If water is added to 145 mL of a 0.55 M KOH solution until the volume is 250 mL, what will the molarity of the diluted solution be?
Answer:
0.319 M
Explanation:
M1V1 = M2V2
M1 = 0.55M
V1=145 mL = 0.145 L
V2 = 250mL = 0.250L
M2 = M1V1/V2=0.55x0.145/0.250 = 0.319 M
what happens to the boiling point of hydrocarbon compounds when the number of carbon atom increases
A. Decreases
B. Increases
C. Remains the same
D. None of these
I NEED YOUR ANSWER RN GUYSS PLEASEE
Name the type of light interaction sing the snow falling through a window
1. Absorbed
2. Reflected
3. Transmittied
Answer: 2
Explanation:
it’s reflected
Answer:
Transmitted
Explanation:
Because this is when its granted safe passage through the medum
Absorbed: energy goes through and disappears
Reflected: is when light bounces off a surface (mirrors)
How many moles are there in 105.69 grams of FeCI2
Answer:
0.8338395752301793
Explanation:
I used an online converter (grams to moles for FeCl2)
What causes the high luster of a metal?
a
excitation of electrons into empty orbitals
b mobility of electrons
C easily ionizable metal atoms
d their low melting points
Answer:
When light is shone on to the surface of a metal, its electrons absorb small amounts of energy and become excited into one of its many empty orbitals. The electrons immediately fall back down to lower energy levels and emit light. This process is responsible for the high luster of metals.
Explanation:
Your well-wisher :-)
What type of reaction is shown here?
C3H2O + 4023 CO2 + 3 H2O
Answer: combustion and girl
Explanation: C3H6O + 4 O2 → 3 CO2 + 3 H2O COMBUSTION
Which statement about Niels Bohr's atomic model is true?
O Higher orbits have lower energies.
Each orbit has a specific energy level.
Electrons can exist in any energy level.
O Orbits close to the nucleus have no energy.
Hurry.
Answer:
o
Explanation:
Answer:
Each orbit has a specific energy level.
Explanation:
Bohr model
Find the mass of 3.27 x 10^23 molecules of H2SO4. Use 3 significant digits
and put the units.
Answer:
Approximately [tex]53.3\; \rm g[/tex].
Explanation:
Lookup Avogadro's Number: [tex]N_{\rm A} = 6.02\times 10^{23}\; \rm mol^{-1}[/tex] (three significant figures.)
Lookup the relative atomic mass of [tex]\rm H[/tex], [tex]\rm S[/tex], and [tex]\rm O[/tex] on a modern periodic table:
[tex]\rm H[/tex]: [tex]1.008[/tex].[tex]\rm S[/tex]: [tex]32.06[/tex].[tex]\rm O[/tex]: [tex]15.999[/tex].(For example, the relative atomic mass of [tex]\rm H[/tex] is [tex]1.008[/tex] means that the mass of one mole of [tex]\rm H\![/tex] atoms would be approximately [tex]1.008\![/tex] grams on average.)
The question counted the number of [tex]\rm H_2SO_4[/tex] molecules without using any unit. Avogadro's Number [tex]N_{\rm A}[/tex] helps convert the unit of that count to moles.
Each mole of [tex]\rm H_2SO_4[/tex] molecules includes exactly [tex](1\; {\rm mol} \times N_\text{A}) \approx 6.02\times 10^{23}[/tex] of these [tex]\rm H_2SO_4 \![/tex] molecules.
[tex]3.27 \times 10^{23}[/tex] [tex]\rm H_2SO_4[/tex] molecules would correspond to [tex]\displaystyle n = \frac{N}{N_{\rm A}} \approx \frac{3.27 \times 10^{23}}{6.02 \times 10^{23}\; \rm mol^{-1}} \approx 0.541389\; \rm mol[/tex] of such molecules.
(Keep more significant figures than required during intermediary steps.)
The formula mass of [tex]\rm H_2SO_4[/tex] gives the mass of each mole of [tex]\rm H_2SO_4\![/tex] molecules. The value of the formula mass could be calculated using the relative atomic mass of each element:
[tex]\begin{aligned}& M({\rm H_2SO_4}) \\ &= (2 \times 1.008 + 32.06 + 4 \times 15.999)\; \rm g \cdot mol^{-1} \\ &= 98.702\; \rm g \cdot mol^{-1}\end{aligned}[/tex].
Calculate the mass of approximately [tex]0.541389\; \rm mol[/tex] of [tex]\rm H_2SO_4[/tex]:
[tex]\begin{aligned}m &= n \cdot M \\ &\approx 0.541389\; \rm mol \times 98.702\; \rm g \cdot mol^{-1}\\ &\approx 53.3\; \rm g\end{aligned}[/tex].
(Rounded to three significant figures.)
What is the pH of a 2.0 × 10-4 M HCl solution?
Answer:
pH = 3.69
Explanation:
HCl is a strong acid. It will disscociates completely into dissoluted ions such that,
[tex][H^+]=2\times 10^{-4}\ M[/tex]
The formula for pH is given by :
[tex]pH=-log[H^+]\\\\pH=-log(2\times 10^{-4})\\\\pH=3.69[/tex]
So, the pH of the solution is 3.69.
The answer to your question is 4.
What is the percent of water in the hydrate whose formula is MgCl2 •6H2O?
Here is my answer. I hope this is helpful.
If 23.2 g of a given gas occupies a volume of 93.2 L at a particular temperature and pressure, what
mass of the gas occupies a volume of 10.4 L under the same conditions?
Answer:
2.59g
Explanation:
Using Avagadro's law equation as follows:
V1/n1 = V2/n2
Where;
V1 = initial volume (litres)
V2 = final volume (litres)
n1 = first amount of gas in grams
n2 = second amount of gas in grams
According to the information provided in this question, v1 = 93.2L, v2 = 10.4L, n1 = 23.2 g, n2 = ?
Using V1/n1 = V2/n2
93.2/23.2 = 10.4/n2
Cross multiply
93.2 × n2 = 23.2 × 10.4
93.2n2 = 241.28
n2 = 241.28/93.2
n2 = 2.588
n2 = 2.59g
The mass of the gas is 2.59g that occupies a volume of 10.4 L under the same conditions.
Avogadro's law equation:V₁/n₁ = V₂/n₂
Where
V₁ = initial volume (litres)
V₂ = final volume (litres)
n₁ = first amount of gas in grams
n₂ = second amount of gas in grams
Given:
V₁ = 93.2L,
V₂ = 10.4L,
n₁ = 23.2 g,
To find:
n₂ = ?
On substituting the values:
93.2/23.2 = 10.4/n₂
93.2 * n₂ = 23.2 * 10.4
93.2* n₂ = 241.28
n₂ = 241.28/93.2
n₂ = 2.588
n₂ = 2.59g
Thus, the mass of the gas is 2.59g.
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HELP PLEASE!! IF YOU DO AND ANSWER CORRECTLY YOU WILL GET A BRAINLIEST 5 STARSSSS AND A THANKS!! PLEASE PLEASE HELPPP
When scientists communicate about their work, what information should they make sure is included:
1.
2.
3.
4.
5.
6.
7.
How many lone pairs are in SO4 2-
Answer:
None
Explanation:
There are two S=O. bonds and two S-O bonds in sulfate ion lewis structure. Sulfur atom is the center atom and four oxygen atoms are located around sulfur atom. There are no lone pairs in the last shell of sulfur atom.
How to make copper chloride from copper carbonate
Answer:
Describe how a sample of copper chloride crystals could be made from copper carbonate and dilute hydrochloric acid. Add excess copper carbonate to hydrochloric acid in a beaker, stirring until there is no further reaction. Filter the mixture to remove the remaining copper carbonate, then heat the remaining solution to the point of crystallisation.
Explanation: Hope this is right.
Enzymes in your body act as a catalyst. Thus the role of enzymes is to
O inhibit chemical reactions
o increase the rate of chemical reactions
O help you breathe
decrease the rate of chemical reactions
How many particles are in one mole of copper (II) sulfate, CuSO4?
Plz help, will give brainliest!
Answer:
C
Explanation:
No change.
The total number moles of products = The Total number of reactants
how many carbon dioxide molecules are produced if 8.45 x 1023 of water molecules of water are produced
The given question is incomplete. The complete question is:
Determine how many carbon dioxide molecules are produced if molecules of water are produced
[tex]C_2H_6(g)+O_2 (g)\rightarrow CO2(g)+H_2O(g)[/tex]
Answer: [tex]5.60\times 10^{23}[/tex] molecules of carbon dioxide are produced
Explanation:
The balanced chemical equation is:
[tex]2C_2H_6(g)+7O_2 (g)\rightarrow 4CO2(g)+6H_2O(g)[/tex]
[tex]\text{Moles of water}=\frac{\text{given molecules}}{\text{Avogadros number}}=\frac{8.45\times 10^{23}}{6.023\\times 10^{23}}=1.40moles[/tex]
Accoding to stoichiometry:
6 moles of water are produced along with = 4 moles of carbon dioxide
Thus 1.40 moles of water are produced along with = [tex]\frac{4}{6}\times 1.40=0.93[/tex] moles of carbon dioxide
Molecules of carbon dioxide = [tex]moles\times {\text {Avogadros number}}=0.93\times 6.023\times 10^{23}=5.60\times 10^{23}[/tex]
Give examples which indicate that nylon fibres are very strong.
Explanation:
is used for making ropes, used for climbing rocks and for making parachutes. Their usage shows that nylon fibres have high tensile strength
a. An undesirable constituent of air
Complete Question:
Give one word for the following.
a. An undesirable constituent of air
b. The constituent of air that helps in burning
c. The thick layer of air surrounding the earth
d. Carbon dioxide does not support this process
Answer:
a. Pollutant.
b. Oxygen.
c. Atmosphere.
d. Combustion.
Explanation:
a. Pollutant: an undesirable constituent of air. Pollution can be defined as the physical degradation or contamination of the environment through an emission of harmful, poisonous and toxic chemical substances known as pollutants. Some examples of pollutant are carbon monoxide, nitrogen dioxide, ozone, etc.
b. Oxygen: the constituent of air that helps in burning. Oxygen is an element that aids in the combustion (burning) process because it is an oxidizing agent.
c. Atmosphere: the thick layer of air surrounding the earth. It comprises of nitrogen, oxygen, carbon dioxide, argon and other gases in very small proportion.
d. Combustion (burning): Carbon dioxide does not support this process but it is an end product of the process.
Combustion can be defined as an exothermic chemical reaction between physical substances, usually in the presence of oxygen and hydrocarbons to produce heat, light and carbon.
Will mark BRAINLIEST. Molarity
Please no Bs answers. Only going to be reported.
If water is added to 145 mL of a 0.55 M KOH solution until the volume is 250 mL, what will the molarity of the diluted solution be?
What is the molarity of the solution that results from diluting 35.0 ml of a 9.02M solution to a new volume of 45.0 ml?
We can use the equation for dilutions that relates concentration and volume:
[tex]M_1V_1=M_2V_2[/tex]
where M is the molarity, V is the volume, and 1 and 2 refer to the initial and final states of the solution, respectively. Here, we are given the molarity of the initial solution and the volumes of the initial and final (diluted) solutions. To find the final concentration (i.e., the molarity of the diluted solution), we would be solving for M₂:
[tex]M_2=\frac{M_1V_1}{V_2} = \frac{(0.55 \text{ M})(145 \text{ mL})}{250 \text{ mL}} \\ M_2 = 0.319 \approx 0.32 \text{ M}.[/tex]
The molarity is given to two significant figures as both our M₁ and V₂ are given to two significant figures.
Note: Although our volumes are in mL instead of L, we do not need to convert them to L for the purposes of our calculation since we would be multiplying our V₁ and V₂ by a common factor that would cancel out in division. All that matters is the ratio between the two volumes, which is the same whether the volumes are in mL or in L.
---
We follow the exact same procedure in the second question as we did in the first problem: solve for M₂ given M₁ = 9.02 M, V₁ = 35.0 mL, and V₂ = 45.0 mL:
[tex]M_2=\frac{M_1V_1}{V_2} = \frac{(9.02 \text{ M})(35.0 \text{ mL})}{45.0 \text{ mL}} \\ M_2 = 7.02 \text{ M}.[/tex]
Stock System naming for NaCl4, SO3, As2F4.
Hi! I need some help with this pleaseeee!!
When two objects of different temperatures are placed in contact with one another, eventually: (choose one option from below)
a) both their average kinetic energy and temperature will be the same
b) their average kinetic energy will be the same
c) neither their average kinetic energy and temperature will be the same
d) their temperature will be the same
If 0.05 mol of I2 were actually produced in a reaction starting with 15 grams of CO what is the percent yield of I2
Answer:
6.2
Explanation:
I AM SMOooOooOooORTno but really trust the processPLEASE HELP.!
While studying meiosis and mitosis for her genetics test, Marisa made notes of the kinds of cells produced from these processes with examples from the body. Which pairing of the cell produced during meiosis and example is correct?
A) diploid cell: liver cell
B) diploid cell: sperm cell
C) haploid cell: egg cell
D) haploid cell: hair cell
Answer:
C
Explanation:
The pairing of the cell produced during meiosis and correct example is haploid cell: egg cell (Option C).
A haploid (n) cell contains only a set of homologous chromosomes, whereas a diploid (2n) cell contains two sets of homologous chromosomes. Meiosis is a type of reductional cell division by which a parental diploid (2n) cell generates four haploid germinal (egg) daughter cells having half of the genetic material.Conversely, mitosis is a type of cell division that produces two genetically identical daughter cells.Meiosis produces germinal (sex) cells, whereas mitosis produces somatic (body) cells.In conclusion, the pairing of the cell produced during meiosis and correct example is haploid cell: egg cell (Option C).
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What is the vapor pressure of propanone
at 50°C?
Answer: If we work it out with direct proportions, the vapor pressure of propanone is 56 degrees Celsius. The atmospheric pressure is about 101.
Explanation: hope this helps.
The vapor pressure of propanone at 50°C is :
- 78° vapor pressure
PropanoneWhen the vapor pressure is specifically work through the extents to a temperature rate it response is intensely subordinate on their possess a mass nature.
The vapor weight of propanone is calculated and shape in degree Celsius in rate.
The rate of vapor when it is calculated by 50°C with propanone its at long last gives us a 78° vapor pressure.
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In terms of valence electrons, explain why metals form positive ions.
Answer:
Explanation:
Metal elements form positively charged ions called cations because they are located on the left side of the periodic table These elements all have valence electrons in an s orbital. These electrons are relatively easy for the atom to lose to achieve a stable octet of electrons in its outermost energy shell.
What is the molar mass of the following compound: C1H3P2
A what is matter that is always composed of the same combination of atoms
Answer:
A substance
Explanation:
In 1774, Joseph Priestly discovered oxygen gas by heating mercury(II) oxide powder with focused sunlight through a lens. How many grams of HgO (216.59 g/mol) would be decomposed to produce 1.50 mol O2 ? A. 650. g HgO B. 325gHgO C. 162gHgO D. 3.00 g HgO
Answer:
A. 650 g
Explanation:
The equation of the reaction is given as;
2 HgO(s) --> 2Hg(s) + O2(l)
From the reaction;
2 mol of HgO produces 1 mol of O2
x mol of HgO would produce 1.50 mol of O2
2 = 1
x = 1.5
Solving for x;
x = 1.5 * 2 / 1 = 3 mol
Converting to mass;
Mass = Number of moles * Molar mass
Mass = 3 mol * 216.59 g/mol
Mass = 649.77 g ≈ 650. g
Correct option is ;
A. 650 g