It is not a solution
1) To get to know that, we need to plug it in the equation and check whether it is true or false.
2) Picking point (-2,8) and plugging -2 into x and 8 into y, we get:
[tex]\begin{gathered} y-9=3x \\ (8)-9=3(-2) \\ -1=-6\:False \end{gathered}[/tex]2) Hence, we can tell that (-2,8) is not a solution to that equation
Graph the line from the table you found in (5). Remember to scale and label your axes!
We are asked to draw a line by using the values given in the table.
Let x denotes the first column of values and y denotes the second column of values
So, the (x, y) ordered pairs are
(0, 4), (2, 0), (1, 2), (3, -2), (-1, 6)
Let us plot these points on the graph then we would draw a line connecting these points.
Therefore, this is how the graph of the line looks like.
The y-intercept of the line is the point where the line intersects the y-axis.
From the above graph, we see that the line intersects the y-axis at y = 4
Therefore, the y-intercept of the line is 4
The slope of the line is given by
[tex]slope=\frac{\text{rise}}{\text{run}}[/tex]The rise is the vertical distance between the two points on the line.
The run is the horizontal distance between the two points on the line.
As you can see, we selected two points on the line. (you may select any two points)
The two points are (2, 0) and (3, -2)
The vertical distance is -2 (negative because it is going down) and the horizontal distance is 1
[tex]slope=\frac{\text{rise}}{\text{run}}=\frac{-2}{1}=-2[/tex]Therefore, the slope of the line is -2
TWO-Variable SystemsThe two lines graphed below are parallel. How many solutions are there to thesystem of equations?O A. TwoO B. ZeroO C. OneO D. Infinitely manyPREVIOUS
Answer:
B. Zero
Explanation:
The solutions of a system of equations are the points where the graphs intersect. If the lines are parallel, the lines will not intersect, so there will be no solutions to the system.
Therefore, the solutions to the system of two parallel lines are
B. Zero
Use the intercepts to graph the equation. y = -6 x-intercept: Enter as a coordinate: such as (a, b). If there is no x-intercept, enter DNE. Enter as a coordinate: such as (a, b). If y-intercept: there is no y-intercept, enter DNE. 8 6 5 4 ربا
Answer:
x -intercept: DNE
y-intercept: (-6, 0)
Explanation:
The x-intercept is the point where the line intersects the x-axis.
The y-intercept is the point where the line intersects the y-axis.
Now when we draw the line y = -6, we get
We see that the red line does not intersects the x-axis at any point; thereffore, the x-intercept does not exist.
x -intercept: DNE
The red line intersects the y-axis at y = -6; therefore, the y-intercept is the point (0, -6)
Mr. Crow, the head groundskeeper at High Tech Middle School, mows the lawn along the side of the gym. The lawn is rectangular, and the length is 5 feet more than twice the width. The perimeter of the lawn is 250 feet.a. Define a variable and write an equation for this problem.b. Solve the equation that you wrote in part (a) and find the dimensions of the lawn. c. Use the dimensions you calculated in part (a) to find the area of the lawn.
Given:
Length of the rectangular lawn is 5 feet more than the width.
Perimeter of the lawn is 250 feet.
The objective is,
a) To define the variables and write an equation.
b) To solve the equation in part (a) and find the dimensions of the lawn.
c) To find the area of the lawn.
a)
Consider the width of the lawn as w feet.
It is give that the length of the lawn is 5 feet more than the width of the feet.
Then, length of the law can be represented as, l = w+5.
Since, the perimeter is given as 250 feet, the equation can be represented as,
[tex]\begin{gathered} P=2(l+w) \\ P=2(w+5+w) \\ P=2(2w+5)_{} \\ P=4w+10 \end{gathered}[/tex]Hence, the required equation is P = 4w+10.
b)
Now, the dimensions of the lawn can be calculated by substituting the value of perimeter in the equation.
[tex]\begin{gathered} 250=4w+10 \\ 4w=250-10 \\ 4w=240 \\ w=\frac{240}{4} \\ w=60\text{ f}eet \end{gathered}[/tex]Since, the length of the lawnis 5 feet more than the width of the lawn.
[tex]\begin{gathered} l=w+5 \\ l=60+5 \\ l=65\text{ f}eet \end{gathered}[/tex]Hence, the width of the lawn if 60 feet and length of the lawn is 65 feet.
c)
Area of rectangluar lawn can be calculated as,
[tex]\begin{gathered} A=l\times w \\ A=65\times60 \\ A=3900ft^2 \end{gathered}[/tex]Hence, the area of the lawn is 3900 square feet.
The scatter plot below shows the average rent (in dollars per month) for a 1-bedroom apartment in NYC each year between 2000 and 2013. A line was fit to the data to model the relationship. Which of these linear equations best describes the given model?A) ŷ = ⅖x + 800B) ŷ = 40x + 800C) ŷ = 800x + ⅖D) ŷ = 800x + 40Based on the equation, use this equation to estimate the average rent in 2020.Round your answer to the nearest dollar.$___.
From the graph, we can conclude:
[tex]\begin{gathered} b=y-intercept_{}\approx800 \\ m\approx\frac{900-800}{3-0}\approx33.33\approx40 \end{gathered}[/tex]So, the linear equation that best describes the given model is:
[tex]\hat{y}=40x+800[/tex]Therefore, for 2020 or x = 20:
[tex]\begin{gathered} \hat{y}(20)=40(20)+800 \\ \hat{y}(20)=1600 \end{gathered}[/tex]Michael Run 3 times last week who are the destinations human
Given the distances Michael ran each day, add them up in order to obtain the total distance, as shown below
[tex]7+16.9+8.48=32.38[/tex]Therefore, the answer is 32.38km
1.). Two planes leave Dingle City at 1 PM. Plane A heads east at 450 mph and Plane B heads due west at 600 mph. How long will it be before the planes are 2100 miles apart? (No wind) but I need to do this with the Read, plan, solve, check format.
We have that the functions that describes their movement are
[tex]x=x_{0A}+v_At[/tex]And:
[tex]x=x_{0B}+v_Bt[/tex]We then proceed as follows:
[tex]x_{0A}+v_At+x_{0B}+v_Bt=2100[/tex]Then:
[tex]v_At+v_Bt=2100[/tex]That since their starting positions are the same and are 0, then:
[tex]t(v_A+v_B)=2100\Rightarrow t=\frac{2100}{v_A+v_B}[/tex]We then replace the values of vA and Vb, these are the velovities of each plane:
[tex]t=\frac{2100}{450+600}\Rightarrow t=2[/tex]The time it would take them to b 2100 miles apart is 2 hours.
* We determine the function that describes the trajectory of each plane with respect to their final position and speed, then since we know their expected distance we add both expressions (Since the total of their trajectories will give us the total distance) and solve for the time.
Shay created the table below to graph the equation r=2-sin theta (rounded to the hundredths place). Analyze the table. Did Shay make a mistake? If there is a mistake, which point is incorrect
The given equation is
[tex]r=2-sin\theta[/tex]To find the incorrect point, we will substitute the value of theta in each point and find the value of r to the nearest 2 decimal points and compare it with the value of r of the point
[tex]\begin{gathered} \theta=0 \\ r=2-sin0 \\ r=2-0 \\ r=2 \end{gathered}[/tex]Answer A is correct
[tex]\begin{gathered} \theta=\frac{\pi}{6} \\ r=2-sin\frac{\pi}{6} \\ r=2-\frac{1}{2} \\ r=1.5 \end{gathered}[/tex]Answer B is correct
[tex]\begin{gathered} \theta=\frac{\pi}{3} \\ r=2-sin\frac{\pi}{3} \\ r=1.13 \end{gathered}[/tex]Since the value of corresponding r is 2.09, then
Answer C is incorrect
The answer is C
Help meeee please!!!!
The coordinates of B' are (1, 0) after transforming the parallelogram down 4 units and right 3 units.
What are coordinates?Coordinates are distances or angles, represented by numbers, that uniquely identify points on surfaces of two dimensions or in space of three dimensions. These are the set of values that shows the exact position. Coordinates are the set of points, or numbers, that locates a point on a line, on a plane, or in space. The points at the coordinates are called coordinate points. The coordinate plane has two axes. Those are horizontal and vertical axes. The two axes intersect each other at a point called the origin. Coordinate axes are one of the fixed reference lines of a coordinate system. It is a two-dimensional number line. It is used to locate the position of any point.
From the graph, the coordinates of B are (-2, 4).
Translating 4 units down means the value of the y-axis is changing. Therefore, new coordinates will be
(-2-0, 4-4)
=(-2, 0)
Then the parallelogram is translated to 3 units to the right. So, the x-axis is changing to a positive end.
The coordinates of B' will be
(-2+3, 0+0)
= (1,0)
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y=9/5x+8/3That's my question
Given an equation of the form:
[tex]\begin{gathered} y=mx+b \\ m=\text{slope} \\ b=y-\text{intercept} \end{gathered}[/tex]For the line:
[tex]\begin{gathered} y=\frac{4}{9}x-\frac{2}{3} \\ m=\text{slope}=\frac{4}{9} \\ b=-\frac{2}{3} \end{gathered}[/tex]what is 7/8 - 3 1/5? i cant firgure it out
Answer:
-93/40 or -2 13/40
Step-by-step explanation:
7/8 - 16/5
Adjust based on the LCM
35/40 - 128/40
35-128/40
[tex] |4x - 5 \leqslant 7| [/tex]here's my absolute value equation
2.
The inequation is given as,
[tex]\lvert4x-5\rvert\leq7[/tex]Consider the analogy,
[tex]\lvert a\rvert\leq b\Rightarrow-b\leq a\leq b[/tex]Applying this analogy to the given inequality,
[tex]-7\leq4x-5\leq7[/tex]Now, we just need to obtain the solution set for this inequality.
Add 5 to each term,
[tex]\begin{gathered} -7+5\leq4x-5+5\leq7+5 \\ -2\leq4x\leq12 \end{gathered}[/tex]Divide by 4 each term of the inequality,
[tex]\begin{gathered} \frac{-2}{4}\leq\frac{4x}{4}\leq\frac{12}{4} \\ -0.5\leq x\leq3 \end{gathered}[/tex]Thus, the solution set to the given inequation is obtained as,
[tex]-0.5\leq x\leq3[/tex]As the number manu fucture increase from soo+200. manufactute (ost increase from 350 to 650 birr. Assume that the given data establishes relationship between Cost. cand number of units made. Q and asume that the the relation This is linear. Assuum the thice unit is birr 13.
y = 3x + 50 is the linear equation relating the total cost to the number of units produced.
We know that a linear equation is of the form
y = mx + b
Where m is the slope (rate of change of y with respect to x) and b is the value when x is 0.
With the given information, the cost increased by
$650 - $350 = $300
When the number of units produced increased by 200 - 100 = 100.
So the rate of change of cost (y) with respect to x (number of units) is 300/100=3.
So the equation is of the form
y = 3x + b
Use one of the two given data points to determine b.
When the production was 100, the total cost was $350:
So,
350 = 3(100) + b
350 = 300 + b
b = 50
Hence the answer is y = 3x + 50 is the linear equation relating the total cost to the number of units is produced.
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y = x2 + 5x - 10y=-x² + 2x + 10
Since in both given equations, the variable y is already clear, then you can equal the two equations and then solve for x. So, you have
[tex]\begin{cases}y=x^2+5x-10\text{ (1)} \\ y=-x^{2}+2x+10\text{ (2)}\end{cases}[/tex][tex]\begin{gathered} x^2+5x-10=-x^2+2x+10 \\ \text{ Add }x^2\text{ to both sides of the equation} \\ \text{ Subtract 2x to both sides of the equation} \\ \text{ Subtract 10 to both sides of the equation} \\ x^2+5x-10+x^2-2x-10=-x^2+2x+10+x^2-2x-10 \\ 2x^2+3x-20=0 \end{gathered}[/tex]To solve for x you can use the quadratic formula, that is,
[tex]\begin{gathered} \text{ For }ax^2+bx+c=0\text{ where a}\ne0 \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \end{gathered}[/tex]In this case
a=2
b=3
c=-20
So,
[tex]\begin{gathered} x=\frac{-3\pm\sqrt[]{(3)^2-4(2)(-20)}}{2\cdot2} \\ x=\frac{-3\pm\sqrt[]{9+160}}{4} \\ x=\frac{-3\pm\sqrt[]{169}}{4} \\ x=\frac{-3\pm13}{4} \\ x_1=\frac{-3+13}{4}=\frac{10}{4}=\frac{5}{2}=2.5 \\ x_2=\frac{-3-13}{4}=\frac{-16}{4}=-4 \end{gathered}[/tex]Now you can plug in the solutions found in any of the given equations to find their respective y-coordinates.
For the first solution, you have
[tex]\begin{gathered} x_1=\frac{5}{2} \\ y_{}=-x^2+2x+10\text{ (2)} \\ y_1=-(\frac{5}{2})^2+2(\frac{5}{2})+10 \\ y_1=-\frac{25}{4}+5+10 \\ y_1=\frac{35}{4} \\ y_1=8.75 \\ \text{ Then} \\ (2.5,8.75) \end{gathered}[/tex]For the second solution, you have
[tex]\begin{gathered} x_2=-4 \\ y=-x^2+2x+10\text{ (2)} \\ y_2=-(-4)^2+2(-4)+10 \\ y_2=-16-8+10 \\ y_2=-14 \\ \text{Then} \\ (-4,-14) \end{gathered}[/tex]Therefore, the solution set of the given system of equations is
[tex]\mleft\lbrace(-4,-14),(2.5,8.75)\mright\rbrace[/tex]Given the standard restricted domains, which of the following relationships does not hold for x=-1? (Assume angles are in radians.)
Answer:
[tex]D:\text{ arccos\lparen cos\lparen-1\rparen\rparen= 1}[/tex]Explanation:
From the restricted domain, we want to check for the relationship that does not hold
All we have to do here is to substitute the value -1 for x, after which we evaluate each of the given equations
We proceed as follows:
[tex]\begin{gathered} a)\text{ sin\lparen}\sin^{-1}(-1))\text{ = -1} \\ b)\text{ arcsin\lparen sin\lparen-1\rparen\rparen = -1} \\ c)\text{ cos\lparen arc cos \lparen-1\rparen\rparen = -1} \\ d)\text{ arc cos\lparen cos\lparen-1\rparen\rparen = 1} \\ e)\text{ tan\lparen arc tan\lparen-1\rparen\rparen = -1} \\ f)\text{ arctan\lparen tan\lparen-1\rparen\rparen = -1} \end{gathered}[/tex]The correct option is thus D
what is the intermediate in the form (x+a)^2=b as a result of completing the square for the following equation?Answer:()^2=
Step 1: Write out the equation
[tex]x^2-12x+32=4[/tex]Step 2: Subtract 32 from both sides of the equation
[tex]\begin{gathered} x^2-12x+32-32=4-32 \\ x^2-12x=-28 \end{gathered}[/tex]Step 3: Complete the square by adding 1/2 of the square of the coefficient of x to both sides
That is
[tex]x^2-12x+(-6)^2=-28+(-6)^2[/tex]This implies that
[tex](x-6)^2=-28+36=8[/tex]Hence the intermediate step is (x - 6)² = 8
3. Which situation could be represented by the graph shown?3027242118A. Garrett buys limes for $0.80 each.B. Sophia buys 12-packs of soda for $1.75 each.C. Jacob buys packs of gum for $1.50 each.D. Allison purchases lemons for $0.75 each.15129631 2 3 4 5 6 7 8 9 10
Find the slope of the graph, use 2 points on the line (0,0) and (4,3)
[tex]m=\frac{3-0}{4-0}=\frac{3}{4}=0.75[/tex]The equation of the graph is y=0.75x, it represents the situation in option D. Allison purchases lemons for $0.75 each
For positive acute angles A and B, it is known that sin A= 7/25 and cos B= 21/29. Find the value of sin(A + B) in simplest form.
Answer
sin A = 7/25
cos B = 21/29
To find sin(A + B), we use double angle formula.
sin(A + B) = sin A cos B + sin B cos A
sin A = 7/25 , cos B = 21/29
From trigonometric identity, sin²θ + cos²θ = 1
cos A = √(1 - sin²A) = √(1 - (7/25)²)
cos A = √(1 - (49/25))
cos A = √(576/625)
cos A = 24/25
Also, sin B = √(1 - cos²B) = √(1 - (21/29)²)
sin B = √(1 - (441/841))
sin B = √(400/841)
sin B = 20/29
Recall that sin(A + B) = sin A cos B + sin B cos A
sin (A + B) = (7/25 x 21/29) + (20/29 x 24/25)
sin (A + B) = (147/725 + 480/725)
sin (A + B) = (147 + 480)/725
sin (A + B) = 627/725
Find and graph the intercepts of the following linear equation: x-4y=16
The given function is:
[tex]x-4y=16[/tex]The x-intercept is the value of x when y = 0.
[tex]\begin{gathered} x-4(0)=16 \\ x=16 \end{gathered}[/tex]The y-intercept is the value of y when x = 0.
[tex]\begin{gathered} (0)-4y=16 \\ -4y=16 \\ \text{ Dividing both sides of the equation by }-4 \\ y=-4 \end{gathered}[/tex].
Find the angle of taper on the steel bar shown if it is equal to twice.
The angle m can be found by noticing that:
cos m = 22.5/25
That's so because if we divide the triangle formed by the taper into two others, we get two right triangles.
Each right triangle has the angle m, the adjacent leg measuring 22.5 mm, and the hypotenuse measuring 25.0 mm.
So, using the formula for the cosine, we get the above relation. Then, solving this equation, we have:
cos m = 22.5/25
m = arccos 22.5/25
m ≅ 25.84º
Therefore, the angle of the taper is:
2 * m = 2 * 25.84º = 51.68º
Now, in order to convert this result using arc minutes, we need to remember that each 1º corresponds to 60' (60 arc minutes). Thus, we have:
1º --- 60'
0.68º --- x
So, cross multiplying those values, we find:
1º * x = 0.68º * 60'
x = (0.68º/1º) * 60'
x = 0.68 * 60'
x = 40.8'
x ≅ 41'
Therefore, the answer is 51º41'.
2) The mass of a radioactive element decays at rate given by m(t) = m0e^-rt, where m(t) is the mass at any time t, m0 is the initial mass, and r is the rate of decay.Uranium-240 has a rate of decay of .0491593745. What is the mass of U-240 left after 10 hours, if the initial mass is 50 grams? (Use e = 2.71828.]A) 28.54387 gB) 30.58254 gC) 32.14286 gD) 32.68034 g
Solution
- We are given the following formula:
[tex]\begin{gathered} m(t)=m_0e^{-rt} \\ \text{where,} \\ r=\text{decay rate} \\ t=\text{time} \\ m_0=\text{ Initial mass} \\ m=\text{mass after time t} \end{gathered}[/tex]- We are told that the Initial mass is 50g, the decay rate is .0491593745, time (t) is 10 hours, and e = 2.71828.
- With the above information, we can proceed to substitute the values given into the formula and get the mass of Uranium after 10 hours.
- This is done below:
[tex]\begin{gathered} m=50\times2.71828^{-(0.0491593745)\times10} \\ \\ m=50\times0.611651003817 \\ \\ \therefore m=30.5825\ldots\approx30.58254g \end{gathered}[/tex]Final Answer
The answer is 30.58254g (OPTION B)
7. Solve this riddle. I am an even number. I am between 10 and 20. And when I am divided by 7, I have no remainder. What number am I?
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
solve the riddle = ?
Step 02:
We must analyze the exercise to find the solution
a. even number
b. 10 ----- 20
c. x / 7 ===> no remainder
11 , 13 , 15 , 17 , 19 ===> even numbers
If X = 7 units, Y = 11 units, Z = 14, and H = 4 units, what is the surface area of the triangular prism ?
we know that
The surface area of a triangular prism is equal to
SA=2B+PL
where
B is the area of the triangular face
P is the perimeter of the triangular face
L is the length of the prism
step 1
Find the area B
B=(1/2)*y*h
substitute the given values
B=(1/2)*11*4
B=22 units^2
step 2
Find teh value of P
P=X+X+y
substitute the given values
P=7+7+11
P=25 units
step 3
Find the surface area
SA=2*22+25*14
SA=394 units^2Cora and Leroy went out to lunch. Leroy's billwas $8.59 less than three times Cora's bill. Iftheir combined bill total was $68.29. how muchmore did Leroy pay than Cora?
Cora and Leroy went out to lunch. Leroy's bill
was $8.59 less than three times Cora's bill. If
their combined bill total was $68.29. how much
more did Leroy pay than Cora?
Let
x -------> Leroy's bill
y -------> Cora's bill
we have
x=3y-8.59 ------> equation A
x+y=68.29 ------> equation B
solve the system
substitute equation A in equation B
(3y-8.59)+y=68.29
solve for y
4y=68.29+8.59
4y=76.88
y=19.22
Find the value of x
xc=3(19.22)-8.59
x=49.07
therefore
Leroy's bill was $49.07Cora's bill was $19.22The admission fee at an amusement park is $2.75 for children and $4.80 for adults. On a certain day, 312 people entered the park, and the admission fees collected totaled $1104. How many children and how many adults were admitted?
Let the number of children admitted be x and let the number of adults admitted be y.
It is given that the total number of 312 people were admitted, this implies that the sum of the number of children and adults is 312:
[tex]x+y=312[/tex]It is given that the admission fee for children is $2.75, this implies that the total fees collected for x children are:
[tex]x\cdot2.75=2.75x[/tex]It is also given that the admission fee for adults is $4.80, this implies that the total fees collected for y children are:
[tex]y\cdot4.80=4.80y[/tex]Since the admission fees collected totaled $1104, it follows that:
[tex]2.75x+4.80y=1104[/tex]Hence, the following system of equations is formed:
[tex]\begin{cases}x+y=312{} \\ 2.75x+4.80y={1104}\end{cases}[/tex]Solve the system of equations:
Solve the first equation for x:
[tex]x=312-y[/tex]Substitute this for x in the second equation:
[tex]\begin{gathered} 2.75\left(−y+312\right)+4.8y=1104 \\ \text{ Simplify both sides of the equation:} \\ \Rightarrow-2.75y+858+4.8y=1104 \\ \Rightarrow-2.75y+4.8y+858=1104 \\ \Rightarrow2.05y+858=1104 \\ \text{ Subtract }858\text{ from both sides:} \\ \Rightarrow2.05y+858−858=1104−858 \\ \Rightarrow2.05y=246 \\ \text{ Divide both sides by }2.05: \\ \Rightarrow\frac{2.05y}{2.05}=\frac{246}{2.05} \\ \Rightarrow y=120 \end{gathered}[/tex]It follows that the number of adults admitted is 120.
Substitute y=120 into the equation x=312-y to find the value of x:
[tex]\begin{gathered} x=312-120 \\ \Rightarrow x=192 \end{gathered}[/tex]Hence, the number of children admitted is 192.
Answer: 192 children and 120 adults were admitted.
Calculate the distance between the points G=(-2,-6) and N=(-9, 2) in the coordinate plane.Give an exact answer (not a decimal approximation).
To find the diatance between two points you use the next formula:
[tex]d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]For the given two points:
[tex]\begin{gathered} d=\sqrt[]{(-9-(-2))^2+(2-(-6))^2} \\ \\ d=\sqrt[]{(-7)^2+8^2} \\ \\ d=\sqrt[]{49+64} \\ \\ d=\sqrt[]{113} \end{gathered}[/tex]Then, the distance between points G and N is the square root of 113
7/8 of a watermelon weight is water. if the watermelon weighs 24 kilograms, how many of the kilograms come from water?
ANSWER
21 kg of the watermelon are water.
EXPLANATION
We have to divide the weight of the watermelon by 8 and then multiply by 7 - or in other words, multiply by 7/8:
[tex]24\times\frac{7}{8}=\frac{24}{8}\times7=3\times7=21[/tex]21 of the 24 kilograms of the watermelon are from water.
Which situation can be represented by the equation y = 9x?Question 3 options:Michael drove x amount of hours in his car. This is 9 times the amount of miles as y.Michael drove x amount of miles in his car. He drove y amount of hours in 9 miles.Michael has y amount of miles to drive. This amount is 9 times x, the amount of miles to drive in hours.Michael has x amount of hours. This amount is 9 times y, the amount of miles to drive in hours.
Solution:
Given:
[tex]y=9x[/tex]This is a linear equation that relates distance, speed, and time.
where;
[tex]undefined[/tex]An arithmetic sequence has a 10th term of 15 and 14th term of 35. show that the equation (y=mx+b) of this graph equals an =-30+(n-1)5.
The arithmetic sequence follows
[tex]a_n=-30+(n-1)5[/tex]Lets see if the 10th term is 15 by replacing the n for 10
n=10
[tex]a_{10}=-30+(10-1)5[/tex][tex]a_{10}=-30+(9)5=-30+45=15[/tex]Now, Lets see if the 14th term is 35 by replacing the n for 14
n=14
[tex]a_{14}=-30+(14-1)5[/tex][tex]a_{14}=-30+(13)5=-30+65=35[/tex]Then so, the sequence follows the equation an =-30+(n-1)5.A car travels at a steady speed of 40 mph. How far will it go in 15 minutes?
The distance travelled by the car in 15 minutes can be determined as,
[tex]\begin{gathered} D=s\times t \\ D=40\text{ mph}\times15\text{ min}\times\frac{1\text{ h}}{60\text{ min}} \\ D=10\text{ miles} \end{gathered}[/tex]Thus, the required distance is 10 miles.