Answers
Recall that:
Interest is the monetary gain for lending money to a third party.
Simple interest is applying the interest to the original amount without considering the extra flow of money each time the interest is applied.
Compounded interest is applying the interest to the total amount including the extra flow of money each time the interest is applied.
1) Plan A. From the given information, in 12 months Ari will earn:
[tex]I=500\cdot0.065\cdot12=390.[/tex]dollars, therefore she will have a total of $890.00.
2) Plan B. Now we use the formula for compounded interest to compute the total amount that Ari will have after one year:
[tex]A=500(1+0.065)^{12}=500\cdot2.129096\approx1064.55.[/tex]3) From the above calculations, we conclude that Ari will make more money if she invests in plan B.
4) Ari has to leave the money for another:
Using plan B. Let t be the number of extra months Ari needs to leave the money in the fund, then:
[tex]1100=500\cdot(1.065)^{12+t}\text{.}[/tex]Solving for t, we get:
[tex]\begin{gathered} 1.065^{12+t}=2.2, \\ (12+t)ln(1.065)=\ln (2.2), \\ 12+t=\frac{\ln (2.2)}{\ln (1.065)}=12.52, \\ t=12.52-12=0.52. \end{gathered}[/tex]Then, Ari needs to leave the money for another half a month but since the interest is applied each month she needs to leave the money for another whole month.
Using Plan A: Let t be the number of extra months Ari needs to leave the money in the fund, then:
[tex]1100=500\cdot0.065\cdot(12+t)\text{ +500.}[/tex]Solving for t we get:
[tex]\begin{gathered} \frac{1100-500}{500\cdot0.065}=12+t, \\ t=\frac{600}{32.5}-12, \\ t=6.46. \end{gathered}[/tex]Then, Ari needs to leave the money for another 6.46 months but since the interest is applied monthly she needs to leave the money for another 7 months.
Related Questions
Consider the relation y = −3|x + 5| − 6. What are the coordinates of the vertex?
Answers
Solution:
Given the relation below
[tex]y=-3|x+5|-6[/tex]The general form, an absolute value function is
[tex]y=a|x-h|+k[/tex]The vertex coordinates are (h, k)
Solving to find the vertex below
[tex]\begin{gathered} x+5=x-h \\ 5=-h \\ h=-5 \\ k=-6 \\ (h,k)\Rightarrow(-5,-6) \end{gathered}[/tex]Hence, the coordinates of the vertex is
[tex](-5,-6)[/tex]Evaluate the expression and leaving your answer in polar form.
Answers
Complex numbers z₁ = 6 · [tex]e^{i\,\frac{17\pi}{20} }[/tex] and z₂ = 6 · [tex]e^{i\,\frac{27\pi}{20} }[/tex] are the square roots of the complex number in polar form.
How to find the square root of a complex number in polar form
In this problem we find a complex number in polar form, that is, a complex number of the form:
z = r · [tex]e^{i\,\theta}[/tex]
Where:
r - Norm of the complex number.θ - Direction of the complex number, in radians.The square root of this number can be found by means of the De Moivre's theorem:
[tex]\sqrt{z} = \sqrt{z} \cdot e^{i\,\left(\frac{\theta + 2\pi\cdot k}{n} \right)}[/tex], for k = {0, 1}
If we know that z = 36 and θ = 17π / 10, then the roots of the complex number are:
z₁ = 6 · [tex]e^{i\,\frac{\frac{17\pi}{10}}{2} }[/tex]
z₁ = 6 · [tex]e^{i\,\frac{17\pi}{20} }[/tex]
z₂ = 6 · [tex]e^{\frac{\frac{17\pi}{10} + 2\pi }{2} }[/tex]
z₂ = 6 · [tex]e^{i\,\frac{27\pi}{20} }[/tex]
The solutions are z₁ = 6 · [tex]e^{i\,\frac{17\pi}{20} }[/tex] and z₂ = 6 · [tex]e^{i\,\frac{27\pi}{20} }[/tex].
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5.True or False: The ordered pair (0, 3) is a solution to the equationy = -5x + 3.
Answers
You have the following equation:
y = -5x + 3
in order to determine if the point (0,3) is solution of the previous equation, replace the values of x = 0 and y = 3, and verify if the equation is consistent, as follow:
3 = -5(0) + 3
3 = 3
the equation is consistent for the given point, then, the point (0,3) is a olution of the given equation
Convert the measurement. 12 in/sec = ft/min
Answers
kmartinez2849, this is the solution:
Let's recall that:
1 inch/second = 5 feet/minute
Thus:
12 inch/second = 5 * 12 feet/minute
12 inch/second = 60 feet/minute
Let's recall that:
1 feet = 12 inches
1 minute = 60 seconds
Therefore:
1 inch/second * 60 = 60 inches/minute
Converting inches to feet
60 inches = 5 feet
In conclusion, 5 feet/minute
Solve each inequality). 2|4t-1|+6>20
Answers
To answer this question we will use the following property:
[tex]|a|>b>0\text{ if and only if }a>b\text{ or }a<-b.[/tex]Subtracting 6 from the given inequality we get:
[tex]\begin{gathered} 2|4t-1|+6-6>20-6, \\ 2|4t-1|>14. \end{gathered}[/tex]Dividing the above inequality by 2 we get:
[tex]\begin{gathered} \frac{2|4t-1|}{2}>\frac{14}{2}, \\ |4t-1|>7. \end{gathered}[/tex]Then:
[tex]4t-1>7\text{ or }4t-1<-7.[/tex]Solving the above inequalities we get:
1)
[tex]4t-1>7.[/tex]Adding 1 to the above inequality we get:
[tex]\begin{gathered} 4t-1+1>7+1, \\ 4t>8. \end{gathered}[/tex]Dividing the above by 4 we get:
[tex]\begin{gathered} \frac{4t}{4}>\frac{8}{4}, \\ t>2. \end{gathered}[/tex]The above inequality in interval notation is:
[tex](2,\infty).[/tex]2)
[tex]4t-1<-7.[/tex]Adding 1 to the above inequality we get:
[tex]\begin{gathered} 4t-1+1<-7+1, \\ 4t<-6. \end{gathered}[/tex]Dividing the above result by 4 we get:
[tex]\begin{gathered} \frac{4t}{4}<-\frac{6}{4}, \\ t<-\frac{3}{2}. \end{gathered}[/tex]The above inequality in interval notation is:
[tex](-\infty,-\frac{3}{2}).[/tex]Answer:
[tex](-\infty,-\frac{3}{2})\cup(2,\infty).[/tex]You buy a house for $299,00. If you make a 20% down payment, how much would you pay in total per month for the 30 year loan if you pay $3200/year in taxes, $1050/year in insurance and $28/month forthe home owners association?
Answers
Charlene calculated that the monthly patyment, including interests is $ 692.88.
Taxes = $ 3,200 annually, if we divide it by 12, we will find the monthly amount, this way:
3,200/12 = $ 266.67
Insurance = $ 1,050 annually, if we divide it by 12, we will find the monthly amount, this way:
1,,050/12 = $ 87.50
Home owners association = $ 28
Therefore, the monthly payment would be:
692.88 + 266.67 + 87.50 + 28
You can finish the calculation, Charlene!
how do I do plus 4 with 928 times 90 equal to what plus 57 divided by 134
Answers
What to plus 57 divided by 134 is 83523.57
301123233What Happened When the Crossword Puzzle Champion Died?Find the graph of the solution set of each inequality below in the corresponding column of graphs. Notice the letter next to it.Write this letter in each box containing the number of that exercise. Keep working and you will find out about this grave event.x<2(10 x<1 0 4x is less than 2-3 -2 -1 0 1 2 3-3 -2 -1 0 1 2X<2D++++-3 -2 -123-3 -2 -1 0 1 2 33 x>2+ 12 -3 2 A +++ +13 x>-3-3 -2 -1 0 1 2-3 -2 -1 0 1 2 3(5) x 114 #-1 ++++-3 -2 -10 1 2 3x < -1 A+++ 6 0 >-3 -2 -12-3 -2 -1 0 1 2 3x>-1 E+6 0 6 +++-3 -2 -1 0 1 2-3 -2 -1 0 1 2 318 0
Answers
I'm doing it on my notebook, hold on, it's easy
how do I write an equation as a multiple of a unit fraction using 3×3/7
Answers
EXPLANATION
An equation can be written as a multiply of a unit fraction using the following relationship:
[tex]x(3\cdot\frac{3}{7})[/tex]A professor had students keep track of the social relations for a week and a number of social directions over the weekend and following the distribution how many students had at least 75 social interactions in the week?
Answers
Answer: 12 students
Since we need to find how many students had at least 75 social interactions in the week, we will add up all the frequencies from at least 75 interactions. Looking at the given table, that would be 3, 6, 1, and 2.
Adding them up together and we will get:
[tex]3+6+1+2=12[/tex]Therefore, 12 students had at least 75 social interactions in the week.
2.Flight of a Model Rocket A model rocket is launched from the ground with veloc-ity 48 ft per sec at an angle of 60° with respect to the ground.(a) Determine the parametric equations that model the path of the projectile.(b) Determine the rectangular equation that models the path of the projectile.(c) Determine approximately how long the projectile is in flight and the horizontaldistance covered.
Answers
The parametric equation for the rocket is given by
x = 24 t and y = 24√3 t
Given velocity = 48 ft per sec
∅ = 60°
Distance = speed × time
d = 48t
Displacement along the x-axis
= v cos ∅
= 48× t ×cos60°
=24 t
displacement along the y axis
= v sin ∅
=48 t sin 60°
=24√3 t
In mathematics, a parametric equation represents a set of numbers as functions between one or maybe more independent variables, often known as parameters.
When equations are used to indicate the dimensions of the constituent parts of a geometric object, such as a curve or surface, they are collectively referred to as the parametric representation (alternatively written as parametrization) of the object.
b) now we will use the parametric equation to calculate the rectangular equation.
we know that x = 24t and y = 24√3 t
again, x/24 = y/24√3
or, √3x = y
c) Hence we can see that the parametric equation for the projectile is given by x = 24 t and y = 24√3 t and the rectangular equation is given by
√3x = y .
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Erica's marks in eight consecutive mathematics examinations were:94,83,75,52,71,68,75,49
Answers
(a) The total marks Erica scored is the sum of the given marks:
total = 94 + 83 + 75 + 52 + 71 + 68 +75 + 49 = 567
(b) The mean is given by the quotient between the total and the number of marks, as follow:
mean = 567/8 = 70.875
what is the value of B ( area of the base) for the following triangular prism?40 ft^248 ft^260 ft^224ft^2
Answers
SOLUTION:
The base of the prism is a triangle and the formula for finding the area of a triangle is "half base multiplied by height".
From the figure of the prism given the base and height of the triangle is 6 ft and 8 ft.
[tex]\begin{gathered} \frac{1}{2\text{ }}\text{ x 6 x 8} \\ \\ \frac{48}{2} \\ \\ 24ft^2 \end{gathered}[/tex]CONCLUSION:
The area of the base of the given triangular prism is 24 squared feet ( the fourth option).
add 3 feet 6 in add 3 feet 6 in + 8 ft 2 in + 4in + 2ft 5in what does that add up to
Answers
We want to find the sum of;
3 feet 6 in + 3 feet 6 in + 8 ft 2 in + 4in + 2ft 5in.
Recall that;
[tex]1\text{ feet = 12 inches}[/tex]Adding we have;
[tex]undefined[/tex]Jeff has 45 pounds of organic apples. He earns $4.50 for every 3/4of a pound of organicapples he sells. How much money will Jeff receive if he sells all his organic apples?
Answers
Given data:
The total weight of the apples Jeff have W=45 pounds.
The amount Jeff earned for every 3/4 pound of apple is A=$4.50.
The expression for the given statement is,
[tex]\begin{gathered} \frac{3}{4}\text{ pound =\$4.50} \\ 1\text{ pound =\$6} \end{gathered}[/tex]Multiple the above expression by 45 on both sides.
[tex]\begin{gathered} 45(\text{ 1 pound)=45(\$6)} \\ 45\text{ pounds =\$270} \end{gathered}[/tex]Thus, the amount Jeff earned is $270.
Find the tangent of the larger acute angle in a right triangle with side lengths 3, 4, and 5.
Write your answer as a fraction.
The tangent of the larger acute angle is ______?______
Answers
The tangent should be in fraction is 4/3
Calculation of the tangent:
Since in a right triangle with side lengths 3, 4, and 5
Here there is the larger acute angle in the 3, 4 and 5 so it should be lies between 3 and 5
So, it should be like
= opposite side ÷ adjacent side
= 4/3
Hence, The tangent should be in fraction is 4/3
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Write two numbers that multiply to the value on top and add to the value on bottom.-14Х5
Answers
Let the first number be m while the second num
Use long division to find the quotient. If there is a remainder do not include it in your answer. Recall:dividend\div divisor=quotient (4x^2-10x+6) \div(4x+2) Answer:
Answers
Let's do the division:
Answer: x-3
Both circles have the same center. What is the area of the shaded region?10.7 md=26.2 mUse 3.14 for a. Write your answer as a whole number or a decimal rounded to the nearesbundredth
Answers
To determine the area of the shaded region, we would subtract the area of the smaller or inner circle from the area of the bigger or outer circle.
From the information given,
diameter of inner circle = 26.2m
radius of inner circle = diameter/2 = 26.2/2 = 13.1m
B applying the formula for determining the area of a circle which is expressed as
Area = pie * r^2,
pie = 3.14
Area of inner circle = 3.14 * 13.1^2 = 538.86 m^2
Radius of outer circle = 10.7 + 13.1 = 23.8m
Area of outer circle = 3.14 * 23.8^2 = 1778.62m^2
Therefore,
Area of shaded region = 1778.62 - 538.86 = 1239.76m^2
Use this graph of y = 2x2 - 12x + 19 to find the vertex. Decide whether thevertex is a maximum or a minimum point.TV-5O A. Vertex is a minimum point at (1,3)B. Vertex is a minimum point at (3,1)C. Vertex is a maximum point at (1,7)D. Vertex is a maximum point at (3,1)
Answers
For a parabola, the vertex is the critical point, in other words, it is the maximum or the minimum of the function.
From the graph, we can see that the minimum (the minimum value of y) of the graph is 1. The vertex is the point (3,1).
Moreover, as we mentioned the vertex is always the minimum or the maximum, in this case, it is the minimum since the rest of the graph is 'above' that point.
The answer is option B. Vertex is a minimum point at (3,1)
Use the given conditions to find the exact values of sin(2u), cos(2u), and tan(2u) using the double-angle formulas.tan(u) = 13/5, 0 < u < /2
Answers
The first step to answer this question is to find tan(2u) by using the double angle formula:
[tex]\begin{gathered} tan(2u)=\frac{2tan(u)}{1-tan^2(u)} \\ tan(2u)=\frac{2(\frac{13}{5})}{1-(\frac{13}{5})^2} \\ tan(2u)=\frac{\frac{26}{5}}{1-\frac{169}{25}} \\ tan(2u)=\frac{\frac{26}{5}}{-\frac{144}{25}} \\ tan(2u)=-\frac{65}{72} \end{gathered}[/tex]It means that tan(2u) is -65/72.
The next step is to rewrite the equations for sin(2u) and cos(2u) to have them in terms of the least number of variables possible, this way:
[tex]\begin{gathered} sin(2u)=2sin(u)cos(u) \\ sin(2u)=2sin(u)\frac{sin(u)}{tan(u)} \\ sin(2u)=\frac{2sin^2(u)}{tan(u)} \end{gathered}[/tex][tex]\begin{gathered} cos(2u)=cos{}^2(u)-sin^2(u) \\ cos(2u)=1-sin^2(u)-s\imaginaryI n^2(u) \\ cos(2u)=1-2sin^2(u) \end{gathered}[/tex]If we rewrite tan(2u) in terms of sin(2u) and cos(2u) we will have:
[tex]\begin{gathered} tan(2u)=\frac{sin(2u)}{cos(2u)} \\ tan(2u)=\frac{\frac{2s\imaginaryI n^{2}(u)}{tan(u)}}{1-2sin^2(u)} \end{gathered}[/tex]We know the values of tan(2u) and tan(u), so we can solve the equation for sin^2(u).
[tex]\begin{gathered} tan(2u)=\frac{2sin^2(u)}{tan(u)(1-2sin^2(u))} \\ -\frac{65}{72}=\frac{2s\imaginaryI n^2(u)}{\frac{13}{5}(1-2s\imaginaryI n^2(u))} \\ -\frac{65}{72}\cdot\frac{13}{5}\cdot(1-2sin^2(u))=2sin^2(u) \\ -\frac{169}{72}(1-2sin^2(u))=2sin^2(u) \\ -1+2sin^2(u)=\frac{72}{169}\cdot2sin^2(u) \\ -1+2sin^2(u)=\frac{144}{169}sin^2(u) \\ 2sin^2(u)-\frac{144}{169}sin^2(u)=1 \\ \frac{194}{169}sin^2(u)=1 \\ sin^2(u)=\frac{169}{194} \end{gathered}[/tex]Using this value we can find the values of sin(2u) and cos(2u):
[tex]\begin{gathered} sin(2u)=\frac{2sin^2(u)}{tan(u)} \\ sin(2u)=\frac{2\cdot\frac{169}{194}}{\frac{13}{5}} \\ sin(2u)=\frac{65}{97} \end{gathered}[/tex][tex]\begin{gathered} cos(2u)=1-2sin^2(u) \\ cos(2u)=1-2\cdot\frac{169}{194} \\ cos(2u)=1-\frac{169}{97} \\ cos(2u)=-\frac{72}{97} \end{gathered}[/tex]It means that sin(2u)=65/97, cos(2u)=-72/97 and tan(2u)=-65/72.
How much should be invested now at an interest rate of 6.5% per year, compounded continuously l, to have $3500 in four years.Round your answer to the nearest cent.
Answers
Okay, here we have this:
Considering the provided information we are going to replace in the formula of continuous compound interest:
[tex]\begin{gathered} A=Pe^{rt} \\ 3500=Pe^{(0.065\cdot4)} \end{gathered}[/tex]Now, let's solve for P:
[tex]\begin{gathered} P=\frac{3500}{e^{0.26}} \\ P=$2,698.68$ \end{gathered}[/tex]Finally we obtain that should be invested $2,698.68.
Find the range of the function for the given domain: {-4, 0, 4}
f(x)=x²-2
O {-14, 2)
O {-14, 2, 18)
O {-2, 14)
O (-18, -2, 14)
Answers
Answer:
{-2,14}
Step-by-step explanation:
f(-4) = f(4) = 14
f(0) = -2
There are 25
students in an
Algebra class. 9 of
them got an A on
the test. What
percent of them
scored an A?
Answers
Answer:
36%
Step-by-step explanation:
First, you would write that as a fraction, which would be 9/25. Then, you'd convert the fraction to a percentage by getting the denominator to 100. Multiply the numerator and denominator by 4 to achieve this. The answer would be 36/100, which translates to 36%.
A group of workers can plant 334 acres in 118 days. What is the unit rate in acres per day? Write your answer as a fraction or a mixed number in simplest form.
Answers
Number of acres = 334
Number of days = 118 days
unit rate = Number of acres/Number of days
Unit rate = 334 acres/114 days
2 is common to both numerator and denominator
Divide both by 2:
Unit rate = 167/57
No other number asides 1 is common to both the numerator and denominator
Hence, the unit rate in acres per day is 167/57
In mixed fraction = 2 53/57
Simplify:6.2n - 8.3 + -9.1 + 1.4n
Answers
ANSWER
7.6n - 17.4
EXPLANATION
We have the expression that we want to simplify.
We have:
6.2n - 8.3 + (-9.1) + 1.4n
The first step is to collect like terms:
=> 6.2n + 1.4n - 8.3 - 9.1
Now, simplify:
7.6n - 17.4
That is the answer.
The organizer of a conference is selecting workshops to include. She will select from 6 workshops about chemistry and 7 workshops about biology. In how many ways can she select 4 workshops if 2 or fewer must be about chemistry?
Answers
Given that there are 6 workshops about chemistry and 7 workshops about biology.
So the total number of workshops available are,
[tex]\begin{gathered} =6+7 \\ =13 \end{gathered}[/tex]The number of ways of selecting 'r' objects from 'n' distinct objects is given by,
[tex]^nC_r=\frac{n!}{r!\cdot(n-r)!}[/tex]The total number of ways of selecting 4 workshops having no workshop about chemistry is calculated as,
[tex]\begin{gathered} n(\text{ 0 chemistry)}=^7C_4 \\ n(\text{ 0 chemistry)}=\frac{7!}{4!\cdot(7-4)!} \\ n(\text{ 0 chemistry)}=\frac{7\cdot6\cdot5\cdot4!}{4!\cdot3!} \\ n(\text{ 0 chemistry)}=\frac{7\cdot6\cdot5}{3\cdot2\cdot1} \\ n(\text{ 0 chemistry)}=35 \end{gathered}[/tex]The total number of ways of selecting 4 workshops having exactly 1 workshop about chemistry is calculated as,
[tex]\begin{gathered} n(\text{ 1 chemistry)}=^7C_3\cdot^6C_1 \\ n(\text{ 1 chemistry)}=\frac{7!}{3!\cdot(7-3)!}\cdot\frac{6!}{1!\cdot(6-1)!} \\ n(\text{ 1 chemistry)}=\frac{7\cdot6\cdot5\cdot4\cdot3!}{3!\cdot4!}\cdot\frac{6\cdot5!}{1!\cdot5!} \\ n(\text{ 1 chemistry)}=\frac{7\cdot6\cdot5\cdot4}{4\cdot3\cdot2\cdot1}\cdot6 \\ n(\text{ 1 chemistry)}=210 \end{gathered}[/tex]The total number of ways of selecting 4 workshops having exactly 2 workshops about chemistry is calculated as,
[tex]\begin{gathered} n(\text{ 2 chemistry)}=^7C_2\cdot^6C_2 \\ n(\text{ 2 chemistry)}=\frac{7!}{2!\cdot(7-2)!}\cdot\frac{6!}{2!\cdot(6-2)!} \\ n(\text{ 2 chemistry)}=\frac{7\cdot6\cdot5!}{2!\cdot5!}\cdot\frac{6\cdot5\cdot4!}{2!\cdot4!} \\ n(\text{ 2 chemistry)}=\frac{7\cdot6}{2\cdot1}\cdot\frac{6\cdot5}{2\cdot1} \\ n(\text{ 2 chemistry)}=315 \end{gathered}[/tex]Consider that the number of ways to select 4 workshops if 2 or fewer must be about chemistry, will be equal to the sum of the individual cases when the number of chemistry workshops in the selection are either 0 or 1 or 2.
This can be calculated as follows,
[tex]\begin{gathered} \text{ Total}=n(\text{ 0 chemistry)}+n(\text{ 1 chemistry)}+n(\text{ 2 chemistry)} \\ \text{Total}=35+210+315 \\ \text{Total}=560 \end{gathered}[/tex]Thus, the total number of ways is 560.
n - 3 over 10 = 3 over 5
Answers
The given expression is
[tex]\frac{n-3}{10}=\frac{3}{5}[/tex]First, we multiply by 10 on each side.
[tex]\begin{gathered} 10\cdot\frac{n-3}{10}=\frac{3}{5}\cdot10 \\ n-3=6 \end{gathered}[/tex]Then, we sum 3 on each side.
[tex]\begin{gathered} n-3+3=6+3 \\ n=9 \end{gathered}[/tex]Therefore, the solution is 9.If f(x) is a third degree polynomia function, how many distinct complex roots are possible?
Answers
Complex roots always appear in pairs, actually if a+ib is a root then a-ib is also a root. Then, at most there are 2 complex roots in a third degree polynomial.
Paul has $50,000 to invest. His intent is to earn 13% interest on his investment. He can invest part of his money at 8% interest and part at 16% interest. How much does Paul need to invest in each option to make a total 13% return on his $50,000?8% interest $ 16% interest $
Answers
Let x be the amount invest at 8%
Let y be the amount invest at 16%
Paul has $50,000 to invest:
[tex]x+y=50,000[/tex]His intent is to earn 13% interest on his investment. He can invest part of his money at 8% interest and part at 16% interest.
[tex]\begin{gathered} 50,000(0.13)=x(0.08)+y(0.16) \\ \\ 6,500=0.08x+0.16y \end{gathered}[/tex]Use the next system of equations to find x and y:
[tex]\begin{gathered} x+y=50,000 \\ 6,500=0.08x+0.16y \end{gathered}[/tex]1. Solve x in the first equation:
[tex]x=50,000-y[/tex]2. Substitute the x in the second equation by the value you get in the previous step:
[tex]6,500=0.08(50,000-y)+0.16y[/tex]3. Solve y:
[tex]\begin{gathered} 6,500=4,000-0.08y+0.16y \\ 6,500=4,000+0.08y \\ 6,500-4,000=0.08y \\ 2,500=0.08y \\ \frac{2,500}{0.08}=y \\ \\ y=31,250 \end{gathered}[/tex]4. Use the value of y to solve x:
[tex]\begin{gathered} x=50,000-y \\ x=50,000-31,250 \\ x=18,750 \end{gathered}[/tex]Solution for the system:
x=18,750
y=31,250
Answer: Paul needs to invers8% interest $18,75016% interest $31,250