x/0.6= 9/0.5 Solve for x please
The solution of the equation given as x/0.6= 9/0.5 is x= 10.8
How to determine the solution of the equation?The equation is given as
x/0.6= 9/0.5
There are no constants to add or subtract in the equation
So, we have
x/0.6= 9/0.5
Multiply through the equation by 0.6
This gives
0.6 * x/0.6= 9/0.5 * 0.6
Evaluate the products
0.6 * x/0.6= 10.8
Evaluate the products, again
x= 10.8
Hence, the solution is 10.8
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A. "Describe the trend in vehicle sales over time" - Should I use a regression model or just a linear model?
Regression
A) We can see the graph and through the data that the most indicated form is to find the regression model since there is not much uniformity among the data to describe it as a purely linear model.
Plotting that scatterplot, and generating the equation we know that the equation is:
[tex][/tex]The measure of an angle is 74° what is the measure of its complementary angle
Answer:
16 degrees
Step-by-step explanation:
Complementary angles = 90 degrees
If the measure of one angle is 74 degrees, that means that the measure of the other angle that is complementary to it is 16 degrees.
74 + x = 90
x = 16
Use the long division method to find the result when 6x4 +423-7x²+3x-7 is
divided by 2x2 + 2x-3. If there is a remainder, express the result in the form
q(x) +5(2).
Answer:−6x4−3x3−2x2−4x−7x2+3=−6x2−3x+16+5x−55x2+3.
Step-by-step explanation: −6x4−3x3−2x2−4x−7x2+3. The Long Division method: −6x2−3x+16
Amir drove from Jerusalém to the lowest place on the earth Dead Sea. His latitude to sea level as a function of time is graphed.What was amir altitude at the beginning of the drive?
Answer:
440 meters.
Explanation:
At the beginning of the drive, time (on the x-axis) is 0.
The value of y when x=0 is 440 meters.
Therefore, Amir's altitude at the beginning of the drive is 440 meters.
Write an equation in slope-intercept form for the line with a slope of -1 and a y-intercept of -2.
Answer:
y = -x - 2
Step-by-step explanation:
Write an equation in slope-intercept form for the line with a slope of -1 and a y-intercept of -2.
slope-intercept form: y = mx + b where m = slope and b = y-intercept
when:
slope of -1
y-intercept of -2
then:
y = -1x + (-2)
y = -x - 2
Answer:
y= -x-2
Step-by-step explanation:
y=mx+b
slope=m
y intercept=b
m= -1
b= -2
input values of m and b to get equation:
y=(-1)x+(-2)
y= -1x-2
y = -x-2
y= -x-2
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In a proof what is the reason that justifies this statement:
Segment BP is congruent to segment BP.
Answer: I believe that the BP segment is equal to BP segment because of the reflexive property.
Step-by-step explanation:
The required reason is that segment BP is congruent to segment BP that Segment BP is the common side among both triangles.
In congruent geometry, the shapes that are so identical. can be superimposed on themselves.
Here,
The necessary explanation is that segment BP and segment BP are congruent because segment BP is the common side of both triangles BPS and BPY, as shown in the figure.
Thus, the required reason is that segment BP is congruent to segment BP and that Segment BP is the common side among both triangles.
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Graph the function by first finding the relative extrema. f(x) = x3 + 4x2 - X - 4 $ HI 4 M 2 4 a 2 4 2 WHATS
The relative extrema of the function f(x) = x³ + 4x² - x - 4 is at
( [tex]-\frac{4+\sqrt{19}}{3} ,\frac{56+38\sqrt19}{27}[/tex] )and the graph of the function is attached below.
The given function is f(x) = x³ + 4x² - x - 4
For the relative extrema we will first have to find the first derivative of the function:
f'(x) = 3x² + 8x - 1
Now for4 the function to have an extremum, f'(x) = 0
3x² + 8x - 1 = 0
Solving we get :
the values of x using the quadratic formula are [tex](-\frac{4-\sqrt{19}}{3} , -\frac{4+\sqrt{19}}{3} )[/tex] .
Now we will substitute the values of x in the function f(x) to get the local extremum.
The maximum value of f(x) is [tex]\frac{56+38\sqrt19}{27}[/tex].
The minimum value of f(x) is [tex]\frac{56-38\sqrt19}{27}[/tex] .
Now we will use various points to find the values of f in the function.
At x = -3 , y = 8
At x = 0 , y = -4
At x =-1 , y = 0
Hence the relative extremum of the function is at [tex](-\frac{4+\sqrt{19}}{3} ,\frac{56+38\sqrt19}{27})[/tex] .
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What is the value for y?
Answer:
28
Step-by-step explanation:
x - 5 = 34, meaning 39 = x
34 + 34 = 68
All triangles add up to 180
180 - 68 = 112
112/4 = 28
make a tree diagram to show the sample space. then, give the total number of outcomes. question 1. making a meal with chicken or steak and broccoli, carrots, potatoes,or green beans.
The sample space which is the total possibilities is 4
The number of murders and robberies per 100,000 population for a random selection of states is shown.
The equation of the regression line has the following shape:
[tex]y=mx+b[/tex]Where m is calculated through the following equation:
[tex]m=\frac{N\sum^{}_{}xy-\sum^{}_{}x\sum^{}_{}y}{N\sum^{}_{}x^2-(\sum^{}_{}x)^2}[/tex]And b is calculated through the following equation:
[tex]b=\frac{\sum^{}_{}y-m\sum^{}_{}x}{N}[/tex]N is the number of samples. 8 for this case.
The values of all the sums present in the above equation are reported in the last row of the table:
[tex]\begin{gathered} \sum ^{}_{}x=31 \\ \sum ^{}_{}y=680.1 \\ \sum ^{}_{}xy=3202.71 \\ \sum ^{}_{}x^2=142.52 \\ \sum ^{}_{}y^2=80033.99 \end{gathered}[/tex]Now, we can begin calculating m by replacing the values:
[tex]\begin{gathered} m=\frac{8\cdot3202.71-31\cdot680.1}{8\cdot142.52-31^2} \\ m=25.333 \end{gathered}[/tex]The slope of the equation is m = 25.333.
Now, we can calculate b:
[tex]\begin{gathered} b=\frac{680.1-25.333\cdot31}{8} \\ b=-13.153 \end{gathered}[/tex]Now that we know the parameters m and b for the linear regression, we can build the equation:
[tex]\begin{gathered} y=mx+b \\ y=25.333x-13.153 \end{gathered}[/tex]Where x represents the murders and y the robberies per 100,000 population.
Then, (a): the equation of the regression line is y = 25.333x - 13.153.
To predict the robberies per 100,000 population when x = 4.5 murders, we just need to replace that 4.5 in the equation that we just found:
[tex]y=25.333\cdot4.5-13.153=100,85[/tex]Finally, (b): according to the linear regression, the number of robberies per 100,000 population when x = 4.5 murders is approximately 100,85.
2. MGSE9-12.A.REI. 1 Which step in solving this equation is justified by the Distributive Property? Consider the sequence of steps to solve the equation: 6v + 3(v – 5) = 4v - (2v + 1) Given = 6v + 3(v — 5) = 4v - (2v + 1) Step 1 = 6 + 3x – 15 = 4y - (2v + 1) Step 2 => 6v + 3v – 15 = 4v – 2y = 1 Step 3 9v – 15 = 4y – 2y - 1 Step 4 => 9v - 15 -- 2v + 4y = 1 Step 5 =9v = 15 = 2y + 1 Step 6 3 7v - 15 =-1 Step 7 3 Tv = 14 Step 8 = v= 2 a. Step 1 b. Step 7 C. Step 5 d. Step 2
6v + 3(v – 5) = 4v - (2v + 1)
Given = 6v + 3(v — 5) = 4v - (2v + 1)
step 1
when you open the first parenthsesis in step 1
we have 6v + 3v - 15 = 4v - (2v + 1)
Then in step 2
we open the second parenthesis,
This gives;
6v + 3v - 15 = 4v - 2v - 1
Therefore; step 1 and step 2 justified the distributive property
a. A company has a policy of retiring company cars; this policy looks at number of miles driven, purpose of trips, style of car and other features. The distribution of the number of months in service for the fleet of cars is bell-shaped and has a mean of 45 months and a standard deviation of 3 months. Using the empirical rule (as presented in the book), what is the approximate percentage of cars that remain in service between 48 and 51 months?b. The physical plant at the main campus of a large state university recieves daily requests to replace fluorescent lightbulbs. The distribution of the number of daily requests is bell-shaped and has a mean of 64 and a standard deviation of 7. Using the empirical rule (as presented in the book), what is the approximate percentage of lightbulb replacement requests numbering between 57 and 64?c. A population of values has a normal distribution with μ=153 and σ= 39.5You intend to draw a random sample of size n=196Find P2, which is the score separating the bottom 2% scores from the top 98% scores. P2 (for single values) = Find P2, which is the mean separating the bottom 2% means from the top 98% means. P2 (for sample means) = Enter your answers as numbers accurate to 1 decimal place. round your answer to ONE digit after the decimal point! Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.d. A population of values has a normal distribution with μ= 117.8 and σ=73.1You intend to draw a random sample of size n=59Find the probability that a single randomly selected value is greater than 113. P(X > 113) = Find the probability that a sample of size n= 59 is randomly selected with a mean greater than 113. P(M > 113) = Enter your answers as numbers accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
a.
For this to make sense, we will plot the bell curve of the distribution.
It is general convention that:
65% of the values in the distribution lie between
[tex]\begin{gathered} \bar{x}\pm\sigma \\ Where\colon \\ \bar{x}=\text{mean} \\ \sigma=s\tan dard\text{ deviation} \end{gathered}[/tex][tex]\begin{gathered} 48\pm3=51\text{ or 45} \\ \text{This means that }65\text{ \% of the values lie within the range 45 and 51.} \\ Therefore,\text{ the range between 48 and 51 will be a half of 65\%} \\ \frac{65}{2}\text{ \% = 32.5\%} \end{gathered}[/tex]35% is the percentage of cars that remain in service between 48 and 51 months
b.
We also plot the distribution curve as in a above,
[tex]\begin{gathered} 64\pm7=71\text{ or }57 \\ \text{This means that }65\text{ \% of the values lie within the range 57 and 71.} \\ Therefore,\text{ the range between 57 and 64 will be a half of 65\%} \\ \frac{65}{2}\text{ \% = 32.5\%} \end{gathered}[/tex]
32.5% is the approximate percentage of lightbulb replacement requests numbering between 57 and 64
Please help me 2/3+ (-1/3)
Answer:
The answer is 1/3.
Step-by-step explanation:
The plus sign before the parenthesis means that everything inside keeps it's signal. So
[tex]\frac{2}{3}+(-\frac{1}{3})=\frac{2}{3}-\frac{1}{3}=\frac{2-1}{3}=\frac{1}{3}[/tex]The answer is 1/3.
Juan had $3.50. Julian had 2 1/2 times as much as juan how much money did julian have
At a sale this week, a suit is being sold for $145.60. This is a 74% discount from the original price. What is the original price?
$145.60 ---> 74%
x -------------> 100%
[tex]\begin{gathered} x\times74=145.60\times100 \\ 74x=14560 \\ \frac{74x}{74}=\frac{14560}{74} \\ x=196.76 \end{gathered}[/tex]answer: $196.76 is the orginal price
Use the diagram to the right to determine whether BC. DE. Justify your answer. AD = 15, DB = 12, AE = 10, and EC = 8. The cut part is BC (top to bottom)
Explanation:
AD = 15, DB = 12, AE = 10, and EC = 8
To determine if line BC is parallel to line DE, we will find the ratio of thier corresponding sides. if it is equal, they are parallelf
Jones, JacobTranslation T maps the point (1, 3) to (2,6). Which of the following rules describes the translation T?OT: (x, y) (2., 2y)OT: (0,y) – (a, fu)OT:(,y) - (x-1,7 - 3)OT:(,) ( + 1, y + 3)
The given points are (1,3) and (2,6).
The pre-image is (1,3) and the image is (2,6).
As you can observe, the image is double than the pre-image, this means the transformation used was a dilation with a scale factor of 2, the rule is
[tex]OT\colon(x,y)\rightarrow(2x,2y)[/tex]Therefore, the right answer is the first choice.In a recent study on world happiness, participants were asked to evaluate their current lives on a scale from0 to 10, where 0 represents the worst possible life and 10 represents the best possible life. The meanresponse was 5.2 with a standard deviation of 2.4.(a) What response represents the 95th percentile?(b) What response represents the 60th percentile?(c) What response represents the first quartile?...
Solution
[tex]\begin{gathered} \text{Given} \\ \operatorname{mean},\text{ }\mu=5.2 \\ \text{standard deviation, }\sigma=2.4 \\ \\ \text{Recall the formula} \\ Z=\frac{x-\mu}{\sigma} \\ x-\mu=Z\sigma \\ x=Z\sigma+\mu \end{gathered}[/tex](a)
[tex]\begin{gathered} Z-\text{score for 95 percentile = 1.645} \\ x=Z\sigma+\mu \\ x=1.645(2.4)+5.2 \\ x=9.148 \\ x=9.15\text{ (2 decimal places)} \end{gathered}[/tex](b)
[tex]\begin{gathered} Z-\text{score for 60 percentile = }0.253 \\ x=Z\sigma+\mu \\ x=0.253(2.4)+5.2 \\ x=5.8072 \\ x=5.81\text{ (2 decimal places)} \end{gathered}[/tex](c)
[tex]\begin{gathered} Z-\text{score for first quartile (25\%) = }-0.674 \\ x=Z\sigma+\mu \\ x=-0.674(2.4)+5.2 \\ x=3.5824 \\ x=3.58\text{ (2 decimal places)} \end{gathered}[/tex]10 Daphne is making bows for extra money. For every 3 feet of ribbon she has, she can make 5 bows. Which table shows the possible values of the number of bows she can make and the amount of ribbon she will use? 3 15 33 5 15 20 55 В. 3 18 27 36 5 60 45 50 3 6 15 30 5 10 25 50 11 3 18 27 5 10 30 40
Daphne makes 5 bows for every 3 feet of ribbon, this means that for every 3 feet increase in length of ribbon the bows increases by five. So,
For 3 feet, bows are 5,
For 6 feet bows are 10,
For 9 feet bows are 15,
For 12 feet bows are 20
For 15 feet bows are 25,
for 18 feet bows are 30,
For 21 feet bows are 35,
For 24 feet bows are 40.
For 27 feet bows are 45
For 30 feet bows are 50.
Thus option C is correct.
The radius of a cylindrical water tank is 6.5 ft, and its height is 12 ft. What is the volume of the tank? Use the value 3.14 for T, and round your answer to the nearest whole number. Be sure to include the correct unit in your answer. Continue 6.5 ft 12 ft 0 K ft X ft² 5 ft3 ?
Solution:
The volume of a cylinder is expressed as
[tex]\begin{gathered} volume=\pi r^2h \\ where \\ r\Rightarrow radius\text{ of its circular end} \\ h\Rightarrow height\text{ of the cylinder} \end{gathered}[/tex]Given the cylindrical water tank below:
where
[tex]\begin{gathered} r=6.5\text{ ft} \\ h=12\text{ ft} \\ \pi=3.14 \end{gathered}[/tex]By substitution, we have
[tex]\begin{gathered} volume\text{ = 3.14}\times(6.5)^2\times12 \\ =1591.98 \\ \Rightarrow volume\approx1592\text{ ft}^3\text{ \lparen nearest whole number\rparen} \end{gathered}[/tex]Hence, the volume of the cylindrical water tank, to the nearest whole number, is
[tex]1592\text{ ft}^3[/tex]V ABCD - EFGH. What is the value of k? Your answer may be exact or rounded to the nearest tenth. Note: Images are not to scale. A E 4 mm k 8 mm B 6 mm H D 6 mm F 8 mm 4 mm C С
Since rectangles ABCD and EFGH are similar, we can take the ratios of the corresponding sides of the rectangles
[tex]\frac{AB}{AD}=\frac{EH}{EF}[/tex][tex]\frac{8}{4}=\frac{k}{6}[/tex]cross multiplying
8 x 6 = 4 x k
48 = 4k
4k = 48
Divide both sides by 4
k = 48/4
k = 12
A popular resort hotel has 300 rooms and is usually fully booked. About 7% of the time a reservation is canceled before the 6:00 p. M. Deadline with no penalty. What is the probability that at least 285 rooms will be occupied? use the binomial distribution to find the exact value.
The probability that at least 285 rooms will be occupied is 0.0885
A popular resort hotel's reservation follows Normal distribution as size of sample is greater than 30 with mean np and standard deviation √npq
Given , Probability of cancelation : q = 7% = 0.07
Probability of no cancellation of room : p = 1 - q
p = 1 - 0.07
p = 0.93
here, Binomial distribution tends to normal
Sample size : n = 300
Mean = np
= 300 × 0.93
= 279
Standard deviation = [tex]\sqrt{npq}[/tex]
= [tex]\sqrt{(300)(0.93)(0.07)}[/tex]
= [tex]\sqrt{19.53}[/tex]
= 4.42
We have to find P(x ≥ 285)
subtracting 279 and dividing by 4.42 to each sides
P(x ≥ 285) = [tex]P(\frac{x - 278}{4.42} \geq \frac{285 - 278}{4.42} )[/tex]
= P(z ≥ 1.357) = 1 - P(z<1.357)
Using Z probability table ,
P(x ≥ 285) = 1 - (0.9115)
= 0.0885 is required probability
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solve the quadratic equation 3x^2+x-5=0 give your answer to 2 significant figures
The resultant answer of the given quadratic equation is x₁,₂ = -1 ± √61/6.
What is a quadratic equation?An algebraic equation of the second degree in x is a quadratic equation. The quadratic equation is written as ax² + bx + c = 0, where x is the variable, a, and b are the coefficients, and c is the constant term.So, solve 3x²+x-5=0 as follows:
Quadratic formula: x = -b ± √b²-4ac/2aNow, evaluate as follows:
x = -b ± √b²-4ac/2ax₁,₂ = -1 ± √1² - 4×3(-5)/2×3x₁,₂ = -1 ± √61/2×3x₁,₂ = -1 ± √61/6Therefore, the resultant answer of the given quadratic equation is x₁,₂ = -1 ± √61/6.
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What is the answer we need the answer
To earn exactly $252, madison needs to work for 21 hours.
Time money
worked earned
5 60
8 96
12 144
15 180
We need to find how many hours should madison work to earn exactly $252
For 5 hours she earns $60
So in 1 hour she earns $ 60/5 = 12
For $1 she needs to work for 1/12 hour
For 252 she need to work for (1/12) 252
For 252 she need to work for 21
Therefore, to earn exactly $252, madison needs to work for 21 hours.
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2A professional pyro technician shoots fireworks vertically into the air from the ground with an initial velocity of 192
feet per second. The height in feet of the fireworks is given by h(t) = -16t² + 192t.
a. How long does it take for the fireworks to reach the maximum height?
b. What is the maximum height reached by the firework?
Answer:
See below
Step-by-step explanation:
Maximum height will be found at the t value = - b/2a
b = 192 a = -16
so max height will be at t = - 192/(2 * -16) = 6 s
Max height will be h = -16(6^2) + 192(6) = 576 ft
In a college there are 16 times as many students as professors. If together the students and professors number 42,500, how many students are there in the collego?The number of students in the college is
Let the number of professors be x.
If there are 16 times as many students as professors, then the number of students will be:
[tex]x\times16=16x[/tex]If the number of students and professors is 42,500, then we have that:
[tex]\begin{gathered} x+16x=42500 \\ 17x=42500 \end{gathered}[/tex]Solving by dividing both sides by 17, we have:
[tex]\begin{gathered} x=\frac{42500}{17} \\ x=2500 \end{gathered}[/tex]Hence, we can calculate the number of students in the college to be:
[tex]\Rightarrow2500\times16=40000[/tex]Therefore, there are 40,000 students in the college.
(-20x)( 3xy-y/x^2 )( 3x/9x^2-3x )
When we simplify the given expression, the given expression equals to -20(3x-y)/x(3x-1)
Expression is a combination of variables, numbers and symbols (operations) which is defined according to some rules. We can apply any formula or solve the given expression according to the operations provided.
Given expression
-20x(3x-y/x^2)(3x/9x^2-3x)
Multiply each term with another term
= -20x × (3x-y)/x^2 × 3x/9x^2-3x
In first term and second term cancel x from numerator and denominators and from last expression take 3x common
= -20 × (3x-y)/x × 3x/3x(3x-1)
Cancel 3x from numerator and denominator in last term and we will get the final result.
= -20 × (3x-y)/x × 1/(3x-1)
= -20(3x-y)/x(3x-1)
The given question is incomplete, the complete question is
Simplify the following expression
(-20x)( 3xy-y/x^2 )( 3x/9x^2-3x )
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Harper learned to play a total of 4 pieces over the course of 2 weeks of piano lessons. After 4 weeks of piano lessons, how many total pieces will Harper be able to play? Assume the relationship is directly proportional.
Step-by-step explanation:
Harper learned to play a total of 4 pieces over the course of 2 weeks of piano lessons. After 4 weeks of piano lessons, how many total pieces will Harper be able to play? Assume the relationship is directly proportional.
4 pieces / 2 weeks = 2 pieces per week
after 4 weeks:
4 weeks * 2 pieces per week = 8 pieces after 4 weeks
Answer:
8 pieces will be learnt in 4 weeks
Step-by-step explanation:
please mark as brainliestGeometry Translation Please help me. This is worth alot of point.