Please help, I don't understand how to put this in CM

Answer:

Space Rovers

Explanation:

The engineering advancement of the invention space rovers has changed space exploration tremendously. The first space rover ever to go out onto another planet was made by NASA and put on mars to learn more about the red planet and see if there where any plausible signs of past or maybe even present life. This mission was incredibly successful and for the first time in space exploration history, there was a spacecraft that you could move around that could with do the conditions of the planet for weeks, months, sometimes years at a time, moving around taking pictures and constantly collecting data. This was revolutionary for scientists, this way they could get copious amounts of information just on rover and not having to send multiple crafts only to die in the first few hours but sending back a relative amount of information. With rovers you can have them collect samples and bring the back to earth, not something  that could’ve been done without a human, until rovers. They have completely changed and improved collecting data from other planets and have been one of the most revolutionary inventions when it comes to space exploration.

This is what I put for the answer, hope it helps in some way.

Answer:

Dimensions are expressed as width by length by height or depth in three-dimensional space.

hope it helps

Answer:

41.5° C

Explanation:

Given data :

1025 steel

Temperature = 4°C

allowed joint space = 5.4 mm

length of rails = 11.9 m

Determine the highest possible temperature

coefficient of thermal expansion ( ∝ ) = 12.1 * 10^-6 /°C

Applying thermal strain ( Δl / l )  = ∝ * ΔT

                                    ( 5.4 * 10^-3 / 11.9 )  = 12.1 * 10^-6 * ( T2 - 4 )

∴  ( T2 - 4 ) =  ( 5.4 * 10^-3 / 11.9 ) / 12.1 * 10^-6

hence : T2 = 41.5°C

Answer:

the process capability index for the precision machining process is 0.667

Explanation:

Given the data in the question;

Lower Specification Limits LSL = 0.99 mm

Upper Specification Limits USL = 1.01 mm.

The standard deviation σ = 0.005 mm

mean μ = 1 mm

capability index Cpk = ?

Cpk = min( USL - μ / 3σ, μ - LSL / 3σ )

we substitute

Cpk = min( 1.01 mm - 1 mm / 3(0.005 mm ), 1 - 0.99 mm / 3(0.005 mm) )

Cpk = min( 0.01 mm / 0.015 mm, 0.01 mm / 0.015 mm )

Cpk = min( 0.6666, 0.6666 )

∴ Cpk = 0.6666 ≈ 0.667

Therefore, the process capability index for the precision machining process is 0.667

Answer:

Option B (Starter Control Circuit) is the right option.

Explanation:

All other given options are not related to the given instance. So the above option is correct.