg\cos \theta=60.04\times\cos 35^o=55.74\text{ N}[/tex]Therefore the magnitude of the tension on the string is 39.03 N
And the normal force is 55.74 N
A passenger train and freight train start from the same time and travel in opposite directions. The passenger train traveled 3 times as fast as the freight train. In 5 hours, they were 360 miles apart. Find the rate of each train.
Answers
Given that the relative distance between 2 trains, d = 360 miles
Time, t is 5 hrs.
Let speed of freight train be v, then the speed of passenger train will be 3v.
For relative speed, the speed of trains will be added.
Hence,
[tex]\begin{gathered} 3v+v=\frac{360}{5} \\ v=\frac{360}{5\times4} \end{gathered}[/tex]Thus, the speed of freight train is 18 miles/hour.
And the speed of passenger train is 3v = 54 miles/hour.
Classify a sample of matter as a pure substance or mixture based on the number of elements or compounds in the sample.
Answers
A pure substance has constant chemical composition and properties.
The element cannot be separated into simples substances.
A mixture is composed of 2 or more pure substances that retain their individual identities but cannot be separated by physical methods.
As the object travels along the track, what is the maximum height that it reaches above point E?
Answers
Given:
Mass of object = 2 kg
At point E, the gravitational potential energy is 0.
Let's find the maximum height the object will reach above point E.
[tex]PE=mgh[/tex]Where:
m is the mass
g is acceleration due to gravity
h is the height.
The maximum height the object will reach above point E will be the height at Point C if the restriction is to the given points.
Point C is 20 m above the ground.
Therefore, the maximum height that it reaches above point E is 20 m.
ANSWER:
20 m.
Which of the following is not true of all waves?Waves carry energy from one place to another.Waves need a mechanical medium through which to propogate.Waves can be used to carry infomation across distances.For a wave propagating in a given medium, wavelength is inversely proportional to frequency.
Answers
Given:
Some statements about the waves
To find:
The statement which is not true of all waves
Explanation:
The waves carry energy from one place to another. The wavelength of a wave is,
[tex]\lambda=\frac{v}{f}[/tex]Here, 'v' is the speed of the wave and 'f' is the frequency of the wave.
So, the wavelength is inc=versely proportional to frequency in a given medium.
The waves line electromagnetic waves do not need any mechanical medium to propagate, they can travel without any media.
Hence, the statement "Waves need a mechanical medium through which to propogate" is not true.
Obtain the potential on the x-axis at x = 0 for the following point charge distributions on the x-axis: 200 μ C at x = 20 cm, -3 00 μ C at x = 30 cm and - 400 μ C at x = 40 cm.
Answers
Potential on x axis will be 9 * [tex]10^{6}[/tex] N [tex]m^{}[/tex]/[tex]C^{}[/tex] in all three cases
Electric potential is defined as the amount of work needed to move a unit charge from a reference point to a specific point against the electric field.
v1 = k ( q1 / r1)
= 9 * [tex]10^{9}[/tex] * ( 200 * [tex]10^{-6}[/tex] / 20 * [tex]10^{-2}[/tex] )
= 90 * [tex]10^{5}[/tex] = 9 * [tex]10^{6}[/tex] N [tex]m^{}[/tex]/[tex]C^{}[/tex]
v2 = k ( q2 / r2 )
= 9 * [tex]10^{9}[/tex] * (-300 * [tex]10^{-6}[/tex] / 30 * [tex]10^{-2}[/tex] )
= 9 * [tex]10^{6}[/tex] N [tex]m^{}[/tex]/[tex]C^{}[/tex]
v3 = k ( q3 / r3 )
= 9 * [tex]10^{9}[/tex] * 400 * [tex]10^{-6}[/tex] / 40 * [tex]10^{-2}[/tex]
= 9 * [tex]10^{6}[/tex] N [tex]m^{}[/tex]/[tex]C^{}[/tex]
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URGENT!! ILL GIVE
BRAINLIEST!!!! AND 100 POINTS!!!!!!
Jennifer uses many forms of energy to get ready for school in the morning. Which table best matches each form of energy to Jennifer's actions?
Answers
Answer:
c I think
Explanation:
pretty sure cuz of common sense
Answer:
A form of energy you use when cheering for your favorite team. answer choices. sound energy. electrical energy. thermal energy. electromagnetic energy.
Explanation:
Hoped it helped :))))
Outline alpha, betta and gamma radiation in terms of depth of tissue penetration, ionizing effect and speed of radiation.
Answers
Penetration and Ionizing effect gamma, betta, and alpha radiation.
The speed of radiation is alpha, betta, and gamma radiation.
A gamma ray, also known as gamma radiation, is a penetrating shape of electromagnetic radiation arising from the radioactive decay of atomic nuclei. It consists of the shortest wavelength electromagnetic waves, typically shorter than the ones of X-rays.
Gamma rays have a lot of penetrating strength that several inches of dense material like lead, or maybe some feet of concrete may be required to forestall them. Gamma rays can skip absolutely through the human body; as they pass through, they are able to purpose ionizations that harm tissue.
These are a number of the most deadly radiation known. If a person happened to be close to a gamma-ray producing item, that they had been fried in an instantaneous. honestly, a gamma-ray burst should affect existence's DNA, inflicting genetic harm lengthy after the burst is over.
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A spring with a spring constant of 30.0N/m Is compressed 5.00m. What is the force that the spring would apply
Answers
Force of the Spring = -(Spring Constant) x (Displacement)
so , Here we need to put the values
F = 30* 5 = 150N
Here, the Force applied is 150N. So, the correct ans is C
You are moving a dresser that has a mass of 36 kg; its acceleration is 0.5 m/s2. What is the force being applied?72 N18 N4.8 N35.5 N
Answers
ANSWER
18 N
EXPLANATION
Given:
• The dresser's mass, m = 36 kg
,• The dresser's acceleration, a = 0.5 m/s²
Find:
• The applied force, F
By Newton's second law of motion, the net force acting on an object is equal to the product between the object's mass and its acceleration,
[tex]F=ma[/tex]Assuming that there is no friction between the dresser and the floor,
[tex]F=36kg\cdot0.5m/s^2=18N[/tex]Hence, the force being applied is 18 N.
Which of the following terms best describes the luminosity of the sun?A. WattageB. TemperatureC. DistanceD. Energy
Answers
The luminosity is a measure of the electromagnetic power of a source of light, therefore, its unit of measure is "Watts". Therefore, the term that best describes the luminosity of the sun is "Wattage".
A PVC pipe has a length of 53.594 centimeters.a. What are the frequencies of the first three harmonics when the pipe is open at both ends? b. What are the frequencies of the first three harmonics when the pipe is closed at one end and open at the other?
Answers
Given:
Length of pipe, L = 53.594 cm
Let's solve for the following:
• (a). What are the frequencies of the first three harmonics when the pipe is open at both ends?
To find the frequency of the first harmonics, apply the formula:
[tex]f_1=\frac{v}{2l}[/tex]Where:
v is the speed of sound = 343 m/s
l is the length of the pipe in meters.
Where:
100 cm = 1 m
53.594 cm = 0.53594 m
Hence, for the frequency, we have:
[tex]\begin{gathered} f_1=\frac{343}{2*0.53594} \\ \\ f_1=319.99\approx320\text{ Hz} \end{gathered}[/tex]For the frequency of the second harmonics, we have:
[tex]\begin{gathered} f_2=2f_1 \\ \\ f_2=2*320 \\ \\ f_2=640\text{ Hz} \end{gathered}[/tex]For the frequency of the third harmonics:
[tex]\begin{gathered} f_3=3f_1 \\ \\ f_3=3*320 \\ \\ f_3=960\text{ Hz} \end{gathered}[/tex]• Part B.
,• What are the frequencies of the first three harmonics when the pipe is closed at one end and open at the other?
For the first harmonics when the pipe is closed at one end, apply the one end open harmonics equation.
[tex]\begin{gathered} f_1=\frac{v}{4l} \\ \\ f_1=\frac{343}{4*0.53594} \\ \\ f_1=160\text{ Hz.} \end{gathered}[/tex]The next 2 harmonics will be the odd multiples of the first.
Hence, we have:
[tex]\begin{gathered} f_3=3f_1 \\ f_3=3*160 \\ f_3=480\text{ Hz.} \\ \\ \\ f_5=5f1 \\ f_5=5*160 \\ f_5=800\text{ Hz.} \end{gathered}[/tex]Therefore, the frequencies of of the first three harmonics when the pipe is closed at one end and open at the other are:
160 Hz, 480 Hz, 800 Hz.
ANSWER:
(A). 320Hz, 640 Hz, 960 Hz.
(B). 160 Hz, 480 Hz, 800 Hz.
Question 8 of 25In a nuclear reactor, what type of a reaction provides the power?O A. FusionB. Controlled fissionC. RedoxO D. Uncontrolled fusionSUBMIT
Answers
Given:
Reaction in the nuclear reactor.
To find:
Type of nuclear reaction in the nuclear reactor that provides power.
Explanation:
In a fusion reaction, two nuclei are fused together to form a heavier nucleus. The energy released in the process is known as fusion energy. The nuclear reactors we are using today are not based on nuclear fusion reactions. Thus option A is incorrect.
Redox reaction is a chemical reaction and is not used in nuclear reactors. Thus, option C is the incorrect option.
In a nuclear fission reaction, the nuclear of an atom is bombarded with neutrons to split the nucleus into two or more two smaller nuclei which are known as daughter nuclei. During this process, a large amount of energy is released and it is known as nuclear fission energy. The nuclear technology that we used today, uses nuclear fusion reactions in the reactors. The reaction is controlled by using control rods. Thus the correct option is option B.
Final answer:
In a nuclear reactor, a controlled fusion reaction provides the power. Thus, the correct option is option B.
As the boat in which he is riding approaches a dock at 3.0 m/s, Jasper stands up in the boat and jumps toward the dock. Jasper applies an average force of 800. newtons on the boat for 0.30 seconds as he jumps.a. How much momentum does Jasper’s 80.-kilogram body have as it lands on the dock?b. What is Jasper's speed on the dock?
Answers
a) Take into account that the force can be written as follow:
[tex]F=\frac{\Delta p}{\Delta t}[/tex]where F is the force, Δp the change in the momentum and Δt the time interval in which the force is applied.
Moreover, consider that the change in the momentum can be written as follow:
[tex]\Delta p=m\Delta v[/tex]where m is the mass and Δv is the change in the velocity.
By replacing the previous expression into the formula for the force F, you can solve for Δv to determine the change in the velocity of Jamper due the force he applies to the boat:
[tex]\begin{gathered} F=\frac{m\Delta v}{\Delta t} \\ \Delta v=\frac{\Delta t\cdot F}{m} \end{gathered}[/tex]In this case, m=80.0kg, Δt = 0.30s and F = 800.0N.
Then, for the change in the speed you obtain:
[tex]\Delta v=\frac{0.30s\cdot800.0N}{80.0kg}=3.0\frac{m}{s}[/tex]It means that related to the boat (where you can consider that Jasper is at rest) the speed of Jasper is 3m/s. However, it is necessary to take into account the speed of the boat before Jasper jumps to the dock, which is 3.0m/s.
The speed of Jasper when he lands on the dock is then:
3.0m/s + 3.0m/s = 6.0m/s
The momentum is the product of mass and speed, then, the momentum of jasper is:
p = (80.0kg)(6.0m/s) = 480.0kg*m/s
b) Based on the previous calculations, you have that the Jasper's speed on the dock is 6.0m/s