Answers
Translations
One point located at (x,y), translated to the point (h,k) has been applied the rule:
T(x,y) -> (h,k)
And the translation changed the coordinates by ( h-x, k-y).
The point (4,-9) is mapped to (9,-14). The change is:
(9 - 4, -14 - (-9 ) = (5 , -5)
The rule of translation is:
T(x,y) -> (x + 5 , y -5)
If we translated the point (-9,-8) under the same rule:
T(-9,-8) -> (-9 + 5 , -8 -5)
T(-9,-8) -> ( -4 , -13)
The image of the point (-9,-8) is ( -4 , -13)
Related Questions
Order these numbers from least to greatest 7.15 , 7 18/25 , 7.134 , 77/10
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a. in radiansb.in degreesHint:HEARRERANote: You can earn partial credit on this problem.Preview My AnswersSubmit Answers
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EXPLANATIONS:
Given;
We are given the following expression;
[tex]arctan(\frac{1}{\sqrt{3}})[/tex]Required;
We are required to find the angle measure of this in both radians, and degrees.
Step-by-step solution;
For the angle whose tangent is given as 1 over square root of 3, on the unit circle, we would have
[tex]\begin{gathered} tan\theta=\frac{1}{\sqrt{3}} \\ Rationalize: \\ \\ \frac{1}{\sqrt{3}}\times\frac{\sqrt{3}}{\sqrt{3}} \\ \\ =\frac{\sqrt{3}}{\sqrt{3}\times\sqrt{3}} \\ \\ =\frac{\sqrt{3}}{3} \end{gathered}[/tex]On the unit circle, the general solution for this value as shown would be;
[tex]tan^{-1}(\frac{\sqrt{3}}{3})=\frac{\pi}{6}[/tex]To convert this to degree measure, we will use the following equation;
[tex]\frac{r}{\pi}=\frac{d}{180}[/tex]We now substitute for the value of r;
[tex]\begin{gathered} \frac{\frac{\pi}{6}}{\pi}=\frac{d}{180} \\ \\ \frac{\pi}{6}\div\frac{\pi}{1}=\frac{d}{180} \\ \\ \frac{\pi}{6}\times\frac{1}{\pi}=\frac{d}{180} \\ \\ \frac{1}{6}=\frac{d}{180} \end{gathered}[/tex]We now cross multiply;
[tex]\begin{gathered} \frac{180}{6}=d \\ \\ 30=d \end{gathered}[/tex]Therefore;
ANSWER:
[tex]\begin{gathered} radians=\frac{\pi}{6} \\ \\ degrees=30\degree \end{gathered}[/tex]If a || band e l f, what is the value of y?(x + 1)[(x-3°
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y = x + 1 [ alternate exterior angles ]
Write a system of equations that could be used to determine the number of commercials and the number of movies on which Alexa songs were played Define the variables that you use to write the system.
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We make a system of equations from the statement
Alexa will earn $20 every time one of her songs is played in a commercial and she will $110 every time one of her songs is played in a movie.
[tex]T=20c+110m[/tex]
where T is the total earned, c the number of commercials and m the number of movies
Alexa earned a total of $340 in 8 commercials and movies
we replace the total (340) on the first equation and make and equation for the total of commercials and movies
[tex]\begin{gathered} 340=20c+110m \\ c+m=8 \end{gathered}[/tex]it is our system
Bella works at a popular clothing store. Last winter, her manager asked her to track thestore's sweater sales. This box plot shows the results.Price of sweaters sold ($)304050607080What fraction of the sweaters cost $50 or less?
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From the given graph, it appears that the price of the sweaters sold ranges in 3 bars - from $45 up $60.
Sweaters costing $50 or less covers 1 out of the 3 bars in the graph. In its equivalent fraction, we get:
[tex]undefined[/tex]I need help I'm still having a bit of trouble with multiplying radicals
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The area of the rectangle is;
[tex]36\sqrt[]{3\text{ }}\text{ sq cm}[/tex]Here, we want to find the area of the rectangle
To do this, we will have to multiply the length of the sides
Mathematically, we have this as follows;
[tex]\begin{gathered} \text{Area = Length }\times\text{ Width} \\ \text{Area = 6 cm }\times\text{ 6}\sqrt[]{3\text{ }}\text{ cm} \\ =\text{ 36}\sqrt[]{3}\text{ sq cm} \end{gathered}[/tex][tex]\begin{gathered} 6\times6\text{ = 36} \\ \sqrt[]{6}\text{ }\times\text{ 6 = 6}\sqrt[]{6} \\ \sqrt[]{6}\text{ }\times\text{ }\sqrt[]{6}\text{ = 6} \\ 6\sqrt[]{6}\text{ }\times\text{ 6}\sqrt[]{6}\text{ = (6}\times6)\times(\sqrt[]{6\text{ }}\text{ }\times\text{ }\sqrt[]{6}\text{ ) = 36}\times6\text{ = 216} \\ \sqrt[]{3}\text{ }\times\text{ }\sqrt[]{2\text{ }}\text{ = }\sqrt[]{\text{ (3}\times2)}\text{ = }\sqrt[]{6} \\ 7\sqrt[]{3}\text{ }\times\text{ 8}\sqrt[]{7\text{ }}\text{ = (7}\times8\text{ )}\times\text{ (}\sqrt[]{3}\text{ }\times\sqrt[]{7\text{ }}\text{ ) = 56}\sqrt[]{21} \end{gathered}[/tex]The system of equations(4x-y = 4(x+1) hasly = 6The system of equations 4x-y=4(x+1) , y = 6 has:A. one solutionB. infinitely many solutionsC. no solution
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EXPLANATION
Plugging in y=6 into the first equation:
[tex]4x-6=4(x+1)[/tex]Applying the distributive property:
[tex]4x-6=4x\text{ +4}[/tex]Subtracting -4x to both sides:
[tex]4x-4x-6=4[/tex]Adding +6 to both sides:
[tex]4x-4x=4+6[/tex]Adding like terms:
[tex]0\ne10[/tex]In conclusion, the system of equations has no solutions.
(2x³-7x² + 7x-2) ÷ (x-2)
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Answer:
Please look at the attachment below, thanks! :D
Step-by-step explanation:
6 - 2x = 5x - 9x + 20
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Answer:
x = 7
Step-by-step explanation:
6 - 2x = 5x - 9x + 20
−2x + 6 = −4x + 20
2x + 6 = 20
2x = 14
x = 14 : 2
x = 7
Four people buy raffle tickets and place all of their tickets into a hat. Raphael bought 8 tickets, Leonardo bought 2 tickets, Michelangelo bought 5 tickets, and Donatello bought 11 tickets. If a person randomly selects one raffle ticket from the hat, what is the probability that Raphael purchased the ticket? Write your answer as a decimal and round three decimal places.
Answers
0.308
Explanation
The probability of an event is the number of favorable outcomes divided by the total number of outcomes possible,so
[tex]P(A)=\frac{favorable\text{ outcomes }}{total\text{ outcomes}}[/tex]so
Step 1
favourable outcome is the result that is desired, so as the result is a that Raphael purchase the ticket
a) Let
[tex]favorable\text{ outcome=}8[/tex]and , the total outcome is the total ticket,so
[tex]\begin{gathered} total\text{ outcome=Raphael+Leonardo+Michelangelo+Donatello} \\ total\text{ outcome=8+2+5+11=26} \end{gathered}[/tex]b) now, replace in the formula:
[tex]\begin{gathered} P(A)=\frac{favorable\text{ outcomes }}{total\text{ outcomes}} \\ P(A)=\frac{8}{26} \\ P(A)=0.3076923 \\ rounded \\ P(A)=0.308 \end{gathered}[/tex]therefore,the answer is 0.308
I hope this helps you
1/2(x+6) = 2x and 5-2x =7x-h
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Expression given:
[tex]\frac{1}{2}(x+6)=2x[/tex][tex]5-2\cdot(\frac{4}{5})=7\cdot(\frac{4}{5})-h[/tex]Procedure:
0. Solving for ,x: ,multiplying both sides by 2
[tex]2\cdot\frac{1}{2}(x+6)=2x\cdot2[/tex][tex]x+6=4x[/tex]Substracting both sides by x
Under her cell phone plan, Ella pays a flat cost of $58.50 per month and $3 per gigabyte, or part of a gigabyte. (For example, if she used 2.3 gigabytes, she would have to pay for 3 whole gigabytes.) She wants to keep her bill under $65 per month. What is the maximum whole number of gigabytes of data she can use while staying within her budget?
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She can consume up to 2 gigabytes of data at a time without exceeding her monthly budget.
Given that Ella pays a one-time fee of $58.50 and has to pay $3 per gigabyte used. She must pay $3xg if she utilizes g gigabytes.
We now need to determine how many gigabytes of data she can utilize in total while staying within her budget.
She is spending less than $65.
For this, we can construct an inequality statement as shown below.
58.50+3g< 65
3g<65-58.50
3g<6.5
g<6.5/3
g<2.163.
Therefore, she should only use a total of 2 gigabytes to keep the cost within her budget.
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5. The function w(x) = 70x represents the number of words w(x) you can type in x minutes. SHOW ALL WORK!!a.) How many words can you type in 5 minutes?b.) How many words can you type in 8 minutes?c.) How long would it take to read 280 words?
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The given function is
[tex]w(x)=70x[/tex]Where x is minutes.
(a) To find the number of words typed in 5 minutes, we just need to replace the variable for 5 and solve
[tex]w(5)=70(5)=350[/tex]Therefore, there are typed 350 words in 5 minutes.
(b) We do the same process for 8 minutes.
[tex]w(8)=70(8)=560[/tex]Therefore, there are typed 560 words in 8 minutes.
(c) To find the type for 280 words, now we replace the other variable w(x), and solve for x
[tex]280=70x[/tex]We divide the equation by 70
[tex]\frac{280}{70}=\frac{70x}{70}\rightarrow x=4[/tex]Therefore, 280 words take 4 minutes.
An airplane pilot over the Pacific sights an atoll at the angle of depressionof 5º. At this time, the horizontal distance from the airplane to the atoll is4,535 meters. What is the height of the plane to the nearest meter?
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Answer:
397 meters
Explanation:
Let us draw a diagram to understand the situation better.
Where H is the height of the plane.
Now the tan ratio for 5° gives
[tex]\tan 5^o=\frac{opposite}{\text{adjacent}}[/tex]Since opposite = H and adjacent = 4535 meters, the above gives
[tex]\tan (5^o)=\frac{H}{4535}[/tex]Multiplying both sides by 4535 gives
[tex]\tan (5^o)\times4535=H[/tex]Since tan(5°) =0.0875.., ( just used a calculator to find out) the above becomes
[tex]0.0875\times4535=H[/tex][tex]H=396.8125[/tex]rounding to the nearest meter gives
[tex]\boxed{H=397.}[/tex]Answer the following. (a) Find an angle between 0 and 2π that is coterminal with -13T/12 (b) Find an angle between 0° and 360° that is coterminal with 810°. Give exact values for your answers.
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(a) Find an angle between 0 and 2π that is coterminal with -13π/12.
To get coterminal angles, we simply have to add or subtract 2π. In this problem, we are looking for a coterminal angle that is between 0 and 2π, so we will add 2π to -13π/12:
[tex]\frac{-13\pi}{12}+2\pi=\frac{11\pi}{12}[/tex](b) Find an angle between 0° and 360° that is coterminal with 810°.
Similarly to the previous exercise, we will substract 360° to 810° to find a coterminal angle that is between 0 and 360°:
[tex]\begin{gathered} 810\text{\degree}-360\text{\degree}=450\text{\degree} \\ 450\text{\degree}-360\text{\degree = 90\degree} \end{gathered}[/tex]ANSWER
a. 11π/12
b. 90°
The points (−5, -5) and (r, 1) lie on a line with slope 1/2. Find the missing coordinate r.
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Solution:
The slope is expressed as
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ where \\ (x_1,y_1)\text{ and} \\ (x_2,y_2)\text{ are the coordinates of points through which the line passes} \end{gathered}[/tex]Given that the points (-5, -5) and (r, 1) lie on the line with slope 1/2, this implies that
[tex]\begin{gathered} x_1=-5 \\ y_1=-5 \\ x_2=r \\ y_2=1 \end{gathered}[/tex]By substituting these valus into the slope formula, we have
[tex]\begin{gathered} \frac{1}{2}=\frac{1-(-5)}{r-(-5)} \\ \Rightarrow\frac{1}{2}=\frac{1+5}{r+5} \\ cross-multiply, \\ r+5=2(1+5) \\ \Rightarrow r+5=12 \\ add\text{ -5 to both sides of the equation,} \\ r+5-5=12-5 \\ \Rightarrow r=7 \end{gathered}[/tex]Hence, the missing coordinate r is evaluated to be
[tex]7[/tex]There are 1300 people over the age over the age of 12 in the small town. If the same rate of cell phone usage continues , how many yrs will it takes for 1300 people have a cell phone.
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We have to find how many years it will take for the 1300 people to have a cellphone.
This means we have to find x for f(x) = 1300, that is "the number of people using cellphones at time x is 1300".
Then, we can write:
[tex]\begin{gathered} f(x)=1300 \\ 880(1.03)^x=1300 \\ 1.03^x=\frac{1300}{880} \\ 1.03^x\approx1.477 \\ x\cdot\ln (1.03)=\ln (1.477) \\ x=\frac{\ln (1.477)}{\ln (1.03)} \\ x\approx\frac{0.39}{0.03} \\ x\approx13.2 \end{gathered}[/tex]Answer: it will take 13.2 years for the 1300 people to have a cellphone.
The bill for the meal was $24.00. Dario left a tip of 16 2/3%. How much was the tip?
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We have to calculate the tip.
It is the 16 2/3% of $24.
We start by converting 16 2/3% to decimals:
[tex](16+\frac{2}{3})\%\cdot\frac{1}{100\%}=\frac{16.6667}{100}=0.166667[/tex]Now, we can calculate the tip by multiplicating this proportion by 24:
[tex]\text{tip}=0.166667\cdot24=4[/tex]Answer: the tip is $4.
Write an equation for a function that gives thr value in the table. Use the equation to find the value of y when x= 12.
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the First, we figure out the equation of the line.
[tex]\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}[/tex]We pick point (8,27) as point 1 and (10,35) as point 2.
Therefore equation of line =
[tex]\begin{gathered} \frac{y-27_{}}{x-8_{}}=\frac{35-27_{}}{10-8_{}} \\ \frac{y-27_{}}{x-8_{}}=\frac{8}{2} \end{gathered}[/tex]Cross multiplying, we have
8x -64 = 2y - 54
Adding 54 to both sides, we have:
8x - 10 = 2y
Dividing both sides by 2, we have:
y = 4x -5
Next, we substitute the value of x with 12 to get:
y = 4(12) - 5
y = 48 - 5
y = 43
2x -10 < 6 solve the inequality[tex]2x - 10 \leqslant 6[/tex]
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The given equation is:
[tex]2x\text{ - 10 }\leq\text{ 6}[/tex]To simply this, just keep the x term on the left side and others at the right side. Therefore,
[tex]2x\text{ }\leq\text{ 6 + 10}[/tex][tex]2x\text{ }\leq\text{ 16}[/tex][tex]x\text{ }\leq\text{ }\frac{16}{2}[/tex]or
[tex]x\text{ }\leq\text{ 8}[/tex]Hence, the solution is x =< 8.
Find the missing sides of the triangle. Leave youranswers as simplified radicals.
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Consider the following right triangle:
To find the missing sides x and y, we can apply the following trigonometric ratios:
[tex]\cos(60^{\circ})=\frac{adjacent\text{ side to the angle 60}^{\circ}}{Hypotenuse}[/tex][tex]\sin(60^{\circ})=\frac{opposite\text{ side to the angle 60}^{\circ}}{Hypotenuse}[/tex]and
[tex]\tan(60^{\circ})=\frac{opposite\text{ side to the angle 60}^{\circ}}{adjacent\text{ side to the angle 60}^{\circ}}[/tex]thus, applying the data of the problem to the last equation, we get:
[tex]\tan(60^{\circ})=\frac{opposite\text{ side to the angle 60}^{\circ}}{adjacent\text{ side to the angle 60}^{\circ}}=\frac{15}{y}[/tex]that is:
[tex]\tan(60^{\circ})=\frac{15}{y}[/tex]solving for y, we obtain:
[tex]y=\frac{15}{\tan(60^{\circ})}=\frac{15}{\sqrt{3}}[/tex]On the other hand, applying the above data to the first equation, we get:
[tex]\cos(60^{\circ})=\frac{adjacent\text{ side to the angle 60}^{\circ}}{Hypotenuse}=\frac{y}{x}=\frac{15}{\sqrt{3}}\text{ }\cdot\frac{1}{x}[/tex]or
[tex]\cos(60^{\circ})=\frac{15}{\sqrt{3}\text{ x}}\text{ }[/tex]solving for x, we obtain:
[tex]x=\frac{15}{\sqrt{3}\cdot\cos(60)}=\text{ }\frac{15}{\sqrt{3\text{ }}\cdot1/2}=\frac{2(15)}{\sqrt{3}}=\frac{30}{\sqrt{3}}[/tex]we can conclude that the correct answer is:
Answer:[tex]x=\frac{30}{\sqrt{3}}[/tex]and
[tex]y=\frac{15}{\sqrt{3}}[/tex]I'm a bit confused and I'm not sure but I think it's D?
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125x + 200 ≥ 1,200
Solve for x
x ≥ (1200 - 200)/125
x ≥ 1000/125
x≥ 8
Then graph solution is
Arrow to right, beggining at 8, including 8 point
Answer is OPTION A)
Write a sequence of dilations and transformations that map circle B onto circle A and that shows the two circles you created are similar.
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We have start with circle B, which is a circle with radius equals to 3 and centered at (4, 4).
The circle A has a radius equals to 4. If we dilate the image of the circle B around the center of circle A by the ratio between the radius, we're going to have circle A.
Translation means the displacement of a figure or a shape from one place to another. If we translate the circle B 8 units to the left, The image is going to have the same center as circle A.
The transformations that takes circle B to circle A are a dilation around (4, 4) by a factor of 4/3, and then a horizontal translation of 8 units to the left.
Express the confidence interval 0.25 < p < 0.43 in the form of p ± E.
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The confidence interval written as 0.25 < p < 0.43 in the form p ± E is; CI = 0.34 ± 0.09
How to express confidence Interval?The general formula for confidence interval is;
CI = x' ± z(s/√n)
where;
CI is confidence interval
x' is sample mean
z is confidence level value
s is sample standard deviation
n is sample size
We are given the confidence interval as;
0.25 < p < 0.43
To write it in the form p ± E means that;
- p = (up confed limit) + (low conf limit)/2
- E= (up confed limit) - (low confed limit)/2
p = (0.25 + 0.43)/2
p = 0.34
E = (0.43 - 0.25)/2
E = 0.09
Thus;
CI = 0.34 ± 0.09
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A triangle has vertices on a coordinate grid at P(4, -9), Q(-1, -9), and R(4,6).What is the length, in units, of PQ?
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Given:
The coordinates of point P, (x1, y1)=(4, -9).
The coordinates of point Q, (x2, y2)=(-1, -9).
The length of PQ can be calculated as,
[tex]\begin{gathered} PQ=\sqrt[]{(x2-x1)^2+(y2-y1)^2} \\ PQ=\sqrt[]{(-1-4)^2+(-9-(-9))^2} \\ PQ=\sqrt[]{(-5)^2+0} \\ PQ=\sqrt[]{5^2} \\ PQ=5 \end{gathered}[/tex]Therefore, the length PQ
if <5 = 130 and m<3 - 13x. find the value of x Round to the nearest tenth if necessary.
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From the figure, it can be seen that ∠3 and ∠5 are co-interior angles. Thus, we find that the value of x is 3.84.
It is given to us that -
∠5 = 130
and, ∠3 = 13x
We have to find out the value of x.
Here, we have two parallel lines. Parallel lines are the lines that do not intersect at any points.
There is also a transversal that passes through the two parallel lines in the same plane intersecting the parallel lines at two separate points.
When a transversal cuts two parallel lines, there are different angles formed as shown in the figure.
∠3 and ∠5 are co-interior angles that lie on the same side of the transversal.
So, ∠3 + ∠5 = 180
=> 13x + 130 = 180
=> 13x = 50
=> x = 3.84
Thus, from the value of the sum of co-interior angles, we find that the value of x is 3.84.
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solve each equation for y=. Without graphing, classify each system as having one solution, no solution, or infinitely many solutions.
x+y=3
y=2x-3
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Answer:
The answer would be y=3, and there is only one solution.
Step-by-step explanation:
In the first expression, x+y=3, we can rearrange it to get it in terms of x so we can substitute it for x in the second expression.
x+y=3
Subtract y from both sides: x=-y+3
Substitute x=-y+3 into the second expression: y=2(-y+3)+3
Distribute the 2: y=-2y+6+3
Simplify the right side: y=-2y+9
Add 2y to both sides: 3y=9
Divide by 3: y=3
Since there is a single y coordinate, that means that there is only one solution.
What is an equation of the line that passes through the point (1,-3) and is perpendicular to the line x+3y=21
The answer I need begins with y =
Please do not answer if your solution doesn't end that way, thank you.
Answers
The linear equation that is perpendicular to the line x+3y=21 is:
y = 3*x - 6
How to find the equation of the line?A general line in the slope-intercept form is written as:
y = m*x + b
Where m is the slope and b is the y-intercept.
Two linear equations are perpendicular if the product between the two slopes is equal to -1.
Rewriting the given line we can get:
x +3y = 21
3y = 21 - x
y = 21/3 - x/3
y = (-1/3)*x + 21/3
Then the slope is (-1/3), if our line is perpendicular to this one, then:
m*(-1/3) = -1
m = 3
our line is:
y = 3*x + b
To find the value of b, we use the fact that our line passes through (1, - 3)
-3 = 3*1 + b
-3 - 3 = b
-6 = b
The line is y = 3*x - 6
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Find the slope-intercept equation of the line that passes
through (-4, 2) and has a slope of 1/4
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Start with y=mx+b and using the slope and the point, find b.
By knowing the slope, you know y = (1/4) x + b.
If you substitute in (-4,2), you'd have: 2 = (1/4)•(-4) + b
2 = -1 + b
3 = b
So your equation is y = 1/4 x + 3.
Omor is preparing the soil in his garden for planting squash. The directions say to use 4 poundsof fertilizer for 160 square feet of soil The area of Omar's garden is 200 square feet.How much fertilizer is needed for a 200 square-foot garden?1
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So the formula say 4 pounds of fertilizer for 160 square feet and he has to made for 200 square feet so we can made a rule of 3 so:
[tex]\begin{gathered} 4\to160 \\ x\to200 \end{gathered}[/tex]and the equation will be:
[tex]\begin{gathered} x=\frac{200\cdot4}{160} \\ x=5 \end{gathered}[/tex]So he need 5 pounds of fertilizer