in 1989, at solar maximum, there were 157 sunspots visible during the year. what would be the next year you would expect to observe about the same number of sunspots?

Answers

Answer 1

The next solar maximus which will be visible with 157 or close to 157 sunspots will be visible after 11 years. which is 2000.

Sunspots are formed in region of higher magnetic field, they appear dark on the surface of the Sun.

Solar maximus is nothing but the regular amount of period of the greatest solar activity during the sun's 11 year solar cycle.

It was not exactly 157 but 140 sunspots were seen in 2000.

As the year follows, the sunspots are becoming lesser and lesser.

This data is yearly created by NASA.

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Related Questions

An ice skater is spinning with her arms out and is not being acted upon by an external torque. When she pulls her arms in close to her body what happens to her angular velocity?

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When she pulls her arms in close to her body, the thing that happens to her angular velocity is that When she pulls her arms in, her rate of spin increases significantly, which reduces her moment of inertia. She exerts effort to pull in her arms, which causes rotational kinetic energy to rise.

What is the angular momentum conservation law?

If there is no net external torque surrounding a location in a fixed inertial reference frame, the angular momentum of the system of particles around that point is conserved:

The overall angular momentum is conserved, as you can see. As long as the aggregate is constant, any one of the constituent angular momenta can change. When there is no external force acting on a system, this equation is equivalent to the conservation of linear momentum.

Therefore, since an ice skater performing a spin as an illustration of the conservation of angular momentum. Because there is hardly any friction between her skates and the ice, the net torque on her is almost nil. Additionally, the friction is applied quite near the pivot.

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two slits of widtheach in an opaquematerial, are separated by a center-to-centerdistance ofa monochromatic light ofwavelength 450 nm is incident on the double-slit. one finds a combined interference anddiffraction pattern on the screen.(a) how many peaks of the interference will beobserved in the central maximum of thediffraction pattern?(b) how many peaks of the interference will beobserved if the slit width is doubled whilekeeping the distance between the slits same?(c) how many peaks of interference will beobserved if the slits are separated by twice thedistance, that is,while keeping thewidths of the slits same?(d) what will happen in (a) if instead of 450-nmlight another light of wavelength 680 nm isused?(e) what is the value of the ratio of the intensityof the central peak to the intensity of the nextbright peak in (a)?(f) does this ratio depend on the wavelength ofthe light?(g) does this ratio depend on the width orseparation of the slits?

Answers

The distance between the slits and the fringe width are inversely proportional. When the distance between the slits is doubled, the fringe's width is reduced by half.

What diffraction and interference pattern is mixed on the screen?

Diffraction. Interference is described as occurring when waves from two different independent sources have differing wavefronts. Diffraction, on the other hand, is described as secondary waves that split off from the primary wave.

Therefore, each wavelength's waves will produce a different type of interference pattern if white light is employed in Young's experiment instead of monochromatic light. The overall result of all these designs may be seen on the screen. Consequently, the middle white fringe.

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Light passes through the entire thickness of the neural layer of the retina to excite the photoreceptors. A) True B) False

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It is true to say that the light passes through the entire thickness of the neural layer of the retina to excite the photoreceptors. So,correct option is A.

At the point when the light raises a ruckus around town (a light-touchy layer of tissue at the rear of the eye), extraordinary cells called photoreceptors transform the light into the electrical signs. These electrical signs travel from the retina through the optic nerve to the cerebrum.

The vision cycle depends intensely on the capacity of the eye to refract light. This happens at both the cornea and the focal point of the eye. The course of vision initially begins with the light going through the cornea. Since the cornea has a round surface it behaves like a uniting focal point.

Hence, option A is correct.

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Jacky starts biking to meet up with her friend. She determines that she will be 3 minutes late if she bikes at a speed of 10 mph and 2 minutes early if she goes 12 mph. How much time does she have left before the appointed meeting time?.

Answers

There are 26.88 minutes left before Jacky's scheduled time.

Let x be the separation between Jacky & her buddies.

Let t be the typical travel time that Jacky would take to go to her friend's house.

Time = Distance ÷ Speed

He will arrive at the meeting three minutes late if she rides at a speed of 10 mph.

Time of lateness in hours = 3 ÷ 60 = 0.05 hours

t  +  0.05  =  x ÷ 10

10t  +  0.5  =  x

She will arrive two minutes before the scheduled meeting time if she rides at a speed of 12 mph.

2 seconds equal 0.033 hours

t  -  0.033 = x ÷ 12

12t  -  0.396  =  x

Compare equations from 10t  +  0.5  =  x and 12t  -  0.396  =  x.

10t  +  0.5   =  12t  -  0.396

12t  -  10t  =  0.5  + 0.396

2t   =  0.896

t   =  0.896/2

t  =  0.448 hours

t  =  0.448  x  60

t   =  28.88 minutes

Jacky has 27 minutes well before the scheduled time or 26.88 minutes.

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Anna and jon sit on a seesaw. Anna has a mass of 60 kg and sits 2 m from the center. Jon has a mass of 70 kg. How far from the center should jon sit so the seesaw is balanced?.

Answers

In order to balance the seesaw, John should sit at a distance of 1.7m from the center.

This question can be solved using the concept of moment. in order to balance on the seesaw the moment on the center of seesaw should be zero or in other words

∑M = 0

Now, the moment is expressed by the formula

∑M = F × d

where, ∑M is the Algebraic sum of moments in the center of the balance, M is the moment in the center point ( N*m), F is the Force (N) and d is the distance of the force to the the center point(N*m).

Now, we have

Mass of Anna (M) = 60kg

Mass of John (m) = 70kg

Distance from Anna to the center of the seesaw (dA) = 2m

Distance from John to the center of the seesaw (dJ) = ?

Acceleration due to gravity (g) = 9.8 m/s²

Also, W = mass × g. So, W = Anna's weight and w = John's weight

Now, to find the distance we write the Moment equation as

∑M = 0

(W)(dA) - (W)(dJ) = 0

(M*g)(dA) - (m*g)(dJ) = 0

We divide the equation by g

(M)(dA) - (m)(dJ)= 0

(M)(dA) = (m)(dJ)

dJ = M(dA)/m

dJ = 60×2/70

dJ = 120/70

dJ = 1.7m which is distance of John from center.

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The demon drop rode at cedar point amusement park falls freely for 4.33 an after starting from rest. What is it’s velocity at the end of this time?

Answers

The velocity of the rode at the end of the time 4.33 seconds is 42.434 m/s.

What is velocity?

Velocity is the rate of change of displacement.

To calculate the velocity of the, we use the formula below.

Formula:

v = u+gt................. Equation 1

Where:

v = Velocity at the end of the timeu = Initial velocityg = Acceleration due to gravityt = Time

From the question,

Given:

u = 0 m/s (From rest)g = 9.8 m/s²t = 4.33 seconds

Substitute these values into equation 1

v = 0+9.8×4.33v = 42.434 m/s

Hence, the velocity at the end of the time is 42.434 m/s.

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if the rectangular barge is 3.5 m by 24.0 m and sits 0.70 m deep in the harbor, how deep will it sit in the river?

Answers

By using Archimedes Principle the Barge will sit at a depth of 0.7203 m

What is Archimedes Principle?

The buoyancy of any floating object partially or totally submerged in a fluid can be computed thanks to Archimedes' principle. The weight of the thing alone exerts a downward force on it. The upward or buoyant force acting on the object is what is meant by the aforementioned Archimedes' principle. The difference between the buoyant force and the object's weight is therefore the net force acting on it. In the event that this net force is positive, the item will rise; in the event that it is negative, the object will sink; and in the event that it is zero, the object will be neutrally buoyant, remaining stationary.

Calculation:

The harbour contains salt water while the river contains fresh water. So assuming that the densities of fresh water and salt water are:

density (salt water) = 1029 kg / [tex]m^3[/tex]

density (fresh water) = 1000 kg / [tex]m^3[/tex]

The amount of water (in mass) displaced by the barge should be equal in two waters.

mass displaced (salt water) = mass displaced (fresh water)

Since mass is also the product of density and volume,

therefore:

[density * volume] of salt water = [density * volume] of fresh water

First we calculate the amount of volume displaced in the harbour (salt water):

V = [tex]3.5 m\ X\ 24.0 m\ X\ 0.70 m[/tex]

V = [tex]58.8 m^3[/tex] of salt water

Plugging in the values into equation 1:

1029 kg /  [tex]m^3[/tex] × 58.8 m^3 = 1000 kg/[tex]m^3[/tex]× Volume fresh water

Volume fresh water displaced = 60.5052 [tex]m^3[/tex]

Therefore the depth of the barge in the river is:

60.5052 [tex]m^3[/tex] = 3.5 m × 24.0 m × h

h = 0.7203 m

By using Archimedes Principle the Barge will sit at a depth of 0.7203 m

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a diatomic ideal gas at pressure p and volume v is expanding to three times its initial volume under constant pressure. t or f

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True. A diatomic ideal gas at pressure P and volume V is expanding to three times its initial volume under constant pressure.

Pressure Variations of a Diatomic Ideal Gas During Expansion

The pressure of the gas will remain constant as the volume expands, therefore the ideal gas law states that the product of pressure and volume will remain constant, meaning the pressure will decrease as the volume increases.

As the diatomic ideal gas expands to three times its initial volume, the pressure of the gas will remain constant due to the ideal gas law, which states that the product of pressure and volume must remain constant. As the volume of the gas increases, the pressure must decrease in order to maintain the constant product. Therefore, although the pressure remains constant, the volume of the gas will increase three-fold.

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Calculate the wavelength (in m) of a 9. 81-g bullet traveling at 1769 miles per hour.

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A bullet that has a mass of 9.81 g traveling at 1769 miles per hour has a wavelength of 0.85 x 10⁻³⁴ m

De Broglie wave

A physicist "Louis de Broglie" put forward a hypothesis that particles can also be treated as particles as well as waves. Using theoretical concepts from black body radiation, de Broglie showed a relationship expressing momentum with wavelength. This equation is derived from the energy equation for a photon in black body radiation. The energy of a photon is a function of the wavelength of the photon.

The equation is:

λ = h/p

We have,

Mass of the bullet = 9.81 g = 0.00981 kg

v = 1769 mph ⇒ 790.81 ms⁻¹

h =  Planck's constant ⇒ 6.63 x 10⁻³⁴ m²kg⁻¹

Determine the momentum (p) of the bullet first,

P = mv

= (0.00981) (790.81 )

= 7.75 kgms⁻¹

So, the wavelength of the bullet:

λ =  6.63 x 10⁻³⁴ / 7.75

= 0.85 x 10⁻³⁴ m

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The theory that dark matter is not real and is just a a problem with our theory of gravity has been falsified by:_______.

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The theory that dark matter is not real and is just a problem with our theory of gravity has been falsified by an observation of what happens when clusters of galaxies collide. The term dark matter was coined in 1933 by Fritz Zwicky.

The observed evidence for dark matter is quite strong, and we know it's unlikely to be a mathematical artifact because different galaxies appear to have different amounts of dark matter, with some not having any at all. If our model of gravity were in error, we would expect to see the same error in all galaxies we observe. This is not the case.

Instead, we observe that some galaxies behave exactly as the model says they should, and some behave as if they're heavier than they ought to be.

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a fire truck is driving quickly toward you with siren blaring. how does the frequency of the sound change compared to a siren at rest?

Answers

The frequency of the sound will increase as the fire truck approaches, as the sound waves are compressed together, creating a higher pitch. As the fire truck passes by, the frequency will gradually decrease, as the sound waves spread out, creating a lower pitch.

The frequency of the sound produced by a fire truck siren changes as it approaches. This is because of the Doppler effect, which states that the frequency of sound waves increases as the source of the sound approaches, and decreases as it moves away.

Step 1: When the firetruck is at rest, the sound waves emitted by the siren travel in a straight line in all directions. This means that the frequency of the sound waves heard at any given point is the same as the frequency emitted by the siren.

Step 2: As the fire truck moves closer to the observer, the sound waves leave the siren at a faster rate than when the truck was at rest. This causes the sound waves to bunch up closer together, which in turn causes the frequency of the sound to increase.

Step 3: As the fire truck continues to move closer to the observer, the sound waves continue to bunch up, resulting in an even higher frequency of sound.

Step 4: Finally, when the fire truck passes the observer, the sound waves start to spread apart again. This causes the frequency of the sound to decrease.

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a possible means for making an airplane invisible to radar is to coat the plane with an antireflective polymer. if radar waves have a wavelength of 3.00 cm and the index of refraction of the polymer is n 5 1.50, how thick would you make the coating?

Answers

The coating should be made 0.5 cm thick.

Wavelength of the radar waves = λ = 3 cm

Index of refraction of the polymer = n = 1.50

Thickness required = t

Generally the equation for Destructive interference for Normal incidence is mathematically given by:

= 2 X n X t = 0.5 X m X λ

If we calculate at minimum thickness, then m = 1.

Thus, thickness = t =

= 2 X n X t = 0.5 X  λ

= 2 X 1.5 X t = 0.5 X 3

= t = (0.5 X 3) / (2 X 1.5)

= t = 0.5 cm

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A wave has a speed of 15 m/s and a frequency of 10 Hz. what is the wavelenght of the wave?

Answers

Answer:

1.5 m

Explanation:

speed=frequency*wavelength

15=10*wavelength

A 8. 0-m long wire with a mass of 10 g is under tension. A transverse wave for which the frequency is 570 hz, the wavelength is 0. 10 m, and the amplitude is 3. 7 mm is propagating on the wire. The maximum transverse acceleration of a point on a wire is closest to.

Answers

The maximum transverse acceleration of a point on a wire is 47410.0839m/sec² having mass of 10g.

Transverse Wave travels from highest point of positive amplitude to negative highest point amplitude. Amplitude is the point where potential energy of wave is highest. Transverse wave travels in definite direction. We have mass=10g=0.001kg,length of wire is 8m,frequency of transverse wave is 570Hz,wavelength =0.10m

Now, we need to transverse wave acceleration, for this we need angular frequency because there is co-relation between transverse wave acceleration and angular frequency.

We know that angular frequency=2πf where f is the angular frequency.

ω=2×π×570

=>ω=2×3.14×570

=>ω=6.28×570

=>ω=3579.6/sec

Now, for acceleration we know that =ω²A where A is the amplitude of the wave.

=>a = (3579.6)²×3.7mm

=>a=((3579.6)²×3.7×1/1000)m/sec²

=>a=[(12813,536.2)×3.7×1]/1000m/sec²

=>a=47410083.8/1000m/sec²

=>a=47410.0839m/sec²

Hence, maximum transverse acceleration is 47410.0839m/sec²

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A box slides on the ground. It has a 20N applied force pushing it to the right. The friction between the box and the ground is 8N. What is the magnitude of the net force on the box?

Answers

Answer:

12 N

Explanation:

Fnet = 20 N - 8 N = 12 N

Force of friction is always in the direction opposite to the direction of motion of the object.  

Underline the statements you think are true:
Gravity depends on the material of the objects.
.Gravity is not a force because it can’t move objects.
Gravity is a force because a force is a push or a pull.
The moon has less gravity than the Earth because it has less mass than the Earth.
The moon has less gravity than the Earth because it has no atmosphere.

Answers

The  statements that I  think are true are:

Gravity depends on the material of the objects.Gravity is a force because a force is a push or a pull.What is gravity?

Gravity can be described as the force by which a planet or other body draws objects toward its center however the force of gravity keeps all of the planets in orbit around the sun.

It should be noted that Gravity do depends on the material of the objects however the Gravity can not be regrded as force because it can't move objects but can be consdidered as the force because a force is a push or a pull, as it can be seen in hoiw the  moon has less gravity than the Earth because it has less mass than the Earth.

In conclusion, Gravity depends on the material of the objects and it should be noted that Gravity is a force because a force is a push or a pull.

Therefore, option A and C are correct.

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How did you determine the coordinates of the vertices of the dilated image?

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To dilate something in the coordinate plane, we need to multiply each coordinate by the scale factor. This is called mapping. A scale factor is labeled \(k\).e (x,y)→(kx,ky).

For any dilation, the mapping has a center and a scale factor. The center is the point of reference for the dilation, and the scale factor tells us how much the figure stretches or shrinks.

A dilation of a triangle is a stretch or a shrink of a triangle by a scale factor. The scale factor for dilation is the proportion by which the original figure is stretched or shrunk. The center of dilation is a reference point by which the dilation of a figure is stretched or shrunk.

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What happens when a rock is under pressure?

Answers

Answer: Stress that makes one rock squeeze or push against another.

Explanation:

calculate the mass (in kg) of 4.87 x 1025 atoms of zn. calculate the mass (in kg) of 4.87 x 1025 atoms of zn. 5.29 kg 1.24 kg 1.89 kg 8.09 kg 1.09 kg.

Answers

5.29 kg is the mass of 4.87 x 10²⁵ atoms of Zn.

What is mass?

As a measure of inertia, which is a fundamental characteristic of all matter, mass is used in physics. It essentially refers to a body of matter's resistance to changing its speed or location in response to the application of a force.The symbol for mass is m or M. The force exerted on a mass as a result of the acceleration brought on by gravity is measured as weight. W typically stands for weight.

As, we know

Mass of 1 mole of Zn = 65.38 gm/mole

= (65.38/1000) kg/mole

= 0.06538 kg/mole

We know,1 mole = 6.023 × 10²³ atoms.

Thus, moles of Zn = 4.87 × 10²⁵ / 6.023 × 10²³

= 80.87 moles

Therefore, mass of Zn = 80.87 moles × 0.06538 kg/mole

= 5.287 kg ≈ 5.29 kg

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the total number of points of work a team can accomplish in each scrum period is called . group of answer choices speed degree velocity score

Answers

The total number of points of work, a team can accomplish in each scrum period is called velocity.

The high data growth speed is another thing is currently a problem. In a way, this problem is closely related to the data volume problem, because the speed of data created is generally directly proportional to the data volume. Data not only come in large numbers but also in a shorter tempo and even some that are real-time.

The burden of storing and processing data in a data warehouse will be more useful if it is utilized for data that is directly related to the business - transaction, financial and consumer data.

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the human ear canal is, on average, 2.5cm long and aids in hearing by acting like a resonant cavity that is closed on one end and open on the other. the length of the ear canal is partially responsible for our sensitivities to certain frequencies. use 340m/s for the speed of sound when performing the following calculations.Part A
What is the first resonant frequency?
Part B
What is the wavelength at second resonance?
Part C
How does the first resonant frequency change if the ear canal is full of water?Part D
At a listener's ear, the intensity of a conversation is 4×10−6W/m24×10−6W/m2 and a typical adult's ear has a surface area of 210×10−3m2210×10−3m2. What is the power of the sound waves on the ear?
Part E
Long-term exposure to loud noises can damage hearing. If a loud machine produces sounds with an intensity level of 100dB100dB, what would the intensity level be if the intensity were reduced by a factor of 4?

Answers

The first resonance frequency is 3400 Hz and the wavelength at second frequency is 3.33 cm. After the ear canal is full of water the first resonance frequency increases. The power of sound waves on the year is  840 X 10⁻⁹ W and if the intensity of sound is reduced by a factor of 4, then the intensity level will be 135 dB.

(a) The ear, being open at one end and closed at the other, is equivalent to a closed pipe. For a closed pipe, the first resonant frequency occurs when one quarter of the wavelength is equal to the length of the pipe.

= λ/4 = l

= λ = 4l

Now, Speed is given by

= v = fλ

where f = frequency

= f = v/λ

At the first resonant frequency,

= f = v/λ

= f = v/4l

= f = 340 / (4 X 2.5 X 10⁻²) m

= f = 3400 Hz

(b) At second resonance,

= (3/4)λ = l

= λ = (4/3) X l

= λ = (4/3) X 2.5 X 10⁻²

= λ = 3.33 cm

(c) Since, sound travels faster in a liquid than in gas, the first resonance frequency increases when the ear canal is filled with water as speed increases. This is because, speed is directly proportional to intensity.

(d) Intensity = i = 4 X 10⁻⁶ W/m²
Surface area = a = 210 X 10 ⁻³ m²

Power of the sound waves = p =

= p = i X a

= p = 4 X 10⁻⁶ X 210 X 10 ⁻³

= p = 840 X 10⁻⁹ W

(e) Intensity level = l = 100 dB

If the intensity is reduced by 4, then using the relationship between decibel and sound intensity is :

= β = 10 X log(I₁ / I₂)

= β = 10 log (0.25/10⁻¹²) dB

=  β = 135 dB

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a 2 mm diameter meteor of specific gravity 2.9 has a speed of 6 km/s at an altitude of 50,000 m where the air density is 1.03 x 10-3 kg/m3. if the drag coefficient at this large mach number condition is 1.5, determine the deceleration of the meteor.

Answers

A 2 mm diameter meteor of specific gravity 2.9 has a speed of 6 km/s at an altitude of 50,000 m where the air density is 1.03 x 10-3 kg/m3. if the drag coefficient at this large number condition is 1.5, 5km/s is the deceleration of the meteor.

A material's density in respect to a standard substance is determined by its specific gravity, also referred to as relative density. When comparing the densities of solids like meteor and liquids, water is commonly used as a reference because it has a density of one kilogram per litre at 4 °C (39.2 °F) (62.4 pounds per cubic foot). At standard conditions (0 °C and 1 standard atmosphere), dry air, which is widely used to compare gases, has a density of 1.29 grams per litre (1.29 ounces per cubic foot). For instance, liquid mercury has a density of 13.6 kg per litre and a specific gravity of 13.6. Even though it has a standard density of 1.976 grams per litre, the gas carbon dioxide has a specific gravity of 1.53 (= 1.976/1.29). The ideas of specific gravity and buoyancy, or an object's propensity to float in water or the atmosphere, are interrelated.

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The specific gravity of an material is defined as the ratio of the density of the material to the density of water. The specific gravity of ice is 0.917, whereas that of seawater is 1.025.What fraction of an iceberg is above the surface of the water?

Answers

The fraction of the ice that lies above the water is obtained as 0.11.

What is the density?

We know that the term density has to do with the ratio of the mass to the volume of an object. In this case we can see that the density has to be looked upon as a kind of property that we can use so as to obtain the identity of a given material.

In this case, we can see that what we have been given in each case is the specific gravity. However, the specific gravity is the ratio of the density of the object to the density of water.

Thus;

Density of ice = 0.917 g/cm^3

Density of sea water =  1.025 g/cm^3

Then we know that the fraction that is above the surface of the water can be obtained by the use of the formula;

Volume above = Density of liquid - Density of ice/ Density of liquid

Volume above =   1.025  - 0.917/ 1.025

= 0.11

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a particle moves along the x-axis. the velocity of the particle at time t is 2 6 . t t - what is the total distance traveled by the particle from time t

Answers

The total distance  of the particle is 7.33

How to calculate total distance ?

Distance is the sum of an object's movements, regardless of direction. Distance can be defined as the amount of space an object has covered, regardless of its starting or ending position.

The distance between two sites is the length of the route. The metric unit of length is the metre.

It's interesting to observe that while some physics symbols, like "d" for distance, are extremely relatable, others, like "c" for light speed, are not.

The distance formula is a formula used to determine how far apart two places are from one another. The dimensions of these points are unlimited.

Given,

Distance s = ∫03It2 - 6t + 8Idt

= ∫02(t2 - 6t + 8)dt + ∫23(6t - t2 - 8)dt

= (t3/3 - 3t2 + 8t)02 + (3t2 - t3/3 - 8t)23

=(8/3 - 12 + 16) + (27 - 9 - 24) - (12 - 8/3 - 16)

= 20/3 - 6  + 20/3 = 22/3

=7.33

Therefore the total distance is 7.33

The complete question is : A particle travels along the x-axis so that at time t≥0 its velocity is given by v(t)=t2−6t+8. What is the total distance the particle travels from t = 0 to t = 3?

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Where is infrared located on the electromagnetic spectrum in relation to other kinds of radiation?

Answers

Infrared rays are located in the electromagnetic spectrum between radio waves and gamma waves.

Electro magnetic radiation travels in waves, just like waves in an ocean. The energy of the radiation depends on the distance between the crests (highest points) of the waves, or the wavelength. In general, the smaller the wavelength, the higher the energy of the radiation. Gamma rays have wavelengths less than ten trillionths of a meter which is about the size of the nucleus of an atom. This means that gamma rays have very high energy.

Radio waves, on the other hand, have wavelengths that range from less than one centi-meter to greater than 100 metres. The energy of radio waves is much lower than the energy of other types of electro magnetic radiation. The only type of light detectable by the human eye is visible light. It has wavelengths about the size of a bacteria cell and its energies fall between those of radio waves and gamma rays.

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What is the frequency of a wave Travelling at 500 m/s with a wavelength of 25 m?

Answers

The frequency of the travelling wave is found to be 20 Hertz.

The relationship between the frequency of the wave, the wavelength of the wave and the speed of the wave is given by

V = fy

Where,

V is the speed of the travelling wave,

F is the frequency of the travelling wave,

y is the wavelength of the travelling wave.

The speed of the travelling wave is given to be 500m/s and the wavelength of the travelling wave is 25m.

Now, putting all the values,

500 = f(25)

f = 500/25

f = 20Hz

So, the frequency of the travelling wave is 20Hz.

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4. A truck travels a curve of radius 10 m at 18 km/hr on a force of 15000 N. What is the mass of the truck?​

Answers

Answer:

The mass of the truck is 1500 Kg.

Explanation:

Given;F = 15000 N

We know that,

F = mg

g = acceleration due to gravity = 10m/s²

m = F/g

m = 15000/10

m = 1500 Kg

m = 1500 KgThus, The mass of the truck is 1500 Kg.

A star is born when
A. it first starts to fuse hydrogen into helium.
B. it first starts to fuse helium into hydrogen.
C. it gets its first planet.
D. when it goes supernova.

Answers

I believe it’s A it first starts to fuse hydrogen into helium

in a movie, a superhero stops an 8 gram bullet moving at 400 m s-1 with his hand. his hand provides an impulse to stop the bullet. the average force provided to the bullet during the time of contact is 1200 newton. a. calculate the time of contact with the hand before the bullet comes to rest. b. calculate the work done by the hand in bringing the bullet to rest. c. calculate how far back the hand has been displaced. d. calculate the change in the kinetic energy of the bullet..

Answers

The bullet's kinetic energy is 4000N.

What exactly is kinetic energy?

To accelerate an item, we must apply force to it. We must make an attempt to utilise force. When work is done on an item, energy is transferred, and the object then travels at a new, constant speed. The energy conveyed is known as kinetic energy, and it is affected by the mass and speed obtained.

Kinetic energy is defined in physics as follows:

The amount of work an item can do while moving is measured by its kinetic energy.

According to the information provided:

mass=10g=10/1000=0.01kg

Initial velocity=u=200m/s

0 m/s final velocity

S=5cm=5/100=0.05m

Using the third equation of motion: V²-u²=2as

0²-(200) ²=2a*0.05

-40000=a/10

a=-400000m/s²

Newton's Second Law states:

F=ma

=0.01*(-400000)

=-4000N

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Kinetic energy is a form of energy that an object or a particle has by reason of its motion. If work, which transfers energy, is done on an object by applying a net force, the object speeds up and thereby gains kinetic energy.

What exactly is kinetic energy?

To accelerate an item, we must apply force to it. We must make an attempt to utilise force. When work is done on an item, energy is transferred, and the object then travels at a new, constant speed. The energy conveyed is known as kinetic energy, and it is affected by the mass and speed obtained.

Kinetic energy is defined in physics as follows:

The amount of work an item can do while moving is measured by its kinetic energy.

According to the information provided:

mass=10g=10/1000=0.01kg

Initial velocity=u=200m/s

0 m/s final velocity

S=5cm=5/100=0.05m

Using the third equation of motion: V²-u²=2as

0²-(200) ²=2a*0.05

-40000=a/10

a=-400000m/s²

Newton's Second Law states:

F=ma

=0.01*(-400000)

=-4000N

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What is the relationship between heat and pressure?

Answers

The relationship between heat and pressure is that they are directly proportional to each other by Gay-lussac law.

What is Heat?

Heat is the energy that moves from one thing to another when temperatures are different. Heat passes from the hotter to the colder body when two bodies with different temperatures are brought together. Usually, but not consistently, this energy transfer results in a rise in the heat of the colder body and a fall in the temperature of the hotter body.

By switching from one physical situation (or phase) to the other, such as melting from a solid to a liquid, sublimation from a solid to a vapor, boiling from a liquid to steam or changing from one stable state to another, a substance can absorb heat without increasing in temperature.

The relationship between pressure and temperature for a given volume of gas is straightforward. Pressure rises in systems when temperature increases, and vice versa. The Gay-law Lussac specifies the link between a gas's pressure and temperature.

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