log 2-log 5 can also be written as ?.

Answers

Answer 1

The formula for difference of two logarthimic terms are,

[tex]\log a-\log b=\log (\frac{a}{b})[/tex]

Determine the expression for log 2 -log 5.

[tex]\log 2-\log 5=\log (\frac{2}{5})[/tex]

Answer: log(2/5)


Related Questions

between 1993 and 1996 there where 6545 injured horses find the ratio of injuries per year

Answers

First, we have to know the total number of years between 1993 and 1996. If we subtract, we find the there are 3 years in between.

Now, we divide the total number of injured horses by the total numbers of years.

[tex]r=\frac{6545}{3}=2,181.7[/tex]

However, we can't round to 2,182 because horses are not incomplete.

Therefore, the total number of injured horses per year is 2,181.

How do you figure out what the order pairs are in this equation? 2x-2=y

Answers

Equations express relationships between variables and constants. The solutions to two-variable equations consist of two values, known as ordered pairs, and written as (a, b) where "a" and "b" are real-number constants. An equation can have an infinite number of ordered pairs that make the original equation true.

Here, the given equation is,

[tex]2x-2=y[/tex]

Rewriting this equation in terms of x, we have,

[tex]\begin{gathered} 2x-2=y \\ 2x=y+2 \\ x=\frac{y+2}{2} \end{gathered}[/tex]

So, now creating a table, with the values, we get the ordered pair. For example, let us take x as 1, then ,

[tex]\begin{gathered} 1=\frac{y+2}{2} \\ 2=y+2 \\ y=0 \end{gathered}[/tex]

So, (1,0) is an ordered pair in this equation.

If x =0,

[tex]y=0-2=-2[/tex]

So the pair is, (0,-2).

Which quadrant includes every points with a negative x-coordinate and a negative y-coordinateA) Quadrant IVB) Quadrant IC) Quadrant IID) Quadrant III

Answers

Hello!

Let's analyze the points from each quadrant:

Quadrant I:

x > 0 and y > 0

Quadrant II:

x < 0 and y > 0

Quadrant III:

x < 0 and y < 0

Quadrant IV:

x > 0 and y < 0

So, the answer is:

Alternative D) Quadrant III.

Graph each line given the slope and y-intercept.Label each one

Answers

A)

Equation:

[tex]y=\frac{1}{3}x-3[/tex]

B)

Equation:

[tex]y=0.5x+1.5[/tex]

C)

Equation:

[tex]y=-2x-5[/tex]

D)

Equation:

[tex]y=\frac{3}{2}x+2[/tex]

Suppose a spherical snowball is melting and the volume is decreasing at a constant rate, changing from 12 in^3/min to 10in^3/min in 30min. How fast is the radius changing when the volume is 8in^3/min? (Answer in terms of pi)

Answers

The radius changing when the volume is 8in^3/min by: -512π /30 in³ /min.

How to find the radius?

First step is to find the  radius changing over time at a constant rate

dr/dt = 10-12 /30

= -2/30 in/min

Now let find the how fast is the radius changing using this formula

dV/dt = 4πr²(dr/dt)

Where,

r =8

Hence,

dV/dt  = 4π (8in)² × -2/30 in/min

dV/dt  = 4π (64in) × -2/30 in/min

dV/dt  = -512π /30 in³ /min

Therefore the change in radius is -512π /30 in³ /min.

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How many possible triangles can be created if measure of angle B equals pi over 6 comma a = 20, and b = 10?

Answers

First, we have to find the height using the following equation:

[tex]h\text{ = }b\sin (B)[/tex][tex]h\text{ = 10}\times\sin (\frac{\pi}{6})=5[/tex]

We have found the height. If h < b < a, we can have only one triangle. That is the case. So the answer will be 1 triangle.

What is the answer
(3t/t^5)^-5

Answers

The resultant answer of the given expression (3t/t⁵)⁻⁵ is t²⁰/243.

What exactly are expressions?A finite collection of symbols that are properly created in line with context-dependent criteria is referred to as an expression, sometimes known as a mathematical expression.To evaluate an algebraic expression, you must substitute a number for each variable and perform the arithmetic operations.The previous example's variable x is equivalent to 6 because 6 plus 6 = 12.If we know the values of our variables, we can replace the original variables with those values before evaluating the expression.

So, solve the expression as follows: (3t/t^5)^-5

Apply exponent rule:

(3t/t^5)^-51/((3t/t^5)^5)

Simplify as shown:

(3t/t^5)^5: 243/t²⁰1/243/t²⁰

Apply function rule:

t²⁰/243

Therefore, the resultant answer of the given expression (3t/t⁵)⁻⁵ is t²⁰/243.

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Find the reference angle for a rotation of 129º.

Answers

In order to find a reference angle, we need to find the smallest possible angle formed between the x-axis and the terminal line of the given angle, going either clockwise or counterclockwise.

Since the given angle is 129°, and 90<129<180, it will look something like this:

As we can see, the reference angle will be

[tex]180-129=51[/tex]

so it will be 51°.

Every rational number is also an integer.TrueorFalse

Answers

Every rational number is also an integer.

we have that

The rational numbers include all the integers

so

the answer is true

It is equally probable that the pointer on the spinner Shown will land on any one of the eight regions number one through eight if the pointer lands on the borderline spin again. find the probability that the pointer will stop on an even number or number greater than three

Answers

SOLUTION

The even numbers here are 2, 4, 6 and 8. That is 4 numbers.

The numbers greater than 3 are 4, 5, 6, 7, and 8, that is 5 numbers.

And we have a total of 8 numbers.

Let P(A) be the probability of the pointer landing on an even number

Let P(B) be the probability of the pointer landing on a number greater than 3

Let P(A or B) be the probability that the pointer stops on an even number or number greater than three

From the probability formula,

[tex]P(\text{A or B) = P(A) + P(B) - P(A}\cap B)[/tex][tex]\text{ P(A}\cap B)\text{ means probability of A and B}[/tex]

Hence

[tex]\begin{gathered} P(A)=\frac{4}{8} \\ P(B)=\frac{5}{8} \end{gathered}[/tex][tex]\begin{gathered} \text{ For P(A}\cap B)\text{ we can s}ee\text{ that betwe}en\text{ } \\ \text{the even numbers 2, 4, 6, 8 and } \\ n\text{umbers greater than 3, which are 4, 5, 6, 7, 8} \\ \text{what is common is 4, }6,\text{ 8} \\ So,\text{ } \\ \text{P(A}\cap B)=\frac{3}{8} \end{gathered}[/tex]

Therefore, P(A or B) becomes

[tex]\begin{gathered} \frac{4}{8}+\frac{5}{8}-\frac{3}{8} \\ \frac{4+5-3}{8} \\ \frac{6}{8} \\ =\frac{3}{4} \end{gathered}[/tex]

Determine the smallest integer value of x in the solution of the following inequality.3x + 4> -18

Answers

We have the following inequality:

3x + 4 > -18

Subtracting 4 from both sides we got:

3x > -22

Dividing both sides by 3 we got:

x > -22/3

Since -22/3 is between -7 and -8 and x must be equal or greater than -22/3, the smallest integer value in the solution of the inequality is -7 (note that -8 isn't part of the solution)

Graph the linear function g(x) = -4+7xGraph the linear function G (x equals negative 4 + 7x

Answers

Given a function,

[tex]g(x)=-4+7x[/tex]

At x = 0,

[tex]g(0)\text{ = -4}[/tex]

At g(x) = 0,

[tex]\begin{gathered} -4+7x=0 \\ x=\frac{4}{7} \end{gathered}[/tex]

At x= 1,

[tex]g(1)\text{ = 3}[/tex]

Therefore, the required graph is,

what does 1,580÷25=I know the answer, I need to show how I got it.

Answers

[tex]\begin{gathered} \sqrt[25]{1580} \\ 1\text{ and 15 cannot divide 25 therefore, we use the first three numbers to divide 25} \\ \frac{158}{25}\text{ = }6\text{ remainder 8} \\ \text{You have to carry that remainder which is 8 and combine it with the 0 in 1580.} \\ \frac{80}{25}\text{ = }3\text{ remainder 5} \\ The\text{ remainder 5 will also divide 25} \\ \frac{5}{25}=0.2 \\ The\text{ quotient values are 63 + 0.2 = 63.2} \end{gathered}[/tex]

Put the following equation of a line into slope-intercept form, simplifying all
fractions.
12y-2x = 108

Answers

Answer: y= x/6+9

Step-by-step explanation:

In the image below ⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯∥⎯⎯⎯⎯⎯⎯⎯⎯⎯LM¯∥OP¯. Given the lines are parallel, ∠≅∠∠LMN≅∠PON because and that ∠≅∠∠LNM≅∠ONP by the , you can conclude the triangles are similar by the AA Similarity Theorem. If NP = 20, MN = x+ 6, NO = 15, and LN = 2x - 3 then x = .

Answers

Given:

Required:

We need to answer the questions

Explanation:

Angle LMN and angle PON are the congruent because both are alternate angles

Now angle LNM and angle ONP are also congruent because those two triamgles are similar and both are internal angles

Now to find the value of x

[tex]\begin{gathered} \frac{NP}{MN}=\frac{NO}{LN} \\ \\ \frac{20}{x+6}=\frac{15}{2x-3} \\ \\ 40x-60=15x+90 \\ 25x=150 \\ x=6 \end{gathered}[/tex]

Final answer:

x=6

How to find the inverse of the matrix Question number 19

Answers

Okay, here we have this:

We need to find the inverse of the matrix, let's do it:

[tex]\begin{bmatrix}{2} & {4} & {1} \\ {-1} & {1} & {-1} \\ {1} & {4} & {0}\end{bmatrix}[/tex]

For that we are going to make the augmented form with the identity matrix and convert the original matrix into the identity:

[tex]\begin{gathered} \begin{pmatrix}2 & 4 & 1 & | & 1 & 0 & 0 \\ -1 & 1 & -1 & | & 0 & 1 & 0 \\ 1 & 4 & 0 & | & 0 & 0 & 1\end{pmatrix} \\ =\begin{pmatrix}2 & 4 & 1 & | & 1 & 0 & 0 \\ 0 & 3 & -\frac{1}{2} & | & \frac{1}{2} & 1 & 0 \\ 1 & 4 & 0 & | & 0 & 0 & 1\end{pmatrix}\text{ }R_2\leftarrow R_2+\frac{1}{2}R_1 \\ =\begin{pmatrix}2 & 4 & 1 & | & 1 & 0 & 0 \\ 0 & 3 & -\frac{1}{2} & | & \frac{1}{2} & 1 & 0 \\ 0 & 2 & -\frac{1}{2} & | & -\frac{1}{2} & 0 & 1\end{pmatrix}\text{ }R_3\leftarrow R_3-\frac{1}{2}R_1 \\ =\begin{pmatrix}2 & 4 & 1 & | & 1 & 0 & 0 \\ 0 & 3 & -\frac{1}{2} & | & \frac{1}{2} & 1 & 0 \\ 0 & 0 & -\frac{1}{6} & | & -\frac{5}{6} & -\frac{2}{3} & 1\end{pmatrix}R_3\leftarrow R_3-2/3R_2 \\ =\begin{pmatrix}2 & 4 & 1 & | & 1 & 0 & 0 \\ 0 & 3 & -\frac{1}{2} & | & \frac{1}{2} & 1 & 0 \\ 0 & 0 & 1 & | & 5 & 4 & -6\end{pmatrix}R_3\leftarrow-6R_3 \\ =\begin{pmatrix}2 & 4 & 1 & | & 1 & 0 & 0 \\ 0 & 3 & 0 & | & 3 & 3 & -3 \\ 0 & 0 & 1 & | & 5 & 4 & -6\end{pmatrix}R_2\leftarrow R_2+\frac{1}{2}R_3 \\ =\begin{pmatrix}2 & 4 & 0 & | & -4 & -4 & 6 \\ 0 & 3 & 0 & | & 3 & 3 & -3 \\ 0 & 0 & 1 & | & 5 & 4 & -6\end{pmatrix}R_1\leftarrow R_1-R_3 \\ =\begin{pmatrix}2 & 4 & 0 & | & -4 & -4 & 6 \\ 0 & 1 & 0 & | & 1 & 1 & -1 \\ 0 & 0 & 1 & | & 5 & 4 & -6\end{pmatrix}R_2\leftarrow\frac{1}{3}R_2 \\ =\begin{pmatrix}2 & 0 & 0 & | & -8 & -8 & 10 \\ 0 & 1 & 0 & | & 1 & 1 & -1 \\ 0 & 0 & 1 & | & 5 & 4 & -6\end{pmatrix}R_1\leftarrow R_1-4R_2 \\ =\begin{pmatrix}1 & 0 & 0 & | & -4 & -4 & 5 \\ 0 & 1 & 0 & | & 1 & 1 & -1 \\ 0 & 0 & 1 & | & 5 & 4 & -6\end{pmatrix}R_1\leftarrow\frac{1}{2}R_1 \end{gathered}[/tex]

Finally the inverse is on the right side of the augmented matrix:

[tex]=\begin{pmatrix}-4 & -4 & 5 \\ 1 & 1 & -1 \\ 5 & 4 & -6\end{pmatrix}[/tex]

Preform the indicated Operation g(n)=2n^2-4nh(n)=n-1find g(h(1-b))

Answers

GIven:

The expressions are given as,

[tex]\begin{gathered} g(n)=-2n^2-4n \\ h(n)=n-1 \end{gathered}[/tex]

The objective is to find g(h(-1-b)).

Explanation:

To find h(-1-b):

The value of h(-1-b) can be calculated by replacing the n with (-1-b) in the expression of h(n).

[tex]\begin{gathered} h(n)=n-1 \\ h(-1-b)=-1-b-1 \\ h(-1-b)=-2-b\text{ . . . . . . (1)} \end{gathered}[/tex]

To find g(h(-1-b)):

The value of g(h(-1-b)) can be calculated by replacing the n with h(-1-b) in the expression g(n).

[tex]\begin{gathered} g(n)=-2n^2-4n \\ g(h(-1-b))=-2(-2-b)^2-4(-2-b)\text{ . . . . (2)} \end{gathered}[/tex]

On further solving the equation (2),

[tex]undefined[/tex]

Solve: x^3= -65 This is for homework

Answers

Step 1

Solve the equation by graphing

You can rewrite the equation as

[tex]x^3+65=0[/tex]

step 2

Using a graphin calculator as Desmos

x=-4.021

The solution is x=-4.021

-

need to show 1,242 ÷ 23 = and 732 x 268 = show answers on graph

Answers

1,242 ÷ 23 = 54

and

732 x 268 = 196, 176

z divided by 13=28 i need the answers this is hard for me

Answers

Answer:

364

Step-by-step explanation:

z/13 = 28

z = 13 x 28

z = 364

determine the type and key parts of the graph of the second equation

Answers

ANSWER

[tex]\begin{gathered} \left(h,\:k\right)=\left(0,\:0\right),\:a=3,\:b=6 \\ major\text{ axis;vertical} \\ minoraxis;horizontal \end{gathered}[/tex]

EXPLANATION

The second equation;

[tex]\frac{x^2}{9}+\frac{y^2}{36}=1[/tex]

It is an Elipse.

Ellipse standard equation;

[tex]\frac{\left(x-h\right)^2}{a^2}+\frac{\left(y-k\right)^2}{b^2}=1[/tex]

Rewrite the given equation in the form of the standard equation;

Hence, we have;

[tex]\frac{\left(x-0\right)^2}{3^2}+\frac{\left(y-0\right)^2}{6^2}=1[/tex]

Therefore the ellipse properties are;

[tex]\left(h,\:k\right)=\left(0,\:0\right),\:a=3,\:b=6[/tex]

Major axis is;

[tex]\begin{gathered} 2a \\ =2\times6=12 \end{gathered}[/tex]

Minor axis is;

[tex]\begin{gathered} 2b \\ =2\times3=6 \end{gathered}[/tex]

How do I simplify -88/4

Answers

[tex]\begin{gathered} \Rightarrow\frac{-88}{4} \\ \Rightarrow\frac{-44}{2} \\ \Rightarrow-22 \end{gathered}[/tex]

A linear function contains the following points.
X
y
What are the slope and y-intercept of this function?
A. The slope is 4.
The y-intercept is (0, -1).
5
B. The slope is.
The y-intercept is (0, -1).
C. The slope is.
The y-intercept is (-1,0).
D. The slope is.
0
-1
The y-intercept is (0, -1).
5
3

Answers

The slope will be 4/5.

And, The y - intercept will be (0, - 1)

What is Equation of line?

The equation of line in point-slope form passing through the points

(x₁ , y₁) and (x₂, y₂) with slope m is defined as;

⇒ y - y₁ = m (x - x₁)

Where, m = (y₂ - y₁) / (x₂ - x₁)

Given that;

The points are,

(0, - 1) and (5, 3)

Now,

Since, The slope of the line passing through the points (x₁ , y₁) and (x₂, y₂) is;

m = (y₂ - y₁) / (x₂ - x₁)

So, The slope of the line passing through the points (0, - 1) and (5, 3) is;

m = (y₂ - y₁) / (x₂ - x₁)

m = (3 - (-1)) / (5 - 0)

m = (3 + 1) / 5

m = 4/5

And, The y - intercept is at x  = 0

Thus, The slope will be 4/5.

And, The y - intercept will be (0, - 1)

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hXL for School: Practice & Problem Solving 5.2.PS-19 Question Help Equivalent ratios can be found by extending pairs of rows or columns in a multiplication table. Write 3 3 ratios equivalent to using the multiplication table. 5 Click the icon to view the multiplication table. 3 Find three ratios that are equivalent to 5 12 6 4 IA. B. OC. 20 10 6 15 15 9 OD OE. F. 9 30 15 Click to select your answer(s) and then click Check Answer. All parts showing Clear All Check Answer Review progress Question 7 of 12 Back Next >

Answers

To find equivalent ratios to 3/5, we just have to multiply each part by 4, 2, and 3.

[tex]\begin{gathered} \frac{3\cdot4}{5\cdot4}=\frac{12}{20} \\ \frac{3\cdot2}{5\cdot2}=\frac{6}{10} \\ \frac{3\cdot3}{5\cdot3}=\frac{9}{15} \end{gathered}[/tex]Hence, the right answers are A, B, and F.

What is the yintercept of O A. (0,0) O B. (0,1) O C. (1,0) OD (9)

Answers

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data

y-intercept = ?

f(x) = (1/2) ^ x

Step 02:

y-intercept :

x = 0

[tex]\begin{gathered} y\text{ = (}\frac{1}{2})^0=1 \\ \end{gathered}[/tex]

The answer is:

y-intercept

(0 , 1)

Write down the expansion of (2x+y)^4

Answers

[tex](2x+y)^4[/tex]

Use the following formula:

[tex](a+b)^4=a^4+4a^3b+6a^2b^2+4ab^3+b^4[/tex]

Let:

[tex]\begin{gathered} a=2x \\ b=y \end{gathered}[/tex]

Therefore:

[tex]\begin{gathered} (2x+y)^4=(2x)^4+4(2x)^3y+6(2x)^2y^2+4(2x)y^3+y^4 \\ (2x+y)^4=16x^4+32x^3y+24x^2y^2+8xy^3+y^4 \end{gathered}[/tex]

The graph shows a relationship between two quantities.ДУ200018001600140012001000800600400200ХOd-8 -6 4-2 0 2 4Which equation best represents the relationship between the variables?

Answers

First let't find the slope

Pick any two point and locate its coordinate

(0, 1500) and (2, 1800)

x₁ = 0 y₁=1500 x₂=2 y₂=1800

substitute the values into the formula below to find the slope

[tex]\text{slope(m)}=\frac{y_2-y_1}{x_2-x_1}[/tex]

[tex]=\frac{1800-1500}{2-0}[/tex][tex]=\frac{300}{2}=150[/tex]

The y-intercept(b) of the graph is b=1500

Substitute the values of the slope and intercept into y=mx +b

This gives the equation of the graph.

That is:

[tex]y=150x\text{ + 1500}[/tex]

7 m The side lengths of the base of a triangular prism are 7 meters, 5 meters, and 8 meters. The height of the prism is 12.5 meters. 12.5 m 6 m What is the lateral surface area of the prism in square meters? 5 m

Answers

Given a triangular prism with side lengths of the base as a, b, and c, and height h, then the lateral surface area, A is given by

[tex]A=(a+b+c)h[/tex]

In our case,

[tex]a=5m,b=6m,c=7m,\text{ and }h=12.5m[/tex]

Hence,

[tex]A=(5+6+7)12.5=18\times12.5=225m^2[/tex]

Therefore, the lateral surface area in square meters is 225

If there are three black, four white, two blue, and four gray socks in a drawer, what would be the probability of picking a blue sock? Round your answer to the nearest tenth.15.4%25%22%15.38%

Answers

The formula for determining probability is expressed as

Probability = number of favorable outcomes/number of total outcomes

number of favorable outcomes = number of blue socks = 2

number of total outcomes = number of all socks = 3 + 4 + 2 + 4 = 13

Thus, the probability of picking a blue sock is

2/13 = 0.1538

Converting to percentage, we would multiply by 100. We have

0.1538 x 100

= 15.38%

1) The expression 5p represents the total price of buying 5 movie tickets. • What do the parts of the expression 5p represent? ) The variable p represents the ticket price The number 5 represents the number of tickets Today there is a discount of $10 off a purchase of 5 or more movie tickets. Which expression can you use to find the total price of 5 movie tickets after the discount? 10p + 5 5p - 10 10p - 5 5p + 10

Answers

Solution

The expression 5p represents the total price of buying 5 movie tickets. • What do the parts of the expression 5p represent?

The variable p represents the ticket price The number 5 represents the number of tickets

For this case the correct answer would be:

5p -10

The coefficient 5 represents the price of 1 ticket

for the next part the answer would be:

7 +3x

And the last part

2/3 y -6

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