If ABCD is a square, and the area covered by the blue equilateral triangle is 49√3cm², what will be the area covered by the yellow region (in cm²)?



a. 139
b. 98
c.42
d. 154

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49√3 = √3/4 a²

49×4 = a²

a = 7×2

a = 14 cm

Side of equilateral triangle = Side of square ABCD = 14cm

Area of square ABCD = a²

A = 14×14

A = 196 cm²

Now diameter of circle = side of square = 14cm

Radius = D/2 = 7 Cm

There are two half circle in the square = one whole circle

Area of circle = πr²

A = 3.14 ×7 ×7

A = 153.86

Area of yellow region = Area of square - Area of circle

Area of yellow region = 196 - 153.86 = 42.14 Cm²

The area covered by the yellow region (in cm²) in the given diagram is 42cm². The correct option is c.42

From the question, the area of the blue equilateral triangle in the given diagram is 49√3cm².

The area of an equilateral triangle can be calculated by finding half the product of the square of a side (all sides are equal in an equilateral triangle) and sin 60° (each interior angle of an equilateral triangle is 60°)

Hence, the area of the blue triangle is given by

[tex]A = \frac{1}{2}/AB/^{2}sin60\°[/tex]

Where A is the area

Therefore,

[tex]49\sqrt{3} = \frac{1}{2}/AB/^{2}sin60\°\\2 \times 49\sqrt{3} = /AB/^{2} \times \frac{\sqrt{3} }{2}[/tex]

[tex]2 \times2 \times 49\sqrt{3} = /AB/^{2} \times \sqrt{3}[/tex]

[tex]196 \sqrt{3} = /AB/^{2} \times \sqrt{3}[/tex]

∴ [tex]/AB/^{2} = \frac{196 \sqrt{3} }{\sqrt{3} }[/tex]

[tex]/AB/^{2} = 196[/tex]

∴ [tex]/AB/ = \sqrt{196}[/tex]

[tex]/AB/ = 14cm[/tex]

Hence, the length of a side of the square is 14 cm and the diameter of the circle is also 14 cm (since the length of a side of the square cuts the circle into equal halves, hence it is the diameter)

Area covered by the yellow region = Area of the square - ( sum of the areas of the two semicircles)

Sum of the areas of the two semicircles = Area of one circle

Area of a circle is given by the formula

[tex]A = \pi r^{2}[/tex]

But r = d/2

where r is radius and d is diameter

∴ r = 14/2 cm

r = 7cm

Hence

Area of the circle = [tex]\pi \times 7^{2}[/tex]

A = [tex]49\pi[/tex]

Taking π = 22/7

∴ A = [tex]49 \times \frac{22}{7}[/tex]

A = 154cm²

This is the sum of areas of the two semicircles

Now, for the area of the square

Area of the square = /AB/²

∴ Area of the square = 196 cm²

Now, as stated earlier,

Area covered by the yellow region = Area of the square - ( sum of the areas of the two semicircles)

∴ Area covered by the yellow region = 196 cm² - 154cm²

Area covered by the yellow region = 42cm²

Hence, the area covered by the yellow region (in cm²) in the given diagram is 42cm²

The correct option is c.42

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