In ACDE, mZC = (4x – 16), m D = (6x - 1)", and mZE = (4x - 13). Find mZC.

In ACDE, MZC = (4x 16), M D = (6x - 1)", And MZE = (4x - 13). Find MZC.

Answers

Answer 1

Explanation:

We can do a diagram of triangle CDE:

The sum of the measures of the interior angles of any triangle is 180º. We can write an equation:

[tex]\begin{gathered} m\angle C+m\angle D+m\angle E=180º \\ (4x-16)+(6x-1)+(4x-13)=180 \\ (4x+6x+4x)+(-16-1-13)=180 \\ 14x-30=180 \end{gathered}[/tex]

Solve for x:

[tex]\begin{gathered} 14x=180+30 \\ 14x=210 \\ x=\frac{210}{14} \\ x=15 \end{gathered}[/tex]

And with x = 15, replace into the expression for the measure of angle C to find it:

[tex]m\angle C=4x-16=4\cdot15-16=60-16=44º[/tex]

Answer:

m

In ACDE, MZC = (4x 16), M D = (6x - 1)", And MZE = (4x - 13). Find MZC.

Related Questions

What is the magnitude of the resultant vector of 8 meters North and 8 meters East displacement. Use the WRISd editor icon Vito answer this question. You canwrite using the pento right. Your drawing will be ttransfered to actural writing

Answers

In order to find the total displacement of a 8 meters north vector and a 8 meters east vector, we first need to know that these vectors forms a right angle (because the north and east directions forms a 90° angle).

So, to find the final displacement, we need to sum these vectors, and this sum can be calculated using the Pythagoras' theorem in the resultant triangle:

[tex]\begin{gathered} d^2=8^2+8^2 \\ d^2=64+64 \\ d^2=128 \\ d=\sqrt{128=8\sqrt{2=}}11.31 \end{gathered}[/tex]

So the total displacement is 11.31 meters.

Are the pair of lines y = 1/3x - 1 and y = 3x parallel, perpendicular, or neither?

Answers

A line with slope m and y-intercept b has the following slope-intercept form equation:

[tex]y=mx+b[/tex]

If two lines have the same slope, they are parallel. If they have slopes that are the negative reciprocal of each other, then they are perpendicular.

If none of the above cases happen, then they are neither parallel nor perpendicular.

The line y = (1/3)x - 1 has slope 1/3.

The line y = 3x has slope 3.

As we see, the slopes are different, so the lines are not parallel. Also, the negative reciprocal of 3 is -1/3, not 1/3.

Therefore, the given lines are neither parallel nor perpendicular.

which of the following are accurate of the distribution below

Answers

A: An outlier is a point that is an exception compared to the distribution of the data. In a histogram, it would appear as a bar away from the distribution with a lower height. We can't observe this in this distribution.

A do not apply.

B: A cluster is an accumulation of point in a certain interval. The interval given is 0 to 39. In the distribution, there are no points for this interval, so no cluster.

B do not apply.

Since A and B do not apply, C do apply.

For each of the following letters, find the equation for a polynomial function whose graph resembles the given letter: U, N, M, and W.

Answers

We are asked to determine polynomic functions which graph resembles the given letters.

For the letter U we will use a second-degree polynomial, which means a polynomial of the form:

[tex]y=ax^2+b[/tex]

Is we take the values of "a" and "b" to be:

[tex]\begin{gathered} a=1 \\ b=0 \end{gathered}[/tex]

We get the function:

[tex]y=x{}^2[/tex]

The graph is the following:

Now, to determine a function that resembles the letter N we will use a polynomic function of third-degree, this means a function of the form:

[tex]y=ax^3+bx^2+cx+d[/tex]

We will use the following values for the constants:

[tex]\begin{gathered} a=\frac{1}{4} \\ \\ b=1 \\ c=0 \\ d=0 \end{gathered}[/tex]

Substituting we get:

[tex]y=\frac{1}{4}x{}^3+x^2[/tex]

The graph of the function is:

To determine a polynomial that resembles the letter "m" we will use a polynomial that has 3 x-intercepts and the end-points are pointing down. This means that the function is of the form:

[tex]y=-(x-a)(x-b)^2(x-c)[/tex]

The middle term has a square because we want the middle intercept to be tangent to the x-axis. Giving values to the constant we get:

[tex]y=-(x+1)(x-1)^2(x-3)[/tex]

The graph of the function is:

Now, we determine a function that resembles the letter "W". We will use a polynomial with two intercepts that are tangent to the x-axis and the end behavior must be upwards. Therefore, the function must be of the form:

[tex]y=(x-a)^2(x-b)^2[/tex]

We will use a = -1 and b = 1:

[tex]y=(x+1)^2(x-1)^2[/tex]

The graph is:

Leo is researching an electric bicycle. He finds this graph, which shows how much range, measured in kilometers, the bicycle gains based on charging time:Leo wants an equation he can use to find how many kilometers of range the bicycle gains (k) based on how many minutes it charges (t). Complete Leo's equation.

Answers

Equation of line in slope intercept form is

k = 4t is the equation which shows how many kilometers of range the bicycle gains (k) based on how many minutes it charges (t)

What is equation of line in slope intercept form?

The most general form of equation of line in slope intercept form is given by y = mx + c

Where m is the slope of the line and c is the y intercept of the line.

Slope of a line is the tangent of the angle that the line makes with the positive direction of x axis.

If [tex]\theta[/tex]  is the angle that the line makes with the positive direction of x axis, then slope (m) is given by

m = [tex]tan\theta[/tex]

The distance from the origin to the point where the line cuts the x axis is the x intercept of the line.

The distance from the origin to the point where the line cuts the y axis is the y intercept of the line.

The graph passes through (5, 20), (10, 40), (15, 60)

Slope =

[tex]\frac{40 -20}{10 - 5}\\\\\frac{20}{5}\\\\4[/tex]

Equation of line

k - 20 =4(t - 5)

k - 20 = 4t - 20

k = 4t

This is the equation which shows how many kilometers of range the bicycle gains (k) based on how many minutes it charges (t)

To learn more about equation of line in slope intercept form, refer to the link-

brainly.com/question/25514153

#SPJ1

Answer:

Step-by-step explanation:

k=4t

i know this because i just answered this question on khan

Which is a solution toy ⩽ -2x + 1 (-3,8)(2,-2)(0,5)(-1, 3)

Answers

To find the right solution, we just have to evaluate the expression with each given point

(-3,8)[tex]\begin{gathered} 8\leq-2\cdot(-3)+1 \\ 8\leq6+1 \\ 8\leq7 \end{gathered}[/tex](2,-2)[tex]\begin{gathered} -2\leq-2\cdot2+1 \\ -2\leq-4+1 \\ -2\leq-3 \end{gathered}[/tex](0,5)[tex]\begin{gathered} 5\leq-2\cdot0+1 \\ 5\leq1 \end{gathered}[/tex](-1,3)[tex]\begin{gathered} 3\leq-2\cdot(-1)+1 \\ 3\leq2+1 \\ 3\leq3 \end{gathered}[/tex]

As you can observe, the last choice satisfies the inequality.

Hence, the answer is (-1,3).

which equation doesn't represent a linear function? [tex]a. \: y = \frac{1}{2}x \: + 2[/tex][tex]b . \: y = {x}^{2} \\ c . \: y = 2x \\ d. \: y = x - 2[/tex]

Answers

The general equation for linear equation is,

[tex]y=mx+b[/tex]

The equation y = x^2, consist of power term on the variable x. So this equation does not follow the linear equation and is a quadratic equation.

Thus, equation y = x^2 is not a linear function. Option B is correct answer.

Find all values of j for which the quadratic equation has no real solutions.7x^2+9x+j=0Write your answer as an equality or inequality in terms of j.

Answers

The discriminant of a quadratic equation tells us whether there are two solutions, one solution or no real solutions and it is described as the part inside the root

[tex]D=b^2-4a\cdot c[/tex]

the conditions are:

[tex]\begin{gathered} D>0;\text{ two real solutions } \\ D=0;\text{ one real solution} \\ D<0;\text{ no real solution} \end{gathered}[/tex]

give values to a, b, and c, which are 7, 9, and j respectively.

using the third condition find the values for j that make the quadratic equation have no solution

[tex]\begin{gathered} 9^2-4\cdot7\cdot j<0 \\ \end{gathered}[/tex]

solve the inequality

[tex]\begin{gathered} 81-28j<0 \\ -28j<-81 \\ 28j>81 \\ j>\frac{81}{28} \end{gathered}[/tex]

Change to Ax+By=C form. y=-5x+9

Answers

The function is:

[tex]y=5x+9[/tex]

Now to put in the form Ax+By=c we hace to let the number that don't have x ot y in the left side of the equation anthe the rest of the term in the right side of the equation:

[tex]-5x+y=9[/tex]

where:

[tex]\begin{gathered} A=-5 \\ B=1 \\ C=9 \end{gathered}[/tex]

The circle is inscribed in the square. Find the area of the shaded region.

Answers

We can solve this by calculating the area of the square and subtracting the area of the inscribed circle. The area of the square is:

[tex]Square=10\cdot10=100cm^2[/tex]

The formula for the area of a circle is:

[tex]A=\pi r^2[/tex]

The radius of the inscribed circle is half the length of the side of the square, then, the radius is r = 5 cm

[tex]Circle=\pi5^2=25\pi\text{ }cm^2[/tex]

Now, we rest:

[tex]Square-Circle=100cm^2-25\pi cm^2\approx21.46cm^2[/tex]

The answer is 21.46cm²

The following figure shows the entire graph of a relationship.Does the graph represent a function?A.yesB.No

Answers

Answer:Yes, it represent a functionExplanations

For the given graph to be a function, it must obey the vertical line test that is an element of the domain must not be marked to more than one element of the codomain.

Since all the domain of the functions has a unique co-domain, hence the entire graph of a relationship is a function.

solve y=f(x) for x. then find the inputs when the output is -3

Answers

Answer:

Given that,

[tex]f(x)=-7x-2[/tex]

To find the inputs when the output is -3 ​

that is, when f(x)=-3, to find the value of x

Put f(x)=-3 in the above equation we get,

[tex]-3=-7x-2[/tex][tex]-7x=-3+2[/tex][tex]\begin{gathered} -7x=-1 \\ x=\frac{1}{7} \end{gathered}[/tex]

Answer is: x=1/7.

62 - 12 ÷ 3 + (15-7)

Answers

62 - 12 ÷ 3 + (15-7)

First, solve the parenthesis:

62-12÷ 3 + 8

Then, solve the division:

62-4+8

Add And subtract

66

The n = 3 row of Pascal's Triangle has the following entries: 1, 3, 3, and 1TrueFalse

Answers

Ok, in the Pascal Triangle, the element in the row number n and column number p is given by:

So let's take n=3 and find all the entries of that row. We are going to use 0, 1, 2 and 3 as possible values for p.

For p=0:

[tex]\frac{3!}{0!(3-0)!}=\frac{6}{1\cdot3!}=\frac{6}{6}=1[/tex]

For p=1:

[tex]\frac{3!}{1!\cdot(3-1)!}=\frac{6}{2!}=\frac{6}{2}=3[/tex]

For p=2:

[tex]\frac{3!}{2!\cdot(3-2)!}=\frac{6}{2\cdot1!}=\frac{6}{2}=3[/tex]

And for p=3:

[tex]\frac{3!}{3!\cdot(3-3)!}=\frac{3!}{3!\cdot0!}=\frac{3!}{3!}=1[/tex]

So the four entries in the third row of Pascal's Triangle are 1, 3, 3 and 1 so the statement is true.

The graph shows the distance Kendrick walks in different lengths of time.How many kilometers does Kendrick walk per hour?5kilometersHow long does it take Kendrick to walk 111 kilometer?hours

Answers

Solution

For this case we can do this:

[tex]\frac{10-5}{2-1}=\frac{5\operatorname{km}}{hr}[/tex]

5 kilometers

We have the following equation

Km = m*hours

hours= 1km/ (5km/hr) =0.2hr

Find the equation of the line containing the point (3,5) and having slope: 4A. y=4x+24B. y=4x+7C. y=4x+17D. y=4x

Answers

Data

Point = (3, 5)

slope = 4

Equation of a line

y - y1 = m(x - x1)

m = slope = 4

x1 = 3

y1 = 5

Substitution

y - 5 = 4(x - 3)

Simplifying

y - 5 = 4x - 12

y = 4x - 12 + 5

Result

y = 4x - 7

FIRST ANSWER WILL GET BRAILIEST! AND 50 PTS!

Which division problem is represented with this model?
Responses

1/5÷6

1/6÷2

1/2÷5

1/5÷2

Answers

Answer:  Choice B

1/6÷2

Reason:

We have 6 slips of paper side by side. Shading one of those 6 represents the fraction 1/6.

Then split that shaded piece of paper in half as shown in the diagram. The blue region in that diagram represents 1/6÷2 which simplifies fully to 1/12.

If you were to do this to all 6 pieces of paper, then we'd have 2*6 = 12 smaller pieces. One of which is shaded, so that explains how we get 1/12.

In other words:

[tex]\frac{1}{6} \div 2 = \frac{1}{6} \times \frac{1}{2} = \frac{1}{12}[/tex]

What are the coordinates of the first and last two points of his route?

Answers

Answer:

Step-by-step explanation:

The table below shows the cost of mailing packages that weigh different amounts. Cost of Mailing Packages Package Weight (ounces) Cost Up to 1.00 $1.17 1.01 to 2.00 $1.34 2.01 to 3.00 $1.51 3.01 to 4.00 $1.68 4.01 to 5.00 $1.85 If the cost continues to increase as shown in the table, how much will it cost to mail a package that weighs exactly 11 ounces? F $2.87 G $4.87 H $3.04 J $5.87

Answers

The last one was about 3.04 so the next one should be 0.45

Rewrite the product (15y)(4x) using the Commutative Property of Multiplication.(15x)(4y)19xy(4x)(15y)(4y)(15x)

Answers

Answer:

(4x)(15y)

Explanation:

The commutative property of multiplication says that

(a)(b) = (b)(a)

Where a and b are the factors. In this case, the factors are 15y and 4x, so

(15y)(4x) = (4x)(15y)

Therefore, the answer is

(4x)(15y)

Suppose the main income of firms in the industry for a year is $80 million with a standard deviation of $13 million. If incomes for the industry are distributed normally what is the probability that a randomly selected firm will earn less than $96 million? Round your answer to four decimal places

Answers

Given that

The mean income of firms in the industry for a year is $80 million with a standard deviation of $13 million. and we have to find the probability that a randomly selected firm will earn less than $96 million.

Explanation -

We have to find the probability that a firm will earn less than $96 million.

The mean is $80 and the standard deviation is $13.

Then, it is written as

[tex]\begin{gathered} P(x<96)=P(z<\frac{96-80}{13}) \\ \\ The\text{ formula to find the z is \lparen here z is the z value\rparen} \\ z=\frac{x-\mu}{\sigma} \\ \mu\text{ is mean and }\sigma\text{ is the standard deviation.} \\ \\ P(<96)=P(z<\frac{16}{13})=P(z<1.2) \end{gathered}[/tex]

The table to find the z value is

According to the z table, the value will be

[tex]\begin{gathered} P(x<96)=P(z<1.2)=0.8849 \\ P(x<96)=88.49\% \end{gathered}[/tex]

Hence, 88.49% of the randomly selected firms will earn less than $96.

So the probability will be 0.8849.

Final answer -

The final answer is 0.8849 or 88.49%.

the following ordered pairs give the entrance exam scores x and the grade-point averages y after 1 year of college for 10 students.interpret the slope of the line in a relationship of the problem.

Answers

Find the slope

we take the points

(75,2.3) and (82,3)

so

m=(3-2.3)/(82-75)

m=0.7/7

m=0.1

the units of the slope are grade-point averages by entrance exam scores

Dertermine weshrer the fraction is 9 over 12 and 9 over 6 are equivalent

Answers

9/12 and 6/8 are equivalent fractions

Explanation:

[tex]\begin{gathered} \text{Given fractions:} \\ \frac{9}{12}\text{ and }\frac{6}{8} \end{gathered}[/tex][tex]\begin{gathered} \text{let's break down the fraction:} \\ \text{for }\frac{9}{12}\text{ we'll divide both numerator and denominator by 3} \\ \frac{9\div3}{12\div3}\text{ = }\frac{3}{4} \end{gathered}[/tex][tex]\begin{gathered} \text{for }\frac{6}{8},\text{ we will divide both numerator and denominator by 2} \\ \frac{6\div2}{8\div2}\text{ = }\frac{3}{4} \end{gathered}[/tex]

We can see when break down both fractions, their simplest term is the same.

Hence, 9/12 and 6/8 are equivalent fractions

What is the value of t? 76 T

Answers

Those are vertical angles, which are two non-adjacent angles formed by intersecting two lines. The intersection forms two pair of vertical angles. So:

[tex]m\angle t=76[/tex]

The problem is:The area of a square picture frame is 55 square inches. Find the length of one side of the frame. explain.Part A. Part B To the nearest whole inch. To the nearest 10th of an inch

Answers

Part A

area = 55 in²

The area of a square is given by:

area = side x side

So

55 in² = side x side

55 in² = side²

Taking the square root of both sides of the equation we get:

√55 in² = side

7 in = side

Part B

side = 7.4 in

The school band brought cheese and pepperoni pizzas in ratio represented in the tape diagram for their end of year party.

Answers

ANSWER

2 pepperoni pizzas

EXPLANATION

From the tape diagram, the ratio of cheese pizzas to pepperoni pizzas is:

3 : 1.

They bought 6 cheese pizzas.

Let the number of pepperoni pizzas be x.

So, by comparison, we have that:

3 : 1 = 6 : x

or

[tex]\begin{gathered} \frac{3}{1}\text{ = }\frac{6}{x} \\ \text{Cross multiply to find x:} \\ 3\cdot\text{ x = 6 }\cdot\text{ 1} \\ \text{Divide through by 3:} \\ x\text{ = }\frac{6}{3} \\ x\text{ = 2} \end{gathered}[/tex]

Therefore, they bought 2 pepperoni pizzas.

identify the correct trigonometry formula to use to solve for the given anglea. sin-¹(1.41)b. cos-¹(1.41)c. sin-¹(.71)d. tan-¹(.71)

Answers

The definition of arctan is opposit side by adjesent side.

[tex]\begin{gathered} \text{Angle}=tan^{-1}(\frac{Oppos\text{ side}}{\text{Adjesent side}}) \\ =\tan ^{-1}(\frac{34}{48}) \\ =\tan ^{-1}(0.71) \end{gathered}[/tex]

Thus, the correct option is option d.

60 is the LCM of witch of the following pair of numbers? 12 and 18 .....10 and 30.......15 and 20......20 and 25 witch on

Answers

The correct pair is 15 and 20

Here, we want to select the pair of numbers which 60 is their LCM

What this mean is we want to select two numbers that 60 is the smallest multiple they have

For 12 and 18, the lcm is 36; so this is incorrect

For 10 and 30, the lcm is 30; so this is also incorrect

for 20 and 25, the lcm is 100; this is also incorrect

for 15 and 20, the lcm is 60 and this is our correct choice

The first day they go to Dreamy Delights. Jack buys a cone with 3.0 oz of frozen yogurt for $9.20. Ianbuys a cone with 5.75 oz of frozen yogurt for $16.95.It says to summarize the information in a table

Answers

To summarize the information in a table:

In the column # of ounces of frozen yogurt put in the first cell the 3.0 oz that Jack bought and in the second cell the 5.75 oz that Ian bought.

In the column total cost in dollars put in the first cell the $9.20 that Jack paid and in the second cell the $16.95 that Ian paid

Solve the following quadratic equation using the quadratic formula in the picture: Problem: -3y^2 - 2y - 6 = 0

Answers

The given equation is,

[tex]-3y^2-2y-6=0[/tex]

Here, a = -3, b = -2, c = -6. Therefore, y can be calculated as,

[tex]\begin{gathered} y=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}=\frac{2\pm\sqrt[]{4-(4)(-3)(-6)}}{-6}=-\frac{1\pm\sqrt[]{-68}}{3} \\ =\frac{-1+\sqrt[]{68}}{3},\frac{-1-\sqrt[]{68}}{3} \end{gathered}[/tex]

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