NO LINKS!! Use the method of substitution to solve the system. (If there's no solution, enter no solution). Part 11z​

NO LINKS!! Use The Method Of Substitution To Solve The System. (If There's No Solution, Enter No Solution).

Answers

Answer 1

Answer:

smaller x value:    -1,-8larger x value:  5,16

The parenthesis part is already taken care of by the teacher.

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Explanation:

y is equal to x^2-9 and also 4x-4. We can equate those two right hand sides and get everything to one side like this

x^2-9 = 4x-4

x^2-9-4x+4 = 0

x^2-4x-5 = 0

Then we can use the quadratic formula to solve that equation for x.

[tex]x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(-4)\pm\sqrt{(-4)^2-4(1)(-5)}}{2(1)}\\\\x = \frac{4\pm\sqrt{36}}{2}\\\\x = \frac{4\pm6}{2}\\\\x = \frac{4+6}{2} \ \text{ or } \ x = \frac{4-6}{2}\\\\x = \frac{10}{2} \ \text{ or } \ x = \frac{-2}{2}\\\\x = 5 \ \text{ or } \ x = -1\\\\[/tex]

Or alternatively

x^2-4x-5 = 0

(x-5)(x+1) = 0

x-5 = 0 or x+1 = 0

x = 5 or x = -1

------------------------------

After determining the x values, plug them into either original equation to find the paired y value.

Let's plug x = 5 into the first equation:

y = x^2-9

y = 5^2-9

y = 25-9

y = 16

Or you could pick the second equation:

y = 4x-4

y = 4(5)-4

y = 20-4

y = 16

We have x = 5 lead to y = 16

One solution is (x,y) = (5,16)

This is one point where the two curves y = x^2-9 and y = 4x-4 intersect.

If you repeat the same steps with x = -1, then you should find that y = -8 for either equation.

The other solution is (x,y) = (-1,-8)

Answer 2

Answer:

[tex](x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}[/tex]

[tex](x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}[/tex]

Step-by-step explanation:

Given system of equations:

[tex]\begin{cases}y=x^2-9\\y=4x-4\end{cases}[/tex]

To solve by the method of substitution, substitute the first equation into the second equation and rearrange so that the equation equals zero:

[tex]\begin{aligned}x^2-9&=4x-4\\x^2-4x-9&=-4\\x^2-4x-5&=0\end{aligned}[/tex]

Factor the quadratic:

[tex]\begin{aligned}x^2-4x-5&=0\\x^2-5x+x-5&=0\\x(x-5)+1(x-5)&=0\\(x+1)(x-5)&=0\end{aligned}[/tex]

Apply the zero-product property and solve for x:

[tex]\implies x+1=0 \implies x=-1[/tex]

[tex]\implies x-5=0 \implies x=5[/tex]

Substitute the found values of x into the second equation and solve for y:

[tex]\begin{aligned}x=-1 \implies y&=4(-1)-4\\y&=-4-4\\y&=-8\end{aligned}[/tex]

[tex]\begin{aligned}x=5 \implies y&=4(5)-4\\y&=20-4\\y&=16\end{aligned}[/tex]

Therefore, the solutions are:

[tex](x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}[/tex]

[tex](x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}[/tex]


Related Questions

suppose we spin the following spinner with the first spin giving us the numerator and the second spin giving the denominator of a fraction. What is the probability that the fraction will be less than or equal to 5/6?

Answers

numerator = top number

denominator = bottom number

numerator less than or equal to 5

total numbers = 4

numbers less than or equal to 5 = 2 ( 5 and 4)

Denominator

5, 6 or 7 = 3

Possible fractions = 4/5, 4/6, 4/7, 5/6 and 5/7

5 out of 16 possible fractions

probability = 5/16

Need help finding the x-intercepts for equation in picture. I can see them on the graph but I need to work it out by solving.

Answers

Answer:

The x-intercepts of the function are;

[tex]\begin{gathered} x=-2 \\ \text{and} \\ x=-4 \end{gathered}[/tex]

Explanation:

Given the function;

[tex]f(x)=-2(x+3)^2+2[/tex]

We want to derive the x-intercepts of the function.

The x-intercept is at f(x)=0;

[tex]\begin{gathered} f(x)=-2(x+3)^2+2=0 \\ -2(x+3)^2+2=0 \\ -2(x^2+6x+9)^{}+2=0 \\ -2x^2-12x-18^{}+2=0 \\ -2x^2-12x-16=0 \\ -x^2-6x-8=0 \\ x^2+6x+8=0 \end{gathered}[/tex]

solving for x;

[tex]\begin{gathered} x^2+6x+8=0 \\ x^2+2x+4x+8=0 \\ (x+2)(x+4)=0 \\ x+2=0 \\ x=-2 \\ \text{and} \\ x+4=0 \\ x=-4 \end{gathered}[/tex]

Therefore, the x-intercepts of the function are;

[tex]\begin{gathered} x=-2 \\ \text{and} \\ x=-4 \end{gathered}[/tex]

Method 2: quadratic root property;

[tex]\begin{gathered} f(x)=-2(x+3)^2+2=0 \\ -2(x+3)^2+2=0 \\ -2(x+3)^2=-2 \\ \text{divide both sides by -2;} \\ (x+3)^2=1 \\ \text{square root both sides;} \\ \sqrt{(x+3)^2}=\sqrt{1} \\ x+3=\pm1 \\ x=-3\pm1 \\ so\text{ the values of x are;} \\ x=-3+1=-2 \\ \text{and} \\ x=-3-1=-4 \end{gathered}[/tex]

Therefore, the x-intercepts are;

[tex]\begin{gathered} x=-2 \\ \text{and } \\ x=-4 \end{gathered}[/tex]

What is the y-intercept of the graph of y = 2.5x?a. 2.5b. 0c. 1d. -1

Answers

Solution

- We are asked to find the y-intercept of the graph of:

[tex]y=2.5x[/tex]

- In order to find the y-intercept, we need to know the definition of the y-intercept.

- The y-intercept is the y-value where the graph crosses the y-axis.

- An implication of this definition is that whenever the graph crosses the y-axis, the x-value at that point is zero. This means that we simply need to substitute x = 0 into the equation given to us to find the y-intercept of the graph.

- The y-intercept can thus is gotten as follows:

[tex]\begin{gathered} y=2.5x \\ \text{put }x=0 \\ y=2.5(0) \\ \\ \therefore y=0 \end{gathered}[/tex]

Final Answer

The y-intercept of the graph is y = 0 (OPTION B)

how do i get 24 using numbers 5,8,0.3,5 once

Answers

The given numbers are 5, 8, 0.3, 5. To get 24 from these numbers, we form the following expression

[tex](5+5)\cdot8\cdot0.3[/tex]

Let's solve it to see if it gives 24 at the end.

[tex](5+5)\cdot8\cdot0.3=(10)\cdot8\cdot0.3=10\cdot0.24=24[/tex]

Therefore, the answer is

[tex](5+5)\cdot8\cdot0.3[/tex]

1. Sue uses 2.59 pounds ofstrawberries and 0.65 poundof blueberries to make fruitsalad. She serves the sameamount of salad in each of 9bowls. What is the weight,in pounds, of each serving tothe nearest tenth?

Answers

Problem:

Sue uses 2.59 pounds of strawberries and 0.65 pounds of blueberries to make a fruit salad. She serves the same amount of salad in each of 9

bowls. What is the weight, in pounds, of each serving to

the nearest tenth?

Solution:

The total weight of the fruit salad is:

2.59 pounds + 0.65 pounds = 3.24 pounds.

Now, if she serves the same amount of salad in each of 9 bowls, we have that the weight in each serving is:

[tex]\frac{3.24}{9}=\text{ 0.36 pounds}[/tex]

Then, we can conclude that the correct answer is:

0.36 pounds.

Dante is saving money to buy a game. So far he has saved $20, which is four-fiths of the total cost of the game. How much does the game cosх$?

Answers

Money saved = $20

According to the statement we can establish the following equation

[tex]20=\frac{4}{5}X[/tex]

where X is the total cost of the game

now let's find X

[tex]\begin{gathered} \frac{4}{5}X=20 \\ 5\cdot\frac{4}{5}X=20\cdot\: 5 \\ 4X=100 \\ \frac{4X}{4}=\frac{100}{4} \\ X=25 \end{gathered}[/tex]

Therefore the total cost of the videogame is $25

1. Graph each of the following equations below using a tale of values or by another method. Fill in theInformation for each graph.X-intercept:a) y = x2 + 4x - 5y-intercept:хуVertex:Max/MinAxis of SymmetryDomain:Range:

Answers

The equation is

[tex]y=x^2+4x-5[/tex]

We can already find the vertex using the vertex formulas

[tex]\begin{gathered} x_V=-\frac{b}{2a}=\frac{-4}{2}=-2 \\ \\ \\ y_V=-\frac{\Delta}{4a}=-\frac{b^2-4ac}{4a}=-\frac{16+20}{4}=-\frac{36}{4}=-9 \end{gathered}[/tex]

Therefore the vertex is

[tex](x_V,y_V)=(-2,-9)[/tex]

Now we have the vertex we also have the axis of symmetry and the max/min of the function, in that case, it's a minimum because a > 0. Therefore

[tex]\begin{gathered} \text{ axis of symmetry = }x_V=-2 \\ \\ \min\lbrace y\rbrace=y_V=-9 \end{gathered}[/tex]

We can find the x-intercept easily

[tex]\begin{gathered} x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \\ \\ x=\frac{-4\pm\sqrt{4^2+4\cdot5}}{2} \\ \\ x=\frac{-4\pm\sqrt{16+20}}{2} \\ \\ x=\frac{-4\pm\sqrt{36}}{2} \\ \\ x=\frac{-4\pm6}{2} \\ \\ \end{gathered}[/tex]

Hence

[tex]\begin{gathered} x=\frac{-4\pm6}{2}=-2\pm3 \\ \\ x_1=-1 \\ x_2=-5 \end{gathered}[/tex]

The y-intercept is just the c value, then it's -5.

Now we can do the domain, there's no restriction for parabolas in the domain, then

[tex]\text{ domain = }\mathbb{R}[/tex]

And the range is

[tex]\text{ range = \lbrack}y_V,+\infty)=[-9,+\infty)[/tex]

Solve for v. v + 4/5 = 1/3. Simplify your answer as much as possible.

Answers

Answer:

v = -7/15.

Explanation:

Given the equation:

[tex]v+\frac{4}{5}=\frac{1}{3}[/tex]

To solve for v, first, subtract 4/5 from both sides of the equation:

[tex]\begin{gathered} v+\frac{4}{5}-\frac{4}{5}=\frac{1}{3}-\frac{4}{5} \\ \implies v=\frac{1}{3}-\frac{4}{5} \end{gathered}[/tex]

Next, simplify the right-hand side by taking the lowest common multiple of the denominators:

[tex]\begin{gathered} v=\frac{5-3(4)}{15}=\frac{5-12}{15} \\ \implies v=-\frac{7}{15} \end{gathered}[/tex]

The value of v is -7/15.

find all real solutions[tex](2x + 17) \div (x + 1) = x + 5[/tex]

Answers

We have the next equation

[tex]\frac{2x+17}{x+1}=x+5[/tex][tex]2x+17=(x+5)(x+1)[/tex][tex]\begin{gathered} 2x+17=x^2+x+5x+5 \\ 2x+17=x^2+6x+5 \end{gathered}[/tex]

Then we sum similar terms

[tex]\begin{gathered} x^2+(6x-2x)+(5-17)=0 \\ x^2+4x-12=0 \end{gathered}[/tex]

then we solve the quadratic equation

We can factorize the equation

[tex](x+6)(x-2)=0[/tex]

so the solutions are

x=-6

x=2

Stuck on this question, any help greatly appreciated.Don't understand the concept of what the question is asking

Answers

You have the line segment PQ shown in the exercise. Notice that you must copy the length of that line using the compass. Notice that one of the endpoints of the new line is R.

In order to copy it, you can follow these steps:

1. You need to place the compass on one of the endpoints of the line PQ.

2. Open the compass to the length of the segment PQ (one leg of the compass must be on the endpoint P and the other one on the endpoint Q).

3. Using the amount of opening found in the previous step, place the compass on the point R and make a mark with the other leg of the compass.

Notice that by applying these steps, you get a segment with the same length of PQ.

Therefore, the answer is:

An expression is shown.2 3/4÷4 1/2What is the value of the expression, in simplest form?

Answers

ANSWER

[tex]\frac{11}{18}[/tex]

EXPLANATION

Given:

[tex]2\frac{3}{4}\div4\frac{1}{2}[/tex]

Lamar has $80,000 in a savings account. the interest rate is 1% per year and is not compounded. to the nearest cent how much will he have in 3 years?

Answers

Simple Interest

The interest rate for Lamar's savings account is 1% per year. This means his money earns 1% at the end of each year.

The formula to calculate the interest is:

I = P.r.t

Where P is the principal or initial saved amount, r is the interest rate, and t is the time.

P = $80,000

r = 1%. This must be converted to decimal

r = 1 / 100 = 0.01

t = 3 years

Calculate the interest:

I = 80,000*0.01*3

I = $2,400

That amount is added to the principal:

A = P + I

A = $80,000 + $2,400

A = $82,400

He will have $82,400 in 3 years

Factor completely.28 – 7x2Show Calculator

Answers

[tex]28-7x^2[/tex][tex]7(4-x^2)[/tex][tex]7((2-x)(2+x))[/tex]

What is the value of cos(150°)?

Answers

Given that cos(150°).

[tex]\cos (150^o)=\cos (180^o-30^o)[/tex][tex]\text{Use }\cos (180^o-30^o)=-\cos 30^o[/tex]

[tex]\cos (150^o)=-\cos (30^o)[/tex][tex]\text{Use }\cos (30^o)=\frac{\sqrt[]{3}}{2}\text{.}[/tex]

[tex]\cos (150^o)=-\frac{\sqrt[]{3}}{2}[/tex]

Hence the required value is

[tex]\cos (150^o)=-\frac{\sqrt[]{3}}{2}[/tex]

The minimum diameter for a hyperbolic cooling tower is 76 feet, which occurs at a height of 173 feet. The top of the cooling tower has a diameter of 93 feet, and the total height of the tower is 250 feet. Write the equation for the hyperbola that models the sides of the cooling tower assuming that the center of the hyperbola occurs at the height for which the diameter is least.Round your a and b values to the nearest hundredth if necessary.

Answers

STEP - BY - STEP EXPLANATION

What to find?

The equation for the hyperbola that models the sides of the cooling tower assuming that the center of the hyperbola occurs at the height for which the diameter is least.

Given:

Minimum diameter = 76 feet

Height = 173 feet

Diameter of the top of cooling tower = 93 feet

Total height of tower = 250 feet

Consider the general hyperbolic formula below:

[tex]\frac{x^2}{a^2}-\frac{y^2}{b^2}=1[/tex]

But;

2a = 76

⇒ a = 38

x=93/2 =46.5

y=250 - 173 =77

Substitute the values into the formula above and determine the value of b.

[tex]\frac{(46.5)^2}{38^2}-\frac{77^2}{b^2}=1[/tex][tex]b=109.18[/tex]

Now substitute the values a= 38 and b=109.18 into the general formula

[tex]\frac{x^2}{38^2}-\frac{y^2}{109.18^2}=1[/tex]

ANSWER

[tex]\frac{x^2}{38^2}-\frac{y^2}{109.18^2}=1[/tex]

(08.01 MC)Find the height of a square pyramid that has a volume of 12 cubic feetand a base length of 3 feet. (1 point)

Answers

Recall that we can do the following picture

We want to find the height of this pyramid and are told the volume of the pyramid. Recall that the volume of a square pyramid of height h and base length b is given by the formula

[tex]V=\frac{1}{3}b^2\cdot h[/tex]

In our case, we have V=12, and b=3. So we have the following equation

[tex]12=\frac{1}{3}\cdot3^2\cdot h=3\cdot h[/tex]

So, we should find the value of h from this equation. To do, we simply divide both sides by 3, so we get

[tex]h=\frac{12}{3}=4[/tex]

so the height of the pyramid is 4 feet.

In the diagram of \bigtriangleup△GKJ below, LH KJ, GL=6, LK=30, and GH=3. What is the length of GJ?

Answers

From the given figures

Since LH // KJ, then

[tex]\frac{GL}{LK}=\frac{GH}{HJ}[/tex]

GL = 6, LK = 30

GH = 3, HJ = y

Substitute them in the ratio above

[tex]\frac{6}{30}=\frac{3}{y}[/tex]

By using cross multiplication

[tex]\begin{gathered} 6\times y=30\times3 \\ 6y=90 \end{gathered}[/tex]

Divide both sides by 6

[tex]\begin{gathered} \frac{6y}{6}=\frac{90}{6} \\ y=15 \end{gathered}[/tex]

Since GJ = GH + HJ

[tex]\begin{gathered} GJ=3+15 \\ GJ=18 \end{gathered}[/tex]

The answer is 36

Which of the following statements is NOT true about the data above?

Answers

Explanation

A matrix is a rectangular array of numbers arranged into columns and rows

[tex]\begin{bmatrix}{a_{11}} & {a_{21}} & {.} & {a_{1n}} \\ {a_{21}} & {.\text{.}} & {.} & {\square} \\ {a_{31}} & {.\text{.}} & {.\text{.}} & {\square} \\ {a_{41}} & {.\text{.}} & {.\text{.}} & {a_{mn}}\end{bmatrix}[/tex]

where m is the number of rows and n is the number of columns

The dimensions of a matrix tells its size: the number of rows and columns of the matrix, in that order.

Step 1

check the dimension of the given functino

rows:5

columns: 4

therefore the matrix is a 5 *4 matrix: true

Step 2

the matrix shows the number of medalls for 5 countries,

we can see that the total for USA is 7, so USA has won the most overall medals in Olumpic soccer :true

Step 3

[tex]C_{3,1}[/tex]

it is

rows:3

column 1

we can see the entry for C(3,1) is

3

hence

C) false

Step 4

[tex]C_{4,1}[/tex]

it is

rows:4

column 1

it indicates Nigeria has won 1 medal in Olympic soccer

threfo

which number is four units away from -1a) -3b) - 4 c) 3d) 4

Answers

3 (option c)

Explanation:

Four units away from -1 could be towards the negative number line or positive number line

Towards the negative number from -1 = -2, -3, -4, -5

4th number = -5

Towards the positive number from -1 = 0, 1, 2, 3

4th number = 3

From the above, the number that could be found in the option is 3

Hence, four units away from -1 is 3 (option c)

I need help with my pre-calc work! The question image is attached.Which of the functions are bounded below? Check the two that apply.g(x) = -4xg(x) = xˆ2g(x) = xˆ3g(x) = | x + 4 | - 1

Answers

using a graphing tool

graph the functions

see the attached figure to better understand the problem

Remember that

A function f is bounded below if there is some number b that is less than or equal to every number in the range of f.

therefore

in this problem

g(x)=x^2 and g(x)=x^3 are bounded below

Which car gets better mileage: a car that gets 23 miles per gallon or a car that gets 45 kilometers per gallon?​

Answers

A car that gets 45 kilometers per gallon has better mileage than a car that gets 23 miles per gallon

What is mileage of a car?

The mileage of a car is the number of miles that it can travel using one gallon or litre of fuel.

The first car that gets a mileage of 23 miles per gallon

The second car gets 45 kilometers per gallon

1 mile = 1.6 km

1 km = 1/1.6 mile

45 km = (1/1.6) 45

45 km = 28.125 miles

28.125  miles > 23 miles

Therefore,  a car that gets 45 kilometers per gallon has better milegae than a car that gets 23 miles per gallon

To learn more about conversion refer here

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how do you write out this number in word 506,341,209.54

Answers

You write this number in word this way:

Five hundred six million three hundred fourty one thousand two hundred nine point fifty four.

The coordinates of the vertices of triangle RST are R(-2, -3), S(4,5), and T (8,2). List the angles of triangle RST in order from smallest to largest.

Answers

The first step is to plot the triangle RST with the given coordinates. The diagram of the triangle RST is shown below. We can see that the smallest angle is angle R, The larger angle is angle T while the largest angle is angle S

Listing the angles in order from smallest to largest.​, it becomes

angle R, angle T and angle S

The scatterplot shows the average number of hours each of 13 people spends at work every week and the average number of hours each of them spends recreational activities every week.Based on the scatterplot,what is the best prediction of the average number of hours a person spends at work every week if that person spends an average of 10 hours on recreational activities every week?A.33 hB.95 hC.50 hD.65 h

Answers

We want to find the best prediction of the average number of hours a person spends at work every week if that person spends an average of 10 hours on recreational activities every week.

We will construct a line that adapts to the system by simple linear regression, and then we will find the x-value that makes the line take y=10.

First, we have the data:

We remember that in a simple regression model, we want to write an equation of the form:

[tex]y=\hat{\alpha}+\hat{\beta}x[/tex]

where:

[tex]\begin{gathered} \hat{\alpha}=\bar{y}-\hat{\beta}\bar{x} \\ \hat{\beta}=\frac{nS_{xy}-S_xS_y}{nS_{xx}-S^2_x}_{} \end{gathered}[/tex]

And the Sx, Sy and Sxx are the sums over all the x-values, the y-values and the multiplication of the x-values and y-values (respectively).

We will find those values:

[tex]\begin{gathered} S_x=\sum ^{13}_{i=1}x_i=370 \\ S_y=\sum ^{13}_{i=1}y_i=336.5 \end{gathered}[/tex]

Also, we have:

[tex]\begin{gathered} S_{xx}=\sum ^{13}_{i=1}x^2_i=12600 \\ S_{xy}=\sum ^{13}_{i=1}x_iy_i=8680_{}_{} \end{gathered}[/tex]

And applying the formula, having in mind that n=13, we get:

[tex]\begin{gathered} \hat{\beta}=\frac{nS_{xy}-S_xS_y}{nS_{xx}-S^2_x}_{} \\ =\frac{13(8680)-(370)(336.5)}{13(12600)-(370^2)} \\ =\frac{-11665}{26900} \\ \approx-0.4336 \end{gathered}[/tex]

And, for alpha:

[tex]\begin{gathered} \hat{\alpha}=\frac{1}{n}S_y-\hat{\beta}\frac{1}{n}S_x \\ =\frac{1}{13}(336.5)-(-0.4336)\frac{1}{13}(370) \\ \approx38.2255 \end{gathered}[/tex]

This means that the linear regression equation will be:

[tex]y=38.2255-0.4336x[/tex]

For finding the x-value that will have 10 hours of recreational activities, we replace the 10 value on y, and clear out the variable x:

[tex]10=38.2255-0.4336x[/tex]

And thus,

[tex]\begin{gathered} 10-38.2255=-0.4336x \\ \frac{-28.2255}{-0.4336}=x \\ 65.09=x \end{gathered}[/tex]

This means that when a person works 65 hours approximately, he will have 10 hours of recreational activities every week.

A rectangular play area has an area of 7,497 square meters. If the width of the rectangle is 49 meters, find the length.

Answers

If a rectangular play area has an area of 7,497 square meters. and the width of the rectangle is 49 meters, then the length is 153 meters

A rectangular play area has an area of 7,497 square meters

If the width of the rectangle is 49 meters

Let the length of the rectangular play be l

Area of a rectangle can be given by

area = length x width

7497 = l x 49

l = 7497 / 49

l = 153

Therefore, if a rectangular play area has an area of 7,497 square meters. and the width of the rectangle is 49 meters, then the length is 153 meters

To learn more about rectangle refer here

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Write the expression that can be used tofind the height of the Eiffel Tower.

Answers

First, let's picture the problem:

I have represented the height of the Effiel tower as H

Using the trigonometric ratios:

[tex]\begin{gathered} \tan 53^0\text{ = }\frac{H}{225} \\ H=225\times\tan 53^0^{} \end{gathered}[/tex]

Hence the required expression is :

[tex]\begin{gathered} \text{Height of tower = d }\times\text{ tan}\phi \\ \text{if d is the distance of the base} \end{gathered}[/tex]

Find each unit price and decide which is the better buy. Assume that we are comparing sizes of the same breadFrozen orange juice $1.51 for 14 ounces $0.51 for 4 ounces Find the unit price if a frozen orange juice which cost $1.51 for 14 ounces

Answers

Answer:

Unit price of a frozen orange juice which costs $1.51 for 14 ounces = $0.108 per ounce

Unit price of a frozen orange juice which costs $0.51 for 4 ounces = $0.128

The better buy is the frozen orange juice which costs $1.51 for 14 ounces

Option B

Explanations:

Cost of 14 ounces of orange juice = $1.51

Cost od 4 ounces of orange juice = $0.51

Unit price of a frozen orange juice which costs $1.51 for 14 ounces

Unit price = $1.51 / 14

Unit price of a frozen orange juice which costs $1.51 for 14 ounces = $0.108 per ounce

Unit price of a frozen orange juice which costs $0.51 for 4 ounces

Unit price = $0.51 / 4

Unit price of a frozen orange juice which costs $0.51 for 4 ounces = $0.128

The better buy is the one with the lower unit price

Since the frozen orange juice which costs $1.51 for 14 ounces has the lower unit price, it is the better buy

Point C is between A and B on AB. Use the given information to write an equation in terms of x. Then solve the equation to find x, AC, BC, and AB.

Answers

We have the following:

[tex]\begin{gathered} AB=AC+CB \\ AC=2x+5 \\ AB=27x \\ CB=5x+15 \end{gathered}[/tex]

replacing:

[tex]\begin{gathered} 27x=2x+5+5x+15 \\ 27x-2x-5x=20 \\ 20x=20 \\ x=\frac{20}{20} \\ x=1 \end{gathered}[/tex]

Therefore:

[tex]\begin{gathered} AC=2\cdot1+5=7 \\ AB=27\cdot1=27 \\ CB=5\cdot1+15=20 \end{gathered}[/tex]

x = 1

AC = 7

AB = 27

CB = 20

Question 8 of 10The table below shows the number of e-mails received each day by acompany employee for two separate weeks. If the data were represented witha comparative dot plot, which day would have more dots for week 2 than forweek 1?Week 1 Week 2Monday74.Tuesday83Wednesday52Thursday97Friday69

Answers

Solution

It's Friday

Because, the number of dots for week 2 is 9, while the number of dots for week 1 is 6.

Hence, the correct option is A.

Is this correct? If not can you show me how to do it?

Answers

D. The rental cost in dollars, for each paddleboard.

Explanation:

You were in the right track with linking 40 to the paddleboards.

But remember that t represent the total cost and not the total number of paddleboards and kayak, and also since p represent the number of paddleboards (while k represent the number of kayak)

To find t, you need to sum the cost of all the kayaks and the sum of all the paddleboards.

=> t = 25k + 40p

with 25k = total cost of all the kayaks

and

with 40p = total cost of all the paddleboards => in others words the total number of paddleboards (p) * the cost of each paddleboards (40)

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