I’m sorry to keep bothering you guys but you’re the third person that I’m trying the last two their answers went partway and then stopped I just need to see how this is worked out

Im Sorry To Keep Bothering You Guys But Youre The Third Person That Im Trying The Last Two Their Answers

Answers

Answer 1

In this case, we'll have to carry out several steps to find the solution.

Step 01

Data:

Graph:

Height of Golf Ball

Step 02:

functions:

We must analyze the graph to find the solution.

Function:

Non linear

intercepts:

x-intercepts: 0 and 120

y-intercept: 0

symmetry:

x = 50

positive:

domain: (0 , 120)

negative:

there are no negative values

increasing:

interval on x: (0 , 50)

decreasing:

interval on x: (50, 120)

That is the full solution.


Related Questions

hi please help me tysmYour mother places 6 flowers in a vase. How many vases does your mother need for 30 flowers?A. 9B. 7C. 5D. 3

Answers

SOLUTION:

Step 1:

In this question, we are given the following:

Your mother placed 6 flowers in a vase.

How many vases does your mother need for 30 flowers?

Step 2:

The details of the solutions are as follows:

[tex]\begin{gathered} 6\text{ flowers = 1 vase} \\ \text{Then, we have that:} \\ 30\text{ flowers = }\frac{(30\text{ x 1)}}{6}=\frac{30}{6}=\text{ 5 vases ( OPTION C)} \end{gathered}[/tex]



Consider the polynomial
1/2a^4 + 3a³ + a.
1) What is the coefficient of the third term?
2) What is the constant term?

Answers

1) The coefficient of the third term is one.

2) The constant term is zero.

We are given a polynomial. A polynomial is a mathematical statement made up of indeterminates and coefficients that solely includes the operations of addition, subtraction, multiplication, and positive integer powers of variables. The polynomial is (1/2)a^4 + 3a³ + a. The polynomial has the variable "a". The polynomial has three terms. So, it is a trinomial. The third term of the polynomial is "a". The coefficient of the third term is 1. There is no constant term in the polynomial. So, we can say that the constant term is 0.

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In a textbook, 900 digits are used for the page numbers. How many pagesare in the textbook, starting with page 1? (Hint: First find how many digitsare used for pages 1-9 and 10-99.)

Answers

Given:

900 digits are used for the page numbers. How many pages are in the textbook, starting with page 1

We will find the number of the pages of the book as follows

The number of digits from 1 to 9 = 9

The number of digits from 10 to 99:

There are 90 numbers, each number has 2 digits

So, the number of digits from 10 to 99 = 90 x 2 = 180

The number of digits from 100 to 999:

There are 900 numbers, and each number has 3 digits

so, the number of digits from 100 to 999 = 900 x 3 = 2700

The overall digits are given = 900

So, number of digits from 1 to 99 = 9 + 180 = 189

Subtract 189 from 900 = 900 - 189 = 711

Divide 711 by 3 = 237

So, the number of pages that have 3 digits = 237

So, the number of pages of the book = 237 + 99 = 336

So, the answer will be 336 pages

What percentage is 1 m longer than 1 yard? Round to one tenth percent. 1 yard = 91.4 cm

Answers

[tex]\begin{gathered} 1m=1.09361\text{ yard} \\ 1\text{ yard=91.44cm} \\ That\text{ means that }meter\text{ is 8.56}cm\text{ longer than }a\text{ yard} \\ So\text{ from the above data }meter\text{ is 10\% longer than a yard.} \end{gathered}[/tex]

What is the average rate of change of f(x) from x1=-10 to x2=-3? Please write your answer rounded to the nearest hundredth. f(x)= the square root of -9x+5

Answers

We have the following information

[tex]\begin{gathered} x_1=-10 \\ x_2=-3 \end{gathered}[/tex]

and the function

[tex]f(x)=\sqrt[]{-9x+5}[/tex]

In order to find the average rate, we need to find y1 and y2. Then, by substituting x1 into the function, we have

[tex]\begin{gathered} f(-10)=\sqrt[]{-9(-10)+5} \\ f(-10)=\sqrt[]{90+5} \\ f(-10)=\sqrt[]{95} \end{gathered}[/tex]

Similarly, by substituting x2, we get

[tex]\begin{gathered} f(-3)=\sqrt[]{-9(-3)+5} \\ f(-3)=\sqrt[]{27+5} \\ f(-3)=\sqrt[]{32} \end{gathered}[/tex]

Therefore, the average rate is given by

[tex]\frac{f(x_2)-f(x_1)}{x_2-x_1}=\frac{\sqrt[]{32}-\sqrt[]{95}}{-3-(-10)}[/tex]

which gives

[tex]\begin{gathered} \frac{f(x_2)-f(x_1)}{x_2-x_1}=\frac{\sqrt[]{32}-\sqrt[]{95}}{7} \\ \frac{f(x_2)-f(x_1)}{x_2-x_1}=\frac{5.6568-9.7467}{7} \\ \frac{f(x_2)-f(x_1)}{x_2-x_1}=-\frac{4.0899}{7} \end{gathered}[/tex]

Therefore, the average rate is

[tex]\frac{f(x_2)-f(x_1)}{x_2-x_1}=-0.58[/tex]

Solve equations x-27=56

Answers

Answer:

x = 83

Step-by-step explanation:

Add 27 to both sides

x - 27 +27 = 56 + 27

x = 83

Find the z-value so that the area to the left of z (shaded in the picture) is 0.9131.

Answers

area shaded to the left = 0.9131

by using the Z cumulative table , we can see that the value that corresponds with Z= 0.913 is 0.838

Translate thefollowing phaseinto an inequality-3 times r is at least 33A) inequality B) Solve the equality for r.C) express the solution in interval notation.

Answers

Given the phrase:

-3 times r is at least 33

Let's translate the given phrase into an inequality.

• Part A.

Let's figure out the inequality in steps.

-3 times r is written as:

-3r

-3 times s is at least 33 means that -3r is greater than or equal to 33.

Hence, we have the inequality:

[tex]-3r\ge33[/tex]

• Part B.

Let's solve the inequality for r.

To solve for r, divide both sides of the inequality by -3:

[tex]\begin{gathered} \frac{-3r}{-3}\ge\frac{33}{-3} \\ \\ r\le-11 \end{gathered}[/tex]

• Part C.

Let's express the solution in interval notation.

Here, the solution is:

[tex]r\le-11[/tex]

It means s must be less than or equal to 11.

Therefore, the solution in interval notation is:

[tex](-\infty,-11\rbrack[/tex]

ANSWER:

• A) -3r ≥ 33

• B) r ≤ -11

• C) (-∞, -11]

Yea I think and if it’s ok we

Answers

Explanation: To solve a derivate we can use a simple technique presented below

- First, we take the exponent and multiply it by the function. Second, we subtract a unit of the exponent. Let's visualize it better on the drawing below

Step 1: Now we can use the same concept to calculate all the derivates we need as follows

Final answer: So the final answers are

[tex]\begin{gathered} letter_{\text{ }}a=5x^4 \\ letter_{\text{ }}b=20x^3 \\ letter_{\text{ }}c=60x^2 \\ letter_{\text{ }}d=120x \end{gathered}[/tex]

.

S-7>3Help please !Don’t really understand

Answers

The given inequality is

[tex]s-7>3[/tex]

To solve it, we need to isolate s on one side and the numerical terms on the other side

To do that we need to move 7 from the left side to the right side with 3, so

Add 7 to both sides

[tex]\begin{gathered} s-7+7>3+7 \\ s+0>10 \\ s>10 \end{gathered}[/tex]

The solution of the inequality is s > 10

We can represent it on the number line

3. When people take medicine, the drug gets metabolized by the body and eliminated at a constant rate.Suppose the initial amount of a drug in the body is 549 mg and it is eliminated at a rate of 12% per hour.Let f(x) refer to the amount of drug left in the body after I hours.(a) Write down an exponential function to model this situation. Write your answer using functionnotation(b) How much of the drug is left in the body after 12 hours? Round to the nearest whole number.(c) How much of the drug is left in the body after 180 minutes? Round to the nearest whole number

Answers

When people take medicine, the drug gets metabolized by the body and eliminated at a constant rate.

Suppose the initial amount of a drug in the body is 549 mg and it is eliminated at a rate of 12% per hour.

Let f(x) refer to the amount of drug left in the body after I hours.

(a) Write down an exponential function to model this situation. Write your answer using function

notation

(b) How much of the drug is left in the body after 12 hours? Round to the nearest whole number.

(c) How much of the drug is left in the body after 180 minutes? Round to the nearest whole number

Part a)

Let

t -----> number of hours

f(x)=a(1+r)^t

where

a=549 mg

r=12%=0.12

substitute

f(x)=549(1+0.12)^t

f(x)=549(1.12)^t

Part b)

For t=12 hours

substitute in the function

f(12)=549(1.12)^12

f(12)=2,139 mg

Part c)

For t=180 minutes

Remember that

1 h=60 minutes

so

180 minutes=180/60=3 hours

For t=3 hours

substitute

f(3)=549(1.12)^3

f(3)=771 mg

An eighth-grade student estimated that she needs $8,800 for tuition and fees for each year of college. She already has $5,000 in a savings account. The table shows the projected future value of the account in five years based on different monthly deposits.future value of a savings account. initial balance, dollars, $5000, $5000, $5000, $5000. Monthly deposit, dollars. $100, $200, $300, $400. Account value in five years, dollars. $12,273; $18,737; $25,202; $31,667.The student wants to have enough money saved in five years to pay the tuition and fees for her first two years of college. Based on the table, what is the minimum amount she should deposit in the savings account every month?AnswerF$200G$300H$100J$400

Answers

Since each year cost $8,800 for two years tuition he will need $17,600 then if he want to save at least this much in five years according to the table he needs to save $200 monthly

Use the factor theorem to determine whether x-2 is a factor

Answers

Factor theorem is usually used to factor and find the roots of polynomials. A root or zero is where the polynomial is equal to zero. Therefore, the theorem simply states that when f(k) = 0, then (x – k) is a factor of f(x).

In this case here, let's find out if 2 is a root of the polynomial given.

As we can see in the box below, 2 is not a root of the polynomial, therefore (x-2) isn't a factor.

[tex]\begin{gathered} P(x)=-2x^3+4x^2-4x-7 \\ P(2)=-2\cdot2^3+4\cdot2^2-4\cdot2-7 \\ P(2)=-16+16-8-7 \\ P(2)=-15 \end{gathered}[/tex]

If h(x) = 3(x2 + 1) - 6, what is the value of h(10)?

Answers

[tex]\begin{gathered} h(x)=3(x^2^{}+1)-6 \\ \text{when they ask by h(10) you must substitute 10 in the place of x:} \\ h(10)=3(10^2+1)-6 \\ h(10)=3(100+1)-6 \\ h(10)=3(101)-6 \\ h(10)=303-6 \\ h(10)=297 \end{gathered}[/tex]

Which sequence of rigid motions will definitely work to take triangle RPQ onto triangle CAB?

Answers

RPQ to CAB transform

Rotation needed = RPQ using C as center ,an angle ACP

Translations= Line RC

Reflections= None

Then answer is

Option D)

Translate RPQ by the direct line segment RC

The figure below is a net for a right rectangular prism. Its surface area is 384 cm2 andthe area of some of the faces are filled in below. Find the area of the missing faces,and the missing dimension.Yes

Answers

Solution

For this case we know the total surface area given by:

384 cm^2

And we have the following: 108+48 +108+48 = 312 cm^2

the ramianing area is:

384 -312= 72 cm^2

And we can do the following:

2*9*? = 72

Solving for ? we got:

? = 72/18 = 4 cm

the final answer is:

The area of each missing face is: 36 cm^2

The lenght of each missing edge is: 4 cm

Identify an angle That's congruent to < PQR in the given figure.

Answers

You need to rotate the figure to see the new orientation

If the product is 900, and the two of its three factors are 3 and 50, what is the third factor?

Answers

We have the multiplication of 3 factors, one of them unknown, that give 900 as a result.

We can write this as:

[tex]\begin{gathered} 3\cdot50\cdot x=900 \\ 150x=900 \\ x=\frac{900}{150} \\ x=6 \end{gathered}[/tex]

The third factor is 6.

Please help solve the following questions using the exponential equation

Answers

SOLUTION

We want to solve

[tex]7^{2x+4}=2^{x-5}[/tex]

Taking logarithm of both sides, we have

[tex]\begin{gathered} \log 7^{2x+4}=\log 2^{x-5} \\ (2x+4)\log 7=(x-5)\log 2 \\ \text{expanding we have } \\ (2x)\log 7+(4)\log 7=(x)\log 2-(5)\log 2 \end{gathered}[/tex]

Collecting like terms we have

[tex]\begin{gathered} (2x)\log 7-(x)\log 2=-(4)\log 7-(5)\log 2 \\ x(2\log 7-\log 2)=-4\log 7-5\log 2 \\ \text{dividing both sides by }(2\log 7-\log 2),\text{ we have } \\ x=\frac{-4\log 7-5\log 2}{2\log 7-\log 2} \end{gathered}[/tex]

Hence the solution set expressed in terms of logarithm is

[tex]x=\frac{-4\log7-5\log2}{2\log7-\log2}[/tex]

Using a calculator to obtain a decimal approximation, we have

[tex]\begin{gathered} x=\frac{-4\log7-5\log2}{2\log7-\log2} \\ x=\frac{-3.3804-1.5051}{1.6902-0.3010} \\ x=\frac{-4.8855}{1.3892} \\ x=-3.51677 \\ x=-3.52 \end{gathered}[/tex]

Hence the answer is -3.52 to 2 decimal places

based on the side lengths given (a, b, and c), which triangles are right triangles????A. a=4, b=6, c=8B. a=6, b=8, c=10C. a=5, b=6, c=(square root of) 61D. a=6, b=9, c=12 PLEASE HELP!!

Answers

Explanation

From the question, a right-angle triangle must obey Pythagoras theorem. Therefore, we can see that

[tex]6^2+8^2=10^2\text{ also, }5^2+6^2=(\sqrt{61})^2[/tex]

The rest of the values do not obey Pythagoras theorem. Therefore;

Answer: Option B and Option C

Use any method to add or subtract (1 point)
5/7 - (3/14 + 3/14)

Answers

Answer:

5/7 - (3/14 + 3/14) = 2/7

See the steps of solution:

5/7 - (3/14 + 3/14) =           Solve parenthesis first5/7 - (3 + 3)/14 =                Add fractions with same denominator5/7 - 6/14 =                        Simplify5/7 - 3/7 =                         Subtract fractions with same denominator(5 - 3)/7 =                           Simplify2/7                                     Answer

Answer:

2/7 (or) 0.285

Step-by-step explanation:

Given problem,

→ 5/7 - (3/14 + 3/14)

Let's solve the given problem,

→ 5/7 - (3/14 + 3/14)

→ (5/7) - (6/14)

→ ((5 × 2)/(7 × 2)) - (6/14)

→ (10/14) - (6/14)

→ (10 - 6)/14

→ 4/14 = 2/7

Hence, required answer is 2/7.

Two electrical lines are parallel to each other. One of the lines is represented by theequation - 4x + y = 8. What is the slope of the other electrical line?

Answers

[tex]\begin{gathered} \text{ the slope- intercept form of the equation is } \\ y=4x+8 \\ \\ \text{ thus the slope is 4, and the slope of the other electrical line is 4} \end{gathered}[/tex]

Solve the system by substitution.y =10xY=4x+22

Answers

Given the system:

[tex]\begin{cases}y=10x \\ y=4x+22\end{cases}[/tex]

Let's clear x from equation 1:

[tex]\begin{gathered} y=10x\rightarrow\frac{y}{10}=x \\ \rightarrow x=\frac{y}{10}\text{ (A)} \end{gathered}[/tex]

And substitute (A) in equation 2:

[tex]\begin{gathered} y=4x+22 \\ \rightarrow y=4(\frac{y}{10})+22 \\ \rightarrow y=\frac{4}{10}y+22 \end{gathered}[/tex]

Solving for y:

[tex]\begin{gathered} y=\frac{4}{10}y+22 \\ \rightarrow y-\frac{4}{10}y=22 \\ \rightarrow\frac{3}{5}y=22\rightarrow3y=110\rightarrow y=\frac{110}{3} \end{gathered}[/tex]

Now, let's use (A) to calculate x:

[tex]\begin{gathered} x=\frac{y}{10} \\ \rightarrow x=\frac{\frac{110}{3}}{\frac{10}{1}}\rightarrow x=\frac{110}{30}\rightarrow x=\frac{11}{3} \end{gathered}[/tex]

This way,

[tex]\begin{gathered} x=\frac{11}{3} \\ \\ y=\frac{110}{3} \end{gathered}[/tex]

[tex]4a ^{2} - 12a - 16[/tex]I need help factoring

Answers

4(a-4)(a+1)

1) Factorizing 4a²-12a -16

4a²-12a -16 Note that the GCD (4,12,16) is 4, Rewrite them

4a²- 4*3a - 4* 4

2) 4(a² -3a -4) Rewrite a² -3a -4 answering the question, What are the numbers whose sum is 3 and product is 4?

Answer:

1 -4 = -3

1 x -4 = -4

3) Hence, the answer is:

4a²-12a -16= 4(a-4)(a+1)

Abrha lives in an apartment and pays the following expenses each month: electric bill, $44.90; TV streaming service, $24.99; and rent, $625.85 Estimate his total expenses for the month by first rounding each value to the nearest tens place.

Answer: $700

Answers

Abrha will be spending $701 monthly, just by arithmetic operation.

What is the arithmetic operation?

The four fundamental operations of arithmetic are addition, subtraction, multiplication, and division of two or more quantities. Included in them is the study of numbers, especially the order of operations, which is important for all other areas of mathematics, including algebra, data management, and geometry. The rules of arithmetic operations are required in order to answer the problem.

If the numerator is bigger, it is referred to as an improper fraction and can also be expressed as a mixed number, which is a whole-number quotient with a proper-fraction remainder.

Abrha lives in an apartment,

electric bill, $44.90 = $50

TV streaming service, $24.99  = $25

Rent, $625.85 = $626

So the Total expenses will be (50+25+626) = $701 just by arithmetic operation

Hence Abrha will be spending $701 monthly.

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#3) Ulices was charged $140 plus a pick up charge of $20 to ship 4 identical boxesbys Fast Ship. The pick up charge applies regardless of how many boxes are pickedup. What would have been the change to Ulices' account if he had shipped just 1box?

Answers

To determine the Ulices's account if he shipped just 1 box, calculate the charge for one box. To calculate the charge, compute the quotient between the charge for 4 boxes between 4 boxes, just as folow:

charge per one box = 140/4 = 35

Hence, for 1 box the charge is $35

Due to it is necessary to pay $20 idependenty of the number of boxex, you sum $20 to the cost for one box:

New Ulices's account = $35 + $20 = $55

Hence, Ulices's account would have been of $55

it says (6^2)^2 then it says select one Add, Subtract, Multiply

Answers

Multiply

Here, we want to select the arithmetic operation that could be used to evaluate the given indices expression

The key to solving this is to use an important indices relationship

That is;

[tex](a^x)^y=a^{xy}[/tex]

Hence, we have to multiply the powers

So the correct option here is multiply

Which is the degree measure of an angle whose tangent is 1.19? Round the answer to the nearest whole number.

Answers

We know that:

[tex]\tan\theta=1.19[/tex]

where theta is the angle we are trying to find; to get the angle we take the inverse tangent at both sides of the equation. Then:

[tex]\begin{gathered} \tan^{-1}(\tan\theta)=\tan^{-1}1.19 \\ \theta=50 \end{gathered}[/tex]

Therefore, the angle we are looking for is 50°

1 금35Lolo19.Which type of variation is modeled in the table?jointdirectcombinedInverse

Answers

The answer to your question is inverse varaiation.

Explanation: Inverse variation is a reciprocal term. Or say a variable is increasing while the other is decreasing.

So it is observed that as when y increases, then x decreases.

And also when y decreases, then x increases.

Thus, It is an inverse variation.

i need help asap with this (Its ACD and not AGD just incase that confuses you)

Answers

4)

In the case of a square, its diagonals are equal and bisect each other, meeting at 90°.

In our case, using a diagram,

Therefore,

[tex]\begin{gathered} a+2b=90 \\ and \\ 2a-b=90 \end{gathered}[/tex]

Solving the system of equations for a and b,

[tex]\begin{gathered} \Rightarrow a=90-2b \\ \Rightarrow2(90-2b)-b=90 \\ \Rightarrow5b=90 \\ \Rightarrow b=18 \end{gathered}[/tex]

Finding a,

[tex]\begin{gathered} b=18 \\ \Rightarrow a=90-2*18=90-36=54 \end{gathered}[/tex]The answers are a=54, b=18

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