Mr. Garner purchased a party hall and wants to repaint it as part of the renovations. He needs to calculate the lateral surface area of the party hall so that he will know how much paint to buy. The party hall is in the shape of a rectangular prism with the dimensions shown below.




Including the doors, what is the lateral surface area of the party hall in square feet?



1,904 ft2


1,860 ft2


3,764 ft2


14,280 ft2

Answer:

I would say it's d (sorry if im wrong)

Answer:

BOGO ko sa math

Step-by-step explanation:

hahaha sorryyyyy

Answer:

The greatest common factor is 4

Step-by-step explanation:

1)     12x3+4x2-8x

2)    (12x3)+(4x2)-8x

3)     36+(4x2)-8x

4)     36+8-8x

5)     44-8x

6)     4(11-2x)

Answer:log a - log b = log (a/b) than use this formula will get

log x^2 -log x = log (x^2 /x) = log x

so answer is log x

Step-by-step explanation:

Answer:

Its an Obtuse angles

Step-by-step explanation:

x+79=2x-37

(x+79)+(-79)=(2x-37)+(-79)

x+79-79=(2x-37)-79

x=2x-37-79

x=116

An obtuse angle has a measurement greater than 90 degrees but less than 180 degrees.

Answer:

946589196.155

Step-by-step explanation:

Hope that helps

Answer:

Vector (ordered pair - rectangular form)

[tex]\vec F = (27.189,12.679)\,[lbf][/tex]

Vector (ordered pair - polar form)

[tex]\vec F = (30\,lbf, 25^{\circ})[/tex]

Sum of vectorial components (linear combination)

[tex]\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N][/tex]

Step-by-step explanation:

From statement we know that force exerted on the wagon has a magnitude of 30 pounds-force and an angle of 25° above the horizontal, which corresponds to the +x semiaxis, whereas the vertical is represented by the +y semiaxis.

The force ([tex]\vec F[/tex]), in pounds-force, can be modelled in two forms:

Vector (ordered pair - rectangular form)

[tex]\vec F = \left(\|\vec F\|\cdot \cos \theta, \|\vec F\|\cdot \sin \theta\right)[/tex] (1)

Vector (ordered pair - polar form)

[tex]\vec F = \left(\|\vec F\|, \theta\right)[/tex]

Sum of vectorial components (linear combination)

[tex]\vec {F} = \left(\|\vec F\|\cdot \cos \theta\right)\cdot \hat{i} + \left(\|\vec F\|\cdot \sin \theta \right)\cdot \hat{j}[/tex] (2)

Where:

[tex]\|\vec F\|[/tex] - Norm of the vector force, in newtons.

[tex]\theta[/tex] - Direction of the vector force with regard to the horizontal, in sexagesimal degrees.

[tex]\hat{i}[/tex], [tex]\hat{j}[/tex] - Orthogonal axes, no unit.

If we know that [tex]\|\vec F\| = 30\,lbf[/tex] and [tex]\theta = 25^{\circ}[/tex], then the force exerted on the wagon is:

Vector (ordered pair - rectangular form)

[tex]\vec F= \left(30\cdot \cos 25^{\circ}, 30\cdot \sin 25^{\circ}\right)\,[lbf][/tex]

[tex]\vec F = (27.189,12.679)\,[lbf][/tex]

Vector (ordered pair - polar form)

[tex]\vec F = (30\,lbf, 25^{\circ})[/tex]

Sum of vectorial components (linear combination)

[tex]\vec F = (30\cdot \cos 25^{\circ})\cdot \hat{i} + (30\cdot \sin 25^{\circ})\cdot \hat{j}\,[N][/tex]

[tex]\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N][/tex]

Answer:

hope this will help you more

good luck...

Answer:

[tex] \frac{ {x}^{ \frac{2}{3} } {y}^{ \frac{1}{3} } }{2} [/tex]

Answer C is correct

Step-by-step explanation:

[tex] \sqrt[3]{ \frac{ {x}^{2} }{8 {y}^{ - 1} } } \\ \frac{ {x}^{2 \times \frac{1}{3} } \times {y}^{1 \times \frac{1}{3} } }{ \sqrt[3]{8} } \\ = \frac{ {x}^{ \frac{2}{3} } {y}^{ \frac{1}{3} } }{2} [/tex]

Answer:

x-intercept

Step-by-step explanation:

Answer:

39

Step-by-step explanation:

Answer:

Solution given:

cotangent x=cot x=-1

now

x=cot -¹(-1)

x=180-45°

x=135°

So

ans is d. 135 degrees.

as cot is negative in 2nd quadrant.

0.59 h + 0.98 b = 1041.37 - 79.37

h + b = 1300

Answer:

5M

Step-by-step explanation:

Answer:

y=−25x+300

Step-by-step explanation:

have a good day/night

may i please have a branlliest

Answer:

[tex]x = \frac{50 + 92}{2} = 71[/tex]

Answer: 95%

Step-by-step explanation:

Answer:

x = 0.6

Step-by-step explanation:

We use tangent because the given numbers are opposite and adjacent from x

So, tangent (x) = opposite/adjacent

tan(x) = 8.78/12

[tex]tan^{-1}(\frac{8.78}{12}) = x[/tex]

x = 0.631664

Round to nearest tenth:

x ~ 0.6

Answer:

- 10 degrees Fahrenheit at 9:00 PM

Step-by-step explanation:

35 - 45 = -10

Answer:

the data of the cubic

as it the distance between the two integers closed under addition

Answer:

120 and 144

120÷24=5

144÷24=6

Answer:

I belive the answer for the first box is 9.67

I belive the answer for the second box is 71.

I hope I helped

Answer:

x=-6, y=1

Step-by-step explanation:

Let's solve your system by substitution.

y=x+7;−2x−11=y

Step: Solve y=x+7 for y:

y=x+7

Step: Substitute x+7 for y in −2x−11=y:

−2x−11=y

−2x−11=x+7

−2x−11+−x=x+7+−x(Add -x to both sides)

−3x−11=7

−3x−11+11=7+11(Add 11 to both sides)

−3x=18

−3x/ −3 = 18/ −3  (Divide both sides by -3)

x=−6

Step: Substitute−6 for x in y=x+7:

y=x+7

y=−6+7

y=1  (Simplify both sides of the equation)

Answer:

x=−6 and y=1

Step-by-step explanation:

question 1

[tex]6 {x}^{4} - 36 {x}^{3} \\ 6 {x}^{3} (x - 6)[/tex]

question 2

[tex]64 {x}^{2} + 48x + 9 \\ {(8x + 3)}^{2} [/tex]

Answer:

106°

Step-by-step explanation:

An isosceles triangle has 2 sides of the same length. All triangles add up to 180°

37 + 37 + x = 180

74 + x = 180

x = 106

Answer:

37.69911184

Step-by-step explanation:

because circumference is equal to pi multiplied by diameter, you will not get the circumference with the radius times pi. in order to get the diameter, you multiply the radius by 2, because the diameter is the length across the circle. So the diameter of this circle is equal to 12. so simply multiply that number by pi (3.14) and there is your answer. Hope i helped.

Answer:

A{-4,-2,1,4} is the domain of function.

Answer:

A) 28 7/12, or 343/12, or 28.583

B) 57.75

C) 86.3 or 86 1/3

Step-by-step explanation: