Let f(x) = x2 - 9a and g(a) = 3 - x?.(f+g)(7) =- (f - 9)(7) =.· (f9)(7) =• (4) (7) -
Answers
Given the functions:
[tex]f(x)=x^2-9x[/tex][tex]g(x)=3-x^2[/tex]1) (f+g)(x) You have to calculate the sum between f(x) and g(x) for x=7
First, calculate the sum between both functions:
[tex]\begin{gathered} (f+g)=(x^2-9x)+(3-x^2) \\ (f+g)=x^2-9x+3-x^2 \end{gathered}[/tex]Order the like terms together and simplify:
[tex]\begin{gathered} (f+g)=x^2-x^2-9x+3 \\ (f+g)=-9x+3 \end{gathered}[/tex]Substitute the expression with x=7 and solve:
[tex]\begin{gathered} (f+g)(7)=-9x+3 \\ (f+g)(7)=-9\cdot7+3 \\ (f+g)(7)=-60 \end{gathered}[/tex]The result is (f+g)(7)= -60
2) (f-g)(7) You have to calculate the difference between f(x) and g(x) for x=7
First, calculate the difference between both functions:
[tex](f-g)=(x^2-9x)-(3-x^2)[/tex]First, erase the parentheses, the minus sign before (3-x²) indicates that you have to change the sign of both terms inside the parentheses, as if they were multiplied by -1, then:
[tex](f-g)=x^2-9x-3+x^2[/tex]Order the like terms and simplify:
[tex]\begin{gathered} (f-g)=x^2+x^2-9x-3 \\ (f-g)=2x^2-9x-3 \end{gathered}[/tex]Substitute the expression with x=7 and solve:
[tex]\begin{gathered} (f-g)(7)=2x^2-9x+3 \\ (f-g)(7)=2(7)^2-9\cdot7+3 \\ (f-g)(7)=2\cdot49-63-3 \\ (f-g)(7)=98-66 \\ (f-g)(7)=32 \end{gathered}[/tex]The result is (f-g)(7)= 32
3) (fg)(7) In this item you have to calculate the product of f(x) and g(x) for x=7
First, determine the product between both functions:
[tex](fg)=(x^2-9x)(3-x^2)[/tex]Multiply each term of the first parentheses with each term of the second parentheses:
[tex]\begin{gathered} (fg)=x^2\cdot3+x^2\cdot(-x^2)-9x\cdot3-9x\cdot(-x^2) \\ (fg)=3x^2-x^4-27x+9x^3 \\ (fg)=-x^4+9x^3+3x^2-27x \end{gathered}[/tex]Substitute with x=7 and solve:
[tex]\begin{gathered} (fg)(7)=-(7^4)+9\cdot(7^3)+3\cdot(7^2)-27\cdot7 \\ (fg)(7)=-2401+9\cdot343+3\cdot49-189 \\ (fg)(7)=-2401+3087+147-189 \\ (fg)(7)=644 \end{gathered}[/tex]The result is (fg)(7)=644
4) (f/g)(7) First, divide both functions:
[tex](\frac{f}{g})=\frac{x^2-9}{3-x^2}[/tex][tex]\begin{gathered} (\frac{f}{g})=\frac{(x-9)x}{3-x^2} \\ (\frac{f}{g})=\frac{(-1)(x-9)x}{(-1)(3-x^2)} \\ (\frac{f}{g})=\frac{(-x+9)x}{(-3+x^2)} \\ (\frac{f}{g})=\frac{(9-x)x}{(x^2-3)} \\ (\frac{f}{g})=\frac{9x-x^2}{x^2-3} \end{gathered}[/tex]Substitute with x=7 and solve:
[tex]\begin{gathered} (\frac{f}{g})(7)=\frac{9\cdot7-7^2}{7^2-3} \\ (\frac{f}{g})(7)=\frac{63-49}{49-3} \\ (\frac{f}{g})(7)=\frac{14}{46} \\ (\frac{f}{g})(7)=\frac{7}{23} \end{gathered}[/tex]The result is (f/g)(7)= 7/23
Related Questions
using the values from the graph, compute the values for the terms given in the problem. Choose the correct answer. Age of car = 4 years Original cost = 13,850 The current market value is $ _
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The current market value is $9086.98
In this problem, supposing a decay of 10% a year, and the original value of $13,850, the parameters are A(0) = 13850, r = 0.1.
Using exponential decay formula, the value of the car in 4 years is given by:
A(t) = A(0)(1 - r)^t
A(4) = 13850(1 - 0.1)^4
A(4) = 13850 * (0.9)^4
A(4) = 9086.98
Therefore, The current market value is $9086.98
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Suppose there is a simple index of three stocks, stock X, stock Y, and stock Z. Stock X opens the day with 5000 shares at $4.10 per share. Stock Y opens the day with 2000 shares at $4.50 per share. Stock Z opens the day with 4000 shares at $3.60 per share. The simple index rises 3.4% over the course of the day. What is the value of the index at the end of the day? Round your answer the nearest hundred. A. $45,100 B. $43,900 C. $45,400 D. $44,800
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Solution:
Step 1:
Calculate the total value of stock X
[tex]\begin{gathered} =5000\times\text{ \$}4.10 \\ =\text{ \$}20,500 \end{gathered}[/tex]Step 2:
Calculate the total value for Stock Y
[tex]\begin{gathered} =2000\times4.5 \\ =\text{ \$}9000 \end{gathered}[/tex]Step 3:
Calculate the total value for stock Z
[tex]\begin{gathered} =4000\times\text{ \$}3.60 \\ =\text{ \$}14,400 \end{gathered}[/tex]Step 4:
Calculate the total value of the shares but without the increase yet
[tex]\begin{gathered} 20,500+9000+14,400 \\ =\text{ \$}43,900 \end{gathered}[/tex]Step 5:
Calculate the increase in the simple index
[tex]\begin{gathered} =\frac{3.4}{100}\times43900 \\ =\text{ \$}1,492.60 \end{gathered}[/tex]Step 6:
Add the increase in the simple index to the total value of the shares
[tex]\begin{gathered} 43,900+1,492.60 \\ =\text{ \$}45,392.60 \\ \approx\text{ \$}45,400 \end{gathered}[/tex]Hence,
The final answer is
[tex]\Rightarrow\text{\$}45,400[/tex]OPTION C is the right answer
Answer:
45,400
Step-by-step explanation:
just took test AP3
The polynomial P(x) = 5x^3 + 2x^2- 42 has ___ local maxima and minima
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SOLUTION:
Case: Local maxima and local minima
Given:
[tex]P(x)=5x^3+2x^2-42^{}[/tex]Required: To find the local maxima and minima
Method:
[tex]\begin{gathered} P(x)=5x^3+2x^2-42^{} \\ \text{ } \end{gathered}[/tex]First the find the first derivative:
[tex]\begin{gathered} P^{\prime}(x)=15x^2+4x \\ we\text{ make P'(x) = 0} \\ 15x^2+4x=\text{ 0} \\ x(15x+4)=0_{} \\ x=0\text{ or 15x+4 =0} \\ x=\text{ 0 or x= }\frac{-4}{15} \end{gathered}[/tex]Let us take the points in the immediate neighbourhood of x = 0. The points are {-1, 1}.
[tex]\begin{gathered} \text{when x=-1} \\ P^{\prime}(x)=15x^2+4x \\ P^{\prime}(-1)=15(-1)^2+4(-1) \\ P^{\prime}(-1)=15(1)^2-4 \\ P^{\prime}(-1)=15^{}-4 \\ P^{\prime}(-1)=11 \\ \text{when x= 1} \\ P^{\prime}(x)=15x^2+4x \\ P^{\prime}(1)=15(1)^2+4(1) \\ P^{\prime}(1)=15^{}+4 \\ P^{\prime}(1)=19 \end{gathered}[/tex]Let us take the points in the immediate neighbourhood of x = -4/15. The points are {-1, 0}
[tex]\begin{gathered} \text{when x= 0} \\ P^{\prime}(x)=15x^2+4x \\ P^{\prime}(0)=15(0)^2+4(0) \\ P^{\prime}(0)=0^{}+0 \\ P^{\prime}(0)=0^{} \end{gathered}[/tex]Final answer:
The local minima is at x= 0 while the local maxima is at x= -4/15
Can you please help and Copy the pictures and put the answers
Answers
x = -1/2, y = -6
x = 0, y = -3
x = 1/2, y = -2
x = 1, y = -3
x = 3/2, y = -6
Explanation:We trace each point on the x-axis to the corresponding point on the y-axis to have the following
x = -1/2, y = -6
x = 0, y = -3
x = 1/2, y = -2
x = 1, y = -3
x = 3/2, y = -6
"A quadrilateral is a square if and only if it has fourright angles."Which of the following terms provides acounterexample for why the biconditional statement is
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Given statement: A quadrilateral is a square if and only if it has four right angles
Counterexample: A quadrilateral with four right angles can be also a rectangle. Then, not all quadrilaterals with four right angles are squares.
Answer: Rectangle
use the information given to answer the question.consider the textbook and its mathematical label.part Awhich statement is true?the answer questions is in the image
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Solution:
Given the textbook and its mathematics label as shown below:
From the above shape of the book and label, the textbook takes the shape of a rectangular prism, while its label is rectangular in shape.
Thus, the textbook is best represented by a rectangular prism, while the label is best represented by a rectangle.
The third option is the correct answer.
The length of a rectangle is 97 m and the width is 14 m find the area give your answer without units
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The area of the rectangle is 1358
Explanation:length of the rectangle = 97m
width of the rectangle = 14m
Area of a rectangle = length × width
[tex]\begin{gathered} \text{Area = 97m }\times\text{ 14m} \\ Area\text{ }of\text{ the rectangle = }1358m^2 \end{gathered}[/tex]The area of the rectangle is 1358 (without units)
whstbis the area in square inches of the shaded part of the retangle below
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The shaded area is trapezium with parallel sides as a = 10, b = 5 and height of trapezium is h = 18 in.
The formula for the area of trapezium is,
[tex]A=\frac{1}{2}\cdot(a+b)\cdot h[/tex]Determine the area of the tapezium.
[tex]\begin{gathered} A=\frac{1}{2}\cdot(10+5)\cdot18 \\ =15\cdot9 \\ =135 \end{gathered}[/tex]So area of shaded region is 135 square inch.
Find the shape, or rate of change, from the following table?
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ANSWER
C. -6
EXPLANATION
The rate of change is the change in the dependent variable when the independent variable changes 1 unit. In this case, all columns in the table have a change in the x variable of 1, so the difference between each column in the y-row is the rate of change,
[tex]m=-9-(-3)=-15-(-9)=-21-(-15)=-6[/tex]Hence, the rate of change is -6.
Commercial agents earn 5% of the cost of each product they sell. If an agent earsn $2000 for selling a product, what was the cost of the product?
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Answer: 40,000
Step-by-step explanation: 5 (the earnings) times twenty is 100 (the total cost) and if we substitute 5 for 2000, the total is 40,000.
Answer: 40,000
Step-by-step explanation:
just because
it take Sarah to 1/2 AJ to make a birdhouse how much of the birdhouse will be built after 2/5 day choose the model that correctly illustrates the problem 2/5 ÷ 1/2
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After 2/5 days Sarah can build 4/5 of a birdhouse.
It is given that Sarah can build birdhouses at the rate of 1/2 day per birdhouse.
Now let us use unitary method to calculate the number of birdhouses she can make in the given amount of time in a day.
Sarah takes 1/2 day to make 1 birdhouse
Sarah takes 1 day to make 1 ÷(1/2) birdhouse
Sarah takes 2/5 day to make 1÷ 1/2 × 2/5 birdhouse
Hence Sarah will make
= 1 ÷ 1/2 × 2/5
= 4/5 birdhouse
The unitary approach is a technique for solving problems that requires first figuring out how much one unit costs, then multiplying that amount to get the answer.
Therefore Sarah will take 2/5 days to make 4/5 of a birdhouse.
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A business person invests $3,367 at 5% compounded semiannually for two years. What is the future value of the investment, and how much interest will they earn over the two-year period?
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The future value of the investment will be $3712.1 and they will earn interest of $345.1 over the two-year period.
Given that business person invests $3,367 at 5% compounded semiannually for two years.
p = $3,367
r = 5%
t = 2 years
A = P(1+r/100)ⁿ
Substitute the values of p,r, and t in the formula,
A = 3,367(1 + 5/100)²
A = 3,367(1 + 0.05)²
A = 4.700 (1.05)²
A = 3712.1175
Rounded to the nearest cent
A = $3712.1
Total interest = A - p = 3712.1 - 3,367 = $345.1
Therefore, the future value of the investment will be $3712.1 and they will earn interest of $345.1 over the two-year period.
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A teacher receivesa monthly salary of $2800.00 What isheraunnual salary?
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The year has 12 months, since the teacher receives a monthly salary of $2800, then his annual salary is:
[tex]2800\times12=33600[/tex]Answer:
$33600
Yolanda is riding in a bike race that goes through a valley and a nearby mountain range,The table gives the altitude (in feet above sea level) for the five checkpoints in the race,Use the table to answer the questions,CheckpointAltitude(feet above sea level)12,2242- 13731,5714-305218(8) How much lower is Checkpoints than check out 2909 i lower
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Step 1
Write the given checkpoint altitude
Checkpoint 1 = 2224
Checkpoint 2 = -137
Checkpoint 3 = 1571
Checkpoint 4 = -39
Checkpoint 5 = -218
Step 2:
a) How much lower is checkpoint 5 than checkpoint 2
You will subtract checkpoint 5 altitude from checkpoint 2
[tex]\begin{gathered} =\text{ -137 - (-218)} \\ =\text{ -137 + 218} \\ =\text{ 81 f}eet \end{gathered}[/tex]b) Altitude of the top hill that is 365 above checkpoint 5.
[tex]\begin{gathered} \text{Altitude of the top hill = 365 - 218 } \\ \text{Altitude of the top hill 365 above checkpoint 5 = 147} \end{gathered}[/tex]Find the values of A, B, and C in the table.Intervalfa) for a in Relation ofinterval fa) to x-axis(0, 1)f(-2)= -12below(-1, A)f(0)=Babove(A, 2)f (1.5) -0.6(2,)f(3) = 8above
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From the first line of the table, it shows
[tex]f(-2)=-12[/tex]This means that
when x = -2, y = -12,
so
[tex]a=-2[/tex]Now,
A fuelling vehicle finished filling a plane with 12.40 tons of fuelat 10:35. If the fuelling rate is 0.20 ton of fuel per min, at whattime did the fuelling start? Give your answer in a 12-hour clockformat, such as 9:00.9:33xHmm, that wasn't the right answer. Let's give it one more try.
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4 numbers that are divisible by both 2 and 9
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A Number to be divisible by 2, the last digit must be even.
divisible by 9 = sum of the digits must be divisible by 9:
So, 4 numbers:
18,36,54,72
Drag each tile to the correct box.Arrange the functions in ascending order, starting with the function that eventually has the least value and ending with the function thateventually has the greatest value.3x + 8+4+3x² + 63x4*
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To answer the question we are going to graph the functions given:
From the graph we notice that the order will be:
[tex]\begin{gathered} 3x \\ 3x+8 \\ x^2 \\ x^2+6 \\ 4^x \\ 4^x+3 \end{gathered}[/tex]What is the measure of ZBDC?What is the measure of arc length BC?
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SOLUTION
Step 1:
To find the measure of
Step 2:
The angle subtended by an arc at the centre is twice the angle subtended at the circumference. More simply, the angle at the centre is double the angle at the circumference.
Step 3:
Dividing both sides by 2, we have;
[tex]\begin{gathered} <\text{BDC = }\frac{BOC}{2}\text{ = }\frac{138}{2} \\ \\Step 4:
We are to find the measure of arc length BC;
Angle BOC is given as 138
[tex]\begin{gathered} \frac{\theta}{360}\text{ x 2 }\pi\text{ r} \\ \\ \frac{138}{360}\text{ x 2 x 3.14 x r } \\ \\ 2.407r \end{gathered}[/tex]Note: Since the value of the radius was not given so we need to express our answer in term of r.
The measure of arc length BC is 2.407r, where r is the radius.
the table shows the number of hours worked and the total amount that each of the four people earned one weekendwhose pay rate was the best whose pay rate was the worst Based on the chart.
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pay rate = money earned/hours worked
Gary's pay rate: $37/4 = $9.25 per hour
Tara's pay rate: $54.9/6 = $9.15 per hour
Lamont's pay rate: $27.6/3 = $9.2 per hour
Darius' pay rate: $46.5/5 = $9.3 per hour
best pay rate: Darius
worst pay rate: Tara
[tex]y = 3(x + 3)(x + 1)[/tex]Intercept form find the vertex
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Answer:
(-2, -3)
Explanation:
If we have an equation with the form:
f(x) = ax² + bx + c
The vertex of the parabola is the point (-b/2a, f(-b,2a)).
So, to find the vertex, we need to write the equation y = 3(x + 3)(x + 1) as:
[tex]\begin{gathered} y=3(x+3)(x+1) \\ y=3(x^2+3x+x+3) \\ y=3(x^2+4x+3) \\ y=3x^2+12x+9 \end{gathered}[/tex]Then, the value of a is 3 and the value of b is 12. It means that -b/2a is equal to:
[tex]-\frac{b}{2a}=-\frac{12}{2(3)}=-\frac{12}{6}=-2[/tex]And f(-b/2a) = f(-2) is equal to:
[tex]\begin{gathered} y=3x^2+12x+9 \\ f(-2)=3(-2)^2+12(-2)+9 \\ f(-2)=3(4)-24+9 \\ f(-2)=12-24+9 \\ f(-2)=-3 \end{gathered}[/tex]Therefore, the vertex is the point (-2, -3)
Factor out the greatest common factor. Simplify the factors, if possible.6x4 - 42x3 + 12x2Select the correct choice below and fill in any answer boxes in your choice.O A. 6x4 - 42x3 + 12x2 =(Type your answer in factored form.)OB. There is no common factor other than 1.ih
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You have to find the greatest common factor first.
To do so, do as follows:
[tex]6x^4-42x^3+12x^2[/tex]Factors of 6 are: 1, 2, 3, 6
Factors of 12 are: 1, 2, 3, 4, 6, 12
Factors of 42 are: 1, 2, 3, 6, 7, 14, 21, 42
The greates common factor is the greatest common factor shared by all values, in this case is 6
Now to factor it out you have to divide each term of the equation by it.
[tex](\frac{6x^4}{6})=x^4[/tex][tex](\frac{42x^3}{6})=7x^3[/tex][tex](\frac{12x^2}{6})=2x^2[/tex]The expression with the GCF factorized is then:
[tex]6(x^4-7x^3+2x^2)[/tex]Ever NL OP N 2 PN, and is the midst of MO. PALUN APON STATEMENTS REASONS: 2. Nisthe MO 1. Gren Given the following proof, what is the 5th reason? 2 MZ - OP 2. Given 3. IN EN 3. Given 2 MIN ON 4. Definition of midpoint 5 5. ALMN 2 APON SAS CPCTC SSS ASA
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In this case, we have to use the SSS Postulate for the congruency of the triangles, that is, if three sides of a triangle are congruent to three sides of another triangle, then the triangles are congruent.
We have that all reasons are given congruent sides. The midpoint divides the segment into two equal parts, then the angles are congruent because of the reason: SSS ( SSS Postulate for congruency of triangles).
Answer To this question so that we can move on to the next question so we can get all this homework done
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y^(3)-27=9y^(2)-27y. could you please show steps
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The solution to the algebraic expression is y =3
Algebraic expressionThis algebraic expression contain variable and constant along with unknow variables.
y^(3)-27=9y^(2)-27y
Add 27y to both sides
y^(3)-27 +27y =9y^(2)-27y +27y
Simplify
y^3-27 +27y =9y^2
Subtract 9y^2 from both sides
y^3-27 +27y-9y^2 =9y^2- 9y^2
y^3-27 +27y-9y^2= 0
Simplify
y^3 - 9y^2 + 27y - 27 =0
Factor by grouping y^3 - 9y^2 + 27y - 27 ; (y-3)^3
(y -3) (-y^2 + 6y -9) = 0
(y-3)^3 =0
Using the zero factor principle if ab = then a = 0 or b= 0
y-3= 0
Add 3 to both sides
y =3
Therefore, solution to the algebraic expression is y =3
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Hero and Lisa are photographers they take pictures of seniors for high school yearbooks they charge a standard fee for taking the pictures there’s also a charge for each set of prints ordered so the number sets of prints determine the total cost S stand for the sets of prints ordered right the rule that describes the students total cost
Answers
Given:
We get the points (0,30), (1,31),(2,32), and (3,33) from the table.
Required:
We need to find the total cost.
Explanation:
From the point(0,30).
There is an initial cost of $30 for print.
Let s be the number of sets of prints ordered.
Let k be the additional cost for each number of sets of print
The equation of the given model is
[tex]Total\text{ cost =ks+30}[/tex]Consider the point (1,31).
Substitute total cost =31 and s=1 in the equation.
[tex]31\text{=k\lparen1\rparen+30}[/tex][tex]31\text{=k+30}[/tex]Subtract 30 from both sides.
[tex]31-30\text{=k+30-30}[/tex][tex]1\text{=k}[/tex]Substitute k =1 in the equation.
[tex]Total\text{ cost =s+30}[/tex]Consider the point (2,32).
Substitute total cost =32 and s =2 in the equation.
[tex]32\text{ =2+30}[/tex]It is true, so the equation satisfies the values in the table,
Final answer:
[tex]Total\text{ cost =s+30}[/tex]2. The sum of the perimeters of similar quadrilaterals is 22.5 dm. Find the perimeters of the quadrilaterals if the similarity coefficient k = 1.25.
Answers
Given:
The sum of the perimeters of similar quadrilaterals is 22.5 dm. The similarity coefficient k = 1.25.
Required:
To find the perimeters of the quadrilaterals.
Explanation:
The quadrilaterals are similar and the similarity coefficient is k = 1.25.
If the quadrilateral is similar then the ratio of their corresponding sides is equal.
Let the perimeter of the one quadrilateral is x then the perimeter of the other quadrilateral will be 1.25x
Now
[tex]\begin{gathered} x+1.25x=22.5 \\ x(1+1.25)=22.5 \\ 2.25x=22.5 \\ x=\frac{22.5}{2.25} \\ x=10 \end{gathered}[/tex]Thus the perimeter of the one quadrilateral is 10dm.
The perimeter of the other quadrilateral = 1.25 x 10 = 12.5 dm
Final Answer:
Thus the perimeter of the quadrilaterals is 10dm and 12.5 dm.
The sum of the ages of Darius and Brooke is 78 years. 7 years ago, Darius's age was 3 timesBrooke's age. How old is Darius now?
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The sum of the ages of Darius and Brooke is 78 years. 7 years ago, Darius's age was 3 times
Brooke's age. How old is Darius now?
Let
x ------> darius's age
y -----> Brooke's age
we know that
x+y=78 ------> equation A
(x-7)=3(y-7) -----> equation B
solve the sytem of equations
isolate the variable x in the equation A
x=78-y -------> equation C
substitute equation C in equation B
78-y-7=3(y-7)
slve for y
71-y=3y-21
3y+y=71+21
4y=92
y=23
Find the value of x
x=78-y
x=78-23=55
therefore
Darius now is 55 year old
What is the value of x in the triangle?a right triangle with a short leg of length x and hypotenuse of length 3 times the square root of 2A. B. C. D. E.
Answers
Solution:
Given the right triangle below:
To solve for x, we use the trigonometric ratio.
In the above triangle, the angles at A and B are equal.
Thus, we have
[tex]\begin{gathered} \angle A+\angle B+\angle C=180(su\text{m of angles in a triangle\rparen} \\ \angle A=\angle B \\ thus, \\ 2\angle\text{B+90=180} \\ \Rightarrow2\angle\text{B=180-90} \\ 2\angle\text{B=90} \\ \Rightarrow\angle\text{B=45} \end{gathered}[/tex]From trigonometric ratio,
[tex]\sin\theta\text{=}\frac{opposite}{hypotenuse}[/tex]In this case, θ is the angle at B, which is 45; opposite is AC, and hypotenuse is AB.
Thus,
[tex]\begin{gathered} \sin45=\frac{x}{3\sqrt{2}} \\ \Rightarrow x=3\sqrt{2}\times\sin45 \\ =3\sqrt{2}\times\frac{1}{\sqrt{2}} \\ =3 \end{gathered}[/tex]Hence, the value of x is
[tex]3[/tex]The correct option is B
What would be the equation for this line? 80 60 40 20 time in minutes 2 3 4 5 6 7 8 9 X distance in miles
Answers
the equation of the line is given as follows,
first we take points on this line
A(2,20)
and
B (4,40)
so, the equation of the line is,
[tex]y-20=\frac{40-20}{4-2}(x-2)[/tex][tex]\begin{gathered} y-20=\frac{20}{2}(x-2) \\ y-20=10x-20 \\ y=10x \end{gathered}[/tex]thus, the equation of the line is
y = 10x