Look around the room and find something. What are its
properties?

When Nickle chloride reacts with lead nitrate then lead chloride precipitate formed NiCl2(aq) + Pb(NO3)2(aq) → Ni(NO3)2(aq) + PbCl2(s).

Solubility is the capacity of a substance, the solute, to shape a solution with any other substance, the solvent. Insolubility is the opposite property, the incapability of the solute to shape the sort of solution.

Solubility is defined because the most quantity of a substance in an effort to dissolve in a given amount of solvent at a unique temperature. Solubility is a characteristic property of a particular solute–solvent combination, and unique substances have significantly differing solubilities.

The reaction is between sodium sulfide and zinc sulfate formed precipitate of zinc sulphide

ZnSO4 (aq) +NaS(aq) - - - - > Na2SO4 (aq) +ZnS(s)

When silver sulphate reacts with lead nitrate then lead dulphate precipitate formed.

Ag2SO4(aq) + Pb(NO3)2(aq) → PbSO4(s) + 2AgNO3(aq)

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The complete combustion of octyne has the form of the following equation:

To balance the equation, we need to count the atoms of each element before and after the reaction occurs. If this number is the same for each type of atom, the reaction is balanced.

Let's start counting:

As you can see, the reaction is not balanced. To balance, we could change the coefficients of each compound in order to count again a lot of times. Doing this, the balanced reaction would be:

The coefficient in front of O2 when the reaction is properly balanced is 23.

Answer:

Light Distribution and Brightness.

Conservation of Energy.

The Appearance of the Space and Luminaires.

Glare.

The Appearance of Color.

Lighting Control and Flexibility.

Lighting of Faces.

Cost of Implementation.

Explanation:

1) Balance the chemical equation.

2) Moles of oxygen needed to produce 18.5 mol NO.

The molar ratio between NO and O2 is 4 mol NO: 5 mol O2.

3) Volume of oxygen required.

3.1- List the known and the unknown quantities.

Sample: O2.

Temperature: 31 ºC.

Pressure: 988 mmHg.

Moles: 23.125 mol.

ideal gas constant: 0.082057 L * atm * K^(-1) * mol^(-1)

Volume: unknown

3.2- Set the equation.

3.3- Converting units.

Temperature: ºC to K.

Pressure

760 mmHg = 1 atm.

3.4- Plug in the known quantities in the ideal gas equation and solve for V (liters).

The volume of O2 required is 444 L.

Answer:

5.77x10^-7 m or 577 nm (nanometers)

Explanation:

The wavelength, λ, and frequency, ν, of light are described by the equation:

c = λν

where c is the speed of light.  

c = 3.0x10^8 m/s

v = 5.2x10^14

λ = c/v

λ = (3.0x10^8 m/s)/(5.2x10^14) = 5.77x10^-7 m

since 1 m = 10^9nm, we can express this as 577 nm (nanometers)

577 nm.  This is in the yellow light span of wavelengths.

Explanation:

a) First, let's find out how many moles are there into 250 mL of orange juice:

0.00214 mol ---- 1000 mL (1L)

x mol ---- 250 mL

1000x = 250 * 0.00214

x = 0.535/1000

x = 5.35 x 10^-4 mol

Now let's transform it to grams. For this, we need to use the molar mass of vitamin C and the following formula: m = n*MM

MM of vitamin C = 176 g/mol

m = 5.35 x 10^-4 * 176

m = 0.09416 g

m = 94.16 mg

Answer a): 94.16 mg of vitamin C

b) Let's transform 80 mg of vitamin C into moles using the formula: n = m/MM

m of vitamin cC = 80 mg = 0.08 g

MM = 176 g/mol

n = 0.08/176

n = 4.54 x 10^-4 moles

Now let's calculate the quantity in mL:

0.00214 mol ---- 1000 mL (1L)

4.54 x 10^-4 moles ---- x mL

0.00214x = 4.54 x 10^-4 * 1000

x = 0.4545/0.00214

x = 212 mL

Answer b): 212 mL

Calculation of the molar mass of C6H8O6:

(6*12)+(8*1)+(6*16) = 176 g/mol

Answer:

Explanation:

a) First, let's find out how many moles are there into 250 mL of orange juice:

0.00214 mol ---- 1000 mL (1L)

x mol ---- 250 mL

1000x = 250 * 0.00214

x = 0.535/1000

x = 5.35 x 10^-4 mol

Now let's transform it to grams. For this, we need to use the molar mass of vitamin C and the following formula: m = n*MM

MM of vitamin C = 176 g/mol

m = 5.35 x 10^-4 * 176

m = 0.09416 g

m = 94.16 mg

Answer a): 94.16 mg of vitamin C

b) Let's transform 80 mg of vitamin C into moles using the formula: n = m/MM

m of vitamin cC = 80 mg = 0.08 g

MM = 176 g/mol

n = 0.08/176

n = 4.54 x 10^-4 moles

Now let's calculate the quantity in mL:

0.00214 mol ---- 1000 mL (1L)

4.54 x 10^-4 moles ---- x mL

0.00214x = 4.54 x 10^-4 * 1000

x = 0.4545/0.00214

x = 212 mL

Answer b): 212 mL

Calculation of the molar mass of C6H8O6:

(6*12)+(8*1)+(6*16) = 176 g/mol

Explanation:

24.90 moles of carbon dioxide are formed if 8.30 moles of propane (c3h8) is burned in air (so oxygen won't run out).

A three-carbon alkane, propane has the chemical formula C3H8. At room temperature and pressure, it is a gas, but it can be compressed into a liquid for transportation.

Given:

8.30 moles of propane

Combustion reaction will be

   C3H8+5O2→3CO2+4H2O

Now from the above reaction it is clear that 1 mole of propane after combustion produces 3 moles of CO2

So 8.30moles of propane will produce

8.30*3molesof CO2/1Mole of C3H8=24.90 moles

Hence,24.90 moles of carbon dioxide are formed if 8.30 moles of propane (c3h8) is burned in air (so oxygen won't run out).

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Answer:

frequency

Explanation:

Sounds are higher or lower in pitch according to the frequency of vibration of the sound waves producing them. A high frequency (e.g., 880 hertz [Hz; cycles per second]) is perceived as a high pitch and a low frequency (e.g., 55 Hz) as a low pitch.

Hyperconjugation makes the alkanes more stable than less substituted alkanes.

Hyperconjugation refers to the delocalization of electrons with the primary sigma bonds. Usually, hyperconjugation involves the interaction of the electrons in a sigma orbital for example C–H or C–C with an adjacent unpopulated non-bonding p or antibonding σ* or π* orbitals to give a pair of extended molecular orbitals.

  It suggests a key factor in shortening of sigma bonds (σ bonds). For example, the single C–C bonds in 1,3-butadiene and propyne are approximately 1.46 Å in length, much less than the value of around 1.54 Å found in saturated hydrocarbons. For butadiene, this can be explained as normal conjugation of the two alkenyl parts. But for propyne, it is generally accepted that this is due to hyperconjugation between the alkyl and alkynyl parts.

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Propanol, ethylene glycol, then butane this is the solubility in water of these molecules. Ethylene glycol is miscible in water. Solubility of butane is 61 mg/l. And propanol is totally soluble in water.

The capacity of a material, the solute, to combine with another substance, the solvent, is known as solubility. Insolubility, or the solute's inability to create such a solution, is the opposite attribute.

Hydrogen bonds as well as dipole-dipole forces can be used by 1-propanol to interact with water. By neither method can butane interact with water. Therefore, 1-propanol has a substantially higher solubility.

The most soluble form of ethylene glycol is water. because it may create a H bond with water because to its two -OH groups. Therefore, more H bonding increases solubility in water.

Thus, most soluble in water to least soluble in water is option A, option B and then option C.

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Answer: 1,2,1,2

Answer:

1,2,1,2

Explanation:

See attached worksheet.  Balancing equations requires some organization and a pencil for making many changes in the process of finding the correct coefficients.  Add a litttle patience is required, but discovering the solution can be fun

Answer: they are shiny metals with low melting points

Answer:

False

Explanation:

Biotic factors are those parts of the environment that are living such as humans, bacteria, fungi and protists.

Abiotic factors are those parts of the environment that are non-living.

Answer:

A b/c aluminum

Explanation:

don't forget to follow rate like

The amount of calcium chloride in the supplied solution weighs 247.49 g is needed to make 785.7 g of a solution that is 31.5% cacl2 in water.

We receive:

Solution mass: 785.7 grams

Water contains 31.5% (m/m) calcium chloride as well.

This indicates that there are 31.5 g of calcium chloride in a 100 g solution.

We employ the unitary technique to determine the mass of calcium chloride in the specified volume of solution:

The mass of calcium chloride present in 100 g of solution is 31.5 g.

Therefore, in 785.7 g of solution, there are 785.7 g of calcium chloride.

31.5/100*785.7

= 247.49 g

Consequently,247.49 g  of calcium chloride are present in the given amount of solution.

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The volume of the solution is 50 dm3. We can use the below formula:

Concentration = [tex]\frac{moles}{volume}[/tex]

But, if we shift the positions of concentration and volume, then:

volume = [tex]\frac{moles}{concentration}[/tex]

Now, just by substituting the corresponding values, we can obtain the volume of solution in the container.

Volume = [tex]\frac{3 moles}{0.06 moles / dm3}[/tex] = 50 dm3.

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2.12 × 10²⁵ number of molecules are present in 7. 05 moles of pyridine.

Pyridine- A nitrogen atom has been added in lieu of one of the -CH groups in the benzene core to create pyridine, an azaarene. It belongs to the family of compounds known as pyridines. It plays a part in contaminating the environment. It is an organic heteromonocyclic mancude parent, an azaarene, a monocyclic heteroarene, and a member of the pyridine family.

Avogadro's number, which is equal to 6.02214076 × 10²³, is the quantity of units in one mole of any material (defined as its molecular weight in grams). Depending on the substance and the nature of the reaction, the units may be electrons, atoms, ions, or molecules (if any)

Given that there are 7.05 moles of pyridine,

The C₅H₅N has a molar mass of 79 g/mol.

One pyridine molecule contains five carbon atoms.

The number of molecules in one mole of pyridine is 5×6.022 10²³.

The number of molecules in 7.05 moles of pyridine are therefore equal to 7.05 × 5 × 6.022 10²³.

⇒ 2.12 × 10²⁵ number of molecules.

Hence, 2.12 × 10²⁵ number of molecules are present in 7. 05 moles of pyridine.

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Answer: the presence of impurities in a compound lowers the melting point and broadens the range.

Explanation: this is because the impurities cause defects in the crystalline lattice of the compounds, it is easier to break down the intermolecular interactions between the compounds.

thus, when the compounds with impurities are given heat, it has less melting point than the purest form because of breakage of intermolecular interactions faster.

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Answer:

The correct answer is, D. growing in size

The most important reason why ordering the elements by increasing atomic mass does not result in an effective periodic table is that the atomic mass does not increase in a regular manner in going from one element to next.

An atom's mass is its atomic mass. Although the kilogram is the SI measure of mass, the unified atomic mass unit, or dalton, is a common way to express atomic mass. An unbound carbon-12 atom in its ground state has a mass of 112 of a Da.

14.0067 u is the atomic mass of nitrogen.

Hence, the most important reason why ordering the elements by increasing atomic mass does not result in an effective periodic table is that the atomic mass does not increase in a regular manner in going from one element to next.

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A  polymer of monosaccharides linked by glycosidic bonds is known as a polysaccharide.

We know that there are different kinds of sugars that we have. This would depend on the way that the atoms of the sugar are joined together. The various kinds of sugars are found to be;

Monosaccharides: These are composed of simple sugar units

Disaccharides: These are composed of two sugar units that are joined together.

Polysaccharides : These are composed of more than two sugar units that are joined together.

Now we have to note that in talking about poly saccharides the idea that they are sugars that are composed of many units have to be at the back of our minds in the discussion. The many units have to be joined by a kind of bond that is called the  glycosidic bonds

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Tools, testing equipment, and personal protective equipment need to be regularly inspected and are tested, and PCBU needs to have procedures in place to make sure of this.

Before each use, all the instruments, testing apparatus, and PPE should be visually inspected for signs of damage. To make sure that equipment, such as tools, PPE, rubber mats, and LV rescue kits, are in good working order before usage, PCBUs should have "pre-start" visual inspection processes in place. Before usage, testing equipment needs to be checked out for damage to the insulated leads and probes and verified to be functional. To make sure it offers the necessary level of protection, testing equipment should be examined on a regular basis. The following variables will affect testing intervals: the frequency of the use, the setting, and the manufacturer's recommendations

With this requirement, both workers performing work and the finished work are guaranteed to be electrically safe.

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When the electron falls from energy level 6 to energy level 2, it will irradiate Balmer  series that lies in the visible region of electromagnetic spectrum.

A hydrogen atom has six spectral lines. Spectral emissions occurs when an electron transitions jumps from a higher energy state to a lower energy state. The spectral lines are grouped into series according to the lower energy level of atomic hydrogen is divided into a number of spectral series, with wavelengths.

Wavelength of these spectral lines can be calculated by the Rydberg formula and these spectral lines are formed due to the electron that undergoes transitions between two energy levels in an atom.

Spectral emissions occurs when an electron transitions jumps from a higher energy level to a lower energy level.

The spectral lines are generally grouped into series according to the lower energy level.

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N₂O₄(g)   ---->  2NO₂(g) is called as the decomposition reaction.

When one reactant in a chemical reaction is decompose to form one or more products then the chemical reaction is said to be decomposition reaction. The reaction is as follows :

N₂O₄(g)   ---->  2NO₂(g)

This equation is balanced equation. Dinitrogen tetroxide containing N - N single bond dissociates to form two molecules of nitrogen dioxide. the reaction is called as decomposition reaction . decomposition reaction are generally endothermic reaction because they require heat to decompose. as we know to break the bond energy is absorbed and formation of bond is the release of energy.

Thus, N₂O₄(g)   ---->  2NO₂(g) is called as the decomposition reaction.

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To determine the moles of a compound from the mass in grams, we must use the molecular mass. The molecular mass is calculated by adding the atomic weights of the elements multiplied by the atoms of the element present in the molecule. To make it easier we can make the following table:

We have that the molar mass of CHCl3 is: 119.377g/mol.

The number of moles will be:

In 16.0g pf CHCl3 there are 0.134 moles

According to the laws of thermodynamics, energy will remain constant in a system, therefore energy will not be created or destroed but it will be transformed, remaining constant. Letter B

Answer:

0.0220 g (22 mg) of NO2.

Explanation:

To solve this type of problem, it is best to work with grams. Remember that 1 kg equals 1000 g and 1 g equals 1000 mg. The conversion for 5.26 kg of nitrogen monoxide (NO) would be:

And for 7.64 mg of oxygen (O2) is:

The next step is to find the number of moles of each reactant using its molar mass. The molar mass of NO is 30 g/mol (you can calculate the molar mass of a compound using the periodic table):

And the moles of oxygen (O2) is 32 g/mol:

The next step is to see how many moles of NO" can be produced for each reactant.

You can see in the chemical equation that 2 moles of NO produce 2 moles of NO2, so the molar ratio between them is 1:1. This means that 175.33 moles of NO reacted produce 175.33 moles of NO2.

Now, you can see that 1 mol of O2 reacted produces 2 moles of NO2, so let's see how many moles of NO2 are being produced:

You can note that the limiting reactant, in this case, is oxygen (O2) because this reactant imposes the "limit" to produce the product.

The final step is to convert from 4.776 x 10^(-4) moles of NO2 to grams using its molar mass which is 46 g/mol. The conversion will look like this:

We obtain 0.0220 g (22 mg) of NO2 from 5.26 kg of NO and 7.64 mg of O2.

The gas that has more kinetic energy is nitrogen.

We know that from the ideal gas equation, the molecules that compose a gas are in constant random motion. The implication of this is that, the kinetic energy of the molecules of the gas would depend on the velocity of the molecules of the gas.

Since we can not measure the individual velocities of the molecules of a gas but we can be able to measure the root mean square speed of the molecules of the gas as we can see.

This root mean square velocity is going to depend on the molar mass of the gas as well as the temperature of the system. Where the system is at the same temperature, the greater the molar mass, the lesser the kinetic energy of the gas.

Nitrogen ([tex]N_{2}[/tex]) has a molar mass of 28 g/mol while oxygen ([tex]O_{2}[/tex]) has a molar mass of 32 g/mol.

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Answer:

carries oxygen, nutrients, and hormones to cells, and removes waste products, like carbon dioxide.

Explanation: