In NOP, PNOP and m2O = 32. Find m P.

Answers

Answer 1

Solving Angle Problems.

[tex]PN\cong\text{ OP implies congruency, that is, length PN is the same as length OP.}[/tex]

It follows therefore that

[tex]\begin{gathered} \angle NPO=\angle NOP=32^o\ldots.(\operatorname{Re}ason\colon\text{ Base angles of the isosceles triangle)} \\ \text{Hence}, \\ m\angle P=32^o \end{gathered}[/tex]

The correct answer is the measure of angle P is 32 degrees

In NOP, PNOP And M2O = 32. Find M P.

Related Questions

Consider the rectangle. IT 4 x+1 Which two expressions represent the area of the rectangle?

Answers

sides of the rectangle:

4

x+1

Area of the rectangle = product of the sides

4 (x+1 )

Apply distributive property:

4(x)+4(1)

4x+4

So, the correct options are:

C. 4x+1

E.4x+4

How wide is the space betweeneach number on this clock?

Answers

Solution:

Given:

We have the angle between each hands of the clock to be

[tex][/tex]

I need help describing the sequence of transformations for 12 and 13.

Answers

12. For the first part we rotate 90° and reflect on the y-axis

Then we reflect on the x-axis

13. First we reflect on the y-axis, then we rotate 90° and finally we reflect on the x-axis

Solve the equation for c: 52 = 4(c + 5)

Answers

Given:

[tex]52\text{ = 4(c + 5)}[/tex]

Solution

We are required to solve the equation for c.

First, we open the bracket:

[tex]52\text{ = 4c + 20}[/tex]

Next, we make c the subject of formular:

[tex]\begin{gathered} 4c\text{ = 52 - 20} \\ 4c\text{ = 32} \\ \text{Divide both sides of the equation by 4} \\ c\text{ = 8} \end{gathered}[/tex]

Answer: c = 8

If the line joining the points (a,4) and (2,-5) is parallel to the line with given equation 2x-3y=12 find the value of a

Answers

Parallel lines have the same slope, thus, using the equation of the parallel line, we can find out the slope of the line that passes through the given points.

To find the slope of a line given its equation, we have to put the equation into the slope-intercept form, whcih we can do by solving the equation for y:

[tex]\begin{gathered} 2x-3y=12 \\ -3y=-2x+12 \\ y=\frac{-2}{-3}x+\frac{12}{-3} \\ y=\frac{2}{3}x-4 \end{gathered}[/tex]

The slope of the line is the coefficient multiplying x, which is 2/3 in this case.

So, let's name the slope m:

[tex]m=\frac{2}{3}[/tex]

Since the lines are parallel, both have the same slope m.

Also, if we want to find the slope given two numbers on the line, we can use the following equation:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

So, we have the points (a, 4) and (2, -5) and we have the slope m = 2/3. Substituting these, we have:

[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1}_{} \\ \frac{2}{3}=\frac{-5-4}{2-a} \\ \frac{2}{3}=\frac{-9}{2-a} \\ 2(2-a)=3\cdot(-9) \\ 4-2a=-27 \\ -2a=-27-4 \\ -2a=-31 \\ a=\frac{31}{2} \end{gathered}[/tex]

Thus, the value of a is 31/2.

choose the expression that is represented by the following phrase:"the square of Y decreased by the quotient of 8 and y"

Answers

[tex]y^2-\frac{8}{y}[/tex]

If f(x) = x2 + x, find f(-3).-123O6

Answers

[tex]f(x)=x^2+x[/tex]

To find f(-3) we have to substitute x = -3 in the equation.

[tex]\begin{gathered} f(-3)=(-3)^2+(-3) \\ f(-3)=9-3 \\ f(-3)=6 \end{gathered}[/tex]

Find the values of x and y in the parallelogram.A46x+2211 BO x= 11, y = 24O x = 24, y = 11Ox=-11, y = 46O x=46, Y =-11

Answers

Since the opposite sides of a parallelogram are congruents, we can write the following equations:

[tex]\begin{cases}DA=BC \\ AB=CD\end{cases}[/tex]

From the first one, we have:

[tex]y=11[/tex]

From the second one, we have:

[tex]\begin{gathered} x+22=46 \\ x=46-22 \\ x=24 \end{gathered}[/tex]

So we have x = 24 and y = 11, therefore the correct option is the second one.

According to the histogram, what is the least number of broken light bulbs received in a shipment?
Responses
A 0
B 1
C 10
D 50

I GIVE YOU BRAINEST PLEASE ANWER UNDER 30 MIN

Answers

0 o maybe 1 I think that

Find the area of the region enclosed by f(x) and the x-axis for the given function over the specified interval. x2 + 2x + 2 x2 The area is 54 (Type an integer or a simplified fraction.)

Answers

To find this area, it is necessary to solve an integral, actually the sum of 2 integrals

[tex]\int (x^2+2x+2)dx+\int (3x+4)dx[/tex]

The first one must be evaluated from -3 to 2 and the second one from 2 to 3

[tex]\begin{gathered} \int (x^2+2x+2)dx+\int (3x+4)dx \\ (\frac{x^3}{3}+x^2+2x)+(\frac{3x^2}{2}+4x) \\ \end{gathered}[/tex]

Evaluate the first integral

[tex]\begin{gathered} \frac{x^3}{3}+x^2+2x\text{ (From -3 to 2)} \\ (\frac{2^3}{3}+2^2+2\cdot2)-(\frac{(-3)^3}{3}+(-3)^2+(2\cdot-3)) \\ \frac{8}{3}+4+4-(-\frac{27}{3}+9-6) \\ \frac{35}{3}+5=\frac{50}{3} \end{gathered}[/tex]

Evaluate the second integral

[tex]\begin{gathered} \frac{3x^2}{2}+4x\text{ (From 2 to 3)} \\ (\frac{3\cdot(3^2)}{2}+4\cdot3)-(\frac{3\cdot(2^2)}{2}+4\cdot2) \\ (\frac{27}{2}+12)-(\frac{12}{2}+8) \\ \frac{15}{2}+4=\frac{23}{2} \end{gathered}[/tex]

Now, solve the sum

[tex]\begin{gathered} \frac{50}{3}+\frac{23}{2} \\ \frac{100+69}{6}=\frac{169}{6} \end{gathered}[/tex]

The area is 169/6

A sociology teacher asked her students to complete a survey at the beginning of the year. One survey question asked, "How responsible are you?" Another question asked, "How many siblings do you have?" Irresponsible Responsible O siblings 6 3 1 sibling 4 5 What is the probability that a randomly selected student has 0 siblings and is irresponsible? Simplify any fractions.

Answers

Answer: Probability is 1/3

Step by step explanation:

The probability (P) of an event is:

[tex]P=\frac{\text{Number of ways it can happen}}{\text{Total number of outcomes}}[/tex]

The probability that a randomly selected student has 0 siblings and is iiresponsible is:

[tex]P=\frac{6}{6+3+4+5}=\frac{6}{18}=\frac{1}{3}[/tex]

a pet store has c tanks of fish. Each tank has 24 fish. Using c, write an expression for the total number of fish in the store

Answers

a pet store has c tanks of fish. Each tank has 24 fish. Using c, write an expression for the total number of fish in the store​

the equation is equal to

Multiply the number of tanks by 24

so

24c

the answer is 24c

Part 2

1/13 is the reciprocal of 13

because

(13)(1/13)=1

a number multiplied by its reciprocal is equal to 1

Find the solution of the system of equations. 3x + 3y = 6 9x - 5y = -24

Answers

3x + 3y = 6 (eq. 1)

9x - 5y = -24​ (eq. 2)

Multiplying equation 1 by 3,

3(3x + 3y) = 3*6

3(3x) + 3(3y) = 18

9x + 9y = 18 (eq. 3)

Subtracting equation 2 to equation 3,

9x + 9y = 18

-

9x - 5y = -24​

---------------------

14y = 42

y = 42/14

y = 3

Replacing this result into equation 1,

3x + 3(3) = 6

3x + 9 = 6

3x = 6 - 9

3x = -3

x = -3/3

x = -1

how do I find the central angle for turn b?

Answers

We will to use the formula to a sector areaa, which is given for:

[tex]A=r^2\theta/2[/tex]

Where r is the radius and θ is the central angle.

We can rewrite the formula to obtain the central angle like this:

[tex]\theta=\frac{2A}{r^2}[/tex]

We replace with the values of the track:

[tex]\theta=\frac{2\ast51\pi}{20\ast3^2}=\frac{17\pi}{30}[/tex]

Then we change radians to degrees:

[tex]\frac{17\pi}{30}\ast\frac{180}{\pi}=102\text{ \degree}[/tex]

Then the correct answer is 102°.

Alex is 12 years older than George, Carl is three times older than Alex, The sum of their ages is 68. Find the ratio of George's age to Carl's age to Alex's age.

Answers

Firstly, let x represent Alex's age, y represent George's age and z represent Carl's age.

from the question;

Alex is 12 years older than George, So;

[tex]x=y+12\ldots\ldots\ldots\ldots.1[/tex]

Carl is three times older than Alex, So;

[tex]z=3x\ldots\ldots\ldots..2[/tex]

The sum of their ages is 68, So;

[tex]x+y+z=68\ldots\ldots\ldots\ldots\ldots3[/tex]

Now we have three equations and three unknowns, so it is solvable.

Let us substitute equation 2 into equation 3; that is replace z with 3x in equation 3.

[tex]\begin{gathered} x+y+3x=68 \\ 4x+y=68\ldots\ldots\ldots\ldots\ldots\ldots4 \end{gathered}[/tex]

Next, let us substitute equation 1 into equation 4. that is replace x with y+12 in equation 4.

[tex]\begin{gathered} 4(y+12)+y=68 \\ 4y+48+y=68 \\ 5y+48=68\ldots\ldots\ldots.5 \end{gathered}[/tex]

we can now solve for the value of y from equation 5.

[tex]\begin{gathered} 5y+48=68\ldots\ldots\ldots.5 \\ \text{subtract 48 from both sides.} \\ 5y+48-48=68-48 \\ 5y=20 \\ y=\frac{20}{5} \\ y=4 \end{gathered}[/tex]

let us now replace y with 4 in equation 1 to get the value of x. since y = 4;

[tex]\begin{gathered} x=y+12\ldots\ldots\ldots\ldots.1 \\ x=4+12 \\ x=16 \end{gathered}[/tex]

then, since x =16 let us replace x with 16 in equation 2 to get z.

[tex]\begin{gathered} z=3x\ldots\ldots\ldots..2 \\ z=3(16) \\ z=\text{ 48} \end{gathered}[/tex]

so we have;

[tex]\begin{gathered} \text{Alex's age = x = 4 years} \\ George^{\prime}sage_{}=y=16\text{ years} \\ Carl^{\prime}sage=z=48\text{ years} \\ \end{gathered}[/tex]

We now need to find the ratio of George, Carl and Alex's age.

[tex]\begin{gathered} 16\colon48\colon4 \\ \text{dividing through by 4 we have;} \\ 4\colon12\colon1 \end{gathered}[/tex]

So the ratio of their ages are;

[tex]4\colon12\colon1[/tex]

DIoll Solve the equation x³ + 2x² - 5x-6=0 given that 2 is a zero of f(x)= x³ + 2x² - 5x-6.The solution set is(Use a comma to separate answers as needed.)

Answers

In this case, we'll have to carry out several steps to find the solution.

Step 01:

data:

f(x) = x³ + 2x² - 5x - 6

zero:

x = 2

Step 02:

roots:

solution set:

2 | 1 2 -5 -6

| 2 8 6

________________

1 4 3 0

x² + 4x + 3 = 0

(x + 3)(x + 1) = 0

x = - 3

x = - 1

The answer is:

solution set:

{-3 , -1 , 2}

The table represents the cost to eat at a buffet-style restaurant.Number ofPeople (p)2Cost (C)(including tax)27.5441.3155.0868.85345682.62Which equation could be used to calculate the cost. C, for any number of people, p, to eat at the restaurant?

Answers

We need to take the values of the table and check which of the options fit with the results.

In the first line of the table we have p=2 and C=27.54.

Using the equation in option A, for p=2 we would get:

[tex]\begin{gathered} C=p+27.54 \\ C=2+27.54 \\ C=29.54 \end{gathered}[/tex]

Which is not value for C in the table. Thus we discard option A.

Using the equation for option B, for the value of p=2, we would get:

[tex]\begin{gathered} C=13.77p \\ C=13.77(2) \\ C=27.54 \end{gathered}[/tex]

Which is indeed the value of the table.

To confirm, we try now with the next value of p, p=3, and check if we get the same result with equation B as with the table:

[tex]\begin{gathered} C=13.77p \\ C=13.77(3) \\ C=41.31 \end{gathered}[/tex]

Which is also the value for C in the table.

Thus we confirm that option B is the correct equation

How many ounces of water must be added to 85oz of a 40% salt solution to make a solution that is 17% salt?

Answers

Okay, here we have this:

Considering the provided information, we are going to calculate the requested value, so we obtain the following:

Accordingly, since the amount of salt remains the same, then we have the following equality, where x represents the amount of water that must be added:

0.4(85)=0.17(x+85)

Let's solve for x:

34=0.17x+14.45

0.17x=34-14.45

0.17x=19.55

x=19.55/0.17

x=115

Finally we obtain that must be added 115 ounces of water to make a solution that is 17% salt.

Determine the domain and range Express your answer in interval notation

Answers

The domain of a function is the set of all values that the x-variable can take.

On the other hand, the range of the function is the set of all values that the function takes when it is evaluated at elements of the domain.

For the given expression:

[tex]p(x)=-\frac{1}{(x-1)^2}[/tex]

The denominator is (x-1)^2. Since the denominator must be different from 0, then:

[tex]\begin{gathered} (x-1)^2\ne0 \\ \Rightarrow x-1\ne0 \\ \Rightarrow x\ne1 \end{gathered}[/tex]

Then, the only restriction for the variable x is not to be equal to 1. Then, the domain of p(x) is the set of all real numbers except 1, which can be written using interval notation as:

[tex](-\infty,1)\cup(1,\infty)[/tex]

Since the exponent of the denominator is 2, then the denominator is always positive. Since the coefficient of the term 1/(x-1)^2 is -1, then the whole expression must always be negative. Additionally, there is no way in which the expression can be equal to 0.

Then, the range of the function is the set of all negative numbers, which can be expressed using interval notation as:

[tex](-\infty,0)[/tex]

Therefore, the answers are:

[tex]\begin{gathered} \text{ Domain: }(-\infty,1)\cup(1,\infty) \\ \\ \text{ Range: }(-\infty,0) \end{gathered}[/tex]

Please help will mark Brainly

Answers

Answer:

Below

Step-by-step explanation:

A  yes     all values of y

B  yes    slope is undefined for a vertical line

C  no      there is no  y axis intercept for this line

D  yes     the line intercepts the x-axis at x = -2

E   no       the domain is only  x = -2

could i have a fast answer please? if not it’s ok

Answers

Given:

Strip diagrams are given.

Option D represents the 175% .

Option D is the correct answer.

The taxes on a house assessed at 90,000 are $3420 a year. If the assessment is raised to 119,000 and the tax rate did not change, how much would the taxes be now?

Answers

The amount of tax to be paid on the assessment of the house is $4522.

How to calculate the tax?

Given that the taxes on a house assessed at 90,000 are $3420 a year, the tax rate will be:

= Tax / Total value.

= 3420 / 90000

= 3.8%

Therefore, when the assessment is raised to 119,000 and the tax rate did not change, the value of the tax will be:

= Tax percentage × New assessment

= 3.8% × 119000

= $4522

The tax is $4522.

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hello this is a plane trigonometry question hopefully you can help I did every thing else it's just the last one I can't get the reference angle for five in this question

Answers

[tex]\theta=\frac{71}{36}\pi[/tex]

What is the quotient in simpilest form? 3/4÷5/16

Answers

the given expression is

[tex]\frac{\frac{3}{4}}{\frac{5}{16}}[/tex][tex]\frac{3\times16}{5\times4}=\frac{12}{5}=2.4[/tex]

so the quotient will be 2.4

Ron bought two comic books on sale. Each comic book was discounted $1 off the regular price r. Write an expression to find what Ron paid before taxes. If each comic book was regularly $2.50, what was the total cost before taxes?

Answers

Step 1

Given;

[tex]\begin{gathered} A\text{ regular price of r for a comic book on sale} \\ A\text{ discount of \$1 before tax} \end{gathered}[/tex]

Required; To

1) write an expression to find what was paid by Ron before taxes

2)Find the total cost before taxes of the comic books, if each one costs $2.50

Step 2

Write the expression of what Ron paid before taxes

[tex]\begin{gathered} \text{\$}2(r-1) \\ \text{Note; One book costs \$(r-1)} \\ \text{\$}(2r-2) \end{gathered}[/tex]

Step 3

If each book was regularly $2.50, find the total cost before taxes

[tex]\begin{gathered} r=\text{\$}2.50 \\ \text{Total cost=\$(2(2.50)-2)} \\ \text{Total cost=\$(5-2)=\$}3 \end{gathered}[/tex]

Question 9, on which interval is the graph negative ?

Answers

The intervals where the graph is negative are those where it goes below the x-axis. With the figure we can easily identify the following negative portion of the graph:

As you can see, these negative values are located for all the points within (-5, -1), this is equivalent to the interval -5 < x < -1. Then option B is the correct answer

Daig 20. Sample Problem using Daum Equation Editor 4 - [3 :) and B - [: 6 51 Determine -3A + 2B Show all work using the Daum Equation Editor. Insert your image here:

Answers

The question is given as : -3A +2 B

[2 5] + { 6 5 }

[7 0 } { 1 1 }

For the first matrix , multiply by -3 and the second matrix multiply by 2

To multiply a matrix, every value in the bracket is multiplied by the scalar.

For -3A multiply the values in the bracket with -3 as;

[tex]\begin{bmatrix}{2} & {5} & \\ {7} & {0} & {} \\ {} & {} & \end{bmatrix}\times-3\text{ = }\begin{bmatrix}{-6} & {-15} & \\ {-21} & {0} & {} \\ {} & {} & {}\end{bmatrix}=-3A[/tex]

For 2B

[tex]\begin{bmatrix}{6} & {5} & {} \\ {1} & {1} & {} \\ {} & {} & {}\end{bmatrix}\times2=\begin{bmatrix}{12} & {10} & \\ {2} & {2} & {} \\ {} & {} & {}\end{bmatrix}=2B[/tex]

Now perform the addition as; -3A + 2B

[tex]\begin{bmatrix}{-6} & {-15} & \\ {-21} & {0} & {} \\ {} & {} & {}\end{bmatrix}+\begin{bmatrix}{12} & {10} & \\ {2} & {2} & {} \\ {} & {} & {}\end{bmatrix}=\begin{bmatrix}{-6+12} & {-15+10} & \\ {-21+2} & {0+2} & {} \\ {} & {} & {}\end{bmatrix}[/tex]

This will give the following;

[tex]\begin{bmatrix}{6} & {-5} & {} \\ {-19} & {2} & {} \\ {} & {} & {}\end{bmatrix}[/tex]

The price of televisions has dropped dramatically over the last three years. Three years ago, a 32 inch television was $500. This year the tv was on sale for $199. What is the percent change?

it is due today!!! 7th honers

Answers

The percent change in the price of television from initial price $500 to final price $199 is 60.2.

What are Percentages?

The term 'per cent' means 'out of a hundred'.

Percentage is a way to define  parts of a whole.

To convert fraction to a percentage, first convert fraction to decimal,

then multiply decimal value with 100, with '%' sign.

So, Percentage change = [tex]\frac{initial-final}{initial}[/tex]×100%

      Percentage change = { ( $500 - $199 ) / $500 } × 100%

                                        = { $301 / $500 } × 100%

                                        = .602 × 100%

                                        = 60.2%

Hence, the percentage change in tv price is 60.2%.

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solve: 10+7-4y=-5+6y+22 and decide whether it has infinite solutions or no solutions or one solution

Answers

[tex]\begin{gathered} 10+7-4y=-5+6y+22 \\ 17-4y=17+6y \\ 17-17-4y=17+6y-17 \\ -4y=6y \\ -4y-6y=6y-6y \\ -10y=0 \\ \frac{-10y}{-10}=\frac{0}{-10} \\ y=0 \end{gathered}[/tex]

answer is one solution

i need help trying to write a system of linear equations for the graph below

Answers

We need to find the equation in slope-intersect form

[tex]y=mx+b[/tex]

of the given lines.

For the horizontal line, we can see that it passes through points

[tex]\begin{gathered} (x_1,\text{y}_1)=(0,7) \\ (x_1,y_2)=(4,6) \end{gathered}[/tex]

the its slope (m) is given by

[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{6-7}{4-0}=\frac{-1}{4}=-\frac{1}{4}[/tex]

Then, the line equation has the form

[tex]y=-\frac{1}{4}x+b[/tex]

where b is the y-intercept. From the picture, we can see that the line crosses the y-axis at y=7, therefore, b=7. Then, the line equation for the horizontal line is

[tex]y=-\frac{1}{4}x+7[/tex]

Similarly, we can apply the same procedure for the other line. We can see that it passes through points

[tex]\begin{gathered} (x_1,\text{y}_1)=(0,-2) \\ (x_2,\text{y}_2)=(4,6) \end{gathered}[/tex]

Then, the slope (m) of this line is given by

[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{6-(-2)}{4-0}=\frac{6+2}{4}=\frac{8}{4}=2[/tex]

Then, the line equation has the form

[tex]y=2x+b[/tex]

Since this line crosses y-axis at y=-2 then b=-2. Hence, the equation is

[tex]y=2x-2[/tex]

In summary, the system of linear equations is:

[tex]\begin{gathered} y=-\frac{1}{4}x+7 \\ y=2x-2 \end{gathered}[/tex]

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