(MP Reason An internet company spends half their yearly profits on advertising for the next year. Of the remaining half, they spend 1/5 on new computers. What fraction of the total profits does the company spend on new computers? Use the number line to show how you can to make his bowl? Write an equati Harcourt Pub 4 find the fraction. 1 o Module 8. Lesson 3

(MP Reason An Internet Company Spends Half Their Yearly Profits On Advertising For The Next Year. Of

Answers

Answer 1

Let the total profit be represented by 1

The internet company spends half their yearly profits on advertising for the next year. The amount of the profit spent on advertising is 1/2 = 0.5

The amount left is 1 - 0.5 = 0.5

Of the remaining half, they spend 1/5 on new computers. It means that the amount spent on new computers is

1/5 * 0.5 = 0.1 = 1/10

Therefore, the fraction of the total profits does the company spend on new computers is

0.1/1 = 0.1 = 1/10

The number line is shown below

(MP Reason An Internet Company Spends Half Their Yearly Profits On Advertising For The Next Year. Of

Related Questions

The area of a soccer field is ( 24x^2 + 100x + 100) m^2. The width of the field is (4x + 10)m. What is the length?Please help, need right away.Be sure to show work. NEED HELP BEEN ON THIS PROBLEM FOR 2 DAYS

Answers

hello

to solve this question, we have to understand that a soccer field is rectangular in shape and we can find this length from factoring the area

formula of area of a rectangle

[tex]\begin{gathered} A=L\times W \\ A=\text{area} \\ L=\text{length} \\ W=\text{width} \end{gathered}[/tex][tex]\begin{gathered} A=24x^2+100x+100 \\ W=4x+10 \\ L=\text{ ?} \end{gathered}[/tex]

we can proceed to solve this by dividing the polynomial or simply checking it from the options

from the options given,

we have option A

3x + 10

let's multiply both the L and W to see if it gives us the answer

[tex](4x+10)\times(3x+10)=12x^2+70x+100_{}[/tex]

option A is incorrect

let's test for option B

L= 6x + 10

[tex]\begin{gathered} A=L\times W \\ (6x+10)\times(4x+10)=24x^2+100x+100_{} \end{gathered}[/tex]

option B is correct

let's test for option C

L= 6x + 1

[tex]\begin{gathered} A=L\times W \\ (6x+1)\times(4x+10)=24x^2+70x+10 \end{gathered}[/tex]

option C is also incorrect and so it'll be for option D

from the calculations above, only option B corresponds with the value of length for the soccer field

The sum of two numbers is 60. The greater number is 6 more than the smaller number which equation can be used to solve for the smaller number

Answers

x ----> is the smaller number

x+6 ----> is the greater number

the equation is

[tex]x+(x+6)=60[/tex]

fing the length of the missing side

Answers

The area is given as

[tex]x^2-6x+9[/tex]

We can either divide the area by the side given and get the other side

OR

We can simply factorize the area and hence determine the two factors that were multiplied together. Note that one factor has already been given (that is x-3).

To factorize the polynomial;

[tex]\begin{gathered} x^2-6x+9 \\ =(x-3)(x-3) \end{gathered}[/tex]

This means the other side is also (x - 3)

392196 divided by 87(using king division)

Answers

Answer: The result of 392,196 divided by 87 is 4,508

The function f(x)=2,500(1.012)^x represents the amount, in dollars, in a savings account after x years. Which statement is true? A. The account earns 0.12% interest per year. B. The account earns 0.012% interest per year. C. The initial amount in the account was $2.500. D. The amount in the account increases by $2,500 each year,

Answers

Answer:

C. The initial amount in the account was $2,500.

Explanation:

The function that represents the amount, in dollars, in a savings account after x years is given as:

[tex]f\mleft(x\mright)=2,500\mleft(1.012\mright)^x[/tex]

When x=0 (Initially)

[tex]\begin{gathered} f\mleft(0\mright)=2,500\mleft(1.012\mright)^0 \\ =2,500\times1 \\ =\$2,500 \end{gathered}[/tex]

Therefore, the initial amount in the account was $2,500.

Which of the following is irrational?A.24.3B./2D. /25C.7

Answers

a) 24.3 is a rational number

[tex]\frac{243}{10}[/tex]

b)

[tex]\begin{gathered} \sqrt{2}=1.41421 \\ \sqrt{2}\text{ is irrational} \end{gathered}[/tex]

c) 7 is a rational number

d)

[tex]\begin{gathered} \sqrt{25}=5 \\ \sqrt[]{25}\text{ is rational} \end{gathered}[/tex]

Answer: Letter B

A.) 0, 1, 2, 3, 4B.) 0, 2, 4, 7, 8C.) 1, 2, 3, 4, 5D.) 1, 3, 5, 7, 9

Answers

Answer

1, 2, 3, 4, 5

Explanation

Given the following data

a(0) = 0

a(i + 1) = a(i) + 1

Find a(0) to a(5)

Step 1: find a(i) when i = 0

a(0 + 1) = a(0) + 1

Where a(0) = 0

a(1) = 0 + 1

a(1) = 1

Find a(2) when i = 1

a(i + 1) = a(1) + 1

a(1) = 1

a(1 + 1) = 1 + 1

a(2) = 2

find a(3) when i = 2

a(2 + 1) = a(2) + 1

a(3) = 2 + 1

a(3) = 3

Find a(4) when i = 3

a(3 + 1) = a(3) + 1

a(4) = 3 + 1

a(4) = 4

Find a(5) when i= 4

a(4+1) = a(4) + 1

a(5) = 4 + 1

a(5) = 5

Therefore,

a(1) = 1

a(2) = 2

a(3) = 4

a(4) = 4

a(5) = 5

The answer is 1, 2, 3, 4, 5

please help me with this pleasethe direction is write the equations in slope interception form

Answers

In this case, we'll have to carry out several steps to find the solution.

Step 01:

7.

Data

point 1 ( -4 , -2) x1 = -4 y1 = -2

point 2 ( 3 , 3 ) x2 = 3 y2 = 3

Step 02:

Slope formula

m = (y2 - y1) / (x2 - x1)

[tex]m\text{ = }\frac{(3-(-2))}{(3-(-4))}=\text{ }\frac{3+2}{3+4}=\frac{5}{7}[/tex]

Slope-intercept form of the line

y = mx + b

intercept (0 , 1 )

b = 1

m = 5 / 7

y = 5/7 x + 1

The answer is:

y = 5/7 x + 1

how many weeks does it take to empty the lake?

Answers

The rate of emptying the lake is -1/8.

The rate of filling the lake is 1/15

Let t be the time in weeks to empty the lake,

Now, add the given rate to get the total rate of emptying of -1/t.

[tex]\begin{gathered} \frac{-1}{8}+\frac{1}{15}=-\frac{1}{t} \\ \frac{-15+8}{120}=-\frac{1}{t} \\ -7\times t=-120 \\ t=\frac{120}{7} \end{gathered}[/tex]

Thus,

[tex]t=17\frac{1}{7}[/tex]

Therefore, it will take 17 weeks and 1 day to empty the lake.

Length of carrier A is about how many football fields ?

Answers

Given:

The total length of carriers A and B, T=4198 feet.

The difference in lengths of the carriers is, D=10 feet.

The length of football field, L=100 yards.

Let a be the length of carrier A and b be the length of carrier B. It is given that carrier A is longer than carrier B.

Hence, the expression for the difference in lengths of the carriers can be written as,

[tex]\begin{gathered} D=a-b \\ 10\text{ =a-b ----(1)} \end{gathered}[/tex]

The total length of carriers A and B can be written as,

[tex]\begin{gathered} T=a+b \\ 4198=a+b\text{ ----(2)} \end{gathered}[/tex]

Add equations (1) and (2) to find the value of a.

[tex]\begin{gathered} 2a=10+4198 \\ 2a=4208 \\ a=\frac{4208}{2} \\ a=2104\text{ f}eet \end{gathered}[/tex]

We know, 1 yard=3 feet.

So, 1 feet=(1/3) yard

The length of carrier A in yards is,

[tex]a=2104\text{ f}eet\times\frac{\frac{1}{3}\text{yard}}{\text{ 1 fe}et}=\frac{2104}{3}\text{yards}[/tex]

We know, the length of a football field is l=100 yards

Now, the ratio between a and l can be found as

[tex]\frac{a}{l}=\frac{\frac{2104}{3}\text{ yards}}{100\text{ yards}}\cong7.0[/tex]

Hence, we can write

[tex]a=7.0\times l[/tex]

Since l is the length of a football field, the length of carrier A is about 7.0 football fields.

How much interest in dollars is earned in 5 years on $8,200 deposited in an account paying 6% interest compounded semiannually round to the nearest cent

Answers

Using compound interest formula:

[tex]A=P(1+\frac{r}{n})^{nt}[/tex]

Where:

A = Amount

P = Principal = 8200

r = Interest rate = 6% = 0.06

n = Number of times interest is compounded per year = 2

t = time = 5

so:

[tex]\begin{gathered} A=8200(1+\frac{0.06}{2})^{2\cdot5} \\ A=11020.11 \end{gathered}[/tex]

Therefore, the interest is the amount minus the amount invested:

[tex]\begin{gathered} I=A-P \\ I=11020.11-8200 \\ I=2820.11 \end{gathered}[/tex]

Answer:

$2820.11

Find the measure of each labeled angle as well as the values of x, y, and z.

Answers

Notice that the angle labelled as 3y and the angle with a measure of 72° are supplementary angles. Then:

[tex]3y+72=180[/tex]

Substract 72 from both sides of the equation:

[tex]\begin{gathered} 3y+72-72=180-72 \\ \Rightarrow3y=108 \end{gathered}[/tex]

The angle labelled as x and the angle labelled as 3y are corresponding angles. Then, they have the same measure:

[tex]x=3y[/tex]

Since 3y=108, then:

[tex]x=108[/tex]

On the equation 3y=108, divide both sides by 3 to find the value of y:

[tex]\begin{gathered} \frac{3y}{3}=\frac{108}{3} \\ \Rightarrow y=36 \end{gathered}[/tex]

Finally, notice that the angle labelled as 3z+18 and the angle labelled as x are corresponding angles. Then, they have the same measure:

[tex]3z+18=x[/tex]

Substitute x=108 and isolate z to find its value:

[tex]\begin{gathered} \Rightarrow3z+18=108 \\ \Rightarrow3z=108-18 \\ \Rightarrow3z=90 \\ \Rightarrow z=\frac{90}{3} \\ \Rightarrow z=30 \end{gathered}[/tex]

Therefore, the measure of the angles labelled as 3z+18, x and 3y is 108°. The values of x, y and z are:

[tex]\begin{gathered} x=108 \\ y=36 \\ z=30 \end{gathered}[/tex]

Use the number line diagram below to answer the following questions.1.What is the length of each segment on the number line?

Answers

Given from the number line that the total number of segments between 0 and 1 is 12 segments.

1) Therefore, the length of each segment on the number line is

[tex]\frac{1-0}{12}=\frac{1}{12}[/tex]

Hence, the answer is

[tex]\frac{1}{12}[/tex]

2) There are 8 segments between 0 and K.

Therefore, point K represents

[tex]\frac{1}{12}\times8=\frac{8}{12}=\frac{2}{3}[/tex]

Hence, the answer is

[tex]\frac{2}{3}[/tex]

3) The opposite of K is

[tex]-\frac{2}{3}\text{ since it falls on the negative side of the number line.}[/tex]

Hence, the answer is

[tex]-\frac{2}{3}[/tex]

the table shows the probability distrubution of a random variable Z.Z- -17, -16,-15,-14,-13 P(Z)- 0.02 , 0.73, 0.02, 0.08, 0.15what is the mean of the probability distrubution

Answers

Mean of a probability distrubution​

In order to find the mean, we have to multiply each value with its probability and then add al the results:

Step 1- multiplying each value by its probability

Step 2 - adding all the results

Now, we add all the results we found on the previous step:

Mean = -0.34 - 11.68 - 0.30 - 1.12 - 1.95

Mean = -15.39

Answer: mean = -15.39

Albert has 16 oz of cheddar cheese and 8 oz of mozzarella cheese. He used 5 1/2 oz of the cheddar and 3 1/3 oz of the mozzarella cheese in a recipe. What is the total amount of cheese that Albert has left?

Answers

PROBLEM

Total

16 cheddar cheese

8 mozzarella cheese

Solution

He uses

[tex]\begin{gathered} 5\frac{1}{2}\text{ of cheddar out of 16} \\ 3\frac{1}{3}\text{ of mozzarella out of 8} \end{gathered}[/tex][tex]\begin{gathered} \\ \text{Cheddar left = 16 - 5}\frac{1}{2}\text{ = 10}\frac{1}{2} \end{gathered}[/tex][tex]\text{Mozzarella left = 8 - 3}\frac{1}{3}\text{ = 4}\frac{2}{3}[/tex][tex]\begin{gathered} \\ \text{Total ch}eese\text{ left } \\ = \end{gathered}[/tex]

[tex]\begin{gathered} \\ =\text{ 10}\frac{1}{2}\text{ - 4}\frac{2}{3} \end{gathered}[/tex][tex]=\text{ 5}\frac{5}{6}[/tex]

Find the volume of this cylinder. Use 3 for A.5 ftV = 7r2h=12 ftV V [?]ft

Answers

We're going to find the volume of the cylinder using the following equation:

[tex]V=\pi\cdot r^2\cdot h[/tex]

Since the radius measures 5 ft, the height measures 12 ft and the problem tells us that we should take pi as 3, we could replace:

[tex]\begin{gathered} V\approx3\cdot(5ft)^2\cdot12ft \\ V\approx3\cdot25ft^2\cdot12ft \\ V\approx900ft^3 \end{gathered}[/tex]

Therefore, the volume is approximately 900ft3.

Larry Mitchell invested part of his $22,000 advance at 2% annual simple interest and the rest at 6% annual simple interest if his total yearly interest from both accounts was $760 find the amount invested at each rate The amount invested at 2%The amount invested at 6%( please don’t need an detailed explanation just the answer)

Answers

Larry Mitchell invested part of his $22,000 advance at 2% annual simple interest and the rest at 6% annual simple interest if his total yearly interest from both accounts was $760 find the amount invested at each rate

The amount invested at 2%

The amount invested at 6%

Let

x -----> amount invested at 2%

(22,000-x) -----> amount invested at 6%

we have that

x(0.02)+(22,000-x)(0.06)=760

solve for x

0.02x+1,320-0.06x=760

0.06x-0.02x=1,320-760

0.04x=560

x=14,000

(22,000-14,000)=8,000

therefore

amount invested at 2% -----> $14,000amount invested at 6% -----> $8,000

108010 -8 -62IC-Find the slope of the line.Slope = m =Enter your answer as an integer or as a reduced fraction in the form A/B.Question Help: Video Message

Answers

The slope formula is givenb by:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

To get the slope from the graph, we will pick out two points lying on the line:

Point 1: (x, y) = (-6, 10)

Point 2: (x, y) = (0, -8)

We will then proceed to use these points to calculate the slope, we have:

[tex]\begin{gathered} m=\frac{-8-10}{0--6}=-\frac{18}{6} \\ m=-3 \end{gathered}[/tex]

The slope (m) = -3

how do I solve a liner model ?

Answers

The values that are represented by the dots are close to the horizontal line, so they are a non-random pattern, because they follow the horizontal line without going to far from it

Since these points are all around the horizontal line, they also represent a linear model

So the answer for hte first box is "non-random" and the answer for the second box is "linear"

A litter of kittens consists of one gray female, two gray males, two black females and one black male. You randomly pick one kitten, what is the probability it is black?

Answers

Total number of kittens = 6

Gray kittens= 1 female+2 males = 3

Black kittens= 2 female+ 1 male =3

Probability of picking one black kitten = black kittens/ total kittens = 3/6 =1/2

12. Write a paragraph proof.Given: AB = CD, BC = DAProve: AABC = ACDA

Answers

Answer:

Triangles ABC and CDA share the side AC, therefore they have three congruent sides. Since AB is congruent to CD and BC is congruent to DA then by the SSS criteria we get that triangles ABC and CDA are congruent.

I need help with getting to the answer to number 6

Answers

Explanation

We have the following pair of functions:

[tex]\begin{gathered} f(x)=x^3+6x \\ g(x)=\sqrt{8x} \end{gathered}[/tex]

And we need to find (fog)(2). In order to do this we can start by calculating the composite function (fog)(x)=f(g(x)). Its expression is given by taking the equation of f(x) and replacing x with the expression of g(x). Then we get:

[tex]\begin{gathered} (f\circ g)(x)=f(g(x))=g(x)^3+6g(x)=(\sqrt{8x})^3+6\sqrt{8x} \\ (f\circ g)(x)=(\sqrt{8x})^3+6\sqrt{8x} \end{gathered}[/tex]

We need to find (fog)(2) so we just need to take x=2 in the equation above:

[tex]\begin{gathered} (f\circ g)(2)=(\sqrt{8\cdot2})^3+6\sqrt{8\cdot2} \\ (f\circ g)(2)=(\sqrt{16})^3+6\cdot\sqrt{16} \\ (f\circ g)(2)=4^3+6\cdot4 \\ (f\circ g)(2)=64+24 \\ (f\circ g)(2)=88 \end{gathered}[/tex]Answer

Then the answer is 88.

Felipe is a software salesman. His base salary is $2100, and he makes an additional $70 for every copy of math is fun he sells. Let P represent his total pay in dollars, and let N represent the number of copies of math is fun he sells. Write an equation relating P to N then use this equation to find his total pay if he sells 27 copies of math is fun.

Answers

Based on the given information, we can determine the constant and the variable payment.

• He gets $2100 as based salary (never changes, constant).

,

• The additional $70 depends on ,N ,(variable).

This information can help us build the equation:

[tex]P=70N+2100[/tex]

Therefore, if he sells 27 copies, then the total payment is:

[tex]P=70\cdot27+2100[/tex][tex]P=1890+2100[/tex][tex]P=3990[/tex]

Answer:

[tex]P=70N+2100[/tex]

P( 27 ) = $3990

Pablo deposited $600 in an account earning 2% interest compounded annually.To the nearest cent, how much interest will he earn in 3 years?Use the formula B=p(1+r)t, where B is the balance (final amount), p is the principal (starting amount), r is the interest rate expressed as a decimal, and t is the time in years.

Answers

The given information is:

- The initial amount is $600

- The interest rate is 2% (compounded annually)

The given formula is:

[tex]B=p(1+r)^t[/tex]

Where B is the balance (final amount), p is the principal (starting amount), r is the interest rate as a decimal, and t is the time in years.

By replacing the known values we obtain the balance after 3 years:

[tex]\begin{gathered} B=600*(1+0.02)^3 \\ B=600(1.02)^3 \\ B=600*1.06 \\ B=636.72 \end{gathered}[/tex]

The answer is $636.72

Which is the measure of an interior angle of a regular decagon?30°36°144°150°

Answers

SOLUTION:

We are to find the measure of an interior angle of a regular decagon.

A decagon is a plane figure with ten straight sides and angles.

To find the sum of interior angles in a decagon;

(n - 2) x 180 (where n = 10)

(10 - 2) x 180

= 8 x 180

= 1440 degrees

The measure of an interior angle of a regular decagon is;

1440 / 10

144 degrees

Write an equation for the line parallel to the given line that contains B. B(3, 8) ; y = - 4x + 7

Answers

You have to write an equation parallel to the line: y=-4x+7 that crosses the point (3,8)

One characteristic that two parallel lines share is that they have the same slope.

The slope for the known line corresponds to the coefficient multiplying the x-term and is m=-4

The line you have to find must have the same slope.

Using the point-slope form you can determine said line. The general structure is:

[tex]y-y_1=m(x-x_1)[/tex]

Where

m is the slope

x₁, y₁ are the coordinates of a point crossed by the line.

Using (3, 8) and m=-4

[tex]y-8=-4(x-3)[/tex]

Now you have to solve it and write it in slope-intercept form. First step is to solve the term in parentheses by applying the distributive propperties of multiplication:

[tex]\begin{gathered} y-8=-4x-3\cdot(-4) \\ y-8=-4x+12 \end{gathered}[/tex]

Next pass "-8" to the other side of the equal sign:

[tex]\begin{gathered} y-8+8=-4x+12+8 \\ y=-4x+20 \end{gathered}[/tex]

The equation for the line parallel to y=-4+7 is y=-4x+20

Precalc and i need help withb. Sec(18pie)c. Sin(7pie/6) tan(8pie/3)d. Tan(pie/12)

Answers

In b we need to find:

[tex]\sec 18\pi[/tex]

It's important to recal that the secant is equal to:

[tex]\sec 18\pi=\frac{1}{\cos18\pi}[/tex]

Another important property that will be useful is:

[tex]\cos x=\cos (x+2\pi m)[/tex]

Where m is any integer. Let's see if we can write 18*pi using this. We can take x=0 so we have:

[tex]\begin{gathered} 18\pi=x+2\pi m=2\pi m \\ 18\pi=2\pi m \end{gathered}[/tex]

If we divide both sides by 2*pi:

[tex]\begin{gathered} \frac{18\pi}{2\pi}=\frac{2\pi m}{2\pi} \\ 9=m \end{gathered}[/tex]

Since m is an integer then we can assure that:

[tex]\cos 18\pi=\cos (0+2\pi\cdot9)=\cos 0=1[/tex]

Then the secant is given by:

[tex]\sec 18\pi=\frac{1}{\cos18\pi}=\frac{1}{\cos 0}=1[/tex]

So the answer to b is 1.

In c we need to find:

[tex]\sin (\frac{7\pi}{6})\tan (\frac{8\pi}{3})[/tex]

Here we can use the following properties in order to write those angles as angles of the first quadrant:

[tex]\begin{gathered} \sin (x)=-\sin (x-\pi) \\ \tan (x)=\tan (x-m\pi)\text{ with }m\text{ being an integer} \end{gathered}[/tex]

So we have:

[tex]\begin{gathered} \sin (\frac{7\pi}{6})=-\sin (\frac{7\pi}{6}-\pi)=-\sin (\frac{\pi}{6}) \\ \tan (\frac{8\pi}{3})=\tan (\frac{8\pi}{3}-3\pi)=\tan (-\frac{1}{3}\pi) \end{gathered}[/tex]

If we convert these two angles from radians to degrees by multiplying 360° and dividing by 2*pi we have:

[tex]\begin{gathered} \frac{\pi}{6}\cdot\frac{360^{\circ}}{2\pi}=30^{\circ} \\ -\frac{1}{3}\pi\cdot\frac{360^{\circ}}{2\pi}=-60^{\circ} \end{gathered}[/tex]

And remeber that:

[tex]\tan x=-\tan (-x)[/tex]

So we get:

[tex]\begin{gathered} \sin (\frac{7\pi}{6})=-\sin (\frac{\pi}{6})=-\sin (30^{\circ}) \\ \tan (\frac{8\pi}{3})=\tan (-\frac{\pi}{3})=-\tan (\frac{\pi}{3})=-\tan (60^{\circ}) \end{gathered}[/tex]

Then we can use a table of values:

Then:

[tex]\sin (\frac{7\pi}{6})\tan (\frac{8\pi}{3})=\sin (30^{\circ})\cdot\tan (60^{\circ})=\frac{1}{2}\cdot\sqrt[]{3}=\frac{\sqrt[]{3}}{2}[/tex]

So the answer to c is (√3)/2.

In d we need to find:

[tex]\tan (\frac{\pi}{12})[/tex]

In order to do this using the table we can use the following:

[tex]\begin{gathered} \tan x=\frac{\sin x}{\cos x} \\ \sin 2x=2\sin x\cos x \\ \cos 2x=\cos ^2x-\sin ^2x \\ \cos ^2x+\sin ^2x=1 \end{gathered}[/tex]

So from the first one we have:

[tex]\tan (\frac{\pi}{12})=\frac{\sin (\frac{\pi}{12})}{\cos (\frac{\pi}{12})}[/tex]

We convert pi/12 into degrees:

[tex]\frac{\pi}{12}\cdot\frac{360^{\circ}}{2\pi}=15^{\circ}[/tex]

So we need to find the sine and cosine of 15°. We use the second equation:

[tex]\begin{gathered} \sin 30^{\circ}=\frac{1}{2}=\sin (2\cdot15^{\circ})=2\sin 15^{\circ}\cos 15^{\circ} \\ \sin 15^{\circ}\cos 15^{\circ}=\frac{1}{4} \end{gathered}[/tex]

Then we use the third:

[tex]\begin{gathered} \cos (30^{\circ})=\frac{\sqrt[]{3}}{2}=\cos (2\cdot15^{\circ})=\cos ^215^{\circ}-\sin ^215^{\circ} \\ \frac{\sqrt[]{3}}{2}=\cos ^215^{\circ}-\sin ^215^{\circ} \end{gathered}[/tex]

And from the fourth equation we get:

[tex]\begin{gathered} \cos ^215^{\circ}+\sin ^215^{\circ}=1 \\ \sin ^215^{\circ}=1-\cos ^215^{\circ} \end{gathered}[/tex]

We can use this in the previous equation:

[tex]\begin{gathered} \frac{\sqrt[]{3}}{2}=\cos ^215^{\circ}-\sin ^215^{\circ}=\cos ^215^{\circ}-(1-\cos ^215^{\circ}) \\ \frac{\sqrt[]{3}}{2}=2\cos ^215^{\circ}-1 \\ \cos 15^{\circ}=\sqrt{\frac{1+\frac{\sqrt[]{3}}{2}}{2}} \\ \cos 15^{\circ}=\sqrt{\frac{1}{2}+\frac{\sqrt[]{3}}{4}} \end{gathered}[/tex]

So we found the cosine. For the sine we use the expression with the sine and cosine multiplying:

[tex]\begin{gathered} \sin 15^{\circ}\cos 15^{\circ}=\frac{1}{4} \\ \sin 15^{\circ}\cdot\sqrt[]{\frac{1}{2}+\frac{\sqrt[]{3}}{4}}=\frac{1}{4} \\ \sin 15^{\circ}=\frac{1}{4\cdot\sqrt[]{\frac{1}{2}+\frac{\sqrt[]{3}}{4}}} \end{gathered}[/tex]

Then the tangent is:

[tex]\tan (15^{\circ})=\frac{\sin(15^{\circ})}{\cos(15^{\circ})}=\frac{1}{4\cdot\sqrt[]{\frac{1}{2}+\frac{\sqrt[]{3}}{4}}}\cdot\frac{1}{\sqrt[]{\frac{1}{2}+\frac{\sqrt[]{3}}{4}}}=\frac{1}{4}\cdot\frac{1}{\frac{1}{2}+\frac{\sqrt[]{3}}{4}}[/tex]

[tex]\tan (15^{\circ})=\frac{1}{4}\cdot\frac{1}{\frac{1}{2}+\frac{\sqrt[]{3}}{4}}=\frac{1}{2+\sqrt[]{3}}[/tex]

Then the answer to d is:

[tex]\frac{1}{2+\sqrt[]{3}}[/tex]

Pamela is 15 years younger than Jiri. The sum of their ages is 29 . What is Jiri's age?

Answers

To determine the age of jiri:

Let P represent Pamela age

Let J represent Jiri age

p + j = 29 (their ages added together is 29)

p = j - 15 (Pam is 15 years younger (less) than Jiri)

We have a value for Pam, so plug it in:

j -15 + j = 29

2j - 15 = 29

Add 15 to both sides:

2j = 44

Divide by 2:

j = 22

Now find Pamela's age:

p = 22 - 15

p = 7

check:

7 + 22 = 29

29 = 29

Therefore the age of Jiri is 22 years

Which sequence describes Ahmed's expected hourly wages, in dollars, starting with his current wage?

Answers

Since Ahmed will start with $7.50 per hour

Then the sequence must start with 7.50

Then the answer should be A or B or C

Since his hourly rate will increase by $0.25 per hour

Then the number in the sequence should be increased

Then the answer is B or C because A is decreasing

We have to add 0.25 to the first rate to get the second rate

[tex]\begin{gathered} 7.50+0.25=7.75 \\ 7.75+0.25=8.00 \\ 8.00+0.25=8.25 \\ 8.25+0.25=8.50 \end{gathered}[/tex]

Then the correct answer is

$7.50, $7.75, $8.00, $8.25, $8.50

The answer is B

How can you represent Pattered from every day life by using tables,expressions and graphs

Answers

For example, we can look at the variations of temperature by the time of the day.

We can write it in a two column table, where we can write the hour in one column and the temperature in the other column.

This will show us a relationship between them that is oscillating.

We can graph this and have something like:

Then, we can adjust a function to that, like a trigonometrical function that can model this relation between temperature and hour of the day. There you wil have an expression for this pattern.

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