Answer:
Where's the question? So that i can answer it!
The pressure at the bottom of a jug filled with water does NOT depend on the
__________.
A) depth of the liquid
B) acceleration due to gravity
C) density of water
D) surface area of the water
E) none of the above
Answer:
D
Explanation:
because of the the side of the bottom
Bella is approaching some congested traffic and wisely slows her Audi from 19.6 m/s to 3.7 m/s at a constant rate of -3.33 m/s/s. How much time elapses before the car is traveling at 3.7 m/s?
The Time that elapses before the car is traveling at 3.7 m/s is 4.8 s.
What is time?Time is a measure of non-stop, consistent change in our surroundings, usually from a specific viewpoint.
To calculate the time require for the to be traveling at 3.7 m/s, we use the formula below.
Formula:
t = (v-u)/a........... Equation 1Where:
t = Timev = Final velocityu = Initial velocitya = AccelerationFrom the question,
Given:
v = 3.7 m/su = 19.6 m/sa = - 3.33 m/s²Substitute these values into equation 1
t = (19.6-3.7)/-3.33t = -15.9/-3.33t = 4.8 sHence, the time need for the car to start traveling at 3.7 m/s is 4.8 s.
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A popular science demonstration is to take several liquids that will not mix together and pour them in a tall glass cylinder so as to stack them one on top of the other. A teacher places vinegar, motor oil and corn syrup were placed in the same tall narrow glass cylinder. Explain what you would expect to se in the glass cylinder provided for you below. Briefly explain why you expect to see these results.
What we expect to observe in the glass is that the given liquids are placed in the following order from bottom to the top:
Corn syrup
Vinegar
Motor oil
The previous order is fue to the fact that substances with lower density float on substances with higher density. Substance with higher density have more mass per unit of volume and the force of gravity is greater over substan.
Part 2/2 please.The answer to Part 1/2 is 4.5 m
In order to calculate the wave speed, we can use the formula below:
[tex]v=\lambda f[/tex]Where lambda is the wavelength and f is the frequency.
If the wavelength is 4.5 meters and the frequency is 3 Hz, the speed is:
[tex]v=4.5\cdot3=13.5\text{ m/s}[/tex]How much potential energy does a person of mass 50 kg have if they are standing at the top of a building that is 54.8 m high? Submit your answer in exponential form.
ANSWER:
2.69 x 10^4 J
STEP-BY-STEP EXPLANATION:
Given:
Mass (m) = 50 kg
Height (h) = 54.8 m
The potential energy is calculated by the following formula:
[tex]E=m\cdot g\cdot h[/tex]We replace and determine the value of the energy:
[tex]\begin{gathered} E=50\cdot9.8\cdot54.8 \\ \\ E=26852=2.69\cdot10^4\text{ J} \end{gathered}[/tex]The potential energy is equal to 2.69 x 10^4 joules.
Pls help. If you cannot see the directions, the directions are: Use the images below to determine whether a substance is a Pure Substance, Mixture, Element, Compound, Mixture of Elements, Mixture of Compounds, or Mixture of both Elements and Compounds.
The classifications of the substances are;
Compound
1,2,3
Mixture
4,5,6
Pure substances
1,7,8
Elements and compounds
1
What is a mixture?The term mixture has to do with a substances that is obtained by a combination of two or more substances that are not chemically combined together. We know that on the other hand a compound is formed when there is a combination of elements that are chemically combined together.
When we talk of a pure substances, we are talking of the substances that are composed of only one kind of material. There are also some compounds that we may call compound elements. These are the compounds that are composed of only one kind of element.
The elements and the compounds are pure substances in the sense that they are composed of only one type of material.
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Newton's third law of motion states that:an object in motion will tend to stay in motion unless outside forces act upon it.objects will accelerate in the direction of the force exerted upon it.an object's inertia will always remain unchanged.all forces come in pairs.
Let's state the Newton's Third Law of Motion.
The Newton's Third Law of Motion states that when two bodies interact, the forces they apply to each other are equal in magnitude and opposite in direction.
Therefore, since the forces the bodies exert equal forces in opposite direction on each other, it means that forces come in pairs.
The forces can be said to be action-reaction force pairs
Therefore, Newton's third Law of Motion states that all forces come in pairs.
ANSWER:
All forces come in pairs.
A 62.7 kg astronaut is holding a 6.5 kg tool pack while drifting at 12.3 m/s to the right. She throws the tool pack away so thatit is drifting at 2.4 m/s to the left. How fast is she moving after the throw? Assume that they are out in deep space with noother forces acting on them.
Answer:
[tex]v_{new}=9.9ms^{-1}[/tex]Explanation: Assuming that it took one second to throw the tool away, then we have to use the final velocity formula to get the new velocity:
[tex]v(t)=v_o+at[/tex]One second would imply that the deceleration in the initial astronaut velocity is:
[tex]\begin{gathered} a=-2.4ms^{-2} \\ \end{gathered}[/tex]Note the sign convention!
The new velocity of the astronaut after the throw would be now:
[tex]\begin{gathered} t=1s \\ \therefore\Rightarrow \\ v(1s)=12.3ms^{-1}+(-2.4ms^{-2})(1s)=(12.3-2.4)ms^{-1} \\ v_{new}=9.9ms^{-1} \end{gathered}[/tex]A person travels by car from one city to another with different constant speeds between pairs of cities. She drives for 15.0 min at 90.0 km/h, 7.0 min at 65.0 km/h, and 40.0 min at 40.0 km/h and spends 40.0 min eating lunch and buying gas.(a) Determine the average speed for the trip. km/h(b) Determine the distance between the initial and final cities along the route. km
a)
To determine the average speed we need to determine the time the person travels and the distance. Since we need the average speed in km/h we need to convert all the times given into hours, let's do this:
[tex]\begin{gathered} 15\text{ min}\cdot\frac{1\text{ h}}{60\text{ min}}=0.25\text{ h} \\ 7\text{ min}\cdot\frac{1\text{ h}}{60\text{ min}}=\frac{7}{60}\text{ h} \\ 40\text{ min}\cdot\frac{1\text{ h}}{60\text{ min}}=\frac{2}{3}\text{ h} \end{gathered}[/tex]Now, that we have the time in each interval of the motion we can determine the distance is travel in each of them:
[tex]\begin{gathered} d_1=90(0.25)=22.5 \\ d_2=65(\frac{7}{60})=7.583 \\ d_3=40(\frac{2}{3})=26.667 \end{gathered}[/tex]This means that the total distance the person traveled is 56.8 km (we use three significant figures as shown in the problem).
Once we know this we need to find the time it takes to make this, from our previos discussion and adding the 40 minutes the person took to eat we have that the total time was 1.7 h, then the average speed is:
[tex]v=\frac{56.8}{1.7}=33.4[/tex]Therefore, the average speed on the trip was 33.4 km/h
b)
From point a we know that the distance was 56.8 km
I need help answering these questions using my experiment results. I will send you the results
Answer:
(a) It changed
(b) It changed
(c) It changed
(d) It changed
Explanation:
For each parameter, we get:
(a) the final velocity of the ball.
The velocity is equal to the distance over time. Since the distance is always 10 m, the velocity will depend on the time. So, when the time is greater, the final velocity is smaller.
In this case, we can see that for each angle, we get different times, so, the angle affects the final velocity of the ball.
(b) work
The work can be calculated as:
W = Fdcosθ
Where F is the force, d is the distance and θ is the angle between them. When we change the angle of the incline, we affect the angle of the Force and the displacement, so the work changes.
(c) initial potential energy
The potential energy depends on the initial height, if the height is greater, the potential energy is greater. So, when the angle of the incline change, the height change, so the potential energy change
(d) final kinetic energy
The kinetic energy depends on the final velocity, if the final velocity is greater, the kinetic energy is greater. Since the final velocity changes with the angle, the kinetic energy also changes with the angle.
A gymnast of mass 52.0 kg is jumping on a trampoline. She jumps so that her feet reach a maximum height of 2.98 m above the trampoline and, when she lands, her feet stretch the trampoline 70.0 cm down. How far does the trampoline stretch when she stands on it at rest? Assume that the trampoline is described by Hooke’s law when it is stretched.
When the gymnast is at 2.98 meters above the trampoline, she has potential gravitational energy in relation to the trampoline:
[tex]\begin{gathered} PE_g=m\cdot g\cdot h \\ PE_g=52\cdot9.81\cdot2.98 \\ PE_g=1520.16\text{ J} \end{gathered}[/tex]When she lands on the trampoline, all this energy will be converted into potential elastic energy:
[tex]\begin{gathered} PE_e=\frac{kx^2}{2} \\ 1520.16=\frac{k\cdot0.7^2}{2} \\ 0.49k=3040.32 \\ k=6204.73\text{ N/m} \end{gathered}[/tex]Now, to find the stretch in the trampoline when the gymnast is at rest, let's use the gymnast weight force in the formula for the force in a string:
[tex]\begin{gathered} F=k\cdot x \\ m\cdot g=k\cdot x \\ 52\cdot9.81=6204.73\cdot x \\ 510.12=6204.73 \\ x=\frac{510.12}{6204.73} \\ x=0.0822\text{ m} \end{gathered}[/tex]Therefore the trampoline stretches 8.22 cm.
what is the centeipital force of a 0.2 kg ball traveling in a circle with a radius of 1 m if it completes one revolution every secondanswer is in meters per second squared
The mass of the ball, m = 0.2 kg
Radius of the circle, r = 1 m
To convert the angular speed to rad per second from revolution per second, multiply by 2π
w = 1 rev/sec = 2π rad/sec
The velocity, v = wr
v = (2π) x 1
v = 2π m/s
The centripetal force is given by the formula:
[tex]\begin{gathered} F\text{ = }\frac{mv^2}{r} \\ F\text{ = }\frac{0.2\times(2\pi)^2}{1} \\ F\text{ = 0.2 }\times\text{ 4}\pi^2 \\ F\text{ = 0.8}\pi^2 \\ F=0.8(3.142)^2 \\ F\text{ = 7.9 N} \end{gathered}[/tex]The centripetal acceleration is given as:
[tex]\begin{gathered} a\text{ = }\frac{v^2}{r} \\ a\text{ = }\frac{(2\pi)^2}{1} \\ a\text{ = 4}\pi^2 \\ a=4(3.142)^2 \\ a\text{ = }39.49m/s^2 \end{gathered}[/tex]Calculate the resistance in milliOhms of a copper wire 2.84 m long and 0.04 m diameter? The resistivity of copper is 1.7 x 10^-8.
therefore, the resistivity is 0.019210 miliOhms
ExplanationStep 1
The resistance of a cylindrical segment of a conductor is equal to the resistivity of the material times the length divided by the area
[tex]\begin{gathered} R=\rho\frac{L}{A} \\ where\text{ }\rho\text{ is the resistivity of the material} \\ L\text{ is the lenght} \\ A\text{ is the area} \end{gathered}[/tex]so
Step 1
a)let
[tex]\begin{gathered} \rho=1.7*10^{-8} \\ L=2.84 \\ diameter=\text{ 0.04 m} \\ Area\text{ = unknown} \end{gathered}[/tex]bI find the area
the area of a circle is given by:
[tex]area=\pi(\frac{diameter^2}{4})[/tex]so, replace
[tex]\begin{gathered} area=\pi(\frac{0.04m^2}{4}) \\ Area=0.0025132741\text{ m}^2 \end{gathered}[/tex]c) now, we can replace the values in the formula
[tex]\begin{gathered} R=\rho\frac{L}{A} \\ R=1.7*10^{-8}\frac{2.84\text{ m}}{0.0025132741\text{ m}^2} \\ R=1.9*10^{-5}\text{ ohm} \\ to\text{ convert into miliOhms , multiply by 1000} \\ R=R=\frac{1.9\text{ohm}}{10^{5}}*\frac{1000\text{ miliOhms}}{1\text{ Ohms}}=0.01921\text{ ohms} \end{gathered}[/tex]therefore, the resistivity is 0.019210 miliOhms
I hope this helps yo u
A pelican flying along a horizontal path drops
a fish from a height of 5.0 m. The fish travels
8.5 m horizontally before it hits the water
below.
What was the pelican’s initial speed? The
acceleration of gravity is 9.81 m/s^2
Answer in units of m/s.
The initial velocity of the pelican, given that it dropped a fish from a height of 5.0 m is 8.5 m/s
How do I determine the initial velocity of the pelican?We'll begin by obtaining the time taken for the fish to hit the water. This can be obtained as follow:
Height (h) = 5.0 mAcceleration due to gravity (g) = 9.81 m/s²Time (t) =?h = ½gt²
5 = ½ × 9.81 × t²
5 = 4.905 × t²
Divide both side by 4.905
t² = 5 / 4.905
Take the square root of both side
t = √(5 / 4.905)
t = 1 second
Finally, we shall determine the initial velocity of the pelican. Detail below:
Horizontal distance (s) = 8.5 mTime (t) = 1 secondInitial velocity of pelican (u) = ?s = ut
8.5 = u × 1
u = 8.5 m/s
Thus, we can conclude that the initial velocity is 8.5 m/s
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Find the capacitance of a parallel-plate capacitor made of two 4.0 cm x 4.0 cm metal plates if the plates are separated by 5.0 mm.Group of answer choices2.8x10-10 F1.0x10-6 F2.8x10-12 F2.0x10-5 F
Given the area is:
A=4.0 cmx4.0 cm
The seperation distance is d=5.0 mm
The capacitance is :
[tex]\begin{gathered} C=\frac{\epsilon_oA}{d} \\ \Rightarrow C=8.85\times10^{-12}\frac{4.0\times10^{-2}\times4.0\times10^{-2}}{5\times10^{-3}} \\ \Rightarrow C=2.83\times10^{-12}F \end{gathered}[/tex]Thus the answer is
[tex]2.8\times10^{-12}F[/tex]Two 4-1 resistors are connected in parallel to a 12-V bat-tery. Use the fact that the voltage across each of the resis-tors is 12 V to find the total current through the battery.What single resistor, if connected to the battery alone(called the equivalent resistance), would draw this samecurrent?
Given data
*The given resistors are
[tex]R_1=R_{2_{}}_{}_{}=4\text{ ohm}[/tex]*The given battery voltage is V = 12 V
The equivalent resistance in parallel combination is calculated as
[tex]\begin{gathered} R_{eq}=\frac{R_1\times R_2}{R_1+R_2} \\ =\frac{4\times4}{4+4} \\ =\frac{16}{8} \\ =2\text{ ohm} \end{gathered}[/tex]The total current flows through the battery is calculated as
[tex]\begin{gathered} I=\frac{V}{R_{eq}} \\ =\frac{12}{2} \\ =6\text{ A} \end{gathered}[/tex]104 km = _______ mUsing the ladder method
1 km=1000 m
Therefore,
[tex]\begin{gathered} 104\text{ km=(104 km)(1000m/1 km)} \\ =104000\text{ m} \end{gathered}[/tex]A model of a helicopter rotor has four blades, each 2.60 m long from the central shaft to the bladetip. The model is rotated in a wind tunnel at 477 rev/min. What is the radial acceleration of theblade tip expressed as a multiple of g?Answer:Choose...Next page
The radial acceleration in terms of the frequency and the radius is given by:
[tex]a_c=4\pi^2rf^2[/tex]To use this formula we need to convert the frequency to revolution per second:
[tex]477\frac{rev}{\min}\cdot\frac{1\text{ min}}{60\text{ s}}=7.95\text{ Hz}[/tex]Plugging the values we have:
[tex]\begin{gathered} a_c=4\pi^2(2.6)(7.95)^2 \\ a_c=6487.35 \end{gathered}[/tex]hence the acceleration is 6487.35 m/s^2. To get the acceleration in terms of g we divide it by its value:
[tex]\begin{gathered} a_c=\frac{6487.35}{9.8} \\ a_c=661.97 \end{gathered}[/tex]This means that the acceleration is approximately 662 times the acceleration of gravity, that is:
[tex]a_c=662g[/tex]5. Law of Acceleration: A 1400 kg car is initially at rest. It is then accelerated by a 3000 N force for 10 seconds.What is the car's acceleration?How fast is it going after 10 seconds?
The force acting on the car can be expressed as,
[tex]F=ma[/tex]Plug in the known values,
[tex]\begin{gathered} 3000\text{ N=(1400 kg)a} \\ a=\frac{3000\text{ N}}{1400\text{ kg}}(\frac{1kgm/s^2}{1\text{ N}}) \\ =2.14m/s^2 \end{gathered}[/tex]Thus, the acceleration of the car is 2.14 m/s2.
The final velocity of the car is given as,
[tex]v=u+at[/tex]Substitute the known values,
[tex]\begin{gathered} v=0m/s+(2.14m/s^2)(10\text{ s)} \\ =21.4\text{ m/s} \end{gathered}[/tex]Thus, the final velocity of the car is 21.4 m/s.
If you throw a 0.3 kg ball straight up with an initial speed of 32 m/s, how fast will it be moving when it’s 20 m above the release point? Round your answer to the nearest tenth and include the appropriate unit.
Given:
The mass of the ball, m=0.3 kg
The initial speed of the ball, u=32 m/s
The height, h=20 m
To find:
The speed of the ball when it is at a height of 20 m.
Explanation:
The ball will be moving under the influence of acceleration due to gravity which is directed downwards.
From the equation of motion,
[tex]v^2=u^2-2gh[/tex]Where v is the final velocity of the ball and g is the acceleration due to gravity.
On substituting the known values,
[tex]\begin{gathered} v^2=32^2-2\times9.8\times20 \\ \implies v=\sqrt{32^2-2\times9.8\times20} \\ =25.1\text{ m/s} \end{gathered}[/tex]Final answer:
The velocity of the ball when it is 20 m above the releasing point is 25.1 m/s
i need help with this because my teacher wont help me
Given:
The speed of the signal is v = 1500 m/s
The time is t = 1.5 s
To find the distance traveled by signal.
Explanation:
The distance traveled by signal can be calculated by the formula
[tex]d=\frac{v\times t}{2}[/tex]On substituting the values, the distance traveled will be
[tex]\begin{gathered} d\text{ = }\frac{1500\times1.5}{2} \\ =\text{ 1125 m} \end{gathered}[/tex]Thus, the distance traveled by the signal is 1125 m
Rearrange the formula for V1 get the formula for V1
To isolate v₁ from the given equation, subtract aΔt from both members of the equation and simplify:
[tex]\begin{gathered} v_2=v_1+a\cdot\Delta t \\ \Rightarrow v_2-a\cdot\Delta t=v_1+a\cdot\Delta t-a\cdot\Delta t \\ \Rightarrow v_2-a\cdot\Delta t=v_1 \\ \therefore v_1=v_2-a\cdot\Delta t \end{gathered}[/tex]Therefore, the formula for v₁ is:
[tex]v_1=v_2-a\cdot\Delta t[/tex]How do I find the force he uses to throw backwards
Remember that the average force F exerted over an object equals the change in the linear momentum of that object divided by the time over which the force is exerted:
[tex]F=\frac{\Delta p}{\Delta t}[/tex]Assume that the direction towards Superman is negative and the direction away from Superman is positive. Find the initial and final linear momentum of General Zod, then calculate the change in the linear momentum and divide it by 1.5 seconds to find the average force exerted by Superman.
The linear momentum p of an object with mass m and speed v is given by:
[tex]p=mv[/tex]The mass of General Zod is 150kg. Its initial speed is 25 m/s towards Superman. Then, its initial velocity is negative and its initial linear momentum is:
[tex]\begin{gathered} p_0=150\operatorname{kg}\times-25\frac{m}{s} \\ =-3750\operatorname{kg}\cdot\frac{m}{s} \end{gathered}[/tex]The final speed of General Zod is 20 m/s away from Superman. Then, its final linear momentum is:
[tex]\begin{gathered} p_f=150\operatorname{kg}\times20\frac{m}{s} \\ =3000\operatorname{kg}\cdot\frac{m}{s} \end{gathered}[/tex]The change in the linear momentum of General Zod is:
[tex]\begin{gathered} \Delta p=p_f-p_0_{} \\ =3000\operatorname{kg}\cdot\frac{m}{s}-(-3750kg\cdot\frac{m}{s}) \\ =3000\operatorname{kg}\cdot\frac{m}{s}+3750kg\cdot\frac{m}{s} \\ =6750\operatorname{kg}\cdot\frac{m}{s} \end{gathered}[/tex]Substitute Δp=6750 kg*m/s and Δt=1.5 s to find the force exerted by Superman:
[tex]F=\frac{\Delta p}{\Delta t}=\frac{6750\operatorname{kg}\cdot\frac{m}{s}}{1.5s}=4500N[/tex]Therefore, the correct choice is option b) 4500 N.
After traveling for 6.0 seconds, a runner reaches a speed of 12 m/s after starting from rest. What is the runner’s acceleration?A. .5 m/s2B. 6 m/s2C. 72 m/s2D. 2 m/s2
We can find the acceleration as follows:
[tex]\begin{gathered} a=\frac{\Delta v}{\Delta t} \\ so: \\ a=\frac{12-0}{6-0} \\ a=\frac{12}{6} \\ a=2m/s^2 \end{gathered}[/tex]Answer:
D. 2 m/s^2
11. [0/10 Points]
A rectangular block has dimensions 2.9 cm x 2.6 cm x 10.0 cm. The mass of the block is 605.0 g
What is the volume of the block?
4.0
DETAILS
x cm³
What is the density of the block?
4.0
X g/cm³
Submit Answer
PREVIOUS ANSWERS
Volume of rectangular block is 75.4 cm^3
Density of the rectangular block is 8.02 g/cm^3
Volume is simply defined as the space occupied within the boundaries of an object in three-dimensional space.
It is also known as the capacity of the object.
Volume of rectangular block = length× breadth× height
=2.9 cm × 2.6 cm × 10.0 cm
=75.4 cm^3
Density is defined as the substance's mass per unit of volume.
Mathematically ,density is defined as mass divided by volume.
Density of the block = Mass of block / volume of block
=605.0 g / 75.4 cm^3
=8.02 g/cm^3
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A boat travels 60 miles downstream in the same time as it takes it to travel 40 miles upstream. The boat's speed in still water is 20 miles per hour. Find the stream of the current.
The equation of the boat upstream is 20-s.
The equation downstream is 20+s.
Where s is the speed of the current.
Then, we know that the time spent is equal in both cases, and we also know that time equals distance divided by the speed. So, we express the following.
[tex]\frac{40}{20-s}=\frac{60}{20+s}[/tex]Solve for s.
[tex]\begin{gathered} 40(20+s)=60(20-s) \\ 800+40s=1200-60s \\ 60s+40s=1200-800 \\ 100s=400 \\ s=4 \end{gathered}[/tex]Therefore, the speed of the current is 4 miles per hour.
Determine the displacement x of the elevator above the starting point at the end of each 5-second interval?
Given data:
* The normal weight of the student is 500 N.
* The initial velocity of the student is 0 m/s at time 0 second.
Solution:
(a). For the time interval 0 to 5 seconds,
The scale reading is 500 N.
Thus, the force acting on the elevator is,
[tex]F=F^{\prime}-W[/tex]where F is the net force with which the elevator is moving in upward direction, F' is the scale reading (apparent weight), and W is the actual weight,
Substituting the known values,
[tex]\begin{gathered} F=500-500 \\ F=0 \end{gathered}[/tex]By the Newton's second law, the acceleration of the elevator is,
[tex]\begin{gathered} ma=F \\ ma=0 \\ a=0ms^{-2} \end{gathered}[/tex]By the kinematics equation, the displacement in the time interval 0 to 5 seconds is,
[tex]D=ut+\frac{1}{2}at^2[/tex]where D is the displacement, u is the initial velocity, a is the acceleration, and t is the time,
Substituting the known values,
[tex]\begin{gathered} D=0+0 \\ D=0\text{ m} \end{gathered}[/tex]Thus, the displacement in the 0 to 5 seconds time interval is zero.
(b). For 5 to 10 seconds interval,
As the scale reading is 700 N, thus, the acceleration of the elevator is,
[tex]\begin{gathered} F=F^{\prime}-W \\ ma=700-500 \\ ma=200\text{ N} \end{gathered}[/tex]where m is the mass,
From the weight, the value of mass is,
[tex]\begin{gathered} W=mg \\ m=\frac{W}{g} \end{gathered}[/tex]where g is the acceleration due to gravity,
Substituting the known values,
[tex]\begin{gathered} m=\frac{500}{9.8} \\ m=51.02\text{ kg} \end{gathered}[/tex]Thus, the acceleration of the elevator is,
[tex]\begin{gathered} ma=200 \\ a=\frac{200}{m} \\ a=\frac{200}{51.02} \\ a=3.92ms^{-1} \end{gathered}[/tex]By the kinematics equation, the displacement of the elevator is,
[tex]D=ut+\frac{1}{2}at^2[/tex]Substituting the known values,
[tex]\begin{gathered} D=0+\frac{1}{2}\times3.92\times5^2 \\ D=49\text{ m} \end{gathered}[/tex]Thus, the displacement of elevator is 49 meters for the time interval 5 seconds to 10 seconds.
(c). For the time interval 10 seconds to 15 seconds,
The apparent weight (scale reading) is 500 N.
Thus, the acceleration of the elevator is,
[tex]\begin{gathered} F=F^{\prime}-W \\ ma=500-500 \\ ma=0 \\ a=0ms^{-2} \end{gathered}[/tex]As the scale count is same as the normal weight, thus, elevator must not be moving or it is stopped at some height after moving some displacement upto 10 seconds. Thus, there will be no displacement of the elevator.
(d). For the time interval of 15 seconds to 20 seconds,
The apparent weight of the student is 300 N.
Thus, the acceleration of the elevator is,
[tex]\begin{gathered} F=F^{\prime}-W \\ ma=300-500 \\ ma=-200 \\ a=\frac{-200}{51.02} \\ a=-3.92ms^{-2} \end{gathered}[/tex]Here, the negative sign indicates the elevator is moving in the downward direction.
By the kinematics equation, the displacement of the elevator in the time interval 15 to 20 seconds is,
[tex]D=ut+\frac{1}{2}at^2[/tex]Substituting the known values,
[tex]\begin{gathered} D=0+\frac{1}{2}\times(-3.92)\times5^2 \\ D=-49\text{ m} \end{gathered}[/tex]Here, the negatiev sign indicates the downward displacement,
Thus, the displacement of the elevator in the -49 meter.
In a reactor, if power is lost what lowers the control rods into the core to shut it down? Select one:a.hydraulicsb.peoplec.robotsd.gravity
Given:
The power is lost in a reactor
To find:
What lowers the control rods into the core to shut it down
Explanation:
Control rods are important safety features of reactors as they allow the user to control the output of the reactor. The control rods are held by electromagnetic fields.
If there is some sort of power failure or loss of signal the control rods are immediately released and fall into the reactor core because of gravity.
Hence, the correct option is gravity.
Win Blonehare and Kent Swimtashore are sail boating in Lake Gustastorm. Starting from rest near the shore, they accelerate with a uniform acceleration of 0.136 m/s/s. How far are they from the shore after 13.6 seconds?
The distance they from the shore after 13.6 seconds is 12.58 m.
What is distance?Distance is the total movement of an object without any regard to direction
To calculate the distance traveled from the shore, we use the formula below.
Formula:
s = ut+at²/2......... Equation 1Where:
s = Distancet = timeu = Initial velocitya = AccelerationFrom the question,
Given:
u = 0 m/s (from rest)a = 0.136 m/s²t = 13.6 sSubstitute these values into equation 1
s = (0×13.6)+(0.136×13.6²/2)s = 12.58 mHence, the distance traveled from the shore is 12.58 m.
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A ramp outside a building is 8 m long. One end of the ramp is 2 m higher thanthe other end. What is the mechanical advantage of the ramp?A. 4B. 6C. 1/4D. 1/8
Given that the slope of the ramp is L = 8 m
The height of the ramp is h = 2 m
We need to calculate the mechanical advantage of the ramp.
The mechanical advantage of the ramp can be calculated by the formula
[tex]\text{Mechanical advantage =}\frac{L}{h}[/tex]Substituting the values, the mechanical advantage will be
[tex]\begin{gathered} \text{Mechanical advantage =}\frac{8}{2} \\ =4\text{ } \end{gathered}[/tex]Thus, the correct option is A. 4