In a poll, 50 residents in Greenville and Fairfield were asked whether they prefer swimming or jogging for exercise. This table shows the relative frequencies from the survey.The graph is in the pictureBased on the data in the table, which statements are true? Select all that apply.
Answers
Looking at the relative frequencies of the data in the table, these statements are true - "Greenville residents prefer jogging over swimming", "Fairfield residents prefer swimming over jogging", "People who prefer swimming are more likely to be from Fairfield", "People who prefer jogging are more likely to be from Greenville", "There is an association between the town a person lives in and their exercise preference".
It is given to us that -
50 residents in Greenville and Fairfield were asked whether they prefer swimming or jogging for exercise
The given table shows the relative frequencies from the survey.
We have to find out all the statements that are true about this survey.
Greenville people that like swimming = 0.18Greenville people that like jogging = 0.38=> Most Greenville residents prefer jogging over swimming
Similarly, we can see that
Fairfield residents prefer swimming over jogging (0.24>0.20)It can also be said true about the statements that -
People who prefer swimming are more likely to be from FairfieldPeople who prefer jogging are more likely to be from GreenvilleSince more people from Greenville prefers jogging to swimming and more people people from Fairfield prefers swimming to jogging, therefore "There is an association between the town a person lives in and their exercise preference"
Thus, according to the relative frequencies these statements are true - "Greenville residents prefer jogging over swimming", "Fairfield residents prefer swimming over jogging", "People who prefer swimming are more likely to be from Fairfield", "People who prefer jogging are more likely to be from Greenville", "There is an association between the town a person lives in and their exercise preference".
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Related Questions
There are 12 inches in 1 foot How many inches are in 2 feet? Enter your answer in the box There are inches in 2 feet.
Answers
24 "
1) Since there are 12 inches in 1 foot we can set a proportion, and find the missing measure:
inches feet
12 1
x 2
x = 12 * 2
x= 24
2) So there are 24 inches in 2 feet.
1/8, 2/7, 1/2, 4/5 what are the next two numbers?
Answers
ANSWER:
5/4 and 2
STEP-BY-STEP EXPLANATION:
If we look closely, we notice that the pattern is that 1 is added to the numerator and one is subtracted from the denominator, as follows:
[tex]\begin{gathered} \frac{1}{8} \\ \frac{1+1}{8-1}=\frac{2}{7} \\ \frac{2+1}{7-1}=\frac{3}{6}=\frac{1}{2} \\ \frac{3+1}{6-1}=\frac{4}{5} \\ \text{therefore, the next two numbers are:} \\ \frac{4+1}{5-1}=\frac{5}{4} \\ \frac{5+1}{4-1}=\frac{6}{3}=2 \end{gathered}[/tex]the product of a number of -9
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If we have a number x, if we take the product of this number by -9:
[tex]-9\cdot x[/tex]Hello! Please check the image attached to see the question!
Answers
To solve this question, we must break down the question into different scenarios.
The speed expression for the first rider is:
[tex]\begin{gathered} s=\frac{d}{t} \\ \text{let us make the distance the first rider covers as y.} \\ d=y\text{ miles} \\ t=3\text{ hours.} \\ s_1=\frac{y}{3} \end{gathered}[/tex]The speed expression for the second cyclist:
[tex]\begin{gathered} s=\frac{d}{t} \\ the\text{ first rider covered a distance of y miles, the remaining distance } \\ \text{left for the second cyclist to cover is:} \\ (108-y)\text{miles at the same time of 3 hours.} \\ s_2=\frac{108-y}{3} \end{gathered}[/tex]Since one cyclist cycles 3 times as fast as the other:
It is expressed thus:
[tex]\begin{gathered} s_1=3\times s_2 \\ s_1=3s_2 \end{gathered}[/tex]Now substitute the values for the speed expression into the expression above, we will have:
[tex]\frac{y}{3}=3\times(\frac{108-y}{3})[/tex]By solving the above expression, we will get the value of y (part of the distance travelled) and we can get the speed of the faster cyclist.
[tex]\begin{gathered} \frac{y}{3}=\frac{324-3y}{3} \\ y=324-3y \\ y+3y=324 \\ \end{gathered}[/tex][tex]\begin{gathered} 4y=324 \\ y=\frac{324}{4} \\ y=81\text{ miles.} \\ \\ So\text{ the speed of the faster cyclist will be:} \\ _{}=\frac{y}{3} \\ =\frac{81\text{ miles}}{3\text{ hours}} \\ =27mi\text{/h} \end{gathered}[/tex]The speed of the faster cyclist is 27 mi/h.
i need help woth this asap i cant get it wrong
Answers
The given equation is a quadratic equation. Recall, the standard form of a quadratic equation is expressed as
ax^2 + bx + c = 0
The given equation is
x^2 - 8x = - 128
By adding 128 to both sides of the equation, we have
x^2 - 8x + 128 = - 128 + 128
x^2 - 8x + 128 = 0
By comparing this equation with the standard form equation,
a = 1, b = - 8, c = 128
The formula for solving quadratic equations is expressed as
[tex]\begin{gathered} x\text{ = }\frac{-\text{ b }\pm\sqrt[]{b^2-4ac}}{2a} \\ By\text{ substituting the given values, it becomes} \\ x\text{ = }\frac{-\text{ - 8 }\pm\sqrt[]{-8^2-4(1\times128)}}{2\times1} \\ x\text{ = }\frac{8\pm\sqrt[]{64-512}}{2}\text{ = }\frac{8\pm\sqrt[]{-\text{ 448}}}{2}\text{ = }\frac{8\pm\sqrt[]{-64\text{ }\times\text{ 7}}}{2} \\ x\text{ }=\frac{8\pm(\sqrt[]{-64)}\times\sqrt[]{7}}{2} \\ \text{Note, }\sqrt[]{-\text{ 1}}\text{ = i} \\ \sqrt[]{-64}\text{ = 8i} \\ x\text{ = }\frac{8\pm8i\sqrt[]{7}}{2} \\ \text{Factoring out 2 in the numerator, we have} \\ x\text{ = }\frac{2(4\text{ }\pm4i\sqrt[]{7})}{2} \\ x\text{ = 4 }\pm4i\sqrt[]{7} \end{gathered}[/tex]Option A is correct
The Elimination MethodTry These BSolve each system using elimination.a. 7x+5y=-14x - y=-16
Answers
Elimination Method : In the elimination method you either add or subtract the equations to get an equation in one variable. When the coefficients of one variable are opposites you add the equations to eliminate a variable and when the coefficients of one variable are equal you subtract the equations to eliminate a variable.
The given system of equation:
7x + 5y = -1 (1)
4x - y = -16 (2)
Multiply the equation (2) by 5 :
5(4x -y ) = 5(-16)
20x - 5y = -80 (3)
Add equation (3) & (1)
(7x + 5y) + (20x -5y ) =(-1) + (-80)
7x + 5y + 20x - 5y = -1 - 80
27x = -81
x = -81/ 27
x = -3
Substitute the value of x =3 in the equation (1)
7x + 5y = -1
7(-3) + 5y = -1
-21 + 5y = -1
5y = -1 +21
5y = 20
y =20/5
y = 4
Thus, the solution of system is (x, y) = (-3, 4)
Answer : x =-3, y = 4
The regular price of an item is $350. The store is having a 25% off sale,plus an additional 20% off discount. What is the price, before tax, you would pay for this item?
Answers
the price before taxes is:
[tex]350\cdot0.75\cdot0.8=210[/tex]$210 is the price before taxes
y = 43 - 9Complete the missing value in the solution to theequation.(3,
Answers
We have the following:
[tex]y=4x-9[/tex]We have a solution pair is (x, y), in this case then x = 3, replacing we have
[tex]\begin{gathered} y=4\cdot3-9 \\ y=12-9 \\ y=3 \end{gathered}[/tex]The answer is: (3, 3)
The perimeter of triangle XYZ is 24 units.
What is the area of triangle XYZ? Round to the nearest
tenth of a square unit.
Trigonometric area formula: Area=1/2absin(C)
o 14.7
square units
14.9 square units
15.0 square units
15.3 square units
Answers
To the nearest tenth, the area of triangle XYZ is approximately 14.7 units².
What is a triangle?A triangle is a 3-sided polygon that is occasionally (though not frequently) referred to as the trigon.
There are three sides and three angles in every triangle, some of which may be the same.
Triangles can be divided into three groups based on the lengths of their sides, and these groups are as follows: Scalene, Isosceles, and Equilateral.
So, the area of the triangle is:
We know that:
<YXZ = 102°
Length of XY = z = 3
Length of YZ = x = 11
Length of XZ = y = ?
The perimeter of the triangle:
x+y+z = 24 units
Length XZ = y:
11+y+3 = 24
14+y = 24
y = 24 - 14
Therefore, y = 0.
Area of triangle XYZ:
The formula for trigonometric area is area of XYZ = 12(yz)sin X.
Putting values of x, y, and z as follows:
Area of ∆ XYZ = ½×10×3×sin 102
= ½×30×0.9782
= 15 × 0.9782
= 14.673
Therefore, to the nearest tenth, the area of triangle XYZ is approximately 14.7 units².
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Correct question:
What is the area of triangle XYZ? Round to the nearest tenth of a square unit. Trigonometric area formula: Area 14.7 square units 14.9 square units 15.0 square units 15.3 square units
12. Which of the following is a function?(A)(B)(C)(D) {(-5,9), (-2,-5),(1,-5),(5,-2)} (E){(-5,9),(-2,-5),(1,-5).(-5,-2)}
Answers
Explanation:
A relation is a function if and only if there is one value of x for different values of y.
This means that if we see repeated x-values then it's not a function. We can see this clearly in the graphs by drawing a vertical line for the values of x. Of the line crosses the graph more than once, then it's not a function.
In every graph the line crosses the graph more than once, so none of these options are functions.
Then, for a set of points we have to check the x-coordinate of each pair. If one repeats in the set, then it's not a function.
In the relation E x = -5 is repeated, so it's not a function. On the other hand, for relation D none of the x-coordinates are repeated. Therefore relation D IS a function
Answer:
Option D is a function
if angle 4 equals 140 what do the other angles equal to.
Answers
If m Angle EOF=26 and m Angle FOG=38, then what is the measure of Angle EOG? The diagram is not to scale.
Answers
Answer:
[tex]m\angle\text{EOG}=64^0[/tex]Explanation:
From the given statement.
[tex]\begin{gathered} m\angle\text{EOF}=26^0 \\ m\angle FOG=38^0 \end{gathered}[/tex]Now:
[tex]\begin{gathered} m\angle\text{EOG}=m\angle\text{EOF}+m\angle F\text{OG} \\ =26^0+38^0 \\ =64^0 \\ \text{Therefore:} \\ m\angle\text{EOG}=64^0 \end{gathered}[/tex]Is the expression below quadratic?3x + 5y - 2A. TrueB.False
Answers
A quadratic expression is given by the following form:
[tex]Ax^2+Bx+C[/tex]Therefore:
[tex]3x+5y-2[/tex]Is not a quadratic expression
When information is presented in the form of a bar graph or time- series graph, you could get more exact values if all the data were just listed out in table form. Then why not always do that. Why bother with graphs?
Answers
Step 1:
Graphs are essentially a visual display of quantitative information along two axes. Visuals are used as a way for our brains to quickly understand information, which is a powerful tool if used correctly. Graphs can show a large amount of data quickly in a way that is easy to process, without distracting people with a bunch of numbers.
What is an equation of the line that passes through the points (4,7) and (2,-1)? Answer in fully reduced form.
Answers
The eqaution of a line between two points is given by:
[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]Plugging our points we have:
[tex]\begin{gathered} y-(-7)=\frac{-1-(-7)}{2-4}(x-4) \\ y+7=\frac{6}{-2}(x-4) \\ y+7=-3(x-4) \\ y+7=-3x+12 \\ y=-3x+12-7 \\ y=-3x+5 \end{gathered}[/tex]Therefore the equation is:
[tex]y=-3x+5[/tex](3m + n )(3m − n )solve by using foil
Answers
Given: The expression below
[tex](3m+n)(3m-n)[/tex]To: Solve using foil
Solution
foil means
F---- FIRST
O- OUTER
I ---- INNER
L ----- LAST
Let us apply the foil method
Therefore,
[tex]\begin{gathered} (3m+n)(3m-n) \\ =3m\times3m+3m\times-n+n\times3m+n\times-n \\ =9m^2-3mn+3mn-n^2 \\ -3mn+3mn=0 \\ Therefore \\ (3m+n)(3m-n)=9m^2-n^2 \end{gathered}[/tex]Hence, the solution is
9m² - n²
Question Sally, an investor, purchases 3,000 shares in company X at $1.75 per share. After purchasing the shares the share price increases to $2.25 per share, after which Sally decides to sell her shares. Sally is required to pay 25% tax on all profits that she makes from the sale of the shares (called Capital Gains tax). Calculate the amount of tax that Sally must pay. Give your answer to the nearest dollar. Give your answer in dollars without the dollar sign or commas.
Answers
We are given the following information
Number of shares = 3,000
Buying price of a share = $1.75
Selling price of a share = $2.25
Capital Gains tax = 25% = 0.25
We are asked to calculate the amount of tax that Sally must pay.
Let us first calculate the profit.
Profit is given by
Profit = Selling price - Buying price
The buying price is given by
Buying price = (Number of shares)×(Buying price of a share)
Buying price = 3,000×1.75
Buying price = $5,250
The selling price is given by
Selling price = (Number of shares)×(Selling price of a share)
Selling price = 3,000×2.25
Selling price = $6,750
Profit = Selling price - Buying price
Profit = $6,750 - $5,250
Profit = $1,500
Finally, the amount of tax is given by
Amount of tax = profit × Capital Gains tax
Amount of tax = 1500 × 0.25
Amount of tax = $375
Therefore, Sally is required to pay a tax of $375
how to you write out and solve this math problem 1.79.1619.90
Answers
EXPLANATION
Considering the addition
Write the numbers one under the other, line up the decimal points.
Add trailing zeroes so the numbers have the same length.
1. 7 9
+ 0. 1 6
+ 1 9. 9 0
----------------
Add each columns of digits, starting on the right and working left.
If the sum of a column is more than ten, 'carry' digits to the net column on the left.
Add the digits of the bolded column: 9 + 6 + 0 = 15
0 1. 7 9
+ 0 0. 1 6
+ 1 9. 9 0
----------------
Carry 1 to the column on the left and write 5 in the bolded column:
1
0 1. 7 9
+ 0 0. 1 6
+ 1 9. 9 0
----------------
5
Add the digits of the bolded column: 1 + 7 + 1 + 9 = 18
1
0 1. 7 9
+ 0 0. 1 6
+ 1 9. 9 0
----------------
8 5
Carry 1 on the colum to the left and write 8 in the bolded column:
1 1
0 1. 7 9
+ 0 0. 1 6
+ 1 9. 9 0
----------------
8 5
Place the decimal point in the answer directly below the decimal points in the term:
1 1
0 1. 7 9
+ 0 0. 1 6
+ 1 9. 9 0
----------------
.8 5
Add the digits of the bolded column : 1 + 1 + 0 + 9 = 11
1 1
0 1. 7 9
+ 0 0. 1 6
+ 1 9. 9 0
----------------
.8 5
Carry 1 to the column on the left and write 1 in the bolded column:
1 1 1
0 1. 7 9
+ 0 0. 1 6
+ 1 9. 9 0
----------------
1 .8 5
Add the digits of the bolded column: 1 + 0 + 0 + 1 = 2
1 1 1
0 1. 7 9
+ 0 0. 1 6
+ 1 9. 9 0
----------------
2 1 .8 5
The answer is 21.85
rewrite using a single positive exponent (7^8)/(7^5)
Answers
Given
[tex]\frac{7^8}{7^5}[/tex]When you divide two exponents with the same base number, to simplify the expression you have to calculate the difference between the index from the numberator and the index from the denominator.
In this case the base number is "7"
The index of the numerator is "8"
The index of the denominator is "5"
You can simplify the expression as follows
[tex]\frac{7^8}{7^5}=7^{8-5}=7^3[/tex]The solution is
[tex]7^3[/tex]Which linear function has the greater rate of change, the one described by the equation y = 3x + 4 or the one described by the table? 1 WN X у 3 10 17 24 4 Choose the correct answer below. O A. The function for the table has the greater rate of change. OB. The function y = 3x + 4 has the greater rate of change.Table:x y1 32 103 174 24
Answers
The rate of change is equivalent to the slope in linear functions.
So, the bigger the slope, the greater the rate of change.
In the case of the linear function y=3x+4, the slope is m=3.
In the case of the table, we have to select two points in order to calculate the slope m.
We will pick the points (1,3) and (2,10).
Then, we can calculate the slope as:
[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{10-3}{2-1}=\frac{7}{1}=7[/tex]As the slope of the function in the table is bigger than the slope of the function y=3x+4, the function from the table has a greater rate of change.
[tex]\begin{gathered} m_t>m_f \\ 7>3 \end{gathered}[/tex]Answer: Option A (The function for the table has the greater rate of change)
6) 3x2 + 10X - 8We have to find the vertex
Answers
Given:
[tex]3x^2+10x-8[/tex]To find the vertex, use the vertex formula below:
[tex]y\text{ = }a(x-h)^2+k[/tex]Where the vertex is: (h, k)
Thus, we have:
[tex]y=3x^2+10x-8[/tex][tex]\begin{gathered} y+8=3x^2+10-8+8 \\ \\ y+8=3x^2+10 \end{gathered}[/tex]Factorize:
[tex]undefined[/tex]Helaine graphed the equation 12x-4y=3 . what was the slope of Helaines line
Answers
The slope of Helaine's line is 3
Explanations:Note that:
The slope - Intercept form of the equation of a line is:
y = mx + c
Where m = the slope
c = the intercept
The given equation is:
12x - 4y = 3
Rewrite the above equation in the form y = mx + c
4y = 12x - 3
Divide through by 4
[tex]\begin{gathered} \frac{4y}{4}=\frac{12x}{4}-\frac{3}{4} \\ \\ y\text{ = 3x - }\frac{3}{4} \end{gathered}[/tex]The slope, m = 3
The intercept, c = -3/4
Therefore, the slope of Helaines line is 3
Determine the volume of the rectangular prism.3 cm3 cm5 1/4cm
Answers
Answer:
47.25 cubic centimetres
Explanation:
The volume of the prism is the product of its dimensions.
[tex]3\operatorname{cm}\times5\frac{1}{4}cm\times3\operatorname{cm}[/tex]Now,
[tex]5\frac{1}{4}=5+\frac{1}{4}[/tex]multiplying 5 by 4/4 gives
[tex]\frac{4\cdot5}{4}+\frac{1}{4}[/tex][tex]=\frac{21}{4}[/tex]Therefore,
[tex]3\operatorname{cm}\times5\frac{1}{4}cm\times3\operatorname{cm}=3\operatorname{cm}\times\frac{21}{4}cm\times3\operatorname{cm}[/tex][tex]=3\cdot\frac{21}{4}\cdot3\operatorname{cm}^3[/tex][tex]=\frac{3\cdot21\cdot3}{4}cm^3[/tex][tex]=\frac{189}{4}cm^3[/tex][tex]=47.25\operatorname{cm}^3[/tex]paper: 100 sheets for $.99, 500 sheets for $4.29. Which is a better buy?
Answers
Answer:
the second option/ 500 sheets for 4.29
Step-by-step explanation:
Answer:
sheets for 4.29 is better buy
Find square root of 49 Find square root of 100
Answers
We are asked to determine the square root of 49, this is written mathematically as:
[tex]\sqrt[]{49}[/tex]This means that we need to determine a number that when multiplied twice yields 49, that is:
[tex]7\times7=49[/tex]Therefore:
[tex]\sqrt[]{49}=7[/tex]If the m angle3 is 112 then find the value of the missing angle measure
Answers
Question:
Solution:
According to the diagram, we get the following equations:
Equation 1:
[tex]m\angle1\text{ + m}\angle2=180^{\circ}[/tex]Equation 2:
[tex]m\angle4\text{ + m}\angle3=180^{\circ}[/tex]the angle 3 is 112 degrees, so replacing this value into the previous equation, we get:
[tex]m\angle4+112^{\circ}=180^{\circ}[/tex]solving for angle 4, we get:
[tex]m\angle4\text{ }=180^{\circ}-112^{\circ}=68^{\circ}[/tex]now, note that
Equation 3:
[tex]m\angle4\text{ + m}\angle1=180^{\circ}[/tex]but the angle 4 is 68 degrees, so replacing this into the above equation, we get:
[tex]68^{\circ}\text{ + m}\angle1=180^{\circ}[/tex]solving for angle 1, we get :
[tex]\text{ m}\angle1=180^{\circ}-68^{\circ}=112^{\circ}[/tex]Finally, from equation 1, we get:
[tex]112^{\circ}\text{ + m}\angle2=180^{\circ}[/tex]then,
[tex]\text{ m}\angle2=180^{\circ}-112^{\circ}=68^{\circ}[/tex]we can conclude that the correct answer is:
[tex]\text{ m}\angle1=112^{\circ}[/tex][tex]\text{ m}\angle2=68^{\circ}[/tex][tex]\text{ m}\angle3=112^{\circ}[/tex][tex]m\angle4\text{ =}68^{\circ}[/tex]
Can someone please help me with this ? I just need the answer
Answers
SOLUTION:
The graph of g(x) is the graph of f(x) translated 5 units to the left.
Thus, the equation is;
[tex]g(x)=(x+5)^2[/tex]What is 57.629 in expanded form?
Answers
To write a number in expanded form, we have to separate it to see the math value of individual digits.
In this case, for the number 57.629, the expanded form is:
[tex]57.629=50+7+0.6+0.02+0.009[/tex]Name the type of angle relationship. If no relationship exists, write "none. a. <1 and < 8 b. < 2 and < 3 C. < 5 and <7 d. < 2 and < 7 e. <1 and < 3 f. < 5 and <8
Answers
Answers:
a. ∠1 and ∠8: Alternate exterior Angles.
b. ∠2 and ∠3: None
c. ∠5 and ∠7: Corresponding angles.
d. ∠2 and ∠7: Alternate interior angles.
e. ∠1 and ∠3: Corresponding angles
f. ∠5 and ∠8: None
Explanation:
a. ∠1 and ∠8: Alternate exterior Angles. They are externals, on opposite sides, and they are formed by the transversal of two lines.
b. ∠2 and ∠3: None
c. ∠5 and ∠7: Corresponding angles. One is internal and the other is external and they are on the same side of the transversal.
d. ∠2 and ∠7: Alternate interior angles. They are interior, on opposite sides, and they are formed by the transversal of two lines.
e. ∠1 and ∠3: Corresponding angles. One is internal and the other is external and they are on the same side of the transversal.
f. ∠5 and ∠8: None
Over the past 6 seasons, one baseball player's batting averages were 0.248, 0.302, 0.248, 0.307, 0.295, and 0.369. A second player's batting averages were 0.349, 0.231, 0.272,0.263, 0.275, and 0.384. What are the range and mean of each player's batting averages? Use your results to compare the players' batting skills.Find the range and mean of the first player's batting averages.The range is (Type an integer or a decimal.)(Round to the nearest thousandth as needed.)The mean is
Answers
First let's write down the batting averages of the first player in ascending order:-
0.248, 0.248, 0.295, 0.302, 0,307, 0,369
The difference between the largest value and the minimum value will give us the range:-
So range for the first player will be = 0.369 - 0.248 = 0.121
Now let;s calculate the mean of the first palyer's batting averages
[tex]\begin{gathered} \text{Mean}_1=\frac{0.248+0.248+0.295+0.302+0.307+0.369}{6} \\ =\frac{1.769}{6} \\ =0.295\text{ (approx)} \end{gathered}[/tex]Now let's write down the batting averages of the second player in ascending order
0.231, 0.263, 0.272, 0.275, 0.349, 0.384
So the range for second player will be:-
0.384-0.231= 0.153
Now let;s calculate the mean of the second palyer's batting averages
[tex]\begin{gathered} \operatorname{mean}=\frac{0.231+0.263+0.272+0.275+0.349+0.384}{6} \\ =\frac{1.774}{6} \\ =0.296(approx) \end{gathered}[/tex]The mean for second player is 0.296 (approx)
And the mean for the first player is 0.295 (approx)
Since the mean avarage of both the players is almost same but the range of second player is more than that of first player, so the second player has good batting skills as compared to the first player.