Given that the amount of rice Anika bought is
more than Mayra bought and Mayra bought x grams while Anika bought y grams then considering the options
#1. y=4/3x - this is true
#2.Y=2/3x - this is not true as this means that the value of y is less than that of x
3#.Y=1/3x - this is not true as this means that the value of y is less than that of x #4.y=x+1/3x - this is same as #1
#5.Y=X-1/3x - this is same as #2
Hence th
4.The value of x isis order these expressions from least to greatest:χ1- xx-1-1 = x
To answer this question we have to evaluate each expression at the given value of x.
Recall that to evaluate an expression we substitute the variable by the given value.
Evaluating each expression at
[tex]x=-\frac{1}{4}[/tex]we get:
[tex]\begin{gathered} x=-\frac{1}{4}, \\ 1-x=1-(-\frac{1}{4})=1+\frac{1}{4}, \\ x-1=-\frac{1}{4}-1=-(1+\frac{1}{4}), \\ -\frac{1}{-\frac{1}{4}}=\frac{1}{\frac{1}{4}}=4. \end{gathered}[/tex]Therefore, the numbers ordered from least to greatest are:
[tex]x-1,\text{ x, 1-x, -1/x.}[/tex]Answer:
[tex]x-1,\text{ x, 1-x, -1/x.}[/tex]write the following comparison as a ratio in simplest form using a fraction, a colon and the word to. _ 198 cents to 234 cents is?
Given data:
The expression for the kratio of 198 cents to 234 cents is,
[tex]\begin{gathered} \frac{198}{234}=\frac{18\times11}{18\times13} \\ =\frac{11}{13} \\ =11\colon13 \end{gathered}[/tex]Thus, the correct option is (d).
Match each measurement on the left with an equal measurement on the right. Some answer options on the right will not be used.31/2 yards66 inches2 miles21/2 miles51/2 feet10,560 feet101/2 feet91/2 feet12,300 feet13,200 feet
Solution
Recall
1 yard is 3feet
1 foot is 12inches
1 mile is 5,280 feet
[tex]3\frac{1}{2}\text{yards =10}\frac{1}{2}\text{ ft}[/tex][tex]66\text{inches =5}\frac{1}{2}ft[/tex][tex]\begin{gathered} 1\text{ miles = 5280 ft} \\ 2\text{miles = 10,560ft} \end{gathered}[/tex][tex]\begin{gathered} 1\text{mile = 5280 ft} \\ 2\frac{1}{2}\text{miles =}13,200ft \end{gathered}[/tex]Hi can you help me with this problem?Formulate a system of equations for the situation below and solve.The total number of passengers riding a certain city bus during the morning shift is 1300. If the child's fare is $0.50, the adult fare is $1.50, and the total revenue from the fares in the morning shift is $1550, how many children and how many adults rode the bus during the morning shift?children=adults=
Let "A" represent the number of adults that ride the bus and "C" represents the number of children that ride the bus.
On a certain morning shift 1300 people rode the bus, this means that the number of adults and the number of children add up to 1300. You can express the total number of passengers on that shift as follows:
[tex]A+C=1300[/tex]The child's fare is $0.50, so if C children ride the bus a total of 0.50C will be paid.
The adult's fee is $1.50, so if A adult rides the bus, the total earned will be 1.50A.
If you add both fares, you will determine the total fares for the shift, which was $1550
[tex]1.50A+\text{0}.50C=1550[/tex]Using both equations you have determined the number of adults and children that rode the bus:
-First, write the first expression for one of the variables, for example, write it for A:
[tex]\begin{gathered} A+C=1300 \\ A=1300-C \end{gathered}[/tex]-Second, replace the expression obtained in the second equation
[tex]\begin{gathered} 1.50A+0.50C=1550 \\ 1.50(1300-C)+0.50C=1550 \end{gathered}[/tex]Now you have to solve for C
→ Distribute the multiplication on the parentheses term:
[tex]\begin{gathered} 1.50\cdot1300-1.50\cdot C+0.50C=1550 \\ 1950-1.50C+0.50C=1550 \end{gathered}[/tex]→Simplify the like terms
[tex]\begin{gathered} 1950+(-1.50C+0.50C)=1550 \\ 1950+-C=1550 \\ 1950-C=1550 \end{gathered}[/tex]→Subtract 1950
[tex]\begin{gathered} 1950-1950-C=1550-1950 \\ -C=-400 \end{gathered}[/tex]→ Multiply both sides by -1 to invert the sign:
[tex]\begin{gathered} (-1)(-C)=(-1)(-400) \\ C=400 \end{gathered}[/tex]Finally, once you have determined the value of C, you can calculate the value of A as follows:
[tex]\begin{gathered} A=1300-C \\ A=1300-400 \\ A=900 \end{gathered}[/tex]So, 400 children and 900 adults rode the bus.
how many terms the expression x^3+4x^2+2x^-9
How many terms the expression
x^3+4x^2+2x^-9? 3 TERMS
Let log, 4= 3; log, C = 2; log, D= 5 Ac? Do log What is the value of O A. -11 O B.-15,378 O c. 49 D. 2
Given:
[tex](x+2)^2+(y-3)^2=9[/tex]Circle equation is
[tex](x-h)^2+(y-k)^2=r^2[/tex](h,k) be the center of the circle and r be the radius.
[tex]\text{Center(-}2,3)\text{ and radius 3}[/tex]Option C is the correct answer.
Is the system of equations consistent and independent, consistent and dependent, or inconsistent? Y=-3x+1 y=-6x+2
Reason:
The equations are y = -3x+1 and y = -6x+2
The slopes of each equation are -3 and -6. Compare the equations to the form y = mx+b to determine the slope m.
Since the slopes are different, it means the lines aren't parallel and intersect at exactly one location. This immediately tells the reader the system is consistent and independent.
-----------------------------
Extra info:
parallel lines have equal slopes, but different y intercepts.consistent = system has at least one solution. When written with "independent" it leads to "exactly one solution".independent = neither equation is a scaled version of one another, i.e. they produce different lines. In contrast a dependent system is where two lines perfectly overlap to produce infinitely many solutions all along that line.inconsistent = the lines are parallel and never intersect; leading to no solutions.write an explicit formula for an nth term of the sequence 7, 35, 175,....
hello
to write an explicit formula, we have to determine what type of sequence is it
7, 35, 17
this is clearly a geometric progression with values of
first term = 7
common ratio = 5
the explicit formula of a geometric progression is given as
[tex]\begin{gathered} a_n=a\cdot r^{(n-1)}^{} \\ n=\text{nth term} \\ a=\text{first term} \\ r=\text{common ratio} \end{gathered}[/tex]now let's substitute the variables into the equation
[tex]\begin{gathered} a_n=a\cdot r^{(n-1)} \\ a_n=7\cdot5^{(n-1)} \\ a_n=35^{(n-1)} \end{gathered}[/tex]the equation above is the explicit formula for the sequence
identify two different types of optional deductions that an employer may subtract from a paycheck
Two possible deductibles can be the social care or the medical care
write the following division expression using a division symbol and as a fraction 7 divided by x
We are asked to write the following division expression using a division symbol and as a fraction.
7 divided by x
Using a division symbol:
Here you need to write the dividend (7) then the division sign and finally the divisor (x)
[tex]\begin{gathered} dividend\: \div\: divisor \\ 7\: \div\: x \end{gathered}[/tex]As a fraction:
Here you need to write the dividend (7) in the numerator (top) and the divisor (x) in the denominator (bottom)
[tex]\begin{gathered} \frac{dividend}{divisor} \\ \frac{7}{x} \end{gathered}[/tex]Therefore, the division expression using a division symbol is
[tex]7\: \div\: x[/tex]Therefore, the division expression as a fraction is
[tex]\frac{7}{x}[/tex]please find the slopes and lengths then fill in the words that best describes the type of quadrilateral.
We can find the slopes using the following formula:
[tex]m=\frac{y2-y1}{x2-x1}[/tex]And the lengths using the following formulas:
[tex]d=\sqrt[]{(x2-x1)^2+(y2-y1)^2}[/tex]Therefore:
[tex]m_{QR}=\frac{5-2}{-1-(-9)}=\frac{3}{8}[/tex][tex]m_{RS}=\frac{9-5}{1-(-1)}=\frac{4}{2}=2[/tex][tex]m_{ST}=\frac{6-3}{-7-1}=\frac{3}{8}[/tex][tex]m_{TQ}=\frac{6-2}{-7-(-9)}=\frac{4}{2}=2[/tex][tex]\begin{gathered} L_{QR}=\sqrt[]{(-1-(-9))^2+(5-2)^2} \\ L_{QR}=\sqrt[]{73} \end{gathered}[/tex][tex]\begin{gathered} L_{RS}=\sqrt[]{(1-(-1))^2+(9-5)^2} \\ L_{RS}=2\sqrt[]{5} \end{gathered}[/tex][tex]\begin{gathered} L_{ST}=\sqrt[]{(6-9)^2+(-7-1)^2} \\ L_{ST}=\sqrt[]{73} \end{gathered}[/tex][tex]\begin{gathered} L_{TQ}=\sqrt[]{(6-2)^2+(-7-(-9))^2}_{} \\ L_{TQ}=2\sqrt[]{5} \end{gathered}[/tex]Since:
[tex]\begin{gathered} m_{RS}=m_{TQ}\to m_{RS}\parallel m_{TQ} \\ m_{QR}=m_{ST}\to m_{QR}\parallel m_{ST} \end{gathered}[/tex]And:
[tex]\begin{gathered} L_{QR}=L_{ST} \\ L_{RS}=L_{QT} \end{gathered}[/tex]According to this, we can conclude it is a parallelogram
simplify the expression 6w + 2/3 + 3w
we have
6w + 2/3 + 3w
step 1
Combine like terms
(6w+3w)+2/3
9w+2/3Write an equation in point-slope form for the line through the given point with the given slope (9,-1); m =4/3 A . Y-1=4/3(x-9)B. Y-9=4/3(x+1) C. Y+1=4/3(x-9)D. Y-1=4/3(x+9
Step 1: List the given data
[tex]\begin{gathered} m\text{ = }\frac{4}{3} \\ \text{Coordinates (x}_{1\text{ , }}y_1)\text{ = ( 9, -1 )} \end{gathered}[/tex]Step 2: Write the equation of a line formula in a point-slope form
[tex]y-y_1=m(x-x_1\text{ )}[/tex]Step 3: Substitute all values in the point-slope form equation.
[tex]\begin{gathered} y\text{ - (-1) = }\frac{4}{3}(x\text{ - 9)} \\ y\text{ + 1 = }\frac{4}{3}(x\text{ - 9)} \end{gathered}[/tex]Step 4: Final answer
[tex]y\text{ + 1 = }\frac{4}{3}(\text{ x - 9) Option C}[/tex]Find the area of the shaded region. Use 3.14 for π as necessary.The circle centered on point A, and has a radius of 5 cm, is shaded. BC is a diameter of the circle. Point D is on the cicle, such that line AD is perpendicular to line BC. Triangle BCD is not shaded.A. 132 cm²B. 53.5 cm²C. 26.8 cm²D. 17.1 cm²
Given
radius = 5 cm
To get the area of the shaded region, get the difference between the area of the circle, and the area of the triangle
We have the following
[tex]\begin{gathered} A_{\text{circle}}=\pi r^2 \\ A_{\text{circle}}=(3.14)(5\text{ cm})^2 \\ A_{\text{circle}}=(3.14)(25\text{ cm}^2) \\ A_{\text{circle}}=78.5\text{ cm}^2 \\ \\ A_{\text{triangle}}=\frac{1}{2}bh \\ A_{\text{triangle}}=\frac{1}{2}(10\text{ cm})(5\text{ cm})\text{ *the base is twice the radius} \\ A_{\text{triangle}}=25\text{ cm}^2 \\ \\ A_{\text{shaded area}}=A_{\text{circle}}-A_{\text{triangle}} \\ A_{\text{shaded area}}=78.5\text{ cm}^2-25\text{ cm}^2 \\ A_{\text{shaded area}}=53.5\text{ cm}^2 \end{gathered}[/tex]Therefore, the area of the shaded region is 53.5 cm².
Which of the following is the median of the data set? 15 20 20 25 30 35 40 40 45 50 55(1) 28(2) 30(3) 32(4) 34
Median: The media is the middle number in a list of values. If there is an even number of values (so there is no middle number) then average the middle two values together.
so:
[tex]set\colon\mleft\lbrace15,20,20,25,30,35,40,40,45,50,55\mright\rbrace[/tex]From the data set, we can conclude that the middle number (median) is:
[tex]35[/tex]Jen L cut out the following figures on the solid lines and folded them on the third lines which figure formed a rectangle prism
A rectangular prism is a figure that has the following shape:
When the figure is unfolded the shape it has is the following:
Therefore, the right answer is the bottom right shape.
1.BhEvaluate the formula V =3O 9.6 in.³O 288 in. 3332 in.O 96 in.3for B = 9 in.² and h = 32 in.
Given -
B = 9 in²
h = 32 in
To Find -
Evaluate the formula (V) =?
Step-by-Step Explanation -
As we are given
[tex]V\text{ = }\frac{Bh}{3}[/tex]Simply putting the values in the above formula:
[tex]V\text{ = }\frac{9\times32}{3}\text{ = 3}\times32\text{ = 96 in}^3[/tex]Final Answer -
Option D. 96 in³
Suppose you invest $2200 at an annual interest rate of 5.3% compounded continuously. How much will you have after 7 years?
Answer:
$3188.20
Explanation:
From the information given:
• Principal, P = $2200
,• Interest Rate, r=5.3% = 0.053
,• Time, t=7 years
For a principal compounded continuously, we use the formula to determine the amount in the account:
[tex]A(t)=Pe^{rt}[/tex]Substituting the given values, we have:
[tex]\begin{gathered} A(t)=2200\times e^{0.053\times7} \\ =\$3188.20 \end{gathered}[/tex]You will have $3188.20 after 7 years.
6 Ms. Carson drove 96 miles in 15 hoursWhat was her speed in miles per hour!48 miles per hourB.54 miles per hourС64 miles per hourD. 144 miles per hour
Use the compound interest formula to determine the final value of the following amount. $1900 at 10.4% compounded monthly for 4.5 years . What is the final value of the amount?
Answer:
$3027.80
Explanation:
The compound interest formula is the following.
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]where
A = final amount
P = principle amount
r = interest rate / 100
n = number of compounds per interval
t = time interval
Now in our case,
A = unknown
P = $1900
r = 10.4/100
n = 12 months / year ( because the interest is compounded monthly)
t = 4.5 yrs
Therefore, the compound interest formula gives
[tex]A=1900(1+\frac{10.4/100}{12})^{12*4.5}[/tex]Using a calculator, we evaluate the above to get
[tex]\boxed{A=\$3027.80}[/tex]which is our answer!
10 + 8x + 2 = 4x + 36
we have
10 + 8x + 2 = 4x + 36
solve for x
step 1
Combine like terms left side
12+8x=4x+36
step 2
subtract 12 both sides
8x=4x+36-12
8x=4x+24
step 3
subtract 4x both sides
4x=24
step 4
Divide by 4 both sides
x=6
the answer is x=6If angle AOB and angle BOC are complementary angles, and m angle AOB = x°, what is the measure of the supplement of angle BOC?
Complementary angles are angles whose sum is 90 degrees.
If angle AOB and angle BOC are complementary and angle AOB is x degrees, it means that angle BOC is (90 - x) degrees
Supplementary angles are angles whose sum is 180 degrees. If angle BOC is (90 - x) degrees, then the measure of its supplement would be
180 - (90 - x)
= 180 - 90 + x
= 90 + x
the measure of the supplement of angle BOC is (90 + x) degrees
Can you help me with this problem 5^3 x 5^1 then it says select one Add, Subtract, Multiply
Fractions and exponents
5^3 x 5^1
FIRST ADD 3+1 = 4
THEN MULTIPLY 4 times 5^4= 5x5x5x5= 625
I don’t know if my answer is correct I got 28
1) Consider that in 2 days she took 7 bottles each one with 16oz of water:
So we can write out the following:
[tex]undefined[/tex]Pat is 20 years older than his son Patrick. In 2 years, the sum of their ages will be 90. How old are they now?Patrick is years old, and Pat is ?years old.
Let "x" be the age of Patrick.
Pat is 20 years older than his son Patrick so we can represent this as "x+20".
In two years, the age of patrick will be x+2 and the age of Pat will be x+22.
Since in 2 years, the sum of their ages will be 90, we can write:
[tex]\begin{gathered} x+2+x+22=90 \\ 2x+24=90 \\ 2x=66 \\ x=33 \end{gathered}[/tex]And, the age of Pat is x+20 which is 53.
Therefore, Patrick is 33 years old, and Pat is 53 years old.
x/4 (this part is division)
x/4 + 3 = 3
What does x equal?
Answer:x=0
Step-by-step explanation:
5] Great America has a season pass that costs $45 plus $7 each time you attend thepark, or you can pay $12 each time you go. How many times do you have to go beforeyou pay the exact same amount?
Let the number of time he attend the park be represented with n.
So that,
C = 45 + 7n ....eqn(1)
C = 12n ..........eqn(2)
Equating both equations, we have,
[tex]\begin{gathered} 12n=45+7n \\ \text{Collecting like terms, we get} \\ 12n-7n=45 \\ 5n=45 \\ \text{Dividing both sides by 5, we get} \\ n=\frac{45}{5}=9 \end{gathered}[/tex]He has to attend the park 9 times before he can pay exactly the same amount.
So, the correct answer is 9.
The systolic blood pressure of women is normally distributed with a mean of 150 mmHg. and a standard deviation of 10 mmHg. What percentage of a 50-year-old women have a systolic blood pressure between 130 mmHg. and 170 mmHg.?
The required percentage of a 50-year-old woman have a systolic blood pressure between 130 mmHg. and 170 mmHg is 95.44%.
Given that,
The systolic blood pressure of women is normally distributed with a mean of 150 mmHg. and a standard deviation of 10 mmHg.
What is probability?
Probability can be defined as the ratio of favorable outcomes to the total number of events.
Here,
z = [ x - μ]/σ
Accoding to the question,
= p[z < (170-150)/10] - p[z < 130-150/10]
= p [z <2] - p [z < -2]
= 0.9772 - 0.0228
= 95.44%
Thus, the required percentage of a 50-year-old woman have a systolic blood pressure between 130 mmHg. and 170 mmHg is 95.44%.
Learn more about probability here:
brainly.com/question/14290572
#SPJ1
The graph shows the profit, y, of a community fundraiser, with respect to the number of tickets sold, x.Use the graph to complete each statement.Drag and drop the answers into the boxes. The y-intercept is Response area.The y-intercept represents Response area.
Answer:
The y-intercept is -700
The y-intercept represents the initial amount of expenses.
Explanation:
The y-intercept of the graph is the point where the graph crosses the vertical axis. In this case, it is also the value of the profit when the number of tickets sold is 0.
Therefore, the answers are:
The y-intercept is -700
The y-intercept represents the initial amount of expenses.
If a person travels at a speed of 33 m/s and travels 132 meters, how long does the trip take?
Answer: 4 seconds.
Step-by-step explanation: Simply divide 132 meters by 33 m/s. This gives you four. (as in the trip took four seconds.)
It is a uniform rectilinear movement which is one in which an object moves in a straight line, in one only direction, with a constant speed.
When we spoke of constant speed we mean that the movement retains the same speed, that is; that the object does not move faster, or slower and always at the same speed.
If a person travels at a speed of 33 m/s and travels 132 meters, how long does the trip take?We obtain the data according to the exercise.
Data:
V = 33 m/s
D = 132 m
t = ?
We have that the uniform motion formula is:
[tex]\large\displaystyle\text{$\begin{gathered}\sf V=\dfrac{d}{t}, \to where \end{gathered}$}[/tex]
[tex]\large\displaystyle\text{$\begin{gathered}\sf V=Speed \end{gathered}$}[/tex][tex]\large\displaystyle\text{$\begin{gathered}\sf D=distance \end{gathered}$}[/tex][tex]\large\displaystyle\text{$\begin{gathered}\sf T=Time \end{gathered}$}[/tex]We solve for time, since that is what we are asked to calculate. And substitute data in the formula.
[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{t=\dfrac{d}{V} } \end{gathered}$}}[/tex]
[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{t=\frac{132 \not{m}}{33 \ \frac{\not{m}}{s} } } \end{gathered}$}}[/tex]
[tex]\boxed{\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{t=4 \ s} \end{gathered}$}}}[/tex]
I brought on the trip, a time of 4 seconds.