Answer:
5 miles
Explanation:
First, we need to transform the mixed number into decimal numbers using as follows:
[tex]\begin{gathered} 4\frac{1}{2}=4+\frac{1}{2}=4+0.5=4.5\text{ miles} \\ 2\frac{1}{4}=2+\frac{1}{4}=2+0.25=2.25\text{ hours} \\ 2\frac{1}{2}=2+\frac{1}{2}=2+0.5=2.5\text{ hours} \end{gathered}[/tex]Now, the average rate was the same, so the ratio of the miles to the hours is always the same. Therefore, we can write the following equation:
[tex]\frac{\text{Miles}}{\text{Hours}}=\frac{4.5\text{ Miles}}{2.25\text{ Hours}}=\frac{x}{2.5\text{ Hours}}[/tex]Where x is the number of miles that Lebron walked on the return trip. So, solving for x, we get:
[tex]\begin{gathered} \frac{4.5}{2.25}=\frac{x}{2.5} \\ \frac{4.5}{2.25}\times2.5=\frac{x}{2.5}\times2.5 \\ 5=x \end{gathered}[/tex]Therefore, Lebron walked 5 miles on the return trip.
Match the steps to put them in the correct order of something. You will not use all of the options.
SOLUTION
[tex]\begin{gathered} Given \\ 2h+9=21 \end{gathered}[/tex][tex]\begin{gathered} Step\text{ 1:} \\ Subtract\text{ 9 from both sides} \\ 2h+9-9=21-9 \\ 2h=12 \end{gathered}[/tex][tex]\begin{gathered} Step\text{ }2: \\ Divide\text{ both sides by 2} \\ \frac{2h}{2}=\frac{12}{2} \\ h=6 \end{gathered}[/tex][tex]\begin{gathered} Final\text{ answer:} \\ h=6 \end{gathered}[/tex]A local health clinic surveys its patients about their water drinking habits it found data is normally distributed the mean amount of water consumed daily is 62 ounces and the standard deviation is 5.2how much water in ounces do approximately 95% of the patients drink each day
The approximate amount of water consumed by 95% of the patients will be given as a range which can be gotten by
[tex]P=x\pm2S[/tex]Where
P = Amount of water.
x = mean
S = Standard Deviation
Therefore,
The lower limit is
[tex]\begin{gathered} x-2s \\ =62-2(5.2) \\ =62-10.4 \\ =51.6\text{ ounces} \end{gathered}[/tex]The upper limit is
[tex]\begin{gathered} x+2s \\ =62+2(5.2) \\ =62+10.4 \\ =72.4\text{ ounces} \end{gathered}[/tex]Therefore, the amount of water that 95% of the patients drink approximately is 51.6 ounces to 72.4 ounces.
Simplify this expression. Assume that x is nonzero.– 11.7X<-11.x?(Type exponential notation with positive exponents.)
If two numbers have the same base ( the number below the exponent) then the multiplication of the two of them is the number with the same base but with the sum of its exponents (rule of exponents)
[tex]x^{-11}\cdot x^7=x^{-11+7}=x^{-4}[/tex]On the other hand, if a number is to the power a negative number, it means that it is the reciprocal elevated to the number, in this case
[tex]x^{-4}=(\frac{1}{x})^4[/tex]What point is a solution to the linear inequality y > 4x -3?
Answer:
(0,-3 )and (0.75,0)
Step-by-step explanation:
y=4x_3
60% of the
students take the
bus. If there were
120 students on the
busses, how many
total students are
there?
Answer:
168
Step-by-step explanation:
60%=120
40% of 120
10%12
10%12
10%12
10%12
12×4=48
120+48=168
Enter in the coordinates for each point in the graph below.Quezon 2Not yetansweredPoints out of16.00H.c.5FlagquestionE.5-1990GD
ANSWER:
A. (-7,2)
B (-5, -2)
C (-3, 5)
D (-2, -7)
E (2, 3)
F (3,3)
G (5,-6)
H (6, 6)
The sum of two numbers is 20. The difference between three times the first rumber and twice the second is 40. Find the two numbers.
Let the first number is x and second number is y.
According to given conditions:
The sum of two numbers is 20.
[tex]x+y=20[/tex]And The difference between three times the first rumber and twice the second is 40.
[tex]3x-2y=40[/tex]Now multiply equation 1 with 2 and add in second eqution;
[tex]\begin{gathered} 2(x+y)+(3x-2y)=2(20)+40 \\ 2x+2y+3x-2y=40+40 \\ 5x=80 \\ x=16 \end{gathered}[/tex]Now put the value of x in equation 1:
[tex]\begin{gathered} 16+y=20 \\ y=4 \end{gathered}[/tex]So the first number is x=16 and second number is y=4.
According to given co
Use the properties of exponents to simplify. Express all answers using positive exponents.each)35x10 over 5x^5
Consider the given expression,
[tex]\frac{35x^{10}}{5x^5}[/tex]Consider the property,
[tex]\frac{x^m}{x^n}=x^{m-n}[/tex]Then the given expression can be simplified as follows,
[tex]\begin{gathered} \frac{35x^{10}}{5x^5} \\ =\frac{35}{5}\times\frac{x^{10}}{x^5} \\ =7\times x^{10-5} \\ =7\times x^5 \\ =7x^5 \end{gathered}[/tex]Thus, the given expression is simplified as,
[tex]\frac{35x^{10}}{5x^5}=7x^5[/tex]You invested $28,000 in two accounts paying 7% and 9% annual interest, respectively. If the total interest earned for the year was $2180, how much was invested at each rate?
We are given the following information:
total of $28,000 invested in 2 accounts
7% and 9% interest rates for each account
total interest was $2,180
We are asked to calculate the amount invested at each rate.
To do this, let us first identify our variable and what it stands for. Let us use the variable x to represent the amount invest at 7%. That leaves us t
What is the minimum? Where is the function increasing? Where is the function decreasing?
As given by the question
There are given that the graph.
Now,
The minimum value of the given graph is shown below:
[tex](2,\text{ -1)}[/tex]What is the remainder when j(x)=x4+2x3−5x2+2x+4 is divided by x+3
From the problem, we have a function :
[tex]j(x)=x^4+2x^3-5x^2+2x+4[/tex]The remainder when j(x) is divided by x + 3 is the value of the function when x = -3
x = -3 comes from :
x + 3 = 0
x = -3
Substitute x = -3 to the function,
[tex]\begin{gathered} j(-3)=(-3)^4+2(-3)^3-5(-3)^2+2(-3)+4 \\ j(-3)=81-54-45-6+4 \\ j(-3)=-20 \end{gathered}[/tex]The answer is -20
Write an Equation: Gary worked for 20 hours tutoring students at the library. He uses $35 to pay for gas on his way home. If he has $60 left after paying for gas, how much money, x, in dollars, was Gary paid per hour?
Answer:4.75 in us dollars it will be 5.31
Step-by-step explanation:
first you divide 95 by 20 witch will give you 4.75 and if you want to check that answer you do 4.75 times 20 and it will give 95
Jada and Priya are trying to solve the equation 2/3 + x = 4 Jada says I think we should multiply each side by 3/2 because that is the reciprocal of 2/3 Priya since I think we should add -2/3 to each side because that is the opposite of 2/3
The equation they are trying to solve is
[tex]\frac{2}{3}+x=4[/tex]In order to solve this equation, they need to add -2/3 on each side (the opposite of 2/3).
[tex]\begin{gathered} \frac{2}{3}-\frac{2}{3}+x=4-\frac{2}{3} \\ x=4-\frac{2}{3} \end{gathered}[/tex]Hence, Priya is correct because they need to use the opposite of 2/3, not the reciprocal.
An equation that can be solved using Jada's strategy is
[tex]\frac{2}{3}x=4[/tex]This equation would need to use a reciprocal, as Jada said.
What is the greatest common factor of 48x^2?and 32x^3?A. 16x^2B. 96x^3C. 8x^2D. 16x
greatest common factor (GCF) of 2 algebraic terms is the largest monomial that evenly divides the two expressions.
We have
[tex]\begin{gathered} 48x^2 \\ \text{and} \\ 32x^3 \end{gathered}[/tex]There are two parts, the numbers and variables.
From the numbers, the largest number we can divide 48 and 32 by is:
16
From the variables, the largest factor is x^2
Putting them together, we can say the GCF is:
[tex]16x^2[/tex]Correct Answer: A
X= 7 4. Find the equation of a line passing through (5, -6) perpendicular (b) 3x + 5y = (d) 7x - 12y (f) x = 7 (a) 2x + y = 12 (c) x + 3y = 8 (e) 2y = 5 Find the equation of the line connecting the points of intersect (a) S x + y = 4 S 3x - y = 12 (b) Sy= and 2x=6 = -6 X=
Given data:
The first set of equations are x+y=4, and x=6.
The second set of equations are 3x-y=12 and y=-6.
The point of intersection of first set of te equations is,
6+y=4
y=-2
The first point is (6, -2).
The point of intersection of second set of te equations is,
3x-(-6)=12
3x+6=12
3x=6
x=2
The second point is (2, -6).
The equation of the line passing through (6, -2) and (2, -6) is,
[tex]\begin{gathered} y-(-2)=\frac{-6-(-2)}{2-6}(x-6) \\ y+2=\frac{-6+2}{-4}(x-6) \\ y+2=x-6 \\ y=x-8 \end{gathered}[/tex]Thus, the required equation of the line is y=x-8.
what digit is in the
The number given in the statement is
2.113 pints.
To write in word form,
Two and one hundred thirteen thousandths.
As in the number from last we have thousand , hundred, tens and ones.
So, we can write the given number in word form.
Two and one hundred thirteen thousandths.
Hence the correct option is c.
Lisa's rectangular living room is 20 feet wide. If the length is 5 feet less than twice the width, what is the area of her living room?
1) Let's gather all the data
Width: 20'
Length: 2w-5
2) Now we can plug that into the formula for the are of a rectangle, like this
[tex]\begin{gathered} A=wl \\ A=20\cdot(2(20)-5) \\ A=20\cdot(40-5) \\ A=20\cdot35 \\ A=700ft^2 \end{gathered}[/tex]Notice that we have plugged into that the width w=20. Therefore the area of the living room is 700ft²
true or false18. In the circle: x^2+(y-2)^2=12, the radius is 12
The general equation of a circle is:
[tex](x-h)^2+(y-k)^2=r^2[/tex]where (h,k) is the center and r is the radius of the circle.
Comparing the given equation of a circle and the above general equation we get:
[tex]r^2=12[/tex]Then, the radius of this circle is:
[tex]r=\sqrt[]{12}[/tex]In conclusion, the sentence is false.
Solve the system by graphing. (If there is no solution, enter NO SOLUTION.)x + 2y < 6y < x − 5
From the problem, we have the inequalities :
[tex]\begin{gathered} x+2y<6 \\ yNote that the boundary line is dashed if the symbols are < or >.Let's graph first the first inequality :
[tex]\begin{gathered} x+2y<6 \\ \text{Change the symbol into ''=''} \\ x+2y=6 \\ \text{Solve for the intercepts} \\ \text{when x = 0} \\ 0+2y=6 \\ y=\frac{6}{2}=3 \\ \\ \text{when y = 0} \\ x+2(0)=6 \\ x=6 \end{gathered}[/tex]Plot the points (0, 3) and (6, 0)
The region will pass through the origin if (0, 0) satisfies the inequality.
Test for (0, 0)
[tex]\begin{gathered} x+2y<6\text{ } \\ 0+0<6 \\ 0<6 \\ \text{TRUE!} \end{gathered}[/tex]Since it is true, the region will pass through the origin.
The graph will be :
Next is to graph the second inequality :
[tex]\begin{gathered} yPlot the points (0, -5) and (5, 0)Check again origin (0, 0) to the inequality :
[tex]\begin{gathered} ySince it is false, the region will not pass through the origin.Tha graph will be :
The solution to the system is the overlapping region between the two inequalities.
1) P(A) = 0.6 P(B) = 0.45 P(A and B) = ? O 0.35 0.65 O 0.75 O 0.27
We are given the following probabilities:
[tex]\begin{gathered} P(A)=0.6 \\ P(B)=0.45 \end{gathered}[/tex]We are to find P(A and B), to do that we will use the following relationship:
[tex]P(\text{AandB)=P(A) x P(B)}[/tex]Replacing we get:
[tex]P(AandB)=0.6\times0.45[/tex]Solving the operations:
[tex]P(\text{AandB)}=0.27[/tex]Therefore, the probability of A and B is 0.27.
c. If x= 3 is specifically a hole (removable discontinuity) of f(x), then what would be true about g(3) and h(3)? Explain your reasoning.
Solution
We have the following function given:
f(x)= g(x)/h(x)
We have a point of discontinuity on x=3
c. If x= 3 is specifically a hole (removable discontinuity) of f(x), then what would be true about g(3) and h(3)? Explain your reasoning.
For this case we can conclude that g(3)/h(3) is not defined since f(3) is not defined for the function and that means that the function is not fully connected on x=3
Find the inverse of the function. g(x)= -5x – 20/7
Given the function:
[tex]g(x)=\frac{-5x-20}{7}[/tex]To find the inverse function, let us first write it as:
[tex]y=\frac{-5x-20}{7}[/tex]Make x the subject of the equation
[tex]\begin{gathered} -5x-20=7y \\ -5x=7y+20 \\ x=\frac{-7y-20}{5} \end{gathered}[/tex]Replace x by y, and y by x to obtain the inverse function
[tex]y=\frac{-7x-20}{5}[/tex]Where
[tex]y=g^{-1}(x)[/tex]Solve the equation for A: 2*Cos A + 2 = 3.
Answer:
A=60 degrees
Explanation:
Given the equation:
[tex]2\cos A+2=3[/tex]Subtract 2 from both sides of the equation.
[tex]\begin{gathered} 2\cos A+2-2=3-2 \\ 2\cos A=1 \end{gathered}[/tex]Divide both sides by 2:
[tex]\begin{gathered} \frac{2\cos A}{2}=\frac{1}{2} \\ \cos A=\frac{1}{2} \end{gathered}[/tex]Finally, solve for A.
[tex]\begin{gathered} A=\arccos (\frac{1}{2}) \\ A=60\degree \end{gathered}[/tex]Which expression is equivalent to 1-51 +131? —8 ООО O2 o 8
Theg given expression : |-5|+|3|
Since modulus is express as |-a|=a and |a|=a
[tex]undefined[/tex]explain how you solve a quadratic equation. How many answers do you expect to get for a quadratic equation?
1. There are several ways to solve (Quadratic Formula, Graphing, Newton's Identities, Factoring) the most common is using the Quadratic Formula.
2. We can always expect two roots, either identical or different.
1) There are some ways to solve a quadratic equation. We can solve it using the Quadratic Formula, Graphing it or via Newton's Identities, or even factoring
The most common way is via Quadratic Formula:
[tex]\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \end{gathered}[/tex]Which a, b, and c are the coefficients of a Quadratic Equation, say:
x²+6x+9, a= 1, b=6, and c=9.
[tex]x=\frac{-6\pm\sqrt[]{6^2-4(1)(9)}}{2(1)}=x_1=x_2=-3[/tex]Note that in this case, both roots were equal to -3
2) We can always expect two roots. When the Quadratic Formula yields just one answer then we can call it double root, or 1 root with multiplicity 2, actually there are two roots with the same value.
3) Thus the answer is:
1. There are several ways to solve (Quadratic Formula, Graphing, Newton's Identities, Factoring) the most common is using the Quadratic Formula.
2. We can always expect two roots, either identical or different.
What is the value of the expression below when z=7 and w=10
Given that z = 7 and w = 10 then the expression 7z + 10w
substituting the values of z and w into tye expression
= 7(7) + 10 (10)
= 49 + 100
= 149
Jake, Becky, and Max are meeting at Charley's Pizza for dinner and then plan to go
pizza place,
each one of them has a different coupbn. They decide to use the coupon that will give them the best deal. movie. When they arrive. the
Jake's coupon is $19.99 for a pizza and pasta meal deal, Becky's
of the menu price; and Max's coupon is for three mediun
coupon is for two large one topping pizas-each at ]
one-topping pizzas - each at -off the menu price. Accordling
to the menu, a medium one-topping pizza is $8.99, and
large one-topping pizza $14.89. They also spend $1.25
for sodas and $5.00 on the tip. At the movie theater. Max has › coupon that's good for ãoff a third movie ticket when
you purchase two other movie tickets at the regular price.
The regular price of each movie ticket is $9.80.
Although Jake, Becky, and Max plan to split the cost of the pizza and movie, they decide that with the coupons, it's just
easier if one of them pays at each place. So, the friends agree that Jake will pay for the pizza and Becky will pay for the
movies. At the end of the night, they'll figure out how much Max owes
both Jake and Becky.
After all costs
split evenly, how much will each person contribute?
between $14 and $15
• between $15 and $16
• between $16 and $17
O between $17 and $18
Answer:
$16 and $17
Step-by-step explanation:
a jacket at Rick's clothing store originally costs $27 the store is having a 45% off sale on all of its merchandise what is the sale price of the jacket
Let:
Op = Original price
Sp = Sale price
r = Discount
Express the discount percentage as a decimal:
45% = 45/100 = 0.45
The sale price will be given by:
[tex]\begin{gathered} Sp=Op-0.45Op \\ where \\ Op=27 \\ so\colon \\ Sp=27-12.5 \\ Sp=14.85 \end{gathered}[/tex]$14.85
Use substitution to solve each system of equations.y + 1/2x = 34y + 2x = 6
Answer:
No solution
Explanation:Given the system of eqations:
[tex]\begin{gathered} y+\frac{1}{2}x=3 \\ 4y+2x=6 \end{gathered}[/tex]From the second equation, find x.
[tex]\begin{gathered} 2x=6-4y \\ x=\frac{6-4y}{2} \\ =3-2y \end{gathered}[/tex]Substitute the obtained value of x into the first equation.
[tex]\begin{gathered} y+\frac{1}{2}(3-2y)=3 \\ y+\frac{3}{2}-y=3 \\ \frac{3}{2}=3 \end{gathered}[/tex]which isnotpossible. So, no solution exists.
directly as Vi and inversely as y°. If: = 61 when = 36 and y = 9, find a if r = 64 and y = 6. (Round off your answer to the nearest hundredth.)
Given: z directly varies as √x and inversely varies as y³
when x = 36 and y = 9 then z = 61
To find:
when x = 64 and y = 6 then z = ?
explanation:
z ∝ √x / y³
z = k √x / y³
when x = 36 and y = 9 then z = 61
[tex]z=\text{ }\frac{k\text{ }\sqrt{x}}{y^3}[/tex][tex]\begin{gathered} 61=\frac{k\text{ * }\sqrt{36}}{9^3} \\ 61=\frac{k*6}{729} \\ k=\frac{61*729}{6}=\frac{61*243}{2}=\frac{14823}{2} \end{gathered}[/tex]when x = 64 and y = 6
[tex]z=\text{ }\frac{14823}{2}*\frac{\sqrt{64}}{6^3}=\frac{14823*8}{2*216}=\frac{4941*4}{72}=\frac{4941}{18}=274.5[/tex]the value of z = 274.5
final answer:
z = 274.5 ≈ 300 when rounded off to the nearest hundredth