Julia rides her bike 14 miles in 2 hours. If she rides at a constant speed, select the answers below that are equivalent ratiosto the speed she rides. Select all ratios that are equivalent,

Julia Rides Her Bike 14 Miles In 2 Hours. If She Rides At A Constant Speed, Select The Answers Below

Answers

Answer 1

Divide the distance over the total time to find the distance Julia rides in one hour:

[tex]\frac{14\text{ miles}}{2\text{ hours}}=7\text{ miles per hour}[/tex]

Do the same for each option to find whether or not they represent the same speed:

A)

[tex]\frac{35\text{ miles}}{6\text{ hours}}=5.83\text{ miles per hour}[/tex]

B)

[tex]\frac{7\text{ miles}}{1\text{ hour}}=7\text{ miles per hour}[/tex]

C)

[tex]\frac{28\text{ miles}}{4\text{ hours}}=7\text{ miles per hour}[/tex]

D)

[tex]\frac{42\text{ miles}}{7\text{ hours}}=6\text{ miles per hour}[/tex]

Therefore, only options B and C represent the same ratio.


Related Questions

We start with triangle ABC and see that angle ZAB is an exterior angle created by the extension of side AC. Angles ZAB and CAB are a linear pair by definition. We know that m∠ZAB + m∠CAB = 180° by the . We also know m∠CAB + m∠ACB + m∠CBA = 180° because .

Answers

The first answer is: definition of complementary angles.

The second is: of the triangle sum theorem.

The third one is: substraction property

10.Find the approximated circumference of a circle whose area is 136.46

Answers

The area of a circle is given by the following formula:

[tex]A=\pi r^2[/tex]

Where r is the radius.

We know the area of the circle, then we can replace it in the formula and find r:

[tex]\begin{gathered} 136.46=\pi\cdot r^2 \\ r^2=\frac{136.46}{\pi} \\ r^2=43.44 \\ r=\sqrt[]{43.44} \\ r=6.59 \end{gathered}[/tex]

The circumference of a circle is given by the formula:

[tex]C=2\pi r[/tex]

By replacing the r-value that we found, we can solve for C:

[tex]\begin{gathered} C=2\cdot\pi\cdot6.59 \\ C=41.41 \end{gathered}[/tex]

The approximated circumference of the circle is 41.41

Given:• ABCD is a parallelogram.• DE=3z-3• EB=2+11• EC = 5x + 7What is the value of x?44.507

Answers

To answer this question, we need to recall that: "the diagonals of a parallelogram bisect each other"

Thus, we can say that:

[tex]DE=EB[/tex]

And since: DE = 3x - 3 , and EB = x + 11, we have tha:

[tex]\begin{gathered} DE=EB \\ \Rightarrow3x-3=x+11 \end{gathered}[/tex]

we now solve the above equation to find x, as follows:

[tex]\begin{gathered} \Rightarrow3x-3=x+11 \\ \Rightarrow3x-x=11+3 \\ \Rightarrow2x=14 \\ \Rightarrow x=\frac{14}{2}=7 \\ \Rightarrow x=7 \end{gathered}[/tex]

Therefore, the correct answer is: option D

I’m not sure how to solve it please help me!

Answers

ANSWER:

33.5%

STEP-BY-STEP EXPLANATION:

We have the amount in 2003 in 5799 fish and in 2014 there are there are 1943 less fish.

The percentage of change would be the difference in fish between these years divided by the initial amount of fish, just like this:

[tex]\begin{gathered} p=\frac{5799-(5799-1943)}{5799}\cdot100 \\ \\ p=\:\frac{1943}{5799}\cdot100\: \\ \\ p=33.505\cong33.5\% \end{gathered}[/tex]

This means that the percentage of change is negative since the population has decreased by 33.5%.

in the diagram below, line CD and BC intersect at a. Which of the following rigid motions could be used to show that

Answers

The only rigid motion that could be used to show that angle BAE is congruent to the angle DAC is D.

Because if we do the rotation of 180° clockwise about A we will obtain the same Figure.

This is the original figure

As we can see making the rotation we obtain same figure

use the equation of a parabola in standard form having a vertex at (0, 0), x^2= 8y.Solve the equation for "p" and then describe the focus (0, p), the directrix, and the 2 focal chord endpoints.

Answers

Solution

We have the following equation:

[tex]x^2=8y[/tex]

the general formula for a parabola is given by:

[tex](x-h)^2=4p(y-k)[/tex]

Where (h,k) =(0,0) represent the vertex, so then our equation is:

[tex]x^2=4py[/tex]

By direct comparison we have this:

4p= 8

p = 2

Then the focus is given by:

(0,p) = (0,2)

the directrix is given by:

y= 0-p = 0-2= -2

y=-2

And finally the 2 focal chord endpoints are:

[tex](|2p|,p)=(4,2),(-|2p|,p)=(-4,2)[/tex]

The figure below is a net for a right rectangular prism. Its surface area is 432 m2 andthe area of some of the faces are filled in below. Find the area of the missing faces,and the missing dimension.

Answers

The surface area is the sum of all the areas in the given prims, then we have:

[tex]SA=72+72+48+48+2A[/tex]

Plugging the value for the surface area and silving for A we have:

[tex]\begin{gathered} 432=72+72+48+48+2A \\ 432=240+2A \\ 2A=432-240 \\ 2A=192 \\ A=\frac{192}{2} \\ A=96 \end{gathered}[/tex]

Now that we know the missing area we can know the missing dimension:

[tex]\begin{gathered} 96=8x \\ x=\frac{96}{8} \\ x=12 \end{gathered}[/tex]

Therefore the missing length is 12.

g(x)= 6/x find (g°g). and domain in set notation.

Answers

We have to find the expression for the composition

[tex]g\circ\text{ g\lparen x\rparen}[/tex]

Where

[tex]g(x)=\frac{6}{x}[/tex]

And express its domain in set notation. We will start by finding the expression for the composition

[tex]g\circ\text{ }g(x)=g(g(x))=g(\frac{6}{x})[/tex]

that is we firsts evaluate the inner functions that in this case is g, now taking as argument y=6/x, we evaluate the outer function that in this case also is g, as follows:

[tex]g\text{ \lparen }\frac{6}{x})=\frac{6}{\frac{6}{x}}=\frac{6}{6}=x[/tex]

That is, the composition g*g is equal to x, the identity.

Now we will find the domain of g*g:

Note that the domain of a composition is an interception, as follows:

[tex]Domain\text{ }g\circ\text{ g=\textbraceleft Domain of }g\text{ \textbraceright }\cap\text{ \textbraceleft Image of }g\text{ \textbraceright}[/tex]

Therefore, we have to find the domain and image of g, and intercept both sets. We start with the domain of g_

[tex]Domain\text{ of }g\text{ }=\text{ }\mathbb{R}\text{ - \textbraceleft0\textbraceright}[/tex]

That is all the real numbers except the 0. Now note that the image of g is

[tex]Image\text{ g= }\mathbb{R}\text{ - \textbraceleft0\textbraceright}[/tex]

Finally, the domain of the composition g*g, can be obtained by the formula above:

[tex]Domain\text{ of }g\circ\text{ g=}\mathbb{R}\text{ -\textbraceleft0\textbraceright }\cap\text{ }\mathbb{R}\text{ - \textbraceleft0\textbraceright= }\mathbb{R}\text{ - \textbraceleft0\textbraceright=}(-\infty\text{ },0)\text{ }\cup\text{ }(0,\infty)\text{ }[/tex]

Therefore, the domain of the composition are all the real numbers excluding the 0.

-

For his long distance phone service, David pays a $7 monthly fee plus 7 cents per mintue. Last month, David's long distance bill was $13.93. For how many minutes was David billed?

Answers

For the long-distance service, David pays a monthly fee of $7 plus 7 cents per minute.

Let "d" represent the minutes the call lasted, and "c" the total cost of the bill, then you can express the total cost of the bill using the following expression:

[tex]c=7+0.07d[/tex]

If the total cost of the bill was c=13.93, to determine the number of minutes David was billed for, you have to replace input this value in the equation and solve it for d

[tex]\begin{gathered} c=7+0.07d \\ 13.93=7+0.07d \end{gathered}[/tex]

Pass 7 to the other side of the equation by applying the opposite operation

[tex]\begin{gathered} 13.93-7=7-7+0.07d \\ 6.93=0.07d \end{gathered}[/tex]

And divide both sides by 0.07 to determine the value of d

[tex]\begin{gathered} \frac{6.93}{0.07}=\frac{0.07}{0.07}d \\ d=99 \end{gathered}[/tex]

David was billed for 99minutes.

Which of the following transformations, when performed on Figure Q, will result in Figure R?A.) a reflection over the y-axis followed by a translation of 1 unit to the rightB.) a translation of 7 units to the rightC.) a rotation of 270 degrees counterclockwise about the originD.) a rotation of 90 degrees clockwise about the origin

Answers

Given:

Given that a figure Q and its transformation R.

Required:

To choose the correct transformation of the given figure.

Explanation:

The figure R is 7 unit right to the figure Q.

Therefore the option B is correct.

Final Answer:

(B) A translation of 7 units to the right.

A couple plans to save for their child's college education. What principal must be deposited by the parents when their child is born in order to have $37,000 when the child reaches the age of 18? Assume the money earns 9% interest, compounded quarterly. (Round your answer to two decimal places.)

Answers

We can use the compound interest formula:

[tex]A=P(1+\frac{r}{n})^{nt}[/tex]

Where:

A = Amount = $37000

P = Principal

r = Interest rate = 9% = 0.09

n = Number of times interest is compounded per unit of time = 4 (Since it is compounded quarterly)

t = time = 18

Therefore:

[tex]37000=P(1+\frac{0.09}{4})^{18*4}[/tex]

Solve for P:

[tex]\begin{gathered} P=\frac{37000}{4.963165999} \\ P=7454.918 \end{gathered}[/tex]

How do you write 476 in scientific notation?

Answers

Answer:

[tex]undefined[/tex]

How to write 476 in scientific notation.

To write a number in scientific notation, express the number in the form:

[tex]m\text{ }\times10^n[/tex]

Where m is a number that has a unit place value. (That is a number less than 10 but greater than 1)

In the case of 476, you put a point after 4, you would see that there are two digits after 4 ( 7 and 6)

The scientific notation of 476 is therefore:

[tex]4.76\times10^2[/tex]

What should your brain immediatelythink when it sees5(11 + 4y)

Answers

Distributive Property , I need to multiply!

Explanation

[tex]5(11+4y)[/tex]

Step 1

to find the value of y, you need isolate it

to do that, you will have to eliminate the parenthesis, you can remove it using

THE DISTRIBUTIVE PROPERTY

[tex]\begin{gathered} a(b+c)=ab+ac \\ \end{gathered}[/tex]

Step 2

then

[tex]5(11+4y)=5\cdot11+5\cdot4y=55+20y[/tex]

I hope this helps you.

Steve made a business trip of 200.5 miles. He averaged 51 mph for the first part of the trip and 62 mph for the second part. If the trip took 3.5 hours, how long did hetravel at each rate?

Answers

Let t = time traveled at 51 mph

The total time is given as 3.5 hours

So (3.5- t )= time traveled at 62 mph

We are going to use the distance formula:

distance = speed* time

51t + 62(3.5-t) = 200.5

51t + 62*3.5 - 62*t = 200.5

51t + 217 - 62t = 200.5

Solve the equal terms

51t - 62t = 200.5 - 217

-11t = -16.5

t = -16.5/-11

t = 1.5

Then he took 1.5 at 51mph

and (3.5- t ) = (3.5-1.5) = 2h at 62 mph

To confirm these results, find the actual speed of each speed:

speed* time = distance

51*1.5 = 76.5miles

62*2. = 124 miles

76.5miles + 124 miles = 200.5miles

A right triangle has legs that are 5 cm and 7 cm long what is the length of the hypotenuse 1.√122.√243.√74 4.√144

Answers

Answer:

3. √74

Explanation:

By the Pythagorean theorem, the length of the hypotenuse can be calculated as:

[tex]c=\sqrt[]{a^2+b^2}[/tex]

Where c is the hypotenuse and a and b are the lengths of the legs.

So, replacing a by 5 and b by 7, we get:

[tex]\begin{gathered} c=\sqrt[]{5^2+7^2} \\ c=\sqrt[]{25+49} \\ c=\sqrt[]{74} \end{gathered}[/tex]

Therefore, the answer is 3. √74

Can you hello me with number 2 using 3.14 and I have to round to the answer to the nearest tenth as well thanks

Answers

Given data:

Radius of the circle = 10in.

To find:

The circumference of the circle.

The formula to find the cicumference of the circle is,

[tex]C=2\pi r[/tex]

subsitute the values of,

[tex]\begin{gathered} r=\text{ 10in} \\ \pi=3.14 \end{gathered}[/tex]

we get,

[tex]\begin{gathered} C=2\cdot3.14\cdot10 \\ =62.8 \end{gathered}[/tex]

THE CIRCUMFERENCE OF THE CIRCLE IS 62.8 IN

Factor 3x² + 10x + 8 using earmuff method.

Answers

[tex]3x^2+10x+8[/tex]

To factor the above quadratic equation using Earmuff Method, here are the steps:

1. Multiply the numerical coefficient of the degree 2 with the constant term.

[tex]3\times8=24[/tex]

2. Find the factors of 24 that when added will result to the middle term 10.

1 and 24 = 25

2 and 12 = 14

3 and 8 = 11

6 and 4 = 10

Upon going over the factors, we will find that 6 and 4 are factors of 24 and results to 10 when added.

3. Add "x" on the factors 6 and 4. We will get 6x and 4x.

4. Replace 10x in the original equation with 6x and 4x.

[tex]3x^2+6x+4x+8[/tex]

5. Separate the equation into two groups.

[tex](3x^2+6x)+(4x+8)[/tex]

6. Factor each group.

[tex]3x(x+2)+4(x+2)_{}[/tex]

7. Since (x + 2) is a common factor, we can rewrite the equation into:

[tex](3x+4)(x+2)[/tex]

Hence, the factors of the quadratic equation are (3x + 4) and (x + 2).

Another way of factoring quadratic equation is what we call Slide and Divide Method. Here are the steps.

[tex]3x^2+10x+8[/tex]

1. Slide the numerical coefficient of the degree 2 to the constant term by multiplying them. The equation becomes:

[tex]\begin{gathered} 3\times8=24 \\ x^2+10x+24 \end{gathered}[/tex]

2. Find the factors of 24 that results to 10 when added. In the previous method, we already found out that 6 and 4 are factors of 24 that results to 10 upon adding. So, we can say that the factors of the new equation we got in step 1 is:

[tex](x+6)(x+4)[/tex]

3. Since we slide "3" to the constant term, divide the factors 6 and 4 by 3.

[tex]\begin{gathered} =(x+\frac{6}{3})(x+\frac{4}{3}) \\ =(x+2)(x+\frac{4}{3}) \end{gathered}[/tex]

4. Since we can't have a fraction as a factor, slide back the denominator 3 to the term x in the same factor.

[tex](x+2)(3x+4)_{}[/tex]

Similarly, we got the same factors of the given quadratic equation and these are (x + 2) and (3x + 4).

Hello I need help with this please , I was studying it I don’t get this

Answers

Given that

The Pythagoras theorem is true for all right triangles or not.

Explanation -

For each and every right-angled triangle the Pythagoras theorem can be used.

So the final answer is True.

3. Determine - f(a) for f(x) =2x/x-1 and simplify.

Answers

Substitute a for x

[tex]-f\text{ (x ) = - f (a) = - }\frac{2a}{a-1}[/tex]

Determine - f(a) for f(x) =2x/x-1 and simplify.​

Thus, the solution becomes:

[tex]-\frac{2a}{a-1}\text{ or }\frac{2a}{1-a}[/tex]

POSThe expression(-4)(x) is equivalent to the expression x”. What is the value of n?n =

Answers

given expression:

[tex]\mleft(-4\mright)\mleft(x\mright)=x^n[/tex]

To find the value of n.

[tex]\begin{gathered} \ln \mleft(\mleft(-4\mright)x\mright)=n\ln \mleft(x\mright) \\ n=\frac{\ln\left(-4x\right)}{\ln\left(x\right)} \end{gathered}[/tex]

which does not name an integer a.-35 b. 0 c. 3/15d. 10/2

Answers

The integer numbers are the whole numbers or the numbers that are not written as a/b

For the given question

-35 is an integer number

0 is an integer number

10/2 = 5 is an integer number

3/15 = 1/5 is not an integer number

So, the answer will be option c. 3/15

Bruce owns a small grocery store and darges per pound et produce Ir a customer orders S pounds of prodeer, om zich das Bruxe charge the castomert function

Answers

bruce will charge the customer $23.75

Explanation:

Amount charged per pound = $4.75

Let the number of pounds of produce = x

Total cost per number of pounds = $4.75 × x

Let the total cost of produce = y

y = 4.75x

If the number of pounds of produce = x = 5

y = 4.75 (5)

y = $23.75

Therefore, bruce will charge the customer $23.75

my work is saying solve for the value of a

Answers

Using the definition of suplementary angles we know that the angle that contains a and the 75° added together are 180°

[tex]75+(9a+6)=180[/tex]

solve the equation for a

[tex]\begin{gathered} 81+9a=180 \\ 9a=180-81 \\ 9a=99 \\ a=\frac{99}{9} \\ a=11 \end{gathered}[/tex]

I need help knowing the range of this function. the graph of it is[tex]y = {x}^{2} - 2x - 8[/tex]

Answers

Given the function:

[tex]y=x^2-2x-8[/tex]

Let's determine the range of the function using the graph.

The range of a function is the set of all possible y-values which define the function.

From the graph shown, the value of y starts from the vertex at y = -9 and goes upward.

Therefore, the range of the function is all values of y greater than or equal to -9.

{y|y ≥ - 9}

Hence, in interval notation is:

[tex][-9,\infty)[/tex]

ANSWER:

[tex][-9,\infty)[/tex]

Tank (#1) Capacitybarrels per Ft: 62.50Barrels per inch: 5.21.Convert Barrels to Feet, and inches with the information given.If you deposited 190 barrels of water into tank #1. What would be the total amount deposited (feet) and (inches).*remember there are only 12 inches in a foot*

Answers

To answer this question, we have to convert the given amount of barrels to feet and to inches using the conversion factors shown.

Barrels to feet:

[tex]190barrels\cdot\frac{1ft}{62.50barrel}=3.04ft[/tex]

Barrels to inches:

[tex]190barrels\cdot\frac{1in}{5.21barrel}=36.47in[/tex]

It means that the total amount deposited would be 3.04 ft or 36.47 in.

What is a formula for the nth term of the given sequence?135, -225,375...

Answers

Step 1: Write out the formula for a geometric sequence

[tex]\begin{gathered} T_n=ar^{n-1} \\ \text{Where} \\ T_n=\text{ the nth term} \\ a=\text{ the first term} \\ r=\text{ the common ratio} \end{gathered}[/tex]

Step 2: Write out the given values and find the formula

[tex]\begin{gathered} a=135, \\ r=-\frac{225}{135}=-\frac{5}{3} \end{gathered}[/tex]

Therefore the formula is given by

[tex]T_n=135(-\frac{5}{3})^{n-1}[/tex]

Hence, the correct choice is the first choice

14 Find the percent increase or decrease for each of the following values (indicate whether each is an increase or a decrease). a. 4x to x/ b. 0.25m to 0.5m 5 c. + 2p to d.y to 0.687 8 р 15 Consider the following relationships. TI. 1

Answers

The percentage increase or decrease is given by

[tex]\frac{final\: \text{amount}-original\: \text{amount}}{original\: \text{amount}}\times100\%[/tex]

Let us find the percentage increase or decrease for the given cases.

a) 4x to x

[tex]\begin{gathered} \frac{x-4x}{4x}\times100\% \\ \frac{-3x}{4x}\times100\% \\ -0.75\times100\% \\ -75\% \end{gathered}[/tex]

Therefore, it is a percentage decrease (-75%) since it is negative.

b) 0.25m to 0.5m

[tex]\begin{gathered} \frac{0.5m-0.25m}{0.25m}\times100\% \\ \frac{0.25m}{0.25m}\times100\% \\ 1\times100\% \\ 100\% \end{gathered}[/tex]

Therefore, it is a percentage increase (100%) since it is positive.

c) 1/2p to 5/8p

[tex]\begin{gathered} \frac{\frac{5}{8}p-\frac{1}{2}p}{\frac{1}{2}p}\times100\% \\ \frac{\frac{1}{8}p}{\frac{1}{2}p}\times100\% \\ \frac{1}{8}\times\frac{2}{1}\times100\% \\ \frac{2}{8}\times100\% \\ \frac{1}{4}\times100\% \\ 25\% \end{gathered}[/tex]

Therefore, it is a percentage increase (25%) since it is positive

d) y to 0.68y

[tex]\begin{gathered} \frac{0.68y-y}{0.68y}\times100\% \\ \frac{-0.32y}{0.68y}\times100\% \\ -0.47\times100\% \\ -47\% \end{gathered}[/tex]

Therefore, it is a percentage decrease (-47%) since it is negative.

Solve the following inequality for kk. Write your answer in the simplest form.8k - 3 > 9k + 10

Answers

Given:

[tex]8k-3>9k+10[/tex]

To solve for k:

Solving we get,

[tex]\begin{gathered} 8k-3>9k+10 \\ 8k-9k>10+3 \\ -k>13 \\ k<-13 \end{gathered}[/tex]

Hence, the answer is,

[tex]k<-13[/tex]


The sum of a number and -2 is no more than 6.

Answers

Answer: 8

Step-by-step explanation: if you add -2 and 8 you get 6.  :) pls give me brainliest

distance is a direct variation of time if the distance

Answers

Explanation

In order to be able to predict the time, it will take to cover 220 miles, we will have to get the relationship

The relationship between distance and the time can be obtained as follow:

When the distance is 80 miles, the time taken is 2 hours

So when the distance is 220 miles, the time taken will be

[tex]x=\frac{220\times2}{80}=5.5[/tex]

Therefore, it will take 5.5 hours to cover a distance of 220 miles

Therefore, the answer is 5.5 hours

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