I just want to know if I did this correctly

0.1M sugar < 0.1 M NaCl < 0.08M CaCl2 < 0.04 M Na2SO4​

First we must understand that the higher thecnoncentration of a compound, the lower the melting point. This shows that 0.04 m Na2SO4​ will have highest melting point followed by 0.08 M CaCl2

Since 0.1M of sBgar and 0.1M of NaCl have the same molarity, we will determine the effect of solute and ionic bonding between compound on melting point. Since common salt (NaCl) is made up of stronger ionic bonds, it will have higher melting point than sugar.

The increasing order of their melting point wile be 0.1M sugar < 0.1 M NaCl < 0.08M CaCl2 < 0.04 M Na2SO4​

Answer

(A) has variable composition

Explanation

Air is a mixture, but not a compound because it can be separated into different components such as oxygen, nitrogen, etc through the process of fractional distillation.

Therefore, air is not a compound because it has a variable composition.

The correct answer is (A) has variable composition

Explanation:

Frequency and wavelength are inversely proportional to each other. The equation that relates them is:

f = c/λ

Where f is the frequency, λ is the wavelength and c is the speed of light.

f = ? λ = 843 nm c = 3.00 * 10^8 m/s

Before we replace these values into the formula we have to convert the wavelength from nm to m.

1 m = 1 * 10^9 nm

λ = 843 nm = 843 nm * 1 m/(1 * 10^9 nm)

λ = 8.43 *10^(-7) m

Finally we can replace the values into the equation and get the answer to our problem.

f = c/λ

f = (3.00 * 10^8 m/s)/( 8.43 *10^(-7) m)

f = 3.56 * 10^14 1/s

f = 3.56 * 10^14 Hz

Answer: the frequency of the light is 3.56 * 10^14 Hz

Explanation:

Molarity, or concentration in amount of matter (mol/L), is the ratio between the amount of matter in the solute (n) and the volume of the solution in liters (V): M = n/V

Here we have:

m = 166 g of KI (solute)

V = 1000 mL = 1L (solution)

So we need to transform 166 g of KI into moles. We use the following formula:

n = m/MM

MM of KI is 166 g/mol

n = 166/166

n = 1 mol

So:

M = 1/1

M = 1 mol/L

Answer: M = 1 mol/L

The reaction will occur.

The given chemical reaction is a double displacement reaction. In this reaction, the compoiunds will react to produce two different compounds.

The balanced form of the reaction is expressed as:

You can see that the reaction of cupper(II)sulphate and sodium carbonate produces sodium sulphate and copper(II)carbonate

Since most carbonate compounds are insoluble, hence the reaction will occur

We have to write the net ionic equation for the reaction between HCl and NaHCO₃.

The molecular equation will show us the products of this equation.

Molecular equation:

HCl (aq) + NaHCO₃ (aq) ------> NaCl (aq) + CO₂ (g) + H₂O (l)

Now we can split this compounds into their ions to get the total ionic equation:

Total ionic equation:

H+ (aq) + Cl- (aq) + Na+ (aq) + HCO3- (aq) ----> Na+ (aq) + Cl- (aq) + CO₂ (g) + H₂O (l)

And finally we can identify the spectator ions. The ones that we have on both sides, they are Na+ and Cl-. We can cancel them out.

Net ionic equation:

H+ (aq) + HCO3- (aq) ----> CO₂ (g) + H₂O (l)

Answer: H+ (aq) + HCO3- (aq) ----> CO₂ (g) + H₂O (l)

To determine the heat required (Q) to increase the temperature of a substance we can apply the following equation:

where,

m is the mass of the substance, 50g

Cp is the specific heat of the substance, 0.386J/g.K

deltaT is the temperature difference, 70K

Now, we have the values we need to calculate the heat required, we replace the known data into the equation:

The heat required to raise the temperature of 50 g of copper by 70 K will be 1347.5J

Its thickness, hardness, and flexibility of the bones will alter, becoming less dense, stronger, and more flexible.

Trabecular or bone graft refers to the porous, spongy-appearing interior of bones, particularly vertebra and the ends of long bones. Compared to cortical bone, it has a larger surface area and undergoes more active remodeling.

As the primary load-bearing bone in vertebral column and the bone that transfers stress from the joints to the cancellous bone in long bones, trabecular bone's elastic behavior must be studied. Additionally, it impacts the bone structure's strength and the fracture risk.

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Answer:

The specific heat of the metal is 0.69 J/g°C.

Explanation:

The given information from the exercise is:

• Metal,:

- Mass (massmetal): 52.3g

- Initial temperature (Tinitialmetal): 126.2°C

- Final temperature (Tfinalmetal): 35.5°C

• Water,:

- Mass (masswater):71.2g

- Initial temperature (Tinitialwater): 24.5°C

- Final temperature (Tfinalwater): 35.5°C

1st) It is necesary to write the Heat formula for both materials, the metal and water. In the case of water, we can solve the formula, because we have all the nedeed information:

• Metal,:

Water:

So, the heat absorbed by the water is 3,276.9 J.

2nd) In the end both materials reach the equilibrium temperature, because the heat released by the piece of metal is absorbed by the water, this is represented as:

Finally, we have to replace the heat of the metal equation (Qm) and the heat of water (Qw) to calculate the specific heat of the metal:

So, the specific heat of the metal is 0.69 J/g°C.

With the given materials following  experiment can be done

Electrical conductivity test:

Metals are good conductors of electricity, therefore when you join metals with a battery, wire, and bulb, you get a bulb.

Similarly, if nonmetals are poor electrical conductors, they may not ignite the bulb when attached to a wire and a battery.

Generally, the above method can be used to identify metals and non-metals. But there are some exceptions also,. Graphite, an allotrope of non-metal carbon, is a good conductor of electricity.

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The periodic chart has many different types of elements. Some elements are metals, some are nonmetals, and yet others are metalloids. Therefore, by electrical conductivity test, we can detect metal and non metal.

Metals are hard, conduct electricity, are ductile, lustrous, and malleable materials.

Since metals have free electrons that's why they can conduct electricity.  Since atoms in metals are very closely packed in a definite crystal solid. It is not brittle that is it can not be broken down easily.

Metals carry electricity well, therefore when you combine metals with a battery, wire, and bulb, you get a light. Similarly, if nonmetals are poor electrical conductors, when connected to a wire and a battery, they may not light the bulb.

Therefore, by electrical conductivity test, we can detect metal and non metal.

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ANSWER

Lead (IV) Arsenate

STEP-BY-STEP EXPLANATION:

The compound consists of two elements which are; Lead and Arsenic, and oxygen

Combination off oxygen and Arsenic gives Arsenate

The name of the compound is Lead (VI) Arsenate

In order to know the values of the quantum numbers n, l and ml for al s4 orbital we go to a quantum table:

And as we can see to de 4s orbital correspond only the values:

n=4

l=0

ml=0

Answer: Particles in the solid phase are tightly compact and they vibrate, while particles in the liquid phase move freely, randomly, and with more room to move

Explanation:

zinc nitrate and solid lead most likely happen when zinc particles are placed in lead nitrate solution

[tex]Pb(NO_3)_2aq.+Zn(s)= Zn(NO_3)_2(aq.)+Pb(s)[/tex]

Without the chemical element zinc (Zn), which is one of the most extensively used metals and is a member of Group 12 (IIb, or the zinc group) of the periodic table, life would not be possible. Zinc has important business implications.

The average amount of zinc in the Earth's crust per tonne is 65 grams (2.3 ounces), which is a little more than copper. Nearly all of the world's zinc ore is composed of the principal zinc mineral sphalerite and its oxidation byproducts, smithsonite and hemimorphite. Australia, New Zealand, and the US are said to have discovered native zinc resources. China, Australia, and Peru are the top three producers of zinc in the beginning of the twenty-first century.

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Given the following parameters

Carbon = 40.0%

Hydrogen = 6.71%

Oxygen = 53.29%

Convert to mass

Carbon = 40.0grams

Hydrogen = 6.71grams

Oxygen = 53.29grams

Convert the mass to moles

Mole of carbon = 40.0/12 = 3.33moles

Mole of hydrogen = 6.71/1 = 6.71 moles

Mole of oxygen = 53.29/16 = 3.33moles

Divide by the lowest number of moles

Carbon: 3.33/3.33 = 1

Hydrogen: 6.71/3.33 = 2.01

Oxygen: 3.33/3.33 = 1

Determine the empirical formula

Empirical formula = CH2O

Determine the molecular formula

Hence the molecular mass of the compound is C3H6O3

Answer:

0.089 M

Explanation:

M1V1=M2V2

Total volume = 150 ml + 85 ml = 235ml

0.157(.085 L) = M2(.235L)

M2 = 0.05678723404 or 0.057 M

Step 1 - "reading" the chemical equation

The given chemical equation is:

The proportion in moles for any chemical equation is given by the "bigger" numbers, those that come before the formula of the substances. We can use them to "read" what the equation is telling us:

1 mole of NaI react with 1 mole of Cu thus producing 1 mole of CuI2 and 1 mole of Na

Since the exercise has specifically asked us about the proportion between sodium iodide (NaI) and copper (Cu), we can simplify the statement to:

1 mole of NaI react with 1 mole of Cu

Therefore, we always need the same quantitie, in moles, of NaI and Cu for this reaction to occur completely.

Step 2 - Discovering how many moles of sodium iodide are required

Since the proportion between NaI and Cu, as we saw, is 1:1 in moles, whenever we use, let's say, x moles of Cu, we will need x moles of sodium iodide as well.

Therefore, the amount needed of sodium iodide would be exactly 3.2 moles.

The oxidation state of nitrogen in Mg(NO₂)₂ is +3.

An oxidation state is an indicator of how electronegative an atom is. The higher the oxidation state, the more electronegative the atom.

To find the oxidation state of Mg(NO₂)₂, first, we need to split the compound and the compound should be again split into elements. On splitting, we get, Mg and (NO₂).  We need to sum up the oxidation states of each element so that we get the total oxidation state of the given compound

The oxidation state of Magnesium = +2

The oxidation state of Nitrogen = +3

The oxidation state of Oxygen = -2

Then the total oxidation state of Mg(NO₂)₂

Total oxidation state = + 2 + 3 - 2

Oxidation state of Nitrogen Mg(NO₂)₂ = +3

Therefore the oxidation state of Mg(NO₂)₂ is +3.

Thus in this way oxidation state of any compound could be found easily.

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Answer

Explanation

Given:

57.69% C, 11.54% H, and 30.77% O by mass,

Meaning:

Mass of carbon = 0.5769 g

Mass of Hydrogen = 0.1154 g

Mass of Oxygen = 0.3077 g

We know:

Molar masses of:-

C = 12.0107 g/mol

H = 1.00794 g/mol

O = 15.999 g/mol

Required: Empirical formula

Solution:

Step 1: Calculate the number of moles of the 3 atoms

C : 0.5769 g/12.0107 g/mol = 0.04826 mol

H : 0.1154 g/1.00794 g/mol = 0.1145 mol

O : 0.3077 g/15.999 g/mol = 0.0192

Step 2: Divide the moles by the lowest number of moles

In this case divide by 0.0192

C: 2.5

H: 6

O:1

Step 3: multiply by 2 to remove a decimal

C: 5

H: 12

O:2

Therefore the answer is: C5H12O2

Answer

C. both

Explanation

Structures in option A and option B both corresponds to the name: pentanoic acid.

The correct answer is C. both

Let us first illustrate the reaction of Copper and Oxygen

• 2Cu +O2 → 2CuO

ratioon > 2 : 1

step 1 : determine moles of Cu and O2 .

(i) Moles Cu = mass Cu/Molar Mass Cu

= 63.6 g/ 63.546g/mol

=1.001 mol

(ii) moles O2 = mass Oxygen/Molar Mass Oxygen

= 71.6/32

= 2.238mol

Step 2 :

Experimental moles of Cu : O2

1.001moles : 2.238moles

take note that excess reactant is O2 and limiting reactant is Cu

Therefore moles of Oxygen that reacted = 1/2 moles of Cu

= 1/2 * 1.001 = 0.5moles

Mass of Oxygen reacted =0.5* 32 (oxygen Molar mass)

=16.01g

This means that 16.01 grams of Oxygen reacted , this value is not in the options provi

7.60grams

The formula for calculating the molarity of a solution is expressed as;

Given the following parameters

molarity of solution = 0.250M

volume of sample = 200mL

Substitute to determine the mole of the solute

Determine the required mass of FesO4

Hence the mass of FeSO4 is 7.60grams

Explanation:

The 3 elements are As, Ga, and Se.

Please, look at the next picture:

According to the 2 pictures above, the right arrangement will be:

Ga < As < Se

Ga has the lowest ionization energy and Se has the highest ionization energy.

Answer: Ga < As < Se

To find the amount represented by 1.5x10^16 molecules of BF3 we have to use Avogadro's Number. It was stated that 1 mol of any substance contains 6.022x10^3 atoms or molecules of that substance, that is what we know as Avogadro's Number:

The answer is 2.5x10^-8 moles of BF3.

Answer

D. 0.04 m (NH4)3PO4

Explanation

Boiling point elevation depends on the solvent, of course, but we're assuming water, and upon the concentration of the solute and how many particles into which the solute breaks. Colligative properties like boiling point elevation, depend on the total number of particles in solution. The solvent used here is water. So elevation in boiling point will be above a boiling point of water for all solutions.

ΔT= i x Kb x m,

Where i = van Hoff's factor, Kb = boiling point elevation constant of water = 0.512, m = molality

Higher ΔT will have a higher boiling point.

For 0.1 m CH4N₂O,

i = 1

ΔT = 1 x 0.512 x 0.1 = 0.0512

For 0.06 m HCI;

i = 2

ΔT = 2 x 0.512 x 0.06 = 0.06144

For 0.05 m CaCl2

i = 3

ΔT = 3 x 0.512 x 0.05 = 0.0768

For 0.04 m (NH4)3PO4;

i = 4

ΔT = 4 x 0.512 x 0.04 = 0.08192

For 0.07 m NaCl

i = 2

ΔT = 2 x 0.512 x 0.07 = 0.07168

0.04 m (NH4)3PO4 has the highest ΔT.

Therefore, the solution that has the highest boiling point would be D. 0.04 m (NH4)3PO4.

Answer: the percent yield of this reaction was 84.7% and the best option to answer the question is the last one (letter E, 85.00%)

Explanation:

The question requires us to determine the percent yield of a reaction, given the amount of product obtained, the chemical equation and the amount of reactants used.

The following information was provided by the question:

mass of Al2O3 produced = 16.0 g

mass of Al used = 10.0 g

mass of O2 used = 19.0 g

balanced chemical equation:

To solve this problem, we'll need to go through the following steps:

1) Calculate the number of moles used of each reactant;

2) determine the limiting reactant from the stoichiometry of the reaction and the amount of reactants used;

3) calculate the theoretical yield of the reaction, or, in other words, the amount of Al that should be produced, considering the limiting reactant;

4) calculate the percent yield of the reaction.

Next, we'll go through these steps to solve the problem:

1) Calculating the number of moles of each reactant

We can use the following equation to determine the amount of moles of Al and O2 that were used in the reaction:

where n is the number of moles (in mol), m is the mass of the sample (in grams) and MM is the molar mass of the compound (in g/mol).

Knowing that the molar masses of Al and O2 are 26.98 and 31.98 g/mol, respectively, we can calculate the number of moles of each reactant as:

Therefore, 0.371 and 0.594 moles of Al and O2 were used in the reaction, respectively.

2) Determining the limiting reactant.

From the balanced chemical equation, we can see that 4 moles of Al are necessary to react with 3 moles of O2. Thus, we can determine how many moles of O2 would be necessary to react with 0.371 moles of Al:

4 mol Al ------------------- 3 mol O2

0.371 mol Al ------------- x

Solving for x, we'll have:

Therefore, 0.278 moles of O2 would be necessary to react with the used amount of Al (0.371 mol). Since the actual amount of O2 used is greater than the necessary amount, we can say that O2 is the excess reactant and Al is the limiting reactant.

3) Calculating the theoretical amount of Al2O3 produced

Now that we know that Al was the limiting reactant in this reaction, we can determine how much Al2O3 should be produced in the reaction.

From the balanced chemical equation, we can see that 4 moles of Al are necessary to produce 2 moles of Al2O3. Thus, we can write:

4 mol Al --------------------- 2 mol Al2O3

0.371 mol Al --------------- y

Solving for y, we'll have:

Therefore, with the amount of Al used, 0.186 moles of Al2O3 would be produced.

We can convert this amount in mass of Al2O3 using its molar mass (MM = 101.96 g/mol):

Therefore, 18.9 g of Al2O3 should be obtained from the given mass of Al given.

4) Calculating the percent yield of the reaction

Note that the amount of Al2O3 expected, from the amount of reactants given, was 18.9g, but only 16.0g of the product was obtained. We can calculate the percent yield of a reaction using the following equation:

Therefore, the percent yield of this reaction was 84.7% and the best option to answer the question is the last one (letter E, 85.00%).

An exothermic reaction is a reaction that releases energy. One example of this type of reaction is burning gas in a gas oven.

An endothermic reaction is a reaction that absorbs energy. One example of this type of reaction is

Mass of titanium having density 4.540 g/cm³) is 565.2g

What are significant figures?

Rules for calculating significant figures:

ex: 1.457 + 83.2 = 84.657 , rounds to 84.7

ex: 4.36 * 0.00013 = 0.0005668 , round to 0.00057

here, density = mass/ volume

mass = density * volume

= 4.540 * 124.50

= 565.23

Value of density has 4 significant figures and value of volume has 5 significant figures. so we choose density, since it has least significant figures and round to 4 digits.

We get, 565.2g as the mass of titanium

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The number of moles of H2O produced when 4 moles of H2SO4 are there is 8 moles of H2O

The reaction is  __H2SO4 + __Cr(OH)3 --> __Cr2(SO4)3 + __H2O. The reaction is as follows;

2Cr(OH)3 + 3H2SO4 → Cr2(SO4)3 + 6H2O

3 moles of H2SO4 produces 6 moles of H2O

1 mole of H2SO4 produces 2 moles of H2O

4 moles of H2SO4 produces 8 moles of H2O

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Step 1 - Understanding the definition of each term

Mass: it measures the amount of matter of a body

Volume: it measures the space occupied by a body

Density: it's the mass divided by the volume

Weight: it is an indirect measure of the mass, since it also includes the action of gravity

Step 2 - Answering the exercise

As we can see, the definition that fits what is being asked is volume.

Answer: volume