i need help please with m and b#1 and graph

I Need Help Please With M And B#1 And Graph

Answers

Answer 1

ANSWER

• m = 2

,

• b = -5

EXPLANATION

This equation is written in slope-intercept form,

[tex]y=mx+b[/tex]

Where m is the slope and b is the y-intercept.

In this case, the slope is m = 2 and the y-intercept is b = -5. This tells us that the line intersects the y-axis at y = -5, so that is our first point. Then, we can find the next point using the slope,

[tex]m=2=\frac{\Delta y}{\Delta x}[/tex]

The next point is 1 unit to the right of the y-intercept, and 2 units up,

To draw a line we only need two points, so we have to draw a line passing through these two points.

I Need Help Please With M And B#1 And Graph
I Need Help Please With M And B#1 And Graph

Related Questions

Let P(x)=6x and Q(x)=2x^3 + 3x^2 + 1. Find P(x)⋅Q(x)

Answers

Explanation

We are given the following functions:

[tex]\begin{gathered} P(x)=6x \\ Q(x)=2x^3+3x^2+1 \end{gathered}[/tex]

We are required to determine the following:

[tex]P(x)\cdot Q(x)[/tex]

This is achieved thus:

[tex]\begin{gathered} P(x)=6x \\ Q(x)=2x^3+3x^2+1 \\ \\ \therefore P(x)\cdot Q(x)=(6x)(2x^3+3x^2+1) \\ P(x)\cdot Q(x)=6x\cdot2x^3+6x\cdot3x^2+6x\cdot1 \\ P(x)\cdot Q(x)=12x^4+18x^3+6x \end{gathered}[/tex]

Hence, the answer is:

[tex]\begin{equation*} 12x^4+18x^3+6x \end{equation*}[/tex]

ABCD is a parallelogram Find m angle C.В,11492x + 1234A4

Answers

Given the parallelogram ABCD:

The sum of every two adjacent angles = 180

so,

m∠B + m∠C = 180

m∠C = 180 - m∠B = 180 - 114 = 66

So, the answer will be m∠C = 66

Choose and evaluate an exponential expression that models the situation.A 1-inch vine begins tripling its length every week. After the first week, the length of the vine is3 inches. After the second week, the length is 9 inches. If this growth pattern continues, howlong will the vine be in 6 weeks?See image below for answer options.

Answers

The pattern is:

3

3x3

3x3x3

and so on

So it's 3^6 = 729

Answer: the second option

Solve the system of equations.−2x+5y =−217x+2y =15

Answers

To solve this question we will use the elimination method.

Adding 7 times the first equation to 2 times the second equation we get:

[tex]14x+4y+(-14x)+35y=30+(-147)\text{.}[/tex]

Simplifying the above equation we get:

[tex]4y+35y=-117.[/tex]

Solving for y we get:

[tex]\begin{gathered} 39y=-117, \\ y=-\frac{117}{39}, \\ y=-3. \end{gathered}[/tex]

Substituting y=-3 in the first equation, and solving for x we get:

[tex]\begin{gathered} -2x+5(-3)=-21, \\ -2x-15=-21, \\ -2x=-6, \\ x=3. \end{gathered}[/tex]

Answer:

[tex]\begin{gathered} x=3, \\ y=-3. \end{gathered}[/tex]

Sara made an error in solve the one-step equation below.5x + 9 = 29-9 -9- 4x = 29/4. /4x = -7.25What is the error that Sara made?What should Sara had done to solve the one-step equation above insteadof what she did?What is the answer that Sara should have found for the above one-step equation?*

Answers

[tex]5x+9=29[/tex]

To solve this one-step equation you:

1. Substract 9 in both sides of the equation:

In this step is the mistake as Sara gets as result -4x=29 and the corret result of substract 9 in both sides of the equation is 5x=20.

2. Divide both sides of the equation into 5:

Then, the answer that Sara should found for the equation is x=4

Can you help me with number 14? Thank you I am having trouble with it.

Answers

To solve number 14, we will make use of the Law of Cosines, which states that:

[tex]=\sqrt[]{^2+^2^{}-2\cos}[/tex]

As in our problem b = 15, c = 13 and A = 95°,we can replace these values in the formula and solve for a:

[tex]=\sqrt[]{15^2+13^2-2\cdot(15\cdot13)\cos 95}[/tex][tex]=\sqrt[]{15^2+13^2-390\cos 95}[/tex][tex]a\approx20.69[/tex]

In our case, a is the segment BC.

Answer: 20.7

The question is on the image below

Answers

Maximum number of identical boxes with no. of supply items in each box will be:

a. 78 boxes with 1 pencil and 1 eraser in each box.

b. 195 boxes with 1 notebook and 1 folder in each box.

c. 65 boxes with 1 eraser, 1 marker and 2 folders in each box.

First Lana will make 78 boxes with 1 pencil and 1 eraser in each box. After that she'll be left with

143 - 78 = 65 erasers.

Secondly she will make 195 boxes with 1 notebook and 1 folder in each box. After that she'll be left with

330 - 195 = 135 folders.

Next she will make 65 boxes with 1 eraser, 1 maker and 2 folders in each box.

By doing this she will be able to make maximum number of identical boxes.

To know more about identical boxes

https://brainly.com/question/14964607

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Hello, I need helping solving for x by completing the square.

Answers

EXPLANATION:

Given;

We are given the quadratic equation as shown below;

[tex]x^2-8x+13=0[/tex]

Required;

We are required to solve for x by completing the square method.

Step-by-step solution;

We start with the constant 13.

Subtract 13 from both sides of the equation;

[tex]x^2-8x+13-13=0-13[/tex][tex]x^2-8x=-13[/tex]

Next we take the coefficient of x (that is -8). We half it, and then square the result. After that we add it to both sides of the equation;

[tex]\begin{gathered} \frac{1}{2}\times-8=-\frac{8}{2} \\ Next: \\ (-\frac{8}{2})^2 \end{gathered}[/tex]

We now have;

[tex]x^2-8x+(-\frac{8}{2})^2=-13+(-\frac{8}{2})^2[/tex]

We can now simplify this;

[tex]x^2-8x+(-4)^2=-13+(-4)^2[/tex][tex]x^2-8x+16=-13+16[/tex][tex]x^2-8x+16=3[/tex]

We now factorize the left side of the equation;

[tex]\begin{gathered} x^2-4x-4x+16 \\ (x^2-4x)-(4x-16) \\ x(x-4)-4(x-4) \\ (x-4)(x-4) \\ Therefore: \\ (x-4)^2 \end{gathered}[/tex]

we can now refine our equation to become;

[tex](x-4)^2=3[/tex]

We can now solve for x as follows;

Take the square root of both sides;

[tex]x-4=\pm\sqrt{3}[/tex]

Therefore;

[tex]\begin{gathered} x-4=\sqrt{3} \\ x=\sqrt{3}+4 \\ Also: \\ x-4=-\sqrt{3} \\ x=-\sqrt{3}+4 \end{gathered}[/tex]

ANSWER:

[tex]\begin{gathered} x_1=4+\sqrt{3} \\ x_2=4-\sqrt{3} \end{gathered}[/tex]

In Seattle, the tax on a property assessed at $500,000 is $9,000. If tax rates are proportional in this city, how much would the tax be on a property assessed at $1,000,000?

Answers

Answer:

$18,000

Explanation:

Let us represent the tax by y and the property value by x. If the tax is proportional to the property value, then the relationship between y and x is the following.

[tex]y=kx[/tex]

where k is the constant of propotionality.

Now, to paraphrase, we are told that when y = $9,000, then x = $500,000. This means

[tex]9000=k(500,000)[/tex]

and we need to solve for k.

Dividing both sides by 9000 gives

[tex]k=\frac{9,000}{500,000}[/tex]

which simplifies to give

[tex]\boxed{k=\frac{9}{500}.}[/tex]

With the value of k in hand, our formula now becomes

[tex]y=\frac{9}{500}x[/tex]

We can now find the tax when x = 1,000,000.

Putting in x = 1,000,000 into the above formula gives

[tex]y=\frac{9}{500}(1,000,000)[/tex]

which simplifies to give

[tex]\boxed{y=18,000.}[/tex]

This means, the tax on a property assessed at $1,000,000 is $18,000.

A rectangular shaped garden is 2 feet longer than the width fios aree is 13sq feet find the dimensions

Answers

We are given that the length a rectangular-shaped figure is 2 feet longer than its width. This can be written mathematically as:

[tex]l=w+2[/tex]

Where "l" is the length and "w" is the width. WE are also told that the area is 13 square feet. Since the area is the product of the length and the width this means the following:

[tex]lw=13[/tex]

From the previous equation we solve for the length by dividing both sides by its width:

[tex]l=\frac{13}{w}[/tex]

Now we replace this in the first equation:

[tex]\frac{13}{w}=w+2[/tex]

Now we multiply both sides by the width:

[tex]13=w^2+2w[/tex]

Subtracting 13 to both sides:

[tex]w^2+2w-13=0[/tex]

We get a quadratic equation. To solve this equation we will factor the equation by completing the square:

[tex](w^2+2w+1)-14=0[/tex]

Factoring the parenthesis:

[tex](w+1)^2-14=0[/tex]

Now we add 14 to both sides:

[tex](w+1)^2=14[/tex]

Taking square root to both sides:

[tex]w+1=\pm\sqrt[]{14}[/tex]

Subtracting 1 to both sides:

[tex]w=-1\pm\sqrt[]{14}[/tex]

We take the positive value for the width, that is:

[tex]\begin{gathered} w=-1+\sqrt[]{14} \\ w=2.74ft \end{gathered}[/tex]

Now we replace this value of the width in the first equation:

[tex]\begin{gathered} l=2.74ft+2ft \\ l=4.74ft \end{gathered}[/tex]

Therefore, the dimensions are:

[tex]\begin{gathered} w=2.74ft \\ l=4.74ft \end{gathered}[/tex]

36\100 as a percentage

Answers

Notice that in the fraction

[tex]\frac{36}{100}[/tex]

Can be interpreted as "36 out of every 100"

As a percentage, this means 36%

How many cubic feet of warehouse space are needed for 430 boxes 12in by 8in by 9in?

Answers

SOLUTION

From the question we want to know how many cubic-feet of a warehouse can contain 430 boxes, whereby "each one" of these 430 boxes measures 12 inches by 8 inches by 9 inches

Firstly we have to change these inches of the sides of ecah of these boxes to feet.

12 inches make a foot.

Hence each box in feet will measure

[tex]\begin{gathered} \frac{12}{12}ft\times\frac{8}{12}ft\times\frac{9}{12}ft \\ =1\times\frac{2}{3}\times\frac{3}{4} \\ =\frac{2}{4} \\ =\frac{1}{2}ft^3 \end{gathered}[/tex]

So each boxes in feet will measure half cubic foot.

The warehouse that will contain 430 of these boxes should measure

[tex]\begin{gathered} 430\times\frac{1}{2} \\ =215ft^3 \end{gathered}[/tex]

Hence, the answer is 215 cubic-feet

How to find the value of X in problem 15

Answers

We are asked to determine the value of "x" and "y".

To determine the value of "y" we will use the facto that since WP is a median this means that:

[tex]AP=PH[/tex]

Substituting the values in terms of "y" we get:

[tex]3y+11=7y-5[/tex]

Now, we solve for "y". To do that we will first subtract "7y" from both sides:

[tex]\begin{gathered} 3y-7y+11=7y-7y-5 \\ -4y+11=-5 \end{gathered}[/tex]

Now, we subtract 11 from both sides:

[tex]\begin{gathered} -4y+11-11=-5-11 \\ -4y=-16 \end{gathered}[/tex]

Now, we divide both sides by -4:

[tex]\begin{gathered} y=-\frac{16}{-4} \\ \\ y=4 \end{gathered}[/tex]

therefore, the value of "y" is 4.

Now, to determine the value of "x" we will use the fact that since WP is an angle bisector we have that:

[tex]m\angle HWP+m\angle PWA=m\angle HWA[/tex]

We also have the:

[tex]m\angle PWA=m\angle HWP[/tex]

Therefore, we have:

[tex]\begin{gathered} m\operatorname{\angle}HWP+m\operatorname{\angle}HWP=m\operatorname{\angle}HWA \\ 2m\operatorname{\angle}HWP=m\operatorname{\angle}HWA \end{gathered}[/tex]

Now, we substitute the values:

[tex]2(x+12)=4x-16[/tex]

Now, we divide both sides by 2:

[tex]x+12=2x-8[/tex]

Now, we subtract 2x from both sides:

[tex]\begin{gathered} x-2x+12=2x-2x-8 \\ -x+12=-8 \end{gathered}[/tex]

Now, we subtract 12 from both sides:

[tex]\begin{gathered} -x+12-12=-8-12 \\ -x=-20 \\ x=20 \end{gathered}[/tex]

This means that the value of "x" is 20.

To determine if WP is an altitude we need to determine if the angle APW is 90 degrees. To do that we use the fact that the sum of the interior angles of a triangle always adds up to 180, therefore:

[tex]m\angle WPA+m\angle PWA+m\angle PAW=180[/tex]

We substitute the values in terms of "x":

[tex]m\angle WPA+(x+12)+(3x-2)=180[/tex]

Now, we substitute the value of "x":

[tex]m\angle WPA+(20+12)+(3(20)-2)=180[/tex]

Solving the operations:

[tex]m\angle WPA+90=180[/tex]

now, we subtract 90 from both sides:

[tex]\begin{gathered} m\angle WPA=180-90 \\ m\angle WPA=90 \end{gathered}[/tex]

Since WPA is 90 degrees and WP is a median and bisector this means that WP is an altitude.

Ingrid deposits $10,000 in an IRA. What will be the value of her investment in 6 years if the investment is earning 3.2% per year and is compounded continuously? Round to the nearest cent.

Answers

We have a initial deposit of $10,000 (PV=10,000).

The investment last 6 years (t=6).

The annual interest rate is 3.2% (r=0.032) and is compounded continously.

The equation to calculate the future value FV of the inverstment for this conditions is:

[tex]\begin{gathered} FV=PV\cdot e^{rt} \\ FV=10,000\cdot e^{0.032\cdot6} \\ FV=10,000\cdot e^{0.192}. \\ FV\approx10,000\cdot1.2116705 \\ FV\approx12,116.71 \end{gathered}[/tex]

The value of her investment will be $12,116.71.

2-18 72 20=34-To=315)-10=35 5)EXTENSION: a) In right A DEF, m D = 90 and mZF is 12 degrees less than twice mze. Find mZE. b) in AABC, the measure of ZB is 21 less than four times the measure of LA, and the measure of ZC is 1 more than five times the measure of ZA. Find the measure, in degrees, of each angle of ABC.

Answers

As given by the question

There are given that in the right triangle DEF, angle D is 90 degrees and angle f is 12 degrees less than angle E.

Now,

The sum of the three measures of a triangle is always 180 degree

So,

[tex]m\angle D+m\angle E+m\angle F=180[/tex]

Where angle D is 90 degree

Then,

[tex]\begin{gathered} m\angle D+m\angle E+m\angle F=180 \\ 90+m\angle E+m\angle F=180 \\ m\angle E+m\angle F=90 \end{gathered}[/tex]

Also we are given that

[tex]\begin{gathered} F+12=2E \\ F=2E-12 \end{gathered}[/tex]

Therefore, substituting for F back into E+F=90

Then,

[tex]\begin{gathered} E+(2E-12)=90 \\ 3E-12=90 \\ 3E=102 \\ E=34 \end{gathered}[/tex]

So, angle E is 34 degrees, which is the answer.

1 8. Dee Saint earns a monthly salary of $750 plus a 6% commission on all sales over $1,000 each month. Last month, her sales were $5,726. What was her income for the month?

Answers

Her monthly income for last month was $1,093.56

Here, we want to calculate the monthly income for Dee Saint

Mathematically, from the information given in the question, we can have this as;

[tex]\begin{gathered} 750\text{ + 6\% of \$5726} \\ \\ =\text{ 750 + 0.06(5726)} \\ \\ =\text{ 750 + 343.56} \\ \\ =\text{ \$1,093.56} \end{gathered}[/tex]

identify the same-side interior angles. Choose all the Apply<3 & <4<3 & <5<3 & <6<3 & <8

Answers

The same-side interior angles are also called consecutive interior angles. They are non-adjacent interior angles that lie on the same side of the transversal (in this case, t). Then, we have that these angles are:

[tex]\measuredangle3,\text{ }\measuredangle5[/tex]

And

[tex]\measuredangle4,\measuredangle6[/tex]

A graph to represent them:

From the options, we have that option B is one answer: <3 and <5. The other possible answer is <4 and <6 (not shown in the possible options).

A game center has a $5 admission fee and charges $0.50 for each game played. Graph the equation on the coordinate plane. Be sure to label the axes appropriately and provide a scale for the axes.

Answers

A game center has a $5 admission fee (this is the y-intercept of the equation)

It charges $0.50 for each game played (this is the slope of the equation)

The equation can be written as

[tex]y=0.50x+5[/tex]

Where y is the cost and x is the number of games played.

To plot the graph, you can either find some (x, y) coordinates using the above equation.

Or you can plot it using the concept of slope and y-intercept.

Start at the point of y-intercept (0, 5)

The slope is 0.50 = 1/2

Then go 1 unit up and two units to the right that is your next point.

Repeat the same, 1 unit up and two units to the right that is your next point and so on...

Let us plot the graph

Scale: one small box = 1 unit

x-axis = number of games

y-axis = Cost ($)

Mr. Fowler's science class grew two different varieties of plants as part of anexperiment. When the plant samples were fully grown, the studentscompared their heights.PlantvarietyHeight of plant(inches)20, 17, 19, 18, 21Mean Mean absolute deviation(Inches)Variety A191.2Variety B13, 18, 11,9,14132.4Based on these data, which statement is true?O A. The maximum height for plants from variety B is greater than forvariety A.B. Plants from variety A always grow taller than plants from variety B.C. The height of a plant from variety B is likely to be closer to themean.D. The height of a plant from variety A is likely to be closer to themean.

Answers

Let's analyze all the statements and see why they are false or true.

A. FALSE

The tallest plant in variety B is just 18 tall, while the variety A we have 21.

B. FALSE

We do have plants in A that have the same height as B.

C. FALSE

The standard deviation measure how far it's from the mean, the variety B has a 2.4 standard deviation, which means that the height can be more distant from the mean than in variety A.

D. True

Justified by C. Variety A has a 1.2 standard deviation, which means it's more likely to be closer to the mean

What is the solution of the inequality shown below? 1 + a 4 enter the correct answer

Answers

We are given the following inequality:

[tex]1+a\le4[/tex]

To solve this inequality we will subtract 1 to both sides:

[tex]\begin{gathered} 1-1+a\le4-1 \\ a\le3 \end{gathered}[/tex]

And thus we get the solution.

what is the GCF of 20 and 32

Answers

Given the following numbers

[tex]20,32[/tex]

To find the greatest common factor, G.C.F.

The factor that can divide through two or more numbers evenly is the G.C.F

The factors of 20 and 32 are as follows

[tex]\begin{gathered} 20\Rightarrow1\times2\times2\times5 \\ 32\Rightarrow1\times2\times2\times2\times2\times2 \end{gathered}[/tex]

The common factors between 20 and 32 is

[tex]\begin{gathered} \text{Common factors }=2,2 \\ G\mathrm{}C\mathrm{}F=2\times2=4 \\ G\mathrm{}C\mathrm{}F=4 \end{gathered}[/tex]

Hence, the GCF of 20 and 32 is 4

Alternatively

Finding the G.C.F using table to find the G.C.F of 20 and 32

Therefore, the G.C.F is

[tex]G.C.F\Rightarrow2\times2=4[/tex]

Hence, the G.C.F of 20 and 32 is 4

Problem ID: PRABDN8J Use what you know about exponential notation to complete the expressions below. (-5) X -X(-5) = 17 times Use the ^ symbol to represent an exponent. For example: (-5)2 should be typed as (-5)^2 engage Type your answer below (numeric expression Submit Answer

Answers

Answer:[tex](-5)^X-X^{-5}=17[/tex]Explanations:

Since (-5)2 using the exponential symbol can be written as (-5)^2

This means -5 in 2 places

(-5)X, using the exponential symbol, can be written as (-5)^X

X(-5), using the exponential symbol can be written as X^(-5)

Therefore:

(-5)X - X(-5) = 17, in exponential form, can be written as:

(-5)^X - X^(-5) = 17

[tex](-5)^X-X^{-5}=\text{ 17}[/tex]

Erica is given the diagram below and asked to prove that AB DF. What would be the missing step of the proof? Given: Point B is the midpoint of EF, and point A is the midpoint of ED. Prove: AB DF

Answers

Given

To find the missi

Use the figure to find the measures of the numbered angles. 95 23 24 = Explain your reasoning.

Answers

The given angle and angle 3 are corresponding angles, that is, angles that are on the same corner at each intersection. Graphically,

Corresponding angles are congruent, so

[tex]\angle3=95\text{\degree}[/tex]

On the other hand, angle 3 and angle 4 are supplementary angles, that is, add up to 180°. Graphically,

[tex]A+B=180\text{\degree}[/tex]

So, you have

[tex]\begin{gathered} \angle3+\angle4=180\text{\degree} \\ 95\text{\degree}+\angle4=180\text{\degree} \\ \text{ Subtract 95\degree from both sides of the equation} \\ 95\text{\degree}+\angle4-95\text{\degree}=180\text{\degree}-95\text{\degree} \\ \angle4=85\text{\degree} \end{gathered}[/tex]

Therefore, the measures of the numbered angles are

[tex]\begin{gathered} \angle3=95\text{\degree} \\ \angle4=85\text{\degree} \end{gathered}[/tex]

Two weather stations are aware of a thunderstorm located at point C. The weather stations A and B are 24 miles apart.

Answers

Assuming the dashed lines are parallel and perpendicular to the base, we can start by draw a third parallel line that passes through C and naming some distances:

Now, we can see that the given angles are alternate interior angles with respect to the angles formed by the new perpendicular line and the lines AC and BC:

Now, we can see that b and the base a + 24 are related with the tangent of 48°:

[tex]\tan 48\degree=\frac{a+24}{b}[/tex]

Also, b and a are related with the tangent of 17°:

[tex]\tan 17\degree=\frac{a}{b}[/tex]

We can solve both for b and equalize them:

[tex]\begin{gathered} b=\frac{a+24}{\tan48\degree} \\ b=\frac{a}{\tan17\degree} \\ \frac{a+24}{\tan48°}=\frac{a}{\tan17\degree} \\ a\tan 17\degree+24\tan 17\degree=a\tan 48\degree \\ a\tan 48\degree-a\tan 17\degree=24\tan 17\degree \\ a(\tan 48\degree-\tan 17\degree)=24\tan 17\degree \\ a=\frac{24\tan17\degree}{\tan48\degree-\tan17\degree}=\frac{24\cdot0.3057\ldots}{1.1106\ldots-0.3057\ldots}=\frac{7.3375\ldots}{0.8048\ldots}=9.1162\ldots \end{gathered}[/tex]

Now, we can relate a and x with the sine of 17°:

[tex]\begin{gathered} \sin 17\degree=\frac{a}{x} \\ x=\frac{a}{\sin17\degree}=\frac{9.1162\ldots}{0.2923\ldots}=31.18\ldots\approx31.2 \end{gathered}[/tex]

And x is the distance between A and C, the storm. Thus the answer is approximately 31.2 miles, fourth alternative.

Complete the coordinate proof. Answer choices are on the bottom.

Answers

Given:

There are given that the triangle, ABC.

Where:

[tex]\begin{gathered} A=(3,6) \\ B=(5,0) \\ C=(1,0) \end{gathered}[/tex]

Explanation:

According to the question, we need to prove that the isosceles triangle:

So,

From the concept of the isosceles triangle:

The isosceles triangle is defined when two sides of the length of any triangle are equal.

Then,

First, we need to find the length of the sides by using the distance formula:

So,

[tex]\begin{gathered} AB=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\ AB=\sqrt{(5-3)^2+(0-6)^2} \\ AB=\sqrt{(2)^2+(-6)^2} \\ AB=\sqrt{4+36} \\ AB=\sqrt{40} \end{gathered}[/tex]

Then,

[tex]\begin{gathered} AC=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\ AC=\sqrt{(1-3)^2+(0-6)^2} \\ AC=\sqrt{(-2)^2+(-6)^2} \\ AC=\sqrt{4+36} \\ AC=\sqrt{40} \end{gathered}[/tex]

And,

[tex]\begin{gathered} CB=\sqrt{(5-1)^2+(0-0)^2} \\ CB=\sqrt{(4)^2+0} \\ CB=4 \end{gathered}[/tex]

Final answer:

Hence, the step and values of the sides are shown below;

[tex]\begin{gathered} CA=d \\ AB=d \end{gathered}[/tex]

And,

The side CA and AB is congruence by the definition of h

And,

Triangle ABC is an isosceles triangle by the the defination of b.

A ladder 7.90 m long leans against the side of a building. If the ladder is inclined at an angle of 74.5° to the horizontal, what is the horizontal distance from the bottom of the ladder to the building?____________ m

Answers

First, let's sketch the problem:

To find the horizontal distance d, we can use the cosine relation of the angle 74.5°.

The cosine is equal to the length of the adjacent leg to the angle over the length of the hypotenuse.

So we have:

[tex]\begin{gathered} \cos74.5°=\frac{d}{7.9}\\ \\ 0.2672=\frac{d}{7.9}\\ \\ d=0.2672\cdot7.9\\ \\ d=2.11\text{ m} \end{gathered}[/tex]

Find the difference. Express the answer in scientific notation.(4.56 times 10 Superscript negative 13 Baseline) minus (1.17 times 10 Superscript negative 13)3.39 times 10 Superscript negative 265.73 times 10 Superscript negative 263.39 times 10 Superscript negative 135.73 times 10 Superscript negative 13

Answers

Given:

given expression is

[tex](4.56\times10^{-13})-(1.17\times10^{-13})[/tex]

Find:

we have to elavuate the difference and write the answer in scientific notation.

Explanation:

we will evaluate the expression as follows

[tex](4.56\times10^{-13})-(1.17\times10^{-13})=(4.56-1.17)\times10^{-13}=3.39\times10^{-13}[/tex]

Therefore, correct option is

[tex]3.39\times10^{-13}[/tex]

I have taken a picture of the question. Thank you.

Answers

The original width of the rectangular piece of metal is 21 inches.

let us take into consideration the width of the rectangle be x,

Length is given to be 5 inches more than the width

∴ length = x+5

Now squares of side 1 inch is cut from all the corners of the rectangle to form a box in the form of a cuboid.

New length of the base of the box = (x+5) - 2 = x+3 inches

new width of the box = x -2 inches

Height of the box = 1 inch

Volume of the box that is formed

= (x+3 ) · (x -2) × 1

= x² - x - 6

The given volume of the box is 414 cubic inches

Therefore:

x² - x - 6 = 414

or, x² - x -420 = 0

Solving the quadratic equation by middle term factorization we get :

or, ( x - 21 ) ( x + 20 ) = 0

Now either x=-20( not possible)

or , x =21 inches.

Therefore the original width of the rectangle is 21 inches.

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Find anexpression which represents the sum of (-6x + 6) and (-3x – 7) insimplest terms.

Answers

We are asked to find the sum of the following expressions

[tex](-6x+6)\: \: and\: \: (-3x-7)[/tex]

First of all, expand the parenthesis

[tex]\begin{gathered} (-6x+6)+\: (-3x-7) \\ -6x+6-3x-7 \end{gathered}[/tex]

Now, collect the like terms together and add/subtract

[tex]\begin{gathered} -6x+6-3x-7 \\ (-6x-3x)+(6-7) \\ (-9x)+(-1)_{} \\ -9x-1 \end{gathered}[/tex]

Therefore, the sum of the given expressions in the simplest form is

[tex]-9x-1[/tex]

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