Multiply. (2x-1)(3x+5)

Answer:

D) 580%

Step-by-step explanation:

you move the decimal to the right twice.

5.8 ---> 580%

hope this helps :)

Answer:

MAYBE

Step-by-step explanation:

Answer:

1. The surface area of the cube is 324 square units

The volume of the cube 360 unit cube

2. The surface area of the cylinder is approximately 169.65 square units

The volume of the cylinder is approximately 169.65 unit cube

3. The surface area of a square pyramid is 360 square units

The volume of the square pyramid is 400 unit cube

4. The surface area of a cone is approximately 452.39 square units

The volume of the cone is approximately 50.27 unit cube

5. The surface area of the triangular prism is 240 square units

The volume of the triangular prism is 180 unit cube

6. The surface area of the sphere is approximately 804.25 square units

The volume of the sphere is approximately 2.144.66

7. The surface area of the composite figure is approximately 653.46 square units

The volume of the composite figure is approximately 1,474.45 unit cube

Step-by-step explanation:

1. The surface area of the figure, SA = 2 × (w·h + l·w + h·l)

Where;

w = The width of the figure = 6

l = The length of the figure = 12

h = The height of the figure = 5

We get;

SA = 2 × (6 × 5 + 12 × 6 + 5 × 12) = 324

The surface area of the figure, SA = 324

The volume of the figure, V = l × w × h

∴ V = 12 × 6 × 5 = 360

The volume of the figure, V = 360

2. The surface area of a cylinder, SA = 2·π·r² + 2·π·r·h

The radius of the given cylinder, r = 3

The height of the given cylinder, h = 6

∴ SA = 2×π×3² + 2×π×3×6 ≈ 169.65

The surface area of the cylinder, SA ≈ 169.65

The volume of a cylinder, V = π·r²·h

∴ V = π×3²×6 ≈ 169.65

The volume of the cylinder, V ≈ 169.65

3. The surface area of a square pyramid, SA = b² + 4·(1/2)·b·√((b/2)² + h²)

Therefore, for the given square pyramid, we have;

SA = 10² + 4×(1/2)×10×√((10/2)² + 12²) = 360

The surface area of a square pyramid, SA = 360

The volume of a square pyramid, V = (1/3) × Area of Base × Height

Therefore, or the given pyramid we have;

V = (1/3) × 10² × 12 = 400

The volume of the square pyramid, V = 400

4. The surface area of a cone, SA = π·r·(r + l)

Where;

The radius of the cone = r

The slant height of the cone, l = 10

The height of the cone, h = 6

∴ The radius of the cone, r = √(10² - 6²) = 8

∴ SA = π×8×(8 + 10) ≈ 452.39

The surface area of a cone, SA ≈ 452.39

The volume of the cone, V = (1/3) × π·r·h

∴ V = (1/3) × π × 8 × 6 ≈ 50.27

The volume of the cone, V ≈ 50.27

5. The surface area of the triangular prism, SA = 2 × (1/2)× b·h + b·w + h·w + w·l

Where;

b = The base length of the triangular surfaces = 5

h = The height of the triangular surfaces = 12

w = The width of the triangular prism = 6

l = The slant length of the prism = 13

Therefore;

SA = 2 × (1/2)× 5 × 12 + 5 × 6 + 12 × 6 + 6 × 13 = 240

The surface area of the triangular prism, SA = 240

The volume of a triangular prism, V = (1/2)·b·h·w

V = (1/2) × 5 × 12 × 6 = 180

The volume of the triangular prism, V = 180

6. The surface of a sphere, SA = 4·π·r²

Where;

r = The radius of the sphere = 8

∴ SA = 4 × π × 8² ≈ 804.25

The surface area of the sphere, SA ≈ 804.25

The volume of a sphere, V = (4/3)·π·r³

∴ V ≈ (4/3)×π×8³ ≈ 2,144.66

The volume of the given sphere, V ≈ 2.144.66

7. The figure is a composite figure made up of a cone and an hemispher

The surface area of the cone shaped part of the figure, SA = π·r·l

Where;

r = The radius of the cone = 8

l = The slant height of the cone = 10

∴ SA₁ = π × 8 × 10 ≈ 251.34

The surface area of the cone shaped part of the figure, SA₁ ≈ 251.34

The volume of the cone, V₁ = (1/3)·π·r²·h

Where;

h = The height of the cone = √(10² - 8²) = 6

∴ V₁ = (1/3) × π × 8² × 6 ≈ 402.12

The volume of the cone, V₁ ≈ 402.12

The surface area of the hemisphere, SA₂ = 2·π·r²

∴ SA₂ = 2 × π × 8² ≈ 402.12

The surface area of the hemisphere, SA₂ ≈ 402.12

The volume of a hemisphere, V₂ = (2/3)·π·r³

∴ V₂ = (2/3) × π × 8³ ≈ 1072.33

The volume of a hemisphere, V₂ ≈ 1,072.33

The surface area of the composite figure, SA = SA₁ + SA₂

∴ SA = 251.34 + 402.12 = 653.46

The surface area of the composite figure, SA ≈ 653.46

The volume of the composite figure, V = V₁ + V₂

∴ V = 402.12 + 1,072.33 = 1,474.45

The volume of the composite figure, V ≈ 1,474.45.

Answer:

Adam scored 60, Brandon scored 66, Chen scored 74, Damion scored 75, and Erica scored 75.

Step-by-step explanation:

Since five friends took the maths test, and Adam, Brandon, and Chen together together scored 200 marks; Brandon, Chen and Damion together scored 215; Chen, Damion and Erica together scored 224; and Damion and Erica scored more than Chen; While the five of them together scored 350 marks, to determine what are their individual scores the following calculations must be performed:

Adam + Brandon + Chen = 200

Damion + Erica = 150

Brandon + Chen + Damion = 215

Adam + Erica = 135

Chen + Damion + Erica = 224

Adam + Brandon = 126

Adam + Brandon = 126 + Chen = 200

Chen = 200 - 126

Chen = 74

Damion and Erica scored more than Chen

Chen + Damion + Erica = 224

74 + Damion + Erica = 224

Damion + Erica = 150

Damion = 75

Erica = 75

Brandon + Chen + Damion = 215

Brandon + 74 + 75 = 215

Brandon = 215 - 74 - 75

Brandon = 66

Adam = 350 - 75 - 75 - 74 - 66

Adam = 60

Therefore, Adam scored 60, Brandon scored 66, Chen scored 74, Damion scored 75, and Erica scored 75.

Answer:

yes

Step-by-step explanation:

mark me brainlist please

Answer:

the answer is d  

Step-by-step explanation:

"The sum of two numbers is 20" can be translated mathematically into the equation:

x + y = 20.

"... and their difference is 10" can be translated mathematically as:

x - y = 10

We can now find the two unknown numbers, x and y, because we now have a system of two equations in two unknowns, x and y. We'll use the Addition-Subtraction Method, also know as the Elimination Method, to solve this system of equations for x and y by first eliminating one of the variables, y, by adding the second equation to the first equation to get a third equation in just one unknown, x, as follows:

Adding the two equations will eliminate the variable y:

x + y = 20

x - y = 10

-----------

2x + 0 = 30

2x = 30

(2x)/2 = 30/2

(2/2)x = 15

(1)x = 15

x = 15

Now, substitute x = 15 back into one of the two original equations. Let's use the equation showing the sum of x and y as follows (Note: We could have used the other equation instead):

x + y = 20

15 + y = 20

15 - 15 + y = 20 - 15

0 + y = 5

y = 5

CHECK:

In order for x = 15 and y = 5 to be the solution to our original system of two linear equations in two unknowns, x and y, this pair of numbers must satisfy BOTH equations as follows:

x + y = 20 x - y = 10

15 + 5 = 20 15 - 5 = 10

20 = 20 10 = 10

Therefore, x = 15 and y = 5 is indeed the solution to our original system of two linear equations in two unknowns, x and y, and the product of the two numbers x = 15 and y = 5 is:

xy = 15(5)

xy = 75

9514 1404 393

Answer:

  4 bags -- the correct answer is marked

Step-by-step explanation:

The area of a parallelogram is given by the formula ...

  A = bh

where b is the base length and h is the height.

Here, the base is the sum of lengths 2.5 yd and 6.5 yd. The height is given as 6 yd. So, the area is ...

  A = (2.5 yd + 6.5 yd)(6 yd) = 54 yd²

At 15 yd² per bag, the farmer will need ...

  (54 yd²)/(15 yd²/bag) = 3 3/5 bags

Assuming the farmer can purchase only whole bags, the farmer should purchase 4 bags of soil.

Answer:

Package 3

Step-by-step explanation:

Package 1,

No. of plates = 5

Cost = $38.75

Cost of 1 plate = [tex]\dfrac{38.75}{5}=\$7.75[/tex]

Package 2,

No. of plates = 8

Cost = $58

Cost of 1 plate = [tex]\dfrac{58}{8}=\$7.25[/tex]

Package 3,

No. of plates = 14

Cost = $94.5

Cost of 1 plate = [tex]\dfrac{94.5}{14}=\$6.75[/tex]

The cost of 1 plate in package 3 is the least. It means she should buy package 3.

Answer:

100

Step-by-step explanation:

Answer:

a) (-1/2,3/2)

Step-by-step explanation:

-3x = x + 2

4x + 2 = 0

4x = -2

x = -1/2

y = -3(-1/2) = 3/2

Answer:

V≈17974.16

Step-by-step explanation:

Using the formulas

V=4

3πr3

d=2r

Solving for V

V=1/ 6πd^3=1/ 6·π·32.53≈17974.16422

Answer:

110:55

Step-by-step explanation:

first, let's simplify all our options

110:55=10:5

the first one works!

(to check if you're not sure, ratios are fractions. using the numerator to divide, you can divide the numerator by the denominator. in this case, the numerator happens to be greater. 110/55=2. 10/5=2. they both equal to 2! they are equivalent. you can use this to solve other problems!!)

24:2= 12:1

this does not work

14:6= 7:3

this does not work

the only one that works is 110:55

hope this helped <33333

Answer:

no solution

Step-by-step explanation:

Given

2(x + 4) - 6 = 2(x - 8) + 1 ← distribute and simplify both sides

2x + 8 - 6 = 2x - 16 + 1

2x + 2 = 2x - 15 ( subtract 2 from both sides )

2x = 2x - 17 ( subtract 2x from both sides )

0 = - 17 ← not possible

This indicates the equation has no solution

Answer:

m∠Q = 109°

m∠QRT = 109°

x = 4

Step-by-step explanation:

1). "Opposite angles of a parallelogram are equal"

By this property,

m∠Q = m∠S = 109°

2). "Opposite sides of a parallelogram are parallel and equal in measure"

By this property,

RQ║ST and diagonal RT is a transversal line.

m∠QRT = ∠SRT = 30° [Alternate interior angles]

3). "Opposite sides of a parallelogram are parallel and equal in measure"

RS = QT

2x = 8

x = 4

Answer:

greatest value of X = 12

Area of square = 144 cm²

Step-by-step explanation:

The greatest value of X will be the highest common factor of 48 and 60 since we are told that the rectangle is divided into squares.

Factors of 48: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48

Factors of 60: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60

The highest common factor between both factors of 48 and 60 is 12.

Thus,

greatest value of X = 12

Area of square = 12 × 12

Area of square = 144 cm²

Answer:

715000

Step-by-step explanation:

1300000 • 55%,

55% = 0.55

1300000 • 0.55 = 715000

Answer

The area is 54cm² To get the area i split the shape into two shape both having a length of 9in and a width of 3in. I calculate the area for one by using lxw=area and get 27 and times that by two to get 54.

When calculating the area for this object you get 54 and you add the ²symbol because its area is not one dimensioned it is two dimensioned or length times width not just length, so you use the ² symbol to show that.

Answer:

the answer is

b.)42cm2

Step-by-step explanation:

if u add all the figures together u will get ur answer

Answer:

The 80% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.149, 0.207).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].

Suppose a sample of 292 tenth graders is drawn. Of the students sampled, 240 read above the eighth grade level.

So 292 - 240 = 52 read below or at eight grade level, and that [tex]n = 292, \pi = \frac{52}{292} = 0.178[/tex]

80% confidence level

So [tex]\alpha = 0.2[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.2}{2} = 0.9[/tex], so [tex]Z = 1.28[/tex].

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.178 - 1.28\sqrt{\frac{0.178*0.822}{292}} = 0.149[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.178 + 1.28\sqrt{\frac{0.178*0.822}{292}} = 0.207[/tex]

The 80% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.149, 0.207).

Given:

The slope of the line joining points (3,2) and (0,a) is -1.

To find:

The value of a.

Solution:

If a line passes through two points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex], the slope of a line is:

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

The slope of the line joining points (3,2) and (0,a) is -1. So,

[tex]\dfrac{a-2}{0-3}=-1[/tex]

[tex]\dfrac{a-2}{-3}=-1[/tex]

Multiply both sides by -3.

[tex]a-2=-1(-3)[/tex]

[tex]a-2=3[/tex]

[tex]a=3+2[/tex]

[tex]a=5[/tex]

Therefore, the value of a is 5.

Answer: there are 3150 boys and 3850 girl

Step-by-step explanation:

45÷100×7000= 3150 and 7000- 3150 = 3850

Hope this helps!!

Step-by-step explanation:

1)

7x+20°+3x=180°{straight angle}

10x=180-20

x=160/10

x=16°

again,

y=7x+20{vertically opposed angle r equal}

Answer:

1. x = 20

y = 120

2. x = 263

Step-by-step explanation:

•••

As AOB is a line,

( 7x - 20 ) + 3x = 180

7x - 20 + 3x = 180

10x - 20 = 180

10x = 180 + 20 = 200

10x = 200

x = 200/10 = 20

Then, as COD is a line,

y + 3x = 180

y + 3(20) = 180

y + 60 = 180

y = 180 - 60 = 120

•••

2. Draw a parallel line AB and CD.

Then,

Angle BAE + Angle y = 180 [Co-interior angles]

56 + y = 180

y = 180 - 56 = 124

Angle DCE + Angle z = 180

41 + z = 180

z = 180 - 41

z = 139

Now, z + y = 139 + 124 = 263

[tex][/tex]

Answer:

58 students

Step-by-step explanation:

Given

[tex]Total = 85[/tex]

[tex]French = 27[/tex]

[tex]Geometry = 51[/tex]

[tex]History = 38[/tex]

[tex]None = 5[/tex]

[tex]All = 2[/tex]

Required

Students that take only 1 subjects

The attached image illustrates the question.

For French only (x), we have:

[tex]x + 7 -2+10-2+2=27[/tex]

[tex]x + 15=27[/tex]

Collect like terms

[tex]x =- 15+27[/tex]

[tex]x =12[/tex]

For Geometry only (y), we have:

[tex]y+10-2+15-2+2=51[/tex]

[tex]y+23=51[/tex]

Collect like terms

[tex]y=-23+51[/tex]

[tex]y=28[/tex]

For History only (z), we have:

[tex]z +15-2+7-2+2=38[/tex]

[tex]z +20=38[/tex]

Collect like terms

[tex]z =-20+38[/tex]

[tex]z =18[/tex]

Students with one subject is then calculated as:

[tex]1\ subject = x+y+z[/tex]

[tex]1\ subject = 12 + 28 + 18[/tex]

[tex]1\ subject = 58[/tex]

Answer:

[tex]|x - y| > 10[/tex] ---- Nita wins

[tex]|x - y| < 10[/tex] --- Eric wins

Step-by-step explanation:

The complete instruction is to determine the range at which Erik or Nita wins.

To start with, let

[tex]x \to[/tex] Erik's score

[tex]y \to[/tex] Nita's score

If the difference is greater than 10, the Nita wins.

This implies that:

[tex]|x - y| > 10[/tex] ---- Nita

If less than 10, then Eric wins

This implies that:

[tex]|x - y| < 10[/tex] --- Eric wins

Now, assume that Nita chose 5.

For Nita to win, we have:

[tex]|x - y| > 10[/tex]

[tex]|x - 5| > 10[/tex]

Remove the absolute symbol

[tex]-10 > x - 5 > 10[/tex]

Split

[tex]-10 > x - 5\ or\ x - 5 > 10[/tex]

Solve for x

[tex]5 -10 > x \ or\ x > 10 + 5[/tex]

[tex]-5> x \ or\ x > 15[/tex]

Rewrite as:

[tex]x< -5 \ or\ x > 15[/tex]

x cannot be negative.

So:

[tex]x > 15[/tex]

x cannot exceed 20.

So:

[tex]15 < x \le 20[/tex]

Answer:

35-P=25

Step-by-step explanation:

P= Number of players he cut

Answer:

C.18

Step-by-step explanation:

In the chart it shows that 18 boys like to read science fiction. Hope this helps :)

Answer: 2y124√y12

How to: Simplify the radical by breaking the radicand up into a product of known factors, assuming positive real numbers.

Have a great day and stay safe !

9514 1404 393

Answer:

  [tex]2\cdot y^{\frac{5}{8}}[/tex]

Step-by-step explanation:

The applicable rules of exponents are ...

  [tex](a^b)^c=a^{bc}\\\\(ab)^c=a^c\cdot b^c\\\\\sqrt[n]{x^m}=x^{\frac{m}{n}}[/tex]

__

So, the given expression can be rewritten to ...

  [tex](4\sqrt[4]{y^5})^{\frac{1}{2}}=(4^{\frac{1}{2}})(y^{\frac{5}{4}})^{\frac{1}{2}}= 2\cdot y^{\frac{5}{4}\cdot\frac{1}{2}}=\boxed{2\cdot y^{\frac{5}{8}}}[/tex]

_____

k = 2; n = 5/8