Jerome bought 2 postcards and received $1.50 in change in quarters,dimes. And nickels.The nickels, were worth $0.15.If he got 9 coins, back how many of each coin did he get

Answer:

Jerome got 5 quarters, 1 dime and, and 3 nickels.

Step-by-step explanation:

Let's define the variables:

N = number of nickels he got

D = number of dimes he got

Q = number of quarters he got

We know that the nickels were worth $0.15

And each nickel is whort $0.05

Then:

N*$0.05 = $0.15

N = $0.15/$0.05 = 3

N = 3

Now we also know that there is a total of 9 coins, then:

N + D + Q = 9

3 + D + Q = 9

D + Q = 9 - 3 = 6

D + Q = 6

And we also know that the total change received is $1.50, then:

D*$0.10 + Q*$0.25 + N*$0.05 = $1.50

We know that N = 3, then we can replace that and get:

D*$0.10 + Q*$0.25 + 3*$0.05 = $1.50

D*$0.10 + Q*$0.25 = $1.50 - $0.15 = $1.35

D*$0.10 + Q*$0.25 = $1.35

Then we have two equations:

D + Q = 6

D*$0.10 + Q*$0.25 = $1.35

To solve this, we can isolate one of the variables in one of the equations, i will isolate D in the first one:

D = 6 - Q

Now we can replace this in the other equation:

(6 - Q)*$0.10 + Q*$0.25 = $1.35

Now we need to solve this for Q.

$0.60 - Q*$0.10 + Q*$0.25 = $1.35

Q*$0.15 = $1.35 - $0.60 = $0.75

Q = ($0.75)/($0.15) = 5

Q = 5

Then Jerome has 5 quarters.

Now we can return to the equation:

N + Q + D = 9

We already know that:

N = 3

Q = 5

Then if we replace those in the equation, we get:

3 + 5 + D = 9

8 + D = 9

D = 9 - 8 = 1

D = 1

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