Step 1:
Write the expression
[tex](3x^5\text{ - }\frac{1}{9}y^3)^4[/tex]Step 2:
a)
[tex]\begin{gathered} (3x^5\text{ - }\frac{1}{9}y^3)^4 \\ =^4C_0(3x^5)^4(-\frac{1}{9}y^3)^0+^4C_1(3x^5)^3(-\frac{1}{9}y^3)^1+^4C_2(3x^5)^2(-\frac{1}{9}y^3)^2+ \\ +^4C_1(3x^5)^1(-\frac{1}{9}y^3)^3+^4C_0(3x^5_{})^0(-\frac{1}{9}y^3)^4 \end{gathered}[/tex]Step 3:
b) simplified terms of the expression
[tex]\begin{gathered} Note\colon \\ ^4C_0\text{ = 1} \\ ^4C_1\text{ = 4} \\ ^4C_2\text{ = 6} \\ ^4C_3\text{ = 4} \\ ^4C_4\text{ = 1} \end{gathered}[/tex]Next, substitute in the expression
[tex]\begin{gathered} =\text{ 1}\times81x^{20}\times1\text{ - 4}\times27x^{15}\text{ }\times\text{ }\frac{y^3}{9}\text{ + 6 }\times9x^{10}\times\frac{y^6}{81}\text{ - 4}\times3x^5\text{ }\times\text{ }\frac{y^9}{729} \\ +\text{ 1 }\times\text{ 1 }\times\frac{y^{12}}{6561}\text{ } \end{gathered}[/tex][tex]=81x^{20}-12x^{15}y^3\text{ + }\frac{2}{3}x^{10}y^6\text{ - }\frac{4}{243}x^5y^9\text{ + }\frac{1}{6561}y^{12}[/tex]Solve the equation.– 2y - 15 = 4y + 15y=
Given the equation;
[tex]-2y-15\text{ = 4y+15}[/tex]You are to calculate the value of y. This is as shown below;
First collect the like terms;
[tex]\begin{gathered} -2y\text{ - 4y = 15+15} \\ \end{gathered}[/tex]Evaaluate the expression an find y;
[tex]\begin{gathered} -6y=30 \\ \end{gathered}[/tex]Divide both sides by -6;
[tex]\begin{gathered} \frac{-6y}{-6}=\frac{30}{-6} \\ y\text{ = -5} \end{gathered}[/tex]Hence the value of y is -5
Graph the polar equation.P = 16 cos20帶이
To make the graph we need to make a table with different pairs of angles and radius.
We can start with θ = 0, and calculate the radius for different values of θ. (π/6, π/3, π/4 and so on. Then, you can join the points.
The equation for radius will be:
[tex]\begin{gathered} r^2=16\cos 2\theta \\ r=\sqrt[]{16\cos2\theta} \\ r=4\cdot\sqrt[]{\cos2\theta} \end{gathered}[/tex][tex]\begin{gathered} \text{for }\theta=0 \\ r=4\cdot\sqrt[]{\cos2\cdot0} \\ r=4\cdot\sqrt[]{\cos0} \\ r=4\cdot\sqrt[]{1} \\ r=4 \end{gathered}[/tex]Then, in the line of θ = 0, you draw a point in the fourth circle.
Then, we get the following table of values:
θ r
04.00
π/63.72
π/43.36
π/32.83
π/20.00
Note that we can't evaluate angles whose cosine is negative (angles in quadrants 2 and 3) since we would be trying to calculate the square root of a negative number, which does not exist among real numbers. Then, we will evaluate angles in the first quadrant (already done) and the 4th quadrant.
θ r
-π/63.72
-π/43.36
-π/32.83
-π/20.00
In the last table we use negative angles, they can be "translated" to positive:
-π/6= π/6
-π/4= 7π/4
-π/3= 5π/3
-π/2= 3π/2
Now, we can draw the points:
Joining the points:
Solve M=2rt^3-3rx for x
You have the following equation:
M = 2rt³ - 3rx
In order to solve the previous equation for x, proceed as follow:
M = 2rt³ - 3rx subtract 2rt³ both sides
M - 2rt³ = -3rx divide by -3r both sides
(M - 2rt³)/(-3r) = x simplify left side
-M/3r + 2/3 t³ = x
Use your number sense to find the values for x and y that satisfy the equations.4y = 8
y = 2
Explanation:The given equation is 4y
Divide both sides of the equation by 4
[tex]\begin{gathered} \frac{4y}{4}=\frac{8}{4} \\ \end{gathered}[/tex]y = 2
Also, since we are asked to use our number sense, we can find what we will multiply by 4 to give 8
Since 4 x 2 = 8, then y = 2
i have an answer in mind i just need to make sure its correct
The names of the angles are ; ∠XYZ , ∠ ZYX or ∠1
Here, we want to give three different ways in which we can name the angle
To name the angle, we can use the two end points and the location of the angle itself as angle
This can be ∠ZYX or ∠XYZ
Lastly, we can make use of the labeling on the angle itself
The name can be ∠1
A triangle has side lengths of 5,6 and 8. Is it a right triangle?Explain why or why not?
ANSWER
Not a right triangle
EXPLANATION
In a right triangle, the hypotenuse is always the longest side. If these are the side lengths of a right triangle, the sides would be,
The Pythagorean theorem must be true for any right triangle,
[tex]8^2=5^2+6^2[/tex]Let's see if it is indeed true,
[tex]64=25+36[/tex][tex]64=61\to not.true[/tex]If the Pytagorean theorem is nort true, then this is not a right triangle
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Given,
g(x) = - x^2
now, in part (b), we have to find g(-2)
It can be done by replacing the value of x with -2, so
g(x) = - x^2
g(-2) = - (-2)^2
g(-2) = - 4
Part d:
g(m) = ?
So, here we will put the 'm' value in place of x.
g(x) = - x^2
g(m) = - (m)^2
g(m) = -m^2
5. An expression is shown. 78 - 14 Between which two consecutive whole numbers does this value lie? Enter your numbers in the box. Between and
78 divide by 14
First, divide the numbers
78/14 = 5.57
5.57 lies between 5 and 6
The perimeter of a rectangular pool is 44 feet. The length is 8ft longer than the width. Find the dimensions.
Given:
A rectangular pool with the following measures,
Perimeter
Length = x + 8
Width = x
Let's determine the measure of its dimensions:
[tex]\text{ Perimeter = 2L + 2W}[/tex][tex]\text{ = 2(x + 8) + 2(x)}[/tex][tex]\text{ 44 = 2x + 16 + 2x}[/tex][tex]\text{ 44 = 4x + 16}[/tex][tex]\text{ 44 - 16 = 4x}[/tex][tex]\text{ 28 = 4x}[/tex][tex]\text{ }\frac{28}{4}\text{ = }\frac{4x\text{ }}{4}[/tex][tex]\text{ 7 = x}[/tex]Let's now determine its dimensions,
Length = x + 8 = 7 + 8 = 15 ft.
Width = x = 7 ft.
Therefore, the dimension of the rectangular pool is Length = 15 ft. and Width =7 ft.
Question 7 using radians, find the amplitudeand period of each function and graph it
Given:
y = 4 sin 4θ
The amplitude is 4.
Period:
[tex]\begin{gathered} P=\frac{2π}{B};\text{ }hence: \\ \\ P=\frac{2π}{4}=\frac{π}{2} \end{gathered}[/tex]The period is π/2.
Graph:
Use the system of equations below to solve for z.7x+3y+2z-4w=184w+5x-3y-2z=6-2w-3x+y+z=-52z+3w+4y-8x=11253
Equations:
[tex]\begin{gathered} 7x+3y+2z-4w=18\text{ \lparen1\rparen} \\ 5x-3y-2z+4w=6\text{ \lparen2\rparen} \\ -3x+y+z-2w=-5\text{ \lparen3\rparen} \\ -8x+4y+2z+3w=11\text{ \lparen4\rparen} \end{gathered}[/tex]Sum (1)+ (2):
[tex]\begin{gathered} 7x+3y+2z-4w=18\text{ }\operatorname{\lparen}\text{1}\operatorname{\rparen} \\ + \\ 5x-3y-2z+4w=6\text{ }\operatorname{\lparen}\text{2}\operatorname{\rparen} \\ 5x+7x+3y-3y+2z-2z-4w+4w=18+6 \\ 12x=24 \\ x=\frac{24}{12}=2 \end{gathered}[/tex]x=2
Now, we are going to sum (3)*2+(2).
[tex]\begin{gathered} 5x-3y-2z+4w=6\text{ }\operatorname{\lparen}\text{2}\operatorname{\rparen} \\ + \\ 2*(-3x+y+z-2w)=-5*2\text{ }\operatorname{\lparen}\text{3}\operatorname{\rparen} \\ 5x-6x-3y+2y-2z+2z+4w-4w=6-10 \\ -x-y=-4 \\ -2-y=-4 \\ y=-2+4=2 \end{gathered}[/tex]y=2.
Replacing y and x in (4) and (3):
[tex]\begin{gathered} -3(2)+2+z-2w=-5\text{ }\operatorname{\lparen}\text{3}\operatorname{\rparen} \\ -8(2)+4(2)+2z+3w=11\text{ }\operatorname{\lparen}\text{4}\operatorname{\rparen} \end{gathered}[/tex][tex]\begin{gathered} -6+2+z-2w=-5 \\ z-2w=-5+6-2 \\ z-2w=-1\text{ \lparen5\rparen} \end{gathered}[/tex][tex]\begin{gathered} -16+8+2z+3w=11 \\ 2z+3w=11+16-8 \\ 2z+3w=19\text{ \lparen6\rparen} \end{gathered}[/tex]Isolating w in (5) ans replacing in (6):
[tex]\begin{gathered} 2w=-1-z \\ w=\frac{-1-z}{2} \end{gathered}[/tex][tex]\begin{gathered} 2z+3(\frac{-1-z}{2})=19 \\ \frac{4z-3-3z}{2}=19 \\ z-3=19*2 \\ z=38-3=35 \end{gathered}[/tex]Answer: z=35.
What be it’s value, to the nearest thousand dollars, in 13 years?
The Solution:
The value of the house in 13 years time can be calculated using the formula below:
[tex]F\mathrm{}V=P\mathrm{}V(1+\frac{r}{100})^n[/tex]In this case,
[tex]\begin{gathered} FV=\text{future value (value after 13 years)=?} \\ PV=\text{present value= \$249000} \\ r=\text{ rate \%=10.5\%} \\ n=\text{ number of years=13 years} \end{gathered}[/tex]Substituting these values in the formula above, we get
[tex]FV=249000(1+\frac{10.5}{100})^{13}=249000(1+0.105)^{13}[/tex][tex]FV=249000(1.105)^{13}=911819.68\approx\text{ \$911820}[/tex]Thus, the value of the house in 13 years is $911820 (to the nearest dollars)
The population of retired citizens in Memphis is 54000. If the population decreases at a rate of 5.9 % each year. What will the population of retirees be in 6 years?Write an exponential growth model for the future population P(x) where x is in years:
We will have the following:
First, we construct the exponential decay function, that is:
[tex]P(x)=54000(1-0.059)^x\Rightarrow P(x)=54000(0.941)^x[/tex]Now, we will determine the population after 6 years:
[tex]P(6)=54000(0.941)^6\Rightarrow P(6)=37491.38638[/tex]So, the population after 6 years will be of approximately 37491 people-
Suppose cluster sampling were being used to survey digital camera users, who amount to 77% of the population of the United States. Based on the table below, which city would be considered the best cluster?
The best cluster is Las Vegas, which has a percentage of 78% that is linearly close to 77%, the percentage of the whole population of the United States.
AnswerLas Vegas
6/2(1+2)help me with math problem
If sides AB and DC of a quadrilateral ABCD are parallel, which additional informationwould be sufficient to prove that quadrilateral ABCD is a parallelogram.ABACABDCACBDADABNone of the other answers are correct
We have a quadrilateral ABCD, where we know that AB || DC.
The other condition for the quadrilateral to be a parallelogram is that the other 2 sides of the parallelogram are congruent.
The other two sides are AC and BD, so the other condition needed is that AC and BD are congruent.
Answer: AC and BD are congruent.
[tex]AC\cong BD[/tex]how do I solve for x intercepts of this equation. I'm having trouble solving it.[tex]y = 2x ^{2} + 12x + 13[/tex]
To find the x-intercepts of this equation, substitute y by 0 at first
[tex]0=2x^2+12x+13[/tex]Now we need to factor this equation into 2 factors
We need 2 numbers their sum = 12 (the middle term)
But we can not find them mentally, then we will use the formula
[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]a is the coefficient of x^2
b is the coefficient of x
c is the numerical term
a = 2, b = 12, c = 13
Let us substitute them in the rule to find x
[tex]\begin{gathered} x=\frac{-12+\sqrt[]{(12)^2-4(2)(13)}}{2(2)} \\ x=\frac{-12+\sqrt[]{144-104}}{4} \\ x=\frac{-12+\sqrt[]{40}}{4} \end{gathered}[/tex]We will simplify the root
[tex]x=\frac{-12+2\sqrt[]{10}}{4}[/tex]Divide up and down by 2 to simplify the fraction
[tex]x=\frac{-6+\sqrt[]{10}}{2}[/tex]The 2nd root will be the same number but a different middle sign
[tex]x=\frac{-6-\sqrt[]{10}}{2}[/tex]The x-intercepts are
[tex](\frac{-6+\sqrt[]{10}}{2},0)\text{and(}\frac{-6-\sqrt[]{10}}{2},0)[/tex]I need help with math please
1. 92 .
2. 7
3. >=<
4. -
5. 8x3=24
Step-by-step explanation:
Which kind of symmetry does the letter D have?A. point symmetry, onlyB. line symmetry, onlyC. neither point nor line symmetryD. both point and line symmetry
Analysing the letter D, we can find the following symmetry (in red):
There is no point of symmetry. Therefore, the correct option is B.
THREE OF THE STATEMENTS BELOW ARE FALSE, USE THE TYPING TOOL TO FIND AND CORRECT THE FALSE STATEMENTS IN THE WHITE BOXES. A D The hypotonuse is the longest side of the right triangle The Pythagorean theorom applies to all triangles. The hypotenuse is always adjacent to the 90° angle E The Pythagorean theorem states that 2a + 2b - 20 INTRO TO PYTHAGOREAN THEOREM The logs, a and b, will always be adjacent to the 90° angle The square of the hypotonuts is always equal to the sum of the squares of the two legs in a right triangle Statement is false. || Statement is falso. Statement is fake Correct the statement: Correct the statement: Correct the statement er notes
We are asked to correct the following statements:
A. "The hypotenuse is the longest side of the right triangle" The statement is true.
B. "The Pythagorean theorem applies to all triangles". The statement is false. The Pythagorean theorem applies to RIGHT triangles.
C. "The hypotenuse is always adjacent to the 90° angle". The statement is false. The hypotenuse is opposite to the 90° angle.
D. "The Pythagorean theorem states that 2a + 2b - 2c". The statement is false. The Pythagorean theorem states that:
[tex]a^2+b^2=c^2[/tex]E. "The logs, a and b, will always be adjacent to the 90° angle". The statement is true, since a and b represent the adjacent sides of the 90 degrees angle.
F.
Members of the football team hold a fundraising dinner to raise money for their annual trip. They must sell tickets to the event at a price that will earn them more money than the cost of food.Here's a formula for this scenario:t = n (p - c)wheret = total profit made from the eventn = number of tickets soldp = price charged for each dinnerC = cost for food per plate The team hopes to sell 100 tickets. The cost for food per plate is $1.75 and they hope to charge $11.75 for each dinner. How much profit should they receive from the event?Enter the correct answer.
t = n(p-c)
t=100(11.75 - 1.75)
t = 100(10)
t=$1000
total profit received = $1000
Solve for 2. Enter the solutions from least to greatest.(x + 6)2 – 16 = 0lesser 1 =greater I =
The given expression is
[tex](x+6)^2-16=0[/tex]First, we add 16 on each side
[tex]\begin{gathered} (x+6)^2-16+16=16 \\ (x+6)^2=16 \end{gathered}[/tex]Then, we apply a square root on each side
[tex]\begin{gathered} \sqrt[]{(x+6)^2}=\sqrt[]{16} \\ x+6=\pm4 \end{gathered}[/tex]Now, we subtract 6 from each side
[tex]\begin{gathered} x+6-6=\pm4-6 \\ x_1=4-6=-2 \\ x_2=-4-6=-10 \end{gathered}[/tex]Therefore, the lesser solution is -10 and the greater solution is -2.For f(x) = 2x and g(x) = x,find f (g(2))
QuestionWrite the following function in terms of its cofunction.csc (pi/4)
Two functions are called cofunctions if they are equal on complementary angles
[tex]\csc \theta=\sec (\frac{\pi}{2}-\theta)[/tex]Since
[tex]\theta=\frac{\pi}{4}[/tex]Substitute it in the rule above
[tex]\csc (\frac{\pi}{4})=sec(\frac{\pi}{2}-\frac{\pi}{4})[/tex][tex]\csc (\frac{\pi}{4})=\sec (\frac{\pi}{4})[/tex]The cofunction is sec(pi/4)
the number line shown is divided into segments of equal length use the number line diagram to answer the following questions A. what is the length of each segment on the number line B.what number does point N represent C. what is the opposite of point N
A. We must divide the distance between the number of divisions
from 0 to 1 we have a distance of 1 and count 8 divisions
so
[tex]\frac{1}{8}=0.125[/tex]so the length of each segment is 1/8 or 0.125
B.
Please help me with this quickly, I need to go to sleep, thank you
x = -43/4
Explanation:Given:
[tex]\frac{17-4x}{12}=5[/tex]To find:
the value of x
[tex]\begin{gathered} \frac{17-4x}{12}=5 \\ multiply\text{ both sides by 12:} \\ 17\text{ - 4x = 5\lparen12\rparen} \\ 17\text{ - 4x = 60} \end{gathered}[/tex][tex]\begin{gathered} add\text{ 4x to both sides:} \\ 17\text{ -4x + 14x = 60 + 4x} \\ 17\text{ = 60 + 4x} \\ \\ subtract\text{ 60 from both sides:} \\ 17\text{ - 60 = 4x} \\ -43\text{ = 4x} \\ \\ divide\text{ boh sides by 4:} \\ x\text{ = -43/4} \end{gathered}[/tex]Select the correct answer.6cis5pi/6Convert57to rectangular form.OA. 3V3 + 31O B. –313 + 3iO C. 373 – 3iOD. -3V3 – 31O E. 3 – 3731
Answer:
Choice B.
Explanation:
The equation can be rewritten as
[tex]6\text{cis}\frac{5\pi}{6}=6\cos \frac{5\pi}{6}+i\sin \frac{5\pi}{6}[/tex]Now since
[tex]6\cos \frac{5\pi}{6}=-3\sqrt[]{3}[/tex]and
[tex]6\sin \frac{5\pi}{6}=3[/tex]the expression becomes
[tex]-3\sqrt[]{3}+3i[/tex]Hence, choice B is the correct answer since it matches the answer we got above.
Select the following that are true.Select one or more:a.If a quadrilateral is a square, then it is a rectangle.b.If a quadrilateral is a square, then it is a parallelogram.c.If a quadrilateral is a rhombus, then it is a parallelogram.d.If a quadrilateral is a rectangle, then it is a rhombus.e.If a quadrilateral is a square, then it is a rhombus.f.If a quadrilateral is a parallelogram, then it is a rectangle.
a. One of the properties of squares is all sides are congruent (they have the same length) and this is not a property of rectangles. But the square is a special rectangle since it fits in the properties of rectangles, but rectangles are not squares. In this case, this is TRUE.
b. A parallelogram is a quadrilateral with two pairs of opposite parallel sides and the opposite sides are congruent. The square fits into this description, so this is TRUE.
c. A rhombus has four equal opposite parallel sides, so we can say it fits into the parallelogram definition. This is TRUE.
d. As we said in part a, a rectangle doesn't have all of its sides congruent, but the rhombus does. Then, this is FALSE.
e. Squares have four equal opposite parallel sides, and rhombus too. Then, a square is a rhombus. This is TRUE.
f. Not all parallelograms have the properties of rectangles, then this is FALSE.
Solve the inequality. State the solution in inequality notation. 4(x - 5) + 10 > 2(5x – 2) – 4x
We will solve as follows:
[tex]4(x-5)+10>2(5x-2)-4\Rightarrow4x-20+10>10x-4-4x[/tex][tex]\Rightarrow4x-10>6x-4\Rightarrow-2x>6\Rightarrow x<-3[/tex]So, the solution is x < -3.
***Breakdown:
*After we obtain:
[tex]4x-10>6x-4[/tex]We operate like terms, that is we separate the variables and integers in the different side [Operating as if it were a normal equation]:
[tex]\Rightarrow4x-6x>-4+10\Rightarrow-2x>6[/tex]After this, we know that by dividing and/or multiplying by negative values in the inequality the orientation of the inequality will shift [That is if it was "<" then it will become ">" and viceversa], that is:
[tex]\Rightarrow x<\frac{6}{-2}\Rightarrow x<-3[/tex]12 posters for 36 students 21 poses for 36 students
In order to find Lorenzo's speed in miles per hour, we need to convert from yard to mile and from second to hour. The rates are:
1 yard = 1/1760 miles
1 second = 1/3600 hours
So we have that:
[tex]\text{speed}=5\frac{yards}{\sec ond}=5\frac{\frac{1}{1760}miles}{\frac{1}{3600}hour}=5\frac{3600}{1760}\frac{miles}{hour}=10.227\text{ miles/hr}[/tex]Lorenzo can ride 10.227 miler per hour.